Answer:
The power transmitted to the pulley is 0.0455 hp.
Explanation:
Given;
mass attached to the rope, m = 5 lb
radius of the pulley, r = 3 in
constant rate of fall of the mass, v = 5 ft/s
acceleration due to gravity, g = 32.2 ft/s²
1 lbf = 32.2 lb.ft/s²
The power transmitted to the pulley is calculated as;
P = Fv
P = (mg)v
[tex]P = 5 \ lb \ \times \ 32.2 \ \frac{ft}{s^2} \ \times \ 5 \ \frac{ft}{s} \ \times \ \frac{1 \ lbf}{32.2 \ lb.ft/s^2} \ \ = 25 \ \frac{ft.lbf}{s} \\\\[/tex]
in horse power, the power transmitted is calculated as;
[tex]P = \frac{25 \ ft.lbf}{s} \ \times \ \frac{1 \ hp}{550 \ ft.lbf/s} \ \ = 0.0455 \ hp[/tex]
Therefore, the power transmitted to the pulley is 0.0455 hp.
Brainliest brainliest help help help mememememememme
Answer:
????????????????????,
Explanation:
I need points sorry
Answer:
honestly this was so long ago can i get brainliest i need 2 more until i am at expert level
Explanation:
if an object is projected upward with an initial velocity of 80 ft per second, what is t at maximum height
Answer:
The time at maximum height is 2.49 s.
Explanation:
The time (t) at the maximum height can be found using the following equation:
[tex] v_{f} = v_{0} - gt [/tex]
Where:
[tex]v_{f}[/tex]: is the final velocity = 0 (at the maximum height)
[tex]v_{0}[/tex]: is the initial velocity = 80 ft/s
g: is the gravity = 9.81 m/s²
Hence, the time is:
[tex]t = \frac{v_{0}}{g} = \frac{80 \frac{ft}{s}*\frac{1 m}{3.281 ft}}{9.81 m/s^{2}} = 2.49 s[/tex]
Therefore, the time at maximum height is 2.49 s.
I hope it helps you!
Potential energy diagrams for a particle are useful in predicting the motion of that particle.
a. True
b. False
Answer:
True
Explanation:
How to intercept a slope
Answer:
The slope intercept form is probably the most frequently used way to express equation of a line. To be able to use slope intercept form, all that you need to be able to do is 1) find the slope of a line and 2) find the y-intercept of a line.
Explanation:
Answer:You plot the numbers and divide
Explanation:
A 450-N rightward force is used to drag a large box across the floor with a constant velocity of 1.2 m/s. The coefficient of friction between the box and the floor is 0.795. Determine the mass of the box.
Answer:
the mass of the box is 51.98 kg.
Explanation:
Given;
applied horizontal force, F = 450 N
coefficient of friction, μ = 0.795
constant velocity, v = 1.2 m/s
At constant velocity, the acceleration of the object is zero and the net force will be zero.
[tex]F_{Net} = F - F_k\\\\0 = F - F_k\\\\F_k = F\\\\\mu \ N = F\\\\\mu (mg) = F\\\\m = \frac{F}{\mu g} \\\\m = \frac{405}{0.795 \ \times \ 9.8} \\\\m = 51.98 \ kg[/tex]
Therefore, the mass of the box is 51.98 kg.
what are examples of an insulator, conductor, and semiconductor?
A person runs up 33 stairs of height 0.25 m. The person weighs 599.85 N. How much energy does it take for the person to reach the top of the stairs? I need the answer ASAP
Answer:
149.96J
Explanation:
Given parameters:
Number of stairs = 33
Height = 0.25m
Weight = 599.85N
Unknown:
Energy the person takes to reach the top = ?
Solution:
To solve this problem;
The energy it takes is given as:
Energy = weight x height
Energy = mass x gravity x height
Now,
Insert the given parameters and solve;
Energy = 599.85 x 0.25 = 149.96J
A planet of mass M and radius R has no atmosphere. The escape velocity at its surface is ve. An object of mass m is at rest a distance r from the center of the planet, where r>>R. The particle falls to the surface of the planet. The total mechanical energy of the particle at the surface of the planet is closest to
The total mechanical energy of the particle of mass m at the surface of the planet of mass M when the distance is R (planet's radius) is [tex] E = \frac{GmM}{R} + \frac{1}{2}mv_{e}^{2} [/tex].
When the particle is at rest at a distance "r" from the planet's center, it only has gravitational potential energy. As the particle falls to the planet's surface, some initial gravitational potential energy converts to kinetic energy.
The total mechanical energy of the particle at the planet's surface is equal to the sum of the gravitational potential energy and kinetic energy, so:
[tex] E = P + K [/tex]
[tex] E = maR + \frac{1}{2}mv_{e}^{2} [/tex] (1)
Where:
m: is the mass of the object
a: is the acceleration due to gravity on the surface of the planet
R: is the radius of the planet
[tex]v_{e}[/tex]: is the escape velocity
The acceleration due to gravity is given by:
[tex] a = \frac{GM}{R^{2}} [/tex] (2)
By entering equation (2) into (1), we have:
[tex] E =mR\frac{GM}{R^{2}} + \frac{1}{2}mv_{e}^{2} [/tex]
[tex] E = \frac{GmM}{R} + \frac{1}{2}mv_{e}^{2} [/tex]
Therefore, the total mechanical energy of the particle is [tex] E = \frac{GmM}{R} + \frac{1}{2}mv_{e}^{2} [/tex]
Learn more here:
https://brainly.com/question/9322440?referrer=searchResultshttps://brainly.com/question/14127859?referrer=searchResultsI hope it helps you!
Water runs out of a horizontal drainpipe at the rate of 135 kg/min. It falls 3.1 m to the ground. Assuming the water doesn't splash up, what average force does the water exert on the ground
Answer:
The average force exerted by the water on the ground is 17.53 N.
Explanation:
Given;
mass flow rate of the water, m' = 135 kg/min
height of fall of the water, h = 3.1 m
the time taken for the water to fall to the ground;
[tex]h = ut + \frac{1}{2}gt^2\\\\h = 0 + \frac{1}{2}gt^2\\\\t = \sqrt{\frac{2\times 3.1}{9.8} } \\\\t = 0.795 \ s[/tex]
mass of the water;
[tex]m = m't\\\\m = 135 \ \frac{kg}{min} \ \times \ 0.795 \ s \ \times \ \frac{1 \ \min}{60 \ s} \ = 1.789 \ kg[/tex]
the average force exerted by the water on the ground;
F = mg
F = 1.789 x 9.8
F = 17.53 N
Therefore, the average force exerted by the water on the ground is 17.53 N.
Sorry it’s twisted but please help, thank you!
Answer:
A-50 N
Explanation:
A coin lies at the bottom of a tank containing water to a Dept of 130cm. If the refractive index of the water is 1.3, calculate the apparent displacement of the coin viewed vertically from above
Answer: 100 cm
Explanation: When an object at the bottom of a tank with water is viewed vertically from above, to the observer, it seems the object is closer to the eye, i.e., the apparent depth of the object is less than the real depth the object is. This is caused by Refraction, which happens when an incident light passing through an interface between two different media causing the light to be deflected.
The relation between real and apparent depths is given by:
[tex]n=\frac{Dr}{Da}[/tex]
where
n is refractive index of the surface
Dr is real depth
Da is apparent depth
For the coin at the bottom of a tank, apparent depth is:
[tex]n=\frac{Dr}{Da}[/tex]
[tex]Da=\frac{Dr}{n}[/tex]
[tex]Da=\frac{130}{1.3}[/tex]
Da = 100
Apparent displacement of the coin viewed vertically from above is 100 cm.
Psychophysic is the study of
Answer:
Psychophysics is the subfield of psychology devoted to the study of physical stimuli and their interaction with sensory systems.
Explanation:
Hope this helps <3
Summarize what you have learned about power and electrical energy.
Answer:
i dont know.
Explanation:
school is pointless
A finch rides on the back of a Galapagos tortoise, which walks at the stately pace of 0.060 m>s. After 1.5 minutes the finch tires of
Complete Question:
A finch rides on the back of a Galapagos tortoise, which walks
at the stately pace of 0.060 m/s. After 1.5 minutes the finch tires of
the tortoise’s slow pace, and takes flight in the same direction for
another 1.5 minutes at 11 m/s.
What was the average speed of the finch for this 3.0-minute interval?
