Java provides a number of interfaces and classes to systematically implement collections.

a. True
b. False

Answer:

the same as

Explanation:

Classified information is confidential information that a government deems to be protected.

There are certain penalties for the person if they ignore any protection measure for classified information when using social networking services and the penalties are the same as if someone uses other media and methods of dissemination.

Hence, the correct answer for the blanks is "the same as".

The penalties for ignoring the requirements for protecting classified information when using social networking services are the same as when using other media and methods of dissemination.

Penalties is the way of punishing an offender for doing wrong.

It is of necessity to ensure that all sensitive data are kept in a confidential manner as the  punishment for someone who  ignored   all the important condition  for protecting sensitive  data or information  are all the same as  when using the following:

•Social networking services

•Media such as Radio,Television

• Methods of dissemination such as Newspaper publication, Publishing in journal

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Options :

The domain name is registered to someone else.

Domain names must end in ".com".

You are not the legal owner of ABC Company.

Domain names must be all in lowercase.

Answer:

The domain name is registered to someone else.

Explanation: In the scenario above, ABCcompany.org represents the domain name of a particular person or establishment which provides access to the website of the owner. The domain name given to an individual or website must be distinct, that is no two different organizations or persons can use exactly the same domain name. Domain names can end with :. com, org, ng and various other and they aren't case sensitive. Therefore, the inability to register the domain name abive will likely stem from the fact that the domain name has is already registered to someone else.

The domain of a website is the name of the website. The most likely reason why the domain cannot be registered is that, it has already been registered/taken by someone else.

There are several reasons why a domain cannot be registered.

The most important reason is that:

When a domain is taken, no other person can have access to that domain until its expiry (and not renewed). So, when a domain has been taken, you will not be able to register such domain.

Another reason is that:

Insufficient funds is another reason, if the domain is not a free domain.

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Answer:

B

Explanation:

When the first time you save a document, the ''Save As screen'' will appear. Hence, the option (b) is correct.

Given that,

To find the screen appears the first time you save a document.

Now, When you save a document for the first time, the "Save As" screen typically appears, allowing you to choose the file name, location, and file format for the document.

This gives you the option to specify where and how the document should be saved on your device.

So, the correct option is,

b. Save As screen

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Answer:

- Peripheral devices

Explanation:

Peripheral devices are defined as computer devices which are not the element of the essential/basic computer function. These devices can be internal as well as external and are primarily connected to the computer for entering or getting information from the computer. For example, the keyboards or mouse functions to enter data into the computer for processing and receiving information while the output devices like speakers, projectors, printers, etc. are used to get the information out of the computer.

Answer:

Word Processor

Explanation:

it is called word processor

Answer:

False

Explanation:

Namecoin is a type of crypto currency which was originally pronged from Bitcoin software. It is coded in the fashion of Bitcoin with the same algorithm as well. Hence it is not a blockchain technology that is used to implement decentralized version of Routing Banking System. Namecoin can store data within its own blockchain transaction database.

Answer:

#include <iostream>

using namespace std;

void PrintPopcornTime(int bagOunces) {

   if(bagOunces < 2)

       cout << "Too small" << endl;

   else if(bagOunces > 10)

       cout << "Too large" << endl;

   else

       cout << 6 * bagOunces <<" seconds" << endl;

}

int main()

{

   int userOunces;

   cin >> userOunces;

   PrintPopcornTime(userOunces);

   return 0;

}

Explanation:

Inside the function PrintPopcornTime, check the parameter bagOunces using if structure. Depending on the value of bagOunces, print the required information.

Inside the main, ask the user for the userOunces. Call the PrintPopcornTime function with the userOunces.

Answer:

D. Remote server public key

E. OCSP

Explanation:

Options D and E are correct because the above question states that its "verifying that a key is valid". This means that it didn't specify which key. Therefore, it sensible that the application wants to verify the validity of the remote host's key. So, in order to use OCSP to verify the validity of that key, that app actually needs the public key of the remote server.

Answer:

[tex]Height = \frac{3}{4}\ unit[/tex]

[tex]Height = 3\ units[/tex]

Explanation:

Given

Shape: Parallelogram

[tex]Area = 18 unit^2[/tex]

[tex]Side\ 1 = 24 units[/tex]

[tex]Side\ 2 = 6 units[/tex]

Required

Determine possible heights of the parallelogram

Area of parallelogram is:

[tex]Area = Base * Height[/tex]

Make Height the subject of formula

[tex]Height = \frac{Area}{Base}[/tex]

When Base = 24 units;

[tex]Height = \frac{18}{24}[/tex]

[tex]Height = \frac{3}{4}\ unit[/tex]

When Base = 6 units;

[tex]Height = \frac{18}{6}[/tex]

[tex]Height = 3\ units[/tex]

When Base = 24 units

When Base = 6 units

Height: 3

Answer:

37 percent

hope it helps u

Answer: D.) Discretionary access control

Explanation: Access control modes provides networks with a security system used for moderating, risk prevention and privacy maintainance of data and computing systems. Several access control modes exists depending on the degree of control required. In the discretionary access control approach, users are afforded the freedom and flexibility of making choices regarding permissions granted to programs. Hence, in this mode, permission are user-defined and as such sets privileges based on how the user deems fit.

