In the winter sport of bobsledding, athletes push their sled along a horizontal ice surface and then hop on the sled as it starts to careen down the steeply sloped track. In one event, the sled reaches a top speed of 9.2 m/s before starting down the initial part of the track, which is sloped downward at an angle of 9.0 ∘.

What is the sled's speed after it has traveled the first 100 m ?

In the real world, humans do not have a flat slope for weight detection. However, some devices such as cameras, electric scales, and airplanes may display a flat slope for weight detection.

For instance, when detecting a change in weight with a hand-held device, humans would be less accurate than with a more sophisticated device such as an electric scale. Furthermore, when detecting a change of weight in an environment with multiple stimuli, such as a room filled with noise, humans may not be able to accurately detect the change at all.

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Answer:

B.

Explanation:

What causes a reflection in still water?

Reflection in water is caused when light hits the surface of still water and travels to our eye so we can see the complete image and light it's reflecting.

All materials reflect light in some way.

Hope it helped!

conductors are not subjected to additional heat due to the raceway installation.that the raceway provides increased cooling and/or ventilation.

Ventilation is the process of providing fresh air to an enclosed space and removing stale air from the same space. It is an important factor in maintaining the quality of air in an environment, both in terms of temperature, humidity, and gaseous pollution. Ventilation is accomplished by either mechanically or naturally moving air from an area of high pressure, where it is typically warmer, to an area of lower pressure, where it is typically cooler. Mechanical ventilation is typically used in closed buildings or spaces, such as homes, offices, and industrial buildings, while natural ventilation relies on the natural flow of air through open windows, doors, and other openings.

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Answer:

Therefore, the boat is approximately 229.7 meters from the base of the cliff.

Explanation:

Let the horizontal distance between the boat and the foot of the lighthouse be x. Then, the angle of elevation of the top of the lighthouse from the boat is 90° - 34° = 56°.

We can use trigonometry to relate the angles and sides of the right triangle formed by the boat, the foot of the lighthouse, and the top of the lighthouse.

Taking the tangent of the angle of elevation of the foot of the lighthouse, we get:

tan(34°) = opposite/hypotenuse

tan(34°) = 150/x

Multiplying both sides by x, we get:

x * tan(34°) = 150

x = 150 / tan(34°)

x ≈ 229.7 meters

Therefore, the boat is approximately 229.7 meters from the base of the cliff.

The time taken for the man's speed to reach 40 m/s is 8.15 seconds.

What do you mean by speed?

Speed is the rate at which something moves or operates. It is usually measured in units such as miles per hour (mph) or kilometers per hour (kph). Speed is often used to describe the rate of change in a physical quantity, such as the speed of light. It can also be used to describe the rate of change in a process or activity, such as the speed at which a computer can process data.

So,

V = 50(1-e^-0.21t)

40 = 50(1-e^-0.21t)

e^-0.21t = (50-40)/50

-0.21t = ln((50-40)/50)

t = ln((50-40)/50)/-0.21

t ≈ 8.15 seconds

Therefore, the time taken is 8.15 seconds.

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The electric field from a negative charge points is radially inward due to a negative charge.

An electric field is a physical fridge and it by the electric charges that exert a force on other charges extracting or appealing them. Electric electrocuted by electric chargers either stationary or moving the electric field is a vector field meaning that it is both thank you and direction the strength of the electric field is measured in moles per metre electric field and used in a variety of application from our generation to medical treatments.

When you move in an electric field, the electric potential changes since the electric field is a vector field. However, if you move perpendicular to the electric field, the electric potential remains unchanged. This is because the electric field strength is constant in all directions, except in the direction of the electric field. Therefore, if you move perpendicular to the electric field, the electric potential does not change.

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Answer:

he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion

Explanation:

The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:

F = ma

0.65 N = 1.7 kg * a

a = 0.38 m/s^2

This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:

d = vit + 1/2 at^2

where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:

d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2

d = 1.78 meters

Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.

Answer:

Explanation:

Let up be the + direction.

Distance is the total length traveled.

Distance = 10 + 10 = 20 m

Displacement = 10 - 10 = 0

The electronic package's steady state temperature can be calculated using the Stefan-Boltzmann Law, which states that the total energy radiated per unit surface area per unit time is proportional to the fourth power of the temperature.

The electronic package's energy balance equation is as follows:

Power absorbed minus power radiated equals power generated.

where P = absorptivity * incoming radiation P = emissivity * Stefan-Boltzmann constant * T4 Power generated = 1950 W (constant)

Because the surface is not in direct sunlight, we can assume that the incoming radiation is 0 and the power absorbed is 0.

