NEED HELP ASAP!! I need to find out x!! Trigonometry!!

NEED HELP ASAP!! I Need To Find Out X!! Trigonometry!!

Answers

Answer 1

Answer:

Hey there!

Well first, don't feel bad, since trig is really hard, especially if you are just learning it.

If you've learned about SOH CAH TOA, you will see that TOA is the best identity to use here.

tangent 20=x/10

tangent 20 (10)=x

x=3.64

Let me know if you have any other trig questions, I'm always here to help :)


Related Questions

100 is deposited into an investment account on January 1, 1998. You are given the following information on investment activity that takes place during the year:
April 19,1998 October 30, 1998
Value immediately prior to deposit 95 105
Deposit 2X X
The amount in the account on January 1, 1999 is 115. During 1998, The annual effective dollar weighted yield is 0%, and the annual effective time weighted yield is y. Calculate y.

Answers

Answer:

y = - 0.681 % ≈ -0.7 %

Step-by-step explanation:

Given:

                                                               April 19,1998            October 30, 1998

Value immediately prior to deposit                95                               105

                     Deposit                                       2X                                 X

amount in the account on January 1, 1999 = 115

effective dollar weighted yield = 0%

annual effective time weighted yield = y

To find:

Calculate y

Solution:

Given that the dollar weighted return is 0%

100 is deposited into investment account on January 1, 1998. So, add 100 to the deposits 2X X

100 + 2x + x = 115

3x = 115 - 100

3x = 15

x = 15/3

x = 5

Compute y

1 + y = (95/100)(105/105)(115/110)

1 + y = 0.95 * 1 * 1.045

1 + y = 0.99318

y = 0.99318 - 1

y = - 0.0068 * 100

y = - 0.681 % ≈ -0.7 %

y = -0.7 %

How much is 2/3 cups plus 1 1/4 cups

Answers

Answer:

[tex]1\frac{11}{12}[/tex]

Step-by-step explanation:

[tex]\frac{2}{3}+1\frac{1}{4}=\frac{2}{3}+\frac{5}{4}=\frac{8}{12}+\frac{15}{12}=\\ \\=\frac{8+15}{12}=\frac{23}{12}=1\frac{11}{12}[/tex]

Given the original number n. Multiply the number by 8. Add 136. Divide this sum by 8. Subtract the original number, n, from the quotient.

Answers

Answer:

8

Step-by-step explanation:

n×8=8n

8n+136=144n

144n÷8=18n

18n-n = 18

what is the simplest form of fraction ​

Answers

Answer:

A fraction is in simplest form when the top and bottom cannot be any smaller, while still being whole numbers. To simplify a fraction: divide the top and bottom by the greatest number that will divide both numbers exactly (they must stay whole numbers).

FOR EXAMPLE

5/10 = 1/2

HERE 1/2 IS THE SIMPLEST FRACTION

-5x-6(-6+3x)=105 what is the answer

Answers

Answer:

x = -3

Step-by-step explanation:

expand -23x + 36 = 105

subtract 36 from both sides -23x +36 -36 = 105 - 36

Simplify -23x = 69

Divid both sides by -23: -23x / - 23 = 69 / -23

x = -3

Find the following products: a) (−12) × (−11) × (10) b) (−25) × (−8) × (−2) WITH EXPLANATION

Answers

Step-by-step explanation:

Hey, there!!

a. (-12)×(-11)×10

Here, (-)×(-)=(+)

(-12)×(-11)=132

so,

=132×10

=1320.

For b.

(-25)×(-8)×(-2)

(-)×(-)=(+)

(-25)×(-8)=200

so,

=200×(-2) { (+)×(-)=(-)}.

= -400.

Therefore, the answer of a. no. is 1320, and no. b is (-400).

Hope it helps....

I WILL GIVE YOU LOTS OF Points

Answers

Answer:

D

Step-by-step explanation:

7^2 + 4^2 = [tex]\sqrt{65\\[/tex]

assume it is a triangle and x is the hypotenuse and use Pythagorean theorem

Answer:

D

Step-by-step explanation:

7^2 + 4^2 =

assume it is a triangle and x is the hypotenuse and use Pythagorean theorem

Which option is an example of an experiment

Answers

Answer: Testing the effectiveness of a mouthwash by allowing one group to use it and comparing the results with those of a group that doesn't use it.

