does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?
Given equation of the Circle is ,
[tex]\sf\implies x^2 + y^2 = 25 [/tex]
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
[tex]\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2[/tex]
Here we can say that ,
• Radius = 5 units
• Centre = (0,0)
Finding distance between the two points :-
[tex]\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }[/tex]
Here we can see that the distance of point from centre is less than the radius.
Hence the point lies within the circle .
inside the circle
Step-by-step explanation:
we want to verify whether (-4,2) lies inside or outside or on the circle to do so recall that,
if [tex]\displaystyle (x-h)^2+(y-k)^2>r^2[/tex] then the given point lies outside the circleif [tex]\displaystyle (x-h)^2+(y-k)^2<r^2[/tex] then the given point lies inside the circleif [tex]\displaystyle (x-h)^2+(y-k)^2=r^2[/tex] then the given point lies on the circlestep-1: define h,k and r
the equation of circle given by
[tex] \displaystyle {(x - h)}^{2} + (y - k) ^2= {r}^{2} [/tex]
therefore from the question we obtain:
[tex] \displaystyle h= 0[/tex][tex] \displaystyle k= 0[/tex][tex] {r}^{2} = 25[/tex]step-2: verify
In this case we can consider the second formula
the given points (-4,2) means that x is -4 and y is 2 and we have already figured out h,k and r² therefore just substitute the value of x,y,h,k and r² to the second formula
[tex] \displaystyle {( - 4 - 0)}^{2} + (2 - 0 {)}^{2} \stackrel {?}{ < } 25[/tex]
simplify parentheses:
[tex] \displaystyle {( - 4 )}^{2} + (2 {)}^{2} \stackrel {?}{ < } 25[/tex]
simplify square:
[tex] \displaystyle 16 + 4\stackrel {?}{ < } 25[/tex]
simplify addition:
[tex] \displaystyle 20\stackrel { \checkmark}{ < } 25[/tex]
hence,
the point (-4, 2) lies inside the circle
Brainly to whomever somehow solves for g & k. I WILL REPORT SCAMS AND UNHELPFUL/ UNRELATED ANSWERS.
Answer:
g = 48
k = 18
Step-by-step explanation:
h / 10 = 60 / 12
h / 10 = 5
h = 5 x 10
h = 50
40 / h = g / 60
40 / 50 = g / 60
4 / 5 = g / 60
g = ( 60 x 4 ) / 5
= 12 x 4
g = 48
90 / k = 60 / 12
90 / k = 5
k = 90 / 5
k = 18
help please
h - (-2) ≥ 10
Answer:
answer
Step-by-step explanation:
h+2 ≥ 10
h ≥ 10 - 2
h ≥ 8
FACTOR....
x^2 + 10× - 2400 = 0
Answer:
x= -5 + 5[tex]\sqrt{97}[/tex], x= -5 - 5[tex]\sqrt{97}[/tex]
Step-by-step explanation:
Since this quadratic is set to zero, we can use the quadratic formula to solve this.
x^2 + 10x - 2400 = 0
Quadractic formula = x= -b +- [tex]\sqrt{b^2 - 4ac}[/tex] /2a
For this equation:
a= 1, b=10, c=-2400
Plug these numbers into the equation and solve.
x= -10 +- [tex]\sqrt{10^2 - 4(1)(-2400}[/tex])/2(1)
x= -10 +- [tex]\sqrt{100 + 9,600}[/tex]/2
x= -10 +- [tex]\sqrt{9,700}[/tex]/2
x= -10 +- [tex]\sqrt{2^2 * 5^2 * 97}[/tex]/2
x= -10 +- 5 * 2[tex]\sqrt{97}[/tex]/2
x= -10 +- 10[tex]\sqrt{97}[/tex] / 2
Divide by 2.
x= -5 +- 5[tex]\sqrt{97}[/tex]
Answer:
x= -5 + 5[tex]\sqrt{97}[/tex] or x= -5 - 5[tex]\sqrt{97}[/tex]
PLSSS I REALLY NEED HELP RIGHT NOW!! 20 POINTSS??