Thus, the energy balance equation becomes:

0 - Power radiated = 1950 W

or

Power radiated = 1950 W

We can use the Stefan-Boltzmann Law to calculate the surface temperature:

Power radiated = emissivity * Stefan-Boltzmann constant * T^4

1950 W = 1 * 5.67 x 10^-8 W/m2K^4 * T^4

T^4 = (1950 / (5.67 x 10^-8))

T = ( (1950 / (5.67 x 10^-8))^(1/4))

The electronic package's steady state temperature is the temperature at which the amount of power generated by the electronics equals the amount of power radiated to space.

Full question.

An electronic package with a surface area of 1 m2 placed in an orbiting space station is exposed to space. The electronics in this package dissipate all 1 kW of its power to the space through its exposed surface. The exposed surface has an emissivity of 1.0 and an absorptivity of 0.25.Given: 0 = 5.67x10-8 W/m2K4  Determine the steady state exposed surface temperature of the electronic package (a) if the surface is exposed to a solar flux of 750 W/m2, and (b) if the surface is not exposed to the sun.

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The probability function at this energy where the Boltzmann approximation has an error less than 1%. (b) is given by

The Boltzmann approximation states that the probability of a particle being in a state of energy E is proportional to the exponential of negative E divided by kT,

where

k is the Boltzmann constant and

T is the temperature in kelvins.

So, the probability function can be written as:

P(E) = (1/Z) * exp(-E/kT),

where

Z is the partition function, which normalizes the probabilities to add up to 1.

To find the energy above Ef (Ef is the Fermi energy) where the Boltzmann approximation has an error less than 1%, we can solve for the energy E such that P(E) is equal to 1% of the maximum probability P(Ef). We can set the following equality:

P(E) = 0.01 * P(Ef)

P(E) = 0.01 * (1/Z) * exp(-Ef/kT)

Rearranging and substituting the expression for P(E) from the Boltzmann approximation, we get:

E = Ef - kT * ln(100).

So, the energy above Ef where the Boltzmann approximation has an error less of than 1% is Ef minus kT times the natural logarithm of 100.

For the value of the probability function at this energy, we can use the expression for P(E) from the Boltzmann approximation:

P(E) = (1/Z) * exp(-E/kT)

P(E) = (1/Z) * exp(-(Ef - kT * ln(100))/kT)

P(E) = (1/Z) * (1/100) * exp(-Ef/kT).

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The acceleration of the cart is 43.12 m/s².

Time it takes the cart to travel from the starting point to the ending point is 3.8 sec.

Acceleration of the cylinder is a = g - (v²)/R.

Time it takes the cylinder to travel from the top of the ramp to the bottom is d = v_0t + 1/2at².

a.) The acceleration of the cart can be calculated using the formula g = 9.8 m/s², where g is the acceleration due to gravity. a = F/m = m × g = 4.40 kg × 9.8 m/s² = 43.12 m/s²

b.) The time it takes the cart to travel from the starting point to the ending point can be calculated using the kinematic equation:

d = v_0t + 1/2at²,

where d is the distance traveled, v_0 is the initial velocity (which is 0 for this case), a is the acceleration (determined in part a), and t is the time.

366 m - 53 m = 313 m

313 = 0t + 1/2(43.12)t² = 1/2(43.12)t²

313 = 21.56t²,  t² = 313 / 21.56

t² = 14.52, t = √14.52 = 3.8 sec.

c.) The acceleration of the cylinder can be calculated using the formula a = g - (v²)/R, where v is the linear velocity of the cylinder's center of mass and R is the radius of the cylinder.

d.) The time it takes the cylinder to travel from the top of the ramp to the bottom can be calculated using the kinematic equation:

d = v_0t + 1/2at²,

where d is the distance traveled, v_0 is the initial velocity (which is 0 for this case), a is the acceleration (determined in part c), and t is the time.

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(i) The change in length is 8.78 x 10⁻⁸ m and the change in the width is -2.63 x 10⁻⁸ m

(ii) The change in volume of the bar is  7.53 x 10⁻¹¹ m³.

The bar undergoes elongation and reduction in cross-sectional area due to the applied loads.

