Answer:
33 g of H2
Explanation:
N2 + 3 H2 -> 2 NH3
3 mol H2 -> 2 mol NH3
x -> 11 mol NH3
x= (11 mol NH3 * 3 mol H2)/ 2 mol NH3
x= 16.5 mol H2
1 mol H2 -> 2 g
16.5 mol H2 ->x
x= (16.5 mol H2 * 2 g)/ 1 mol H2
x= 33 g
How many bonding electrons are present in PO43- ?
the half life for the reactant A in the first order reaction A-> B is 36.2 seconds what is the rate constant for this reaction
answer :
b because 24 <3
Explanation:
hdjsna surveyed I need points lol sorry for wasting time
Select the correct image
Trees with light brown bark dominate an ecosystem. The ecosystem has populations of insects that thrive on the tree bark. Over time, some
Insect species developed certain physical characteristics that helped them thrive on the tree bark. These physical characteristics also helped the
Insects defend themselves from predators. Which insect species is probably the species with the new physical characteristics?
Answer:
I think the insect would be the one in the second photo reading from left to right
Explanation:
the other insects:
the first of the first photo is a change of what would be the external surface of the insect, it is not the insect itself.
In the third photo, the insect has short legs with little grip, which indicates that it does not climb large areas on top, and finally, the 4 image is of an insect that lives in desert areas and is poorly coordinated in areas of high heat. and sand.
These are the reasons why I chose photo number two reading from left to right
Answer:
I would say that your answer would be the second one.( the red one)
Explanation:
because the legs it has seem like it would grip onto trees fairly well.
During trial 1, the limiting reactant is __________ because_____________________________.
A)aluminum; there was still copper left over after the reaction stopped.
B)copper chloride; there was still aluminum left over after the reaction stopped.
Answer:
B
Explanation:
David prepared the potassium phosphate solution by adding 46.3g to 250 mL of water. Kim needs 0.10M potassium phosphate solution. How many stock solutions does she need if she wants to mix 150 ml of diluent?
Answer:
17.2mL
Explanation:
Step 1:
Determination of the molarity of potassium phosphate K3PO4 solution.
This is illustrated below:
Mass of K3PO4 = 46.3g
Molar Mass of K3PO4 = (39x3) + 31 + (16x4) = 212g/mol
Mole of K3PO4 =..?
Mole = Mass /Molar Mass
Mole of K3PO4 = 46.3/212 = 0.218 mole
Volume of water = 250mL = 250/1000 = 0.25L
Molarity = mole /Volume
Molarity of K3PO4 = 0.218/0.25
Molarity of K3PO4 = 0.872M
Step 2:
Determination of the volume of the stock solution of K3PO4 needed.
Molarity of stock solution (M1) = 0.872M
Volume of stock solution needed (V1) =..?
Molarity of diluted solution (M2) = 0.1M
Volume of diluted solution (V2) = 150mL
The volume of the stock solution needed can be obtained as follow:
M1V1 = M2V2
0.872 x V1 = 0.1 x 150
Divide both side by 0.872
V1 = (0.1 x 150)/0.872
V1 = 17.2mL
Therefore, the volume of the stock solution needed is 17.2mL
Calculate the number of moles of Li3PO4 in 2.2 L of a 0.60 M Li3PO4 solution.
Answer:
1.32 mole
Explanation:
The following data were obtained from the question:
Volume of solution = 2.2L
Molarity of solution = 0.60M
Mole of Li3PO4 =..?
Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is represented as:
Molarity = mole /Volume
With the above formula we can easily calculate the number of mole of Li3PO4 as shown below:
Molarity =mole /Volume
0.6 = mole of Li3PO4 /2.2
Cross multiply
Mole of Li3PO4 = 0.6 x 2.2
Mole of Li3PO4 = 1.32 mole
Therefore, 1.32 mole of Li3PO4 is contained in the solution.
1-bromo-3-isobutil-4-heptanol
Answer:
See explanation.
