Your answer is July.
From least to greastest:
January: $50
February: $80
September: $80
May: $95
April: $100
March: $110
June: $250
August: $300
July: $320
I hope this helps!
The month that had the largest deposit is the month of; July
How do you Interpret a Histogram?
From the given histogram with savings account on the x-axis and amount deposited on the y-axis, we can see the following amounts deposited for each month as follows;
January = $50February = $80March = $110April = $100May = $95June: $250July: $320August: $300September: $80The month with the largest deposit is clearly July
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The probability that a person will develop the flu after getting a flu shot is 0.04. In a random sample of 100 people in a community who got a flu shot, what is the probability that 5 or more of the 100 people will get the flu
Answer:
0.3711 = 37.11% probability that 5 or more of the 100 people will get the flu
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they will develop the flu after getting the shot, or they will not. The probability of a person developing the flu after getting the shot is independent of any other person, which means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The probability that a person will develop the flu after getting a flu shot is 0.04.
This means that [tex]p = 0.04[/tex]
Random sample of 100 people:
This means that [tex]n = 100[/tex]
What is the probability that 5 or more of the 100 people will get the flu?
This is:
[tex]P(X \geq 5) = 1 - P(X < 5)[/tex]
In which
[tex]P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)[/tex]
So
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{100,0}.(0.04)^{0}.(0.96)^{100} = 0.0169[/tex]
[tex]P(X = 1) = C_{100,1}.(0.04)^{1}.(0.96)^{99} = 0.0703[/tex]
[tex]P(X = 2) = C_{100,2}.(0.04)^{2}.(0.96)^{98} = 0.1450[/tex]
[tex]P(X = 3) = C_{100,3}.(0.04)^{3}.(0.96)^{97} = 0.1973[/tex]
[tex]P(X = 4) = C_{100,4}.(0.04)^{4}.(0.96)^{96} = 0.1994[/tex]
Then
[tex]P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0169 + 0.0703 + 0.1450 + 0.1973 + 0.1994 = 0.6289[/tex]
[tex]P(X \geq 5) = 1 - P(X < 5) = 1 - 0.6289 = 0.3711[/tex]
0.3711 = 37.11% probability that 5 or more of the 100 people will get the flu
Jerome is cooking dinner. He needs 8 ounces of broccoli for each person. Part A: Jerome is not sure how many people will come to dinner. Write an expression with a variable that represents the amount of broccoli Jerome needs for dinner. Identify what the variable represents. Part B: If Jerome has 32 ounces of broccoli, how many people can he feed? Create an equation and show all work to solve it.
Answer:
A. 8x = amount of broccoli needed
B. 4 people; 32÷8=4
Step-by-step explanation:
A. the variable (x) represents the amount of people.
B. 32 ounces divided by 8 ounces is enough for four people.
29. Family income in the middle class: Bauer et al. (2011) identified the median income of a middle-class family in their sample to be $84,200 annually; the mean family income was $85,300 annually. In their data, the lowest family income reported in this group was $65,100 annually, and the highest family income reported was $103,400 annually. Based on the data given, was the mean an appropriate value to summarize these data
Answer:
No it is not
Step-by-step explanation:
The median is 84200
The mean is 85300
Low income is 65100
High income is 103400
From this information, we can see a skewed data. The mean would not be a good estimate value. Rather the center (median) would be more appropriate.
When we calculate the middle value for this data
65100+103400 = 168500/2 = 84250
84250 is closer to the median score of 84200. The median is best in the presence of outliers.
A wooden log 10 meters long is leaning against a vertical wall with its other end on the ground. The top end of the log is sliding down the wall. When the top end is 6 meters from the ground, it slides down at 2m/sec. How fast is the bottom moving away from the wall at this instant?
Answer:
Step-by-step explanation:
This is a related rates problem from calculus using implicit differentiation. The main equation is Pythagorean's Theorem. Basically, what we are looking for is [tex]\frac{dx}{dt}[/tex] when y = 6 and [tex]\frac{dy}{dt}=-2[/tex].
The equation for Pythagorean's Theorem is
[tex]x^2+y^2=c^2[/tex] where x and y are the legs and c is the hypotenuse. The length of the hypotenuse is 10, so when we find the derivative of this function with respect to time, and using implicit differentiation, we get:
[tex]2x\frac{dx}{dt}+2y\frac{dy}{dt}=0[/tex] and divide everything by 2 to simplify:
[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex]. Looking at that equation, it looks like we need a value for x, y, [tex]\frac{dx}{dt}[/tex] and [tex]\frac{dy}{dt}[/tex].
