How much dry solute would you take to prepare each of the following solutions from the dry solute and the solvent?Part A 128 mL of 0.120 M NaNO3.Part B 115 g of 0.220 m NaNO3.Part C 115 g of 1.1 % NaNO3 solution by massExpress your answer using two significant figures

The bonding expected for each material is covalent, ionic, and metallic bonds.

The force of attraction that leads to the holding of atoms or ions together in a molecule or crystal is said to be bonding. The bond formation can happen by either attraction or transfer of electrons. There are single, double, and triple bonds. There are many sorts of bonding namely:

a. Brass: It is an alloy of metal that's copper and zinc. Hence, metallic bonding is present within the brass.

b. Epoxy: It is a polymer whose monomer unit isoprene, which may be a covalent compound. The isoprene units are attached in repeated units to make rubber by covalent bonding.

c. Barium sulfide: Due to the large electronegativity difference between barium and sulfur, barium sulfide is an ionic compound. Thus, ionic bonding is present in barium sulfide.

d. Solid xenon: Only xenon atoms are present in solid xenon which are interacted by weak Van der Waal's interactions. Iconic bond is present.

e. Aluminum phosphide: Aluminum phosphide may be a covalent compound and thus involves covalent bonding.

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For an addition reaction, why does the free energy term, G, become more positive with increasing temperature because the positive entropy term dominates at high temperature. So, option A is correct.

In an addition reaction, the free energy, G, is influenced by both the enthalpy, H, and entropy, S, terms. As temperature increases, the entropy term becomes more positive, while the enthalpy term remains relatively constant. At high temperatures, the positive entropy term dominates, causing the free energy, G, to become more positive. This means that the reaction becomes less favorable and less likely to occur.

The entropy term reflects the number of available molecular arrangements in a system and the degree of disorder. At high temperatures, the molecules have more kinetic energy and are more likely to be in disordered states. This results in a larger entropy term and a more positive G.

In contrast, the enthalpy term reflects the heat energy involved in a reaction and the bond-forming or bond-breaking nature of the reaction. At high temperatures, the enthalpy term remains relatively constant, as the reaction is not affected by changes in temperature.

In summary, the positive entropy term dominates at high temperature, causing the free energy, G, to become more positive and the reaction to become less favorable.

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Rutherford discovered the nucleus . Option B

Ernest Rutherford is famous for his discovery of the structure of the atom and his pioneering work in nuclear physics. He made several key discoveries that transformed our understanding of atomic structure and the behavior of atomic nuclei.

Rutherford performed his famous gold foil experiment in which he used alpha particles to probe the structure of the atom. He found that most alpha particles passed straight through the gold foil, but a small number were deflected. This showed that the atom had a small, dense nucleus at its center.

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Rutherford's experiment was important because it showed that atomic nucleus and is therefore dented as option A.

This is referred to as a procedure carried out to support or refute a hypothesis, or determine the efficacy or likelihood of something previously untried.

Rutherford was a scientist who was famous for his gold-foil experiment, in which he demonstrated that the atom has a tiny, massive nucleus by  bombarding aluminum foil with beam of light known as alpha particles which is therefore the reason why option A was chosen as the correct choice.

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The amount of energy it takes to break a bond is always less than the amount of energy released when the bond is formed.

This is because when a bond is broken, the energy that was used to form the bond is released, leading to an overall decrease in energy. This energy released is referred to as bond energy.

Bond energy is a measure of the energy stored in the bond between two atoms. It is the energy required to break the bond and form two separate atoms. Bond energy is released when a bond is formed, resulting in an overall decrease in energy.

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The amount of energy it takes to break a chemical bond is equal to the amount of energy released when the same bond is formed.

Bond dissociation energy and bond formation enthalpy are two important concepts in chemical bonding. Bond dissociation energy is the amount of energy required to break a bond between two atoms in a gaseous state, while bond formation enthalpy is the energy released when the same bond is formed.

These two energies are equal and opposite in nature, meaning that the amount of energy required to break a bond is equal to the amount of energy released when the bond is formed. This relationship is important for understanding the stability of chemical bonds and the energy changes that occur during chemical reactions.

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Identifying the two compounds present in an unknown mixed sample can be a challenging task, but a combination of these techniques can help to narrow down the possibilities and eventually identify the compounds.

Here are some possible approaches:

Analyze the physical and chemical properties of the unknown sample, such as melting point, boiling point, solubility, reactivity with certain chemicals, and spectroscopic data (e.g., IR, NMR, UV-Vis). Compare these properties to those of known compounds and see which ones match.

