john owns a truck. he rents out the truck with himself as a driver for $75 per hour. last month john earned $6375 how many of hours of work is that for john and his truck.

Answers

Answer 1
it would be 85 hours because 6375÷75=85

Related Questions

If a polynomial function f(x) has roots -9 and 7-i, what must be a factor of f(x)
(x-(7+i))
(x-(-7-i))
(x+(7+i))
(x+(7-i))

Answers

Answer:

f(x) = [x-(7-2i)][x-(7+2i)]

= [(x-7)+2i][(x-7)-2i]

= (x-7)2 - (2i)2

= x2 - 14x + 49 - 4i2 = x2 - 14x + 49 +4

= x2 - 14x + 53

Answer:

[tex](x-(7-i))[/tex]

Step-by-step explanation:

For a polynomial with roots [tex]a[/tex] and [tex]b[/tex], the polynomial [tex]f(x)[/tex] can be written in factored form [tex](x-a)(x-b)[/tex]. That way, when you plug in any of the roots, [tex]f(x)[/tex] returns zero.

Since the polynomial has at least two roots-9 and 7-i, two of its factors must then be:

[tex](x-(-9)\implies (x+9)\\(x-(7-i))\impli[/tex]

Therefore, the desired answer is [tex]\boxed{(x-(7-i))}[/tex]

Someone tell me where everyone is going right please !!

Answers

9514 1404 393

Explanation:

The problem statement tells you the meaning of t. It is minutes after Riko leaves. 0 ≤ t < 52.5 is the answer to the question regarding the interval Riko is behind Yuto. It means Riko is behind Yuto for 52.5 minutes after she leaves their house.

t will not be negative because time moves forward. Here, we're only counting time after Riko leaves the house. A negative value for t would refer to a time before Riko leaves the house, which is irrelevant in this problem.*

_____

* One might argue that Riko is behind Yuto for all values of time after Yuto leaves the house, which would be for -21 < t < 52.5. The concept of "behind Yuto" has no meaning except in that interval.

Answer:

again again again hello or merhaba(hello)

speed = path / time

so we can say this;

speed × time = path

note;

two speeds in different directions add up

and

two speeds in the same direction subtract

our speeds are in the same direction so we subtract

0.35 - 0.25 = 0.10 speed

and our path is 5.25 miles because there are 5.25 miles between Yuto and Rico

when will they be in the same place now?

Let's solve with the formul;

speed × time = path

0.10 × time = 5.25 miles

in this equation we find the time 52.5 minutes

After 52.5 minutes they will be in the same place but before 52.5 minutes Riko will be behind Yuto

When Riko was behind Yuto;

0≤ t ≤ 52,5 ( this is our equation of time)

now the second question?

Why can't t be less than 0?

because time cannot take a negative value, as soon as they start moving, time passes and this cannot take a negative value

GOOD LUCK :D

Step-by-step explanation:

greetings from Turkey (≧▽≦)

The Fun Committee is hosting the Annual City Festival. Jennifer is in charge of the committee and is planning a race to raise money for the Festival. The runners will earn money from donors for the number of miles they run. If the runners start at the park, run to City hall, and then run back to the park, how many total miles will each runner run? Show your work and leave your answer in simplest radical form if necessary.

Answers

Answer:  [tex]6\sqrt{5}[/tex]  miles

This is the same as writing 6*sqrt(5) miles

==========================================================

Work Shown:

P = park

C = city hall

Point P is at the location (10,11)

Point C is at the location (7,5)

Apply the distance formula to find the length of segment PC

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(10-7)^2 + (11-5)^2}\\\\d = \sqrt{(3)^2 + (6)^2}\\\\d = \sqrt{9 + 36}\\\\d = \sqrt{45}\\\\d = \sqrt{9*5}\\\\d = \sqrt{9}*\sqrt{5}\\\\d = 3\sqrt{5}\\\\d \approx 6.7082039\\\\[/tex]

The exact distance between the park (P) and city hall (C) is [tex]3\sqrt{5}[/tex] miles.

