Answer:
2.0 x 10^-21 kilograms
Explanation:
Dimensional analysis is a technique for converting between different measuring units. The procedure is identifying the measurement units involved, figuring out the conversion factor between them, and then utilising the conversion factor to compute the desired outcome.
We need to translate 2.0 x 10-15 grams to kilograms in this instance. One kilograms is equivalent to 106 grams. In order to find the kilograms. We can divide the amount of grams by 106:
2.0 x 10-15 grams per 106 is 2.0 x 10-15 kilograms per 106 grams, or 2.0 x 10-21 kilograms.
Consequently, 2.0 x 10-15 grams are equal to 2.0 x 10-21 kilos.
a gas has a pressure of 1.26 atm and accupies a volume of 7.40 l. if the gas is compressed to a volume of 2.93 l, what will its pressure be, asumming constant temprature?
According to the question, 3.26 atm will its pressure be, asumming constant temprature.
What is temprature?
Temperature is a measure of the amount of heat energy present in a system. It is measured in degrees on a variety of scales, including Celsius, Fahrenheit, and Kelvin. Temperature is a fundamental physical property that can be used to characterize the state of a system. It is an important factor in determining the speed of chemical reactions, the rate at which materials expand and contract, and the amount of energy released or absorbed. Temperature affects the behavior of gases, liquids, and solids, and it has a significant impact on the physical and chemical properties of a substance.
Using the ideal gas law, the new pressure of the gas can be calculated as follows: P2 = (1.26 atm × 7.40 L) / 2.93 L
P2 = 3.26 atm
Therefore, the pressure of the gas will be 3.26 atm when its volume is decreased to 2.93 L, assuming constant temperature.
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g a solution of the primary standard sodium carbonate was prepared by dissolving 3.2990 g of na2co3 in 1.000 l of water. a 25.00-ml aliquot of this solution required 28.39 ml of hydrochloric acid solution (hcl (aq)) for titration. find the molarity of the hcl solution.
The molarity is viewed as 0.00109 M if a solution sodium carbonate was prepared by dissolving 3.2990 g of na2co3 in 1.000 l of water. a 25.00-ml aliquot of this solution required 28.39 ml of hydrochloric acid solution.
The molarity of the HCl arrangement can be determined involving the fair substance condition for the response between sodium carbonate (Na2CO3) and hydrochloric corrosive (HCl):
Na2CO3 + 2 HCl - > 2 NaCl + CO2 + H2O
One mole of sodium carbonate responds with two moles of hydrochloric corrosive. We realize how much sodium carbonate utilized in the response (3.2990 g) and its molar mass (106.0 g/mol), so we can work out the quantity of moles of sodium carbonate:
n = m/M = 3.2990 g/106.0 g/mol = 0.03109 mol
We additionally know the volume of the HCl arrangement utilized in the response (28.39 ml), so we can work out its molarity:
M = n/V = 0.03109 mol/(28.39 ml/1000 L/ml) = 0.00109 M
Thus, the molarity of the HCl arrangement is 0.00109 M (adjusted to 5 huge digits).
The molarity of the HCl arrangement can be determined by finding the quantity of moles of sodium carbonate utilized in the response and separating it by the volume of HCl arrangement utilized. The quantity of moles can be found by partitioning the mass of sodium carbonate by its molar mass. The molarity is viewed as 0.00109 M.
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when 0.982 g of mercury oxide are heated until all oxygen is expelled, 0.909g of mercury remain. what is the formula of this oxide
when 0.982 g of mercury oxide are heated until all oxygen is expelled, 0.909g of mercury remain then the formula of the oxide will be HgO.
The formula of the oxide can be determined by using the mass loss during heating as a clue to the number of moles of oxygen that was present in the original sample.
