How many grams of a nonelectrolyte (78.2 g/mol) must be dissolved in 1 kg of solvent to obtain a freezing point of solution of 1.57ºC? The freezing point of the pure solvent is 4.72ºC and the freezing point depression constant of the solvent is 3.89 ºC/m

Answers

Answer 1

Answer Tu mama por si acaso

Explanation:

jkand


Related Questions

List the 4 cell structures from largest to smallest

Answers

Answer: The smallest structure is the double helix while the largest is the chromosome.

2. G2 phase is the third stage in cellular division wherein the cell prepares itself for the M phase.

3. Interphase comprises of 3 phases, namely, G1 phase, G2 phase, and S phase.

4. Metaphase is known to take less amount of time to complete.

Explanation:

1. The double helix of the DNA or deoxyribonucleic acid, nucleosome, coil, supercoil, and the chromosomes are all linked to the DNA and they vary in their sizes. The nucleosome is known to be the basic unit of the eukaryotic chromosome that is composed of DNA coiled around the histones. The supercoils and coils indicate to the structures which are derived from the folding as well as wrapping of the structure of the DNA. The chromosome refers to the thread-like structure which is made up of nucleic acid and is observed in the nucleus of the living organisms.

2. Cell cycle refers to the cellular division of the cell; it is the series of events which occurs within a cell that results in duplication of the DNA or deoxyribonucleic acid as well as division of the cytoplasm and other organelles in order to generate two daughter cells. This cycle comprises of 4 phases, namely, G1, S, G2, and M phase.

The cell enters the G1 phase wherein the cell synthesizes the proteins as well as mRNA or messenger ribonucleic acid in preparation for the next upcoming phases which lead to mitosis. Next stage is the S phase wherein the synthesis of DNA takes place.

G2 phase is the next phase wherein the cell prepares itself by allowing it to grow as well as generate new proteins needed for the next phase called M phase. Mitosis is the final stage wherein the two identical daughter cells are made from one parent cell.

3. The cell cycle is broadly segregated into 3 phases, namely, interphase, M phase, and cytokinesis. Interphase is the longest stage of the cellular cycle and it comprises of 3 phases, G1 phase, S, and G2 phase. There is a G0 phase or quiescent phase. During the G1 phase, the cell prepares itself for the next phases of cell cycle, S phase involves synthesis of DNA, and G2 is the production of new proteins needed for the M phase.

4. During the mitotic phase, the parental cell segregates and produces 2 identical daughter cells. This phase is further segregated into prophase followed by metaphase, anaphase, and finally telophase. During metaphase, the chromosomes align themselves onto the equatorial or metaphase plate and the centrosomes prepare to segregate the sister chromatids. This phase takes only about 4% of the time needed to finish the entire cell cycle.

Explanation:

PLEASE HELP ME
If you start with 6 waters
going in during photosynthesis, how many waters are released during cellular respiration?

2

6

12

3

Answers

Answer:

Water is also a product of photosynthesis. This water is produced from the oxygen atoms in the carbon dioxide molecules. The oxygen molecules released into the atmosphere come exclusively from the original water molecules, not from the carbon dioxide molecules...

Hope this helps answer your question!

B r a i n l e i s t ?

Oxidation of a dithiol such as 2,5-hexanedithiol forms a six-membered ring containing a disulfide group as part of the ring. Draw the structure of this cyclic disulfide (Hint: Draw the starting compound in line structure format first).

Answers

Answer:

See picture below

Explanation:

In general terms, oxidation of thiol are rather different than oxidations with alcohols.

A dithiol is a molecule that has two thiols in an organic compound. In the case of the 2,5 hexanedithiol, we have the thiols in the carbon 2 and carbon 5.

When oxidation of thiols occurs, and depending of the number of thiols in the molecule, the final compound will have a sulfide group.

This is because the oxydation makes that the hydrogen atom of the sulfur is substracted. So, in the case of the dithiols, we have that both hydrogen atoms are substracted and then, they are available to join. Therefore, As the thiols are in the same molecule, it will occur a self condensation reaction.

The picture below will show the final product.

