Mountaineers often use a rope to lower themselves down the face of a cliff (this is called rappelling). They do this with their body nearly horizontal and their feet pushing against the cliff. Suppose that an 82.0 kg climber who is 1.90m tall and has a center of gravity 1.1 m from his feet rappels down a vertical cliff with his body raised 35.0° above the horizontal. He holds the rope 1.40m from his feet, and it makes a 25.0° angle with the cliff face. (a) What tension does his rope need to support? (b) Find the horizontal and vertical components of the force that the cliff face exerts on the climber's feet. (c) What minimum coefficient of static friction is needed to prevent the climber's feet from slipping on the cliff face if he has one foot at a time against the cliff?

Answers

Answer 1

(a) Tension in the rope = 1162.57 N

(b) Horizontal component of force = 965.74 N and the vertical component of force = 196.83 N

(c) Coefficient of static friction = Unknown

(a) To determine the tension the rope needs to support, we first need to find the force of gravity acting on the climber. We can use the equation:

F_gravity = m * g where,

m is the mass of the climber (82.0 kg) g is the acceleration due to gravity (9.8 m/s^2).

F_gravity = 82.0 kg * 9.8 m/s^2 = 803.6 N

Next, we'll use trigonometry to find the force that the rope needs to support.

T = F_gravity * cos(25) + F_gravity * sin(35)

where T is the tension in the rope.

T = 803.6 N * cos(25) + 803.6 N * sin(35) = 607.63 N + 554.94 N = 1162.57 N

(b) To find the horizontal and vertical components of the force that the cliff face exerts on the climber's feet, we can use trigonometry.

F_horizontal = T * cos(25)

F_vertical = T * sin(25)

F_horizontal = 1162.57 N * cos(25) = 965.74 N

F_vertical = 1162.57 N * sin(25) = 196.83 N

(c) To find the minimum coefficient of static friction needed to prevent the climber's feet from slipping, we'll use the equation:

F_friction = friction_coefficient * F_norm where,

F_norm is the normal force acting on the climber's feet friction_coefficient is the coefficient of static friction.

F_norm = F_vertical = T * sin(25) = 196.83 N

friction_coefficient = F_friction / F_norm = Unknown / 196.83 N

It's important to note that this is a simplified scenario and in a real-life scenario, the rope, angles, and forces will be changing, so the tension and the friction coefficient will be dynamic, this is just a snapshot of a specific scenario. Also, as the friction coefficient is unknown, we cannot calculate it without knowing the force of friction.

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Related Questions

In shallow water of depth d the speed of waves is approximately v=√gd.
Find the speed of a wave with a wavelength of 2.6 cm in water that is 0.85 cm deep.
Find the period of a wave with a wavelength of 2.6 cm in water that is 0.85 cm deep.

Answers

the speed and period  of a wave with a wavelength of 2.6 cm in water that is 0.85 cm deep is 28.8 cm/s and 0.09s respectively.

What are wavelength and frequency?

The wavelength, which will also apply to troughs, is the separation between two wave crests. The number of vibrations that pass over a specific place in a second is known as the frequency and is expressed in cycles per second (Hz) (Hertz).

v=[tex]\sqrt{gd}[/tex]

=> [tex]\sqrt{9.8 x 0.0085}[/tex]

=> 0.288m/s => 28.8 cm/s

f, frequency = velocity/wavelength = 1/period

             => 28.8/2.6 = 1/period

Period = 0.09s

What happens as wavelength gets longer?

A wavelength's frequency and energy (E) drop as it gets longer. These equations show that as the frequency increases, the wavelength decreases. The wavelength lengthens as the frequency drops. The two main categories of waves are electromagnetic and mechanical.

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The south pole of a bar magnet is brought toward the current loop of (Figure 1). Part A Does the bar magnet attract, repel, or have no effect on the loop? Explain. Match the words in the left column to the appropriate blanks in the sentences on the right.