Using the formula for longitudinal strain, we can calculate the change in length (ΔL) as follows:

ΔL = (180 × 10³ N) x (100 × 10⁻³ m) / (205 × 10⁹ N/m²)

ΔL = 8.78 x 10⁻⁸ m

The change in width (Δb) can be calculated using the formula for lateral strain:

Δb = -v x ΔL = -0.3 x  ΔL

Δb = -0.3 x 8.78 x 10⁻⁸ m

Δb = -2.63 x 10⁻⁸ m

The change in volume can be calculated as follows:

ΔV = (35 × 10⁻³ m)  x (35 × 10⁻³ m) x (ΔL + Δb)

ΔV =  (35 × 10⁻³ m) x  (35 × 10⁻³ m) x (ΔL - 0.3 x ΔL)

ΔV =  (35 × 10⁻³ m) x  (35 × 10⁻³ m) x (8.78 x 10⁻⁸m -2.63 x 10⁻⁸ m)

ΔV = 7.53 x 10⁻¹¹ m³

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Answer:

The greatest height will be as follows:

h = (v²sin2θ)/2g

h = [(30m/s)² (2)] / (2 × 9.8 m/s²)

h = 225m

The corresponding horizontal distance will be as follows:

d = (v² sinθcosθ)/g

d = [(30m/s)² (2 × 1)] / 9.8 m/s²

d = 306m

The time of flight will be as follows:

t = (2v sinθ) / g

t = (2 × 30m/s × 2) / 9.8 m/s²

t = 12.24s

The given problem is a projectile motion problem in Physics. It can be solved using the formulas of kinematics considering the initial velocity of the particle and the angle of projection. Substituting the given values in their respective formulas will determine the time of flight, maximum height, and horizontal distance.

The subject matter of this question is based on the physics principle of projectile motion. To solve this problem, we can use some basic formulas of kinematics regarding time of flight, maximum height, and horizontal distance. The angle of projection here is given as \\tan^{-1}2\\ which equals approximately 63.4 degrees.

Firstly, the time of flight (T) can be found using the formula: T = 2u*sin(theta)/g, where 'u' is the initial velocity, 'theta' is the angle of projection, and 'g' is the acceleration due to gravity (approx. 9.81 m/s\^2 ).

Secondly, the greatest height (H) can be found using the formula: H = u^2*sin^2(theta)/2g.

Last but not least, the horizontal distance or the range (R) can be found using the formula: R = u^2*sin(2*theta)/g.

By substituting the given values in these formulas, we will be able to find the time of flight, the greatest height, and the horizontal distance.

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The electric field due to a charged rod of length 2a with total charge q uniformly distributed along its length, placed along the z axis with its center at the origin.

Through the application of Coulomb's equation and the concept of superposition, we can determine the electric field everywhere caused by the charged rod. The electric field due to a tiny piece of the rod at a point P in space is given by:

dE = k dq / r²

where

k = Coulomb's constant,

dq i= the segment's charge,

r = the segment's distance from point P, and

dE = the segment's contribution to the electric field.

We integrate this formula along the entire length of the rod, from -a to +a, to determine the total electric field at P as follows:

E = ∫ dE = k ∫ dq / r²

where the rod's length is used as the integral. The charge per unit length of the rod, or dq, can be expressed in terms of the charge density as dq = ds, where ds is an element along the rod with an infinitesimal length. r = √(s² + z²) where z is the segment's distance from the z axis, we can also describe r in terms of the distance s from the origin to the segment.

E = k ∫ dq / r^2 = k ∫ λ ds / (s² + z²)

E = k λ z ∫_{-arctan(a/z)}^{arctan(a/z)} dθ / (1 + (a/z)² tan² θ)

E = k λ z / (2πε_0) ∫_{-a/z}^{a/z} du / (1 + u²)

E = k λ z / (2πε_0) [arctan(a/z) - arctan(-a/z)]

E = k λ a / (2πε_0 z√(a² + z²))

This is the equation for the electric field produced by a charged rod of length 2a, arranged along the z axis with its center at the origin, and with total charge q evenly distributed throughout its length. The electric field radiates outward from the rod, and as you move away from the rod, its strength diminishes as 1/r².

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Here is a straight forward schematic showing the electrical circuit:

DC Generator ----> Component (D) ----> Ammeter (A) ----> Voltmeter (V)

What purpose does a DC generator serve?

The uses of DC generators

These generators are employed to power illumination, excite alternators, and charge cells. In Vdc railroads, they are utilized to supply dc current voltage for diesel generator. They are found in Stepper motor whenever rotary encoder is necessary.

How do DC generators operate?