Hope this helps

Oxidation of a dithiol such as 2,5-hexanedithiol forms a six-membered ring containing a disulfide group as part of the ring. The structure of the cyclic disulfide that is 2,5-hexanedione is shown below.

Oxidation is a chemical reaction that involves the loss of electrons by a molecule, atom, or ion. This process results in an increase in the oxidation state of the species undergoing oxidation.

The oxidation of 2,5-hexanedithiol is a chemical reaction in which the thiol [tex]\rm (-SH)[/tex] groups of the molecule are converted into disulfide[tex]\rm (-S-S-)[/tex] bonds, resulting in the formation of 2,5-hexanedione. This reaction usually requires an oxidizing agent, such as hydrogen peroxide or nitric acid.

Therefore, the structure of cyclic disulfide(2,5-hexanedione) is shown below.

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Sulfuric acid, H 2 S O 4 , is an important industrial chemical, typically synthesized in a multi-step process. What is the percent yield if a batch of H 2 SO 4 has a theoretical yield of 3.9 kg, and 2.8 kg are obtained at the end of the process

Answers

Answer:

71.8%

Explanation:

The percent yield of a process or a chemical reaction is calculated as:

percent yield = actual yield/theoretical yield x 100%

From the problem we have:

theoretical yield = 3.9 kg

actual yield = 2.8 kg

Thus, we calculate the yield of H₂SO₄ production as follows:

percent yield = (2.8 kg/3.9 kg) x 100 = 71.79 % ≅ 71.8%

Over an interval of 2.0 s the average rate of change of the concentration of C was measured to be 0.0540 M/s. What is the final concentration of A at the end of this same interval if its concentration was initially 2.000 M

Answers

Answer:

Explanation:

the average rate of change of the concentration =

( initial concentration - final concentration ) / time

Initial concentration = 2.000 M

the average rate of change of the concentration = .0540 M/s

time = 2 s

Putting the values

.0540 =  (2.000 - X ) / 2

0.108 = 2.000 - X

X = 1.892 M .

Final concentration = 1.892 M .

Which of the following statements about semi-empirical methods are true?
a. It combines a theoretically sound model of bonding with some experimentally determined parameters.
b. It is faster to calculate than ab initio methods.
c. It can determine precisely both the location and the energy of bonding electrons.
d. It treats bonds simply as springs.

Answers

Answer:

a

Explanation:

The correct statement about semi-empirical methods is

It combines a theoretically sound model of bonding with some experimentally determined parameters.

These methods are typically referred to by acronyms which encode some of the underlying theoretical assumptions.

A reaction that proceeds by first-order irreversible kinetics is oxidizing chemical A in a wastewater treatment basin with a mean residence time of 1.5 hours. The reaction rate constant is The basin is unbaffled and may be characterized as two completely mixed tanks in series. If the steady-state influent concentration is 30 mg/l, find the effluent concentration. If baffles are placed in the basin so that the basin may be characterized as four completely mixed tanks in series, and the mean residence time remains constant, find the effluent concentration.

Answers

This question is incomplete, the complete question is;

A reaction that proceeds by first-order irreversible kinetics is oxidizing chemical A in a wastewater treatment basin with a mean residence time of 1.5 hours. The reaction rate constant is 2.0 Hr-1.The basin is unbaffled and may be characterized as two completely mixed tanks in series.  If the steady-state influent concentration is 30 mg/l, find the effluent concentration.

If baffles are placed in the basin so that the basin may be characterized as four completely mixed tanks in series, and the mean residence time remains constant, find the effluent concentration.

Answer:

a) (two completely mixed tanks in series) the find the effluent concentration is 4.8 [tex]\frac{mg}{l}[/tex]

b) (four completely mixed tanks in series) find the effluent concentration is 3.2 [tex]\frac{mg}{l}[/tex]

Explanation:

Given the data in the question;

we can determine the effluent concentration of two completely mixed tanks in series for first order irreversible reaction using the following equation;

C = Co ( 1 / ( 1 + K[tex]\frac{t}{n}[/tex] )ⁿ

t is the mean hydraulic residence time for two completely mixed tanks in series ( 1.5 hr)