Answer:
15/12
Step-by-step explanation:
[tex]x = \frac{31}{12} - \frac{8}{6} = \frac{15}{12} [/tex]
and it says don't reduce otherwise u could also say 5/4
Find the solutions of the equation 3x = x4, rounded to two decimal places. (Enter your answers as a comma-separated list.)
Answer:[tex]-0.802; \ 1.517[/tex]
Step-by-step explanation:
Given
[tex]3^x=x^4[/tex]
Here, two functions are given that is [tex]y=3^x[/tex] and [tex]y=x^4[/tex]
Check for the intersection of the graph of two curves
From the graph, they cut at two different points i.e. [tex]x=-0.802\ \text{and}\ x=1.517[/tex]
Rest two roots are negative.
can you explain it please and which method is correct?
Answer:
The second one (answer of 3), but the other ones could've worked, they were just calculated wrong.
Step-by-step explanation:
Here's why each one did or didn't work:
First answer- you had the right idea by cancelling out the two in the denominator, however if you're going to divide 2, you have to divide it from everything in the equation. Meaning you would divide 4 by 2 to get 2, and then add the 1 + 2 to get final answer 3.
Second answer- since you added the numerator separately and then did the basic division, this worked.
Third one- similarly to the first one, you would have to also divide the 2 by 2 to get 1, then adding 1 + 2 to get 3.
Determine whether the lines are parallel, perpendicular, or neither.
9x + 3y = 12
24x + 8y = 35
Answer:
parallel
Step-by-step explanation:
Let's rewrite each equation into the slope-intercept form so that we can easily identify the slope of each line.
slope-intercept form: y= mx +c, where m is the gradient and c is the y-intercept.
9x +3y= 12
3x +y= 4 (÷3 throughout)
y= -3x +4 -----(1)
24x +8y= 35
8y= -24x +35 (-24x on both sides)
[tex]y = - 3x+ 4 \frac{3}{8} [/tex] -----(2)
Thus, the slopes of the lines are both -3. Since both lines have the same gradient, they are parallel to each other.
Notes:
• parallel lines have the same gradient
• the product of the gradients of two perpendicular lines is -1
• gradient and slope has the same meaning and can thus be used interchangeably
3c(p-6)+4(p-6)= write the correct expression in factored form.
[tex]\tt\displaystyle\ 3c\underline{(p-6)}+4\underline{(p-6)}=(p-6)(3c+4)[/tex]
can you help me with these algebra problems please
Answer:
4
Step-by-step explanation:
3*10=10+5s
30 = 10 + 5s
30-10 = 5s
or, 20/5= s
or, 4 =s
therefore the value of s is 4.
thank you
help me pls I dont get this
Answer:
D
Step-by-step explanation:
The answer is D because if you flip those circles down and wrap the rectangle around it will create a cylinder
(4, -6), (3, -8)
Find midpoint
Find the area of the rectangle whose dimensions are 5cm x 9cm.
Answer: 45
Step-by-step explanation: 9*5=45
Step-by-step explanation:
hope it helps you........
If z varies jointly as x and y and inversely as w^2?, and
z = 72 when x = 80, y = 30 and
w=5, then find z when x = 20, y = 60 and w=9.
Answer:
Step-by-step explanation:
z = (k*x*y) / w²
Where,
k = constant of proportionality
z = 72 when x = 80, y = 30 and w = 5
z = (k*x*y) / w²
72 = (k * 80 * 30) / 5²
72 = 2400k / 25
Cross product
72 * 25 = 2400k
1800 = 2,400k
k = 2,400/1800
k = 24/18
= 4/3
k = 1 1/3
k = 1.33
find z when x = 20, y = 60 and w=9
z = (k*x*y) / w²
z = (1.33 * 20 * 60) / 9²
z = (1596) / 81
Cross product
81z = 1596
z = 1596/81
z = 19.703703703703
Approximately,
z = 19.7
What is the product?
