Answer:
Step-by-step explanation:
Frt7v6c87buhinjomp,l.;
PLEASE HELP: A standard six-sided die is rolled.
What is the probability of rolling a number greater than 4? Express your answer as a simplified fraction or a decimal rounded to four decimal
places.
Answer in fraction form is 1/3
Answer in decimal form is 0.3333
Pick one answer only.
==========================================================
Explanation:
The sample space is the set of all possible outcomes. In this case, the outcomes consist of values between 1 and 6
S = sample space
S = {1,2,3,4,5,6}
There are 6 items here. Let B = 6.
We want to roll a number greater than 4, so the event space we're after is
E = {5,6}
which consists of 2 items. Let A = 2.
The probability we want is A/B = 2/6 = 1/3 = 0.3333
So if you go with the fraction option, then you'll type in 1/3
If you go with the decimal option, then you'll type in 0.3333
2(-x-4)+3=-7x+5+5x
Pls help!!!!!!!!
Find the least positive integer, written only by numbers 0, 1 and 2, which is divisible by 225.
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Answer:
1,222,200
Step-by-step explanation:
A search using a computer program found ...
5432 × 225 = 1,222,200
__
1000 mod 225 = 100
4 × 225 = 900
This suggests that if we have some number of thousands whose digits total 9, that we will have the number of interest. Of course, we can add 200 to some number of thousands with a digit total of 7. The smallest such digit total will be had with the number 1222 using the specified digits {0, 1, 2}. This gives rise to the result above: 1222×1000 +200 = 1,222,200. It also explains why moving the 1 to the right will also give a multiple of 225.
calculate limits x>-infinity
-2x^5-3x+1
Given:
The limit problem is:
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]
To find:
The value of the given limit problem.
Solution:
We have,
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]
In the function [tex]-2x^5-3x+1[/tex], the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.
So, the function approaches to positive infinity as x approaches to negative infinity.
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex]
Therefore, [tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex].
For the inequality 4x2>y−3, where is the graph shaded and is the curve solid or dotted?
Answer:
Dotted Curve
Shaded Area includes the Origin.
Step-by-step explanation:
I am assuming that you mean 4x² > y-3.
Since the inequality sign is greater than, the line would be dotted. The curve would be solid if the inequality was an 'X or equal to' sign.
----------------------------------
4(0)² > 0 - 3
0 > -3
Since the given statement is true, the origin is a solution and we would shade below the curve.
----------------------------------
See the graph attached.
Hope this helps.
A bag contains 7 red marbles, 11 blue marbles, and 7 yellow marbles.
Two marbles are selected, one at a time, without replacement.
Find the probability that the first marble is blue and the second marble is red.
Express your answer as a decimal, rounded to the nearest hundredth.
1 pts
Ounction 3
Answer:
the total of marbles = 7 red + 11 blue + 7 Yellow
= 25 marbles
P ( b n r) = 11/25 + 7/24
=0.732
Step-by-step explanation:
1. find the total marbles
2. find the probability of each without replacement means the demoinator will reduce
3.add the two probability
GET 95 POINTS Let f(x) = 1/x and g(x)=x² + 6x. What
two numbers are not in the domain of fᵒg?
Separate your answers with a comma.
Answer:
hey there hope this answer helps you out
Step-by-step explanation:
we have two functions f(x) and g(x) such that
[tex]f(x) = \frac{1}{x} [/tex]
and
[tex]g(x) = {x}^{2} + 6x[/tex]
solving for f ° g, we'll substitute the x in f(x) by the value of g(x)
[tex]fog = \frac{1}{g(x)} [/tex]
[tex]fog \: = \frac{1}{ {x}^{2} + 6x } [/tex]
taking x common in denominator
[tex]fog = \frac{1}{x(x + 6)} [/tex]
for a function to exist it should not have 0 in its denominator
checking the values of x for which the denominator of f ° g becomes 0 :-
x = 0 and x = -6so the function doesn't exist at values x = 0, -6
So, 0, -6 cannot be in the domain of f°gQuestion 19 of 30
An angle is formed by two rays or segments that share a(n).
A. Vertex
B. Side
Ο Ο Ο Ο
O C. Endpoint
OD. Ray
Answer:
A a vertex
Step-by-step explanation:
When rays meet they form a point is formed known as the vertex.
Not sure how to do this.