Answer:
[tex]Speed = 5.53 m/s[/tex]
Explanation:
Distance is calculated as:
[tex]Distance = Speed * Time[/tex]
First, we calculate the distance for the first 1.5 minutes
For the first 1.5 minutes, we have:
[tex]Speed = 0.060m/s[/tex]
[tex]Time = 1.5\ mins[/tex]
[tex]D_2= 0.060m/s * 1.5\ mins[/tex]
Convert 1.5 mins to seconds
[tex]D_2= 0.060m/s * 1.5 * 60s[/tex]
[tex]D_2= 5.4m[/tex]
Next, we calculate the distance for the next 1.5 minutes
[tex]Speed = 11m/s[/tex]
[tex]Time = 1.5\ mins[/tex]
[tex]D_2= 11m/s * 1.5\ mins[/tex]
Convert 1.5 mins to seconds
[tex]D_2 = 11m/s * 1.5 * 60s[/tex]
[tex]D_2= 990m[/tex]
Total distance is:
[tex]Distance = 990m + 5.4m[/tex]
[tex]Distance = 995.4m[/tex]
The average speed for the 3.0 minute interval is:
[tex]Speed = \frac{Distance}{Time}[/tex]
[tex]Speed = \frac{995.4\ m}{3.0\ mins}[/tex]
Convert 3.0 minutes to seconds
[tex]Speed = \frac{995.4\ m}{3.0 * 60 secs}[/tex]
[tex]Speed = \frac{995.4\ m}{180 secs}[/tex]
[tex]Speed = 5.53 m/s[/tex]
Does Newton’s 1st Law of Motion apply to sports
Answer: Yes indeed it does.
Explanation: Newton's Three Laws of Motion explain how forces create motion in sport. These laws are usually referred to as the Laws of Inertia, Acceleration, and Reaction. maybe brainliest to level up.
what are three ways the electricity we use can be generated
C
D
А
E
15
Which letter represents the position at which the basketball has the greatest potential energy? Explain
Which letter represents the position at which the basketball has the greatest potential energy? Explain. Point C. At this point, which is the highest point, all of the ball's energy is gravitational potential energy.
What type of wavelength can we feel as heat and it is used to change the television channel with a remote?
microwaves
ultraviolet waves
X-rays
infrared waves
Answer:
d)infrared waves
Explanation:
A remote control uses light waves just beyond the visible spectrum of light—infrared light waves—to change channels on your TV. This region of the spectrum is divided into near-, mid-, and far-infrared.
newtons first law 1 to 5.
What is each of the net force for all of the 5 questions?
Answer:
1. 65 N.
2. 160 N.
3. 0 N.
4. 210 N.
5. 90 N.
Explanation:
1. Determination of the net force.
Force applied to the right (Fᵣ) = 80 N
Force applied to the left (Fₗ) = 145 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 145 – 80
Fₙ = 65 N
Thus, the net force is 65 N
2. Determination of the net force.
Force 1 applied to the left (F₁) = 35 N
Force 2 applied to the left (F₂) = 125 N
Net force (Fₙ) =?
Fₙ = F₁ + F₂
Fₙ = 35 + 125
Fₙ = 160 N
Thus, the net force is 160 N.
3. Determination of the net force.
Force applied to the right (Fᵣ) = 75 N
Force applied to the left (Fₗ) = 75 N
Net force (Fₙ) =?
Fₙ = Fₗ – Fᵣ
Fₙ = 75 – 75
Fₙ = 0
Thus, the net force is 0 N
4. Determination of the net force.
Force 1 applied to the right (F₁) = 150 N
Force 2 applied to the right (F₂) = 60 N
Net force (Fₙ) =?
Fₙ = F₁ + F₂
Fₙ = 150 + 60
Fₙ = 210 N
Thus, the net force is 210 N.
5. Determination of the net force.
Force applied to the right (Fᵣ) = 115 N
Force applied to the left (Fₗ) = 25 N
Net force (Fₙ) =?
Fₙ = Fᵣ – Fₗ
Fₙ = 115 – 25
Fₙ = 90 N
Thus, the net force is 90 N
Which has more volume a liter of a quart?
1. A quart
2. Both are the same
3. Neither describes volume
4. A liter
The period of a satellite circling planet Nutron is observed to be 84 s when it is in a circular orbit with a radius of 8.0 x 106 m. What is the mass of planet Nutron
Answer:
4.3 * 10^28 kg
Explanation:
Given:
Period, T = 84s
Radius of satellite orbit, r = 8*10^6
Using the relation :
M = 4π²r³ / GT²
Where G = Gravitational constant, 6.67 * 10^-11
M = 4*π^2*(8*10^6)^3 / 6.67 * 10^-11 * 84^2
M = (20218.191872 * 10^18) / 47063.52 * 10^-11
M = 0.4295937 * 10^18 - (-11)
M = 0.4295937 * 10^29
M = 4.295937 * 10^28 kg
M = 4.3 * 10^28 kg
Mass of planet Nutron = 4.3 * 10^28 kg
Small cuts or scratches on your body, which are easier to "repair," lead to very rapid
blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.