Answers

Given a current loop, find the direction of the magnetic field using the right-hand rule  The magnetic field created by the current loop goes from right to left.

Current travels clockwise (relative to the magnet), so now bend the fingers of your right hand clockwise and point your thumb in the direction of the magnetic field.

This creates a magnetic dipole with the north pole on the left and the south pole on the right.

Now, in a magnet, opposite poles attract and like poles repel, so if we move the magnet towards the loop as shown in the figure, his south pole of the magnet will be repelled by the nearest south pole of the current loop. increase.

Magnetic field in current loop

A current in a circular loop creates a magnetic field that is more concentrated in the center of the loop than outside it. Stacking multiple loops further concentrates the field in what is called a solenoid.

What is the magnetic moment of the current loop?

The magnetic moment m of a current loop is a vector whose magnitude is equal to the area of ​​the loop times the magnitude of the current flowing through it (m = IA) and whose direction is perpendicular to the plane through which the current flows. .

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under what condition will you and a friend share the same realm of spacetime?

Answers

These two situations will allow you and a friend to share the same region of spacetime: you are both side by side and travelling at constant speed; or you are both side by side and at rest.

A particle gains constant velocity when it crosses an equal-length linear path multiple times at regular intervals. The uniform speed of a particle travelling in a straight line at a constant speed is another definition. This means that the particle will move along a straight line at constant speed. In physics, the concept of spacetime refers to a mathematical model that unifies an inertial reference frame of space and time (x, y) with a non-inertial reference frame of space and time (x', t') to create a four-dimensional model that connects a position to the field.

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for a given process at constant pressure, w is positive. this means that the process involves______
A) work being done by the system on the surroundings
B) work being done by the surroundings on the system
C) no work being done
D) an equal amount of work done on the system and by the system
E) work being done against a vacuum

Answers

For a given process at constant pressure, w is positive. this means that the process involves work being done by the system on the surroundings

Work (w) is a term used in thermodynamics to describe the transfer of energy from a system to its surroundings. The formula w = -PV determines how much work a system does on its surroundings while a process takes place at constant pressure. P represents the constant pressure, while V represents the system's volume change.

As long as the pressure remains constant, the effort will be directly proportional to the transpose in volume. The work the system performs on its surroundings changes from negative to positive as its volume increases, transferring energy from the system to its setting in the form of work. This is consistent with the statement that the process involves the system working on the environment.

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how many nanometers are there in one gram?

For example enter 105 as 1x105

Answers

One gigameter, or 1 Gm, equals one million billion billion billion nanometers, or nm. It is the equivalent length of one gigameter, but expressed in the alternative length unit of nanometers.

How much is a nanometer?

One nanometer is equal to one billionth of a metre in the International System of Units because the word "nano" stands for one billionth, or 10-9. Here are some illustrations to help you understand just how tiny that is: The thickness of a sheet of paper is 100,000 nanometers.

Similar to metres and centimetres, nanometers are a unit of length measurement. A nanometer is 0.000000001 or 10-9 metres, or one billionth of a metre. Greek for "dwarf" is the root of the word "nano." Objects with diameters between one and one hundred nanometers are referred to as nanoscale (nm).

One billionth of a metre is known as a nanometer (nm).

"Nano" is a prefix that literally meaning one billionth. One nanometer is equal to 0.000000001 m when written out.

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The angle of incidence when light travels from air to water of refractive index 4/3 and then to glass of refractive index 1.60 is 60 degrees. Calculate the angle of refraction in the glass.

Answers

The angle of refraction in the glass is 37.51 degree

How can we calculate the angle of refraction in the glass?

The angle of incidence when light travels from air to water of refractive index 4/3 and then to glass of refractive index 1.60 is 60 degrees. To calculate the angle of refraction in the glass, we can use Snell's law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two materials.