Answer:
-4 ≤ x ≤ -2, 4 ≤ x ≤ 7
Step-by-step explanation:
A function shows the relationship between two or more variables. A function is said to be constant over an interval if its output value is same for every input value within that interval.
As seen in the question, the x variable is the input while the y variable is the output. The function is constant from x = -4 to x = -2. Also, the function is constant within the interval from x = 4 to x = 7. Hence, the interval is:
-4 ≤ x ≤ -2, 4 ≤ x ≤ 7
If U= {1,2,3,......8} , A={1,4,6,7} , B= {2,4,5,7} & C= {3,5,6,7} prove that 1) An( BUC ) = ( AnB) U ( AnC ). 2) AU (BnC)= (AUB) n ( AUC )
Step-by-step explanation:
BUC={2,3,4,5,6,7}
An(BUC)={4,6,7}
AnB={4,7},AnC={6,7}
(AnB)U(AnC)={4,6,7}
Au(BnC)={1,4,5,6,7}
(AUB)n(AUC)= {1,4,5,6,7}
HELP ASAP?
the two answers not showing on screen are
C:y<6x-3
D:y<6-3
Answer:
A is that answer
A) y<2x-3
Golf Scores In a professional golf tournament the players participate in four rounds of golf and the player with the lowest score after all four rounds is the champion. How well does a player's performance in the first round of the tournament predict the final score
Answer:
Mean scores.
Step-by-step explanation:
The golf player will score in the first round, according to these scores the golf player scores can be predicted. The golf player can perform high in first round but he may score lesser in the second round due to stress or mental pressure. The scores can be predicted taking mean of the scores and adding standard deviation to it.
Does it pay to ask for a raise? A national survey of heads of households showed the percentage of those who asked for a raise and the percentage who got one. According to the survey, of the men interviewed, 21% had asked for a raise and 60% of the men who had asked for a raise received the raise. If a man is selected at random from the survey population of men, find the following probabilities. (Enter your answers to three decimal places.)
Answer:
a) P(man asked for a raise) = 0.21.
b) P(man received raise, given he asked for one) = 0.6.
c) P(man asked for raise and received raise) = 0.126.
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
Question a:
21% asked for a raise, so:
P(man asked for a raise) = 0.21.
Question b:
Event A: Asked for a raise.
Event B: Received a raise:
21% had asked for a raise and 60% of the men who had asked for a raise received the raise:
This means that [tex]P(A) = 0.21, P(A \cap B) = 0.21*0.6[/tex], thus:
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.21*0.6}{0.6} = 0.6[/tex]
P(man received raise, given he asked for one) = 0.6.
Question c:
[tex]P(A \cap B) = 0.21*0.6 = 0.126[/tex]
P(man asked for raise and received raise) = 0.126.
What is the greatest common factor of 3^3 x 5^4 and 2 x 5^3 x 11?
[tex]\huge\textsf{Hey there!}[/tex]
[tex]\mathsf{3^3 \times 5^4}[/tex]
[tex]\mathsf{3^3}[/tex]
[tex]\mathsf{= 3\times3\times3}[/tex]
[tex]\mathsf{= 9\times3}[/tex]
[tex]\mathsf{= \bf 27}[/tex]
[tex]\mathsf{5^4}[/tex]
[tex]\mathsf{= 5\times 5\times5\times 5}[/tex]
[tex]\mathsf{= 25\times25}[/tex]
[tex]\mathsf{= \bf 625}[/tex]
[tex]\mathsf{27 \times625}[/tex]
[tex]\mathsf{= \bf 16,875}[/tex]
[tex]\mathsf{2\times5^3\times11}[/tex]
[tex]\mathsf{5^3}[/tex]
[tex]\mathsf{= 5\times 5\times5}[/tex]
[tex]\mathsf{= 25\times 5}[/tex]
[tex]\mathsf{\bf = 125}[/tex]
[tex]\mathsf{2\times125\times11}[/tex]
[tex]\mathsf{= 250\times11}[/tex]
[tex]\mathsf{\bf = 2,750}[/tex]
[tex]\large\textsf{Find the Greatest Common Factor (GCF) of 16,875 \& 2,750}[/tex]
[tex]\large\textsf{16,875: 1, 3, 5, 9, 15, 25, 27, 45, 75, 125, 135, 225, 375, 625, 675, 1,125,}\\\\\large\textsf{1,875, 3,375, 5,625, \& 16,875}[/tex]
[tex]\large\textsf{2,750: 1, 2, 5, 10, 11, 22, 25, 50, 55, 110, 125, 250, 275, 550, 1,375, \& 2,750}[/tex]
[tex]\boxed{\boxed{\huge\textsf{Answer: the GCF is \bf 125 }}}\huge\checkmark[/tex]
[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Using the following image, solve for x.