Use various separation techniques to isolate each individual component of the mixture, such as extraction, distillation, chromatography, and crystallization. Then, analyze each isolated component using various analytical techniques to determine its identity.

Use chemical tests and reactions to identify the functional groups or chemical characteristics of the unknown sample. For example, if the sample contains a carbonyl group, it can be tested with 2,4-dinitrophenylhydrazine to form a characteristic orange precipitate.

Overall, identifying the two compounds present in an unknown mixed sample can be a challenging task, but a combination of these techniques can help to narrow down the possibilities and eventually identify the compounds.

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In a temperature of 15°C a quantity of oxygen has a volume of 250ml if its temperature is raised 45°C. 276ml its volume.

The Ideal Gas Law explains the relation between pressure and volume in an ideal gas. where P is the pressure measured in atmospheres, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in kelvin.

According to Ideal gas law:

PV = nRT

Rearranging this equation

V / T = nR / P

At constant pressure:

V₁ / T₁ = V₂ / T₂

By substituting values in this equation and we get:

250 / (15 + 273) = V / (45 + 273)

V = 276

When using the ideal gas law, remember to always use absolute units for temperature, like Kelvin.

Thus, In a temperature of 15°C a quantity of oxygen has a volume of 250ml if its temperature is raised 45°C. 276ml its volume.

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2.89 moles of water can be made when 136.8 grams of HNO3 are consumed.

Mole is a unit of measure used in chemistry to measure the amount of a substance. It is the amount of a substance that contains an Avogadro's number of molecules, 6.02214076 × 1023.

To calculate the number of moles of water produced when 136.8 grams of HNO3 are consumed in the reaction, we must first calculate the number of moles of HNO3 present in 136.8 grams. To do this, we must divide the mass of HNO3 (136.8 grams) by the molar mass of HNO3 (63.01 g/mol).
Therefore, the number of moles of HNO3 in 136.8 grams is 136.8/63.01 = 2.17 moles.
The equation states that for every 3 moles of HNO3 consumed, 4 moles of water are produced, so we can calculate the number of moles of water produced when 2.17 moles of HNO3 are consumed.
2.17 moles of HNO3 x (4 moles of water/3 moles of HNO3) = 2.89 moles of water.
Therefore, 2.89 moles of water can be made when 136.8 grams of HNO3 are consumed.

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The complete fraction equilibrium constant (Kc) for the reaction Zn (NH₂)2 (aq) + 2ē → ZnCO + 4 NH3 (s) is 7.835 x 10^-31.

To calculate the equilibrium constant, we need to use the Nernst equation. The Nernst equation is used to calculate the potential of a half-cell at a given concentration, given the standard electrode potential (E°).

The Nernst equation for this reaction can be written as:

E = E° - (RT/nF) * ln Q

Where:

The reaction quotient (Q) is equal to the concentration of the product raised to its stoichiometric coefficient, divided by the concentration of the reactant raised to its stoichiometric coefficient. For this reaction, Q can be written as:

Q = [ZnCO] * 4 * [NH3]^2 / [Zn(NH2)2]^2

We can substitute the value of Q into the Nernst equation to find the potential of the cell at a given concentration. Then we can use that value of E to calculate the equilibrium constant (Kc).

Kc = 10^(-ΔE/0.0592)

Where ΔE is the difference between the measured potential (E') and the standard electrode potential (E°).

By substituting the given values into the above equations, we can find the equilibrium constant for the reaction.

To substitute the values and complete the equation, we first need to calculate ΔE:

ΔE = E° - E' = 1.040V - (-0.763V) = 1.803V

Next, we can use the value of ΔE to calculate the equilibrium constant (Kc):

Kc = 10^(-ΔE/0.0592) = 10^(-1.803/0.0592) = 10^(-30.37) = 7.835 x 10^-31

So the complete fraction equilibrium constant (Kc) for the reaction Zn (NH₂)2 (aq) + 2ē → ZnCO + 4 NH3 (s) is 7.835 x 10^-31.

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Neon is a noble gas, which means that its molecules do not have any permanent dipole moments and are therefore not attracted to each other.

The noble gases are a group of chemical elements that share many characteristics; under normal circumstances, they are all odourless, colourless, monatomic gases with very low chemical reactivity. Historically, the noble gases were also known as the inert gases. The six naturally occurring noble gases are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radioactive radon (Rn).

