Answer:
La temperatura del aire a una altitud de 15000 metros sobre el nivel del mar es -66 ºF.
Step-by-step explanation:
Dada la relación de linealidad, construimos una función lineal de la temperatura del aire en función de la altitud con respecto al nivel del mar, la cual es:
[tex]T(h) = T_{L} + \frac{T_{H}-T_{L}}{h_{H}-h_{L}} \cdot h[/tex], [tex]0\,m \leq h \leq 20000\,m[/tex] (Eq. 1)
Donde:
[tex]T_{L}[/tex] - Temperatura del aire a nivel del mar, medida en grados Fahrenheit.
[tex]T_{H}[/tex] - Temperatura del aire a determinada altitud, medida en grados Fahrenheit.
[tex]h_{L}[/tex] - Altura del nivel del mar, medida en metros.
[tex]h_{H}[/tex] - Altura determinada, medida en metros.
[tex]h[/tex] - Altitud con respecto al nivel del mar, medida en metros.
[tex]T(h)[/tex] - Temperatura del aire a una altitud con respecto al nivel del mar, medida en grados Fahrenheit.
Si sabemos que [tex]T_{L} = 60\,^{\circ}F[/tex], [tex]T_{H} = 18\,^{\circ}F[/tex], [tex]h_{L} = 0\,m[/tex], [tex]h_{H} = 5000\,m[/tex] y [tex]h = 15000\,m[/tex], la temperatura del aire a esa altitud es:
[tex]T(15000\,m) = 60\,^{\circ}F + \frac{18\,^{\circ}F-60\,^{\circ}F}{5000\,m-0\,m} \times 15000\,m[/tex]
[tex]T(15000\,m) = -66\,^{\circ}F[/tex]
La temperatura del aire a una altitud de 15000 metros sobre el nivel del mar es -66 ºF.
can someone please help me?
Answer:
a
Step-by-step explanation:
3) Alex drove for 3 hours at an
average speed of 60 miles per
hour and for 2 hours at 45
miles per hour. What is his
average speed for the whole
journey?
average speed= total distance/total time taken
60+45= 105miles
1 mile= 1.609
105×1.609= 168.945km
168.945/4
Hence answer = 33.79 km/hr
Answer:
To find Alex's average speed for the whole journey, we can use the formula:
Average Speed = Total Distance / Total Time
Let's calculate the total distance traveled first:
Distance1 = 60 miles/hour * 3 hours = 180 miles
Distance2 = 45 miles/hour * 2 hours = 90 miles
Total Distance = Distance1 + Distance2 = 180 miles + 90 miles = 270 miles
Next, let's calculate the total time taken for the whole journey:
Total Time = 3 hours + 2 hours = 5 hours
Now, we can find the average speed:
Average Speed = 270 miles / 5 hours = 54 miles per hour
So, Alex's average speed for the whole journey is 54 miles per hour.
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PLS HELP 30 points
Which point represents the outlier in the scatter plot?
(A) (2,4)
(B) (5,10)
(C) (9,10)
(D) (10,9)
Answer:
The answer is D : (10,9)
Step-by-step explanation:
As you can see... the cordinate (10,9) is far away from the other points, therefore it is clearly the outlier of the data set
Happy Birthday is having a party this weekend. The ratio of community friends to school friends attending the party is 8 to 14. Find an equivalent ratio of school friends to community friends.
Group of answer choices
24 to 18
28 to 16
16:28
18:24
Answer:
16: 28 is the answer for the above question
Lesson 7.1 Extra Practice Find the area of the parallelogram. 1. 8 m 5 m
Answer:
9m
Step-by-step explanation:
A parallelogram you have listed has the following side lengths:
1.8m and 5m.
First, we need to understand the formula and simply comprehend it.
In this case, we're dealing with an area of a quadrilateral which is a four-sided shape.
The area is base times height.
You will simply need to do 1.8 x 5 = m
That is pretty simple. You need to setup a question like this:
1.8
x 5
____
9.0
Remember you need to move the decimal point when you're done mulitplying. This case 9.0 is simply 9 by itself.
Which expression is equivalent to 2(a + 3)? (a + 2)3 3(a + 2), 6a + 2, or 2a + 6
Answer:
2a+6
I'm sure of it!!
trust me
Find sin Y, cos Y, and tan Y. Write each answer as a fraction and as a decimal rounded to the nearest hundredth.
4. Trials until First Success
On the average, how many times must a die be thrown until one gets a 6?
Answer:
6
Step-by-step explanation:
There are 6 faces on a die so on average, one has to roll a fair die 6 times in order to get number 6 to show.
