How many ml of 0.24 M HBr solution are needed to react completely with 10.00 ml of 0.24 M Sr(OH)2 solution

Answers

Answer 1

Answer:

10mL

Explanation:

Using the formula as follows:

CaVa = CbVb

Where;

Ca = concentration of acid, HBr (M)

Cb = concentration of base, Sr(OH)2 (M)

Va = volume of acid, HBr (Litres)

Vb = volume of base, Sr(OH)2 (Litres)

According to the information given in this question;

Ca = 0.24M

Cb = 0.24M

Va = ?

Vb = 10.0ml

Using CaVa = CbVb

0.24 × Va = 0.24 × 10

0.24Va = 2.4

Va = 2.4 ÷ 0.24

Va = 10mL

10mL of HBr is needed.


Related Questions

g Consider two different liquids at atmospheric pressure: hexane and water. Hexane has a higher vapor pressure than water. As a result, the temperature at which hexane will boil will be [ Select ] water and its vapor pressure when it is boiling will be [ Select ] water when water is boiling.

Answers

Answer:

Lower than

Higher than

Explanation:

The vapour pressure and boiling point of liquids are inversely related. Thus, the higher the vapour pressure of a liquid, the lower it's boiling point. Lower vapour pressure implies that the liquid is easily converted into vapour phase.

If hexane has a higher vapour pressure than water then its boiling point is lower than that of water and its vapor pressure when it is boiling will be higher than water when water is boiling.

A 2,31M solution of trans-4-methyl-2-pentene (C6H12, 85mL) is combined with 7,5mL of 3,55M elemental bromine to form an addition product. With an expectation of 100% yield, more than 25mmols of elemental bromine would be consumed during this chemical process.
a. True
b. False

Answers

Answer:

The statement is false

Explanation:

Number of moles of alkene = 2.31 × 85/1000 = 0.196 moles

Number of moles of Br2 = 3.55 × 7.5/1000 = 0.0266 moles

Given that the reaction is 1:1

1 mole of alkene reacts with 1 mole of bromine

0.196 moles of alkene should react with 0.196 moles of bromine

Hence, to achieve 100%yield, 0.196 moles of bromine and not 25mmols of elemental bromine

The equilibrium constant (K p) for the interconversion of PCl 5 and PCl 3 is 0.0121:
PCl5 (g) → PCl3 (g) + Cl2 (g)
A vessel is charged with PCl 5 giving an initial pressure of 0.123 atm and yields PCl 3 and Cl 2. At equilibrium, the partial pressure of PCl 3 is ________ atm.
A) 0.0782.
B) 0.0455.
C) 0.0908.
D) 0.0330.
E) 0.123.

Answers

Answer: At equilibrium, the partial pressure of [tex]PCl_{3}[/tex] is 0.0330 atm.

Explanation:

The partial pressure of [tex]PCl_{3}[/tex] is equal to the partial pressure of [tex]Cl_{2}[/tex]. Hence, let us assume that x quantity of [tex]PCl_{5}[/tex] is decomposed and gives x quantity of [tex]PCl_{3}[/tex] and x quantity of [tex]Cl_{2}[/tex].

Therefore, at equilibrium the species along with their partial pressures are as follows.

                         [tex]PCl_{5}(g) \rightarrow PCl_{3}(g) + Cl_{2}(g)\\[/tex]

At equilibrium:  0.123-x          x              x

Now, expression for [tex]K_{p}[/tex] of this reaction is as follows.

[tex]K_{p} = \frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}\\0.0121 = \frac{x \times x}{(0.123 - x)}\\x = 0.0330[/tex]

Thus, we can conclude that at equilibrium, the partial pressure of [tex]PCl_{3}[/tex] is 0.0330 atm.

Acetic acid and water react to form hydronium cation and acetate anion, like this:

HCH3CO2(aq) + H2O → H3O+(l)(aq) + CH3CO2^-(aq)

Imagine 226 mmol of CH3CO2- are added to a flask containing a mixture of HCH3CO2, H2O, H3O + and CH3CO2- at equilibrium.