Step-by-step explanation: It's the most effective

given the points (0,2) and (8,4) , what's the slope of the line?

Answers

To find the slope of this line, let's use the slope formula.

m = y2 - y1 / x2 - x1

m = 4 - 2 / 8 - 0 ⇒ 2/8 ⇒ 1/4

So m = 1/4.

what is the greatest common factor of 6d² and 18d

Answers

gcd  =  6  ⋅  d

Step-by-step explanation:

We have that  

6 d ^2  =  6  ⋅  d  ⋅  d and  18 d  =  3  ⋅  6  ⋅  d  hence the  gcd  =  6  ⋅  d

(Hope this helps <3)

If you use a 0.10 level of significance in a two-tail hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean equals 500 if you use the Z test

Answers

Answer:

If the value of our test statistics is less than the critical values of z at a 5% level of significance (where critical values are -1.645 and 1.645), then we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

If the value of our test statistics is more than the critical values of z at a 5% level of significance (where critical values are -1.645 and 1.645), then we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Step-by-step explanation:

We are given that the population mean equals 500 and we use a 0.10 level of significance in a two-tail hypothesis test.

Let [tex]\mu[/tex] = population mean.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu[/tex] = 500

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] [tex]\neq[/tex] 500

Here, the null hypothesis states that the population mean is equal to 500.

On the other hand, the alternate hypothesis states the population mean is different from 500.

Now, firstly we should note that for the two-tailed test, the level of significance to be taken is ([tex]\frac{\alpha}{2}=\frac{0.10}{2}[/tex]) = 0.05 or 5%.

So, the decision rule for rejecting a null hypothesis is given by;

If the value of our test statistics is less than the critical values of z at a 5% level of significance (where critical values are -1.645 and 1.645), then we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.If the value of our test statistics is more than the critical values of z at a 5% level of significance (where critical values are -1.645 and 1.645), then we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

A manufacturing plant has 25 fuses. 12 failures occurred within 30 days. After each failure, the molding fuse is immediately replaced. What is the MTTF for the fuses

Answers

Answer:

MTTF for the fuses =  62.5

Step-by-step explanation:

Given:

Total fuses = 25

Number of failures = 12

Number of days = 30

Find:

MTTF for the fuses.

Computation:

MTTF for the fuses = Total operation time / Number of failures

MTTF for the fuses =  (25 × 30) / 12

MTTF for the fuses =  62.5

3 packs of soda cost $10 less than 5 packs of soda. Write an equation and solve to find the cost of one pack of soda *
1 point

Answers

Answer:

3s = 5s - 10

Step-by-step explanation:

Khalid wants to buy a long sandwich for a party. Store A sells a 5 foot sandwich for $42.50. Store B sells a 6 foot sandwich for $49.50. Which store has the better buy? Show your work.

Answers

Store A: 1 foot= 42.50÷5 = $8.50

Store B= 1 foot= 49.50÷6 = $8.25

Answer:

Store B has a better buy because the price for 1 foot sandwich is cheaper than Store A.

Hello, I need some help resolving this problem of Trigonometric Identities. Use the reciprocal identities to resolve it SinA+cosA*cotA= cscA

Answers

Answer:

Please see steps below

Step-by-step explanation:

Start by writing all trig functions in the equation in terms of their simplest forms using the two basic trig functions: [tex]sin(\alpha) \,\,and\,\,cos(\alpha)[/tex]:

[tex]sin(\alpha)+ cos(\alpha)\,\frac{cos(\alpha)}{sin(\alpha)} = \frac{1}{sin(\alpha)}[/tex]

Now work on the left side (which is the most complicated one), trying to simplify it using the properties for adding fractions with different denominators:

[tex]sin(\alpha)+ cos(\alpha)\,\frac{cos(\alpha)}{sin(\alpha)}=sin(\alpha)+\frac{cos^2(\alpha)}{sin(\alpha)} =\frac{sin^2(\alpha)}{sin(\alpha)} +\frac{cos^2(\alpha)}{sin(\alpha)}=\frac{sin^2(\alpha)+cos^2(\alpha)}{sin(\alpha)}=\frac{1}{sin(\alpha)}[/tex]

where in the last step we have used that the Pythagorean identity for:

