In the diagram, the length of segment QV is 15 units. What is the length of segment TQ?

Answer:

1.-dh/dt  =  5.31*10⁻⁵ m/seg

2.-dh/dt =   1.99*10⁻⁵  m/seg

3.-dh/dt  =  1.59*10⁻⁴  m/seg

Step-by-step explanation:PREGUNTA INCOMPLETA NO SE INDICAN LAS FORMAS DE LOS TANQUES.

Asumiremos que los tres tanques son:

el primero cilindro recto     de  Vc = π*r²*h      ( r es radio de la base y h la altura)

el segundo asumiremos que es eliptico recto de Ve = π*a*b*h aqui a y b son los ejes de la elipse y h la altura

El tercero es un cono invertido Vco  = 1/3 *π*r²*h  ( r es el radio de la base.

1.-Caso del cilindro

Vc = π*r²*h

Derivando en ambos miembros de la expresión tenemos:

dV(c) / dt  = π*r²*dh/dt

Sustituyendo

1.5 Lts/seg =  3.14 * (3)²*dh/dt  

1.5/1000 m³/seg  =  28.26 m² dh/dt

1.5/ 28260 m  =  dh/dt

Despejando dh/dt

dh/dt  =  1.5 / 28260    =  5.31*10⁻⁵ m/seg

dh/dt  =  5.31*10⁻⁵ m/seg

2.-La elipse

Ve  = π*a*b*h  

Aplicando el mismo procedimiento tenemos:

DVe/dt  =  1.5 Lts/seg  =  π* 6*4* dh/dt

1.5 /1000   =  75.36 *dh/dt

dh/dt =  1.5 / 75360  m/seg

dh/dt =   1.99*10⁻⁵  m/seg

3. El cono invertido

Vco = (1/3)*π*r²*h

DVco/dt =  (1/3)*π*r²*dh/dt

1.5/1000  =  9.42 *dh/dt

dh/dt  =  1.5/9420

dh/dt  =  1.59*10⁻⁴  m/seg

Answer:

4,5,5,7

Step-by-step explanation:

The answer is 4,5,5,7

Answer:

[tex]P(Age\ 12) = \frac{2}{3}[/tex]

Step-by-step explanation:

Given

        Age 11    Age 12    Total  

Girls   3             5              8

Boys   1             3             4

Required

[tex]P(Age\ 12)[/tex]

The number of aged 12 children is:

[tex]Age\ 12 = 5 + 3[/tex]

[tex]Age\ 12 = 8[/tex]

The total number of children is:

[tex]Total=8+4[/tex]

[tex]Total = 12[/tex]

So, we have:

[tex]P(Age\ 12) = \frac{Age\ 12}{Total}[/tex]

[tex]P(Age\ 12) = \frac{8}{12}[/tex]

Simplify

[tex]P(Age\ 12) = \frac{2}{3}[/tex]

9514 1404 393

Answer:

 5/36

Step-by-step explanation:

5 and 36 have no common factors, so the fraction 5/36 is already in simplest form.

Answer:

Step-by-step explanation:

Answer:

Assume x greater-than-or- equal-to 0 and y ... 0 StartRoot x squared y cubed EndRoot + 2 StartRoot x cubed y Superscript 4 Baseline EndRoot + x y StartRoot y EndRoot.

Step-by-step explanation:

Option (b) is correct.

The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

Step-by-step explanation:

Given:Expression \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy

We have to find the sum of the given expression and choose the correct from the given options.

Consider the given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy .

\sqrt{x^2y^3}x2y3 can be written as \sqrt{x^2y^2y}=xy\sqrt{y}x2y2y=xyy

Also, 2\sqrt{x^3y^4}2x3y4 can be written as 2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}2x3y4=2x2x(y2)2=2xy2x

Now, the given expression becomes,

x2y3+2x3y4+xyy

=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}=xyy+2xy2x+xyy .

Now, adding like term, terms having same variable with same degree.

