If you were to roll one die, one time what is the probability it will land on a number other than 3?

Answer:

Larry’s graph is incorrect.He should used a closed circle at -5

Step-by-step explanation:

Answer:

A)Larry’s graph is incorrect. He should have used a closed circle at –5.

Step-by-step explanation:

Answer:

314 cm²

Step-by-step explanation:

Area of a circle is A= πr²

pi is 3.14 and radius is 10:

A= 3.14(10)²

A= 314

Answer:

7/6pie. i think

Step-by-step explanation:

1/2 + 2/3 = 3/6 + 4/6 = 7/6 = 1 1/6

Answer:

1 and 1/6

Step-by-step explanation:

1/2 + 2/3 = 3/6 +4/6= 1 1/6

Answer: 3/4 of the original price.

Step-by-step explanation:

Ok, so Sam buys 4 boxes in Store A.

We know that in Store A you can get 4 boxes paying only for 3.

If P is the price of a Box, then he got 4 boxes and paid 3*P

then the amount that he paid for each box is equal to the total amount that he paid divided the number of boxes that he received.

this is: 3P/4 = (3/4)*P

Meaning that he paid 3/4 of the original price for each box.

Answer:

Your answer will be 1,000

Step-by-step explanation:

One thousand

Hope this helps : )

Answer:

1000

Step-by-step explanation:

Add 100 10 times and you will get 1000

Answer:

23,41 cm (if it's a square triangle)

Step-by-step explanation:

a²+b² = c²

22²+8² = c²

√548 = √c²

23,41 = c

Answer:

s=50*2+1/2*10*2^2=100+20=120 miles

The car travels 120 miles from this point in the next 2 hours, if the acceleration is constant.

There are three equation of motions that can be used when motion of the object is under constant acceleration and on a straight path.

They are listed below as:

[tex]v = u + at\\\\s = ut + \dfrac{1}{2} at^2\\\\v^2 = u^2 + 2as[/tex]

where, the symbols have following meanings:

u = initial velocity of the considered object

v = final velocity of the object

a = acceleration of the object

s = distance traveled by the object in 't' time.

Given; A car is running at a velocity of 50 miles per hour and the driver accelerates the car by 10 miles/hr2.

We are asked that how far the car travels from this point in the next 2 hours, if the acceleration is constant.

s = 50*2 + 1/2*10*2^2

s = 100+20

s = 120 miles

Therefore, the car travels 120 miles from this point in the next 2 hours, if the acceleration is constant.

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Answer:

the slope is either -2/1 or -1/2

Step-by-step explanation:

hope this helped sorry i didnt know the y intercept but i think its 0

Answer:

x×x-5x-6

x × -4X - 6

Step-by-step explanation:

x×x-5x-6

x × -4X - 6

Answer:

  {6-√21, 6+√21}

Step-by-step explanation:

It usually works well to put the x-terms on one side of the equal sign. Then add the square of half the x-term coefficient.

  x^2 -12x = -15 . . . . . . subtract 12x

The x-term coefficient is -12, so the square of half that is (-12/2)^2 = 36. Adding 36, we have ...

  x^2 -12x +36 = -15 +36

  (x -6)^2 = 21

  x -6 = ±√21 . . . . . take the square root

  x = 6 ±√21 . . . . . add 6

The solution set is ...

  {6-√21, 6+√21}

Answer:

[tex] p(O)=\frac{8}{18}=\frac{4}{9}[/tex]

And since we want the complement of choosing an orange juice box the answer would be:

[tex] P(O') =1 - P(O) = 1-\frac{4}{9}= \frac{5}{9}[/tex]

And the nest answer for this case is:

5/9

Step-by-step explanation:

For this case we know that we have 4 apple juice boxes, 8 orange juice boxes, and 6 fruit punch juice boxes, so then the size of the sample space is:

[tex] 8+4+6= 18[/tex]

Then we can find the probability of selecting an orange juice box with the definition of Laplace given by:

[tex] p =\frac{possible}{total}[/tex]

And for this case the possible cases are 4 and the total 18 so then the probability is given by:

[tex] p(O)=\frac{8}{18}=\frac{4}{9}[/tex]

And since we want the complement of choosing an orange juice box the answer would be:

[tex] P(O') =1 - P(O) = 1-\frac{4}{9}= \frac{5}{9}[/tex]

And the nest answer for this case is:

5/9

Answer:

270cm^2

Step-by-step explanation:

The side length is irrelevant and does not matter.

The area of a triangle is found by multiplying the base by the height and then dividing that by two.

For this problem it would be...

30*18=540

540/2=270

So the area would be 270cm^2

Answer:

270

Step-by-step explanation:

Answer:

75%

Step-by-step explanation:

48 of 64 times 100

48/64 × 100

0.75 × 100

75

So 75% of the bottle of orange juice is water

Hope this helps!!

Answer:

-0.06 left-middle

0.28 right-middle

0.03 right-top

0.1 middle-top

0.12 middle-bottom

Step-by-step explanation:

column-row

Answer:

2.53

Step-by-step explanation:

Answer:

p=5

Step-by-step explanation:

please mark brainliest

Answer:

976

Step-by-step explanation:

triangle= 1/2(24)14 times 2

square or rectangle= 10(14), 10(25), 10 (25)

Answer:

10 inches

Step-by-step explanation:

It is 10 inches as you have chosen because the length from the midpoint to a side or the apothem is the length of one side. As given, a side length is 10 inches so, the length of the apothem is 10 inches.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

Answer:

[tex]5\sqrt{3} inches[/tex]

Step-by-step explanation:

Answer:

The solution is attached here. Hope it helps ☺️

Answer:

[tex]r = 3.18cm[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

Answer:

g(x), f(x), h(x)

Step-by-step explanation:

The required functions sequence are -x³, -x² and -|x|.

Three functions in order from the fastest decreasing average rate of change to the slowest decreasing average rate of change on the interval [0, 3].

Rate of change is defined as the change in value with rest to the time is called rate of change.

Question seems to be incomplete, we assumed three functions -x³, -x² and -|x|.
Now, the function has fastest decreasing average rate of change is  -x³
and the function has slowest decreasing average rate of change is  -|x| on the interval [0, 3]. While plotting on graph.

Thus, the required functions sequence are -x³, -x² and -|x|.

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Answer:

Small Boxes: 10

Large boxes: 12

Step-by-step explanation:

Answer:

We conclude that there is difference in the proportion of deaths between the 2 groups.

Step-by-step explanation:

We are given that among 2823 drivers not wearing seat belts, 31 died as a result of injuries, and among 7765 drivers wearing seat belts 16 were killed.

Let [tex]p_1[/tex] = proportion of deaths when drivers were not wearing seat belts.

[tex]p_2[/tex] = proportion of deaths when drivers were wearing seat belts.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1=p_2[/tex]      {means that there is no difference in the proportion of deaths between the 2 groups}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1\neq p_2[/tex]     {means that there is difference in the proportion of deaths between the 2 groups}

The test statistics that would be used here Two-sample z test for proportions;

                          T.S. =  [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex]  ~ N(0,1)

where, [tex]\hat p_1[/tex] = sample proportion of deaths when drivers were not wearing seat belts = [tex]\frac{31}{2823}[/tex] = 0.011

[tex]\hat p_2[/tex] = sample proportion of deaths when drivers were wearing seat belts = [tex]\frac{16}{7765}[/tex] = 0.002

[tex]n_1[/tex] = sample of drivers not wearing seat belts = 2823

[tex]n_2[/tex] = sample of drivers wearing seat belts = 7765

So, the test statistics  =  [tex]\frac{(0.011-0.002)-(0)}{\sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} } }[/tex]

                                       =  4.438

The value of z test statistics is 4.438.

Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistic doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that there is difference in the proportion of deaths between the 2 groups.

Also, Margin of error (E) =  [tex]1.96 \times \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} }[/tex]

                                        =  [tex]1.96 \times \sqrt{\frac{0.011(1-0.011)}{2823}+\frac{0.002(1-0.002)}{7765} }[/tex]

                                        =  0.00397

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

[tex]C = \frac{N!}{(N-K)!*K!}[/tex]

For the juniors we have N = 13 and K = 6

[tex]Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716[/tex]

For the seniors we have N = 16 and K = 8

[tex]Cs = \frac{16!}{8!8!} = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870[/tex]

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

In order to wipe out the whole job, it takes

(9 persons) x (8 hours/day) x (25 days)  =  1,800 person-hours .

12 workers working for 15 days will accomplish

(12 persons) x (H hours/day) x (15 days)  =  180H person-hours  of work.

180H person-hours  =  1,800 person-hours

H = 10

The 12-person team must work 10 hours/day to make this scheme all work out.  

What'll really happen:  

-- In order to keep tabs on the project and make sure it gets done on the accelerated schedule, the managers in Chicago in suits will assign the supervisor to complete the project in 14 days instead of 15, and they'll require him to send them a status report twice each day.

-- After completing and emailing the Noon status report each day, the supervisor will put on his hard-hat and PPE, and head out to work alongside the 12 sweating workers, who will all begin to sag when they pass 9 hours each day.

-- Day #12 will be solid torrential rain, and no progress will be possible.  The men will want to get some rest, but Chicago will call a Zoom meeting to deliver a motivational pep-talk. Attendance will be mandatory.

-- Days #13 and #14 will stretch to 12 hours, but the project will finish in the allotted 14 days.

-- On Day #15, in Chicago, the customer will treat the managers to a fine dinner, drinks, and a Bulls game, in appreciation for completing the project in 15 days.  In the field, the supervisor and the 12 workers will get to sleep in for a whole hour later than usual, before they clean up the job site and begin the long drive home.

(Been there. Done that.)

Answer:

No, the origin is Located at (0,0)

Answer:

no

Step-by-step explanation:

The origin is located at the center of a graph, at (0, 0)

Answer:

B, D

Step-by-step explanation:

The product of a sum and a difference results in a difference of squares.

The product must be of the form (a + b)(a - b) to work.

Answer: B, D

Answer:

(w-2.5)(w+2.5) And (-4v-9)(-4v+9)

Step-by-step explanation:

E2020

Answer:

Null hypothesis: [tex] \mu \geq 60[/tex]

Alternative hypothesis: [tex] \mu <60[/tex]

Since the sample size is large enough we can assume that the distribution for the statistic is normal so then in order to find the critical value for this test taking in count the significance level given of 0.05 we need to look in the normal standard distribution a value who accumulates 0.05 of the area in the left and would be:

[tex] z_{crit}= -1.64[/tex]

Step-by-step explanation:

For this case we have the following data given:

[tex] \bar X = 53[/tex] represent the sample mean

[tex] s = 23[/tex] represent the sample deviation

[tex]n = 10000[/tex] represent the sample size.

We want to test for this case if the true mean is less than 60 so then the system of hypothesis are:

Null hypothesis: [tex] \mu \geq 60[/tex]

Alternative hypothesis: [tex] \mu <60[/tex]

Since the sample size is large enough we can assume that the distribution for the statistic is normal so then in order to find the critical value for this test taking in count the significance level given of 0.05 we need to look in the normal standard distribution a value who accumulates 0.05 of the area in the left and would be:

[tex] z_{crit}= -1.64[/tex]

Answer:

Media: 167.88 cm

Mediana:  167.6 cm

Modo: 166.67 cm

Step-by-step explanation:

Hola!

La variable de interés es:

X: estatura de un alumno de noveno año de educación básica.

1)

Primero debes ordenar los datos de menor a mayor y contar cuantos de ellos corresponden dentro de cada intervalo determinado, por ejemplo, el primer intervalo es:

[160;164)

Los intervalos están definidos con el límite inferior cerrado, es decir que incluye el valor de dicho límite, y el límite inferior abierto, es decir, que ese valor no está incluido en el intervalo.

160,160,160,161,162,163,164,165,165,165,165,166,167,167,167,167,168,168,168,169,170, 170, 170,171,173,173,173,175,175,176.

f(1)= 6 (seis valores de estatura corresponden a este intervalo)

La sumatoria de todas las frecuencias absolutas debe dar por resultado el total de observaciones n= 30

Para el segundo intervalo [164;168)

f(2)= 10

2)

hi representa la frecuencia relativa simple y esta se calcula como fi/n

Por ejemplo para el primer intervalo:

h(1)= f(1)/n= 6/30= 0.20

Esta indica la proporción de que las alturas estén entre 160 y 164 cm.

En porcentaje se expresa como hi*100, para el primer intervalo: 0.20*100)= 20%

Para el segundo intervalo h(2)= f(2)/n= 10/30= 0.33 y su porcentaje es 33%

Como indican la proporción de cada categoría de la distribución, la sumatoria de las frecuencias relativas simples de todas las categorías debe ser 1.

3)

Como lo dice su nombre, esta frecuencia es acumulada y se calcula como la sumatoria de las frecuencias absolutas simples, para el primer intervalo, dado que previo a él no hay "nada" es igual a la frecuencia absoluta simple:

F(1)= f(1)

Para el segundo intervalo, es la frecuencia absoluta simple del primer intervalo más la frecuencia relativa simple del segundo intervalo:

F(2)= f(1) + f(2)= 6 + 10= 16

4)

Esta frecuencia también representa la sumatoria de las frecuencias relativas simples.

H(1)= h(1)= 0.20 como previo al primer intervalo no existe distribución definida, la frecuencia relativa acumulada es igual a la frecuencia relativa simple.

Para el segundo intervalo la frecuencia relativa acumulada es:

H(2)= h(1)+h(2)?= 0.20+0.33= 0.57

Adjunta a la respuesta encontrarás la tabla completa.

5)

Como no específica medidas de tendencia central requeridas, voy a calcular la media, mediana y modo utilizando la tabla.

Media

X[barra]= (∑x'fi)/n= ∑x'*hi

Dónde x' representa la marca de clase de cada intervalo. Para calcular la marca de clase de los intervalos debes realizar un promedio entre sus límites y su valor siempre debe encontrarse dentro de los límites del intervalo. Si no es así, has cometido un error de cálculos:

(Limite inferior + Limite superior)/2

1. [160;164)  x₁'= (160+164)/2= 162

2. [164;168)  x₂'= 166

3. [168;172)  x₃'= 170

4. [172;176)  x₄'= 174

Una vez que calculaste las marcas de clase, puedes calcular la media:

X[barra]= ∑x'*hi= (162*0.20)+(166*0.33)+(170*0.27)+(174*0.20)= 167.88 cm

Mediana:

La mediana es el valor de la variable que divide a la muestra en dos (50%-50%).

Para poder calcularla primero debes identificar su posición, en este tipo de presentación, debes identificar el intervalo en el que se encuentra incluida la mediana.

Para muestras pares, la posición de la mediana se calcula como:

PosMe= n/2= 30/2= 15

Esto significa que la mediana corresponde a la 15va observación de la muestra, observando la columna de las frecuencias absolutas (simples o acumuladas) debes identificar cual es el intervalo de la mediana:

Al segundo intervalo se corresponde una frecuencia acumulada de 16, lo que significa que la posición de la mediana está incluida en este intervalo:

[164;168)

Entonces puedes calcular la mediana como:

[tex]Me= Li + c [\frac{PosMe-F_{(i-1)}}{f_i} ][/tex]

Dónde

Li: es el límite inferior del intervalo de mediana.

c: es la amplitud del intervalo

F₍i₋₁₎: frecuencia absoluta acumulada del intervalo anterior al intervalo mediana

fi: frecuencia absoluta del intervalo mediana

[tex]Me= 164 + 4 [\frac{15-6}{10} ]= 167.6[/tex]

Me= 167.6 cm, como puedes notar, el valor de la mediana se encuentra entre los límites del intervalo.

Modo o Moda:

El modo o la moda de una distribución corresponde al valor más observado, es decir, al valor con mayor frecuencia absoluta simple. Al igual que la media, para calcular el modo primero debes identificar el intervalo que lo contiene. En este caso, el intervalo modal será aquel con la mayor frecuencia absoluta simple.

[164;168)

La fórmula para calcular el modo es:

[tex]Md= Li + c[\frac{(f_{max}-f_{ant})}{(f_{max}-f_{ant})+(f_{max}-f_{post})} ][/tex]

Li: es el límite inferior del intervalo modal

c: es la amplitud del intervalo

[tex]f_{max}[/tex]: es la frecuencia absoluta simple del intervalo modal.

[tex]f_{ant}[/tex]: es la frecuencia absoluta simple del intervalo anterior al intervalo modal.

[tex]f_{post}[/tex]: es la frecuencia absoluta simple del intervalo posterior al intervalo modal.

[tex]Md= 164 + 4[\frac{10-6)}{(10-6)+(10-8)} ]= 164+4[\frac{4}{4+2} ]= 166.67[/tex]

Md= 166.67 cm

¡Espero que tengas un buen día!

Answer:

Hi there!

To find the volume of the ball, we should follow this formula: 

4/3*pi*r^3

Since the radius is 4, we can just plug the value in:

4/3*3.14*4^3

= 267.946667

Round to the nearest tenth:

= 267.9

Your answer is 267.9. 

Hope this helps!

Answer: c

Step-by-step explanation: