Answer:
By preventing the government from taking property without fair payment.
Explanation:
Answer 1
Please mark me as brilliant and thank you
Answer:
this is under the wrong section
Assess It! Question #2: Which of the following statements about the Law
of Acceleration is true?
5 points
A: Increasing an object's mass decreases the amount of force required to move it
B: Decreasing the mass of an object increases its acceleration while force is
constant
C: Increasing the force applied to an object does not change its acceleration while
mass is constant
D: Decreasing the force applied to an object increases its acceleration while mass is
constant
Answer:
Statement B is the only true statement
"Decreasing the mass of an object increases its acceleration while force is constant."
Explanation:
Recall that Newton's 2nd Law states:
F = m * a
Therefore, if the force (F) is constant, and the mass (m) decreases, the acceleration (a) of the object must increase.
This agrees with the statement labeled as B: "Decreasing the mass of an object increases its acceleration while force is constant."
The true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.
NEWTON'S LAW:
The relationship between the force, mass and acceleration has been explained by Newton in his law. The equation is as follows:Force = mass × accelerationAccording to the equation, the mass is inversely proportional to the acceleration. This means that as the mass increases, the acceleration decreases and vice versa. Therefore, the true statement about the law of acceleration is that decreasing the mass of an object increases its acceleration while force is constant.Learn more at: https://brainly.com/question/25116504?referrer=searchResults
A baseball player uses a pitching machine to help him improve his batting average. He places the 67.1 kg machine on a frozen pond. The machine fires a 0.101 kg baseball horizontally at a speed of 32.6 m/s. What is the magnitude of the recoil velocity of the machine
Answer:
The magnitude of the recoil velocity of the machine is 0.05 m/s.
Explanation:
Given;
mass of the baseball, m₁ = 0.101 kg
mass of the machine, m₂ = 67.1 kg
velocity of the baseball, v₁ = 32.6 m/s
let v₂ be the recoil velocity of the machine.
Apply the principle of conservation of linear momentum; the total momentum before and after firing the ball must be constant.
sum of the initial momentum of the ball and the machine = 0 (at rest)
sum of the final momentum of the ball and the machine = m₁v₁ + m₂v₂
Since total momentum is constant; m₁v₁ + m₂v₂ = 0
m₁v₁ + m₂v₂ = 0
(0.101 x 32.6) + (67.1)v₂ = 0
67.1v₂ = -3.2926
v₂ = (-3.2926) / 67.1
v₂ = -0.05 m/s (the negative sign shows that it is the opposite direction)
Thus, the magnitude of the recoil velocity of the machine is 0.05 m/s.
Imagine you are ice skating with your BFF. Both of you are at rest in the middle of the ice, when you shove your BFF away from you. You have a mass of 70 kg and your BFF has a mass of 60kg. When you shove off, you are moving with a velocity of 2.5 m/s.
What should the total net momentum be after the push?
Answer:
The total net momentum after the push is 0.
Explanation:
The total net momentum is given by:
[tex] p_{f} = p_{1_{f}} + p_{2_{f}} = m_{1}v_{1} + m_{2}v_{2} [/tex]
Where:
m₁: is the mass of 70 kg
m₂: is the mass of 60 kg
v₁: is the speed of 2.5 m/s
v₂:?
To find the final momentum first we need to find the speed v₂:
[tex]m_{1}v_{1} + m_{2}v_{2} = p_{i}[/tex]
Where [tex]p_{i}[/tex] is the initial momentum = 0 (they are at rest)
[tex] v_{2} = -\frac{m_{1}v_{1}}{m_{2}} = -\frac{70 kg*2.5 m/s}{60 kg} = -2.92 m/s [/tex]
The minus sign is because the second person is moving in the opposite direction to the first person.
Now, the total net momentum is:
[tex] p_{f} = m_{1}v_{1} + m_{2}v_{2} = 70 kg*2.5 m/s + 60 kg*(-2.92 m/s) = 0 [/tex]
The final total momentum (after the push) should be zero because of momentum conservation.
Therefore, the total net momentum after the push is 0.
I hope it helps you!
Two students race up a flight of steps together. "Student A" reaches the top of the steps 2 seconds ahead of
"Student B". Which of the students is more powerful?