[tex]sin^2(\alpha)+cos^2{\alpha)=1[/tex]

Notice that we arrived at the expression: [tex]\frac{1}{sin(\alpha)}[/tex], which is exactly what appears on the other side of the initial equation/identity we needed to prove, so the prove has been completed.

someone Help if u know the answer pls put the step by step
6 = √v-2

Answers

Answer:

64

Step-by-step explanation:

I am assuming the -2 is outside the sqrt.

8 = sqrt(v)

v = 64

Simplify 5x + 3x + 2 +4

Answers

Hi

add "x" with "x" and numbers with numbers

5x+3x+2+4 = 8x+6

Answer: [tex]8x+6[/tex]

Add

[tex]5x+3x=8x\\2+4=6\\8x+6[/tex]

log(16x+2) - log(4x+2)= log(2x+4)​

Answers

Same as my answer last time:

Answer:

NO solution

Step-by-step explanation:

log(16x+2) - log(4x+2) = log((16x+2)/(4x+2)).

remove log

(16x+2)/(4x+2) = 2x + 4

multiply both sides by 2x + 1

8x + 1 = (2x + 4)(2x + 1)

distribute

8x + 1 = 4x^2 + 10x + 4

move to one side

4x^2 + 2x + 3 = 0

factor

but you can't

so you try to use quadratic formula, but you find that the discriminate is less than zero.

So there is no solution when x is a real number.

the length of tangent is 15 cm drawn from point whose distance from center of circle is 17 cm find the radius of circle​

Answers

Answer:

Then what is the radius of the circle? Since, the tangent of any point of a line is perpendicular to the radius through the point of contact. Hence, radius of the circle = 8 cm.

Translate from algebra to English: 14 < 21.

Answers

Answer:

14 is less than 21

Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-type crashes. Red-Light-Running System A resulted in 60% angle crashes over a sample of 720 total crashes. Red-Light-Running System B resulted in 52% angle crashes over a sample of 680 total crashes. Was there a difference between the proportions of angle crashes between

Answers

Complete Question

Two different red-light-running signal systems were installed at various intersection locations with the goal of reducing angle-type crashes. Red-Light-Running System A resulted in 60% angle crashes over a sample of 720 total crashes. Red-Light-Running System B resulted in 52% angle crashes over a sample of 680 total crashes. Was there a difference between the proportions of angle crashes between the two red-light-running systems installed? Use an alpha of 0.10.

Answer:

Yes there is a difference between the proportions of angle crashes between the two red-light-running systems installed

Step-by-step explanation:

From the question we are told that

   The first sample  proportion  is  [tex]\r p_ 1 = 0.60[/tex]

   The  second sample proportion is  [tex]p_2 = 0.52[/tex]

    The first sample size is  [tex]n_1 = 720[/tex]

     The second sample size is  [tex]n_2 = 680[/tex]

     The  level of significance is  [tex]\alpha = 0.10[/tex]

     

The null hypothesis is [tex]H_o : \r p_1 - \r p_2 = 0[/tex]

The  alternative hypothesis is  [tex]H_a : \r p_1 - \r p_2 \ne 0[/tex]

Generally the pooled proportion is mathematically represented as

       [tex]p_p = \frac{(\r p_1 * n_1 ) + (\r p_2 * n_2)}{n_1 + n_2 }[/tex]

=>     [tex]p_p = \frac{(0.6 * 720) + ( 0.52 * 680)}{720 +680 }[/tex]

=>    [tex]p_p = 0.56[/tex]

 Generally the test statistics is evaluated as        

       [tex]t = \frac{ ( \r p_1 - \r p_2 ) - 0 }{ \sqrt{ (p_p (1- p_p) * [ \frac{1}{n_1 } + \frac{1}{n_2 } ])} }[/tex]

