Lee watches TV for 4 hours per day. During that time, the TV consumes 150 watts per hour. Electricity costs (10 cents)/(1 kilowatt-hour). How much does Lee's TV cost to operate for a month of 30 days?

Answer:

possibly (9, 9) (9, 5) (5, 9)

The computation of the percentage shows that the kilograms of seed that won't be watered is 12 kilograms.

Your information is incomplete. Therefore an overview will be given. Let's assume that the watered squares are 35 while the total squares are 50.

Then, the percentage of the watered squares will be:

= 35/50 × 100

= 70%

Therefore, the percentage of the unwatered squares will be:

= 100% - 70%

= 30%

Then, the kilograms of the seed that won't be watered will be:

= Percentage of unwatered seed × Entire kilograms of seed

= 30% × 40kg

= 12kg

In conclusion, the seed that won't be watered is 12 kg.

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Answer:

I believe he sells each bar for .75 cents

Answer:

54

Step-by-step explanation:

Multiply:

37x37=72

Subtract:

180-72=108

Divide:

108/2=54

Answer:

143 degrees

Step-by-step explanation:

37(2) + 2x = 360
74 + 2x = 360
2x = 286

x = 143

Hope this helps :)

Answer:

It states they ran the same speed in the first race so that means only the distance they ran would be different. Thus that means Brady only ran 95 meters instead of 100 meters. If Brady was put 5 meters back that means it will be a tie if they ran at the same speed the entire race.

Step-by-step explanation:

Have a great rest of your day
#TheWizzer

It would be a tie. Brady is 5 meters faster then Quinn. So if Brady were to stay behind 5 meters and they ran the same speed as they did before, then it would be a tie.

Answer:

6

Step-by-step explanation:

52+52=104
104/7=14.8

7*14=98
104-98=6

Answer:

Area of triangle = 1/2 of base × height

Area of triangle = 1/12 of 12×17

Area of triangle = 102m²

It is a tool as it represents the language of patterns.

It is also a means of working with abstract notions and then applying them, which frequently leads to the formation of generalisations and insights outside of the original context.

Answer:

To find the volume of a rectangular prism, multiply the length, width, and height. The unit for measuring the volume of a rectangular prism is cubic units, i.e., cm3, mm3, in3, m3, etc.

Step-by-step explanation:

hope it helps

Answer:

  5

Step-by-step explanation:

If x is the middle number of the 5 consecutive odd numbers, their product is ...

  x(x -2)(x +2)(x -4)(x +4) = x(x² -4)(x² -16)  = x⁵ -20x³ +64x

The first 3-digit prime is 101, so the product of that with this is ...

  101(x⁵ -20x³ +64x) = 101x⁵ -2020x³ +6464x

Since we're only interested in the units digit, we can find the mod 10 value of this to be ...

  (x⁵ +4x) mod 10

Possible units digits of x are 1, 3, 5, 7, 9, so possible units digits of this product are ...

  x(x⁴ +4) = 1(1⁴ +4) = 5

  3(3⁴ +4) = 3(1 +4) = 5 . . . . mod 10

  5(5⁴ +4) = 5(5 +4) = 5 . . . . mod 10

  7(7⁴ +4) = 7(1 +4) = 5 . . . . mod 10

  9(9⁴ +4) = 9(1 +4) = 5 . . . . mod 10

In every case, the units digit of 101z will be 5.

Answer:

80 degrees

Step-by-step explanation:

This is a really confusing question with a really confusing answer. Basically, the 80 degree angle that they give us (Angle 2, I think) is equivalent to Angle 4, Angle 5, and Angle 3. I know that might seem really weird, but if you look closely at all the angles I just named, they all look like they are about the same measure. They are all slightly less than a right angle (90 degrees) and none of them are obtuse angles- they're all acute. Basically, the answer is 80.

And if I'm wrong, I am so sorry! I still sometimes get confused on these type of questions. Well, I hope its right and I hope that if it is, it was helpful! Have a lovely day!! :)

The next two times at which the hands of the clock will be perpendicular are at 1:20 and at 1:50.

The two hands will be perpendicular when the angle between them is 90°. Remember that every 5 minutes that the minute clock moves, there is an angle of 30°.

Each hour that the hour hand moves, there is an angle of 30°.

The first time that we will have an angle of 90° between the hands is at:

1:20

Because the minute hand is at an angle of -30° with respect to the x-axis at 20 minutes, and the hour hand is at an angle of 60° at 01.