=2xy\sqrt{y}+2xy^2\sqrt{x}=2xyy+2xy2x .

Thus, The sum of given expression  \sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}x2y3+2x3y4+xyy is  2xy\sqrt{y}+2xy^2\sqrt{x}2xyy+2xy2x

[tex]\displaystyle\bf \boxed{V=abh \ ; \ 1dm^3=1litre=1000cm^3} \\\\a=12cm \ ; \ b=8 cm ;\: h_1=7 \; ; \ h_0=h_1+h_2=?\\\\abh_2=1,2litre=1,2dm^3\ = 1200cm^3\\\\ 8\cdot 12 h_2=1200\\\\h_2=12.5 cm\: then \\\\h_0= 7+12,5=19,5 \\\\Answer : the \ height \ of \ the \ tank \ is \ 19,5 cm[/tex]

Answer:

-2 0 2 3 this is the domain of the ordered pairs shown in the graph above

Answer:

2nd one, 3rd one and last one

Answer:

D

Step-by-step explanation:

Answer:

1/2 + 2/3 + 5/4 = 29/ 12 = 2 5/  12  ≅ 2.4166667

Step-by-step explanation:

Add: 1/ 2  + 2/ 3  = 1 · 3/ 2 · 3  + 2 · 2/ 3 · 2  = 3/ 6  + 4/ 6  = 3 + 4/ 6  = 7/ 6

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(2, 3) = 6. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 2 × 3 = 6. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - one half plus two thirds = seven sixths.

Add: the result of step No. 1 + 5/ 4  = 7/ 6  + 5/ 4  = 7 · 2/ 6 · 2  + 5 · 3/ 4 · 3  = 14/ 12  + 15/ 12  = 14 + 15/ 12 = 29/ 12

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(6, 4) = 12. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 6 × 4 = 24. In the next intermediate step, the fraction result cannot be further simplified by canceling.

In words - seven sixths plus five quarters = twenty-nine twelfths.

hope it helps...

correct me if I'm wrong...

Answer:

The answer is "What is important for me to understand?".

Step-by-step explanation:

It is because it is based also on the conclusion that the word in the text read the Jac can draw. Essentially, the particular excerpt read by Jac in his coding book explains that, whether old or new, all older techniques used in the past, compared with the new factorization methods, in truth all shortcuts in mathematics are not feasible and hence all steps have to occur. This implies Jac has to discover what really is important, what he must comprehend, and whether whatever tactics he is using are old and new. The same would be valid of life itself; irrespective of how he chooses to live his life, there are times where shortcuts cannot be used.

Answer:

[tex]C(n)=30-20n[/tex]

Step-by-step explanation:

Arithmetic sequence given in the question is,

10, -10, -30, -50........

Explicit formula of an Arithmetic sequence is given by,

[tex]C(n)=C(1)+(n-1)d[/tex]

Here, [tex]C_1=[/tex] First term

[tex]n=[/tex] number of terms

[tex]d=[/tex] common difference

From the given sequence,

[tex]C(1)=10[/tex]

[tex]d=-10-10[/tex]

  [tex]=-20[/tex]

Substitute the values in the formula,

[tex]C(n)=10+(n-1)(-20)[/tex]

[tex]C(n)=10-20n+20[/tex]

[tex]C(n)=30-20n[/tex]

Answer:

240 If its wrong pleas correct me

Answer:

Step-by-step explanation:

233 322

Answer:

See Explanation

Step-by-step explanation:

(For Diagram please find in attachment)

Since DE∥BC

∴ By Basic Proportionality Theorem,

AD/DB  = AE/EC

​ Since it is Given, AD=DB

∴ AE/EC  =1

∴ AE=EC  (Proved)

Answer:

the correct options are 1, 2, 5, and 6th

1. and 2.

all functions have a dependant variable y and independent variable x, and the set of dependant variables is called its range whereas the set of independent variables is called its domain.