Explanation:
Hello,
In this case, the chemical structure of the given compound, which is an alcohol, based on the suffix "ol", the bromo radical at the first carbon and the isobutyl radical at the 3rd carbon is shown on the attached picture wherein the hydroxyl is drawn at the 4th carbon. Remember that IUPAC rules for nomenclature help us to easily name or draw organic molecules by indicating the radicals and their positions and the main chain at the en of the name.
Best regards.
The diagrammatic structure for the compound 1-Bromo-3-isobutyl-4-heptanol can be seen in the image below.
When naming an organic compound, we will first consider the longest chain of the carbon atom and attach the substituents in such a way that we will have the lowest number when adding them.
In the compound 1-Bromo-3-isobutyl-4-heptanol, we first draw the seven carbon chain with -OH substituent on the fourth carbon. This was followed by adding the substituent of isobutyl to carbon atom 3 and bromine to carbon atom 1.
Learn more about naming organic compounds here:
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How many liters of air are in a room that measures 10.0 ft × 11.0 ft and has an 8.00 ft ceiling? 1 in. = 2.54 cm (exactly); 1 L = 103 cm3
Answer:
2.42x10^5 L
Explanation:
10.0ft x 11.0 ft x 8.00 ft = 880. ft^3 (1 cubic foot = 28316.8 cubic cm)
880. ft^3 * (28316.8 cubic cm/ 1 cubic foot) = 24,918,784 cm^3
(1L=103 cm^3)
24,918,784 cm^3 (1L/103 cm^3) = 2.42x10^5 L
[tex]2.42*10^5[/tex] liters of air are in a room.
Unit conversions:It helps to show another person the exact amount you have. Assist in solving a mathematical problem, especially in chemistry, where you can follow the units to get to the answer. Show which measurement system the person is using.
1 in. = 2.54 cm
1 L = 10³ cm³
Given: 10.0 ft × 11.0 ft 8.00 ft ceiling
Now, converting into given quantities:
[tex]10.0ft * 11.0 ft * 8.00 ft = 880. ft^3 ( = 28316.8 \text{ cubic cm})\\\\880. ft^3 * (\frac{28316.8 \text{ cubic cm}} {\text{1 cubic foot}} }) = 24,918,784 cm^3\\\\24,918,784 cm^3 (\frac{1L}{10^3 cm^3})= 2.42*10^5 L[/tex]
→ Thus,[tex]2.42*10^5[/tex] liters of air are in a room that measures 10.0 ft × 11.0 ft and has an 8.00 ft ceiling.
Find more information about Unit conversion here: brainly.com/question/13016491
how many moles are in 15 grams of lithium?
Answer:
there are approximately 52 moles in 15 grams of lithium.
How to make crystals using table salt?
Please help I"ll mark you as the BRAINLIEST!!!
Answer:
1.heat a pan of water with just a little bit of water,have a boil
2.chosse ure salt
3.stir in has much salt has u can than take the pan off the heat
4.pour the mix into a glass jar
5.tie a string to an objeet that can lay accross the top and put just the string in ure mix
Explanation oh and look at it everyday hope that helps
Write the formula of the conjugate base for acid HF. Express your answer as a chemical formula or an ion. nothing Request Answer Part B Write the name of the conjugate base found in part A. Spell out the full name of the compound or ion. Request Answer Part C Write the formula of the conjugate base for acid H2O. Express your answer as a chemical formula or an ion. nothing Request Answer Part D Write the name of the conjugate base found in part C. Spell out the full name of the compound or ion. Request Answer Part E Write the formula of the conjugate base for acid H2CO3. Express your answer as a chemical formula or an ion. nothing Request Answer Part F Write the name of the conjugate base found in part E. Spell out the full name of the compound or ion. Request Answer Part G Write the formula of the conjugate base for acid HSO−4. Express your answer as a chemical formula or an ion. nothing Request Answer Part H Write the name of the conjugate base found in part G. Spell out the full name of the compound or ion.
