In ΔCDE, the measure of ∠E=90°, ED = 28, CE = 45, and DC = 53. What ratio represents the tangent of ∠C?

Answer:

42

Step-by-step explanation:

Perimeter is [tex]2l+2w[/tex]

Answer: 42

Hope this helped! Please mark brainliest :)

Answer:

P=-2.3662299854

Step-by-step explanation:

6.87p = - 7.056 -9.2

So 6.87p= - 16.256

P=-2.3662299854

The question is not complete as the scatter plot is missing.

Thus, I have attached the complete question showing the scatter plot.

Answer:

D: On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

Step-by-step explanation:

From the attached image showing the question and scatter plot, we can see that the scatter plot is modeled by the line; y = -5.9x + 850

Where;

x is the high temperature in °F

y is the amount of fluid ounces sold

Let's try x = 0°F

Thus;

y = 0 + 850

y = 850 fluid ounces

Let's try x = 10°F

Thus;

y = -5.9(10) + 850

y = 850 - 59

y = 791

This means for every increase in temperature of 10°F, the amount sold is approximately 60 fluid ounces lesser.

Looking at the options in the attached file, the only correct one that corresponds to our answer is option D where it says;. On a day with a high temperature of 0°C, the shop can expect to sell about 850 fluid ounces of hot coffee

Answer:

sorry i cannot help you

Answer:

It should be B,  180 cm

Step-by-step explanation:

x = circumference of  circle D

18/360 = 9/x

9*360 = 18x

9*360/18 = x

x = 180

Answer:

11. B.

12. C.

13. A.

14. D.

Step-by-step explanation:

for 11: we know that angles D and J are congruent from the tick marks, we also know that ∠FKD and ∠LKJ are congruent (vertical angles are congruent) therefore we need the sides between them

for 12: we know that ∠STU and ∠TUG are congruent, we also know that line TU is congruent to TU (reflexive property), therefore we need the angles adjacent to the first angles listed.

for 13: we know that ∠PQR and ∠CQR are congruent, we also know that lines RQ and RQ are congruent (reflexive property), therefore we need the other angles to which line RQ is between.

for 14: we know ∠B is congruent to ∠T and line AB is congruent to line ZY. therefore the angle cannot be connected to lines AB and ZY.

Answer:

Procedure:

1) Form a system of 3 linear equations based on the two zeroes and a point.

2) Solve the resulting system by analytical methods.

3) Substitute all coefficients.

Step-by-step explanation:

A quadratic function is a polynomial of the form:

[tex]y = a\cdot x^{2}+b\cdot x + c[/tex] (1)

Where:

[tex]x[/tex] - Independent variable.

[tex]y[/tex] - Dependent variable.

[tex]a[/tex], [tex]b[/tex], [tex]c[/tex] - Coefficients.

A value of [tex]x[/tex] is a zero of the quadratic function if and only if [tex]y = 0[/tex]. By Fundamental Theorem of Algebra, quadratic functions with real coefficients may have two real solutions. We know the following three points: [tex]A(x,y) = (r_{1}, 0)[/tex], [tex]B(x,y) = (r_{2},0)[/tex] and [tex]C(x,y) = (x,y)[/tex]

Based on such information, we form the following system of linear equations:

[tex]a\cdot r_{1}^{2}+b\cdot r_{1} + c = 0[/tex] (2)

[tex]a\cdot r_{2}^{2}+b\cdot r_{2} + c = 0[/tex] (3)

[tex]a\cdot x^{2} + b\cdot x + c = y[/tex] (4)

There are several forms of solving the system of equations. We decide to solve for all coefficients by determinants:

[tex]a = \frac{\left|\begin{array}{ccc}0&r_{1}&1\\0&r_{2}&1\\y&x&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]a = \frac{y\cdot r_{1}-y\cdot r_{2}}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x+x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]a = \frac{y\cdot (r_{1}-r_{2})}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]b = \frac{\left|\begin{array}{ccc}r_{1}^{2}&0&1\\r_{2}^{2}&0&1\\x^{2}&y&1\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]b = \frac{(r_{2}^{2}-r_{1}^{2})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x +x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

[tex]c = \frac{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&0\\r_{2}^{2}&r_{2}&0\\x^{2}&x&y\end{array}\right| }{\left|\begin{array}{ccc}r_{1}^{2}&r_{1}&1\\r_{2}^{2}&r_{2}&1\\x^{2}&x&1\end{array}\right| }[/tex]

[tex]c = \frac{(r_{1}^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1})\cdot y}{r_{1}^{2}\cdot r_{2}+r_{2}^{2}\cdot x + x^{2}\cdot r_{1}-x^{2}\cdot r_{2}-r_{2}^{2}\cdot r_{1}-r_{1}^{2}\cdot x}[/tex]

And finally we obtain the equation of the quadratic function given two zeroes and a point.