5. and 6.

In a horizontal line 1 input associates itself with exactly one ouput, even tho the output is constant (same) for all values of x, and that's the property of a function

Answer:

all functions have dependent variables

all functions have an independent variable

a horizontal line Is an example of a functional relationship

Answer:

the square of hypotenuse rs eqaul to the sum of the square of the legs

(x - [3])² + (y- [2])² = 16

Answer:

3

Step-by-step explanation:

-2x = -6

or, x = -6 / -2

or, x = 3

Answer:

5.6 days

Step-by-step explanation:

We are given;

Initial Mass; N_o = 25 g

Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)

k = 0.1229

Formula is given as;

N_t = N_o•e^(-kt)

Plugging in the relevant values;

12.5 = 25 × e^(-0.1229t)

e^(-0.1229t) = 12.5/25

e^(-0.1229t) = 0.5

(-0.1229t) = In 0.5

-0.1229t = -0.6931

t = -0.6931/-0.1229

t = 5.6 days

Answer:

4

−

4

+

8

2

+

8

Step-by-step explanation:

Answer:

C: y=-3x

Step-by-step explanation:

Rise over run: in this case you go down so -3/1=-3

Step-by-step explanation:

hope it helps

Answer:

Step-by-step explanation:

89x = 89 * x

16x = 2 * 2 * 2 * 2 * x

-30x = -1 * 2 * 5 * 3 * x

x is the only factor that is common in all three.

GCF = x

Check this link: https://brainly.com/question/12053038

The same question is explained here :).

Hope it helps.

Answer:

1: 16

2: 4940

3: 24

4: 25

5: 9

Step-by-step explanation:

A permutation is a method of calculating the number of possible outcomes. It follows the following general formula;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

There (n) is the number of objects, and (r) is the number of objects selected.

1. Arranging 4 pots with different plants in a row

In order to solve this, one needs two pieces of information, the number of objects, and the number of objects selected. One is given the number of objects; (4), but when the problem states "in a row" it never specifies how many plants are in a row. Thus, let one assume that a "row" can have an infinite amount of space, but in this case, only (4) space will be used. Therefore there are (4) objects with (4) objects selected. However, the drawback is that the combination formula doesn't work when the two parameters (n) and (r) are the same. Hence, to solve this special case, one simply multiplies the two numbers to get the answers:

[tex]n*r\\\\=4*4\\\\=16[/tex]

2. Forming a four-digit ATM pin

One is given that there are (4) digits in the ATM pin, this is the number of objects selected. One is also given that number of objects, there are (10) digits including (0). Set up the permutation and solve;

[tex]_nP_r=\frac{n!}{(n-r)!}[/tex]

[tex]_1_0P_4=\frac{10!}{(10-4)!}\\\\=\frac{10!}{6!}\\\\=\frac{10*9*8*7*6*5*4*3*2*1}{6*5*4*3*2*1}\\\\=10*9*8*7\\\\=4940[/tex]

3. Securing a motorcycle with a three-digit combination lock using the numbers (1), (2), (3), and (6).

There are (4) digits to choose from on the lock. But there are (3) numbers that can be selected.

[tex]_4P_3=\frac{4!}{(4-3)!}\\\\=\frac{4!}{1!}\\\\=\frac{4*3*2*1}{1}\\\\=4*3*2*1\\\\=24[/tex]

4. Displaying 3 identical small vases, 1 figure, and a photo frame in a row.

There are (5) objects, and (5) spaces (read problem (1) for an explanation for the objects being put in a row). Thus, this is a special case; multiply the two numbers to get the result;

[tex]n*r\\=5*5\\=25[/tex]

5. 3 girls sitting around a circular table

There are (3) subjects, and (3) spaces in this problem. Apply the same logic applies to a row in this problem. Therefore, this is another special case; multiply the two numbers to get the result;

[tex]n*r\\=3*3\\=9[/tex]

what's the whole question??