if the image
Formed by alens in
always diminished!
and erect. What
nature o
F the lens​

Answers

Answer 1

Answer:

The lens is a concave lens

Explanation:

In concave lens, the image formed is erect. diminished and virtual. The more the distance of the object from the mirror, the more diminished the image formed will be. Concave lens are used in binoculars and telescopes and are installed before or in the eye piece to enable a clear focus.


Related Questions

When a satellite is in orbit around the Earth, the force of the gravity on the satellite is...

Answers

Answer:

Is always towards the center of the Earth

Explanation:

find the mass of an object with a density of 1.5 g/cm^3 and had a volume of 8cm^3

Answers

Answer:

12 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 1.5 × 8

We have the final answer as

12 g

Hope this helps you

A copper block rests 17.4 cm from the center of a steel turntable. The coefficient of static friction between block and surface is 0.465. The turntable starts from rest and rotates with a constant angular acceleration of 0.406 rad/s 2 . The acceleration of gravity is 9.8 m/s 2 . After what interval will the block start to slip on the turntable

Answers

Answer:

12.61 s

Explanation:

Given that

Distance from the center if the turntable, r = 17.4 cm = 0.174 m

Coefficient of static friction, μ = 0.465

Angular acceleration, α = 0.406 rad/s²

Acceleration due to gravity, g = 9.8 m/s²

We know that

F_max = μmg

Also, we know that

F = mω²r

Now, for slip to occur, both forces must be equal to one another, and thus

mω²r = μmg

ω²r = μg

ω² = μg/r

ω² = (0.465 * 9.8)/0.174

ω² = 4.557 / 0.174

ω² = 26.19

ω = √26.19

ω = 5.12 rad/s

t = ω/α

t = 5.12/0.406

t = 12.61 s.

Thus, after 12 seconds, the block will start to slip on the turntable

What is the best description for a transverse wave? *
A.The movement of the atoms around the wave is parallel to the movement of the ENERGY it is transferring.
B.The movement of the atoms around the wave is parallel to the movement of the MATTER it is transferring.
C.The movement of the atoms around the wave is perpendicular to the movement of the energy it is transferring.
D.The movement of the atoms around the wave is perpendicular to the movement of the matter it is transferring.

Answers

Answer:

Option - C

Hope it helps you

A machinist with normal vision has a near point at 25 cm. This machinist wears +4.25-diopter eyeglasses in order to do very close work. With these eyeglasses, what is the near point of the machinist?

a. 12 cm
b. 10 cm
c. 7 cm
d. 15 cm
e. 17 cm

Answers

Answer: 12cm.

Explanation:

First we need to calculate the focal length which will be:

= 100 / 4.25

= 23.529

The near point of the machinist will be solved using the equation:

1/u + 1/v = 1/f

where,

v = -25

f = 23.529

1/u + 1/v = 1/f

1/u - 1/25 = 1/23.529

1/u = 1/23.529 + 1/25

u = 12.12cm

u = 12cm approximately

Therefore, the near point of the machinist is 12cm

What is a possible equation fir an ionic compound with calcium

Answers

Answer:

CaO, CaMg, or CaF2

Ca2Cl, CaNa, or CaP

CaF, CaMg, or CaNa

CaO, CaF2, or CaCl2

Explanation: i think

what is simple harmonic motion
give two examples

Answers

Answer:

S.H.M:- If the acceleration of the vibrating body directly varies with the displacement of the body from the mean position and always directed to the mean position, the motion of that body is called simple harmonic motion.

Ex:- (i) The motion of a pendulum is an S.H.M.

(ii) The motion of vibrating mass attached to a spring is an S.H.M.

Ex1- Swing

Swings that we see in the park is an example of simple harmonic motion

Ex2- Hearing

The process of hearing is is impossible without simple harmonic motion. The sound waves that enter our ear causes the eardrum to vibrate back and forth

Bonus Ex- cradle

The back and forth movement of the cradle caused due to a single push and is maintained by the principle of SHM, and hence, caused the baby to sleep.

Hope it helps

A metallic spherical shell has a charge density of 1 mC/m2 on its surface. The shell has radius of 7.5 cm. Determine the electric field magnitude (in kV/m) 10 meters away from the center of the shell.