First, we'll calculate the mass of oxygen that was expelled:
0.982 g - 0.909 g = 0.073 g
Next, we'll convert the mass of oxygen to moles:
0.073 g / (16.00 g/mol) = 0.00456 mol
Next, we'll convert the mass of mercury to moles:
0.909 g / (200.59 g/mol) = 0.00453 mol
The ratio of moles of mercury to moles of oxygen in the original sample is approximately 1:1, which means that the formula of the oxide is HgO.
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classify the type of microscope based on a radiation they use
Answer:
Light vs electron
Explanation:
Light Microscope vs Electron Microscope. Light microscopes and electron microscopes both use radiation - in the form of either light or electron beams, to form larger and more detailed images of objects (e.g. biological specimens, materials, crystal structures, etc.) than the human eye can produce unaided.
you are trying to acidify a liquid in a breaker, but no matter how much hcl (strong acid) you dump in the liquid, the ph remains at 7. the liquid in the breaker can best be described as a
The given solution is a buffer.
When acidic or basic components are added to a buffer solution, it can withstand changes in pH. The solution's pH can be maintained relatively stable by neutralizing small amounts of added acids or bases. This is important for processes and reactions that require a specific and stable pH range. A buffer is an aqueous acid or base solution consisting of a mixture of a weak acid and its conjugate base or vice versa. Addition of a small amount of strong acid or strong base hardly changes the pH.
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A system at equilibrium contains 0. 377 mol SO2 , 0. 377 mol NO2 , 0. 673 mol SO3 , and 0. 727 mol NO. O2 is added to the container and NO reacts completely with the O2. Calculate the amount of SO3 in the container after the system returns to equilibrium
The amount of SO3 in the container after the system returns to equilibrium is 0.673 mol.
How do you calculate if a system is at equilibrium?
Equilibrium is a state in which all forces or influences that act upon a system are balanced. To calculate if a system is at equilibrium, you must determine the net force and net torque acting on the system. If the net force and net torque are both zero, then the system is at equilibrium.
The reaction between NO and O2 can be described by the following equation:
2 NO(g) + O2(g) ⇌ 2 NO2(g)
When NO reacts completely with O2, the amount of NO decreases to zero and the amount of NO2 increases to 2 * 0.727 = 1.454 mol.
The reaction between SO2 and O2 to form SO3 can be described by the following equation:
SO2(g) + O2(g) ⇌ SO3(g)
At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction. The equilibrium constant (Kc) for this reaction can be written as:
Kc = [SO3] / [SO2][O2]
After NO reacts completely with O2 and the system returns to equilibrium, the initial concentrations of SO2 and O2 are 0.377 mol and 0.727 mol, respectively, and the final concentration of SO3 can be calculated using the equilibrium expression:
Kc = [SO3] / [SO2][O2] = [SO3] / (0.377 mol)(0.727 mol) = [SO3] / 0.274 mol^2
At equilibrium, the change in the concentration of SO3 must be equal to zero, as the system is at equilibrium. Therefore, we can write:
Δ[SO3] = [SO3]final - [SO3]initial = 0
Substituting [SO3]initial = 0.673 mol, we get:
0 = [SO3]final - 0.673 mol
[SO3]final = 0.673 mol
Therefore, the amount of SO3 in the container after the system returns to equilibrium is 0.673 mol.
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how many electrons does a noble gas, other than helium, have in its highest-occupied energy level?
A noble gas, other than helium, have 8 electrons in its highest-occupied energy level.
The noble gas are a group of elements in the periodic table that have exceptional chemical stability and low reactivity due to their complete valence shell of electrons. These elements are found in the far right-hand column of the periodic table and include helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and radon (Rn). Unlike other elements in the periodic table, the noble gases do not readily form compounds with other elements, making them highly unreactive. This characteristic makes them useful in a variety of industrial applications, such as filling incandescent lamps, as cooling agents in cryogenics, and in the production of semiconductors. The electron configurations of the noble gases, excluding helium, follow the pattern s^2p^6, meaning that the highest-occupied energy level has 8 electrons. This full valence shell of electrons gives the noble gases their exceptional stability and non-reactivity, making them unique among the elements in the periodic table.
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if 39.0 g of c6h6 reacts with excess chlorine and produces 28.0 g of c6h5cl in the reaction above, what is the percent yield of c6h5cl? the molar mass of c6h6
According to the question, the molar mass of C₆H₆ is 60.5%.
What is molar mass?
Molar mass is the mass of one mole of a substance, measured in grams per mole. It is calculated by summing the atomic masses of the atoms in the molecular formula of the substance. Molar mass can be used to calculate the mass of a given amount of a substance, or to determine the amount of a substance needed to obtain a particular mass. Molar mass is an important concept in chemistry as it is used to calculate the amount of energy released or absorbed in a chemical reaction, as well as the amount of products formed.
Molar mass of C₆H₆ = 78.11 g/mol
Moles of C₆H₆ = 39.0 g / 78.11 g/mol = 0.500 mol
Molar mass of C₆H₅Cl = 92.56 g/mol
Moles of C₆H₅Cl = 28.0 g / 92.56 g/mol = 0.301 mol
Theoretical yield of C₆H₅Cl = 0.500 mol x 92.56 g/mol = 46.28 g
Actual yield of C₆H₅Cl = 28.0 g
Percent yield of C₆H₅Cl = (Actual yield / Theoretical yield) x 100%
= (28.0 g / 46.28 g) x 100%
= 60.5%
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Lead is melted and is poured into a mold to make fishing weights
Lead is melted and is poured into a mold to make fishing weights. This is an example of a physical change.
Chemical or physical changes are both possible. Anything that has mass and takes up space is referred to as "matter." It has both physical and chemical qualities and is composed of small particles.
A sort of change known as physical change occurs when the physical characteristics of matter change. Physical changes include those in color, odor, solubility, and the condition of matter, among others.
The chemical makeup or content of matter are not altered after a physical transformation. The internal makeup is unaffected as molecules rearrange themselves during this transformation. The chemical attribute is unaffected by a physical change.
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The complete question is
Lead is melted and is poured into a mold to make fishing weights. This is an example of a________change.
1) physical
2)chemical
The first step in deforestation in Amazon is?
Answer:
Logging is the first step in deforestation in Amazon.
Explanation:
I don't have much to go off of, but usually with any deforestation the first step is logging the area. You must remove all the trees before you can effectively utilize the area.
You have made up a stock aqueous dye solution of known concentration equal to 500. 0 parts per million (ppm) of green dye. If you take 2. 0 mL of the stock solution and add 8. 0 mL of water to it, what would the concentration of the diluted solution be in units of ppm?
The concentration of the diluted solution be 100 ppm.
What is the Ppm solution?Chemistry uses the term PPM, or parts per million, to describe extremely low concentrations of solution. One liter of solution containing milligrams of the chemical is what is meant by this term. Technically speaking, it is a dimensionless quantity that can be used to measure lower concentrations in a solution.There are numerous scientific uses for this conversion.
It refers to how many of the one million parts that make up the entire solution a specific substance or molecule occupies. It is used to describe substance concentrations that are typically dissolved in a solvent. When there are two solutions, and one of them has a known ppm concentration, the ppm concentration can be calculated by:
ppm1 x volume = ppm2 volume
500 ppm x 2 mL = ppm2 x 10 mL
ppm 2 = 500 ppm x 2 mL/ 10 mL
ppm 2 = 100 ppm
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Which is the correct conversion for converting 54.0 grams of Chlorine to moles of Chlorine?
Answer:
1.523143316503566 moles.
Explanation:
1 grams Chlorine = 0.028206357713029 mole using the molecular weight calculator
Please helpppp with my chemistry homework
Answer:
25.34 g of KCI.
Explanation:
To calculate the mass of KCI produced, you can use the balanced chemical equation and stoichiometry.
Given the balanced equation:
[tex]1 mol\: K + 1 mol Cl_2 \rightarrow 1 mol KCI[/tex]
Since we have 0.34 mol Cl2, we can calculate the amount of K needed:
0.34 mol Cl2 / 1 mol Cl2 = 0.34 mol K
Using the molar mass of KCI (74.55 g/mol), we can calculate the mass of KCI produced:
0.34 mol * 74.55 g/mol = 25.34 g of KCI
So the answer is: 25.34 g of KCI.
when mtbe (shown) is reacted with hbr, carbons a and b will undergo nucleophilic substitution to yield two alkyl halides. by what mechanism of substitution will each c-o bond be cleaved?
when mtbe (shown) is reacted with hbr, carbons a and b will undergo nucleophilic substitution to yield two alkyl halides then by SN2 mechanism each c-o bonds will be cleaved.
When MTBE (methyl tert-butyl ether) is reacted with hydrogen bromide (HBr), the two C-O bonds in the molecule are expected to undergo an S N 2 substitution mechanism. This is because the reaction conditions are favorable for a bimolecular, concerted mechanism, where the nucleophilic (HBr) and substrate (MTBE) interact with each other to produce the products.
In the S N 2 mechanism, the C-O bonds in MTBE are cleaved via backside attack by the nucleophile, HBr. This involves the simultaneous formation of a new C-Br bond and breaking of the existing C-O bond. The attack takes place in a stereospecific manner, so that the orientation of the substrate and nucleophile determines the stereochemistry of the products. The S N 2 mechanism is typically favored under conditions where the substrate is a good leaving group and the nucleophile is a strong base.
In summary, both of the C-O bonds in MTBE are expected to be cleaved via an S N 2 mechanism when reacting with HBr.
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QuestionWhen the concentration of solutes is greater outside the cells than inside the cells, the solution outside the cells is AIsotonicBHypertonicCHypotonicDNone of the aboveMedium
When the concentration of solutes is greater outside the cells than inside the cells, the solution outside the cells is Hypotonic (C)
What is Hypotonic solution?The term "hypotonic solution" describes a solution that, when passed through a semipermeable membrane, has a lower solute concentration than other solutions. A solution like this one will result in a lower solute concentration as well as an overall flow of water within the cell. This results in the swelling breaking apart. As a direct consequence of this, the osmotic pressure of a hypotonic solution is significantly lower than the osmotic pressure of other solutions.
The osmotic potential of a hypotonic solution causes water molecules to move into a cell from outside the cell. When water molecules continue to diffuse into a cell, the cell can enlarge. And it can cause the cell to rupture or undergo cytosis. But unlike animal cells, plant cells have a solid cell wall and are less likely to burst.
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How many nitrogen molecules are produced from complete reaction of 12.3 L of N2O(g) according to the reaction below? Assume the density of N2O(g) is 1.48 g/L.
2 N2O(g) → 2 N2(g) + O2(g)
Answer:
Delta H = -163.14 kJ.
Explanation:
how many hydrogen bonds are found between each complementary base pairing?
PLEASEEEE HELP ME IM IN NEDD OF HELP
The response is untrue, thus no. Methane (CH4) and oxygen combine to produce water and carbon dioxide. Since there are different numbers of hydrogen atoms on either side.
Why happens when methane and oxygen interact?Methane (CH4) and oxygen combine to generate water and carbon dioxide. Since there are different numbers of hydrogen atoms on either side, we can see that the process is not balanced in this instance. The quantity of oxygen atoms is the same.
Methane and carbon dioxide are converted in what way?Natural gas mostly consists of methane. Methane is released into the atmosphere where it ultimately mixes with oxygen to create additional carbon dioxide (CO2). This straightforward chemical process turns methane into carbon dioxide.
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Sulfuric acid is produced by first burning sulfur to produce sulfur trioxide gas
2S(s) + 3O2(g) → 2SO3(g)
then dissolving the sulfur trioxide gas in water
SO3(g) + H2O(l) → H2SO4(l)
Calculate the mass of sulfuric acid produced if 1.25 g of sulfur is reacted as indicated in the above equations.
The mass of sulfuric acid produced is 2.77 g.
To calculate the mass of sulfuric acid produced, we need to use stoichiometry. Here are the step-by-step calculations:
So the mass of sulfuric acid produced is 2.77 g.
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equal volumes of 0.1 m agno3(aq) and 2.0 m nh3(aq) are mixed and the reactions represented above occur. which ag species will have the highest concentration in the equilibrium system shown below, and why?
The reaction between AgNO3 and NH3 has the following chemical equation for balance: Ag(NH3)2+ + NO3- from AgNO3 + 2NH3. As a result, the silver-ammonia complex will contain the majority of the silver ions in the equilibrium system.
AgNO3, or silver nitrate, is a chemical that is frequently utilised in a variety of industries, including photography, medicine, and scientific research. It is a white, crystalline solid that dissociates into silver ions and nitrate ions in water. It is also extremely soluble in water. Halide ions in solution are frequently detected using the reagent AgNO3, which reacts with them to produce visually identifiable insoluble silver halides. Additionally employed as an antiseptic in medicine, AgNO3 is applied topically to treat skin diseases including warts and burns. It is also a typical precursor for the creation of additional silver compounds.
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Answer:
Ag(NH3)2+ (aq)
Explanation:
Because Kep3 will equal 1.6 x 10^7
.0 carat is equal to 200 mg (0.200 g). if the density of a ruby is 4.02 g/cm3, what is the volume of a 1.00 carat ruby?
If the density of the ruby is 4.02 g/cm³, the volume of a 1.00 carat ruby is 0.049 cm³.
The density of the ruby = 4.02 g/cm³
The mass of the ruby = 1 carat
1 carat = 200 mg = 0.200 g
The mass of the ruby 0.200 g
The density is expressed as :
Density = mass / volume
The volume = mass / density
Volume = 0.200 / 4.02
Volume = 0.049 cm³
The volume of the ruby in mL = 0.049 mL.
Thus, the volume of the ruby is 0.049 mL in the 1 carat of the ruby.
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determine the molecular formula of the compound with an empirical formula of ch and a molecular molar mass of 78 g/mol.
The molecular formula of the compound with an empirical formula of CH and a molecular molar mass of 78 g/mol is, [tex]C_6H_6[/tex].
An Empirical formula is the chemical formula of a compound that gives the proportions (ratios) of the elements present in the compound but not the actual numbers or arrangement of atoms. This would be the lowest whole number ratio of the elements in the compound.
Given,
Empirical formula = CH
The molar mass of empirical is 12+1 = 13 g
The molar mass of molecular formula = 78 g
To find the number of empirical units divide the molecular mass + empirical mass
No. of units = 78÷13 = 6
So, the molecular formula is 6×(CH)
[tex]C_6H_6[/tex]
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system a and system b contain the same substance. system a is a saturated vapor and is at the same temperature as system b. if system b has a lower pressure than a, what phase is system b in?
System B is in a liquid phase since it is at the same temperature as System A, but has a lower pressure.
When a substance is heated, the pressure of the vapour increases, and eventually the pressure of the vapour and the liquid become equal at the substance's boiling point. This is known as the saturated vapour point. If the pressure of the vapour is lowered, then the vapour will condense into a liquid, as is the case with System B. As a result, System B is in a liquid phase due to the lower pressure.
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1.The boiling point of helium is 4 K. When helium boils, what interactions and/or bonds are overcome?
2. The boiling point of hydrogen is 20 K. When hydrogen boils, what interactions and/or bonds are overcome?
3. What interactions and/or bonds are overcome when hydrogen at 30 K is heated to 6000 K?
1. Helium has a boiling point of 4 k, and as it does so, the London dispersion force breaks bonds and interactions.
2. Helium has a boiling point of 20 k, and as it does so, the London dispersion force breaks bonds and interactions.
3. Hydrogen is able to break covalent bonds when heated from 30 K to 6000 K.
The least powerful bond-interaction force is the London dispersion force. The atoms of a substance are temporarily attracted to one another. Two atoms' electrons combine in a way that causes them to form dipoles. This force underlies every helium gas reaction.
When two species share electrons, a covalent link is created. Usually, they happen amongst compounds with comparable electronegativities. Bond strength is based on how many bonds there are between the atoms.
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Andrea's ballpoint pen leak ink, a permanent onto her white blouse. Her friends suggested that she soaked the stain in nail polish remover, in rubbing alcohol or wash the stain in soap or water. Andrea asked you, a good science student which of these suggestions she should try. Plan and design an experiment to identify which solvent is best for removing ink stain from Andrea's blouse
Experiment to determine best solvent for ink stain removal: soak 4 identical cloths with ink stains in nail polish remover, rubbing alcohol, soap+water, and water, observe stain removal, repeat 3 times, analyze results to find best solvent.
Here's a plan for an experiment to identify which solvent is best for removing an ink stain from a white blouse:
Obtain the following solvents: nail polish remover, rubbing alcohol, soap, and water.Cut four identical pieces of white cloth.Place an ink stain on each piece of cloth using a ballpoint pen.Soak one cloth in nail polish remover, one in rubbing alcohol, one in soap mixed with water, and one in water only.Soak the cloths for 10 minutes, then remove and gently dab the cloths to remove excess solvent.Observe and record the extent of stain removal on each cloth.Repeat the experiment three times to ensure accuracy and consistency of results.Analyze the results and determine which solvent was the most effective in removing the ink stain from the white cloth.Learn more about Stain:
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Calculate the kinetic energy of a 100kg cart moving at a speed of 6 m/s.
The kinetic energy of a 100kg cart moving at a speed of 6 m/s is 1800 J.
Kinetic energy is defined as the energy that an object has because of its motion. If you want to accelerate an object, then you must apply a force. Force can be applied when work is done by us. After work has been done, the energy will get transferred to the object, and the object will be moving with a new constant speed.
K.E = 1/2 mv²
m = 100 kg
v = 6 m/s
Substituting the values we get,
K.E = 1/2 × 100 × 6 × 6
⇒ K.E = 1800 J
Hence, The kinetic energy of a 100kg cart moving at a speed of 6 m/s is 1800 J.
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What carbonyl compounds might you start with to prepare the following compounds by Grignard reaction? List all possibilities.a) 2-methyl-2propanalb) 1-ethylcyclohexanolc) 3-phenyl-3-pentanold) 2-phenyl-2-pentanol
The reaction of carbonyl compounds with Grignard reagents to prepare the following compounds a)2-methyl-2propanal b) 1-ethylcyclohexanol c) 3-phenyl-3-pentanol d) 2-phenyl-2-pentanol is present above in figure.
The Grignard reagent is formed by reacting an organomagnesium compound with haloalkane in ether solvent. The carbon atoms in Grignard's reagent are partially negatively charged and serve as good nucleophiles. Grignard reagents usually react with carbonyl compounds (aldehydes or ketones) to form alcohols.
Reacts with formaldehyde to form primary alcohol.Forms secondary alcohols when interacting with other aldehydes. When interacting with ketones, tertiary alcohols are formed.Now, a) For the preparation of 2-methyl-2-propanal, we have to use actone ( carbonyl compound).
b) For the preparation of 1-ethylcyclohexanol, we have to use cyclohexane ( carbonyl compound).
c) For the preparation of 3-phenyl-3-pentanol, we have to use 3-pentanone ( carbonyl compound).
d) For the preparation of 2-phenyl-2-pentanol, we have to use 2-pentanone ( carbonyl compound). All carbonyl compounds are reactied with respective grignard reagents.
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Complete question:
What carbonyl compounds might you start with to prepare the following compounds by Grignard reaction? List all possibilities.
a) 2-methyl-2propanal
b) 1-ethylcyclohexanol
c) 3-phenyl-3-pentanol
d) 2-phenyl-2-pentanol
calculate the ph for each of the cases in the titration of 35.0 ml of 0.190 m naoh(aq) with 0.190 m hbr(aq).
The ph for each of the cases in the titration of 35.0 ml of 0.190 m Noah(aq) with 0.190 m hbr(aq) is 13.02 and 7.
To calculate the pH for each of the cases in the titration of NaOH with HBr, we need to determine the amount of HBr that has been added to NaOH at each point in the titration. We can use the balanced chemical equation for the reaction to do this:
NaOH(aq) + HBr(aq) → NaBr(aq) + H2O(l)
moles of HBr = moles of NaOH
moles of NaOH = concentration × volume
moles of NaOH = 0.190 M × 0.0350 L = 0.00665 mol
pH = 14.00
pH = 7.00
moles of NaOH remaining = 0.00665 - 0.00300 = 0.00365 mol
concentration = moles / volume
to calculate the concentration of NaOH remaining in the solution:
concentration of NaOH remaining = 0.00365 mol / 0.0350 L = 0.104 M
Kw = [H+][OH-] = 1.0 × [tex]10^-14[/tex]
[H+] = Kw / [OH-] = 1.0 ×[tex]10^-14[/tex] / 0.104 = 9.62 × [tex]10^-14\\[/tex] M
pH = -log[H+] = -log(9.62 × [tex]10^-14[/tex]) = 13.02
Therefore, the pH of the solution 13.02 and 7.
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Unstable isotopes undergo radioactive decay. What is something that can occur during radioactive decay?
During radioactive decay Unstable isotopes can occur by releasing particles.
Isotopes are atoms with the same number of protons but differing numbers of neutrons. They differ in mass, which affects their physical characteristics even if they have nearly identical chemical properties. There are unstable isotopes that emit radiation as well as stable isotopes that do not. These are referred to as radioisotopes.
Unstable isotopes undergo radioactive decay.The unstable isotope can release particles like alpha particles, beta particles, or gamma rays during radioactive decay. By emitting particles, the isotope transforms into a different element or isotope and becomes stable.
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Determine the pH at the equivalence point in the titration of 50. 0 ml of 0. 300 m ch3cooh with. 3 M NaOH. The Value of Ka for CH3COOH is 1. 8 x 10^-5
The pH at the equivalence point in the titration of 50.0 ml of 0.300 M CH₃COOH with 0.3 M NaOH is approximately 4.68.
To calculate the pH at the equivalence point, we need to determine the concentration of acetate ion (CH₃COO⁻) and hydronium ion (H³O⁺) at this point.
At the start of the titration, the initial concentration of acetic acid is 0.300 M and the initial concentration of hydronium ion is the same.
Let's say that x moles of NaOH are added to the solution. This will lead to the formation of x moles of acetate ion (CH³COO⁻) and x moles of hydroxide ion (OH⁻).
The final concentration of acetic acid will be (0.300 M - x M) and the final concentration of hydronium ion will be (x M).
The ionization constant (Ka) for acetic acid can be used to determine the concentration of acetate ion and hydronium ion in the solution. The equation for the ionization of acetic acid is:
CH₃COOH + H₂O ↔ CH₃COO⁻ + H₃O⁺
Ka = [CH₃COO⁻][H₃O⁺] / [CH₃COOH]
At the equivalence point, [CH₃COOH] = (0.300 M - x M), [CH₃COO⁻] = x M, and [H₃O⁺] = x M. Substituting these values into the equation for Ka, we get:
1.8 x 10⁻⁵ = (x)(x) / (0.300 - x)
Solving for x, we get:
x = 2.1 x 10⁻⁵ M
The pH at the equivalence point is equal to the negative log of the hydronium ion concentration:
pH = -log[H₃O⁺] = -log(2.1 x 10⁻⁵) = 4.68
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