Sin(incident angle) / Sin(refraction angle) = (refractive index of air) / (refractive index of glass)

sin(60) / sin(x) = 1 / 1.60

where x is the angle of refraction in the glass.

Solving for x,

x = sin^-1(sin(60) / 1.60)

= sin^-1(1 / 1.60)

= sin^-1(0.625)

=37.51 degree

Therefore, the angle of refraction in the glass is 37.51 degree.

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A gas undergoes a change of state described by the pV diagram shown in the figure below.

Answers

The gas is undergoing an isothermal process, which is a process in which temperature remains constant. This process involves the gas expanding from a compressed state to a more expanded state.

What is gas?
Gas
is a form of energy that is produced through the burning of fossil fuels, such as coal, oil, and natural gas. It is used to power many of the everyday things we use, including our cars, stoves, and furnaces. Gas is also used to generate electricity, as well as provide heat for homes and businesses. When burned, gas creates a number of pollutants, such as carbon dioxide, carbon monoxide, sulfur dioxide, and nitrogen oxides, which can have a negative effect on the environment. To reduce its environmental impact, gas should be used as efficiently as possible. This means using appliances with higher energy ratings and making sure that any maintenance needed is kept up to date. In addition, using renewable energy sources, such as solar and wind power, can help reduce the use of gas.

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Parallel light rays cross interfaces from medium 1 into medium 2 and then into medium 3 as shown below. What can we say about the relative sizes of the indices of refraction of those media? (a) n_1 > n_2 > n_3 (b) n_3 > n_2 > n_1 (c) n_2 > n_3 > n_1 (d) n_1 > n_3 > n_2 (e) n_2 > n_1 > n_3 (f) None of the above

Answers

When rays enter medium 2, they are bent in the direction of the normal, therefore n2 > n1. However, when entering medium 3, rays are bent away from the normal, so n3>n2. So, n2 > n1 > n3.

Parallel beam of light refers to a collection of rays that are perpendicular to one another. Parallel light rays traverse medium 1 and medium 2 surfaces before entering medium 3. The Snell's rule only connects the refraction indices of the two media A and B to the angles I and r. As a result, n=sini/sinr is the refractive index of medium B in comparison to medium A. The frequency remains constant even when the speed of light changes when it moves from one medium to another (v=c/n). Thus, the light deviates.

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what would be the radius of a 23892u nucleus if it had the density of the earth?

Answers

Since volume grows as a cube of radius, a planet with a 1.5 earth radius would have a volume that is 1.53, or roughly 3.375 times that of the current Earth.

Given that Earth has a density of 5.513 g/cm3, its new density would be around 1.63 g/cm3 if its radius were doubled by 50% but its mass remained constant. Jupiter has a density of 1.326 g/cm3 as a point of comparison. However, it's possible that you're referring to what would happen if both size and mass were scaled appropriately, making this new Earth identical to existing super-earths with 1.5 earth radii. The density would then be around 6-7 g/cm3.

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also due rn sooo thx

Answers

Earth's most recent glacial period ended about 11,500 years ago.

The Great Oxygenation Event began about 2.3 billion years ago.

About 160 years ago  carbon dioxide began increasing exponentially to unprecedented levels.

What is the glacial period?

A glacial period is described as an interval of time within an ice age that is marked by colder temperatures and glacier advances.

There are three types of continental glaciers, and they include:

ice sheets, ice caps, and outlet.

An ice sheet covers an area larger than 50,000 square kilometers. Greenland and Antarctica and are covered by massive ice sheets today.

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A vertically hung spring has a spring constant of 150 newtons per meter. A 2.00-kg mass is suspended from the spring and allowed to come to rest. Calculate the elongation of the spring produced by the suspended 2.00-kg mass. Write your answer in units of m.

PLEASE HELPPP!!