Co is initial concentration of the influent ( 30 [tex]\frac{mg}{l}[/tex] )

C is final concentration of effluent,

n is the number of tanks series ( 2)

k is rate constant for the given first order reaction( 2[tex]\frac{1}{hour}[/tex] )

so we substitute

C = 30 [tex]\frac{mg}{l}[/tex]  ( 1 / ( 1 + 2[tex]\frac{1}{hour}[/tex] . [tex]\frac{1.5}{2}[/tex] )²

C = 30 [tex]\frac{mg}{l}[/tex]  × ( 1/2.5)²

C = 30 [tex]\frac{mg}{l}[/tex] × 0.16

C = 4.8 [tex]\frac{mg}{l}[/tex]

Therefore, (two completely mixed tanks in series) the find the effluent concentration is 4.8 [tex]\frac{mg}{l}[/tex]

b)

using;

C = Co ( 1 / ( 1 + K[tex]\frac{t}{n}[/tex] )ⁿ

t is the mean hydraulic residence time for two completely mixed tanks in series ( 1.5 hr)

Co is initial concentration of the influent ( 30 [tex]\frac{mg}{l}[/tex] )

C is final concentration of effluent,

n is the number of tanks series ( 4)

k is rate constant for the given first order reaction( 2[tex]\frac{1}{hour}[/tex] )

so we substitute

C = 30 [tex]\frac{mg}{l}[/tex]  ( 1 / ( 1 + 2[tex]\frac{1}{hour}[/tex] . [tex]\frac{1.5}{4}[/tex] )⁴

C = 30 [tex]\frac{mg}{l}[/tex] × ( 1/1.75)²

C = 30 [tex]\frac{mg}{l}[/tex] × 0.107

C = 3.2 [tex]\frac{mg}{l}[/tex]

Therefore, (four completely mixed tanks in series) find the effluent concentration is 3.2 [tex]\frac{mg}{l}[/tex]

Rearrange each jumbled letters
1. EMITNGL IPTNO
2. USLTBIAOMNI
3. RZFENIGE OTPNI
4. ENSODIOTIP
5. ETHA

Answers

Answer:

1. MELTING POINT

2. SUBLIMATION

3. FREEZING POINT

4. DEPOSITION

5. HEAT

Explanation:

1. Melting point 2.

For the reaction C + 2H2 → CH4, how many grams of hydrogen are required to produce 13.1 moles of methane, CH4 ?


Round your answer to the nearest tenth. If your answer is a whole number like 4, report the answer as 4.0

Answers

Answer:

7.0

Explanation:

With the given chemical compounds, what is the balanced chemical equation when lit with fire?

Answers

Answer:

Russia es el mejor pais? Vladimir Putin, es el mejor presidente del mundo

Which has more calories: table sugar or aspartame?

Answers

Hello there!

Aspartame has 4 kilocalories of energy per gram and table sugar has 3.9 kilocalories. They are pretty much same but aspartame is 200 times sweeter than sucrose so probably would be aspartame that has more calories.

Which formulas represent ionic compounds and which represent covalent compounds?

Covalent compound:

CsF

Na o

CHN

PCI,

Cao

CHO

NH

WO

lonic compound:

Cs

CdBr,

N

SOS

Answers

Answer:

See answer below

Explanation:

This is pretty easy to solve. First you need to understand that an ionic compound is usually formed between a metal and a non metal. This usually happens between elements from group 1 through group 10 or 11 of the periodic table. A covalent compound is always given in non metal elements from the periodic table, and it's usually the elements from group 13 through group 17.

Some compounds there are missing some atoms, but I manage to find this question and saw the atoms missing, so, in my answer you will see the corrected compound. so don't be surprised.

According to what I state above, then the covalent compounds are:

C₆H₅N

PCl₃

C₂H₄O

NH₃

N₂

SO₄²⁻

The ionic compounds are:

CaO

CdBr₂

WO₂

Na₂O

CsF

Hope this helps

what was the area of the himalayas like 40 million years ago

Answers

Answer:

yeskkfslszv

Explanation:

frgkkfsssssssss

Answer:

They were relatively flat.

24. The vaporization point of water is the same as its condensation point. True or False?
a. True
b. False

Answers

Answer:

pretty sure it's false

Explanation:

Observation of balloon rub with cloth?

Answers

Answer:

When rubbing a balloon with a wool cloth, it puts negative charges on the balloon. Negative charges attract to positive charges. ... When both balloons are rubbed with the wool cloth, the both receive negative charges, so they will repel each other.

i need help with this science pls

Answers

Answer:

1)40n

2)25n

Explanation:

subtract the numbers if its on the opposite sides and add if its on same side

thank u hope it helps

How much heat energy is required to raise the temperature of 0.362 kg of copper from 23.0 ∘C to 60.0 ∘C? The specific heat of copper is 0.0920 cal/(g⋅∘C) .

Answers

Answer:

83

Explanation:

23+60=83

Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing carbon dioxide gas and water vapor. Calculate the moles of oxygen needed to produce of water. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.

Answers

Answer:

0.225 mol = 0.23 mol to 2 significant figures

Explanation:

Calculate the moles of oxygen needed to produce 0.090 mol of water

The equation of the reaction is given as;

2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

From the equation of the reaction;

5 mol of O2 produces 2 mol of H2O

x mol of O2 produces 0.090 mol of H2O

5 = 2

x = 0.090

x = 0.090 * 5 / 2

x = 0.225 mol

How many grams of O2 are formed from 13.34 moles of KClO3? Provide your final answer rounded to two decimal places.

2 KClO3 → 2 KCl + 3 O2

Answers

Answer:

640.32 g

Explanation:

2KClO₃ → 2KCl + 3O₂

First we convert KClO₃ moles to O₂ moles, using the stoichiometric coefficients:

13.34 mol KClO₃ * [tex]\frac{3molO_{2}}{2molKClO_{3}}[/tex] = 20.01 mol O₂

Then we convert O₂ moles to grams, using its molar mass:

20.01 mol O₂ * 32 g/mol = 640.32 g

So 640.32 g of O₂ are formed from 13.34 moles of KClO₃.

The mineral content of rocks helps to
classify them.
B
weigh them.
с
melt them.
D
find them.

Answers

Answer:

Explanation:

The rocks are composed of mineral grains combined in different ways and having various properties. Minerals are naturally occurring chemical compounds in which atoms are arranged in three-dimensional patterns.

Heat will continue to move until the objects or areas have reached the same ______.

Answers

Answer: Thermal Equilibrium

Explanation:

Answer:

temperature  

Explanation:

I think that's it i'm sorry if i'm wrong

what is the atomic number for meitnerium

Answers

Answer:

"Meitnerium/Atomic number""109"

Explanation:

Meitnerium, the topic of this podcast, with the symbol Mt and atomic number 109, sits in the middle of this band in group 9 underneath cobalt, rhodium and iridium.

Hope this is fine for you

Write the balanced equation and draw the particulate representation of the following chemical reaction: sodium metal reacts with chlorine gas to produce sodium chloride.
Draw the complete decomposition of 4 molecules of hydrogen peroxide (H2O2) into water and oxygen gas.
Complete the particulate representation of the combustion of methane (CH4) with oxygen to form carbon dioxide (CO2) and water.

Answers

Answer:

2Na + Cl2 ------> 2NaCl

4H2O2 --------> 4H2O + 2O2

CH4 + 2O2 -------> CO2 + 2H2O

Explanation:

The balanced chemical equations for the given chemical reactions are given serially i) 2 Na+Cl₂[tex]\rightarrow[/tex] 2 NaCl  ii) 4 H₂O₂[tex]\rightarrow[/tex] 4 H₂O + 2 O₂  iii)CH₄ +2 O₂[tex]\rightarrow[/tex]CO₂ +2 H₂O

What is  chemical equation ?

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

The first chemical equation was put forth by Jean Beguin in 1615.By making use of chemical equations the direction of reaction ,state of reactants and products can be stated. In the chemical equations even the temperature to be maintained and catalyst can be mentioned.

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1. How many grams are there in 1.5 x 10^25 molecules of CO2?

Answers

Answer: 1.1 kg

Explanation:

Mw CO2 is 44g —> 6.02214076*10^23 molecules

1.5*10^25 molecules —> 1.1 kg

Which group of elements is listed in order of decreasing size? O oxygen, nitrogen, carbon, boron O xenon, krypton, argon, neon O carbon, silicon, germanium, tin O lead, thallium, mercury, gold​

Answers

Answer:

oxygen, nitrogen, carbon, boron

Explanation:

The person in front of me is correct

Describe the breeding place, type of fertilization, and development of the
embryo of the selected animals listed in the table below.
Table 2. Reproduction and Development in Selected Animals

help help
patulong po​

Answers

Answer:

Breeding is defined as the process of mating or sexual reproduction between two organism to produce an offspring.

Fertilization is the process in which eggs and sperm fuse together to form a zygote.

After fertilization, embryo development takes place inside females body and form a whole new organism or plant.

In the given examples:

Milkfish:

Breeding place land or water: water

Fertilization external or internal: internal

Development of embryo (outside or inside) the female's body: outside

Cat:

Breeding place land or water: Land

Fertilization external or internal: internal

Development of embryo (outside or inside) the female's body: inside

Frog:

Breeding place land or water: Land

Fertilization external or internal: inside

Development of embryo (outside or inside) the female's body: outside

Duck:

Breeding place land or water: Land

Fertilization external or internal: Internal

Development of embryo (outside or inside) the female's body: Outside

Cow:

Breeding place land or water: Land

Fertilization external or internal: internal

Development of embryo (outside or inside) the female's body: inside

Which of the following does not describe a chemical property?
A. Gasoline burns.
B. Gold does not react with oxygen.
C. Bleach is poisonous when swallowed.
D. Lead is more dense than gold.

Answers

C . Bleach is poisonous when swallowed i think

The one that does not describe a chemical property is bleach is poisonous when swallowed. The correct options are C.

What are chemical properties?

Chemical properties are those properties that show the reactivity of an element. These chemical properties are pH, chemical stability, reactivity, radioactive decay, flammability, toxicity, etc.

Gasoline is a chemical compound, its burning will be a chemical property because it shows how it reacts when it comes in contact with another chemical.

Gold is a pure element, its reactivity tendency is a chemical property, and it is not reactive with oxygen. Density is also a property of an element. And lead is denser than gold, which will show a chemical property.

Thus, the correct options are C. Bleach is poisonous when swallowed.

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Please explain to me!!!

Answers

Answer:

nice handwrtting

Explanation:

A student increases the temperature of a 200 cm balloon from 60°C to 120°C.
What will the new volume of the balloon be?
A)100cm^3
B)200cm^3
C)263cm^3
D)400cm^3

Answers

Answer:

236 cubic cm

Explanation:

We are given that

Initial volume, V1=200 cubic centimeter

Initial temperature, T1=60 degree Celsius=60+273=333 K

Final temperature, T2=120 degree Celsius=120+273=393 K

Kelvin temperature=Celsius temperature+273

We have to find the new volume of the balloon.

We know that

Charles's law

[tex]\frac{V_1}{T_1}=\frac{V_2}{T_2}[/tex]

Using the formula

[tex]\frac{200}{333}=\frac{V_2}{393}[/tex]

[tex]V_2=\frac{200\times 393}{333}[/tex]

[tex]V_2=236cm^3[/tex]

Hence, the new volume of the balloon will be 236 cubic cm.

Racecar driver Keimesha was in a race and accelerated from rest to 39 m/s by the time she reached the finish line. Keimesha’s car moved in a straight line and traveled from the starting line to the finish line in 6.0 seconds. What was the acceleration of the dragster?

Answers

Answer:

the acceleration of the racecar is 6.5 m/s²

Explanation:

Given;

initial velocity of the racecar, u = 0

final velocity of the racecar, v = 39 m/s

time of motion, t = 6.0 s

The acceleration of the racecar is calculated as;

[tex]a = \frac{v-u}{t} \\\\a = \frac{39-0}{6} \\\\a = \frac{39}{6} \\\\a = 6.5 \ m/s^2[/tex]

Therefore, the acceleration of the racecar is 6.5 m/s²

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