Answer:
The entire rainbow of radiation observable to the human eye only makes up a tiny portion of the electromagnetic spectrum – about 0.0035 percent. This range of wavelengths is known as visible light.
Explanation:
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It takes 130 j of work to compress a certain spring 0.10m. (a) what is the force constant of this spring? To compress the spring an additional 0.10m, does it take 130
Answer:
Explanation:
The PE equation for a mass/spring system is
[tex]PE=\frac{1}{2}k[/tex]Δx² and filling in:
[tex]130=\frac{1}{2}k(.10)^2[/tex] and
[tex]k=\frac{2(130)}{(.10)^2}[/tex] so
k = 26000 N/m
If the displacement from equilibrium changes more, the PE needed to compress it will also change.
[tex]PE=\frac{1}{2}(26000)(.20)^2[/tex] gives us that
PE = 520J
Which statement is correct about how the temperature of an object changes?
Group of answer choices
The molecules making up object collide with the molecules of the other and some of the potential energy from a cooler object is transferred to the warmer one.
The molecules making up object collide with the molecules of the other and some of the kinetic energy from a warmer object is transferred to the cooler one.
The molecules making up object collide with the molecules of the other and some of the kinetic energy from a cooler object is transferred to the warmer one.
The molecules making up object collide with the molecules of the other and some of the potential energy from a warmer object is transferred to the cooler one.
The molecules making up object collide with the molecules of the other and some of the kinetic energy from a warmer object is transferred to the cooler one.
Using diagram 1.1 and diagram 1.2, compare the number of turn of the coils, the pattern of the iron fillings and the angle of deflection of the ammeter pointer
Answer:
The number of turns in the second coil is more than the coil 1.
Explanation:
The magnetic field lines are the imaginary path on which an isolated north pole moves if it is free to do so.
The tangent at any point to the magnetic field line, gives the direction of magnetic field at that point.
More be the crowd ness of magnetic field lines more is the strength of magnetic field.
Here the crowd ness of magnetic field lines is more in figure 2 , so the magnetic filed in figure 2 is more than 1. It shows that the number of turns in the second coil is more than the 1 and also the current in the coil 2 is more than 1 .
Imagine you find a venomous snake crawling up your leg after taking a drug that prevented sympathetic nervous system activation. What would the James-Lange theory predict about your experience?
Answer:
I would not feel fear because I haven't had the physiological arousal necessary to induce that emotional state.
Explanation:
The James-Lange theory is a theory of emotions. According to the James-Lange theory, the emotions of a human occur as a result of the physiological reactions to the surrounding events. His theory is one of the well known psychological theories of emotions.
In the context, I took a medicine that prevented the activation of my sympathetic nervous system and imagined a venomous snake that crawls up my leg, I did not feel any fear as I have not had the emotion or the phycological arousal that is necessary to induce the emotional state. It is according the theory of James-Lange.
In which region is there most likely to be a volcano
A
B
C
D
how much does a car weighr if each tyre cover of 4cm^2 and exert a pressure of 100000Nm^-2 on the ground it is physics questions
Answer:
Weight = 160 N
Explanation:
The weight of an object is a measure of the gravitational force on the object. So that weight is synonymous to the force applied by the object.
i.e Weight = mass x gravitational force
Also, the pressure of an object is the ratio of its force to area covered by the object. So that;
P = [tex]\frac{F}{A}[/tex]
Given that: area = 4 [tex]cm^{2}[/tex] (0.0004 [tex]m^{2}[/tex]), and pressure = 100 000 N[tex]m^{-2}[/tex].
Then;
F = PA
= 100 000 N[tex]m^{-2}[/tex] x 0.0004 [tex]m^{2}[/tex]
F = 40 N
The force applied on the ground by each of the four tyres of the car is 40 N.