This doubles to [tex]2*3\sqrt{5} = 6\sqrt{5}[/tex] miles because the runners go from P to C, then back to P again. In other words, they run along segment PC twice. This is assuming there is a straight line road connecting the two locations.

Extra info:

[tex]6\sqrt{5} \approx 13.41641[/tex] so the runner travels a total distance of roughly 13.4 miles.

Can someone help me with this math homework please!

Answers

7h + 43 = 64

Hourly cost = $3

Thanks for helping me two more problems

Answers

Answer:

A. Energy (weight)

Step-by-step explanation:

Mark me as brainiest

(iii) If a, b, c are rational numbers, then
a x (b-c) #ax b-ax c. true or false ​

Answers

Answer:

false

Step-by-step explanation:

answer:ab-ac=ab-ac

find the distance between the points (7,23) and (3,-3), rounded to the hundredths place​

Answers

Answer:

26.31

Step-by-step explanation:

Use distance formula

d = [tex]\sqrt{(x_{2}-x_{1)^{2} + (y_{2}-y_ ^{1)^2} } }[/tex]

substitute in points and solve

d =  [tex]\sqrt{(7-3)^2 + (23-(-3))^{2} }[/tex]

d = [tex]\sqrt{4^{2}+26^{2} }[/tex]

d = [tex]\sqrt{16 + 676}[/tex]

d = [tex]\sqrt{692}[/tex]

d = 26.30589288

d = 26.31 rounded

Find x

Help me please
I'll give you 13 points if it's correct

Answers

ITS 19 TRUSTTTTT MEEE

write 36,438 correct to 2 significant figure
(show how you did it)​

Answers

Answer:

36,000

Step-by-step explanation:

Rounding Significant Figures Rules

Non-zero digits are always significant Zeros between non-zero digits are always significant Leading zeros are never significant Trailing zeros are only significant if the number contains a decimal point

Rounding Rules

When rounding significant figures the standard rules of rounding numbers apply, except that non-significant digits to the left of the decimal are replaced with zeros.

Example: 356 rounded to 2 significant digits is 360

This calculator rounds down if the next digit is less than 5 and rounds up when the next digit is greater than or equal to 5.

In the table below 305.459 is rounded from 0 to 6 significant figures. For comparison the same number is rounded from 0 to 6 decimal places. You can see the difference between rounding for significant figures and rounding to decimal places.

At a point 25 ft. from the base of a totem pole, the angle of elevation of the top of the pole is 50.1 °. How tall is the totem pole to the nearest foot?

Answers

Answer:

height ≈ 30 ft

Step-by-step explanation:

The situation is modelled by a right triangle.

let h be the height of the totem pole, then

tan50.1° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{h}{25}[/tex] ( multiply both sides by 25 )

25 × tan50.1° = h , then

h ≈ 30 ft ( to the nearest foot )

why is the sum of two negative numbers not a positive number
please dont make the whole answer a example:)

Answers

Answer:

because when two negatives are together they can't add

Step-by-step explanation:

because when two negatives are together they can't add no matter if there's an addition sign

You are given the exponential function g(x)=3^x. Which ootion below gives the formula for the new function h created by stretching g by a factor of 3 along the y-axis?

Answers

Answer:

h(x) = 3^(x + 1)

Step-by-step explanation:

The exponential function is;

g(x) = 3^(x)

Now, in transformation of exponential functions of say f(x) = b^(x), when the new function g(x) is created by stretching by a factor of say c along the y-axis, we have;

g(x) = c•b^(x)

In this question, we are told it is stretched by a factor of 3 along the y-axis.

Thus, new function h is;

h(x) = 3 × 3^(x)

Using law of indices, we have;

h(x) = 3^(x + 1)

If / is a midsegment of /, find x.

A.
2
B.
3
C.
6
D.
9



Please select the best answer from the choices provided


A
B
C
D

Answers

The answer is going to be b I think not sure but help me to lol

Answer:

It is d

Step-by-step explanation:

The rate (In mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function 110I 12 +1+ 9 where I is the light intensity (measured in thousands of foot-candles). For what light intensity is P a maximum?