Answer:
Explanation:
HF acid
F ⁻ conjugate base , name is fluoride ion .
H₂O acid
OH⁻ conjugate base , name hydroxide ion
H₂CO₃ acid ,
HCO₃⁻ conjugate base , name bicarbonate ion .
HSO₄⁻ acid bisulphate ion
SO₄⁻² ion , conjugate base ,name sulphate ion .
Use the following terms to fill in the blanks:
a. Molality,
b. Mole Fraction,
c. Molarity, Percent by Mass,
d .Unsaturated, Concentration
1. In chemistry, the most commonly used unit of concentration is_________ .
2. The amount of solute (in any measurement unit) divided by the amount of solvent or solution (in any measurement unit) is defined by the basic term of________________ .
3. Dividing the mass of solute by the total mass of solvent and solute will give you the _____________.
4. A method of describing concentration which shows the comparison of moles of solute to moles_____________.
Answer:
1. Molality.
2. Concentration.
3. Percent by mass.
4. Mole fraction.
Explanation:
Molarity is the measurement by which the number of moles is measured by a solute. The solution here is one liter respectively.
Concentration is the product which is emerged when the amount of the solute is divided by the amount o the solvent or solution.
Mole fraction refers to the number of component moles divided by the number of the solution moles.
1. _ LiBr2 + __K2CO3 -->___ LiCO3 +_ KBr
Reaction Type:
Answer:
Double displacement chemical reaction.
Explanation:
Hello,
In this case, for the given reaction we firstly balance it:
[tex]LiBr_2 +K_2CO3 \rightarrow LiCO3 +2KBr[/tex]
Then, since the lithium and potassium cations are being exchanged to each other from bromide and carbonate, we are talking about a double displacement chemical reaction.
Best regards.
.The Lithosphere is another name used for one of the earth systems. Name this system!
Answer:
Earth's crust
Explanation:
The lithosphere is the rigid outer part of the earth, consisting of the crust and upper mantle. It is the, rigid, rocky outer layer of the Earth, consisting of the crust and the solid outermost layer of the upper mantle. It extends to a depth of about 60 miles (100 km). It is the outer part of the solid earth composed of rock essentially like that exposed at the surface, consisting of the crust and outermost layer of the mantle.
We can also look at it as the solid part of the earth on which plants grow and animals survive. It contains all the rock formations that bear the various minerals found on earth.
The lithosphere is composed of both the crust and the portion of the upper mantle that behaves as a brittle, rigid solid.
Which of the following elements has the lowest ionization energy?
Na
C
F
He
Rb
Explanation:
Na
Na (gas) -> Na+ (g) + e-
Answer:
Rb
Explanation:
If electrons are collectively compressed into a very small volume (e.g., within the core of a dying white dwarf star) where quantum mechanical considerations become important in preventing one electron from occupying space near to a second electron (Pauli exclusion principle), what is the result?
Answer: A degenerate pressure will generate a large force to repel further compression.
Explanation: In the production of new stars from the core of old dying white dwarf stars, the inner parts of the star will experience contraction with the release of heat , as they contract, their atoms will be squeezed such that their electrons start to overlap, and because of the Pauli's exclusive principle which states that no two electrons can occupy same space, the electrons will begin to repel each other and an opposing pressure called degenerate pressure will create a force so that the electrons cannot continually be crushed or overlap. With the limit of contraction, the outer parts of the star will expand and be repelled releasing the old stars called nebula and creating space for the inner new stars to form.
A tetrahedral site in a close-packed lattice is formed by four spheres at the corners of a regular tetrahedron. This is equivalent to placing the spheres at alternate corners of a cube. In such a close-packed arrangement the spheres are in contact and if the spheres have a radius r, the diagonal of the face of the cube is 2r. The tetrahedral hole is inside the middle of the cube. Find the length of the body diagonal of this cube and then find the radius of the tetrahedral hole.