Answer:

first step - make x² the subject of the formula

x² = 25

second step :

find the square root of both sides

√x² = √25

x = 5

Step-by-step explanation:

Answer:

[tex]x=0, \\x=\pi[/tex]

Step-by-step explanation:

Recall the trigonometric identity [tex]\sin 2x=2\sin x\cos x[/tex].

Therefore, given [tex]\sin 2x=2\sin x[/tex], rewrite the left side of the equation:

[tex]2\sin x\cos x=2\sin x[/tex]

Subtract [tex]\sin x[/tex] from both sides:

[tex]2\sin x\cos x-2\sin x=0[/tex]

Factor out [tex]2\sin x[/tex] from both terms on the left:

[tex]2\sin x(\cos x-1)=0[/tex]

We now have two cases:

[tex]\begin{cases}2\sin x=0, x=k\pi\text{ for }k\in \mathbb{Z}\\\cos x-1=0,x=k2\pi\text{ for }k\in \mathbb{Z}\end{cases}[/tex]

Since the problem stipulates that [tex]x[/tex] is in the interval [tex][0, 2\pi)[/tex], we have:

[tex]\text{For }x\in [0, 2\pi):\\\sin x=0\rightarrow \boxed{x=0, x=\pi}\\\cos x-1=0\rightarrow \boxed{x=0}[/tex]

Recall that square brackets mean inclusive and parentheses mean exclusive. Therefore, [tex]2\pi \notin [0, 2\pi)[/tex].

Answer:

Option C.

Step-by-step explanation:

For a given set of N elements:

{x₁, x₂, ..., xₙ}

The mean is given by:

[tex]M = \frac{x_1 + x_2 + ... + x_n}{N}[/tex]

And the variance is given by:

[tex]v = \frac{(x_1 - M)^2 + (x_2 - M)^2 + ... + (x_n - M)^2}{N}[/tex]

Then for our set:

{70, 80 ,75, 75, 80}

We have 5 elements, then N = 5

The first thing we need to find is the mean.

[tex]M = \frac{70 + 80 + 75 + 75 + 80}{5} = 76[/tex]

Then the variance will be:

[tex]v = \frac{(70 - 76)^2 + (80 - 76)^2 + (75 - 76)^2 + (75 - 76)^2 + (80 - 76)^2}{5} = 14[/tex]

The correct option is C, 14.

Answer:

x = 6

Step-by-step explanation:

6 is x so this is the answer

Answer:

7 students

Step-by-step explanation:

1+2+4=7students

Answer:

The speed of the plane with no wind is 378 miles per hour.

Step-by-step explanation:

Since at maximum speed, an airplane travels 1680 miles against the wind in 5 hours, and flying with the wind. the plane can travel the same distance in 4 hours, to determine what is the speed of the plane with no wind, the following calculation must be performed:

Against the wind = 1680/5 = 336

With the wind = 1680/4 = 420

420 - ((420 - 336) / 2) = X

420 - 42 = X

378 = X

Therefore, the speed of the plane with no wind is 378 miles per hour.

They are parallel, as shown by the graph.

Answer:

From what I learn it is 360 degrees

Answer:

y = -1/3x + 14/3

Step-by-step explanation:

We have the standard equation as;

y = mx + b

where m is the slope and b is the y-intercept

the given points are;

(-1,5) and (2,4)

So we plug x and y for each of the points

then we create two linear equations which we can solve simultaneously to get the values of m and b

From the points;

5 = -m + b•••••••(i)

4 = 2m + b

from i;

b = 5 + m

substitute this into equation ii

4 = 2m + 5 + m

4 = 3m + 5

4-5 = 3m

3m = -1

m = -1/3

Recall;

b = 5 + m

b = 5-1/3

b = 14/3

so we have the equation as;

y = -1/3x + 14/3

Multiply through by 3

3y = -x + 14

Answer:

x=30

Step-by-step explanation:

Hi there!