Thus, the weight of the car = 4 x 40 N
= 160 N
[tex]what \: is \: mirror \: {?}[/tex]
A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axis. Just before the collision, one ball, of mass 3.0 kg, is moving upward at 22 m/s and the other ball, of mass 1.3 kg, is moving downward at 11 m/s. How high do the combined two balls of putty rise above the collision point
Answer:
The height balls rise above the collision point, is approximately 7.37 meters
Explanation:
The given parameters just before the collision are;
The mass, m₁ and velocity, v₁ of the ball moving upward are;
m₁ = 3.0 kg, v₁ = 22 m/s
The mass, m₂ and velocity, v₂ of the ball moving downward are;
m₂ = 1.3 kg, v₂ = -11 m/s (downward motion)
The type of collision = Inelastic collision
We note that the momentum is conserved for inelastic collision
Let, [tex]v_f[/tex], represent the final velocity of the balls after collision, we have;
∴ Total initial momentum = Total final momentum
m₁·v₁ + m₂·v₂ = (m₁ + m₂)·[tex]v_f[/tex]
Therefore, we get;
m₁·v₁ + m₂·v₂ = 3.0 kg × 22 m/s + 1.3 kg × (-11) m/s = 51.7 kg·m/s
(m₁ + m₂)·[tex]v_f[/tex] = (3.0 kg + 1.3 kg) ×
∴ 51.7 kg·m/s = 4.3 kg × [tex]v_f[/tex]
[tex]v_f[/tex] = (51.7 kg·m/s)/4.3 kg ≈ 12.023 m/s
The final velocity, [tex]v_f[/tex] ≈ 12.023 m/s
The maximum height, h, the combined balls will rise from the point of collision, moving upward at a velocity of [tex]v_f[/tex] ≈ 12.023 m/s, is given from the kinetic equation of motion, v² = u² - 2·g·h, as found follows
At maximum height, we have;
[tex]h_{max} = \dfrac{v_f^2}{2 \cdot g }[/tex]
Therefore;
[tex]h_{max} \approx \dfrac{12.023^2}{2 \times 9.81 } \approx 7.37[/tex]
The height the combined two balls of putty rise above the collision point, [tex]h_{max}[/tex] ≈ 7.37 m.
a)Watt (W) is a derived unit.
b)The atomic clock is suitable for measuring time.
c)There is fluctuation in time measured by a pendulum clock.
d)The weight of an object is more at pole and less at equator of the earth.
e)The weight of an object on the moon is about one-sixth the weight it would have on the earth.
f)In average, the weight of 1 kilogram mass on the earth surface is 9.8 N.
please answer all questions
Answer:
a) Watt is a derived unit because it's not a “base unit.”
b) The atomic clock is suitable for measuring time because natural atomic oscillations happen at a higher frequency and as a result they are more stable.
c) There is fluctuation in time measured by a pendulum clock because the pendulum rod changes in length slightly with changes in temperature, causing changes in the rate of the clock. An increase in temperature causes the rod to expand, making the pendulum longer, so its period increases and the clock loses time.
D) The weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.
e) The weight of an object on the moon is about one-sixth the weight it would have on the earth because the moon's gravitation force is determined by the mass and the size of the moon. Hence, the weight of an object on the moon is 1/6th its weight on the earth.
the suns energy comes from which nuclear reaction?
Find the time taken if the speed of a train increased rom 72km/h to 90km/h for 234km
Answer:
2.89 hours
Explanation:
given :
Vo = 72 km/h
Vt = 90 km/h
S = 234 km
find : the time taken (t) = ?
solution :
2.a.s = Vt² - Vo²
2.a.(234) = 90²- 72²
468.a = 8100 - 5184
= 2916
a = 2916/468 = 6.23 km/h²
so,
t = (Vt-Vo) /a
= (90-72)/ 6.23
= 18/ 6.23
= 2.89 hours
A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of
Toronto. The total displacement of the car is:
Answer:
The total displacement of the car is 250 km.
Explanation:
Given that,
A car at a position 150 km [W] of Toronto travels to a position 400 km [W] of Toronto.
Total displacement = final position - initial position
= 400 km - 150 km
= 250 km
So, the total displacement of the car is 250 km.
A car is stationary. It accelerates at 0.8 ms^2
for 10 s and then at 0.4 ms^2
for a further 10 s. Use
the equations of motion to deduce the car’s final displacement. You will have to split the journey
into two parts, since the acceleration changes after 10 s.