The next time will be when the minute clock moves another 30 minutes (half the circle) and this will be at 01:50.

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Answer:

[tex]\displaystyle \frac{7}{37}[/tex]

Step-by-step explanation:

[tex]\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-49 + 35}{-56 - 18} = m \hookrightarrow \frac{-14}{-74} = m \\ \\ \boxed{\frac{7}{37} = m}[/tex]

I am joyous to assist you at any time.

Step-by-step explanation:

(−3/4b^2)(−6a^2b^5)

= 9 a²b³

Answer:

48.56

Step-by-step explanation:

We have to multiply 24.28x2 because there are 2 people so if we multiply it we will get the answer 48.56.

Step-by-step explanation:

only the circle

as cylinder is neither oval nor triangle not a rectangle..

so cylinder has circle as the cross section

Answer:

This is for a different question but hope this helps too!

Step-by-step explanation:

Answer:

19000

Step-by-step explanation:

1 hour = 50 miles

2 hour = 100 miles

50×380 = 19000

Answer:

One bucket of popcorn:  6$

One box of candy: $3.75

2 buckets of popcorn:  $12

3 boxes of candy:  $11.25

2 buckets of popcorn and 3 boxes of candy:  $23.25

Step-by-step explanation:

We can find the cost of one bucket of popcorn and one box of candy using a system of equations

[tex]4P + 6C=46.50\\P + C =9.75[/tex]

We can use the elimination method and thus multiply the second equation by -4:  

[tex]4P + 6C = 46.50\\-4(P+C=9.75)\\\\4P + 6C = 46.50\\-4P -4C=-39\\\\2C = 7.5\\\\C = 3.75[/tex]

We can plug C into the second equation to find P:

[tex]P + 3.75 = 9.75\\P = 6[/tex]

Thus, the cost of two buckets of popcorn is 6 * 2 = $12

And the cost of three boxes of candy is 3.75 * 3 = $11.25

And the cost of both two buckets of popcorn and three boxes of candy is (6*2) + (3*3.75) = 12 + 11.25 = $23.25

The distance between the two points is 93.9 units

The formula for calculating the distance between two points is expressed as:

[tex]D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}[/tex]

Given the coordinate points (0, 0) and (40, 85). The distance between the points is expressed as:

[tex]D=\sqrt{(85-0)^2+(40-0)^2}\\D=\sqrt{7225+1600}\\D=93.9 units[/tex]

Hence the distance between the two points is 93.9 units

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Answer:89.4

Step-by-step explanation:

[tex]\green{ \underline { \boxed{ \sf{Average = \frac{Sum \:of \: observation}{Number \:of \: observation}}}}}[/tex]

[tex]\longrightarrow[/tex]Here, no of observation are 5

Now,

[tex]\begin{gathered}\\\implies\quad \sf Average = \frac{1+9+11+13+26}{5} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Average = \frac{60}{5} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf Average = 12 \\\end{gathered} [/tex]

[tex]\longrightarrow[/tex]The Average of given set of numbers is 12 .

[tex]\therefore\: [/tex] Option A) is correct ✔️

Answer:

-2.3, 8.6 to the nearest tenth.

Step-by-step explanation:

-16t^2+100t+316=0

Simplify it first.

Divide  by -4:

4t^2 - 25t - 79 = 0

Using the quadratic formula:

x = [-(-25) +/- √(-25)^2 - 4*4*-79) ] / 8

= (25 +/- √(1889)) / 8

=   3.125 +/- 43.463/8

= 3.125 +/- 5.433

= -2.308, 8.558

Answer:

quadratic formula normally normally applies in such cases

There was a total of w + 36 people at the party.

Mathematical expressions consist of at least two numbers or variables, at least one arithmetic operation, and a statement. It's possible to multiply, divide, add, or subtract with this mathematical operation.

Given, The adults and children in a neighborhood attended a party. There were 18 children.

Let "x" be the number of Persons in the party

Since,

There were w fewer children than adults.

thus,

Number of Adults in the party = w + 18

x = w  + 18

Total number of people at party = x + 18

Total number of people at party = w + 18 + 18

Total number of people at party = w + 36

Therefore, there were w + 36 people at the party.

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Answer:

f(x)= (x-3)^2-3

Step-by-step explanation:

Vertex Form: y= a(x-h)^2+k

a is the reflection

h and k are the vertex so in an ordered pair (x,y) = (h,k)

Since it is translating 3 units down it is going to be a negative 3.  If it was translating up it would be positive 3.  This represents the "k" because it is moving on the y-axis.