For A to be parallel to B, 5x would be equal to 3x+60. (If they were parallel, these two angles would be alternate exterior angles, which are equal.)

[tex]5x=3x+60[/tex]

Subtract 3x from both sides

[tex]5x-3x=3x+60-3x\\2x=60[/tex]

Divide both sides by 2

[tex]x=30[/tex]

I hope this helps!

Answer:

58

Step-by-step explanation:

Answer:

(B)

Step-by-step explanation:

Can't explain lol, but that's the answer

Answer:

3,082,000

Step-by-step explanation:

THE ANSWER IS 3,082,000 HOPE IT HELPS

Answer:

yo congratulations on finishing 10th grade (congratulate me on finishing 8th)

hamood spelled backwards is doomah so...um...

also do u mean 7/2/21..bc 6/2/21 is like in June and we're in July

Answer:

Same side interior angles

Step-by-step explanation:

Same side interior angles are interior angles and on the same side. Sorry don't know how to better explain.

Answer:

[tex]m \angle A = m \angle C[/tex] by reason [tex]\overline{AB} \cong \overline{BC}[/tex] and [tex]m \angle B = m \angle M = m \angle P[/tex].

[tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem

Step-by-step explanation:

We proceed to demonstrate the statement by Geometric means:

1) [tex]\overline{AB} \cong \overline{BC}[/tex], [tex]\overline {AM} \cong \overline {PC}[/tex], [tex]m\angle AMO = m\angle CPO[/tex] Given.

2) [tex]\frac{AM}{AB} = \frac{PC}{BC}[/tex] Proportionality.

3) [tex]\frac{AM}{AM + MB} = \frac{PC}{BP + PC}[/tex] Definition of line segments.

4) [tex]\frac{1}{1+\frac{MB}{AM} } = \frac{1}{\frac{BP}{PC}+1}[/tex] Algebra.

5) [tex]\frac{BP}{PC} + 1 = 1 +\frac{MB}{AM}[/tex] Algebra.

6) [tex]\frac{BP}{PC} = \frac{MB}{AM}[/tex] Algebra.

7) [tex]BP = BM[/tex] By 1)

8) [tex]m \angle B = m \angle M = m \angle P[/tex] By 1), 7)

9) [tex]\triangle AMO \sim \triangle ABC[/tex], [tex]\triangle CPO \sim \triangle ABC[/tex] By 1), 7), 8). Defintion of simmilarity.

10) [tex]\frac{AM}{MO} = \frac{AB}{BC}[/tex], [tex]\frac{PO}{PC} = \frac{AB}{BC}[/tex] Definition of proportionality.

11) [tex]\frac{AM}{MO} = \frac{PO}{PC}[/tex] Algebra.

12) [tex]AM^{2} = PO\cdot MO[/tex] Algebra.

13) [tex]PO = MO[/tex] By 12) and Algebra.

14) [tex]\overline{PO} \cong \overline{MO}[/tex] By 13).

15) [tex]\triangle AMO \cong \triangle CPO[/tex] SAS Theorem/Result.

Answer:

x(x + 7) = 169

Step-by-step explanation:

We are given that

Let length of shorter leg of right triangle = x ft

Length of other leg = x+7 ft

Hypotenuse of right triangle = 13 ft

We have to find the equation which can be used to find x, the length of shorter leg.

By pythagorous theorem

(Hypotenuse)^2=(Base)^2+(Perpendicular\;side)^2

Substitute the values then, we get

(13)^2=x^2+(x+7)^2

x^2+(x+7)^2=169

This is required equation which can used to find x.

Answer:

d. x2 + (x + 7)2 = 169

Step-by-step explanation:

use Pythagorean theorem, substitute in the given values, and you get this

Answer:

try 4

Step-by-step explanation:

basically need to find number that when multiplied 3 times equals 64 so 4*4*4=64

Step-by-step explanation:

simply take the average of the x and y coordinates

Answer:

50

Step-by-step explanation:

simplify the radical by breaking the redicand up into a product of known factors, assuming positive real numbers.

Answer:

31.80°

Step-by-step explanation:

In ∆ ABC :-