Step-by-step explanation:
(3a^2b^7)(5a^3b^8)15a^5b^15hope it helps
stay safe healthy and happy...Answer:
Step-by-step explanation:
Multiply the numbers. For multiplying variables, if they have same variables, add the exponents.
(3a²b⁷)*(5a³b⁸) = 3*5* a²⁺³ *b⁷⁺⁸
= 15a⁵b¹⁵
Find the area of the shape below.
11 cm
14 cm
9 cm
20 cm
Answer:
length divided by breadth divided by height
pls add me as brainliest
Solution:
20 - 1 1 = 9 cm
We can divide figure in 2 parts
rectangle = 14 cmx 11 cm
square = 9 cm x 9 cm
Area of rectangle = 14 * 11 = 154 cm²
Area of square = 9 * 9 = 81 cm²
Total area = 154 + 81
= 235 cm²
What else would need to be congruent to show that triangle EFG=~ triangle HIJ by SSS?
A
P
E
X
Answer:
C
Step-by-step explanation:
In order to prove congruency using SSS, we need to prove that all three pairs of sides are congruent.
We are already given that EF ≅ HI and that FG ≅ IJ.
Therefore, the last bit of information we need to prove congruency using SSS is that EG ≅ HJ.
Hence, our answer is C.
alguien que me ayude porfavor !!!!!
please help answer these!!!!
Jimmy’s family moved to a tropical climate. For the year that followed, he recorded the number of days that had a temperature above 400C each month. His data contained -
14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13 and 8
1) Find the mean for his data set of days that had a temperature above 400C.
2) Find the median for his data set of days that had a temperature above 400C.
3) Find the mode for his data set of days that had a temperature above 400C.
4) If, instead, there are 5 more days per month that had a temperature above 400C, what will be the mean for the data?
5) If, instead, there are 2 more days per month that had a temperature above 400C, what will be the mode for the data?
Answer:
1) 11.75
2) 11.5
3) 11 and 14
4) 16.75
5) 13, and 16
Step-by-step explanation:
The given data is 14, 14, 10, 12, 11, 13, 11, 11, 14, 10, 13, 8
1) The mean, [tex]\overline x[/tex] = (14+14+10+12+11+13+11+11+14+10+13+8)/12 = 11.75
2) The data arranged in increasing order is presented as follows;
8, 10, 10, 11, 11, 11, 12, 13, 13, 14, 14, 14
The count of he data points = 12
The median = The data at the (n + 1)/2 = (12 + 1)/2 = 6.5th position = 11 + (12 11)/2 = 11.5
The median = 11.5
3) The mode of the data set are 11 and 14
4) Where there are 5 more days per month that had a temperature above 40°C, we get;
The mean, [tex]\overline x_1[/tex] = (14+14+10+12+11+13+11+11+14+10+13+8+5×12 )/12 = 16.75 = [tex]\overline x[/tex] + 5
5) Given that there are 2 more days per month that had a temperature above 40°C, we get the days per month with temperatures above 40°C as follows;
8 + 2, 10 + 2, 10 + 2, 11 + 2, 11 + 2, 11 + 2, 12 + 2, 13 + 2, 13 + 2, 14 + 2, 14 + 2, 14 + 2
10, 12, 12, 13, 13, 13, 14, 15, 15, 16, 16, 16
Therefore, the mode are 13, and 16
Express tan J as a fraction in simplest terms
Answer:
3/4
Step-by-step explanation:
tangent is opp/ad
so that is 15/20, or 3/4
Which equation represents a line which is parallel to the line y=3x–8
Answer:
The equation of line which is parallel to the given line is y = 3 x + k.
Step-by-step explanation:
The equation of the line is
y = 3 x - 8
Compare with the standard equation
y = mx + c
The slope of line is
m = 3
So, the line parallel to the given line is
y = 3 x + k
where, k is any real number.
Please help me with this
Answer:
120 in^2
Hope it helps
WILL MAKE BRAINLIEST IF CORRECT!!