Answer:
please provide an image.
Weatherwise magazine is published in association with the American Meteorological Society. Volume 46, Number 6 has a rating system to classify Nor'easter storms that frequently hit New England states and can cause much damage near the ocean coast. A severe storm has an average peak wave height of 16.4 feet for waves hitting the shore. Suppose that a Nor'easter is in progress at the severe storm class rating.
(A) Let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. What would be the null hypothesis regarding average wave height?
a) μ < 16.4.
b) μ > 16.4.
c) μ = 16.4.
d) μ ≠ 16.4.
(B) If you wanted to test the hypothesis that the storm is getting worse, what would you use for the alternate hypothesis?
a) μ < 16.4.
b) μ = 16.4.
c) μ ≠ 16.4.
d) μ > 16.4.
(C) If you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis?
a) μ < 16.4.
b) μ ≠ 16.4.
c) μ > 16.4.
d) μ = 16.4.
(D) Suppose you do not know if the storm is getting worse or dying out. You just want to test the hypothesis that the average wave height is different (either higher or lower) from the severe storm class rating. What would you use for the alternate hypothesis?
a) μ > 16.4.
b) μ = 16.4.
c) μ ≠ 16.4.
d) μ < 16.4.
(E) For each of the tests in parts (b), (c), and (d), would the area corresponding to the P-value be on the left, on the right, or on both sides of the mean?
a) left; right; both.
b) left; both; right.
c) both; left; right.
d) right; left; both.
Answer:
a) c) μ = 16.4.
b) d) μ > 16.4.
c) a) μ < 16.4.
d) c) μ ≠ 16.4.
e) d) right; left; both.
Step-by-step explanation:
Question a:
Test if it is getting worse, so at the alternative hypothesis we test if the mean is of greater than 16.4 inches, but at the null hypothesis we test if it is still of 16.4 options, so option C.
Question b:
At the alternative hypothesis we test if the mean is of greater than 16.4 inches, as said above, so the answer is given by option d.
Question c:
Dying down, so if the mean is lower than 16.4 inches, so option a.
Question d:
Don't know, so just test if it is different, which includes both lower or greater, so the correct answer is given by option c.
Question e:
Test if more -> right, so on question b) is a right tailed test.
Test if less -> left, so on question c) is a left tailed test.
Different -> both sides, so on question d) it is a two-tailed test.
Thus the correct answer is given by option d.
Mark gathered data about the number of pink and red flowers that bloomed on several of his flowering shrubs. The scatter plot shows the data he gathered and the line of best fit.
The scatter plot showing data gathered and line of best fit is attached below :
Answer:
69
Step-by-step explanation:
Given the regression model :
y = 1.73x + 0.0924
Where,
y = number of pink flowers
x = Red flowers
Slope = 1.73
Intercept = 0.0924
The number of pink flower that are predicted to bloom on a shrub of 40 red flowers :
Put x = 40 and calculate the value of y
y = 1.73(40) + 0.0924
y = 69.2 + 0.0924
y = 69.2924
Number of pink flowers = 69
PLEASE HELP WILL MARK BRAINLIEST!
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Answer:
7.5
Step-by-step explanation:
Corresponding sides are proportional, so ...
UV/VW = LM/MN
x/6 = 15/12
x = 6(15/12) = 15/2
x = 7.5
What is the area of triangle ABC? - OP 03 square units 0 7 square units o 11 square units 0 15 square units see pic
Answer:
7 sq unit
Step-by-step explanation:
Area of triagle ABC = Area of rectangle mnBp - Area of trangle AmC - Are of triangle CnB - Area of triangle ABp
Area of rectangle mnBp = 5x3 = 15 sq unit
Area of trangle AmC = 4x2 /2 = 4 sq unit
Are of triangle CnB = 5x1 /2 = 2.5 sq unit
Area of triangle ABp = 3x1 /2 = 1.5 sq unit
I believe you can work out thd answer from the above
Translate the sentence into an inequality. The product of w and 2 is less than 23.