Answer:
the car’s final displacement is 60 m
Explanation:
Given;
initail velocity of the car, u = 0
acceleration of the car, a = 0.8 m/s²
time of motion, t = 10 s
The first displacement of the car:
[tex]x_1 = ut + \frac{1}{2} at^2\\\\x_1 = 0 + \frac{1}{2} (0.8)(10)^2\\\\x_1 = 40 \ m[/tex]
The second displacement of the car;
acceleration, a = 0.4 m/s², time of motion, t = 10 s
[tex]x_2 = ut + \frac{1}{2} at^2\\\\x_2 = 0 + \frac{1}{2} (0.4)(10)^2\\\\x_2 = 20 \ m[/tex]
The final displacement of the car;
x = x₁ + x₂
x = 40 m + 20 m
x = 60 m
Therefore, the car’s final displacement is 60 m
Give reason:
Mass and volume are called physical quantities.
a.
b
Ionath is called
Mass and volume are called physical quantities because they can be measured by using physical devices i.e. mass is measured by using beam balance and volume is measured by using metre scale .
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eview
A circular loop of radius 0.0400 m is
oriented 35.0 degrees to a 0.152 T
magnetic field. What is the magnetic
flux through the loop?
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Hint: How do you find the area of a circle?
[?] x 10"") Wb
Pls I need helpppp!
Answer:6.26*10^-4
Explanation:
The magnetic flux through the loop is 6.255 x 10⁻⁴ Weber.
What is magnetic flux?The number of magnetic field lines passing through a cross-section area defines the magnetic flux. It is denoted by ∅.
∅ = BAcosθ
Given is the magnetic field B = 0.152T, radius r = 0.04m and the angle of orientation θ=35.0 degrees
Area of cross- section A = πr² = 3.14 x ( 0.04)² = 5.024 x 10⁻³ m²
Magnetic flux, ∅ = 0.152 x 5.024 x 10⁻³ x cos 35°
∅ = 6.255 x 10⁻⁴ Weber
Thus, the magnetic flux through the loop is 6.255 x 10⁻⁴ Weber.
Learn more about magnetic flux.
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What is the meaning of the word "force"?
Answer:
Explanation:
The word force has a precise meaning. A force is exerted on one object by another. The idea of a force is not limited to living things or non-living things. All objects (living and non-living) can apply a force on or to another object also all objects (living and non living) can be affected by forces.
An ammeter with a resistance of 5.0 ohm is connected in series with a 3.0V cell and a lamp rated at 300 mA, 3V. Calculate the current that the ammeter will measure
Answer:
I = 0.2 A
Explanation:
Lamp is rated at 300 mA
I_lamp = 0.3 A
Voltage is; V = 3V
Thus; Resistance is given by;
R = V/I
R = 3/0.3
R = 10 ohms
Now, since the ammeter of 5 ohms is connected in series with the lamp. Thus equivalent resistance;
R_eq = 10 + 5
R_eq = 15 ohms
Ammeter current will be;
I = V/R_eq
I = 3/15
I = 0.2 A
Question 26 of 30
Which of the following is a type of mechanical wave?
Check all that apply.
A. Longitudinal
B. Surface
O C. Transverse
D. Electromagnetic
Answer:
Mechanical waves are A. Longitudinal and C. Transverse.
Explanation:
I hope this helps you.^_^
A ball tied on a string rotates in a circular path as shown above. The only forces acting on the ball at any point are the weight and of the string. What is the equation for the net centripetal force at point C?
Answer:
the third one T-W
Explanation:
the direction of the Tension and weight are opposite
A. A
B. C
C. D
D. B
HELLLP GUYS!!!
Answer:
B
Explanation:
Wavelengths of incoming solar radiation are __________________ the wavelengths of reradiated heat. Which term best completes the sentence
Explanation:
Hydraulic Pressure-Control, On-Off Deluge Valve
FP-400Y-5DC
The BERMAD model 400Y-5DC is an elastomeric, hydraulic line pressure operated deluge valve, designed specifically for advanced fire protection systems and the latest industry standards. The 400Y-5DC is activated by a hydraulically operated relay valve, through which opening and closing of the valve can be controlled either with a remote hydraulic command or with a wet pilot line with closed fusible plugs. An integral pressure reducing pilot valve ensures a precise, stable, pre-set downstream water pressure. The optional valve position indicator can include a limit switch suitable for Fire & Gas monitoring systems. The 400Y-5DC is ideal for systems that combine a remote wet pilot line with a high pressure water supply.