What is the equation of the line? *easy*
Answer:
y = - 7
Step-by-step explanation:
The equation of a horizontal line parallel to the x- axis is
y = c
where c is the value of the y- coordinates the line passes through.
The line passes through all points with a y- coordinate of - 7, then
y = - 7 ← equation of line
the segment shown below would form a triangle 9 4 11
A study was conducted that showed strong positive correlation between eating strawberries and the number of freckles on a person's face. Can we say that eating strawberries causes freckles? Explain. Hint: Think about what causes freckles to be more visible. Name a lurking variable for this situation.
Answer:
No
Step-by-step explanation:
No we cannot say that eating strawberries causes freckles. The question says that the study showed a strong positive correlation. The answer is no because a positive correlation does not mean that there is a causation. When two things are said to correlate, it does not mean that one causes the other, correlation between two things could be as a result of another third variable that affects the both of them. The lurking variable here is going to be sunlight. this is because sunlight exposure affects both variables by causing increases in the growth of strawberries and freckles.
The answer to whether eating strawberries causes freckles is; No, it doesn't cause freckles
What is a lurking variable?
A lurking variable is an explanatory variable that was not considered in a study, but yet affects the value of the response variable in the study.
In this question, the lurking variable is going to be sunlight due to the fact that sunlight exposure affects both variables by causing increase in the growth of strawberries and freckles.
Thus, we can conclude that there is no way we can say that eating strawberries causes freckles due to the fact that a positive correlation does not mean that there is a causation.
Read more about Lurking variables at; https://brainly.com/question/14289293
Which overlapping triangles are congruent by ASA?
B.
3
Select one:
O a.
AABE , ADEA
O b. AADC AEDA
O c.
AABE & ACDA
O d.
AADC AEBC
ya
Answer:
D. ADC EBC
Step-by-step explanation:
cb & cd have that little line showing they're the same
Module 5: Directions: Respond to this question to demonstrate your understanding of the topic/content. Be sure to provide adequate and relevant details learned in the module to support your response. Pay close attention to organizing your response so it makes sense and uses correct grammar. Your response should be at least 5-7 sentences at a minimum.
Question: How do you determine whether a system of linear equations has no solution, one solution, or infinitely many solutions? Describe what each type of solutions look like.
Answer:
Step-by-step explanation:
H
Which expression has a solution of 11, if m = 1?
m - 11
11 + m
14 - m
m + 10
Answer:
m+10 has the solution of 11
Find the constant of proportionality (r) in the equation y=rx
Answer:
0.1
Step-by-step explanation:
r = y/x
r = 1.4 / 14 = 0.1
Between the numbers 15/20 and 35/40 , the greater number is
a. 15/20 b. 20/15 c. 35/40 d. 45/30
Answer:
35/40
Step-by-step explanation:
To compare, both denominator should be same.
[tex]\frac{15}{20}=\frac{15*2}{20*2}=\frac{30}{40}\\\\\\\frac{30}{40} \ < \ \frac{35}{40}\\\\\\\frac{15}{20} \ < \ \frac{35}{40}[/tex]
[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]
⠀the numbers 15/20 and 35/40⠀⠀⠀[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]
⠀⠀⠀⠀
the greater number is[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]
we have to find the greater number between 15/20 and 35/40
To do this,
we have to compare the denominator same.
[tex]\sf{\dfrac{35}{40}=\dfrac{35×1}{40×1}=\dfrac{35}{40} }[/tex] [tex]\sf{\dfrac{15}{20}=\dfrac{15×2}{20×2}=\dfrac{30}{40} }[/tex]According to the question,
we have to find the greatest one
[tex]\sf{\dfrac{35}{40} > \dfrac{30}{40} }[/tex] [tex]\sf{\dfrac{35}{40}>\dfrac{15}{20} }[/tex][tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]
⠀⠀
[tex]\therefore\mathrm{\dfrac{35}{40} > \dfrac{15}{20} }[/tex]
⠀⠀