A copper coil rotated in a magnetosphere induces a voltage, which is how a current (DC) generator operates. The voltage that is produced in the coil depends on how quickly the coil spins in the magnetosphere.

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The required, apple is moving at a velocity of 7 m/s when it hits the ground.

The equation of motion is a mathematical expression that describes the relationship between the position, velocity, and acceleration of an object. It can be used to predict the motion of an object

The velocity of the apple just before it hits the ground can be calculated using the equation of motion for freely falling objects, which is:

v = √2gs

where v is the final velocity, g is the acceleration due to gravity (9.8 m/s²),

v = √2gs

Substitute the values in the above equation,
v = √[2 × 9.8 × 2.5]
v = 7 m/s

So the apple is moving at a velocity of 7 m/s when it hits the ground.

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Ways Anthropologists are adjusting by focusing on the ways that migration and communication patterns connect groups and by altering their study methodologies.

The anthropologist's job description:

Anthropologists as well as archaeologists both research the origin, progress, and behaviors of individuals. They examine global linguistic and cultural diversity, physical characteristics, and artifacts found in archaeology. creating research plans that include underrepresented topics. using research methods that make advantage of an extensive study design. promoting the use of collaborative techniques to co-create material

What do anthropologists study?

Anthropology compares human communities across borders and through time. For instance, we contrast the current and earlier legal and religious systems. While contrasting political systems, including family relationships, we look at multinational organizations.

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The impulse is given as -75 n.s

We would first have to solve for the initial momentum and then the final momentum

The initial momentum is given as 6 x 5 = 30

The final momentum = -9 x 5 = -45

Then the impulse would be the change in momentum which is gotten as

I = Pf - Pi

I = -45 - 30

I = -75

The impulse is given as I = -75

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The work done is  2321 J.

We have to note that the acceleration has to do with the change in the velocity of the object with time. We are told that there is a movement of the crate as we can see. Let us note that the work that is done by the object subtracted from the work done by the friction. Thus we have that;

Work = (46 * 9.8 * 10.3) - (0.5 * 46 *9.8 *  10.3)

Work = 4643 - 2321

= 2321 J

The work that has been done is  2321 J. This is done in  moving the object

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The orbital period of the rocks in the asteroid belt is approximately 5.73 years.

What is the average distance, a, between the sun and the asteroid, expressed in astronomical units?

The distance from the Sun to the asteroid belt is between 2-4 AU, or between 300 and 600 million kilometers (186-272 million mi).

Using Kepler's Third Law, we have:

P² = a³

where P is the orbital period of the rocks in years, and a is the semi-major axis of their orbit in astronomical units (AU).

Substituting a = 3.2 AU, we get:

P² = (3.2 AU)³

P² = 32.768 AU³

P = [tex]\sqrt{32.768}[/tex] years

P ≈ 5.73 years

Therefore, the orbital period of the rocks in the asteroid belt is approximately 5.73 years.

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The buoyant force and volume of water displaced are 19.6 N and 0.065 [tex]m^{3}[/tex] respectively.

Explanation:

According to Archimedes' principal, When a body is immersed fully or partially in a fluid, the the body experiences an upward force called buoyant force which is equal to the weight of fluid dispersed.

Buoyant force ([tex]F_{b}[/tex]) = mg

where, m is the mass of ball

            g is acceleration due to gravity i.e. 9.8 [tex]ms^{-2}[/tex]

From the question putting the values we get,

[tex]F_{b} =[/tex] 2×9.8 = 19.6 N

Now,

Water displaced = Volume occupied by the ball

                          [tex]= \frac{4}{3} \pi r^{3}[/tex] ( as ball is sphere)

                            {diameter of the ball = 50cm or, 0.5m  So radius =[tex]\frac{0.5}{2}[/tex]}

                          =     [tex]\frac{4}{3}*\frac{22}{7}*(\frac{0.5}{2}) ^{3}[/tex]    

                          [tex]=\frac{4}{3}[/tex] × [tex]\frac{22}{7}[/tex]×[tex]\frac{0.125}{8}[/tex]

                          [tex]= \frac{4}{3}[/tex] × [tex]\frac{22}{7}[/tex] × [tex]\frac{125}{8000}[/tex]

                          [tex]= 0.065 m^{3}[/tex]

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The vapor pressure of Substance X at -98. C is 1.01 atm, rounded to 2 significant digits.