Answers

K= 150 N/M
M= 2Kg
Fs= Fg= 19.6N
PEs= Fs X = ½ (19.610) (13M)
= 121
PE = 1/2 K x 2
= .5 (150N/M) (1. 3m)^2
=1.27J

A 1,100kg car is turning on a flat roadway, moving in a circle with a radius of 12m. The car is going maximum speed through the turn without skidding. If the coefficient of friction between the car and the road is 0.57, find the speed of the car.

speed = ___ m/s (round to the nearest tenth)

Answers

Answer: 20.7 m/s.

Explanation: To find the speed of the car, we need to use the equation for centripetal force, which is:

Fc = m * a = m * v^2 / r

where Fc is the centripetal force, m is the mass of the car, a is the centripetal acceleration, v is the velocity of the car, and r is the radius of the turn.

We know that the coefficient of friction between the car and the road is 0.57

and it is the maximum speed, so the force of friction is equal to the centripetal force.

f = Fc = m * a = m * v^2 / r

f = μ * N = μ * m * g

so

m * v^2 / r = μ * m * g

where g is the acceleration due to gravity.

By substituting the known values into the equation, we get:

(1100 kg) * v^2 / (12 m) = (0.57) * (1100 kg) * (9.8 m/s^2)

Solving for v, we get:

v = sqrt((0.57 * 9.8 * 12 * 1100) / 1100)

v ≈ 20.7 m/s

To the nearest tenth, the speed of the car is 20.7 m/s.

explain how the energies associated with the outer orbital electrons (e-) of the cl and h atoms drives this reaction from left to right. feel free to use the analogy of val the waitress, but demonstrate that you understand the concept involved.

Answers

Electron configuration is the distribution of electrons of an atom in the atomic orbitals in the increasing order of their atomic energies.

As a result, the orbitals are filled in the following order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p

The electrons found in the outermost shell are referred to as

valence electrons. In contrast, the electrons found in the innermost shell or the lowest energy levels are called core electrons.

(A) The electron gain enthalpy is exothermic and is more than those required for dissociation and I.E of H

(B) If total heat of the reaction is negative , it is clear that the reaction proceed from left to right.

The ground-state electron configuration of a noble gas is ns2 np6

The noble gas elements' shells are completely filled, resulting in a stable electronic configuration. Hence, removing the first electron from the stable configuration necessitates a great amount of energy.

Thus, noble gases have a high ionization energy value.

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What is the radial distance between the 500 VV equipotential surface and the 1000 VV surface?
Express your answer with the appropriate units.

Answers

The radial distance between the 500 VV equipotential surface is 34.2 m, and the 1000 VV surface is 17.1 m .

What is distance ?

Distance is the overall distance that an object actually travels along its course. The displacement of an object between two points is the smallest straight-line distance between those two points, measured from one position to the other. The metric system is used to measure both displacement and distance (m).

What is equipotential surface  ?

When a surface has an equipotential potential, all of its points have the same electric potential. The charge will have the same potential energy at any location along the equipotential surface as a result.

V = k Q / r

(a) 500 V = (9 x 109 ) (1.90 x 10-6 ) / r1

     r1 = 34.2 m

and 1000 = (9 x 109 ) (1.90 x 10-6 ) / r2

  r2 = 17.1 m

distance between them = r1 - r2 = 17.1 m  

(B) for 1500 V

1500 = (9 x 109 ) (1.90 x 10-6 ) / r3

r3 = 11.4 m

distance = r2 - r3 = 5.7 m  

Therefore, radial distance between the 500 VV equipotential surface is 34.2 m, and the 1000 VV surface is 17.1 m .

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Velocity and Acceleration Problem

Answers

Answer:

velocity is a hell of a drug treatment classes in the position you are offering to help you with your medical needs and your needs and your needs and your needs and your needs for the future and to be getting your son in a better place for the better of the richest of his family and his life in the world.