True
False
Small cuts or scratches on your body, which are easier to "repair," lead to very rapid
blood clotting; more serious wounds, like a deep gash in your leg, clot more slowly.
TRUE ☜(ﾟヮﾟ☜)
Air in a balloon does 40 J of work expanding the balloon while absorbing 60 J of heat. What is the change in internal energy
Answer:
DU = 20 Joules
Explanation:
Given the following data;
Heat absorbed, Q = 60J
Workdone, W = 40J
To find the internal energy;
We would use first law of thermodynamics given by the formula;
Change in internal energy (DU) = Q - W
where;
U is internal energy.
Q is the heat absorbed.
W is the work done.
Substituting into the equation, we have;
DU = 60 - 40
DU = 20 Joules
explain how electrically neutral objects can become electrically charged even though charge cannot be created or destroyed
Answer:
The object gains or loses electrons to become charged. Both are a movement of electrons from the negative to the positive charge. A circuit has a continuous current provided by a voltage source.
Explanation:
A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volume of the block. Then, use that answer to determine the density of the block. *
Answer:
6g/cm³
Explanation:
Density is the mass per unit volume of any substance. To solve this problem:
Density = [tex]\frac{mass}{volume}[/tex]
Since mass = 600g
Let us find the volume;
Volume = length x width x height
Volume = 25cm x 2cm x 2cm = 100cm³
Therefore;
Density = [tex]\frac{600}{100}[/tex] = 6g/cm³
How does the mass of and distance between the Sun and the Earth impact the number of days in a year?
Answer:
Force of sun on earth can be written:
F = G M m / R^2
Centripetal force on earth can be written:
F= m w^2 R
Equating these:
G M / R^2 = w^2 R
Or w^2 = G (M / R^3)
Since no/ days per year is proportional to w (time for 1 revolution)
Increasing M (mass of sun) would increase w or decrease length of year
Increasing the mean radius R would decrease w or increase length of year
Distinguish between elastic collasin
and inelastic collasin
Explanation:
In an elastic collision, two or more bodies are in contact with one another and there is no net loss of kinetic energy in the system. By the virtue of this, the bodies and objects do not stick together after they collide.
Both momentum and kinetic energy are conserved in an elastic collision. An example is when a football hits a wall.
For an inelastic collision, the bodies sticks together after they collide and there is a loss of kinetic energy after they collide. An example of this type of collision is when a gum is throw against a wall.
How many significant figures are there in each of the following?
(a) 85.8 + 0.9
Answer:
86.7
Explanation:
sana makatulong yung answer ko
Curious George is whirling a 2.0 kg bunch of bananas on a smooth floor in a circular path having a radius of 0.50 m. What force must he apply to keep the motion constant so that the bananas complete one revolution every 4.0 seconds
Answer:
The force will be [tex]F_{c}=2.47 N[/tex]
Explanation:
Let's use the centripetal force equation.
[tex]F_{c}=m\omega ^{2}R[/tex]
Where:
m is the mass of the bunch of bananas
ω is the angular speed
R is the radius
Now, 1 rev every 4 seconds or 0.25 rev/sec is the angular speed, but we need to write this speed in rad per second.
[tex]\omega =0.25\frac{rev}{s}=0.25*2\pi \frac{rad}{s}=1.57 \frac{rad}{s}[/tex]
FInally, the force will be:
[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]
[tex]F_{c}=2.0*1.57^{2}*0.5[/tex]
[tex]F_{c}=2.47 N[/tex]
I hope it helps you!
2. Use the data table below to respond to the
question:
4 seconds
At seconds
Speed (meters per second Im/s]
At 1 second At 2 seconds At 3 seconds
2
+
6
At 4 seconds
8
Car A
0
B
2
Car B
2
2
2
2
4
Car C
3
2
1
0
0
Car D
5
5
5
5
5
5
ant
Which car had the greatest acceleration?
A. A
B. B
C. C С
D. D
Answer:
car d
Explanation:
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