Answers

Answer:

Explanation:

charge on the shell = 4πR²  x charge density

= 4 x 3.14 x 7.5² x 10⁻⁴ x 10⁻³ C

= 706.5 x 10⁻⁷ C  

electric field = k Q / d² , d is distance of point from centre

= 9 x 10⁹ x 706.5 x 10⁻⁷ / 10²

= 6358.5 N /C

= 6.358 kV / m

If the light ray moves from inside the glass toward the glass–air interface at an angle of 30.0° to the normal, determine the angle of refraction.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete, however, the relationship to between the angle of incidence and angle of refraction is best explained by snell's law with the equation below

ni sinθi = nr sinθr

where ni is the refractive index of the incident medium (assuming it's plate glass then 1.52)

nr is the refractive index of the refractive medium (1.33)

θi is the angle of incidence (30°)

θr is the angle of refraction (X)

If we substitute the values, we have

1.52 × sin 30 = 1.33 × sin X

1.52 × 0.5 = 1.33 × sin X

0.75 = 1.33 × sin X

sin X = 0.75/1.33

sin X = 0.571

X = sin⁻¹ 0.571

X = 34.82°

Thus, the angle of refraction will be 34.82°

the force of gravity acting on an object is known as

Answers

it’s known as the weight of an object

Light of wavelength 400 nm falls on a metal surface having a work function 1.70 eV. What is the maximum kinetic energy of the photoelectrons emitted from the metal?

a. 4.52 eV
b. 3.11 ev
c. 141 eV
d. 2.82 eV
e. 1.70 eV

Answers

Answer:

Ke = 1.41 eV

Explanation:

We know that

h = 6.626 x 10⁻²⁴

c = 3 x 10⁸

λ = 4 x 10⁻⁹ x 1.6 x 10⁻¹⁹

Computation:

Ke = [hc / λ] - w

Ke = [(6.626 x 10⁻²⁴)(3 x 10⁸) / (4 x 10⁻⁹ x 1.6 x 10⁻¹⁹)] - 1.70

Ke = 1.41 eV

While Barb was playing soccer, she was kicked in the anterior thigh by an opposing teammate. Due to this injury, what muscle function may she find difficult to perform?

Answers

Answer:

knee extension is the muscle function that will be difficult to perform.

Explanation:

Barb was kicked in the anterior thigh. Now, the thigh muscles performs a combined operation of moving the knee and leg and they reside in the following compartments.

- Anterior compartment which is composed of knee joint extension and thigh flexion.

- Lateral Compartment which is composed of the tensor fasciae latae, which is a tiny muscle that abducts and centrally will make the thigh to rotate.

-Medial compartment which involves thigh addiction which is rotating of the thigh around the hips.

- Posterior compartment which involves knee joint flexion and high extension.

Thus, from the different compartments listed above, we can see that the muscles that extend the knee and flex the thigh all lie in the anterior compartment of the upper leg.

Thus, we can conclude that knee extension is the muscle function that will be difficult to perform.

A student puts a besker of warm water next to a besker of cold water so that they fough which two statements are true? DA Thermal energy will move from the warm water to the cold water Thermal energy will move from the air to the cold water. Thermal energy utill move from the air to the warm water Thermal energy till move from the cold water to the warm water ​

Answers

Explanation:

so sorry

don't know but please mark me as brainliest please

Which dwarf planet has a moon nearly as large as itself?

Answers

Answer:

The answer is the Pluto.

frequency of a vibrating string with a period of 4 seconds ​

Answers

Answer: 2 Hz (8 cycles/4 s = 2 cycles/s).

Explanation:

If a coil of slinky makes 3 vibrational cycles in one second, then the frequency is 3 Hz. And if a coil makes 8 vibrational cycles in 4 seconds, then the frequency is 2 Hz (8 cycles/4 s = 2 cycles/s).

I need help with this science work

Answers

Please tell us the question and we will try to answer.

Sir what’s your question? You can write it down in the comments

n an experiment of a simple pendulum, measurements show that the pendulum has length m, mass kg, and period s. Take m/s2 . i. Use the measured length to predict the theoretical pendulum period with a range of error (use the error propagation method you learned in Lab 1). ii. Compute the percentage difference (as defined in Lab 1) between the measured value and the predicted value .

