In a certain fraction, the denominator is 4 larger than the numerator. If 2 is added to both the numerator and the denominator,the result is 3\5. Find the original fraction. PLS ANSWER
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Step-by-step explanation:
Here you go, I tried my best
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The original fraction is [tex]\frac{4}{8}[/tex]
Let the numerator = a
Let the denominator = b
Denominator is 4 larger than the numerator: b = a + 4
2 is added to both the numerator and the denominator: (a + 4 +2) and a + 2
The algebraic equation from the given statement is formed as follows;
[tex]\frac{a+ 2}{a+4+2 } = \frac{3}{5} \\\\\frac{a+ 2}{a + 6} =\frac{3}{5} \\\\5(a + 2) = 3(a + 6)\\\\5a + 10 = 3a + 18\\\\5a - 3a = 18 -10\\\\2a = 8\\\\a =4[/tex]
The original fraction is calculated as follows;
[tex]\frac{a }{a +4} = \frac{4}{4+ 4} = \frac{4}{8}[/tex]
Thus, the original fraction is [tex]\frac{4}{8}[/tex]
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Step-by-step explanation:
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