Answer:
Now length of body diagonal of this cube = √3×√2×r =2.45r
Explanation:
a) length of body diagonal of this cube = √3×√2×r = 2.45 r
it can solved as following
length of body diagonal = √3a (where a is edge length of cube)
length of face diagonal = √2a
But length of face diagonal = 2r
Therefore a = 2r /√2 = √2×r
Now length of body diagonal of this cube = √3×√2×r
Two cylinders are made of the same material. Cylinder A is one-fourth (1/4) the length of cylinder B and it has a radius that is four times greater than the radius of cylinder B. What is the ratio of the mass of cylinder A to the mass of cylinder B?
Answer:
[tex]M_{A}[/tex] : [tex]M_{B}[/tex] = 4 : 1
Explanation:
Given that:
Volume of a cylinder = [tex]\pi[/tex][tex]r^{2}[/tex]h
For cylinder A, [tex]l_{A}[/tex] = [tex]h_{A}[/tex] = [tex]\frac{1}{4} l_{B}[/tex] and [tex]r_{A}[/tex] = 4[tex]r_{B}[/tex].
Volume of cylinder A = [tex]\pi[/tex][tex](4r_{B}) ^{2}[/tex] × [tex]\frac{1}{4} l_{B}[/tex]
= 4[tex]\pi[/tex][tex]r_{B} ^{2}[/tex] [tex]l_{B}[/tex]
Volume of cylinder B = [tex]\pi[/tex][tex](r_{B}) ^{2}[/tex] [tex]l_{B}[/tex]
= [tex]\pi[/tex][tex]r_{B} ^{2}[/tex][tex]l_{B}[/tex]
To determine the ratio of their masses, density (ρ) is defined as the ratio of the mass (M) of a substance to its volume (V).
i.e ρ = [tex]\frac{M}{V}[/tex]
Thus, since the cylinders are made from the same material, they have the same density (ρ). So that;
density of A = density of B
density of A = [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex]
density of B = [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]
⇒ [tex]\frac{M_{A} }{4\pi r_{B} ^{2}l_{B} }[/tex] = [tex]\frac{M_{B} }{\pi r_{B} ^{2}l_{B} }[/tex]
The ratio of mass of cylinder A to that of B is given as;
[tex]\frac{M_{A} }{M_{B} }[/tex] = [tex]\frac{4\pi r_{B} ^{2} l_{B} }{\pi r_{B} ^{2} l_{B} }[/tex]
⇒ [tex]\frac{M_{A} }{M_{B} }[/tex] = [tex]\frac{4}{1}[/tex]
Therefore, [tex]M_{A}[/tex] : [tex]M_{B}[/tex] = 4 : 1
Answer:
4.
Explanation:
Hello,
In this case, since we are talking about the same material, their densities are the same:
[tex]\rho _A=\rho _B[/tex]
And each density is defined by:
[tex]\rho _A=\frac{m_A}{V_A} \\\\\rho _B=\frac{m_B}{V_B}[/tex]
Thus, we also define the volume of a cylinder:
[tex]V_{cylinder}=\pi r^2h[/tex]
Therefore, we obtain:
[tex]\rho _A=\frac{m_A}{\pi r_A^2h_A}[/tex]
[tex]\rho _B=\frac{m_B}{ \pi r_B^2h_B}[/tex]
Now, the given information regarding the the length and the radius is written mathematically:
[tex]h_A=\frac{1}{4} h_B\\\\r_A=4 r_B[/tex]
So we introduce such additional equations in:
[tex]\frac{m_A}{\pi r_A^2h_A}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{\pi (4r_B)^2(\frac{1}{4}h_B)}=\frac{m_B}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}[/tex]
So we simplify for the radius and lengths:
[tex]\frac{m_A}{m_B} =\frac{\pi (4r_B)^2(\frac{1}{4}h_B)}{\pi r_B^2h_B}\\\\\frac{m_A}{m_B} =16 *\frac{1}{4}\\ \\\frac{m_A}{m_B} =4[/tex]
So the ratio of the mass of cylinder A to the mass of cylinder B is 4.
Best regards.
can you pls tell me the net ironic equation of H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
please its urgent
Answer:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Explanation:
H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)
A careful observation of the equation above, shows that the equation is already balanced.
To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:
H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)
Base your answers on the graph below, which represents uniform cooling of a sample of a pure substance, starting as a gas. Solid and liquid phases can exist in equilibrium between points
Answer:
D & E
Explanation:
I think this is dealing with latent heat and D & E would be the range where you will find solid and liquid phases in equilibrium, cuz it starts as gas at from A to B, B to C is gas and liquid equilibrium, C to D is liquid, D to E solid and liquid, and then E to F is solid.
2. A flask and stopper have a mass of 110.525 g. A 50.0-mL sample of gasoline is transferred to the flask, and the flask, stopper, and liquid have a mass of 145.028 g. Find the density of gasoline in g/mL. Show work and report density with the appropriate number of significant figures.
Answer:
0.690 g/mL
Explanation:
Density is the ratio of mass to volume:
gasoline mass = (flask+gas mass) - (flask mass) = 145.028 g -110.525 g
gasoline mass = 34.503 g
Density = (gas mass)/(gas volume) = (34.503 g)/(50.0 mL)
Density = 0.690 g/mL
_____
The least-precise number in this calculation is the sample volume, which has 3 significant figures. Thus, the answer is good only to 3 significant figures.
Why was meteorology such a late developer compared to other branches of science?
Answer:
Because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface
Explanation:
Hello,
In this case, meteorology is the branch of science studying the atmosphere in its weather processes and forecasting and it had a late development because of the difficulties of measuring the atmosphere's properties above the earth's reachable surface. We cannot forget that even nowadays, it is very difficult to predict upcoming weathers with the 100 % assurance and with many days in advance.
Best regards.
Meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.
Meteorology is a late developer compared to other branches of science because the measuring the climatic conditions in the atmosphere is difficult and even impossible without the presence of advance technologies.
To find out the weather as well as climatic conditions can't be measured due to it is not reachable to the human like other materials present on the earth surface so we can conclude that meteorology is developed lately as compared to other branches of science due to far away from the reach of humans.
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What is the [H30+] in a solution with (OH) = 1.0 x 10-12 M?
Answer:
Concentration of hydronium ion, H3O+ is 1x10^-2 M
Explanation:
The following data were obtained from the question:
Concentration of Hydroxide ion, [OH-] = 1.0x10^-12 M
Concentration of hydronium ion, [H3O+] =?
Next, we shall determine the pOH of the solution. This is illustrated below below:
pOH = - Log [OH-]
pOH = - Log 1.0x10^-12
pOH = 12
Next, we shall determine the pH of the solution.
pH + pOH = 14
pOH = 12
pH + 12 = 14
Collect like terms
pH = 14 - 12
pH = 2
Finally, we shall determine the Concentration of hydronium ion, [H3O+] as follow:
pH = - log [H3O+]
pH = 2
2 = - log [H3O+]
- 2 = log [H3O+]
[H3O+] = Antilog (-2)
[H3O+] = 0.01M = 1x10^-2 M
How do you draw the following structural formulas: 2,4-dimethylhexane; 4-methyl-2-pentene; 4-chloro-7-methyl-2-nonyne
Answer:
The answer to your question is given below
Explanation:
1. 2,4-dimethylhexane can be drawn as follow:
a. The parent name: Hexane i.e it contains 6 carbon atom.
b. The substitute group attached: Methyl i.e CH3 and it is at carbon 2 and 4.
c. Draw 6 carbon atom in a straight line and put CH3 at carbon 2 and 4. As shown in attach photo.
2. 4-methyl-2-pentene can be drawn as follow:
a. The parent name: pentene i.e it contains 5 carbon atom and the double bond is at carbon 2.
b. The substitute group attached: Methyl i.e CH3 and it is at carbon 4.
c. Draw 5 carbon atom in a straight line and put a double bond at carbon 2 and CH3 at carbon 4 as shown in attach photo.