Answer:

The reasonable power will be "0.234 μW".

Explanation:

The given values are:

P = 15 μW

d = 175 m

As we know,

Propagation follows inverse cube power law, then

∴  [tex]Power \ \alpha \ \frac{1}{d^3}[/tex]

⇒ [tex]Power=\frac{K}{d^3}[/tex]

On substituting the estimated values, we get

⇒  [tex]15\times 10^{-6}=\frac{K}{(173)^3}[/tex]

⇒  [tex]K=15\times (175)^3\times 10^{-6}[/tex]

Now,

"P" at 0.7 km or 700 m from BS will be:

⇒  [tex]P=\frac{K}{d^3}[/tex]

⇒  [tex]P=\frac{15\times (175)^3\times 10^{-6}}{(700)^3}[/tex]

⇒  [tex]P=0.234 \ \mu W[/tex]

Ani need free points cus i have zero sry

Explanation:

they are all eukaryotic cells

Answer:

they are all unicellular

Explanation:

Our technological world has become deeply dependent upon the continuous availability of electrical power. In most countries, commercial power is made available via nationwide grids, interconnecting numerous generating stations to the loads. The grid must supply basic national needs of residential, lighting, heating, refrigeration, air conditioning, and transportation as well as critical supply to governmental, industrial, financial, commercial, medical and communications communities. Commercial power literally enables today’s modern world to function at its busy pace. Sophisticated technology has reached deeply into our homes and careers, and with the advent of e-commerce is continually changing the way we interact with the rest of the world. Intelligent technology demands power that is free of interruption or disturbance. The consequences of large-scale power incidents are well documented. A recent study in the USA has shown that industrial and digital business firms are losing $45.7 billion per year due to power interruptions.1 Across all business sectors, an estimated $104 billion to $164 billion is lost due to interruptions with another $15 billion to $24 billion due to all other power quality problems. In industrial automatic processing, whole production lines can go out of control, creating hazardous situations for onsite personnel and expensive material waste. Loss of processing in a large financial corporation can cost thousands of unrecoverable dollars per minute of downtime, as well as many hours of recovery time to follow. Program and data corruption caused by a power interruption can create problems for software recovery operations that may take weeks to resolve. Many power problems originate in the commercial power grid, which, with its thousands of miles of transmission lines, is subject to weather conditions such as hurricanes, lightning storms, snow, ice, and flooding along with equipment failure, traffic accidents and major switching operations. Also, power problems affecting today’s technological equipment are often generated locally within a facility from any number of situations, such as local construction, heavy startup loads, faulty distribution components, and even typical background electrical noise

Hey There!!~ I think the best answer is A). An event in which electricity coming into a device exceeds 120 volts for three or more nanoseconds an event in. Because, An unexpected increase in the amplitude of a signal that lasts for two or less nanoseconds anything more is considered a surge. If not properly protected, a power spike can cause damage to any electrical component, including a computer. And, All electrical devices, including your computer, should have a surge protector to help prevent them from becoming damaged when an electrical surge occurs.

Hope This Helps....!!~

Answer:

2

Explanation:

hope this helps you! :)

The answers B which is Talking to customers more than listening!

PLS MARK AS BRAINLIEST

Answer and Explanation:

Technicians who travel constantly and are most likely working from remote locations would require information support that is ready and available as at when needed (24/7). The following would help them access technical information easily:

Internet knowledge based system: this could be like a encyclopedia for technicians where they could easily search up information they need for their work from anywhere.

Web-based system : this can help technicians ask or search for technical information online and also communicate and give out information to other technicians.

fax and email: a ready and available email support system and fax would boost information availability to technicians

Based on the information given, the system that should be implemented should be one where the information will be stored in a database.

Also, the system will have an application that the technicians will use to login into the system. It should also be noted that the system will be divided based on the technician's roles.

In this case, the technicians will have different access that they can use to get the data from the database.

Lastly, encryption should be used to secure the data.