Since it is translating 3 units to the right it is going to be positive 3.  If it was translating left it would be negative 3. This represents the "h" because it is moving on the x-axis.

After plugging it into the vertex form formula: f(x)= (x-3)^2-3

*notice when I plugged the "h" in it became negative because x-(3)= x-3*

Answer:

8 i think im not really sure

Step-by-step explanation:

[tex]\dfrac{x^2+7x+12}{x^2-x-12}\\\\=\dfrac{x^2 +3x+4x +12}{x^2 -4x+3x-12}\\\\=\dfrac{x(x+3)+4(x+3)}{x(x-4)+3(x-4)}\\\\=\dfrac{(x+4)(x+3)}{(x-4)(x+3)}\\\\=\dfrac{x+4}{x-4}\\\\\text{Restrictions:}~ x\neq 4 ,~ x\neq -3[/tex]

Answer:

Step by step  explanation:

Answer:

[tex] 55 < A < \frac{149}{2} [/tex]

Step-by-step explanation:

Given:

Function g(x) = 2x²-x-1, [2,5],

N = 6 rectangles

To find:

Two approximation (Left endpoint and Right endpoint of the area) of the area.

Solution:

Using Right endpoint approximation,

[tex]\Delta x = \frac{b - a}{N} \\ \Delta x = \frac{5 - 2}{6} \\ \Delta x = \frac{3}{6} = \frac{1}{2}[/tex]

Now,

[tex]\displaystyle\sf \: R_n = \Delta x \: \sum_{i=1}^N f(a + i \Delta x)[/tex]

Where i = 1,2,3,4......

Substituting value of N, ∆x and a in above equation,

[tex]\displaystyle\sf \: R_n = \Delta x \: \sum_{i=1}^N f(a + i \Delta x) \\ \displaystyle\sf \: R_n = \frac{1}{2} \: \sum_{i=1}^6 f(2 + i \cdot \frac{1}{2} ) \\ \displaystyle\sf \: R_n = \frac{1}{2} \: \sum_{i=1}^6 f(2 + \frac{i}{2} ) \\ \displaystyle\sf \: R_n = \frac{1}{2} \: \sum_{i=1}^6 f( \frac{4 + i}{2} ) [/tex]

[tex]\displaystyle\sf \: R_n = \frac{1}{2} \bigg( f( \frac {5}{2}) + f( 3) +f( \frac {7}{2}) + f( 4) + f( \frac {9}{2}) + f( 5) \bigg) [/tex]

Substituting the corresponding values of x in given function 2x²-x-1

[tex]\displaystyle\sf \: R_n = \frac{1}{2} \bigg(2 \times { (\frac{5}{2} )}^{2} - \frac{5}{2} - 1 ....... +2 \times { ({5} )}^{2} - {5}- 1 \bigg) [/tex]

After solving each function,

[tex]\displaystyle\sf \: R_n = \frac{1}{2} \bigg(9 + 14 +20 + 27 + 35 + 44\bigg) \\ \displaystyle\sf \: R_n \: = \frac{149}{2} [/tex]

Similarly for left endpoint approximation,

[tex]\displaystyle\sf \: L_n = \Delta x \: \sum_{i=0}^{N - 1} f(a + i \Delta x)[/tex]

Where i = 0,1,2,3......

Substituting value of N, ∆x and a in above equation,

[tex]\displaystyle\sf \: L_n = \Delta x \: \sum_{i=0}^{N } f(a + i \Delta x) \\ \displaystyle\sf \: L_n = \frac{1}{2} \: \sum_{i=0}^{N } f(2 + i \frac{1}{2} ) \\\displaystyle\sf \: L_n = \frac{1}{2} \: \sum_{i=0}^6 f( \frac{4 + i}{2} ) [/tex]

[tex]\displaystyle\sf \: L_n = \frac{1}{2} \bigg(f( 2) + f( \frac {5}{2}) + f( 3) +f( \frac {7}{2}) + f( 4) + f( \frac {9}{2}) + \bigg) [/tex]

Substituting the corresponding values of x in given function 2x²-x-1

[tex]\displaystyle\sf \: L_n = \frac{1}{2} \bigg(5+ 9 + 14 +20 + 27 + 35 \bigg) \\ \displaystyle\sf \: L_n \: = \frac{110}{2} = 55 \\ [/tex]

Right approximation 149/2

Left approximation 55

Hence the Area is bounded in,

[tex] 55 < A < \frac{149}{2} [/tex]

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