3. 4-chloro-7-methyl-2-nonyne can be drawn as follow:
a. The parent name: nonyne i.e it contains 9 carbon atom and the triple bond is at carbon 2.
b. The substitute group attached:
i. Chlorine (Chloro) i.e Cl and it is at carbon 4.
ii. Methyl i.e CH3 and it is at carbon 7.
c. Draw 9 carbon atom in a straight line and put a triple bond at carbon 2, Cl at carbon 4 and CH3 at carbon and 7 as shown in attach photo.
The Pecos Pueblo developed as a trading center over time. What evidence in the text supports the idea that this took a long time?
Because of its value as trading center, the Pecos Pueblo grew in size."
One of the last places the trail passed through was the Pecos Pueblo.
The site was just right for the trade.
Today, the trail attracts tourist instead of traiders.
Answer:
hi idk the answer
Explanation:
Using the cell voltage measured for the first cell studied, with cell chemistry Zn/Zn^2+ \ Cu^2+/Cu, and the known half life potential for Zn^2/Zn calculate the reduction potential for Cu^2+/Cu and enter value below.
The information received for this problem were the values obtained during an online lab:
Cu xM cell voltage:1.100 V
Range: 0.005 V
Temp: 25 degrees C
Answer:
The reduction potential of [tex]Cu^2+/Cu[/tex] is [tex]E_c^o = 0.34 \ V[/tex]
Explanation:
From the question we are told that
The potential of the cell is [tex]M_{cell} = E^o _{cell} = 1.100 \ V[/tex]
The range is [tex]R = 0.005 \ V[/tex]
The temperature is [tex]T = 25 ^oC[/tex]
Note the reason why Zn is oxized and Cu is reduced is because Zn is higher than Cu on the electrochemical series
The reaction at the anode is
[tex]Zn ^{2-} _{(aq)} + 2e \to Zn_{(s)} \ \ \ \ \ E^o_a = -0.76 \ V[/tex]
The [tex]E^o\ is \ the \ standard\ oxidation \ potential\ value\ for\ Zn\ oxidation[/tex]
The reaction at the anode is
[tex]Cu^{2+} _{(aq)} + 2e^{-} \to Cu_{(s)} \ \ \ \ \ \ \ \ E^o_c = c \ V[/tex]
Now
[tex]E^o _{cell} = E_c^o - E_a^o[/tex]
substituting values
[tex]1.100 = E_c^o -(- 0.76)[/tex]
[tex]E_c^o = 1.100 - 0.76[/tex]
[tex]E_c^o = 0.34 \ V[/tex]
Hence the reduction potential of [tex]Cu^2+/Cu[/tex] is [tex]E_c^o = 0.34 \ V[/tex]
A burner on a stove produces?
Answer:
thermal energy
Explanation:
Answer:
B- Thermal Energy
Explanation:
Thermal energy is produced due to all of the movement of particles inside the material.
A certain half-reaction has a standard reduction potential E0red = +0.13V . An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.10V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell.
Required:
a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?
b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?
Answer:
a. 1.23 V
b. No maximum
Explanation:
Required:
a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?
b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?
The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E°cell = E°red, cat - E°red, an
If E°cell must be at least 1.10 V (E°cell > 1.10 V),
E°red, cat - E°red, an > 1.10 V
E°red, cat - 0.13V > 1.10 V
E°red, cat > 1.23 V
The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.
The student is now told that the four solids, in no particular order, are magnesium bromide (MgBr2), sugar (C6H12O6), acetic acid (CH3COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.
Answer:
Order is MgBr₂ > KBr > (CH₃COOH) > (C₆H₁₂O₆)
Explanation:
Find the given attachment
A solution with a concentration of 0.0640 g/L CsOH contains 1.260 g CsOH. What is the volume of the solution?
Answer:
19.7 L
Explanation:
Answer:
The answer is 19.7
Explanation: