IT professionals have a responsibility to educate employees about the risks of hot spots. Which of the following are risks associated with hot spots? Check all of the boxes that apply.

third-party viewing

unsecured public network

potential for computer hackers

unauthorized use

Answer:

Yes

Explanation:

Online privacy is a controversial topic due to the fact that it's a very hard thing to navigate. Some websites use cookies that are used to store your data so in a way there taking your privacy away which is controversial because of the way they use the information. Some websites store it for use of ads while others sell it. This issue is applicable to me and my peers because of the way we use technology. It can be used to steal my information about where I live and what I look up online. Also, the information stored could have my credit or debit card credentials. This issue should be a federal and nationwide issue because this is an everyday occurrence and leaves tons of people in crushing   debt every year.

Answer:

The answer to this question is given below in the explanation section. However, the correct option is Technician B.

Explanation:

There are eight steps procedures to diagnose the engine.  

Step 1 Verify the Problem

Step 2 Perform a Thorough Visual Inspection and Basic Tests

Step 3 Retrieve the Diagnostic Trouble Codes (DTCs)

Step 4 Check for Technical Service Bulletins (TSBs)

Step 5 Look Carefully at Scan Tool Data

Step 6 Narrow the Problem to a System or Cylinder

Step 7 Repair the Problem and Determine the Root Cause

Step 8 Verify the Repair and Clear Any Stored DTCs

So the correct technician is Technician B that says that the second step is to perform a thorough visual inspection.

Answer:

Application

Explanation:

Application software comes in many forms like apps, and even on computers. The software is most common on computers of all kinds while mobile applications are most common on cellular devices.

Answer:

Colunm Chart

Explanation:

Trust me

Answer:

Nmap development list

Explanation:

The list being mentioned in this question is known as the Nmap development list. This list basically acts as an information gathering and analytical tool. It allows the user to easily roll out and integrate Nmap tools on a network in order to easily detect all of the IP addresses that are connected as well as analyze all of the details regarding each connected individual system. All of this information is highly valuable to a developer and facilitates the development process.

Answer:

Modify

If scores[index] > highest then highest = scores[index]

End Of highest

Name = students[index]

End For Display

to

If scores[index] > highest then highest = scores[index]

Name = students[index]

End Of highest

End For Display

Explanation:

In the code, you posted the code segment that gets the name of the student with the highest score is outside the if condition that determines the highest.

To make correction, we only need to bring this code segment into the loop.

See Answer

Answer: document

Explanation:

Answer:

Please find the code and its output in the attached file.

Explanation:

In the above-given code, an interface "Runner" is defined, inside the interface, an abstract method run is declared.

In the next step, three class "Athlete, Machine, and PoliticalCandidate" s defined that implements the run method, and use the print message that holds a given value as a message.

In the next step, a class "DemoRunners" is defined, and inside the main method, the three-class object is declared, which calls the run method.

Answer:

4096 VLANs

Explanation:

A VLAN (virtual LAN) is a group of devices on one or more LAN connected to each other without physical connections. VLANs help reduce collisions.

An 802.1Q Ethernet frame header has VLAN ID of 12 bit VLAN field. Hence the maximum number of possible VLAN ID is 4096 (2¹²).  This means that a switch supporting the 802.1Q protocol can have a maximum of 4096 VLANs

A lot of VLANs ID are supported by a switch. The maximum number of VLANs that can be configured on a switch supporting the 802.1Q protocol is 4,094 VLANS.

But that of 0x000 and 0xFFF are set apart. This therefore makes or leaves it as 4,094 possible VLANS limits. Under IEEE 802.1Q, the maximum number of VLANs that is found on an Ethernet network is 4,094.

Learn more about VLANs from

https://brainly.com/question/25867685

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

Based on the information given regarding CPU scheduling, the correct option is C. The process's state will be changed from running to blocked.

It should be noted that in a system where Round Robin is used for CPU scheduling, when a process cannot finish its computation during its current time quantum, the process's state will be changed from running to blocked.

It should be noted that a prices transition to a blocked state occurs when it's waiting for some events like a particular resource becoming available.