        [tex]t = \frac{ (0.60 - 0.52 ) - 0 }{ \sqrt{ (0.56 (1- 0.56) * [ \frac{1}{720} + \frac{1}{680 } ])} }[/tex]    

       [tex]t = 3.0[/tex]

The  p-value obtained from the z-table is  

      [tex]p-value = P(Z> t ) = 0.0013499[/tex]

From the question we see that [tex]p-value < \alpha[/tex] so the null hypothesis is rejected

 Hence we can conclude that there is a difference between the proportions

         

Question 1 (1 point)
Danny wants to buy a truck in 4 years. He is going to put away $2,500.00 into his savings account that will pay him 6.75% interest compounded
monthly. How much will he have when he withdraws the funds to give a down payment?

Answers

Answer:

Amount after 4 years = $3274.125

Step-by-step explanation:

Time t= 4 years

Principal amount p= $2500

Interest rate R= 6.75%

Number of times compounded n= 4*12

Number of times compounded n= 48

Amount A = p(1+r/n)^(nt)

A= 2500(1+0.0675/48)^(48*4)

A= 2500(1+0.001406)^(192)

A= 2500(1.001406)^192

A= 2500(1.30965)

A= 3274.125

Amount after 4 years = $3274.125

what is 7 over 2 as a decimal

Answers

Answer:

3.5

Step-by-step explanation:

I recommend using a calculator. Divide 7/2.

answer is 3.5. checked and it is correct

20+x= (-15)
what does x eqaul?

Answers

Answer:

x= -35 because you have tk get x alone. so you subtract 20 from -15

Answer:

x = -35

Step-by-step explanation:

20 + x = -15

(20 + x) - 20 = -15 - 20

x = -35

A ladder 10 m long,leans against a vertical wall at an angle of 70° to the ground.if the ladder slips down the wall 4m,find,correct to 2 significant figure
(a) the new angle which the ladder makes with the ground

(b) the distance the ladder slipped back on the ground from it's original position

Answers

Answer:

(a) the new angle the ladder makes with the ground is [tex]32.7^o[/tex]

(b) the ladder slipped back about 5 meters

Step-by-step explanation:

Notice that the ladder doesn't change its length in the process.

So let's start from the initial situation , finding the distance from the ground at which the ladder touches the wall when the angle with the ground is 70^o. Notice that this situation is represented by a right angle triangle with the right angle between the wall and the ground (see attached image), and that we can use the sine function to find the side opposite to the 70 degree angle:

[tex]sin(70^o)=\frac{opposite}{hypotenuse} \\sin(70^o)=\frac{h}{10}\\h=10\, sin(70^o) \approx 9.4 \,\,m[/tex]

therefore 9.4 meters is approximately the height at which the ladder touches the wall initially.

Now, if the tip of the ladder goes down the wall 4 meters, it is now at 9.4 m - 4 m = 5.4 m from the ground. We can therefore use again the sine function to solve for the new angle:

[tex]sin(x)=\frac{opposite}{hypotenuse} \\sin(x)=\frac{5.4}{10} \\sin(x)=0.54\\x=arcsin(0.54)\\x= 32.7^o[/tex]

To answer the second question we need to find the original distance from the wall that the bottom of the ladder was originally, and for that we can use the cosine function:

[tex]cos(70^o)=\frac{adjacent}{hypotenuse} \\cos(70^o)=\frac{x}{10}\\x=10\,cos(70^o)\\x\approx 3.4 \,\,m[/tex]

Now fro the new position of the bottom of the ladder relative to the wall:

[tex]cos(32.7^o)=\frac{adjacent}{10} \\adjacent=10\,cos(32.7^o)\\adjacent\approx 8.4\,\,m[/tex]

then the difference in between those two distances is what we need:

8.4 m - 3.4 m = 5 m

A rectangular piece of metal is 20 in longer than it is wide. Squares with sides 4 in long are cut from the four corners and the flaps are folded upward to form an open box. If the volume of the box is 1200 in3,
what were the original dimensions of the piece of metal?

Answers

Answer:

width = 12.5

Step-by-step explanation:

rectangular volume = height * width * length

1200 = 4 * w * (20 + 4)

1200 = 4 * w * 24

1200 = 96w

12.5=w

what is 1/16 times 1/4 as a fraction?