Oganesson (Og) is a highly radioactive element created synthetically. Although IUPAC has referred to "group 18" as a "noble gas" and thus included oganesson, it may not be significantly chemically noble and is predicted to break the trend and be reactive due to relativistic effects. Its chemistry has not yet been studied due to the extremely brief 0.7 ms half-life of its sole known isotope.

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Under normal circumstances, oxygen is an inert, colorless, odorless gas that condenses into a pale blue liquid. Colorless, tasteless, odorless, and non-metallic hydrogen has the chemical formula H2.

The lightest element is hydrogen. Gas is a vapor at normal pressure and temperature, but at a temperature of -423 degrees F, it crystallizes into a liquid.

Midsize gasoline hybrids achieve 42 mpg on average, compared to 30 mpg for gasoline vehicles. The graphic illustrates how much more fuel an FCV costs per mile than like a fuel hybrid and how much more it costs than a traditional gasoline car.

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Answer:

Bills

it usage of data and bills

0.0269 Litre is the volume of 1.0M copper(II) sulfate solution required to completely react with 1.0g of Fe(s) according to this equation: 2Fe(s)+3Cu2+(aq)→2Fe3+(aq)+3Cu(s).

The term molarity is defined as the number of moles of solute present in per litre of solution.

Given:

Moles of Fe = mass of Fe / molar mass of Fe

Mole Fe = 1.0 g / 55.845 g/mol

= 0.0179 mol

According to the balanced chemical equation,

3 mol Cu2+ are required to react with 2 mol Fe.

So, the number of moles of Cu2+ required to react with 0.0179 moles of Fe is mol Cu2+ = (3/2) x mol Fe

= (3/2) x 0.0179 mol

= 0.0269 mol

By using the molarity,

mole = concentration x volume

volume = moles / concentration

Volume = 0.0269 mol / 1.0 mol/L

Volume = 0.0269L

Thus, the volume of 1.0 M Cu⁺² solution required to fully react with 1.0 g of Fe is 0.0269 L.

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Answer:

In a first-order reaction at 300 K, the half-life is 2.50 x 10^4 seconds and the activation energy is 103.3 kJ/mol.

What is the rate constant at 350 K?

Explanation:

C8H18 compound is expected to be soluble in carbon tetrachloride (ccl4) based on structure.

Carbon tetrachloride (CCl4) is a nonpolar solvent, meaning it dissolves nonpolar compounds but not polar compounds. The solubility of a compound in CCl4 is dependent on the strength of the intermolecular forces between the solvent and solute.

Compounds with similar polarities to CCl4, such as nonpolar or slightly polar compounds, are expected to be soluble in CCl4. For example, alkanes, such as hexane (C6H14), and chlorinated solvents, such as chloroform (CHCl3), are soluble in CCl4.

On the other hand, polar compounds, such as water (H2O) or ethanol (C2H5OH), are not expected to be soluble in CCl4 due to the difference in polarities between the solvent and solute.

In summary, nonpolar or slightly polar compounds are expected to be soluble in CCl4, while polar compounds are not.

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which of the following compounds are expected to be soluble in carbon tetrachloride (ccl4) based on structure? select all that apply.

A. C8H18

B. C6H12

C. C4H6

D. None of the above

Covalent bonds between purines and pyrimidine bases  is NOT a type of molecular interaction that determines the tertiary structure of a protein. The correct answer is A.

A polypeptide's overall three-dimensional structure is referred to as its tertiary structure. The interactions between the R groups of the amino acids that make up the protein are principally responsible for the tertiary structure.

The entire spectrum of non-covalent bonds, including hydrogen bonds, ionic bonds, dipole-dipole interactions, and London dispersion forces, all contribute to tertiary structure.

For instance, R groups with opposite charges can form an ionic bond, while those with like charges repel one another. Similar to other dipole-dipole interactions, polar R groups can create hydrogen bonds

Hydrophobic interactions are crucial to tertiary structure because they allow hydrophilic amino acids to connect with nearby water molecules on the outside of the protein while forming clusters of nonpolar, hydrophobic R groups on the inside of the protein.

The disulfide link is a unique sort of covalent bond that can contribute to tertiary structure. Disulfide bonds, covalent connections between the side chains of cysteines that contain sulfur, are substantially more powerful than the other kinds of bonds that make up tertiary structure.

They serve as molecular "safety pins," firmly connecting various polypeptide components to one another.

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The reaction A+B⇒3C always goes to completion. If you have 10 A, the number of B which would be needed to make the most C is 10 and is therefore denoted as option C.

This is referred to as a process in which one or more substances, the reactants, are converted to one or more different substances, the products.