Since we are looking for [tex]\frac{dx}{dt}[/tex], that can be our only unknown and everything else has to have a value. So what do we know?
If we construct a right triangle with 10 as the hypotenuse and use 6 for y, we can solve for x (which is the only unknown we have, actually). Using Pythagorean's Theorem to solve for x:
[tex]x^2+6^2=10^2[/tex] and
[tex]x^2+36=100[/tex] and
[tex]x^2=64[/tex] so
x = 8.
NOW we can fill in the derivative and solve for [tex]\frac{dx}{dt}[/tex].
Remember the derivative is
[tex]x\frac{dx}{dt}+y\frac{dy}{dt}=0[/tex] so
[tex]8\frac{dx}{dt}+6(-2)=0[/tex] and
[tex]8\frac{dx}{dt}-12=0[/tex] and
[tex]8\frac{dx}{dt}=12[/tex] so
[tex]\frac{dx}{dt}=\frac{12}{8}=\frac{6}{4}=\frac{3}{2}=1.5 m/sec[/tex]
A papaya is accidentally dropped from a bridge, which is 30 m above the water. Ignoring air resistance, the papaya's speed just before it hits the water will be __________ m/s.
Answer:
24 .30ms is the answer I think so if the answer is correct plz mark me as brainliest.
The papaya's speed just before it hits the water will be 24.24 m/s.
What is speed?The rate at which objects moves is called speed. It is given by
[tex]s = \frac{d}{t}[/tex]
An object held above the ground has a potential energy related to the height at which it is held,
PE = mgh
If you drop the object, its potential energy will become the kinetic energy of motion:
KE = ½ mv²
½ mv² = mgh
v = √(2gh)
v = √(2*9.8*30)
v = 24.24 m/s
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Calculate the perimeter
Answer:
sorry i cannot help you
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500. Is there sufficient evidence at the ?= 0.05 level to conclude that the mean cost has increased. Solve the question by traditional approach.
Answer:
The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.
Step-by-step explanation:
The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.
At the null hypothesis, we test if the mean cost is still the same, that is:
[tex]H_0: \mu = 13252[/tex]
At the alternative hypothesis, we test if the mean cost has increased, that is:
[tex]H_1: \mu > 13252[/tex]
The test statistic is:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.
13252 is tested at the null hypothesis:
This means that [tex]\mu = 13252[/tex]
The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.
This means that [tex]n = 20, X = 15560, s = 3500[/tex]
Value of the test statistic:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}[/tex]
[tex]t = 2.95[/tex]
P-value of the test and decision:
The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.
The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.
A survey of 249 people asks about their favorite flavor of ice cream. The results of this survey, broken down by the age group of the respondent and their favorite flavor, are as follows:
Chocolate Vanilla Strawberry
Children 40 10 44
Teens 34 10 38
Adults 17 43 13
If one person is chosen at random, find the probability that the person:______.
a) is an adult.
b) likes chocolate the best.
c) is an adult OR likes vanilla the best.
d) is a child AND likes vanilla the best.
e) likes strawberry the best, GIVEN that the person is a child.
f) is a child, GIVEN that the person likes strawberry the best.
Answer:
a) [tex]P(Adult)=\frac{73}{249}=0.2932=29.32%[/tex]
b) [tex]P(Chocolate)=\frac{91}{249}=0.3655=36.55%[/tex]
c) [tex]P(AdultorVanilla)=\frac{31}{83}=0.3734=37.34%[/tex]
d) [tex]P(ChildandVanilla)=\frac{10}{249}=0.0402=4.02%[/tex]
e) [tex]P(Strawberry/Child)=\frac{22}{47}=0.4681=46.81%[/tex]
f) [tex]P(Child/strawberry)=\frac{44}{95}=0.4632=46.32%[/tex]
Step-by-step explanation:
a)
In order to solve part a of the problem, we need to find the number of adults in the survey and divide them into the number of people in the survey by using the following formula>
[tex]P=\frac{desired}{possible}[/tex]
In this case we have a total of 17+43+13 adults which gives us 73 adults and a total of 249 people surveyed so we get:
[tex]P(Adults)=\frac{73}{249}=0.2932=29.32%[/tex]
b)
The same principle works for part b
there are: 40+34+17=91 people who likes chocolate ice cream the best so the probability is:
[tex]P(Chocolate)=\frac{91}{249}=0.3655=36.55%[/tex]
c)
when it comes to the or statement, we can use the following formula:
P(A or B) = P(A) + P(B) - P( A and B)
In this case:
[tex]P(Adult)=\frac{73}{249}[/tex]
[tex]P(Vanilla)=\frac{10+10+43}{249}=\frac{63}{249}[/tex]
[tex]P(AdultandVanilla)=\frac{43}{249}[/tex]
so:
[tex]P(AdultorVanilla)=\frac{73}{249}+\frac{63}{249}-\frac{43}{249}[/tex]
[tex]P(AdultorVanilla)=\frac{31}{83}=0.3734=37.34%[/tex]
d)
Is a child and likes vanilla the best.