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase. It is an indication of a liquid's evaporation rate. It is directly related to the vapor's temperature, and increases with increasing temperature.

ln (P2/P1) = (ΔHvap/R) * ((1/T1) – (1/T2))
where:
P2 = vapor pressure of the substance at temperature T2
P1 = vapor pressure of the substance at temperature T1
ΔHvap = enthalpy of vaporization of the substance
R = ideal gas constant
T1 = normal boiling point of the substance
T2 = temperature at which the vapor pressure is being calculated
In this case, we are trying to calculate the vapor pressure of Substance X at -98. C.
We can plug in the known values into the equation to calculate the vapor pressure of Substance X at -98. C:
ln (P2/P1) = (21.0 kj/mol/8.314 J/mol-K) * ((1/19) – (1/273))
ln (P2/P1) = 0.0087
P2 = exp (0.0087) * P1
P2 = 1.009 * P1
P2 = 1.009 * 1.00 atm (atm is the vapor pressure of Substance X at 19. C, its normal boiling point)
P2 = 1.009 atm
Therefore, the vapor pressure of Substance X at -98. C is 1.01 atm, rounded to 2 significant digits.

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At any given point, the net electric field can point in multiple directions at any given point, the net electric field is the vector sum of all component electric fields - False

The electric field is a measure of the electric force experienced by a charged particle in a specific location. It is a vector field, meaning it has both magnitude and direction.

The electric field at a particular point in space can be visualized as a field of force lines that emanate from positive charges and converge towards negative charges. The strength of the electric field is proportional to the number of force lines and the direction of the field is the direction that a positive test charge would experience a force if placed at that point.

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Answer:

see below

Explanation:

We have ,

So , from V = iR ,

i = V/R

i = 9/3 A

i = 3A [ option B ]

again, we know that, Power = v²/R , so ;

P = 9²/3 W

P = 27W [ option E ]

and we are done!

(a) The centripetal acceleration of the ball at 7.72 rev/s is 30.2m/s²

(b) The centripetal acceleration at 6.39 rev/s is 33.9m/s².

What is a radius?

Using the definition of speed and noting that the ball travels in a circular path,

v= d/Δt

= 2πR/T

​where R is the radius of the circle and T is the period, that is, the time interval required for the ball to go around once. For the periods given in the problem,

8.00rev/s→T= 1/8.00rev/s =0.125s

6.00rev/s→T= 1/6.00rev/s =0.167s

Therefore, the speeds in the two cases are:  8.00rev/s→v= 2π(0.600m)/ 0.125s

​ =30.2m/s²

6.00rev/s→v= 2π(0.900m)/0.167s

=33.9m/s²

Therefore, 6.00rev/s gives the greater speed of the ball.

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Internal hard disk is Removable but not fixed. Thus, option A is the correct answer.

A hard disk drive (HDD) is a type of non-volatile storage device that stores digital data on rapidly rotating disks (platters) coated with magnetic material. Hard disk drives are commonly used in computers as the primary storage for the operating system and for user data, as well as in other devices such as external hard drives, network-attached storage (NAS) devices, and digital video recorders (DVRs). An HDD consists of one or more disks that spin at high speeds (usually 5,400 or 7,200 RPM) and are read from and written to by magnetic read/write heads that move across the disk surfaces. The data is stored on the disk in magnetic patterns, and the read/write heads can detect and change these patterns to read and write data.

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Answer:

V=115.2m/s

Explanation:

V=fλ

where v=wave speed,f=frequency,λ=wavelength

convert 180cm to m

1.8m

V=64×1.8

V=115.2m/s

The expression for (F net)x when the position of Q and -Q are given, is calculated to be Fx = 2k Qqa/[(a² + y²)]^3/2 x^.

Coulomb's law establishes that the electric force exerted by a point charge q₁ on q₂ is proportional to the values of the charges and inversely proportional to the square of the distance between them. Coulomb obtained this dependence experimentally and introduced a proportionality constant in its law, k = 9 × 10⁹ N m²/c² is coulomb's constant.

Mathematically, Coulomb's law is,

F = k q₁ q₂/r² r^

Let us denote the position of the charge q on the y-axis as 'y'.

The force between 'Q' and'q' is

F₁ = k Qq/(x² + y²)

F₁x = F₁ cosθ

where,

θ is the angle between F₁ and x-axis

F₁x = [k Qq/(x² + y²)] [x/√(x² + y²)]

when x = a, F₁x = k Qqa/[(a² + y²)]^3/2

F₂x = k × -Qq/(a² + y²) × [-a/√(a² + y²)]

Thus, the x-component of the net force,

Fx = 2k Qqa/[(a² + y²)]^3/2 x^

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