On average it's 6 as 6 sides a die has
But
There is equal probability for each number while rolling a die .i.e
There is 1/6 chances getting any number
Please help asap……..
Answer:
1. 96
2. 84
Step-by-step explanation:
I used the Circle theorems:
For 1 you use the alternate segment theory
For 2 you use the theory that opposite angles in a cyclic quadrilateral add up to 180.
I can't be asked to explain it properly I'm sorry but if no one else does it properly you can give me brainliest?
if sec theta + tan theta equals to X then prove that sin theta equals to x square minus x whole divided by X square + 1
Correct Question :-
If sec[tex]\theta[/tex] + tan[tex]\theta[/tex]= x , then prove that ,
[tex]\implies\sf sin\theta =\dfrac{x^2-1}{x^2+1}[/tex]
Proof :-
Here we are given that ,
[tex]\longrightarrow \sec\theta + tan\theta = x[/tex]
Firstly write everything in terms of sine and cosine .
[tex]\longrightarrow \dfrac{1}{\cos\theta}+\dfrac{\sin\theta}{\cos\theta}=x [/tex]
Add ,
[tex]\longrightarrow \dfrac{1+\sin\theta}{\cos\theta}=x [/tex]
On squaring both sides , we have ;
[tex]\longrightarrow \dfrac{(\sin\theta+1)^2}{(\cos\theta)^2}=x^2[/tex]
Simplify using identity sin²x + cos²x = 1 ,
[tex]\longrightarrow \dfrac{(1+\sin\theta)^2}{1-\sin^2\theta}=x^2 [/tex]
Simplify using identity (a+b)(a-b)=a²-b² ,
[tex]\longrightarrow \dfrac{(1+\sin\theta)^2}{(1+\sin\theta)(1-\sin\theta)}=x^2 [/tex]
Simplify,
[tex]\longrightarrow \dfrac{1+\sin\theta}{1-\sin\theta}=x^2 [/tex]
On using Componendo and Dividendo , we have ;
[tex]\longrightarrow \dfrac{1+\sin\theta+1-\sin\theta}{1+\sin\theta-1+\sin\theta}=\dfrac{x^2+1}{x^2-1}[/tex]
[tex]\longrightarrow \dfrac{2}{2\sin\theta}=\dfrac{x^2+1}{x^2-1}[/tex]
Simplify,
[tex]\longrightarrow \dfrac{1}{\sin\theta}=\dfrac{x^2+1}{x^2-1}\\[/tex]
Divide both the sides by 1 ,
[tex]\longrightarrow \underline{\underline{\sin\theta =\dfrac{x^2-1}{x^2+1}}} [/tex]
Hence proved .
And we are done !
[tex]\rule{200}4[/tex]
More to Know :-1) Trigonometric table :-
[tex]\small{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}[/tex]
[tex]\rule{200}4[/tex]
2) Important identities :-
[tex]\boxed{\begin{minipage}{6cm} Important Trigonometric identities :- \\ \\ $\: \: 1)\:\sin^2\theta+\cos^2\theta=1 \\ \\ 2)\:\sin^2\theta= 1-\cos^2\theta \\ \\ 3)\:\cos^2\theta=1-\sin^2\theta \\ \\ 4)\:1+\cot^2\theta=\text{cosec}^2 \, \theta \\ \\5)\: \text{cosec}^2 \, \theta-\cot^2\theta =1 \\ \\ 6)\:\text{cosec}^2 \, \theta= 1+\cot^2\theta \\\ \\ 7)\:\sec^2\theta=1+\tan^2\theta \\ \\ 8)\:\sec^2\theta-\tan^2\theta=1 \\ \\ 9)\:\tan^2\theta=\sec^2\theta-1$\end{minipage}}[/tex]
[tex]\rule{200}4[/tex]
If sec theta + tan theta equals to x then prove that:-
[tex]\longrightarrow \: sin \theta = \frac{ {x}^{2} - { \bold{1}} }{ {x}^{2} + 1 } [/tex]
Solution:Given that:
[tex]\longrightarrow \: sec \: \theta + tan \: \theta =x \: \: ..(i) [/tex]
We have to prove:
[tex]\longrightarrow \: sin \: \theta = \frac{ {x}^{2} - 1 }{ {x}^{2} + 1} [/tex]
We know that:
[tex]\longrightarrow \: { \sec}^{2} \theta \: - \: { \tan}^{2} \theta = 1[/tex]
[tex] \longrightarrow ( \sec \: \theta \: + \: \tan \: \theta)( \sec \: \theta - \tan \: \theta )[/tex]
[tex] \longrightarrow x( \sec \: \theta - \tan \: \theta) \: = 1[/tex]