In the table we can see that 10 children like vanilla so the probability is:
[tex]P(ChildandVanilla)=\frac{10}{249}=0.0402=4.02%[/tex]
e)
Likes strawberry the best, GIVEN that the person is a child.
In this case we can make use of the following formula:
[tex]P(B/A)=\frac{P(AandB)}{P(A)}[/tex]
so we can get the desired probabilities. First, for the probability of the person liking strawberry the best and the person being a child, we know that 44 children like strawberry the best, so the probability is:
[tex]P(childrenandstrawberry)=\frac{44}{249}[/tex]
Then, we know there are 40+10+44=94 children, so the probability for the person being a child is:
[tex]P(Child)=\frac{94}{249}[/tex]
Therefore:
[tex]P(Strawberry/Child)=\frac{\frac{44}{249}}{\frac{94}{249}}[/tex]
[tex]P(Strawberry/Child)=\frac{22}{47}=0.4681=46.81%[/tex]
f)
The same works for the probability of the person being a child given that the person likes strawberry the best.
First, for the probability of the person liking strawberry the best and the person being a child, we know that 44 children like strawberry the best, so the probability is:
[tex]P(childrenandstrawberry)=\frac{44}{249}[/tex]
Then, we know there are 44+38+13 persons like strawberry, so the probability for the person liking strawberry is:
[tex]P(Child)=\frac{95}{249}[/tex]
Therefore:
[tex]P(Child/Strawberry)=\frac{\frac{44}{249}}{\frac{95}{249}}[/tex]
[tex]P(Child/strawberry)=\frac{44}{95}=0.4632=46.32%[/tex]
Which expression is equivalent to 3 square root of x^5*y
Answer:
√3 x^5y
First, let's do √3
√3=1.7
1.7 • x^5 • y
if you want
1.7 • X^4• x• y.
There are tons of equivalent's!
HELP HELP QUICK QUICK
Answer:
multiplication by -1 will reflect over the x-axis
multiplication by a positive number will "scale" or "stretch" the function
Step-by-step explanation:
Question 4 of 10
Is the graph increasing, decreasing, or constant?
O A. Decreasing
O B. Constant
O C. Increasing
what is the H.C.F of 30 and 45
Answer:
15
Hope this helped ^^
2[30 5[45
3[15 3[9
5[5 3[3
[1 [1
30=2*3*5*1
45=5*3*3*1 HCF= 3*1=3
hope its helps you
keep smiling be happy stay safe
Think about tossing two coins.
What is
P (H on first coin)? ………………………….
P (H on second coin)? ……………………..
List the paired outcomes for tossing two coins: ………………………………
How many ways are there for two coins to land? ………………………
What is P (HH)? …………………………
Given:
Two coins are tossed.
To find:
1. P(H on first coin)?
2. P(H on second coin)?
3. List the paired outcomes for tossing two coins.
4. How many ways are there for two coins to land?
5. What is P(HH)?
Solution:
If a a coin is tossed, then we have to possible outcomes, i.e., heads (H) and tails (T).
It is given that two coins are tossed.
1. The probability of getting a heads on first coin is:
[tex]P(H \text{ on first coin})=\dfrac{1}{2}[/tex]
2. The probability of getting a heads on second coin is:
[tex]P(H \text{ on second coin})=\dfrac{1}{2}[/tex]
3. If two coins are tossed, then the total possible outcomes are:
[tex]\{HH,HT,TH,TT\}[/tex]
4. The number of ways for two coins to land is 4.
5. The probability of the heads on both tosses is:
[tex]P(HH)=\dfrac{1}{4}[/tex]
Therefore, the required solution are:
1. [tex]P(H \text{ on first coin})=\dfrac{1}{2}[/tex]
2. [tex]P(H \text{ on second coin})=\dfrac{1}{2}[/tex]