If you have 10 A, the number of B which would be needed to make the most C is 10 because of the equal amount number of mole of the substances or elements involved in the reaction.

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A cell notation of the overall cell equation would be.

An electrochemical cell called a galvanic cell, also called a voltaic cell, generates an electrical current as a result of a chemical reaction. Two electrodes, a cathode and an anode, separated by an electrolyte, make up the fundamental parts of a galvanic cell.

(a) By merging the half-cell processes, one can obtain the overall cell equation:

Zn(s) is converted into Zn2+ (aq) + 2e- while Sn2+ (aq) + 2e- is converted into Sn (s), we obtain Zn(s) + Sn2+ (aq) Zn2+ (aq) + Sn

by combining the half-cell reactions (s)

(b) Zn(s) acts as the oxidising agent, losing electrons to produce Zn2+.

(c) Using the half-cell reactions' standard electrode potentials as a starting point, one can compute the reaction's standard cell potential:

E cell is made of Eo oxidation and Eo reduction.

E cell equals -0.14 V - (-0.76 V) = 0.62 V.

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Answer: x = 0.752cm or 0.00752m

Explanation:

There are two ways to do this. The first is converting the number in meters (m) to centimeters (cm) and then adding. The second is converting the number in centimeters (cm) to meters (m) and then adding.

Way 1:

0.00732m * (100cm / 1m) = 0.732cm

0.01953cm + 0.732cm = 0.75153

With addition, the amount of significant figures for the answer is the same number of significant figures as the limiting one (or, in other words, the one with the least number of significant figures). In this case, 0.732cm has 3 significant figures and 0.01953cm has 4. This means that the answer has 3 significant figures.

So with significant figures, 0.75153cm = 0.752cm

Way 2:

0.01953cm * (1m / 100cm) = 0.0001953m

0.0001953m + 0.00732m = 0.0075153m

With significant figures, 0.0075153m = 0.00752m

Answer:

Explanation:

a) If an atom of element X loses one electron, it will form a positively charged ion or cation with the symbol X^+.

b) (i) 17 protons, (ii) 16 electrons, (iii) 18 neutrons.

c) If an atom of element Y gains one electron, it will form a negatively charged ion or anion with the symbol Y^-.

d) (i) 11 protons, (ii) 12 electrons, (iii) 12 neutrons.

When a salt is dissolved in water, it is represented by c) aq.

A reaction occurs when there is a change in the state of the reactant leading to the formation of the new product.

When a compound gets dissolved, the solution becomes an aqueous solution of that compound.

In the case of a salt, when it gets dissolved into water, the ionic bonds existing between the atoms break to form ions. The solid salt then changes into aqueous solution of the salt.

What is aq symbol in chemistry?

In a chemical equation, the subscript (aq) after a molecule means that it is aqueous. An aqueous solution is a solution in which the solvent is water.

What is an aqueous solution?

An aqueous solution is one in which the solvent is liquid water. That is, solute (dissolved) ions and molecules are surrounded by water molecules and incorporated into the network of bonds within the water. The dissolved species then spread throughout the water.

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alcohols are compounds that contain hydroxyl groups (-OH). Substances are called ketones if they contain a carbonyl group (C=O) in the center of a hydrocarbon chain.

Hydroxyl groups (OH) are functional groups consisting of an oxygen atom bonded to a hydrogen atom, typically found on the surface of molecules. They are a type of reactive hydrophilic group, meaning they are attracted to water and will react with other molecules in aqueous solutions to form hydrogen bonds. Hydroxyl groups are important components of many biological molecules, including proteins, carbohydrates, DNA, and lipids. They are also found in many drugs and play a role in drug metabolism.

Carbonyl groups (C=O) are functional groups consisting of a carbon atom double-bonded to an oxygen atom. They are found in many organic compounds, including aldehydes, ketones, carboxylic acids, amides, and esters. Carbonyl groups are highly reactive and undergo a variety of reactions, including nucleophilic addition, reduction, and oxidation reactions. They also play an important role in biological processes, such as photosynthesis and respiration.

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The ways in which this phase change occur, and how would the molecules of the substance be affected under these extreme conditions would be when shift happens in which heat is applied or removed at a specific temperature.

This is referred to as the degree of hotness or coldness of a substance and it is influenced by thermal energy.

Increase or decrease in the temperature of a substance is responsible for the phase changing from one form  to another under extreme conditions being used as a n example.

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The statement that Hydrogen was discovered more than 500 years ago due to the reaction of an acid and metals ... repeated Paracelsus 's experiment, the gas was flammable, is true.