Required:
What is the rate of the reverse reaction before any CH3CO2^- has t:een added to the flask?

Answers

Answer:

The rate of the reverse reaction before any addition of CH3CO2- is zero

Explanation:

When the reaction is in equilibrium:

HCH3CO2(aq) + H2O ⇄ H3O+(l)(aq) + CH3CO2^-(aq)

The reaction quotient, Q = Ka and no more products or reactants are produced because their concentrations are in the right proportion.

Now, as no reaction occurs,

The rate of the reverse reaction before any addition of CH3CO2- is zero


Essentially all of the mass of an atom is due to the?
nucleons
electrons.
protons
Neutrons

Answers

Answer:

nucleons

Explanation:

The answer to the question is nucleons. Because there are both protons and neutrons in the nucleon, it will be heavier. Also, protons and neutrons are much heavier than the weight of an electron, because electrons float around the atom so it is not the answer. So, our final answer is actually option A.

Which of the following represents a compound?

Na
CO2
Со
Mn

Answers

Answer:

CO2

Explanation:

Carbon dioxide is a chemical compound that consists of two oxygen atoms and one carbon atom

Calculate the Experimental Molar Volume in L/mol of the Hydrogen gas, H2, if the volume of H2 at STP is 52.8 mL and the mass of Magnesium metal, Mg, used in the experiment is 0.055 g.

Answers

Answer:

The Experimental Molar Volume in L/mol of the Hydrogen gas=23.36L/mol

Explanation:

We are given that

Volume of H2 at STP=52.8mL

Mass of magnesium metal ,M(Mg)=0.055g

We have to find the Experimental Molar Volume in L/mol of the Hydrogen gas.

Molar mass of Mg=24.305 g/mol

Number of moles=[tex]\frac{given\;mass}{molar\;mass}[/tex]

Using the formula

Number of moles of Mg=[tex]\frac{0.055}{24.305}[/tex]moles

Number of moles of Mg=0.00226moles

Number of moles of Mg=Number of moles of H2

Number of moles of H2=0.00226moles

Molar volume of Hydrogen gas (H2)=[tex]\frac{volume\;at\;STP}{No\;of\;moles\;H_2}[/tex]

Molar volume of Hydrogen gas (H2)=[tex]\frac{52.8}{0.00226}mL/mol[/tex]

Molar volume of Hydrogen gas (H2)=[tex]\frac{52.8}{0.00226}\times 10^{-3}L/mol[/tex]

[tex]1L=1000mL[/tex]

Molar volume of Hydrogen gas (H2)=23.36L/mol

Hence, the Experimental Molar Volume in L/mol of the Hydrogen gas=23.36L/mol

every sperm has ____(one/two) sex chromosomes

PLEASE TELL THE ANSWER!!​

Answers

Two chromosomes

Explanation:

The chromosomes are XY

Please mark me brainliest

Answer:

Two

Explanation:

Every sperm cell has two chromosomes.One is X and other is Y .They are found in pairs either XY or XX

Balance the following reactions and identify the species that have been oxidized and the species that have been reduced.
CL2 +I- -------------> I2 +CL-
WO2 + H2 ---------------> W + H2O
CA + H2O -----------------> H2 + CA(OH)2
AL+ O2 --------------------> AL2O3

Answers

Answer:

Balance the following reactions and identify the species that have been oxidized and the species that have been reduced.

CL2 +I- -------------> I2 +CL-

WO2 + H2 ---------------> W + H2O

CA + H2O -----------------> H2 + CA(OH)2

AL+ O2 --------------------> AL2O3

Explanation:

Oxidation is the process where an atom loses electrons.

During oxidation, the oxidation number of the atom increases.

Reduction is the process where an atom gains electrons.

During reduction, the oxidation number of the atom decreases.