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Answer:

Here is the JAVA program:    

import java.util.Scanner;

public class Operations{      

  public static void main(String[] args) {      

    Scanner input= new Scanner(System.in);

      float first,second;

      System.out.println("Enter first number:");

       first = input.nextFloat();

       System.out.println("Enter second number:");

       second = input.nextFloat();

       System.out.println("Enter 1 for Addition, 2 for Subtraction 3 for Multiplication, 4 for Division and 5 for Average:");

       int choice;

       choice = input.nextInt();

       switch (choice){

       case 1: //calls add method to perform addition

           System.out.println("Addition result = " + add(first,second));

           break;

       case 2: //calls sub method to perform subtraction

           System.out.println("Subtraction result = " + sub(first,second));

           break;      

       case 3: //calls mul method to perform multiplication

           System.out.println("Multiplication result = " +mul(first,second));

           break;

       case 4: //calls div method to perform division

           System.out.println("Division result = " +div(first,second));

           break;

       case 5: //calls average method to compute average

           System.out.println("Average = " +average(first,second));

           break;

       default: //if user enters anything other than the provided options

               System.out.println("Invalid Option"); }}

   public static float add(float first, float second)    {

       float result = first + second;

       if(result<0)

       {System.out.println("Oops option 1 is returning a negative number that is: ");      }        

       return result;    }

   public static float sub(float first, float second)    {

       float result = first - second;

       if(result<0){System.out.println("Oops option 2 is returning negative number that is: ");}        

       return result;    }

   public static float mul(float first, float second)    {

       float result = first*second;

        if(result<0)

        {System.out.println("Oops option 3 is returning negative number that is: ");}        

       return result;    }

   public static float div(float first, float second){

       if(second==0)

       {System.out.println("Division by 0");}

       float result = first/second;

        if(result<0){System.out.println("Oops option 4 is returning negative number that is: ");}      

       return result;    }    

   public static float average (float first,float second)    {

       Scanner inp= new Scanner(System.in);

       float first2,second2;

        System.out.println("Enter two more numbers:");

        System.out.println("Enter first number:");

       first2 = inp.nextInt();

      System.out.println("Enter second number:");

       second2 = inp.nextInt();

       float result;

       float sum = first+second+first2+second2;

       result = sum/4;

        if(result<0)

        {System.out.println("Oops option 5 is returning negative number that is: ");}        

       return result;  }}

Explanation:

The above program first prompts the user to enter two numbers. Here the data type of two number is float in order to accept floating numbers. The switch statement contains cases which execute according to the choice of user. The choice available to user is: 1,2,3,4 and 5

If the user selects 1 then the case 1 executes which calls the method add. The method add takes two numbers as parameters, adds the two numbers and returns the result of the addition. This result is displayed on output screen. However if the result of addition is a negative number then the message: "Oops option 1 is returning the negative number that is:" is displayed on the screen along with the negative answer of that addition.

If the user selects 2 then the case 2 executes which calls the method sub. The method works same as add but instead of addition, sub method takes two numbers as parameters, subtracts them and returns the result of the subtraction.

If the user selects 3 then the case 3 executes which calls the method mul. The method mul takes two numbers as parameters, multiplies them and returns the result of the multiplication.

If the user selects 4 then the case 4 executes which calls the method div. The method div takes two numbers as parameters and checks if the denominator i.e. second number is 0. If its 0 then Division by 0 message is displayed along with result i.e. infinity. If second number is not 0 then method divides the numbers and returns the result of the division.

If the user selects 5 then the case 5 executes which calls the method average. The average method then  asks the user to enter two more numbers first2 and second2 and takes the sum of all four numbers i.e. first, second, first2 and second2. Then the result of sum is divided by 4 to compute average. The method returns the average of these four numbers.

Answer:

c. 20

Explanation:

The program works as following:

x is initialized to 10

y is initialized to 30

if (x < 0) statement checks if the value of x is less than 0. This condition evaluates to false because x=10 so 10 is greater than 0. So the statement inside the body of this if condition will not execute. Hence the program control moves to the else if part:

else if (x < 10) statement checks if the value of x is less than 10. This condition evaluates to false because x=10 so x is equal to 10 and not less than 10. So the program control moves to the else part and the statement in else part executes:

else {

y = 20;

}

This statement in else part assigns the value 20 to y

Then the program control moves to the following statement:

cout << y;

This statement prints the value of y. As the else part assigns 20 to y so the output is:

20

Answer:

True

Explanation:

It is possible to organize a classroom environment to promote social interaction and minimize potential points of stress

Answer:

The list of those two situations is given below.

Explanation:

Case 1:

Yet another condition for manual cluster formation that wasn't an improvement would be whenever the number of observations measured is higher than even the machine can accommodate.  

Case 2:

The second scenario which isn't an improvement whenever the original data is recognized for automated cluster analysis, and therefore also implementing the algorithms doesn't generate any extra details.