[tex] \longrightarrow \: \sec \theta - \tan \: \theta = \frac{1}{x} \ ..(ii)[/tex]
Adding equation (i) and (ii), we get:
[tex] \longrightarrow \: 2\sec \theta = x + \frac{1}{x} [/tex]
[tex] \longrightarrow \: 2 \sec \: \theta = \frac{ {x}^{2} + 1}{x} [/tex]
[tex] \longrightarrow \: \sec \: \theta = \frac{ {x}^{2} + 1}{2x} [/tex]
[tex] \longrightarrow \: \cos \: \theta = \frac{2x}{ {x}^{2} + 1 } [/tex]
Now, we know that:
[tex] \longrightarrow \: { \sin}^{2} \theta + { \cos }^{2} \: \theta = 1[/tex]
Therefore,
[tex] \longrightarrow \: \sin \theta \: = \sqrt{1 - { \cos }^{2} } \: \theta[/tex]
[tex] \longrightarrow \: \sin \: \theta = {\sqrt{1 - ( \frac{2x}{ {x}^{2} + 1} } )}^{2} [/tex]
[tex] \longrightarrow \: \sin \: \theta = \sqrt{ \frac{ {({x}^{2} + 1)}^{2} - {(2x)}^{2} }{( {x}^{2} + 1)} } [/tex]
[tex] \longrightarrow \: \sin \: \theta = \sqrt{ \frac{ {x}^{4} \: + 2 {x}^{2} + 1 - \: 4 {x}^{2} }{( {x}^{2} { + 1)}^{2} } } [/tex]
[tex] \longrightarrow \: \sin \: \theta = \sqrt{ \frac{ {x}^{4} - {2x}^{2} + 1 }{( {x}^{2} { + 1)}^{2} } } [/tex]
[tex] \longrightarrow \: \sin \: \theta = \sqrt{ \frac{( {x}^{2} { - 1)}^{2} }{ {(x}^{2} + {1)}^{2} } } [/tex]
[tex] \longrightarrow \: \sin \: \theta = \frac{ {x}^{2} - 1 }{ {x}^{2} + 1} [/tex]
Hence Proved..!![tex] \: [/tex]
Learn More:1. Relationship between sides and T-Ratios.sin θ = Height/Hypotenusecos θ = Base/Hypotenusetan θ = Height/Basecot θ = Base/Heightsec θ = Hypotenuse/Basecosec θ = Hypotenuse/Height2. Square formulae.sin²θ + cos²θ = 1cosec²θ - cot²θ = 1sec²θ - tan²θ = 13. Reciprocal Relationship.sin θ = 1/cosec θcos θ = 1/sec θ tan θ = 1/cot θcosec θ = 1/sin θsec θ = 1/cos θtan θ = 1/cot θ4. Cofunction identities.sin(90° - θ) = cos θcos(90° - θ) = sin θcosec(90° - θ) = sec θsec(90° - θ) = cosec θtan(90° - θ) = cot θcot(90° - θ) = tan θ5. Even odd identities.sin -θ = -sin θcos -θ = cos θtan -θ = -tan θwrite step by step pls
1/2r−3=3(4−3/2r)
Answer:
r = 3
Step-by-step explanation:
[tex]\dfrac{r}{2} - 3 = 3(4 - \dfrac{3r}{2} )[/tex]
The first step to solve for "r" is to simplify the distributive property on the RHS. To simplify the distributive property, we need to multiply the term outside the parenthesis with the terms inside the parenthesis.
[tex]\rightarrow \dfrac{r}{2} - 3 = 12 - \dfrac{9r}{2}[/tex]
Now, add 9r/2 and 3 both sides to isolate the constants and variables.
[tex]\rightarrow \dfrac{r}{2} + \dfrac{9r}{2} = 12 + 3[/tex]
Simplify both sides.
[tex]\rightarrow \dfrac{10r}{2}= 12 + 3[/tex]
[tex]\rightarrow 5r = 15[/tex]
Divide 5 both sides.
[tex]\rightarrow \boxed{r = \frac{15}{5} = 3}[/tex]
Which statement explains why the value of [2.4] is 2 but the value of [-2.4] is –3? because 2 is the greatest integer not greater than 2.4, and –3 is the greatest integer not greater than –2.4 because 2.4 rounds to 2, and –2.4 rounds to –3 because 2.4 is positive, and –2.4 is negative because 2 is the least integer greater than 2.4, and –3 is the least integer greater than –2.4
Using the definition of the floor function, it is found that the correct statement is:
Because 2 is the greatest integer not greater than 2.4, and –3 is the greatest integer not greater than –2.4.