Explanation:

no exceptions

Which statement about alcohol's path through the human body is true?

a.
alcohol is metabolized by the kidneys

b.
no digestion is needed in alcohol absorption

c.
most alcohol is absorbed through the stomach lining

d.
consumption of food will stop alcohol from entering the bloodstream

Answers

No digestion is needed in alcohol absorption. Is statement about alcohol's path through the human body .

What is absorption in biology?

Absorption is the process by which the products of digestion are absorbed by the blood to be supplied to the rest of the body. During absorption, the digested products are transported into the blood or lymph through the mucous membrane.

What is meant by adsorption and absorption?

Adsorption and absorption mean quite different things. Absorption is where a liquid is soaked up into something like a sponge, cloth or filter paper. The liquid is completely absorbed into the absorbent material. Adsorption refers to individual molecules, atoms or ions gathering on surfaces.

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Repeat the previous problem for glasses that are 1.75 cm from the eyes. Reference Previous Problem:
A myopic person sees that her contact lens prescription is –4.00 D . What is her far point?

Answers

The far point of a myopic person with a prescription of -4.00 D is the point at which the eye can focus clearly on objects without the aid of corrective lenses.

What is objects?

Object is an entity that possesses state and behavior. It can be physical or a virtual component. In programming, an object is a self-contained component which consists of both data and procedures/functions to manipulate the data. Objects can interact with other objects, and the interaction between objects forms the basis of object-oriented programming.

This point is approximately 4 meters (13 feet) away from the eye. The far point is the furthest point away from the eye at which a person with myopia can see clearly. In other words, the person with -4.00 D myopia can see clearly with their corrective lenses up to 4 meters away from them. Beyond that point, the person will need to use their corrective lenses to see clearly.

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what is the magnitude of the total flux through the five non-shaded faces?

Answers

The magnitude of the total flux through the five non-shaded faces is 5 times the magnitude of the flux through a single face.

What does total flux mean?

Total flux is a measure of the overall rate of flow of a physical quantity, such as energy or particles, through a given surface or region. It is typically expressed as the total amount of the physical quantity that passes through the surface or region per unit time.In other words, total flux is a measure of the overall rate at which something is being transferred across a given area.

What does Magnatitude means?

Magnatitude is a term used to describe the strength or intensity of something, such as an emotion, a physical force, or an event. It is often used to describe the intensity of an earthquake, hurricane, or other natural disaster. In some cases, the term can also be used to describe the power of a person or group, such as the magnatitude of a leader's influence or the magnatitude of a corporation's reach.

Therefore, the magnitude of the total flux through the five non-shaded faces is 5 times the magnitude of the flux through a single face, or 5F, where F is the magnitude of the flux through a single face.

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is 12 m/s a realistic speed for an object that you can throw with your hands?

Answers

Answer:

As 26.8 mph is equivalent to 12 m/s, it is a relatively fast speed for something you would throw with your hand.

The average person would have a hard time throwing objects at this speed without special training or equipment, There are athletes for example cricketers who can throw an object (ball) at 100-130 kph

The important thing to remember is that throwing an object from your hand requires no other external energy source, so it's primarily mechanical energy, which the human body can supply, and it can be improved with the right training and technique.

Jumbo is back! Jumbo is the 4.8-Mg elephant. This time he's standing at the outer edge of a 11-Mg turntable of radius 8.5 m, rotating with angular velocity 0.15 s?1 on friction less bearings. Jumbo then walks to the center of the turntable. Treat Jumbo as a point mass and the turntable as a solid disk.
Part A: Find the magnitude of the angular velocity of the turntable once Jumbo reaches the center. ?t = ? rad/s
Part B: Find the work Jumbo does in walking to the center. W = ?

Answers

Consequently, the turntable's angular velocity when the elephant reaches its center is [tex]$1.459 \mathrm{rad} / \mathrm{sec}$[/tex]

The giant performs 37945.68J of work while walking to the center.

