Answer:
1/3 fraction of whole paint is used by mark
Step-by-step explanation:
Mark used 1/2 out of 3/2 cans.
[tex]\frac{1}{2}[/tex] ÷ [tex]\frac{3}{2} = \frac{1}{2}*\frac{2}{3}=\frac{1}{3}[/tex]
HELP PLEASE 50 points !!! Given a polynomial function describe the effects on the Y intercept, region where the graph is increasing and decreasing in the end behavior when the following changes are made make sure to account for even and odd functions
When f(x) becomes -f(x)+ 2
When f(x) becomes f(x+3)
Even function:
A function is said to be even if its graph is symmetric with respect to the , that is:
Odd function:
A function is said to be odd if its graph is symmetric with respect to the origin, that is:
So let's analyze each question for each type of functions using examples of polynomial functions. Thus:
FOR EVEN FUNCTIONS:
1. When becomes
1.1 Effects on the y-intercept
We need to find out the effects on the y-intercept when shifting the function into:
We know that the graph intersects the y-axis when , therefore:
So:
So the y-intercept of is one unit less than the y-intercept of
1.2. Effects on the regions where the graph is increasing and decreasing
Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function increases and decreases in the same intervals of
1.3 The end behavior when the following changes are made.
The function is shifted one unit downward, so each point of has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:
FOR ODD FUNCTIONS:
2. When becomes
2.1 Effects on the y-intercept
In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.
An example is shown in Figure 1. The graph in blue is the function:
and the function in red is:
So you can see that:
2.2. Effects on the regions where the graph is increasing and decreasing
The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of
In Figure 1 you can see that both functions increase at:
and decrease at:
2.3 The end behavior when the following changes are made.
It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.
So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.
FOR EVEN FUNCTIONS:
3. When becomes
3.1 Effects on the y-intercept
We need to find out the effects on the y-intercept when shifting the function into:
As we know, the graph intersects the y-axis when , therefore:
And:
So the new y-intercept is the negative of the previous intercept shifted one unit upward.
3.2. Effects on the regions where the graph is increasing and decreasing
In the intervals when the function increases, the function decreases. On the other hand, in the intervals when the function decreases, the function increases.
3.3 The end behavior when the following changes are made.
Each point of the function has the same x-coordinate just as the function and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:
FOR ODD FUNCTIONS:
4. When becomes
4.1 Effects on the y-intercept
In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.
4.2. Effects on the regions where the graph is increasing and decreasing
In this case it happens the same. So in the intervals when the function increases, the function decreases. On the other hand, in the intervals when the function decreases, the function increases.
4.3 The end behavior when the following changes are made.
Similarly, each point of the function has the same x-coordinate just as the function and the y-coordinate is the negative of the previous coordinate shifted one unit upward.
QUICKLY!! We know that a triangle with side lengths x^2-1,2x and x^2+1 is a right triangle. Using those side lengths, find the missing triples and x-values.
Write the triples in parentheses, without spaces between the numbers, and with a comma between numbers. Write the triples in order from least to greatest.
Type the correct answer in each box.
x value--------------------pythagorean triple
3 ____________
________ (8,15,17)
5 ______________
__________ (12,35,37)
Answer:
[tex]\begin{array}{ccl}x \ value&&Pythagorean \ triple\\3&&(6, 8, 10)\\4&&(8, 15, 17)\\5&&(10, 24, 26)\\6&&(12, 35, 37)\end{array}[/tex]
Step-by-step explanation:
The given side lengths of the right triangle are;
x² - 1, 2·x and x² + 1
A Pythagorean triple are three numbers, a, b, and c, such that, we have;
a² + b² = c²
From the given side lengths, we have;
We note that (x² + 1) > (x² - 1)
(x² + 1) > 2·x for x > 1
Therefore, with (x² + 1) as the hypotenuse side, we have;
(x² - 1)² + (2·x)² = (x² + 1)²
Therefore, when the x-value is 3, we have;
(3² - 1)² + (2 × 3)² = (3² + 1)²
8² + 6² = 10²
The least is 6² = (2 × 3)², from (2·x)²
Therefore;
The Pythagorean triple is 6, 8, 10
The order of the triple is (2·x), (x² - 1), (x² + 1)
2) The x-value for the triple, (8, 15, 17), is obtained as follows;
The least, 8 = 2·x
∴ x = 8/2 = 4
The x-value = 4
3) The Pythagorean triple where the x-value = 5 is therefore;
(2·x), (x² - 1), (x² + 1), where x = 5 gives; (2×5 = 10), (5² - 1 = 24), (5² + 1 = 26)
Therefore, the Pythagorean triple where x = 5 is 10, 24, and 26
4) The x-value for the Pythagorean triple (12, 35, 37) is given by 12 = 2·x
Therefore, x = 12/2 = 6
Therefore, we get;
[tex]\begin{array}{ccl}x \ value&&Pythagorean \ triple\\3&&(6, 8, 10)\\4&&(8, 15, 17)\\5&&(10, 24, 26)\\6&&(12, 35, 37)\end{array}[/tex]
SOMEONE PLEASE HELPPP MEEEE OUTTTT!!!
Answer:
29 av
Step-by-step explanation:
Which ensation strates the Sum Version
12-8-15-12-15-3
1218115-12-13-15)
o 12-8-15-18.15
12-8-15-12-31 15
Answer:
desculpa mas não sei essa
What is the equation of the line written in general form? I need the answer ASAP
Answer:
The answer is 3x-y-2=0
Step-by-step explanation:
Answer:
2nd option
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate the slope using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (1, 1) and (x₂, y₂ ) = (2, 4) ← 2 points on the line
m = [tex]\frac{4-1}{2-1}[/tex] = 3
The line crosses the y- axis at (0, - 2 ) ⇒ c = - 2
y = 3x - 2 ← in slope- intercept form
subtract y from both sides
0 = 3x - y - 2 , that is
3x - y - 2 = 0 ← in general form
Find the distance between the lines with equations 7x-2y-2=0 and y=7/2x-10?
a. 2.47 b. 2.48 c. 2.5 d. 2.49
Answer:
the distance between the lines is 2.48
Which represents the inverse of the function f(x) = 4x?
O
h(x) = x + 4
h(x) = X- 4
h(x)
3,
4
h(x) = =x
Help please !!! At a local Brownsville play production, 420 tickets were sold. The ticket prices varied on the seating
arrangements and cost $8, $10, or $12. The total income from ticket sales reached $3920. If the
combined number of $8 and $10 priced tickets sold was 5 times the number of $12 tickets sold, how
many tickets of each type were sold?
Answer:
n = 12$ x = 8$ y = 10$ where n, x, and y are number of tickets
12 n + 8 x + 10 y = 3920 and n + x + y = 420
12n + 8 (x + y) + 2 y = 3920
12 n + 8 (5 n) + 2 y = 3920 since 5 (x + y) = n
52 n + 2 y = 3920 or y = 1960 - 26 n
Also, n + x + y = 420 or n + 5 n = 420 since x + y = 5 n
n = 70 so 70 of the $12 were sold
And since y = 1960 - 26 n we have y = 140 tickets
Now 12 * 70 + 8 x + 140 * 10 = 3920
This gives x = 210 tickets
Check: 210 + 140 + 70 = 420 tickets
Also, 12 * 70 + 210 * 8 + 140 * 10 = 3920
What value of x is in the solution set of 2x – 3 > 11 – 5x?
• -3
• 0
• 2
• 4
Hello!
2x - 3 > 11 - 5x
2x + 5x > 11 + 3
7x > 11 + 3
7x > 14
x > 14 : 7
x > 2
x = 4 → the solution
Good luck! :)
How many 20 can lengths of a pipe can be cut from a pipe 8.7 m long?
Answer:
(8.7×100)cm=870cm
870cm/20cm=43.5
so 43 20cm can be cut
Can someone help me with this math homework please!
1.f(0) = 6
2.f(4)=5
3.f(-3)=-5
4. V(r) represent volume of basketball when radius is r
5.f(9) =5
Answer:
(3)(3)(1)(2)(1)Step-by-step explanation:
1.
[In the attachment]
2.
again taking 4 as x and 5 as y.
since,
y = f(x)
5 = f(4)
that is option 3.
3.
x = -3
y = -5
y = f(x) = -5
f(-3) = -5
1st option
4.
V(r) = 4/3 pi r³
here the ou.tput is V(r) when the input is r.
and since V(r) denotes volume of air inside the basketball
V(r) is the volume of basketball when the radius is r.
that is option 2.
5.
given that:-
x = 9, f(x) = 5
•°• f(9) = 5
that is the 1st option
does anyone know the domain and range of this?
Answer:
domain=1
range= -2
hope it helps
stay safe healthy and happy.Casey wants to buy a gym membership. One gym has a $150 joining fee and costs $35 per month. Another gym has no joining fee and costs $60 per month. When would Casey pay the same amount to be a member of either gym? How much would he pay?
Answer:
x=6
Step-by-step explanation:
150+35x=60x
-35x -35x
150= 25x
What is the domain of the square root function graphed below
Answer:
Dominio de una Raíz cuadrada
Cuando tenemos una raíz, para estudiar su existencia debemos saber que una raíz existe si y solo sí el radicando (lo que está dentro de la raíz) sea mayor o igual a cero.
Por lo tanto deberemos estudiar el signo de lo que se encuentra dentro de la raíz; y determinar las zonas positivas y las raíces que son las zona de existencia de la función raíz o dominio de esta función.
Step-by-step explanation:
qsy
which of the points lies on the curve y=x^3
Answer:
D
Step-by-step explanation:
Hello,
A: no since (1/3)^3=1/27 not 1/9
B: no since (-1)^3=-1 not 1
C: no since (-2)^3=-8 not -6
D: yes since (-1/2)^3=-1/8
Answser D
Determine the domain and range of the function f(x) = 23/1082
O {x| all real numbers} {yly >0}
O {x} all real numbers}; {yl y 2 0}
O {x\ x >0}; {y| all real numbers}
O {x\ x 2 0}; {yl all real numbers}
Answer:
A
Step-by-step explanation:
The domain is all real numbers and the range is all real numbers greater than zero
The domain is {x| all real numbers} and the range is {y| y > 0}
How to find the domain of a function?
The domain of a function is the set of inputs that we can use in the function. To find it, we initially assume that it is the set of all real numbers, and then remove the problematic values of x.
For example, a problematic point would be a value of x that causes the denominator to be equal to zero.
In this particular case, we can see that the variable is in the exponent, thus it can take any real value and it will not cause any problem, so the domain is the set of all real numbers.
The range is the set of possible outputs. Because in this case, the base is a positive number, the outcomes will only be positive, then the range is given by:
y > 0.
So the correct option is A.
If you want to learn more about range and domain, you can read:
https://brainly.com/question/1770447
Consider the following hypothesis test: : : A sample of provided a sample mean and a sample standard deviation . Enter negative values as negative numbers. a. Compute the value of the test statistic (to three decimal places).
Answer:
-1.540
Step-by-step explanation:
H0 : μ = 18
H0 : μ ≠ 18
The sample size, n = 48
Sample mean, xbar = 17
Sample standard deviation, s = 4.5
α = 0.05
The test statistic :
(xbar - μ) ÷ (s/√(n))
(17 - 18) ÷ (4.5 / √48))
-1 ÷ 0.6495190
= -1.5396
= -1.540 (3 decimal places ).
Be sure to show your work and solve for e:
(264 + 3 x 6) divided by 3 = e
Answer:
94
Step-by-step explanation:
(264+3*6)/3 = e
PEMDAS, so multiplication first.
3*6 = 18
= (264 + 18)/3
= 282/3
= 94
11. What is the value of y when 10y-5=20
Answer:
y = 2.5
Step-by-step explanation:
Given
10y - 5 = 20 ( add 5 to both sides )
10y = 25 ( divide both sides by 10 )
y = 2.5
Answer:
5/2
Step-by-step explanation:
The given equation to us is ,
[tex]\implies 10y -5 = 20 [/tex]
Add 5 both sides ,
[tex]\implies 10y -5 +5 = 20 +5 \\[/tex]
[tex]\implies 10y = 25[/tex]
Divide both sides by 10 ,
[tex]\implies 10y \div 10 = 25\div 10 \\[/tex]
[tex]\implies \boxed{ y = \dfrac{5}{2}}[/tex]
During a month, the average temperature in day time of a placewas 430C. The average temperature during night was recorded to be -30C. Find the difference between the average day temperature and the average night temperature.
Answer:
Difference between average day temperature and average night temperature = 70°
Step-by-step explanation:
Given;
Average day temperature = 43° C
Average night temperature = -30° C
Find:
Difference between average day temperature and average night temperature
Computation:
Difference between average day temperature and average night temperature = Average day temperature - Average night temperature
Difference between average day temperature and average night temperature = 43 - (-30)
Difference between average day temperature and average night temperature = 70°
help asap please ----------------
Answer:
-1 Not in domain
0 In domain
1 In domain
Step-by-step explanation:
The domain for the square root function is all positive numbers including (0). The domain is the set of real numbers which when substituted into the function will produce a real result. While one can substitute a negative number into the square root function and get a result, however, the result will be imaginary. Therefore, the domain for the square root function is all positive numbers. It can simply be expressed with the following inequality:
[tex]x\geq0[/tex]
Therefore, one can state the following about the given numbers. Evaluate if the number is greater than or equal to zero, if it is, then it is a part of the domain;
-1 => less than zero; Not in domain
0 => equal to zero; In domain
1 => greater than zero: In domain
find the compound interest on rs 800 for 2 years at 8% per annum interest being payable annually
Answer:
Rs 968
Step-by-step explanation:
Given :-
P = Rs 800 Rate = 8% Time = 2 yrs .To Find :-
Compound Interest .Solution :-
We know CI as ,
> CI = P ( 1 + R/100)ⁿ
> CI = Rs 800 ( 1 + 10/100)²
> CI = Rs 800 × 11/10 × 11/10
> CI = Rs 968 .
Solve the inequality:
[tex]4x+3\ \textgreater \ 19[/tex]
Answer:
x > 4
Step-by-step explanation:
4x + 3 > 19
4x + 3 - 3 > 19 - 3
4x > 16
4x/4 > 16/4
x > 4
Hope this helps.
[tex]4x + 3 > 19 \\ = > 4x > 19 - 3 \\ = > 4x > 16 \\ = > x > \frac{16}{4} \\ = > x > 4[/tex]
Answer:
x > 4
Hope you could understand.
If you have any query, feel free to ask.
One number exceeds another number by 6. One fourth of the sum of the two numbers is two less than the smaller.
Find the numbers.
Answer:
7 and 13
Step-by-step explanation:
let the 2 numbers be x and y , x > y , then
x = y + 6 → (1)
[tex]\frac{1}{4}[/tex] (x + y) = y - 2 ( multiply both sides by 4 to clear the fraction )
x + y = 4y - 8 ( subtract 4y from both sides )
x - 3y = - 8 → (2)
Substitute x = y + 6 into (2)
y + 6 - 3y = - 8
- 2y + 6 = - 8 ( subtract 6 from both sides )
- 2y = - 14 ( divide both sides by - 2 )
y = 7
Substitute y = 7 into (1)
x = 7 + 6 = 13
The 2 numbers are 7 and 13
Tess rolls 2 fair dice.
What is the probability of obtaining two 4's?
Answer:
1/36
Step-by-step explanation:
Since Tess rolled 2 different dices, there are 36 different possibilities. Rolling two 4's is 1 of them.
Therefore, the probability of Tess rolling 2 fair dice is 1/36
Hope this helped have a great rest of your day!
Answer:
1 out of 36 chance because add what a dice equals to then divide
Rewrite the expression using rational exponents .
Answer:
Step-by-step explanation:
[tex]\sqrt[5]{(3y)^{4}} = [(3y)^{4}]^{\frac{1}{5}}=(3y)^{4*\frac{1}{5}}=(3y)^{\frac{4}{5}}[/tex]
use the figure at the right the complete inequality statements
A rectangular price tag has a perimeter of 10 centimeters and an area of 6 square centimeters. What are the dimensions of the price tag?
Answer:
3 by 2
Step-by-step explanation:
3+2+3+2=10
3*2=6
Hope this Helps!!!
Solve the equation : 4x-(-2)=18
[tex]\large\boxed{ \sf{Answer}} [/tex]
[tex]4x - ( - 2) = 18 \\ 4x + 2 = 18 \\ 4x = 18 - 2 \\ 4x = 16 \\ x = \frac{16}{4} \\ x = 4[/tex]
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
Step-by-step explanation:
4x-1-2=18
4x+2=18
4x=18-2
4x=16
x=16/4
x=4
Help me please correct answers only
Answer:
well your answer should be "F"
Step-by-step explanation:
we have
Y<-2x+10 -----> inequality A
The solution of the inequality A is the shaded area below the dashed line
Y = -2x+10
The y-intercept of the dashed line is (0,10)
The x-intercept of the dashed line is (5,0)
Y<1/2x-2 ----> inequality B
The solution of the inequality B is the shaded area below the dashed line
Y= 1/2x-2
The y-intercept of the dashed line is (0,-2)
The x-intercept of the dashed line is (4,0)
The solution of the system of inequalities is the shaded area between the two dashed lines
Remember that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must lie on the shaded area of the solution
therefore
The solution are the points
E, F and G
i hope this helps