Answers

Answer:

The answer is "[tex](1.265 \pm 0.010) \ s \ and \ 0.709 \%[/tex]"

Explanation:

In point i:

[tex]T_{theo}= 2\pi \sqrt{\frac{l}{g}}[/tex]

        [tex]=2\pi\sqrt{\frac{0.397}{9.8}}\\\\= 1.265 \ s[/tex]

If  error in the theoretical time period :

[tex]\frac{\Delta T_{theo}}{T_theo} = \frac{1}{2} \frac{\Delta l }{l}\\\\\Delta T_{theo} = 1.265 \times \frac{1}{2} \times \frac{0.006}{0.397}[/tex]

           [tex]= 0.010 \ s[/tex]

 [tex]T_{theo} = (1.265 \pm 0.010) \ s[/tex]

In point ii:

[tex]\% \ difference = \frac{|T_{exp} -T_{theo}|}{\frac{T_{exp}+T_{theo}}{2}} \times 100[/tex]

                    [tex]= \frac{1.274 -1.265}{\frac{1.274+1.265}{2}} \times 100\\\\=0.709 \%[/tex]

This is a graph of a car speeding up and then reaching a constant speed of 105 m/s . After it finishes speeding up, how far does the car travel during the last 6 seconds of the graph, from 4 to 10 s?

Answers

Answer:

60 m

Explanation:

Concept Used:

We know that the area under a velocity-time graph represents the Displacement of the body

Displacement in the Last 6 seconds:

To find the Displacement in the last 6 seconds, we will find the area under the graph between x = 4 and x = 10

We can see that the shape formed is a rectangle also shown in the given graph. So, the area of the rectangle is the Displacement of the car in the last 6 seconds

Area of the Rectangle:

From the graph, we know that the rectangle is 10 (m/s) tall and 6 (s) wide

Area of Rectangle=  length*Breadth        

replacing the values

Area = 10 (m/s) * 6 (s)

Area = 60 m

Hence, the car travelled 60 m in the last 6 seconds of the graph

Under what conditions the reaction rate of an enzymolysis that follows Michaelis-Menten kinetics is a quarter of its maximum value?

a. [S]=KM
b. [S]=KM/3
c. [S]=2KM
d. [S]=KM+3
e. [S]= (KM)^1/3

Answers

Solution :

Michaelis-Menten kinetics in the field of biochemistry is considered as one of the well known models for enzyme kinetics. The model represents an equation that describes the enzymatic reactions's rate by relating the reaction rate to the substrate's concentration. The equation is named after the two famous scientists,  Leonor Michaelis and Maud Menten.

The formula is :

[tex]$v=\frac{V_{max}[S]}{K_M + [S]}$[/tex]

where v = velocity of reaction

           [tex]$V_{max}$[/tex] = maximum rate achieved

           [tex]$K_M$[/tex] = Michaelis constant

           [S] = concentration of the substrate, S

According to the question, by putting the velocity of reaction, v as [tex]$\frac{V_{max}}{4}$[/tex], we get the above equation as

[tex]$[S]= \frac{K_M}{3}$[/tex]

Therefore the answer is [tex]$[S]= \frac{K_M}{3}$[/tex]

At the focal point of a converging lens, the object cannot be seen. O A. True B. False​

Answers

Answer: True

Explanation: Guessed on A p E x and it was correct

Answer:

True

Explanation:

a p e x

Calculate the pressure in pascals if a 560N is applied to an area of 1.6m².​

Answers

Answer:

P = 350 [Pa]

Explanation:

The pressure is calculated by knowing the force and area. By means of the following formula can be calculated by means of the following equation.

Units of 1 [Pa] = 1 [N/m²]

P = F/A

where:

P = pressure [Pa]

F = force = 560 [N]

A = area = 1.6 [m²]

P = 560/1.6

P = 350 [Pa]

What form of energy is released into the atmosphere by the earth's surface

Answers

Answer:

Thermal Energy (Heat)

Answer:

Heat

Explanation:

the form that is raised from the atmosphere from earths surface is heat

Imagine holding two identical bricks under water. Brick A is just beneath the surface of the water, while brick B is at a greater depth. What is the force needed to hold brick B in place? (Assume the density of water doesn't change with height.) a) the same as b) larger c) smaller than the force required to hold brick A in place.

Answers

Answer:

I think it's c

Explanation:

The brick's mass, helps to hold it under the water but brick A is being held up. If you dropped the brick, it would sink to the bottom. You need a stronger force to hold it up.