Answer: provided in the explanation section

Explanation:

FCC is the abbreviation for The Federal Communications Commission (United States Federal Communication Commission). It is, as a rule, an administrative area. It is a free Federal administrative office of the United States government dependable straightforwardly to Congress, built up by the Communications Act and made by resolution to manage interstate and worldwide interchanges by radio, TV, wire, satellite, and link. It includes an investigation on pending changes in the remote world.

FCC certainly has consequences for the present status of 5 GHz Bridging Spectrum. As far as possible one of the U-NII groups which can be utilized outside with the 5.725-5.825 band which is perfect fitting open air tasks. The 2.4 GHz ISM band might be utilized outside where the yield power at the purposeful radiator can't surpass 1 watt. In the United States, the FCC manages the frequencies utilized, the yield power levels, and the open air utilization restrictions.

There is an effect of the FCC 5 GHz U-NII report and a request on Wi-Fi Networks. FCC's activities are to change some specialized principles for the 5 GHz U-NII groups. The specialized change that is affirmed is - U-NII 1 band (5.150 - 5.250 GHz) indoor activity limitation being evacuated permitting utilization of the band for open air hotspots, WISPs, and scaffold joins. There will be a development of open hotspots profiting by this change. The FCC considers 11 channels under the Operating Frequencies.

The FCC has characterized UNII-2 and UNII-3 groups, the two of which had four channels. The channels were divided 20 MHz separated with a RF range data transmission of 20 MHz giving non-covering channels utilizing 20 MHz channel width.

The UNII-2 band was assigned additionally for open air tasks and allowed outside recieving wires. The UNII-3 band was proposed for open air connect items and allowed outer radio wires, however the UNII-3 band is likewise utilized for outside 802.11a/n/air conditioning WLANs.

FCC (America) underpins Operating Frequency Range for 802.11b and 802.11g on Center Frequency: 2412, 2417, 2422, 2427, 2432, 2437, 2442, 2447, 2452, 2457, 2462. FCC has delivered an amendment to the guidelines covering the 5 GHz 802.11a channel utilization. This correction has included 11 extra channels, carrying the accessible channel's ability to 23 channels.

As far as possible your complete force yield by utilizing a sliding scale when you set up a significant distance Wi-Fi connect. The scale really begins at 30 dBm of enhancement power utilizing a 6 dBi directional reception apparatus. For each 1 dBm drop in enhancement power, there would be an expansion in the intensity of directional radio wire by 3 dBi. The FCC permits this sliding scale since when you utilize a bigger highlight point radio wire, your shaft example will cover less territory and cause less impedance for other people.

Answer:

O( n ) of the 100 element array, where "n" is the item location index.

Explanation:

From the meaning of the word "sequential", the definition of this algorithm should be defined. Sequential donotes a continuously increasing value or event, like numbers, increasing by one in an arithmetic progression.

A list in programming is a mutable data structure that holds data in indexed locations, which can be accessed linearly or randomly. To sequentially access a location in a list, the algorithm starts from the first item and searches to the required indexed location of the search, the big-O notation is O( n ), where n is the index location of the item searched.

Answer:

Apologize for the inconvenience and proceed with any necessary assistance.

Explanation:

Remember, the rules of business communication entails a friendly disposition to clients. We note here that George is a user or what we may client, and has an unresolved complaint.

Consequently, apollogizing to him may open him further into the details of the issue as you now work to resolve his complaints.

Answer:

I would state that performance is not the main challenge of an atm, nor is multi-threading. Robustness and provable correctness is of greater importance, and those are much easier to achieve using a single-threaded solution.

Answer:

Two bits would be not enough.

Four bits would be enough.

Explanation:

With two bits, only 4 unique binary numbers are available. They are:

00

01

10

11

And since there are 5 lowercase vowel letters and 5 uppercase vowel letters in the English language, making a total of 10 vowel letters, two bits will only cater for 4 of the 10 letters and as such will not be enough.

With three bits, only 8 unique binary numbers are available. They are:

000

001

010

011

100

101

110

111

Three bits will therefore only cater for 8 of the 10 letters and as such will not be enough.

With four bits however, there are 16 binary numbers available. They are:

0000

0001

0010

0011

0100

0101

0110

0111

1000

1001

1010

1011

1100

1101

1110

1111

Four bits are more than enough to cater for all the 10 vowel letters in the English language.

PS: The number of unique binary numbers that can be found in n bits is given by;

2ⁿ

So;

If we have 3 bits, number of unique binary numbers will be

2³ = 8

If we have 6 bits, number of unique binary numbers will be

2⁶ = 64

Using bits concepts, it is found that two bits is not enough to assign a binary number to each vowel in the English language, as two bits can represent at most 4 symbols, and there are 5 vowels.

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