Answers

Answer:

[tex]\frac{1}{16}[/tex] x [tex]\frac{1}{4}[/tex] = [tex]\frac{1}{64}[/tex]

multiply 16 by 4 to get the denominator

The fraction 1/16 times 1/4 is equal to 1/64.

To find the product of 1/16 and 1/4, we can multiply the numerators (top numbers) together and the denominators (bottom numbers) together.

1/16 x 1/4

= (1 x 1) / (16 x 4)

The product of the numerators is 1 x 1 = 1, and the product of the denominators is 16 x 4 = 64.

So, the result is:

1/16 x 1/4 = 1/64

Therefore, 1/16 times 1/4 is equal to 1/64.

Learn more about fraction here:

https://brainly.com/question/29019463

#SPJ6

1. What is the name of a number that can be written in the form a+bi where a and b are nonzero real numbers?
A. a complex number
B. a real number
C. an imaginary unit
D. a pure imaginary number

2. Which of the following statements is not true?
A. In order for a+bi to be a complex number, b must be nonzero.
B. A complex number is a number that can be written in the form a+bi where a and b are real numbers.
C. For a complex number written in the form a+bi, the value of a is called the real part of the complex number.
D. Every real number is also a complex number.

3. What is the real part of 4−5i?

4. What is the imaginary part of 7−6i?

5. Determine if the statement below is true or false. If it is false, rewrite it so it is true. Rewriting −10−−−−√ in terms of i results in −10i.
A. This statement is true.
B. This statement is false. Rewriting −10−−−−√ in terms of i results in 10i.
C. This statement is false. Rewriting −10−−−−√ in terms of i results in −10−−−−√i.
D. This statement is false. Rewriting −10−−−−√ in terms of i results in 10−−√i.

Answers

Re-writing question 5:

5. Determine if the statement below is true or false. If it is false, rewrite it so it is true. Rewriting √-10 in terms of i results in −10i.

A. This statement is true.

B. This statement is false. Rewriting √-10 in terms of i results in (√10)i.

C. This statement is false. Rewriting √-10 in terms of i results in −10√i.

D. This statement is false. Rewriting √-10 in terms of i results in 10√i.

Answer:

1) C. an imaginary number

2) A. In order for a + bi to be a complex number, b must be nonzero

3) 4

4) -6

5) B. The statement is false. Rewriting √-10 in terms of i results in (√10)i

Step-by-step explanation:

1. When a number can be expressed in the form a+bi where a and b are real numbers, then the number is said to be a complex number.

For example, the following are complex numbers where i = √-1 ;

i. 3 + 5i

ii. 4 - 7i

iii. -3 - 9i

Well, even real numbers are a subset of complex numbers. For example,

=> 5 can be written as 5 + 0i

=> -12 can be written as -12 + 0i

-- But when a and b are non-zero real numbers or at least b is a non-zero real number, then the number is said to be an imaginary number.

-- If a is zero, then the number is a purely imaginary number

-- If b is zero, then the number is a purely real number

2. For a number to be called a complex number;

i. it can be written in the form a + bi where a and b are real numbers,

ii. either a or b, or both, may be zero,

iii. a is the real part of the complex number,

iv. b is the imaginary part of the complex number.

v. it could also be a real number since every real number is also a complex number.

3. Given 4 - 5i

The real part is 4

and the imaginary part is -5

4. Given 7 - 6i

The real part is 7

and the imaginary part is -6

5. Rewrite √-10 in terms of i

Remember that i = √-1

Therefore,

√-10 = √(-1 x 10) = √-1 x √10

=> √-10 = √-1 x √10

=> √-10 = i x √10

=> √-10  = (√10)i

Solve the following quadratic equation 3x²-8x+5=0

Answers

To solve this equation, let's factor the left side.

Although you can factor it in different ways, I will show you a trick.

First, forget about the 3 and we have x² - 8x + 5.

Now, multiply the 3 by the constant to get 15.

So we have x² - 8x + 15.

Now factor to get (x - 5)(x - 3).

Now divide each of the constants in the

binomials by the leading coefficient, 3.