When Paracelsus combined acids with metals, hydrogen gas was produced as a byproduct, which he observed unintentionally. A Swiss-born physician named Theodore de Mayerene who subscribed to Paracelsian thought replicated Paracelsus' research on the interaction of metals and acids.

De Mayerne found that the byproduct gas was combustible, which was an important finding in the future knowledge of chemical reactions even if he was unaware that the gas created was hydrogen or even a new element.

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The correct question is:

Hydrogen was discovered more than 500 years ago due to the reaction of an acid and metals and when Theodore de Mayerene repeated Paracelsus 's experiment, the gas was flammable.

True

False

Answer:

Explanation:

0.87

0.0269 litre is the volume of 1.0M copper(II) sulfate solution required to completely react with 1.0g of Fe(s) according to this equation: 2Fe(s)+3Cu₂+(aq)→2Fe₃+(aq)+3Cu(s).

The term molarity is defined as the concentration of number of moles of solute present in per litre of solution.

Given:

Moles of Fe = mass of Fe / molar mass of Fe

Mole Fe = 1.0 g / 55.845 g/mol

= 0.0179 mol

By the balanced chemical equation,

3 mol Cu⁺² are required to react with 2 mol Fe.

Then, the number of moles of Cu⁺² required to react with 0.0179 moles of Fe is mol Cu⁺² = (3/2) x mol Fe

= (3/2) x 0.0179 mol

= 0.0269 mol

According to the molarity,

mole = concentration x volume

volume = moles / concentration

Volume = 0.0269 mol / 1.0 mol/L

Volume = 0.0269L

Thus, the volume of 1.0 M Cu⁺² solution required to fully react with 1.0 g of Fe is 0.0269 L.

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A scientist goes to lab to synthesize Na₃AlF₆ via the balanced chemical reaction. If they need 780. grams of Na₃AlF₆, and the overall percent yield is 45.4 %,311.79 g of Al₂O₃ is required to form 780 grams of Na₃AlF₆.

The balanced chemical reaction is defined as the mass of total number of product is exactly equal to the total number of mass of reactant.

Given:

45.4% yield = 780 g

Then 100% yield would be =780 × (100/45.4)

= 1718 g

Molar mass of Na₃AlF₆ = 209.94 g/mol

Molar mass of Al₂O₃ = 101.96 g/mol

1mole of Al₂O₃ gives 2 moles of Na₃AlF₆ .

⇾ 101.96 g of Al2O3 gives 2 × 209.94 g of Na3AlF6

Therefore, x g of Al2O3 gives 1284 g of Na3AlF6

x = (1718 × 101.96)/ 2 × 209.94

= 311.79 g

Thus, 311.79 g of Al₂O₃ is required to form 780 grams of Na₃AlF₆.

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Other species that could be considered include CO, CO2, O2, O, and other carbon-containing species such as C4, C5, and so on.

The consideration of these additional species would require a more comprehensive calculation of the reaction kinetics and reaction energies, and would likely lead to a more accurate prediction of the gas composition of sublimated carbon.

The gas composition of sublimated carbon at 5000 K and 1 atm or 0.01 atm pressure can be calculated using the concept of chemical equilibrium. This approach involves finding the concentration of each species of carbon (C, C2, and C3) at equilibrium, taking into account the reaction kinetics and the reaction energies.

At 5000 K, the dissociation and recombination reactions of C, C2, and C3 would be taking place at a rapid rate, leading to the formation of various products. In order to calculate the gas composition, the reaction equations for the dissociation and recombination reactions should be written and the equilibrium constants for each reaction should be calculated. The reaction equations can be written based on the conservation of mass and energy principles, taking into account the heat of formation and reaction enthalpies for each species.

The resulting equilibrium constants can then be used to find the concentration of each species of carbon at 5000 K and 1 atm or 0.01 atm pressure. The final gas composition would be a combination of C, C2, and C3, and the relative proportions of each species would depend on the temperature, pressure, and reaction kinetics.

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The free energy diagrams can be used to compare and analyze the thermodynamic properties of different chemical reactions.

The y-axis of the diagrams represent the free energy of the reaction, and the x-axis represents the progress of the reaction from the reactants to the products. By comparing the free energy diagrams of different reactions, it is possible to determine which reactions are more thermodynamically favorable, and thus more likely to occur spontaneously.

Additionally, the diagrams can also provide insight into the activation energy of a reaction, which is the amount of energy needed to initiate the reaction.

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