how many 3 combinations can you make with 11 numbers

Answers

Answer 1

Answer:

Step-by-step explanation:

Related Questions

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K), and the familiarity with the jokes (denoted by F) using this formula:

Answers

Answer:

L = f(J, K, F)

L = (JK²)/F

So, as the formula appears, the appropriate units will be option A.

Unit for number of laughs = (jokes*knowledge²) / familiarity

Just like the formula suggests.

Step-by-step explanation:

Complete Question

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K) and the familiarity with the jokes (denoted by F) using this formula: L = (JK²)/F

Select an appropriate unit for number of laughs:

A) (jokes*knowledge²) / familiarity

B) familiarity / (jokes*knowledge²)

C) familiarity² / (jokes*knowledge)

D) (jokes*knowledge) / familiarity²

Solution

L = f(J, K, F)

where

L = number of laughs

J = number of jokes

K = amount of knowledge about the joke material

F = familiarity with the jokes

Analysing how the dependent variable depends on each of the independent variables.

- Number of jokes

The number of laughs will increase with the number of jokes and vice versa. It can be stated that there is a direct variation between the number of laughs and number of jokes.

- Amount of knowledge about the joke material

The more one understands the joke material, the funnier the joke. In fact, the joke can be termed funnier when one understands the joke material deeply. The direct variation of number of laughs to knowledge about joke material isn't just enough, the number of laughs varying directly as the square of the knowledge of joke material seems more fitting.

- Familiarity with the joke

The more familiar one is with a joke, the less funny it is. Hence, it's an inverse relationship between number of laughs and the familiarity with the joke.

L = (JK²)/F

So, as the formula appears, the appropriate units will be

(jokes*knowledge²) / familiarity

Just like the formula suggests.

Hope this Helps!!!

The question is incomplete. Here is the complete question.

Select an appropriate unit for number of laughs:

(jokes*knowledge²) / familiarity

familiarity / (jokes*knowledge²)

familiarity² / (jokes*knowledge)

(jokes*knowledge) / familiarity²

Answer: Unit for number of laughs is (jokes*knowledge²) / familiarity

Step-by-step explanation: Number of laughs (L) is related to jokes (J), knowledge (K) and familiarity (F) according to the proportion: [tex]L = \frac{J.K^{2} }{F}[/tex]

The unit for L will be: L = (jokes.knowledge²).familiarity⁻¹

L = [tex]\frac{jokes*knowledge^{2} }{familiarity}[/tex]

2. The cone has a radius of 30 mm and slant height of 34 mm. What is the height h for this cone?

Answers

Answer:

h = 16

Step-by-step explanation:

By applying the Pythagorean Theorem, the slant height is given by the formula:

[tex]\sqrt{r^2+h^2}[/tex]

34 = [tex]\sqrt{30^2 + h^2}[/tex]

[tex]34^2 = 30^2 + h^2[/tex]

[tex]1156 = 900 + h^2[/tex]

[tex]256 = h^2[/tex]

[tex]h = \sqrt{256}[/tex]

[tex]h = 16[/tex]

At the start of 2014 Mikes car was worth £12000. the value of his car decreased 30% every year.
work out the value of the car at the start of 2017

Answers

Answer:

The worth of car at the start of 2014 = $12000

The value of the car decreased 30% every year.

At start of 2015:

30% of 12000 = \frac{30}{100} \times 12000

100

30

×12000 = 3600

So, the value of the car at start of 2015 = 12000-3600 = $8400.

At start of 2016:

30% of 8400 = \frac{30}{100} \times

8400

100

30

×8400 = 2520

So, the value of the car at start of 2016 = 8400-2520 = $5880.

At start of 2017:

30% of 5880 = \frac{30}{100} \times

5880
100

30

×5880 = 1764

the value of the car at start of 2017 = 5880-1764 = $4116.

So, the value of his car at the start of 2017 is $4116.

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