3. List of possible outcomes is [tex]\{HH,HT,TH,TT\}[/tex].
4. Number of possible outcomes is 4.
5. [tex]P(HH)=\dfrac{1}{4}[/tex]
simplify 3x⁵y³ ÷2y² step by step
Answer:
3/2 x^5 y
Step-by-step explanation:
3x^5y^3
----------------
2y^2
Simplify the y terms
y^3 / y^2 = y^(3-2) = y
3/2 x^5 y
Answer:
[tex] \frac{3}{2} x {}^{5} y {}^{} [/tex]
Step-by-step explanation:
it's all in the image
I need help :)What’s m
Answer:
[tex] \large{ \tt{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]
[tex] \large{ \tt{⇢m \: \angle \: GHI= m \: \angle \: GHQ + m \: \angle \: QHI}}[/tex]
[tex] \large{ \tt{➝14x + 6 = 3x - 3 + 130 \degree}}[/tex]
[tex] \large{ \tt{➝14x + 6 = 3x + 127}}[/tex]
[tex] \large{ \tt{➝ \: 14x - 3x = 127 - 6}}[/tex]
[tex] \large{ \tt{➝ \: 11x = 121}}[/tex]
[tex] \large{ \tt{➝ \: x = \frac{121}{11} }}[/tex]
[tex] \large{ \tt{➝ \: x = 11}}[/tex]
[tex] \large{ \tt{✣ \: REPLACING \: VALUE}} : [/tex]
[tex] \large{ \tt{✺ \: m \: \angle \: GHI = 14x + 6 = 14 \times 11 + 6 = \boxed{ \tt{160 \degree}}}}[/tex]
Our final answer : 160° . Hope I helped! Let me know if you have any questions regarding my answer! :)▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Researchers study the mean weight (in pounds) of adults between the ages of 30-40. The researchers form a SRS of adults and build a 90% confidence interval: [160, 180]. Which of the following statements are true about this confidence interval?
a. 90% of intervals built according to the method capture the true mean weight of adults between the ages of 30-40.
b. The intervals margin of error is 20.
c. There is a 90% chance that the mean weight of adults between the ages of 30- 40 is between 160 and 180 pounds.
d. The sample mean used to build this interval was 170 pounds.
Answer:
d. The sample mean used to build this interval was 170 pounds.
Step-by-step explanation:
Confidence interval concepts:
A confidence interval has two bounds, a lower bound and an upper bound.
A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.
The margin of error is the difference between the two bounds, divided by 2.
In this question:
Bounds 160 and 180, so the sample mean used was (160+180)/2 = 170, and thus the correct answer is given by option d.
You buy a six pack of Gatorade for $9.00. What is the unit price or the price per bottle?
Answer:
Price per bottle is 1.5 or $1.50
Step-by-step explanation:
To get price per unit, you just divide the amount of money spent by the items purchased. 9/6 = 1.5
1000^1000
i would like to simplify it into 10^x, how?
Answer:
10^3000
Step-by-step explanation:
1000¹⁰⁰⁰
= (10³)¹⁰⁰⁰
= 10^(3×1000)
= 10³⁰⁰⁰ or 10^3000
Answered by GAUTHMATH
How to find the surface area of a cuboid
45 is what percent of 78?
Answer:
35.1
Step-by-step explanation:
45×78/100 that's 100% correct
(1) If the regression line equation of y on x is : û :
= 0.2x + 3, the value
ofy from the table when x=5 is 4.6, then the value of the error in the
value of y is ...
a 0.6
b 0.4 C 0.3
d 0.1
Answer:
0.6
Step-by-step explanation:
Given the regression equation :
y = 0.2x + 3,
The actual value of y when x = 5 is 4.6
The predicted of y using the model when x = 5 is :
Put x = 5 in the equation :
y = 0.2(5) + 3
y = 1 + 3
y = 4
The error in the value of y predicted is :
Error = Actual value - Predicted value
Error = 4.6 - 4
Error = 0.6
Ray is constructing a flower bed
Answer:
41 feet
Step-by-step explanation:
12 +12 + [tex]\sqrt{144+144}[/tex]
Answer:
Perfilar. Comienza por delimitar la forma y dimensión del macizo. ...
Cavar y abonar. ...
Enmarcar y rastrillar. ...
Distribuir y plantar.
Step-by-step explanation:
What’s is the domain
9514 1404 393
Answer:
(b) x -3 ≥ 0
Step-by-step explanation:
The square root function will return non-negative values, so the inequality √(x-3) ≥ 0 gives no new information. What is required is that the argument of the square root function be non-negative:
x -3 ≥ 0
What is the solution to
this system of linear
equations?