The balanced chemical equations for the given reactions are shown below:

[tex]Cl_2 +2I^- -> I_2 + 2Cl^-[/tex]

Iodine undergoes oxidation and chlorine undergoes reduction.

[tex]WO_2 +2 H_2 -> W+ 2 H_2O\\[/tex]

In this reaction, W (tungsten) undergoes reduction and hydrogen undergoes oxidation.

[tex]Ca+2 H_2O ->H_2+Ca(OH)_2\\[/tex]

Ca undergoes oxidation and hydrogen undergoes reduction.

[tex]4Al+3O_2->2Al_2O_3\\[/tex]

Al undergoes oxidation and oxygen undergoes reduction.

Determine whether each phrase describes carboxylic acids or esters.

a. Usually have a sour odor _____________
b. Notable for their pleasant fragrances ___________
c. Do not form hydrogen bonds amongst themselves and have higher vapor pressure _____________
d. Their reactions with base are known as neutralizations ____________
e. Their reactions with base are known as saponifications _____________

Answers

the right answer is b

Glass tubes of the following diameters are arranged in a water trough. Rank the following glass tubes in decreasing order of their capillary rise.
Rank from highest to lowest capillary rise. To rank items as equivalent, overlap them.
1.25 mm, 1 mm, 0.75 mm, 0.25 mm, 0.50 mm

Answers

Answer:

0.25 mm> 0.50 mm > 0.75 mm> 1mm> 1.25 mm

Explanation:

Capillary movement involves the movement of liquid up through a capillary tube.

Looking at the question, we can see all the various diameters of the capillary tube are involved.

Note that, that the narrower the diameter of the capillary tube, the better the capillary action of the liquid (the liquid rises more now than then).

Which statement is true about how scientists draw conclusions from data?

A. Scientists do not allow others to make conclusions about their data.

B. Teams of scientists never share their data to help other teams draw conclusions.

C. Any two scientists will always come to the same conclusion about a data set.

D. Two scientists may have different underlying assumptions that lead them to different conclusions about the same data. ​

Answers

I believe the answer is D.
Scientists are biased, and want to prove their specific hypothesis is right.

Answer:

D. Two scientists may have different underlying assumptions that lead them to different conclusions about the same thing.

Explanation:

It's all about how a person analyzes data. Some do it mathmatically while others do it logically. By doing it different ways, you may still come to the same conclusion, despite working at the problem in a different way.

D
Question 2
1 pts
How many moles of carbon tetrachloride are present in
18.Og of CC14?

Answers

i think .117018

now to get to the 20charaeactrs minimum.

the question is in the attachment

Answers

Answer:

About redox reaction which of the given statements are true?

Explanation:

Redox reaction is the one in which both oxidation and reduction reactions take place simultaneously.

For example:

[tex]C(s)+O_2(g)->CO_2(g)[/tex]

In this reaction, carbon undergoes oxidation and oxygen undergoes reduction simultaneously.

During this reaction, mutual exchange of electrosn take place between the oxidant and the reductant.

Among the given options,

Option B. electrons are transferred

and

option C.They include both oxidation and reduction takes place are the correct answers.

b) What is the change in entropy of the reaction if ΔH° = -3.2 kJ mol-1?

Answers

I would go w A I just took the test it was very way I got straight b on it

I need help with the practice question at the bottom. Thank you.

Answers

Explanation:

For this question, we apply the equation: Q = mCp AT Where m is the mass of the substance, Cp

is its specific heat capacity and AT is the

temperature change. Q = 896 x 0.45 x (5-94)

Q = -35884.8 Joules

So about -36 kilojoules of heat is released.

mark as brainliest

determine the number of atoms of H in 35.0 grams of C2H4O2

Answers

Answer:

1.40x10^24 atoms of H

Explanation:

Please help me, I don't bite. 3.