Learn more about CPU scheduling on:

https://brainly.com/question/19999569

Answer:

I think it's Pandora, though I am familiar with others

Answer:

CNN

Explanation:

Answer:

True

Operating System

Booting

Answer:

To create a pivot table, select the columns to pivot and click on the insert option, click on the pivot table option and select the data columns for the pivot, verify the table range, select the location for the pivot and click ok. To format a column, select the columns and click the number option on the home tab, select the currency option and click on the number of decimal places

Explanation:

Microsoft Excel is a great tool for data analysis and visualization. It has several mathematical, engineering, statistical, and graphical tools for working with data.

A pivot-table is an essential tool for describing and comparing data of different types.

The steps to follow in order to produce a Pivot table would be as mentioned below:

Learn more about 'Pivot Table' here:

brainly.com/question/13298479

Answer:

b. tags

Explanation:

When you write HTML code, you use tags to describe the structure of information on a webpage. These tags are represented by the following symbols <>. All of HTML is written using different types of tags such as <body>, <main>, <div>, <nav>, etc. Each of these serves a different purpose but are all used for structuring the specific information on a website so that the information is well organized and is not all on top of each other. This also allows for specific sections to be easily targeted and styles separately from the other sections.

Answer:

The answer is below

Explanation:

Adjacency list is a technique in a computer science that is used for representing graph. It deals with a gathering of unorganized lists utilized to illustrate a limited graph. In this method, each list depicts the group of data of a peak in the graph

Adjacency List are most preferred to Adjacency Matrix in some cases which are:

1.  When the graph to is required to be sparsely.

2.  For iterability, Adjacent List is more preferable

Answer:

Well, First of all, use Linear

Explanation:

My sis always tries to explain it to me even though I know already, I can get her to give you so much explanations XD

I have the Longest explanation possible but it won't let me say it after 20 min of writing

Answer:

just tryin' to help you

Explanation:

The three stages of computing are input, processing and output. A computer works through these stages by 'running' a program. A program is a set of step-by-step instructions which tells the computer exactly what to do with input in order to produce the required output.

Answer:

The answer to this question is given below in the explanation section

Explanation:

The correct option for this question is Animation tab.

Animation tab in PowerPoint ribbon is a unique tab that is not found in other office applications such as in word, excel, outlook, publisher etc.

Because in PowerPoint you can use animation to make your slides animated and all animation can be managed and animation-related settings, you can find in the animation tab.

However, other tabs such as Home, Insert, and View are common in all office applications.

Answer:

See Explanation

Explanation:

Your program is correct and doesn't need an attachment.

However, there's a mismatch in placement of curly braces in your program

{

}

I've made corrections to that and I've added the corrected program as an attachment.

Aside that, there's no other thing to be corrected in your program.

Use another compiler to compile your program is you are not getting the required output.

Answer:

four

Explanation:

quad means four so it runs four times faster

Answer:

lookup value

Explanation:

Answer:

270 nsec

Explanation:

Ripple-carry adder is a combination of multiple full-adders. It is relatively slow as each full-adder waits for the output of a previous full-adder for its input.

Formula to calculate the delay of a ripple-carry adder is;

  = 2( n + 1 ) x D

delay in a full-adder = 150 nsec.

number of full-adders = number of ripple-carry bits = 8

 = 2 ( 8 + 1 ) x 150

 = 18 x 150

 = 270 nsec

Answer:

Here is the JAVA program:

import java.util.*;  

public class Solution {    // class name

   public static String getSmallestAndLargest(String s, int k) {   //method that takes a string s and and integer k and returns lexicographically smallest and largest substrings

       String smallest = "";   //stores the smallest substring

       String largest = "";   //stores the largest substring

       smallest = largest = s.substring(0, k);  //sets the smallest and largest to substring from 0-th start index and k-th end index of string s

       for(int i = 0;i<=s.length()-k;i++){  //iterates through the string s till length()-k

            String subString = s.substring(i,i+k);  //stores the substring of string s from ith index to i+k th index

            if(i == 0){ //if i is equal to 0

                smallest = subString;              }  //assigns subString to smallest

            if(subString.compareTo(largest)>0){ //checks if the subString is lexicographically greater than largest

                largest = subString;  //sets subString to largest

            }else if(subString.compareTo(smallest)<0)  //checks if the subString is lexicographically less than smallest

                smallest = subString;       }       //sets subString to smallest

       return smallest + "\n" + largest;     }  //returns the lexicographically smallest and largest substrings

   public static void main(String[] args) {  //start of main method

       Scanner scan = new Scanner(System.in);  //creates Scanner object

       String s = scan.next();  //scans and reads input string from user

       int k = scan.nextInt();  //scans and reads integer k from user

       scan.close();  

