Link BD consists of a single bar 36 mm wide and 18 mm thick. Knowing that each pin has a 12-mm diameter, determine the maximum value of the average normal stress in link BD if (a) θ 5 0, (b) θ 5 90°.
Answers
Answer:
hello the diagram attached to your question is missing attached below is the missing diagram
answer :
a) 48.11 MPa
b) - 55.55 MPa
Explanation:
First we consider the equilibrium moments about point A
∑ Ma = 0
( Fbd * 300cos30° ) + ( 24sin∅ * 450cos30° ) - ( 24cos∅ * 450sin30° ) = 0
therefore ; Fbd = 36 ( cos ∅tan30° - sin∅ ) kN ----- ( 1 )
A ) when ∅ = 0
Fbd = 20.7846 kN
link BD will be under tension when ∅ = 0, hence we will calculate the loading area using this equation
A = ( b - d ) t
b = 12 mm
d = 36 mm
t = 18
therefore loading area ( A ) = 432 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd = [tex]\frac{Fbd}{A}[/tex] = 20.7846 kN / 432 mm^2 = 48.11 MPa
b) when ∅ = 90°
Fbd = -36 kN
the negativity indicate that the loading direction is in contrast to the assumed direction of loading
There is compression in link BD
next we have to calculate the loading area using this equation ;
A = b * t
b = 36mm
t = 18mm
hence loading area = 36 * 18 = 648 mm^2
determine the maximum value of average normal stress in link BD using the relation below
бbd = [tex]\frac{Fbd}{A}[/tex] = -36 kN / 648mm^2 = -55.55 MPa
The maximum value of the average normal stress in link BD at the given angles are;
At θ = 0°; 64.15 MPa
At θ = 90°; 66.66 MPa
Average Normal Stress
The image of the link and the single bar is missing and so i have attached it.
From the image of the link and single bar attached, i have drawn a free body diagram of link ABC that will help us to solve this question.
Taking Moments about point A and summing to zero, we can solve for F_bd at the given angles as;
A) At θ = 0°;
From the diagram, AC = 450 mm = 0.45 m and force acting at point C is 24 kN or 24000 N. Thus;
(0.45 * sin 30)(24000) - F_bd(0.3 * cos 30) = 0
Thus;
(0.45 * sin 30)(24000) = F_bd(0.3 * cos 30)
⇒ 5400 = 0.2598F_bd
F_bd = 5400/0.2598
F_bd = 20785.22 N
Area at tension Loading is;
A = (0.03 - 0.012)0.018
A = 324 × 10⁻⁶ m²
Thus;
Average Normal stress is;
σ = 20785.22/(324 × 10⁻⁶)
σ = 64.15 × 10⁶ Pa = 64.15 MPa
B) At θ = 90°;
(0.45 * cos 30)(24000) + F_bd(0.3 * cos 30) = 0
Thus;
-(0.45 * cos 30)(24000) = F_bd(0.3 * cos 30)
F_bd = -36000 N
Area at compression Loading is;
A = 0.03 * 0.018
A = 540 × 10⁻⁶ m²
Thus;
Average Normal stress is;
σ = -36000/(540 × 10⁻⁶)
σ = 66.66 × 10⁶ Pa = 66.66 MPa
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Related Questions
For a 55 wt% Pb–45 wt% Mg alloy slowly cooled from 700°C to 300°C, at what temperature does the first solid phase form?
Answers
Answer:
hello your question is incomplete attached below is the complete question
answer : 550°c
Explanation:
From the phase diagram attached we can see that at point between 500° and 600° i.e.550°c on the phase diagram the first solid phase was form when a 55 wt% Pb-45 wt% Mg alloy slowly cools down from 700 to 300°c
Calculate the radius of a vanadium atom, given that it has a BCC crystal structure, density of 5.96 g/cm3, and an atomic weight of 50.9 g/mol (Max. pts. 5).
Answers
Answer:
The answer is "[tex]\bold{1.32 \times 10^{-3} \ cm}[/tex]".
Explanation:
All of the atoms in a BCC crystalline structure are contained in the 8-corner unit cell.