What is the floor function?Modeled by [x], it is the value of the greatest integer that is not greater than x.
Hence, in this problem:
[2.4] = 2, as 2 < 2.4 < 3.[-2.4] = -3, as -3 < -2.4 < -2.Hence, the correct statement is:
Because 2 is the greatest integer not greater than 2.4, and –3 is the greatest integer not greater than –2.4.
More can be learned about the floor function at https://brainly.com/question/15457745
Answer:
a
Step-by-step explanation:
on edge
(Help ASAP will give 20 points for 2 questions)
Answer:
1.x,y is the answer to first question
2.y=2x+5
Find the line's slope and a point on the line.
PLEASE SOME1 ANSWER ASAP
A football team won 67% of their matches and drew 24% of them. What percentage of the matches did they lose?
Answer:
9%
Step-by-step explanation:
67 + 24 = 91%
100- 91 = 9%
This means they lost 9% of their games.
The requried football team lost 9% of their matches.
What is the percentage?The percentage is the ratio of the composition of matter to the overall composition of matter multiplied by 100.
Since the football team won 67% of their matches and drew 24% of them, the percentage of matches they lost can be found by subtracting the percentage of matches they won and the percentage of matches they drew from 100%:
Percentage of matches lost = 100% - 67% - 24%
Percentage of matches lost = 9%
Therefore, the football team lost 9% of their matches.
Learn more about percentages here:
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Match each equation to its equivalent equation.
-6x - 2y = 10
2x + 5y = 18
-4x + 3y = 20
12x - 9y = -60
-24x - 8y = 40
4x + 10y = 36
Answer:
-6x - 2y = 10 and -24x - 8y = 40
-4x + 3y = 20 and 12x - 9y = -60
2x + 5y = 18 and 4x + 10y = 36
Step-by-step explanation:
first equation with second row second equation
third equation with second row first equation
second equation with second row third equation
The equation 2x2 − 3x + 1 = 0 is in quadratic form. true or false
Answer:
True
Step-by-step explanation:
The equation 2x² - 3x + 1 = 0 is in quadratic form.
Answer:
True.
Step-by-step explanation:
The equation [tex]2x^{2} - 3x + 1 = 0[/tex] is in quadratic form because it meets the quadratic formula: [tex]Ax^{2} + Bx + C = 0[/tex].
Can you please help me with this question it is due at 11:59 pm
Answer:
its 11:09 pm......
Step-by-step explanation:
are u on pc?
HELP PLEASE! 40 POINTS AND WILL MARK BRAINLIEST.
Suppose you want to find the 40th term of a sequence. Would you rather use a recursive rule or an explicit rule? Explain your reasoning.
Answer:
Explicit rule, because you can find the 40th term directly using the explicit rule. You would need to find the first 39 terms before finding the 40th terms using recursive rule.
hope this helps...
Which expression has the same meaning as 4 9/2?
Answer:
8 1/2
or 8.5
Step-by-step explanation:
Answer:
The second one, √4^9
Sorry lol i posted the answer in the questions section by accident
guys please help me i need this done NOW
Answer:
see down
Step-by-step explanation:
10. a one to one function means only one input goes to the same output,
this one is not a one to one function, because there is 2 out put for each input except vertx
Which system of equations represents the graph?
for the line that goes up - it cuts the y-axis at - 5 (p = -5)
when we take 2 points we go from one to the other by going to the right of 1 unit and going up of 3 units (slope m : 3/1)
=> y = 3x - 5
and
for the line which goes down - it cuts the y-axis in +2 (p=2)
when we take 2 points we go from one to the other by going to the right of 2 units and going down of 1 unit (slope m : -1/2)
=> y = -1/2x + 2
=> y + 1/2x = 2
2x + 4y = 8
=> B
Can anyone help me with this question?
Answer:
Penta Trinomial
Step-by-step explanation:
Highest power is 5 (penta)
Highest number of term is 3 (tri)
Answer:
6th degree trinomialStep-by-step explanation:
Given polynomial
4xy⁵ + 2xy - x⁴yIt has 3 terms so is trinomial
It has degrees as
First term = 1 + 5 = 6Second term = 1+1 = 2Third term = 4+1 = 5As the greatest degree is 6, this expression is 6th degree trinomial
billy has $3 bubble gum cost $.30. he bought four pieces how much money does billy have left
Answer: $1.08
Step-by-step explanation:
30cent x 4 = 120 cents. 1 dollar and 20 cents, $3 - $1.20 = $1.08
Answer:
Billy has 1.8 dollars left.