Using conservation of angular momentum

[tex]& I_1 \omega_1=I_2 \omega_2[/tex]

Where [tex]I_1[/tex] is equal to [tex]& \left(\frac{1}{2} M r^2+m r^2\right)[/tex]

Substitute the value in above equation we get,

[tex]& \left(\frac{1}{2} M r^2+m r^2\right) \omega_1=\left(\frac{1}{2} M r^2\right) \omega_2[/tex]

Notice that [tex]$I_2$[/tex] (moment of inertia for elephant) is zero as he is at the centre.

Given M is equal to 11 Mg.

where m is equal to 4.8Mg

While radius is given as 8.5m

Substitute the value in above angular momentum equation we get.

[tex]& \left(\frac{1}{2} \times 11000 \mathrm{~kg} \times(8.5 \mathrm{~m})^2+4800 \mathrm{~kg} \times(8.5 \mathrm{~m})^2\right) 0.15 \mathrm{rad} / \mathrm{sec}[/tex]

Further we get

[tex]\\=\left(\frac{1}{2} \times 1100 \times(8.5)^2\right) \omega_2[/tex]

[tex]& (39737.5+346800) 0.15=39737.5 \omega_2 \\& \omega_2=1.459 \mathrm{rad} / \mathrm{sec}[/tex]

Angular velocity of the turntable when the elephant reaches the center is [tex]$1.459 \mathrm{rad} / \mathrm{sec}$[/tex]

(b)

Work done is equal to change in rotational kinetic energy

[tex]\mathrm{W} & =\frac{1}{2} I_2\left(\omega_2\right)^2-\frac{1}{2} I_1\left(\omega_1\right)^2[/tex]

Substitute the value in above equation we get,

W=42294.23 - 4348.55

W=37945.68J

Work done by the jumbo in walking to the centre is 37945.68J

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A 5 kg mass is attached to a spring with a spring constant of 490 N/m. The spring is stretched 14 cm from equilibrium and released at t = 0 s. a) Write the equation for the position as a function of time. b) What is the position of the spring at t = 0.25 s?

Answers

(a) The equation for the position as a function of time is x (t) = 14 cos(9.9t).

(b) The position of the spring at t = 0.25 s is -11 cm.

What is the angular speed of the spring?

The angular speed of the spring is calculated as follows;

ω = √ ( k / m )

where;

k is the spring constantm is the mass of the spring

ω = √ ( 490 / 5 )

ω = 9.9 rad/s

The equation for the position as a function of time is written as;

x (t) = A cos(ωt)

where;

A is the amplitude = 14 cmω is the angular speed = 9.9 rad

x (t) = 14 cos(9.9t)

when the time, t = 0.25 s

x (0.25) = 14 cos ( 9.9 x 0.25 )

x (0.25) = -11 cm

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Marianne really likes coffee, but on summer days she doesn't wantto drink a hot beverage.
If she is served 230 { mL} of coffee at 84^\circ {\rm{C}} in a well-insulatedcontainer, how much ice at 0 ^\circ {\rm{C}} should she add toobtain a final temperature of 38^\circ {\rm{C}}?

Answers

307.89 g ice at 0 ^\circ {\rm{C}} should she add toobtain a final temperature of 38 ^\circ {\rm{C}}

What is the scientific definition of temperature?

The associated with the motion power of the electrons in an item is measured by its temperature. The velocity of these particles likewise increases as the temperature rises. A thermometer or a temperature probe is used to determine the temperature.

The idea of heat conservation may be used to determine how much ice Marianne should put in the coffee. The energy gained by the melting ice is equivalent to the energy lost by the hot coffee.

The heat absorbed by the ice is given by the equation:

Q = mcΔT

where Q is the heat absorbed, m is the mass of the ice, c is the specific heat capacity of water (4.18 J/g*°C) and ΔT is the change in temperature (0 - 38 = -38°C).