Answers

Answer:

P is maximum at I = 2

Step-by-step explanation:

Here is the complete question

The rate (in mg carbon/m³/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 100I/(I² + I + 4) where I is the light intensity (measured in thousands of foot candles). For what light intensity P is a maximum?

To find the value of I at which P is maximum, we differentiate P with respect to I and equate it to zero.

So, dP/dI =  d[100I/(I² + I + 4)]/dI

= [(I² + I + 4)d(100I)/dI - 100Id(I² + I + 4)/dI]/(I² + I + 4)²

= [(I² + I + 4)100 - 100I(2I + 1)]/(I² + I + 4)²

= [100I² + 100I + 400 - 200I² - 100I]/(I² + I + 4)²

= [-100I² + 400]/(I² + I + 4)²

=  -100[I² - 4]/(I² + I + 4)²

Since dP/dI = 0,  -100[I² - 4]/(I² + I + 4)² = 0 ⇒ I² - 4 = 0 ⇒ I² = 4 ⇒ I = ±√4

I = ±2

Since I cannot be negative, we ignore the minus sign

To determine if this is a maximum point, we differentiate dP/dI. So,

d(dP/dI)/dI = d²P/dI² = d[-100[I² - 4]/(I² + I + 4)²]/dI

= [(I² + I + 4)²d(-100[I² - 4])/dI - (-100[I² - 4])d(I² + I + 4)²/dt]/[(I² + I + 4)²]²

= [(I² + I + 4)²(-200I) + 100[I² - 4]) × (2I + 1) × 2(I² + I + 4)]/(I² + I + 4)⁴

= [-200I(I² + I + 4)² + 200[I² - 4])(2I + 1)(I² + I + 4)]/(I² + I + 4)⁴

= [-200(I² + I + 4)[I(I² + I + 4) - [I² - 4])(2I + 1)]]/(I² + I + 4)⁴

= [-200(I² + I + 4)[I³ + I² + 4I - I² + 4])(2I + 1)]]/(I² + I + 4)⁴

= [-200(I² + I + 4)[I³ + 4I + 8])(2I + 1)]]/(I² + I + 4)⁴

Substituting I = 2 into d²P/dI², we have

= [-200(2² + 2 + 4)[2³ + 4(2) + 8])(2(2) + 1)]]/(2² + 2 + 4)⁴

= [-200(4 + 2 + 4)[8 + 8 + 8])(4 + 1)]]/(4 + 2 + 4)⁴

= [-200(10)[24](5)]]/(10)⁴

= -240000/10⁴

= -24

Since d²P/dI² = -24 < 0 at I = 2,  this shows that it I = 2 is a maximum point.

So, P is maximum at I = 2

PLEASE SOMEONE HELP I need help ASAP!!!

Answers

Answer:

using the pythagoras theorem

Step-by-step explanation:

[tex] \sqrt{4 {}^{2} - ( \sqrt{7}) {}^{2} } = 3[/tex]

. It is known that the glucose level in blood of diabetic persons follows a normal distribution model with mean 106 mg/100 ml and standard deviation 8 mg/100 ml. a. Calculate the probability of a random diabetic person having a glucose level less than 120 mg/100 ml. b. What percentage of persons have a glucose level between 90 and 120 mg/100 ml?

Answers

Answer:

a. 0.9599 = 95.99% probability of a random diabetic person having a glucose level less than 120 mg/100 ml.

b. 0.9371 = 93.71% of people have a glucose level between 90 and 120 mg/100 ml.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 106 mg/100 ml and standard deviation 8 mg/100 ml

This means that [tex]\mu = 106, \sigma = 8[/tex]

a. Calculate the probability of a random diabetic person having a glucose level less than 120 mg/100 ml.

This is the p-value of Z when X = 120. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 106}{8}[/tex]

[tex]Z = 1.75[/tex]

[tex]Z = 1.75[/tex] has a p-value of 0.9599

0.9599 = 95.99% probability of a random diabetic person having a glucose level less than 120 mg/100 ml.

b. What percentage of persons have a glucose level between 90 and 120 mg/100 ml?

The proportion is the p-value of Z when X = 120 subtracted by the p-value of Z when X = 90. So

X = 120

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 106}{8}[/tex]

[tex]Z = 1.75[/tex]

[tex]Z = 1.75[/tex] has a p-value of 0.9599

X = 90

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{120 - 106}{8}[/tex]

[tex]Z = -2[/tex]

[tex]Z = -2[/tex] has a p-value of 0.0228

0.9599 - 0.0228 = 0.9371

0.9371 = 93.71% of people have a glucose level between 90 and 120 mg/100 ml.

Region A has a total of 81,218,576 acres. Estimate the number of acres owned by the government in Region A. Choose the correct estimate below.

Answers

Answer:

See Explanation

Step-by-step explanation:

Given

[tex]Region\ A = 81218576[/tex]

Required

The acres owned by the government

The question is incomplete as the proportion (p) owned by the government is not given.

However, the formula to use is as follows:

[tex]Govt = p * Region\ A[/tex]

Assume the proportion is 28%, the equation becomes

[tex]Govt = 28\% * 81218576[/tex]

[tex]Govt = 22741201.28[/tex]

The acres owned by the government will be 22741201.28

cross out 3 digits in the number 51489704 so that the number remaining is divisible by 45

Answers

Answer:

1,152

Step-by-step explanation:

So here, we shall be removing random numbers

For ease, since the number is divisible by 45: it is advisable to end the selected number with zero

So we have it that;

we are crossing the first 4, 9 and 7

So, we are left with;

51,840

dividing this by 45 will give 1,152

6) Qual número deve ser acrescentado a expressão x² - 12x, para que se obtenha um trinômio quadrado perfeito? * 6 5 12 10

Answers

Respuesta:

36

Explicación paso a paso:

Para completar el cuadrado tendremos que sumar la mitad del cuadrado del coeficiente de x a la expresión;

Coeficiente de x = -12

Mitad del coeficiente = (-12/2) = -6

Tomando el cuadrado del resultado = (-6) ^ 2 = 36

Por lo tanto, el número que se debe sumar para obtener un cuadrado perfecto es 36.

Find the TWO integers whos product is -12 and whose sum is 1

Answers

Answer:

The two INTEGERS are :-

-3 and +4

-3 * (+4) gives us -12

-3 + (+4) gives us 1

hope it helps

have a nice day

Answer:

[tex] \rm Numbers = 4 \ and \ -3.[/tex]

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

[tex]\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}[/tex]

Hence the numbers are 4 and -3.

Help, I have a time limit for this

Answers

Answer:

I believe that it is the first one.

Step-by-step explanation:

PLEASE HURRY
perform the following series of rigid transformations on ∆abc
translate triangle abc by moving it 5 units to the right and 2 units up
Draw the line y=-x and reflect Triangle A’B’C’ across the line
Rotate A’’B’’C’’ counterclockwise about the fact origin by 270 degress

Answers

Answer:

Step-by-step explanation:

Coordinates of the vertices of ΔABC,

A(-6, -1), B(-3, -3), C(-1, -2)

Step - 1

Rule for the translation of a point (x, y) by 'h' units right and 'k' units upwards,

A(x, y) → A(x + h, y + k)

If ΔABC is translated by 5 units right and 2 units up, image points will be,

A(-6, -1) → H(-6 + 5, -1 + 2)

            → H(-1, 1)

B(-3, -3) → J(-3 + 5, -3 + 2)

             → J(2, -1)  

C(-1, -2) → K(-1 + 5, -2 + 2)

            → K(4, 0)

Step - 2

If the image triangle HJK is reflected across a line [tex]y=-x[/tex], rule for the reflection will be,

H(x, y) → A'(-y, -x)

By this rule,

H(-1, 1) → A'(-1, 1)

J(2, -1) → B'(1, -2)

K(4, 0) → C'(0, -4)

Step - 3

Rule for the rotation of a point 270° counterclockwise about the origin,

A'(x, y) → A"(y, -x)

By this rule, image points of ΔA'B'C' will be,

A'(-1, 1) → A"(1, 1)

B'(1, -2) → B"(-2, -1)

C'(0, -4) → C"(-4, 0)

Now we can graph the image triangle A"B"C".

Answer:

(∠ABC) 108 (for all)

(∠ACB) 27 (for all)

(∠CAB) 45 (for all)

Step-by-step explanation:

A particle is projected with a velocity of [tex]29.4ms^-^1[/tex] . Find it's maximum range on a horizontal plane through the point of projection.
A.88.2m B.44.1m C.32.6m D.29.4m E.14.7m

Answers

A.88.2m

Answer:

Solution given:

initial velocity[u]=29.4m/s

g=9.8m/s²

maximum range=?

now

we have

[tex]\theta=90°[/tex]

maximum range =[tex]\frac{29.4²*sin90}{9.8}=88.2m[/tex]

The initial velocity is,

→ u = 29.4 m/s

General assumption,

→ g = 9.8m/s²

→ θ = 90°

Then the maximum range is,

→ (29.4² × sin90)/9.8

→ 88.2 m

Hence, option (A) is answer.

What is the midpoint of the segment with endpoints(-4, -
2) and (2, 6)?

Answers

Answer:

(-1,2)

Step-by-step explanation:

hope you find this useful!

https://ncalculators.com/geometry/mid-points-calculator.htm

The diameter of a wheel on harrys bicycle is 0.65m calculate the circumference of the wheel give your answer correct to 2 decimal places

Answers

Answer:

Step-by-step explanation:

[tex]C =2\pi r[/tex] and since we have to state the answer to 2 decimal places, that means that we are using the number value for π. In specific, π = 3.1415 is good enough. The other thing we note is that the formula for circumference could also be written in terms of its diameter as opposed to its radius:

C = πd. Let's use that one since we are given the diameter of the tire, not the radius.

C = (3.1415)(.65) so

C = 2.04 m

The circumference of the wheel  is C = 2.04 m.

What is area of the circle?Area of a circle is the region occupied by the circle in a two-dimensional plane. It can be determined easily using a formula, A = πr2, (Pi r-squared) where r is the radius of the circle. The unit of area is the square unit, such as m2, cm2, etc

Given ,

          d = 0.65 m

          π = 3.14

   

Let's use that one since we are given the diameter of the tire, not the radius.

Use this formula ,     C = πd

                         C = (3.1415)(.65)

                       so, C = 2.04 m

Therefore, the circumference of the wheel  is C = 2.04 m.

Learn more about circumference of circle brainly.com/question/16622077 here

#SPJ2

                             

Can someone help with 11 & 13

Answers

[tex]11. \: we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{7 + 11 + 13 + 6 + 8 + x}{6} = 8 \\ = > \frac{45 + x}{6} = 8 \\ = > 45 + x = 8 \: \times 6 \\ = > 45 + x = 48 \\ = > x = 48 - 45 \\ = > x = 2 \\ \\ 12. we \: know \: that \\ \frac{sum \: of \: all \: quantities}{number \: of \: quantities} = mean \\ => \frac{2 + 5 + 1.3 + 2.2 + x}{5} = 1.8 \\ = > \frac{10.5 + x}{5} = 1.8 \\ = > 10.5 + x = 5 \times 1.8 \\ = > 10.5 + x = 9 \\ = > x = 9 - 10.5 \\ = > x = - 1.5 \\ [/tex][/tex]

This is the answer.

Hope it helps!!

There are 24 students in a class. Three new students join the class. Work out the percentage change in the number of students in the class.