       System.out.println(getSmallestAndLargest(s, k));      }  }  //calls method by passing string s and integer k to it to display lexicographically smallest and lexicographically largest substring

Explanation:

The program takes a string s and an integer k and passes them to function getSmallestAndLargest that returns the lexicographically smallest and lexicographically largest substring. The method works as follows:

Lets say s = helloworld and k = 3

       smallest = largest = s.substring(0, k);

s.substring(0, k);  is returns the substring from 0th index to k-th index so it gives substring hel

       for(int i = 0;i<=s.length()-k;i++) This loop iterates through the string s till s.length()-k times

s.length()-k is equal to 7 in this example

At first iteration:

i = 0

i<=s.length()-k is true  so program enters the body of loop

String subString = s.substring(i,i+k); this becomes:

subString = s.substring(0,3);

subString = "hel"

if(i == 0) this is true so:

smallest = subString;

smallest = "hel"

At second iteration:

i = 1

i<=s.length()-k is true  so program enters the body of loop

String subString = s.substring(i,i+k); this becomes:

subString = s.substring(1,4);

subString = "ell"

if(subString.compareTo(smallest)<0) this condition is true because the subString ell is compared to smallest hel and it is lexographically less than smallest so :

smallest = subString;

smallest = "ell"

So at each iteration 3 characters of string s are taken and if and else if condition checks if these characters are lexicographically equal, smaller or larger and the values of largest and smallest change accordingly

After the loop ends the statement return smallest + "\n" + largest; executes which returns the smallest and largest substrings. So the output of the entire program with given example is:

ell                                                                                                                                           wor

Here ell is the lexicographically  smallest substring and wor is lexicographically  largest substring in the string helloworld

The screenshot of the program along with its output is attached.

Answer:

mobile computing system

Explanation:

Answer:

mobile computing system... C

Answer:

Follows are the code to this question:

def build_word_counter(string):#defining a method build_word_counter that accepts string as a parameter  

   d = dict()#defining d variable as a dictionary

   for x in string:#defining for loop that use string

       x = x.lower()#Use lower method  

       if not d.get(x):#defining if block that holds value in d variable

           d[x] = 1#use dictionary to hold value in 1

       else:#defining else block

           d[x] += 1#use dictionary to increment value by 1

   return d#return dictionary

print(build_word_counter(["Like","like","LIKE"]))#use print method to call method

def build_letter_distribution(string):#defining a method build_letter_distribution that accepts string variable

   d = dict()#defining d variable as a dictionary

   for i in string:#defining for loop to count string value

       for j in i:#defining for loop to hold string as number

           if not d.get(j):#defining if block that doesn't get value in dictionary  

               d[j] = 1#hold value in dictionary  

           else:#defining else block

               d[j] += 1#use dictionary to increment the dictionary value

   return d#return dictionary

print(build_letter_distribution(["Like","test","abcdEFG"]))#use print method to return its value

Output:

please find the attached file.

Explanation:

In the first program a method, "build_word_counter" is defined that accepts a string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the for loop to hold string value and convert all value into lower case.

In the next step, a conditional statement is used that holds value in the dictionary and count its word value.

In the second program a method, "build_letter_distribution" is defined that holds string variable in its parameter, and inside the method, a dictionary variable "d" is defined that uses the two for loop and in if the block, it holds value in the dictionary and returns its value, and use print method to print its return its value.

Answer:

The correct answer to this question is given below in the explanation section.

Explanation:

in most programming languages, the print() function is used to display a string value to the screen. Because, the print function prints all the string given in it as a parameter.

for example: to print hello world.

we use the function to print hello world as print("hello world").

However, it noted that other options are not correct because the main() function is an entry point of a program and it does not print string value to the screen. while run and show function do not print string value of screen also.

Answer:

in python print()

Answer:

Search

Explanation:

Because you are searching up a specific recording using keywords.

I hope this helps

Answer:

Filter

Explanation:

I got it correct for a quiz.