The heat lost by the coffee is given by the equation:

Q = mcΔT

where Q is the heat lost, m is the mass of the coffee, c is the specific heat capacity of water (4.18 J/g*°C) and ΔT is the change in temperature (84 - 38 = 46°C).

We can put the two equations equal to one another and find the mass of the ice since the heat released by the coffee is equal to the heat absorbed by the ice:

m_ice * c * (-38) = m_coffee * c * 46

m_ice = m_coffee * 46 / (-38)

The mass of the coffee is given by the volume of coffee (230 mL) and the density of water (1 g/mL)

m_coffee = 230 mL * 1 g/mL = 230 g

so the mass of the ice needed is :

m_ice = 230 g * 46 / (-38) = -307.89 g

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Convert 560 kilometers into miles

Answers

Answer:

347.967868

Explanation:

A string of length L = 2.2 m and mass m = 0.035 kg is fixed between two stationary points, and when the string is played a transverse wave of frequency f = 94 Hz is generated. The wave is vibrating in an unknown harmonic.
a. If the wavelength is 10.0 cm, which harmonic is this, counting the fundamental as 1?
b. For the case described in Part (a), what is the tension in N?

Answers

The wave is vibrating in an unknown harmonic are:

a. This is the 4th harmonic, counting the fundamental as 1.

b. The tension in the string would be T = 0.742 N.

What is wave?
Wave
is a type of energy transfer through a medium, such as water, air, or sound. It is a disturbance that is propagated in two directions, forming a continuous oscillation of particles in the medium. Waves transfer energy without transferring matter, and can travel long distances without losing energy. Wave motion is characterized by its wavelength, frequency, and amplitude. Wavelength is the distance between two corresponding points on a wave, frequency is the number of waves that pass a point in a given time, and amplitude is the maximum displacement of the particles from their rest position. Wave motion is important for many physical phenomena, including sound, light, and ocean waves.

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Which of the following does not require work to be done? An increase in:
a) potential energy
b) kinetic energy
c) a combo of potential and kinetic
d) none of the above

Answers

None of the given options requires work to be done.

Does potential energy require work to be done?

Potential energy is a concept of the energy that results from the object's position; as a concept, it refers to the work you have to do to move the object from U=0.

How is potential energy related to work?

The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r. The force you must exert to move it must be equal but oppositely directed, and that is the source of the negative sign.

Does kinetic energy require work?

Kinetic energy is the energy an object has because of its motion. If we want to accelerate an object, then we must apply a force. Applying a force requires us to do work. After work has been done, energy has been transferred to the object, and the object will be moving with a new constant speed.

Thus, both kinetic and potential energy is not related to work. So, the correct option is D

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Mary wants to investigate the relationship between magnetism and the movement of an electric charge.she has a call of wire hooked up to an ammeter to measure current. She has a moveable magnet inside the coil. As she moves the magnet within the coil, the ammeter indicates a certain current. Mary wants to increase the amount of current from the device.

Answers

Moving magnetic fields cause electrons to be pulled and pushed. There are loosely held electrons in metals like copper and aluminum. By rotating a coil of wire around a magnet or vice versa, an electrical current is produced by pushing the wire's electrons.

What is meant by electrons?Unattached or attached to an atom, an electron is a negatively charged subatomic particle (not bound). One of the three main types of particles inside an atom, along with protons and neutrons, is an electron that is linked to the atom. An atom's nucleus is made up of electrons, protons, and neutrons.The tiniest and least massive component of an atom is an electron, which has a negative charge. In a neutral atom, the number of protons and electrons is equal. For instance, the hydrogen atom only contains one proton and one electron. While the uranium atom has 92 protons and, thus, 92 electrons.

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If a car travels 200 meters in 10 seconds, what is the car's speed?