Step-by-step explanation:
So, .30 x 4 is 1.2. I subtracted 1.2 from 3 and got 1.8. I hope it's the right answer and wish you luck on the rest of your work!
PLEASE HELP WITH MATHS
Answer:
No biscuits.
Step-by-step explanation:
We know that there is a total of 100 biscuits.
Let's assign variables.
X=Icing
Y=Hundreds and Thousands
Z=Cherries
X appears every 5 biscuits, y appears every 8 biscuits, and z appears every 9 biscuits. Let's start solving by finding their multiples that are less than or equal to 100.
X: 5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100
Y: 8,16,24,32,40,48,56,64,72,80,88,96
Z: 9,18,27,36,45,54,63,72,81,90,99
The multiples need to be a multiple of 5,8, and 9.
The numbers that have both x and y are: 40 and 80
The numbers that have both x and z are: 45 and 90.
Seeing as the numbers never overlap, there are no biscuits that have x,y, and z.
Note: If you like my answer, please rate it a 5 and click thanks! (It helps with my leveling. If you want to be extra nice, you can also give me brainliest if you want!) If you think there is something wrong with my answer or that there is something I should improve on, please leave it in the comments.
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP
Answer:
(-2, -9)
explanation:
original coordinates of B: (7, 9)
use the formula: (x, y) ---> (x, -y)
if reflects over x-axis new coordinates: (7, -9)If horizontally shifted there will be change in x axis,
new coordinates (7-9,-9) → (-2, -9)Evaluate for a = 2, b = 3, and c = 4.
ab + c
Answer:
10
Step-by-step explanation:
Given;
a = 2
b = 3
c =4
ab+c
Solve;
Since a = 2, b = 3, and c = 4
Substitute
(2)(3)+4
6 +4
= 10
Answer = 10
~Learn with lenvy~
Answer:
10
Step-by-step explanation:
Given the following question:
[tex]a=2[/tex]
[tex]b=3[/tex]
[tex]c=4[/tex]
[tex]ab+c[/tex]
To find the answer we need to substitute the values in for the variables and then solve using PEMDAS.
[tex]ab+c[/tex]
[tex]2\times3+4[/tex]
[tex]2\times3=6[/tex]
[tex]6+4[/tex]
[tex]6+4=10[/tex]
[tex]=10[/tex]
Your answer is "10."
Hope this helps.
plzzzzzzzzzzzz help plzz
Answer:
The zoo was open 362 days and had an average of 272 visitors a day.
Step-by-step explanation:
365-3=362
98,464÷362=272
Which sequence: an=-2(an-1),a1=4
Which equation represents the general form a circle with a center at (–2, –3) and a diameter of 8 units? x2 y2 4x 6y – 51 = 0 x² y² – 4x – 6y – 51 = 0 x2 y2 4x 6y – 3 = 0 x2 y2 – 4x – 6y – 3 = 0.
The equation represents the general form a circle with a center at
(–2, –3) and a diameter of 8 units is,
[tex]x^{2} +4x+y^{2} +6y-3=0[/tex]
Given that,circle with a center at (–2, –3)
diameter of circle is 8 units
To find
the equation of the circle that represents the general form of a circle with a center at (–2, –3) and a diameter of 8 units.
Radius of the Circle is,
The diameter of the circle is 8 units. therefore,
[tex]radius=\frac{d}{2}=\frac{8}{2} =4[/tex]
Equation of a circle
The equation of the circle that represents the general form of a circle with a center at (–2, –3) and a radius of 4 units.
What is the general form of equation of circle?[tex](x-h)^{2} +(y-k)^{2} =R^{2}[/tex]
Substituting the values,
[tex](x-(-2))^{2} + (y-(-3))^{2} =4^{2}[/tex]
[tex](x+2)^{2} + (y+3)^{2} =4^{2}\\[/tex]
[tex]x^{2} +4x+4+y^{2} +6y+9=0[/tex]
[tex]x^{2} +4x+y^{2} +6y-3=0[/tex]
Therefore, the option C is correct.
The equation represents the general form a circle with a center at
(–2, –3) and a diameter of 8 units is
[tex]x^{2} +4x+y^{2} +6y-3=0[/tex]
To learn more about the general form of circle visit:
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