So we have (x - 5/3)(x - 3/3).

Simplify to get (x - 5/3)(x - 1).

Now move any denominators in front of the x in the binomial.

Moving the 3 in front of the x, we have 3x.

So our answer is (3x - 5)(x - 1) = 0.

So either 3x - 5 = 0 or x - 1 = 0.

Solving from here, we get x = 5/3 or x = 1.

Determine if the following relation is a function.

Answers

yes it is a function

Answer:

It is a function.

Step-by-step explanation:

It is proven via the vertical line test.

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Incurred program and supporting services expenses during 20x3 as follows (depreciation expense for 20x3 has been properly allocated to the functional expenses): Research Public health education Community services Management and general (does not include the audit that was donated) Fund-Raising $250.888 191.888 150, 100 125,900 114,300 Required: Prepare a statement of activities in good form for United Ways for the year ended December 31, 20X3. (Negative values should be entered with a minus sign.) Find a linear inequality with the following solution set. Each grid line represents one unit.(Give your answer in the form $ax+by+c>0$ or $ax+by+c\geq0$ where $a,$ $b,$ and $c$ are integers with no common factor greater than 1.) Which of the following is equal to the opposite of 45? (45) 45 |45| |45| Evaluate the expression: 15c4A. 8,190B. 32,760C. 1,365D. 5,460 Please help ASAP! Find y: 1/6 y 1/2 =3 1/2 y Thank you! Help ASAP! Find x: 4x/5 + x+2/3 =6 Thank you! Comparing rational numbers Which statements are true? Check all that apply. The City of Waterman established a capital projects fund for the construction of an access ramp from the parking garage to the citys office building to be used by individuals with disabilities. The estimated cost of the ramp is $213,000. On January 1, 20X2, a 10 percent, $154,000 bond issue was sold at 103 with the premium transferred to the debt service fund. At that date, the county board provided a $59,000 grant. After a period of negotiation, the city council awarded a construction contract for $186,000 on April 5, 20X2. The ramp was completed on August 8, 20X2; its actual cost was $193,000. The city council approved payment of the total actual cost of $193,000. In addition to the $193,000, the ramp was carpeted with all-weather material at a cost of $6,780. On November 3, 20X2, the city council gave the final approval to pay for the ramp and the carpeting. After all bills were paid, the remaining fund balance was transferred to the debt service fund.The City of Waterman established a debt service fund to account for the financial resources used to service the bonds issued to finance the ramp is $213,000. The 10 percent, $154,000 bond issue was sold at 103 on January 1, 20X2. It is a 10-year serial bond issue. The resources to pay the interest and annual principal will be from a property tax levy.Additional Information:1.The operating budget for 20X2 included estimated revenue of $37,100. Budgeted appropriations included $15,400 for principal, $15,400 for interest, and $4,300 for other items. The budget also included an estimated transfer in of $6,300 from the capital projects fund.2.The property tax levy was for $42,200 and an allowance for uncollectibles of $4,500 was established. Collections totaled $36,100. The remaining taxes were reclassified as delinquent and the allowance was reduced to $1,600. The bond premium was received from the capital projects fund.3.The current portion of the serial bonds and the interest due this year were recorded and paid. Other expenses charged to the debt service fund totaled $1,880, of which $1,400 was paid.4.The nominal accounts were closed.Required:a.Prepare entries for the debt service fund for 20X2. (If no entry is required for a transaction/event, select "No journal entry required" in the first account field.)b.Prepare a balance sheet for the debt service fund as of December 31, 20X2.c.Prepare a statement of revenues, expenditures, and changes in fund balance for the debt service fund for 20X2. Crowder Company acquired a tract of land containing an extractable natural resource. Coronado is required by its purchase contract to restore the land to a condition suitable for recreational use after it has extracted the natural resource. Geological surveys estimate that the recoverable reserves will be 2560000 tons, and that the land will have a value of $1080000 after restoration. Relevant cost information follows:Land $9,000,000Estimated restoration costs 1,500,000If Crowder maintains no inventories of extracted material, what should be the charge to depletion expense per ton of extracted material?extracted material?A. $1.90B. $2.10C. $1.60D. $1.80