& What is meant by expansion effect of heating?
Answer:
it's when heat demolished the object
A 1.25cm diameter cylinder is subjected to a load of 2500kg.Calculate the stress on the bar in mega pascal
Answer:200 Mpa
Explanation:
Given that diameter of cylinder = d = 1-25cm = 1.25 100 =0.0125m
Load or mass = m = Stress 0 = ? 2500kg
Solution: Formula N = F A
Area of Cross-section of cylinder = A=πr2 A = π(d/2) 2
= π(d2/4)
=(3.14)(0.0125)2/4
A = 1.226x10-4
F ・ mg = = F A 24500 2500 x 9.8 = 24500 N
1-226x10-4
1998 36 867.9
= 200 x 106 Pa
= 200 MPa
*Hope it helps you*
Good luck
Hallar la distancia que recorre una movil al cabo
de 8s si posee una velocidad de 5m/s y acelera a razón de 3 m/s
Answer:
Distancia, S = 136 metros
Explanation:
Dados los siguientes datos;
Aceleración, a = 3 m/s²
Velocidad inicial, u = 5 m/s
Tiempo, t = 8 segundos
Para encontrar la distancia recorrida, usaríamos la segunda ecuación de movimiento;
S = ut + ½at² Sustituyendo en la fórmula, tenemos;
S = 5 × 8 + ½ × 3 × 8²
S = 40 + 1,5 × 64
S = 40 + 96
Distancia, S = 136 metros
Which statement is the best interpretation of the ray diagram shown?
Answer:
Explanation:
First off, this lens is concave. Second, the image is obviously smaller, and third, the only thing that is NOT obvious, is the fact that real images are always upside down and virtual images are always right-side-up. So the choice you're looking for is D.
Answer:
D - A concave lens forms a smaller, virtual image
Explanation:
A body weighs 63 N on the surface of the earth. What is the gravitational force on it due to the earth at a height of 3200 km from the earth's surface? (Radius of the earth is 6400 km)
Answer:
you are kind of better than I am I don't read much but with brainly I will be intelligent
A shell is fired at an initial speed of 2500 m/s at an initial angle of 45 degrees. Find the shell's horizontal range and the amount of time the shell is in motion. (note that because it is fired from the ground to the ground, they displacement = 0.)
Answer:
d= 637323 meters
t= 360.5 seconds
Answer:
Explanation:
Since the height from which the shell was fired is the same as the height at which it lands (on the ground, to be specific), we will use the range equation. That is the only time you CAN use the range equation (when the initial height and the final height are exactly the same). The range equation is:
[tex]r=\frac{v_0^2sin(2\theta)}{g}[/tex] where v0 is the initial velocity, theta is the angle, and g is the pull of gravity (NOT negative). Filling in:
[tex]r=\frac{(1500)^2sin(9.0*10^1)}{9.8}[/tex] so, doing all that math gives us:
r = 6.4 × 10⁵ meters
coulomb what is the meaning in physics??
Answer:
Coulomb, unit of electric charge in the metre- kilogram- second- ampere system, the basis of SI system of physics unit. The coulomb is defined as the quantity of electricity transported in one second by a current of one ampere.
Sí un auto viaja a 8m/s determine Tiempo en llegar a 200km de distancia Distancia que recorre en 40 minutos
Answer:
a. Tiempo = 25000 segundos
b. Distancia = 19200 metros
Explanation:
Dados los siguientes datos;
Velocidad = 8 m/s
Distancia = 200 km a metros = 200 * 1000 = 200,000
Para encontrar el tiempo para cubrir la distancia anterior;
Tiempo = distancia/velocidad
Tiempo = 200000/8
Tiempo = 25000 segundos
b. Para encontrar la distancia recorrida en 40 minutos;
Tiempo = 40 minutos a segundos = 40 * 60 = 2400 segundos
Distancia = velocidad * tiempo
Distancia = 8 * 2400
Distancia = 19200 metros
You can see stars brighter than magnitude +6 with your naked eye under dark sky conditions, and you can also see the full moon at magnitude –13. (You can glance at the Sun, which is at magnitude –27, but you can't safely look at the Sun.) Given these limits, what is the dynamic range of the naked eye?