Hope this helps you! x

Buoyancy force is needed to hold brick B in place.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Upthrust, often known as buoyancy, is an upward force applied by a fluid against the weight of an object that is partially or completely submerged. The weight of the fluid on top causes pressure in a fluid column to rise with depth. The brick's mass, helps to hold it under the water but brick A is being held up. If you dropped the brick, it would sink to the bottom. You need a stronger force to hold it up.

Buoyancy force is needed to hold brick B in place.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ6

For a 99 kg person standing at the equator, what is the magnitude of the angular momentum about Earth's center due to Earth's rotation?

Answers

Answer:

L = 4.58 x 10⁴ kg.m²/s

Explanation:

The angular momentum is given by the formula:

L = mvr

but, v = rω

Therefore,

L = mr²ω

where,

L = Angular Momentum of the person = ?

m = mass of person = 99 kg

r = radius of earth = 6.37 x 10⁶ m

ω = Angular Speed of Earth's Rotation = θ/t

Since, earth completes 1 rotation in 1 day. Hence,

ω = (2π rad/1 day)(1 day/24 h)(1 h/3600 s)

ω =  7.27 x 10⁻⁵ rad/s

Therefore,

L = (99 kg)(6.37 x 10⁶ m)²(7.27 x 10⁻⁵ rad/s)

L = 4.58 x 10⁴ kg.m²/s

I need help ASAP
The water cycle functions because the matter in water changes:

a.forms
b.properties
c.minerals

Answers

Answer:

(a). forms.

Explanation:

Bro even i ain't sure.

Answer:

I think its A? Because in the water cycle it goes from a liquid to a gas?

Explanation:

If an object has a mass of 47 kg and it is moved 27 meters in 60 seconds, how much power was used?

Answers

Answer: 207 W

Explanation: I assumed here that the object is moved vertically. If that is the case, the work done on the object is equal to its change in gravitational potential energy:

where

m = 47 kg is the mass of the object

g = 9.8 m/s^2 is the acceleration of gravity

is the change in height

Substituting,

Now we can calculate the power used, which is given by

Hope this helps I'm sorry if i'm wrong but I tried :(

The density for gold is 19.3 g/cm3. What would be the mass of a 45 cm3 piece of gold?

Answers

Answer:

868.5 g

Explanation:

Mass= Density x Volume

Mass= 19.3 x 45

=868.5

Answer:

675.5g

Explanation:

The formula for density is: D = m/V.

To solve this problem, we need to rearrange this formula to solve for mass:

m = D x V.

Next, we plug the given values in for density, D, and volume, V:

m = 19.3 g/cm3 x 35 cm3

So, m = 675.5 g

People have been able to make materials such as fiber optics cables A. using nails and screws. B. using glue and scissors. C. using rocks and stones. D. using science and technology.

Answers

Answer:

D

Explanation:

When a 20.0-ohm resistor is connected across the terminals of a 12.0-V battery, the voltage across the terminals of the battery falls by 0.300 V. What is the internal resistance of this battery?

a. 3.60 Ω
b. 0.51 Ω
c. 0.30 Ω
d. 1.56 Ω
e. 0.98 Ω

Answers

Answer:

B. 0.51 ohms

Explanation:

Our data is as follows:

Resistor R = 20.0ohms

V1 = 12 volts

V2 = 0.300 V

We are to get the internal resistance of this battery

Now,

I = change in voltage/R

Change in voltage = v1-v2

= 12-0.300

= 11.7

Then,

I = 11.7/20

= 0.585Ri

Now

O.300 = 0.585Ri

Ri = 0.300/0.585

= 0.51 ohms

This is therefore the internal resistance of the battery.

Thank you!

A particle with charge q and mass m moving with speed v in the x direction enters a magnetic field of strength B pointing in the y direction. The magnitude of the acceleration of the particle as it travels one semicircle is

Answers

Answer:

The acceleration of the particle as it travels one semicircle is

[tex]a= \frac{\pi R}{t^2}[/tex]

Explanation:'

Kindly see attached a sketch of a semi-circle

Step one:

given data

velocity =v

let the time taken be t

The path PQM is the distance covered

so distance [tex]d= \pi R[/tex]

we know that time= distance/velocity

t= πR/v

step two:

velocity =distance/time

[tex]velocity=\frac{\pi R}{t}[/tex]

also, we know that acceleration is velocity/time

[tex]a= \frac{\pi R}{\frac{t}{t} }[/tex]

[tex]a= \frac{\pi R}{t}*\frac{1}{t}[/tex]

[tex]a= \frac{\pi R}{t^2}[/tex]

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