Each corner connects the atom to a single cell [tex]\frac{1}{8}[/tex]
Therefore, the unit cell number of atoms:
[tex]= 8 \times \frac{1}{8}+ 1 \\\\= 1+1 \\\\= 2 \ atom[/tex]
[tex]The mass unit cell = \frac{ \text{Number of atoms} \times \text{atomic weight}} {Avagadro number}\\\\= \frac{2 \times 50.9}{6.023 \times 10^{23}} \\\\= 1.69 \times 10^{-22} \ g\\\\Area Of the atom= \frac{4r}{\sqrt{3}}\\\\ 5.96 = \frac{1.69 \times 10^{-22}}{volume}\\\\volume= 2.835 \times 10^{25}\\\\v=d^3\\\\v= (\frac{4r}{\sqrt{3}})^3\\\\\to 2.835 \times 10^{-23} \times (\sqrt{3})^3 = 4^3 r^3[/tex]
[tex]\to \sqrt[3]{\frac{{2.835 \times 10^{-23} \times (\sqrt{3})^3}}{4^3}} =r\\\\\to r= 1.32 \times 10^{-3} \ cm[/tex]
The shape of the wood beam is a rectangle. In a paragraph explain the tradeoffs an engineer would make in selecting a wood with a rectangle shape versus manufactured beams with other stronger but lighter weight shapes.
Answers
Answer:
Wood is heavy
Explanation:
What are the prefixes for 1, 10, 1000, 1,000,000, .1, .01, .001, .000001
Answers
Prefix Symbol Multiplier Exponential
yotta Y 1,000,000,000,000,000,000,000,000 1024
zetta Z 1,000,000,000,000,000,000,000 1021
exa E 1,000,000,000,000,000,000 1018
peta P 1,000,000,000,000,000 1015
tera T 1,000,000,000,000 1012
giga G 1,000,000,000 109
mega M 1,000,000 106
kilo k 1,000 103
hecto h 100 102
deca da 10 101
1 100
deci d 0.1 10¯1
centi c 0.01 10¯2
milli m 0.001 10¯3
micro µ 0.000001 10¯6
nano n 0.000000001 10¯9
pico p 0.000000000001 10¯12
femto f 0.000000000000001 10¯15
atto a 0.000000000000000001 10¯18
zepto z 0.000000000000000000001 10¯21
yocto y 0.000000000000000000000001 10¯24
For RTK to work, what do we need besides two or more receivers collecting data from a sufficient number of satellites simultaneously?
Answers
Answer:
phase measurement and the information content
Explanation:
The full form of RTK is Real Time Kinematic. It is used for satellite navigation technique to increase the precision of the position data that is derived from the positioning systems based on satellites like the NavIC, GPS, Galileo, BeiDou and GLONASS. It takes help of the measurements of phase of signal's carrier wave and also the information content of these signals and it also relies on the single interpolated virtual station in order to provide the real time corrections and provide correct and accurate information.
what is the correct answer A, B, C, D
will give 35 points and brainiest
Which of the following devices is used to determine if an item is horizontal?
A. a level
B. a lever
C. a shank
D. a clamp
Answers
Answer:
B a lever because it can move up and down
Explanation:
A series resistive circuit has two resistors. R1 is 570 ohms and R2 is 560 ohms.
The total circuit current is 17.9 milliamps.
Find the voltage drop across R1 in volts.
Answers
Answer:
10.203 Volts
Explanation:
For this problem, we need to understand that a series resistive circuit is simply a circuit with some type of voltage source and some resistors, in this case, R1 and R2.
First, we need to find the voltage in the circuit. To do this, we need to find the total resistance of the circuit. When two resistors are in series, you sum the resistance. So we can say the following:
R_Total = R1 + R2
R_Total = 570 Ω + 560 Ω
R_Total = 1130 Ω
Now that we have R_Total for the circuit, we can find the voltage of the circuit by using Ohm's law, V = IR.
V_Total = I_Total * R_Total
V_Total = 17.9 mA * 1130 Ω
V_Total = 20.227 V
Now that we have V_Total, we can find the voltage drop across each resistor by using Ohm's law once more. Note, that since our circuit is series, both resistors will have the same current (I.e., I_Total = I_1 = I_2).
V_Total = V_1 + V_2
V_Total = V_1 + I_2*R2
V_Total - I_2*R2 = V_1
20.227 V - (17.9 mA * 560 Ω) = V_1
20.227 V - (10.024 V) = V_1
10.203 V = V_1
Hence, the voltage drop across R1 is 10.203 Volts.
Cheers.
List the three main phases of photo interpretation in photogrammetry
Answers
Answer:
Stages of Interpretation and Mapping
Selection of photographs. Whenever possible, all photographs of a site or small area should be assessed for fitness of purpose. ...
Control points. A good spread of control points on a photograph is vital to establish the exact location or size of features. ...
Transformation.
Explanation:
how do the brushes control the amount of charging an alternator does
Answers
Explanation:
Think of brushes as a sliding contact.
In an alternator the brushes provide power to the field coil which is physically mounted on the rotating shaft. They provide this direct current through two slip rings.
By controlling the power flow to the field, the power output of the alternator can be controlled. A regulator circuit is used to control the field so that the output voltage is maintained to about 13.5 to 14.5 VDC.
FUN FACT: Many brush holders have a small holes near the brush exit. When you assemble the alternator you physically push the brushes all the way into their holder and then thread a small wire through these hole. After the alternator is assembled you can pull the wire out and the brushes will snap into position.
30 points and brainiest if correct please help A, B, C, D
Which of the following describes the purpose of the button on the housing of a tape measure?
A. to measure right angles
B. to lock the tape into place
C. to hold a measuring pencil
D. to help wind the tape by hand
Answers
Answer:
B. to lock the tape into place
Explanation:
the button on the front of the housing locks the tape into place when pressed, preventing the tape from being pulled out further it retracting
Cody’s car accelerates from 0m/s to 45 m/s northward in 15 seconds. What is the acceleration of the car

Answers
Answer:
3 m/s²
Explanation:
Acceleration is calculated as :
a= Δv/ t
where ;
Δv = change in velocity
Δv = 45 - 0 = 45 m/s
t= 15 s
a= 45 /15
a= 3 m/s²
What is different about residential construction on the local level from residential construction on the national level?
Answers
Answer:
The difference lies in the coverage of the construction. While local level construction focuses on the local area, national level construction has a nation-wide coverage.
Explanation:
Residential construction concentrates on the construction of residential buildings that have sleeping accommodations. Such constructions are opposed to the construction of other buildings that are meant for commercial uses as they lack sleeping accommodations. The federal, state, and local governments can embark on the construction of residential quarters for their residents. The constructions are also funded at the given level. When it is locally funded, the construction is meant to satisfy specific local needs. The constructions by the federal government consider the needs of many localities, and may not meet specific local needs.
Answer: A Residential construction is local in its effects even though those effects have a national impact.
Explanation:
Determine the brake horsepower required by a pump for a discharge of 0.2 m3/s and a total dynamic head of 20m, with an efficiency of 80%.
Answers
Answer:
The BHP would be "65.659 HP".
Explanation:
The given values are:
Discharge,
Q = 0.2 m³/s
Dynamic head,
H = 20 m
Efficiency,
% = 80%
Now,
The Power will be:
⇒ [tex]P=\delta QH[/tex]
On substituting the values, we get
⇒ [tex]=1000\times 9.81\times 0.2\times 20[/tex]
⇒ [tex]=39240 \ W[/tex]
The brake horse power will be:
⇒ [tex]BHP=\frac{100 Q H}{3960n}[/tex]
On putting values, we get
⇒ [tex]=\frac{100\times 0.2\times 20}{3960\times 0.80}[/tex]
⇒ [tex]=65.659 \ HP[/tex]
What are the numbers for the coil connection of the LB2 relay?
Answers
Answer:
85 and 86 are the coil pins while 30, 87, and 87a are the switch pins. 87 and 87a are the two contacts to which 30 will connect. If the coil is not activated, 30 will always be connected to 87a. Think of this as the relay in the Normally Closed (OFF) position.
Explanation:
Once you have chosen a topic, what should you do before beginning the research process? a. Find as many possible facts and details on your topic c. Discuss your idea with others b. Choose a position d. None of these Please select the best answer from the choices provided A B C D
Answers
Answer:
The answer is C
Explanation:
Once you have chosen a topic, the next thing you should do before beginning the research process is: C. discuss your idea with others.
What is a research topic?A research topic refers to an event, issue, or subject that a researcher is keenly and deeply motivated or interested in, especially when conducting a study or research.
Based on scientific information and records, it is very important you discuss your idea with others once you have chosen a topic, before beginning the research process.
Read more on research topic here: https://brainly.com/question/24590700
#SPJ2
35 points and brainiest is it A, B, C, D
Which of the following nails would most likely be used in securing a delicate, decorative piece of thin wood trim to a cabinet face?
A. 2d
B. 10d
C. 60d
D. 100d
Answers
Answer:
c thereeeeeeeeeeeeeeeeee
The current through a 0.1 Henrys (H) inductor is i(t) = 10 t e^-5tA. Find the voltage across the inductor.
a. v(t) = 10 te^-5t V
b. v(t) = 0.1 (10te^-5t) V
c. v(t) = 5te^-5t V
d. v(t) = (1 - 5t) e^-5t V
Answers
Answer: d. [tex]v(t)=(1-5t)e^{-5t}[/tex]V
Explanation: Inductance is a property of an inductor: when there is a change in current passing through a conductor, it creates a voltage in the conductor itself and in the other conductors. Inductance unit is Ω.s or henry (H)
So, the relation between Voltage and Current in an inductor is given by
[tex]v=L\frac{di}{dt}[/tex]
in which
L is inductance in H
i is current in A
Current is [tex]i(t)=10te^{-5t}[/tex], so, derivative will be:
[tex]\frac{di}{dt}=10e^{-5t}+10t(-5)e^{-5t}[/tex]
[tex]\frac{di}{dt}=10e^{-5t}-50te^{-5t}[/tex]
[tex]\frac{di}{dt}=10e^{-5t}(1-5t)[/tex]
Then, voltage is
[tex]v=0.1.10.e^{-5t}(1-5t)[/tex]
[tex]v=(1-5t)e^{-5t}[/tex]
Voltage across the 0.1H inductor is [tex](1-5t)e^{-5t}[/tex] V
Refrigerant-134a enters an adiabatic compressor as saturated vapor at 160 kPa at a rate of 2.4 m3/min and is compressed to a pressure of 900 kPa. Determine the minimum power that must be supplied to the compressor. Use the tables for R-134a
Answers
Answer:
11.65kWExplanation:
Step one:
given data
from the table for R-134a
For the given pressure state the following data were extracted.
s=0.94202kJ/kg.K
h1=241.14kJ/kg
∝1=0.12355m^3/kg
By interpolation, the final enthalpy and pressure with data from the table of R-134a
h2=277.12kJ/kg
The minimum power output is then determined from the energy balance
W=m(h2-h1)
W=V1/∝1(h2-h1)
W=2.4/60/0.12355(277.12-241.14)
W=0.04/0.12355(35.98)
W=0.3237(35.98)
W=11.65kW Approx.
The minimum power output of the compressor is 11.65kW
A steam power plant with a power output of 230 MW consumes coal at a rate of 60 tons/h. If the heating value of the coal is 30,000 kJ/kg, determine the overall efficiency of this plant.
Answers
Answer:
[tex]\eta =46\%[/tex]
Explanation:
Hello!
In this case, we compute the heat output from coal, given its heating value and the mass flow:
[tex]Q_H=60\frac{tons}{h}*\frac{1000kg}{1ton}*\frac{1h}{3600s}*\frac{30,000kJ}{kg}\\\\Q_H=500,000\frac{kJ}{s}*\frac{1MJ}{1000J} =500MW[/tex]
Next, since the work done by the power plant is 230 MW, we compute the efficiency as shown below:
[tex]\eta =\frac{230MW}{500MW}*100\% \\\\\eta =46\%[/tex]
Best regards!
35 points an brainiest if correct
Which of the following nails would most likely be used in securing a delicate, decorative piece of thin wood trim to a cabinet face?
2d
10d
60d
100d
Answers
If the cuvet is dirty (caused by fingerprints, water spots, or lint), what effect does it have on the absorbance of the sample?
Answers
When we talk of cuvette,we are talking about the instrument we use to hold the solutions that we make use of in the calorimetry experiment and so we will take a measurement of the volume of the solution,if there is some water and other impurities present,we will go ahead to take a measurement of the more volume, however,if some water or other impurities are there,will go ahead and take a measurement of the more volume and now,it will be less of the actual content as a result of some amount of water or impurity in it.
When Concentration = Mass/Volume
A higher volume will be taken, then assumption of mass can be made to be the same because the water or the impurity will as well have mass and as we are taking the mass long also with the mass of the sample when doing this.
Therefore,the concentration will be less.
simple Brayton cycle using air as the working fluid has a pressure ratio of 10. The minimum and maximum temperatures in the cycle are 295 and 1240 K. Assuming an isentropic efficiency of 83 percent for the compressor and 87 percent for the turbine, determine (a) the air temperature at the turbine exit, (b) the net work output, and (c) the thermal efficiency.
Answers
Answer:
a) 764.45K
b) 210.48 kJ/kg
c) 30.14%
Explanation:
pressure ratio = 10
minimum temperature = 295 k
maximum temperature = 1240 k
isentropic efficiency for compressor = 83%
Isentropic efficiency for turbine = 87%
a) Air temperature at turbine exit
we can achieve this by interpolating for enthalpy
h4 = 783.05 kJ/kg ( calculated in the background ) at state 4 using Table A-17 for Ideal gas properties of air
T4 ( temperature at Turbine exit ) = 760 + ( 780 - 760 ) [tex](\frac{783.05-778.18}{800.13-778.18} )[/tex] = 764.45K
b) The net work output
first we determine the actual work input to compressor
Wc = h2 - h1 ( calculated values )
= 626.57 - 295.17 = 331.4 kJ/kg
next determine the actual work done by Turbine
Wt = h3 - h4 ( calculated values )
= 1324.93 - 783.05 = 541.88 kJ/kg
finally determine the network output of the cycle
Wnet = Wt - Wc
= 541.88 - 331.4 = 210.48 kJ/kg
c) determine thermal efficiency
лth = Wnet / qin ------ ( 1 )
where ; qin = h3 - h2
equation 1 becomes
лth = Wnet / ( h3 - h2 )
= 210.48 / ( 1324.93 - 626.57 )
= 0.3014 = 30.14%
35 points and brainiest. A, B, C, D
Which of the following identifies what carbide-tipped bits, lines on machine bolts, and lock washers all have in common?
A. All are very expensive items.
B. All are very recent inventions.
C. All are rather outdated inventions.
D. All provide an added level of strength.
Answers
Answer:c
Explanation:
Water at 70 kPa and 1008C is compressed isentropically in a closed system to 4 MPa. Determine the final temperature of the water and the work required, in kJ/kg, for this compression.
Answers
Answer:
The answer is "909.3928 KJ".
Explanation:
[tex]70 \ kPa \ \ and \ \ 100^{\circ}C \\\\s_i= 7.56162\ \frac{kJ}{kgK}\\\\u_i= 2509.39 \ \frac{kJ}{kg}\\\\[/tex]
The method is isentropic since the cylinders are shielded.
Calculating the work:
[tex]w= u_2-u_i \\\\[/tex]
[tex]= 3418.7728-2509.38 \\\\=909.3928 \ KJ[/tex]
The final temperature of the water is 676.164 °C and the specific work required is 1171.384 kilojoules per kilogram.
Let suppose that compression occurs quasi-statically, work is done on the closed system and enthalpy is increased. By First Law of Thermodynamics, we model compression process as following:
[tex]W_{in} + (U_{1} - U_{2}) + (P_{1}\cdot V_{1} - P_{2}\cdot V_{2}) = 0[/tex] (1)
Where:
[tex]W_{in}[/tex] - Compression work, in kilojoules. [tex]U_{1}[/tex], [tex]U_{2}[/tex] - Initial and final internal energies of the system, in kilojoules.[tex]P_{1}[/tex], [tex]P_{2}[/tex] - Initial and final pressures of the system, in kilopascals.[tex]V_{1}[/tex], [tex]V_{2}[/tex] - Initial and final volumes of the system, in cubic meters.By definition of enthalpy, in kilojoules per kilogram, and by dividing the resulting expression by the mass of the entire system, we have the following expression:
[tex]w_{in} = h_{2}-h_{1}[/tex] (2)
Where:
[tex]w_{in}[/tex] - Specific compression work, in kilojoules per kilogram.[tex]h_{1}[/tex], [tex]h_{2}[/tex] - Initial and final specific enthalpies, in kilojoules per kilogram.From steam tables we find that initial and final states of the water are represented by the following data:
Initial state
[tex]P = 70\,kPa[/tex], [tex]T = 100\,^{\circ}C[/tex], [tex]h = 2679.76\,\frac{kJ}{kg}[/tex], [tex]s = 7.56162\,\frac{kJ}{kg\cdot K}[/tex] (Superheated steam)
Final state
[tex]P = 4000\,kPa[/tex], [tex]T = 676.164\,^{\circ}C[/tex], [tex]h = 3851.144\,\frac{kJ}{kg}[/tex], [tex]s = 7.56162\,\frac{kJ}{kg}[/tex] (Superheated steam)
By (1) we have that the specific work required is:
[tex]w_{in} = 3851.144\,\frac{kJ}{kg} - 2679.76\,\frac{kJ}{kg}[/tex]
[tex]w_{in} = 1171.384\,\frac{kJ}{kg}[/tex]
The final temperature of the water is 676.164 °C and the specific work required is 1171.384 kilojoules per kilogram.
To learn more on closed systems, we kindly invite to check this verified question: https://brainly.com/question/3690180
four subjects civil engineers need to study
Answers
Answer:
A civil engineering degree program applies mathematics and physical science to solve specific, real-world problems in commerce and industry. A strong civil engineering program typically emphasizes the practical use of geometry, trigonometry, and calculus in conjunction with physics, material science, and chemistry.
Explanation:
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Tahir travel twice as far as ahmed, but onley one third as fast. Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm. Tahir starts travel same day after 3hr of ahmed. In which time tahir reach at point z?
Answers
Answer:
6:00 pm the next day
Explanation:
Given that
Tahir traveled twice as far as Ahmed. We say,
Ahmed traveled a distance, D
Tahir would travel a distan, 2D
Tahir traveled 1/3 as fast as Ahmed, so we say
Ahmed traveled at a speed, S
Tahir would travel at a speed, S/3
If Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm,
Time taken by Ahmed to travel is
9:00 pm - 12:00 pm = 9 hours
Ahmed, traveled 300 km in 9 hours, meaning he traveled at 33.3 km in an hour.
Speed, S that Ahmed traveled with is 33.3 km/h
Remember, we stated that Tahir travels at a speed of S/3, that is, The speed of Tahir is
33.3/3 = 11.1 km/h.
300 km would then be traveled in 300 km/11.1 km/h = 27 hours.
Tahir started traveling, 3 hours after Ahmed, that is 12:00 pm + 3:00 hrs = 3:00 pm, and if he's to spend 27 hours on the journey he would reach destination z at 6:00 pm the next day
A solid cylinder of diameter 100 mm and height 50 mm is forged between two frictionless flat dies to a height of 25 mm. What is the percentage change in diameter?
a. 0
b. 2.07
c. 20.7
d. 41.4
Answers
Answer:
d. 41.4
Explanation:
The initial diameter di = 100mm
The initial height hi {✓59m
Final height = 25 m
Final diameter = ?
Initial volume = after forging volume
D*(di)²*hi = D *(df)²*hf
D will cancel out from either sides of the equation
100² x 50 = df²x25
10000x2 = df²
20000 = df²
df = √20000
df = 141.42mm
Change in diameter = 141.42-100
= 41.42
The percentage change = 41.42/100*100
= 41.4%
The last option is the answer
A rod with a length of L has to be made to carry load F. You need to select from the following alloys: Material Density g/cc Yield Strength, MPa AI 7075 2.81 503 AISI 4340/SAE 7.85 1160 Mg-ZK61 1.83 195 Ti8Al1Mo1V 4.37 570 Which one will have the lightest weight
Answers
Answer:
AI 7075
Explanation:
Material Density g/cc Yield strength
AI 7075 2.81 503
AISI 4340/SAE 7.85 1160
Mg-ZK61 1.83 195
Ti8A|1Mo1V 4.37 570
Determine the alloy with the lightest weight using this relationship
weight ∝ ( S / E )
E = yield strength
S = density
for AI 7075 = 2.81 / 503 = 0.00558648for AISI 4340/SAE = 7.85 / 1160 = 0.00676724for Mg-ZK61 = 1.83 / 195 = 0.00938462for Ti8A|1Mo1V = 4.37 / 570 = 0.00766667from the above calculation the alloy with the lightest weight is ;
AI 7075
I can't log in even though it says all ages are accepted.Instead when I TRY logging in it says this. "We're sorry, but we are not able to complete your registration at this time". And I have tried refreshing the page and and X-ing out of the tab and restarting my computer and it doesn't work! And I know people aren't that crazy to get a account for brainly. Please help me out I really need a answer.
Answers
Answer:
Explanation:
This is not a question so to say. This is more like a complaint about how the platform works. Are you needing help with solving a personal problem or having troubles with the platform in itself
A segment of a roadway has a free flow speed of 45 mph and a jam density of 25 ft per vehicle. Determine the maximum flow and at a flow rate of 1950 vph
Answers
Answer:
2376 vph
Explanation:
Given data
free flow speed ( Vf ) = 45 mph
Jam density = 25 ft per vehicle
flow rate = 1950 vph
first we calculate the Jam density in vehicle /mile
= 5280 / 25 = 211.2 vehicle/mile
where ; 1 mile = 5280 feet
The maximum flow can be calculated using Greenshield method
q = ( Vf * jam density ) / 4 = ( 45 * 211.2 ) / 4
= 2376 vph