Answers

Answer:

jjjjjjjjj

Explanation:

hhhhhhhhhhh

When 2-methyl-3-hexene is treated with Cl2 in methanol, three products are formed (neglecting stereoisomers). Draw curved arrows to show the movement of electrons in this step of the reaction mechanism.

Answers

Answer:

Explanation:

The structural formula of 2-methyl-3-hexene is drawn in the attached image below. After then, the three possible structures were drawn and the mechanism reaction.

From the mechanism shown, methanol deprotonates methoxide proton and neutralizes the positive charge to form methoxide. This is followed by the movement of electrons that takes place from the region of higher electron density to lower electron density.

20. What intermolecular forces would affect the interactions of water molecules? Explain why.

Answers

Answer:

Water has strong hydrogen bond dipole-dipole intermolecular forces that give water a high surface tension and a high heat of vaporization and that make it a strong solvent

Methyl orange can change color by transitioning from one chromophore to another. When added to a clear solution and the solution turns red, it is determined to be a(n) __________ in its __________ stable form.

Answers

Answer:

acidic titration in its stable form

Explanation:

Methyl orange can change its color in titration solution. The yellow color is towards alkaline solution and red color is towards acidic solution. The Ph value of solution will change during this chemical process.

In what kind of orbital do the lone-pair electrons on the nitrogen of dimethylacetamide reside, and is it in the same plane as the ch3 groups

Answers

Answer:

The lone pairs on nitrogen in dimethylacetamide reside in sp3 orbitals which are coplanar with the methyl groups

Explanation:

The compound dimethylacetamide consists of oxygen bearing two lone pairs of electrons and a nitrogen atom bearing a lone pair of electrons and has two methyl groups attached to the nitrogen atom.

The lone pair on the nitrogen atom is accommodated in an sp3 orbital of nitrogen as shown in the question. This sp3 orbital is coplanar with the two methyl groups.

she goes away change to negative form​

Answers

She goes away.

Negative

She doesn't go away.

If the volume of the gas is increased to 9.6 L , what will the pressure be?

Answers

The pressure will be 438 mm Hg

A gas mixture is made by combining 8.7 g each of Ar, Ne, and an unknown diatomic gas. At STP, the mixture occupies a volume of 17.28 L. What is the molar mass of the unknown gas

Answers

Answer: Molar mass of the unknown gas is 73.153 g/mol.

Explanation:

Given: Mass of each gas = 8.7 g

Volume = 17.28 L

Let us assume that the molar mass of gas is m g/mol.

Molar mass of Ar is 40 g/mol and Ne is 20 g/mol.

Hence, total moles of each gas are as follows.

[tex](\frac{8.7}{40} + \frac{8.7}{20} + \frac{8.7}{m}) mol[/tex]

At STP, the total volume of these gases is as follows.

[tex](\frac{8.7}{40} + \frac{8.7}{20} + \frac{8.7}{m}) mol \times 22.4 L = 17.28 L\\(\frac{8.7}{40} + \frac{8.7}{20})22.4 L + \frac{8.7}{m} \times 22.4 L = 17.28 L\\14.616 + \frac{8.7}{m} \times 22.4 L = 17.28 L\\\frac{8.7}{m} \times 22.4 L = (17.28 L - 14.616)\\\frac{8.7}{m} \times 22.4 L = 2.664 \\m = 73.153 g/mol[/tex]

Thus, we can conclude that molar mass of the unknown gas is 73.153 g/mol.

A dilute solution of an unknown ionic compound must be identified. Several experiments are run on solutions that contain the possible ions with the results tabulated below. Cation Addition of HCl Heated in hot water Ag+ White precipitate is formed No observable change Pb+2 White precipitate is formed Precipitate dissolves Zn+2 No observable change No observable change Anion Addition of Ca(NO3)2 Addition of HNO3 CO3–2 White precipitate is formed Precipitate dissolves and bubbles form PO4–3 White precipitate is formed Precipitate dissolves A white precipitate is formed when HCl is added to the unknown compound. When the white precipitate is heated in hot water, it does not dissolve. A white precipitate is formed when Ca(NO3)2 is added to the unknown compound. When HNO3 is added to the precipitate, it dissolves and bubbles are formed. What is the chemical formula of the unknown ionic compound?

Answers

Answer:

The chemical formula of the unknown ionic compound is Ag₂CO₃.

Explanation:

The method used to identify the ions present in a given solution of an unknown compound is known as qualitative analysis. Specific tests are carried based on the chemical reaction of these ions and the results they give in these reactions, the ions present innthe compound are identified. Some of the results or observations include formation of precipitates on addition of certain reagents, evolution of gases, colour changes, as well as the color changes that are observed in a flame test of a solutionmof these compounds.

In the given question, when testing for cations, a white precipitate is formed when HCl is added to the unknown compound. When the white precipitate is heated in hot water, it does not dissolve.

From the table of observations, both Ag+ and Pb²+ give a white precipitate on addition of HCl but Zn²+ does not. So the cation present is either Ag+ or Pb²+. However, when heated in hot water, the white precipitate does not dissolve as will be observed if Ag+ were the cation present. Thus, the cation is Ag+.

When testing for anions, a white precipitate is formed when Ca(NO3)2 is added to the unknown compound and when HNO3 is added to the precipitate, it dissolves and bubbles are formed.

Now comparing these results with that as observed with CO₃²- and PO₄³-, both form white precipitates on addition of Ca(NO₃)₂, and the precipitate dissolves on addition of HNO₃. However, only CO₃²- dissolves with the production of bubbles when HNO₃ is added. Thus, the anion is CO₃²-.

Therefore, the compound is Ag₂CO₃ which is formed from the cation Ag+ and CO₃²-.

When Michelle's blood was testedthe chloride level was 0.45 g/dL. . What is this value in milliequivalents per liter? b. According to Table 9.6, is this value abovebelow within the normal range ?

Answers

Answer:

?what

Explanation:

i am having a hard time reading this

The molar mass of a compound can be determined by the freezing point depression method. The solution must be relatively dilute and you must know the molal freezing point depression constant of the solvent, Kf. Which statement regarding Kf is true?
A. Kf should be small so that the solvent will not sublimate.
B. Kf will change depending on what solute is dissolved in the solvent.
C. Kf should be negative so the freezing point of the solution will decrease.
D. Kf should be large so the temperature change will be large enough to measure.

Answers

Answer:

K should be large so the temperature change will be large enough to measure.

Explanation:

Let us recall that;

∆T = k m I

Where;

∆T= change in boiling point

K= freezing point constant

m= molality

i= Van't Hoff factor

Since the change in temperature depends on k, the larger the value of k the larger the temperature change(Ts - Tb). Hence; K should be large so the temperature change will be large enough to measure.

Ts= freezing temperature of pure solvent

Tb= freezing temperature of solution

Please helpplease please..help

Answers

Answer:

vague symptoms are characteristic of an acute toxin, because of the of the lack of well defined consistency that these symptoms have in relation to the course of the disease progress.

a compound has a percent compostion of carbon equal to 48.8383%, hydrogen equal to 8.1636%, and oxygen equal to 43.1981%. what is the mepirical formula

Answers

Answer:

C₂H₃O

Explanation:

From the question given above, the following data were obtained:

Carbon (C) = 48.8383%

Hydrogen (H) = 8.1636%

Oxygen (O) = 43.1981%

Empirical formula =?

The empirical formula of the compound can be obtained as follow:

C = 48.8383%

H = 8.1636%

O = 43.1981%

Divide by their molar mass

C = 48.8383 / 12 = 4.07

H = 8.1636 / 1 = 8.1636

O = 43.1981 / 16 = 2.7

Divide by the smallest

C = 4.07 / 2.7 = 2

H = 8.1636 / 2.7 = 3

O = 2.7 /2.7 = 1

Thus, the empirical formula of the compound is C₂H₃O

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