Answer:
2w<23
Step-by-step explanation:
The product of w and 2 mean that w multiplied by 2
5. Lisa has a cubed-shaped box with a
volume of 512 cm. If Lisa fills the box
with 1-cubic centimeter blocks, how
many blocks make up each layer?
Answer:
64
Step-by-step explanation:
[tex]\sqrt[3]{512} = 8\\8x8 = 64[/tex]
How to find B?
what type of angle is it?
Answer:
Obtuse angle; 57°
Step-by-step explanation:
b and 43° form a right angle. A right angle is 90°. Solution: 90°-43°=57°
43° is acute, so angle b must be obtuse.
For any number n>1, is
|(.5 +.2i)^n|
A. greater than 1?
B. less than 1?
C. equal to 1?
PLZ HELP
Answer:
B. Less than 1
Step-by-step explanation:
You could plug in values of n greater than 1 and see what happens....
Example n=2 gives |(.5+.2i)^2|
Simplifying inside gives |(.5)^2+2(.5)(.2i)+(.2i)^2|
=|.25+.2i+.04i^2|=|.25+.2i-.04|=|.21+.2i|.
Applying the absolute value part gives sqrt(.21^2+.2^2)=sqrt(.0441+.04)=sqrt(.0841)=.29
This value is less than 1.
We should also be able to do the absolute value first then the power.
|.5+.2i|=sqrt(.25+.04)=sqrt(.29)
So |.5+.2i|^2=.29 which is what we got long way around.
Anyways (sqrt(.29))^n where n is greater than 1 will result in a number greater than 0 but less than 1.
A person participates in a weekly office pool in which he has one chance in ten of winning the prize. If he participates for 5 weeks in succession, what is the probability of winning at least one prize.
The probability of winning at least one prize is 0.40951.
What is probability?Probability is the likelihood that an event will occur.
The following information can be deduced:
P = probability of winning = 1/10
q = probability of not winning = 1- (1/10) = 9/10
x = no. of winning
then, p (x ≥ 1) = 1 - p (x < 1)
= 1 - p (x=0)
= 1 - ⁵C₀ (1/10)^⁰ (9/10)^(5-0)
= 1 - (1) (1) (9/10)^5
= 1 - (9/10)^5
= 1 - 0.59049
= 0.40951
Therefore, the probability is 0.40951.
Learn more about probability on:
https://brainly.com/question/24756209
#SPJ1
Please answer i will give you brainlest please help me
have attached the solution, couldn't solve 13 and 17 tho, if it helps, then do mark me the brainliest...
Btw, which class r u in?
Step-by-step explanation:
Find functions f(x) and g(x) so the given function can be expressed as
h(x) = f(g(x)).
(Use non-identity functions for
f(x) and g(x).)
h(x) = 5/x-4
Answer:
[tex]f(x) = \frac{5}{x}[/tex]
[tex]g(x) = x - 4[/tex]
Step-by-step explanation:
Composite function:
[tex]h(x) = f(g(x)) = (f \circ g)(x)[/tex]
h(x) = 5/x-4
We have x on the denominator and not the numerator, so the outer function is given by:
[tex]f(x) = \frac{5}{x}[/tex]
The denominator is x - 4, so this is the inner function, so:
[tex]g(x) = x - 4[/tex]
If s(x)= 2 -x^2 and f(x)=3x, which value is equivalent to (s°f)(-7)
Please help i need answer asap
Answer:
23
Step-by-step explanation:
When simplified (32/3125)^(2/5) is the same as 4/25 true or false?
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Answer:
True
Step-by-step explanation:
Your calculator can tell you this is true. Or, you can simplify the given expression:
[tex]\left(\dfrac{32}{3125}\right)^{2/5}=\left(\dfrac{2^5}{5^5}\right)^{2/5}=\dfrac{2^2}{5^2}=\boxed{\dfrac{4}{25}}[/tex]
__
The applicable rule of exponents is (a^b)^c = a^(bc).
Which statement is true about the equations
-3x + 4y = 12 and 1/4x-1/3y = 1
O The system of the equations has exactly one solution at (-8, 3).
O The system of the equations has exactly one solution at (-4, 3).
O The system of the equations has no solution; the two lines are parallel.
O The system of the equations has an infinite number of solutions represented by either equation.