A. 200 m/s
B. 210 m/s
C. 10 m/s
D. 20 m/s

Answers

d. 20 because 20 • 10 is 200

The speed of the car is 20 m/s. Therefore, Option D is correct

We know that Speed (S)= Distance (D) / Time (T)

Here, Distance (D)= 200 meters

Time (T) = 10 seconds

Therefore,

Speed= 200/10

Speed= 20m/s

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A cat runs and jumps from one roof top to another which is 5 meters away and 3 meters below

Answers

Answer: 6.45 m/s

Explanation:

Find out the time value

3 = 1/2*a*T^2

6/10 = t^2

t = 0.77 seconds

and the distance is given as 5 m

thus speed,= distance/time.

Putting values,

speed = 5/0.77

= 6.45 m/s

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A ball is kicked at an angle θ = 45°. It is intended that the ball lands in the back of a moving truck which has a trunk of length L = 2.5m. If the initial horizontal distance from the back of the truck to the ball, at the instant of the kick, is d = 5m, and the truck moves directly away from the ball at velocity V = 9m/s (as shown on the next page), what is the maximum and minimum velocity vo so that the ball lands in the trunk? Assume that the initial height of 3 the ball is equal to the height of the ball at the instant it begins to enter the trunk. 

Answers

To find the maximum and minimum velocities that the ball can have and still land in the trunk of the truck, we need to use the equations of motion for the horizontal and vertical positions of the ball as a function of time. Since the truck is moving away from the ball, the horizontal position of the ball will be given by:

x(t) = x0 + Vt - v0cos(θ)*t

Where x0 is the initial horizontal distance from the back of the truck to the ball, V is the velocity of the truck, t is the time, and v0 is the initial velocity of the ball.

Similarly, the vertical position of the ball will be given by:

y(t) = y0 + v0*sin(θ)*t - (1/2)gt^2

Where y0 is the initial height of the ball, v0 is the initial velocity of the ball, g is the acceleration due to gravity and t is the time.

We know that the ball will land in the trunk of the truck if the horizontal position of the ball is equal to the length of the trunk (L) at the same time that the vertical position of the ball is equal to the initial height of the ball (y0).

We can find the time of flight by setting y = 0,

t = (2v0sin(θ))/g

Now, we substitute this value of t and y0 = 0 in the equation of x(t) and equate it with L.

x0 + Vt - v0cos(θ)*t = L

We can solve this equation for v0 to get the initial velocity of the ball.

v0 = (L + x0cos(θ) - Vt)/(cos(θ) - t*sin(θ))

Finally, we know that the minimum and maximum initial velocities will correspond to the maximum and minimum values of sin(θ) and cos(θ). Since θ = 45°, we can find the maximum and minimum velocities as follows:

v0_max = (L + x0cos(45) - Vt)/(cos(45) - tsin(45))

v0_min = (L + x0cos(45) - Vt)/(cos(45) + tsin(45))

Note that in this case x0=5m, L=2.5m, θ=45°, V=9m/s, t = (2v0sin(45))/g and g is 9.8m/s^2

you can use these values to find out v0_max and v0_min.

The cathode-ray tubes that generated the picture in early color televisions were sources of x rays. If the acceleration voltage in a television tube is 14.6 kV , what are the shortest-wavelength (in nm) x rays produced by the television? (Modern televisions contain shielding to stop these x rays.)

Answers

The shortest-wavelength (in nm) x rays produced by the television is when a cathode-ray tubes that generated the picture in early color televisions were sources of x rays is 0.85Å.

Given the accelerating voltage in a television tube (V) = 14.6KV

We know that from energy equation E = eΔV where e is the charge.

Also E = hc/∧ where h is planck's constant, c is the speed of light and ∧ is the wavelength of light.

So by comparing above equations, we say that

eΔV = hc/∧ where hc = 1240eV

e x 14.6 x 10^3 V = 1240/∧ eV

∧ = 1240/14.6 x 10^3 = 8.5 x 10^-2 nm = 0.85Å.

Hence the the shortest-wavelength (in nm) x rays produced by the television is 0.85Å.

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