Answers

Answer:

12.5% increase

Step-by-step explanation:

To find the percentage increase ( students joined)

Take the new number minus the original amount

There are 27 students in the class after 3 joined

27 - 24 = 3

Divide by the original amount

3/24 = 1/8 = .125 = 12.5%

Answer:

12.5%

Step-by-step explanation:

Intial number = 27

Final number = 24 + 3 = 27

Percentage change :-

% change = 3/24 × 100 % change = 100/8 % Change = 25/2 % change = 12.5 %

Sketch the graph of each of the following quadratic functions. (a) f(x) = x² - 4x - 5 for -2 ≤ x ≤ 6.
pls help me solve this​

Answers

To sketch the graph we have to solve the function with each value of x to get the coordinates.

f(x) = x² − 4x − 5

−2 ≤ x ≤ 6

This inequality represents the domain for x. Therefore x is greater than equal to -2 but less than equal to 6.

The range of x is as follows:

x = -2, -1, 0, 1, 2, 3, 4, 5, 6

We already have the values for x therefore, we must substitute the values of x into the function f(x) = x² − 4x − 5 to find the y values.

Solutions:

For x = -2

f(x) = x² − 4x − 5

= -2² − 4(-2) - 5

= 4 + 8 - 5

= 7

Point = (-2,7)

For x = -1

f(x) = x² − 4x − 5

= -1² - 4(-1) - 5

= 1 + 4 - 5

= 0

Point = (-1,0)

For x = 0

f(x) = x² − 4x − 5

= 0² - 4(0) - 5

= 0 - 0 - 5

= -5

Point = (0,-5)

For x = 1

f(x) = x² − 4x − 5

= 1² - 4(1) - 5

= 1 - 4 - 5

= -8

Point = (1,-8)

For x = 2

f(x) = x² − 4x − 5

= 2² - 4(2) - 5

= 4 - 8 - 5

= -9

Point = (2,-9)

For = 3

f(x) = x² − 4x − 5

= 3² - 4(3) - 5

= 9 - 12 - 5

= -8

Point = (3,-8)

For x = 4

f(x) = x² − 4x − 5

= 4² - 4(4) - 5

= 16 - 16 - 5

= -5

Point = (4,-5)

For x = 5

f(x) = x² − 4x − 5

= 5² - 4(5) - 5

= 25 - 20 - 5

= 0

Point = (5,0)

For x = 6

f(x) = x² − 4x − 5

= 6² - 4(6) - 5

= 36 - 24 - 5

= 7

Point = (6,7)

Coordinates for graph = (-2,7) , (-1,0) , (0,-5) , (1,-8) , (2,-9) ,  (3,-8) ,  (4,-5) , (5,0) ,  (6,7)

These are the points to sketch the quadratic graph.

Which expression is equivalent to 3/2?

Answers

Answer: the answer is D. I took the test & got it right

Step-by-step explanation:

The expression is equivalent to 3/2 will be;

⇒ 3y/(2y - 6) + 9/(6 - 2y)

Option D is true.

What is an expression?

Expression in math is defined as the collection of the numbers, variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that;

Equivalent expression is 3/2.

Now,

Let the expression is;

⇒ 3y/(2y - 6) + 9/(6 - 2y)

Solve the expression as;

⇒ 3y/(2y - 6) - 9/(2y - 6)

⇒ (3y - 9) / (2y - 6)

⇒ 3 (y - 3) / 2 (y - 3)

⇒ 3/2

So, The expression is equivalent to 3/2 will be;

⇒ 3y/(2y - 6) + 9/(6 - 2y)

Option D is true.

Learn more about the fraction visit:

https://brainly.com/question/20323470

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Luego de su cumpleaños, Benjamín ha decidido donar la tercera parte del dinero que recibió de regalo de sus familiares a una fundación. Considerando las variables cantidad de dinero recibido por Benjamín y cantidad de dinero que donará Benjamín. a. ¿Cuál es la variable dependiente en esta situación.

Answers

Answer:

The dependent variable is the amount of money he received for birthday.

Step-by-step explanation:

After his birthday, Benjamin has decided to donate a third of the money he received as a gift from his relatives to a foundation. Considering the variables amount of money received by Benjamin and amount of money that Benjamin will donate. to. What is the dependent variable in this situation.

Here, the money he received for the birthday is x.

So, he donated x/3.

The variable is the money which he gets, so the dependent variable is amount of money he received for the birthday.

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