3
2
1
-4-3-2-1,0 1 2 3 4
Aώ Ν.
A
(1, -3)
B
(-3, 1)
Find two positive numbers whose product is 64 and whose sum is a minimum. (If both values are the same number, enter it into both blanks.) (smaller number) (larger number)
Answer:
Both the numbers are 8.
Step-by-step explanation:
Let the two numbers are p and 64/p.
The sum is given by
[tex]S = p +\frac{64}{p}\\\\\frac{dS}{dp}= 1 - \frac{64}{p^2}\\\\\frac{dS}{dp}=0\\\\\frac{64}{p^2}=1\\\\p= \pm 8[/tex]
So, the sum is minimum for p = 8 0r - 8, so the two numbers 8.
Find the domain and range of the function graphed below, in interval notation.
Answer:
Domain: [-2,1)
Range: [0,4]
Step-by-step explanation:
The required domain and range of the function graphed are -2 ≤ x < 1 and 0 ≤ y ≤ 4.
Given that,
To determine the domain and range of the function graphed below, in interval notation.
Range, it is the set of the values that come out to an outcome for a certain mathematical operations.
Here,
The projected line of the curve on the horizontal axis is from greater and equal to -2 to less than 1,
Domain = -2 ≤ x < 1
The projected line of the curve on the vertical axis is from greater or equal to 0 to less than or equal to 4,
Range = 0 ≤ y ≤ 4.
Thus, the required domain and range of the function graphed are -2 ≤ x < 1 and 0 ≤ y ≤ 4.
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Identifying Possible Triangles
From which set of dimensions could a triangle be constructed?
side length of 8
side length of 5
side length of 14
O side length of 7
side length of 8
side length of 15
side length of 2
side length of 6
side length of 7
side length of 6
side length of 3
side length of 10 can somebody answer this quickly pls
Answer:
3rd triangle can be constructed with dimensions 2,6,7.
Step-by-step explanation:
sum of any two sides > third side.
difference of any two sides < third side
1.
8+5=13 not >14 (no triangle.)
2.
7+8=15 not >15 (no triangle)
3.
2+6=8>7
2+7=9>6
7+6=13>2
7-2=5<6
7-6=1<2
6-2=4<7
so it is a triangle.
4.
6+3=9 not >10 (not a triangle)
By recognizing each series below as a Taylor series evaluated at a particular value of x, find the sum of each convergent series.
A. 1 + 1/5 + (1/5)^2 + (1/5)^3 + (1/5)^4 +.....+ (1/5)^n + .... = _____.
B. 1 + 5 + 5^2/2! + 5^3/3! + 5^4/4! +....+ 5^n/n! +....= _____.
The first sum is a geometric series:
[tex]1+\dfrac15+\dfrac1{5^2}+\dfrac1{5^3}+\cdots+\dfrac1{5^n}+\cdots=\displaystyle\sum_{n=0}^\infty\frac1{5^n}[/tex]
Recall that for |x| < 1, we have
[tex]\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n[/tex]
Here we have |x| = |1/5| = 1/5 < 1, so the first sum converges to 1/(1 - 1/5) = 5/4.
The second sum is exponential:
[tex]1+5+\dfrac{5^2}{2!}+\dfrac{5^3}{3!}+\cdots+\dfrac{5^n}{n!}+\cdots=\displaystyle\sum_{n=0}^\infty \frac{5^n}{n!}[/tex]
Recall that
[tex]\exp(x)=\displaystyle\sum_{n=0}^\infty\frac{x^n}{n!}[/tex]
which converges everywhere, so the second sum converges to exp(5) or e⁵.
Can someone help me find the volume of this?
Answer:
227.5
Step-by-step explanation:
basically for a triangle prism you would do is
(1÷2) since it's a triangle and multiple all 3 angels
ex: 1/2 × 5 × 7 × 13
Answer:
227.5 cubic yards
Step-by-step explanation:
Formula for area of triangular prism is:
1/2 • length x height x width
Use formula with the given dimensions:
1/2 • 7 • 5 • 13 = 227.5
After x hours, the distance between two trains traveling in opposite directions from the same station is 704 km. If one train travels 96 km/h and the other travels 80 km/h, find the number of hours they traveled if they left at the same time.
Answer:
4 hr
Step-by-step explanation:
96 x 4= 384
80 x 4=320
384+320=704