A ball is thrown straight up and rises to a maximum height of 22 m. At what height is the speed of the ball equal to half of its initial value
Answer:
The height of the ball when the speed of the ball is half of its initial value is 16.5 m
Explanation:
Given;
maximum height reached by the ball, h = 22 m
let the initial velocity of the = u
The equation of maximum height reached by the ball is calculated as;
v = u² - 2gh
where;
v is the final velocity at the maximum height = 0
0 = u² - (2 x 9.8)22
0 = u² - 431.2
u² = 431.2
u = √431.2
u = 20.765 m/s
Half of the initial speed = ¹/₂ x 20.765 m/s = 10.383 m/s
The height of the ball at this half value of speed is calculated as;
v² = u² - 2gh
where;
v is the final speed = 10.383 m/s
u is the initial speed = 20.765 m/s
(10.383)² = (20.765)² - (2 x 9.8)h
(2 x 9.8)h = (20.765)² - (10.383)²
19.6h = 323.379
h = 323.379 / 19.6
h = 16.5 m
Therefore, the height of the ball when the speed of the ball is half of its initial value is 16.5 m
Yeah, so, my teacher finna kill me if I don't turn this in today..
The Fnet = m • a equation is often used in algebraic problem solving. The table below can be filled by substituting into the equation and solving for the unknown quantity. Try it yourself and then use the click on the buttons to view the answers. To get a (acceleration) by itself, you must divide net Force by mass.
Answer:
Blank 1: 10
Blank 2: 4
Blank 3: 10
Blank 4: 5
Blank 5: 5
explain why astronauts around the earth either in spaceship, a space station, or on a spacewalk appear to be weightless but are not actually weightless.
Answer:
Zero gravity
Explanation:
Astronauts around the earth either in spaceship, a space station or on a space walk appear to be weightless because of the zero gravity in such environment.
Weight is a function of the mass and acceleration due to gravity a body has.
Weight = mass x acceleration due to gravity
In a place where acceleration due to gravity is 0, the weight would be zero and a person would appear to be weightless.
If earth suddenly stops rotating, how will the 'Acceleration due to Gravity' change?
Hope this helps
The velocity of a bob on a simple pendulum at the lowest position is 10.56 m/s. What is the maximum vertical height it is able to rise to?
um I do not know sorry
Explanation:
ummmmmmjjhfgfffff
The electric field strength at a point in space a fixed (known) distance from a point charge source is 5000 N/C. How does the field strength change if the source charge has doubled charge
Answer:
See explanation
Explanation:
Electric field strength;
E = kq/d^2
k= coulombs constant
q= magnitude of charge
d = distance if separation
If
d is constant
q = 2q
Then;
E = 2 kq/d^2
Hence, the electric field strength will double.
What is the approximate momentum of a car with a mass of 1200 kg and a
velocity of 30.0 km/h? *
A. 13.0 N.S
B. 40.0 N.S
C.3.60 104 N.S
D. 5.40 x 104 N.S
A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volume of the block. Then, use that answer to determine the density of the block. *
Answer:
6g/cm³
Explanation:
Given parameters;
Mass = 600g
Dimension = 2cm wide, 2cm tall and 25cm long
Unknown:
Density = ?
Solution
Density is the mass per unit volume of any substance. To solve this problem:
Density = [tex]\frac{mass}{volume}[/tex]
Since mass = 600g
Let us find the volume;
Volume = length x width x height
Volume = 25cm x 2cm x 2cm = 100cm³
Therefore;
Density = [tex]\frac{600}{100}[/tex] = 6g/cm³
How come the arrow points the other direction when we look at it through a glass of water?
To move the Center of Gravity (CG) forward, you could do which of the following?
Add clay to the nose.
Increase the density of the nose material.
Decrease the volume of the horizontal and vertical stabilizer material.
All of the above.
its not Increase the density of the nose material bc i tried that so help pleasee
Answer:
I think it's no. 3
Decrease the volume of the horizontal and vertical stabilizer material.
Explanation:
Lemme know if it's correct
Answer:
all of the above
Explanation:
How could you find the mass of a box of pencils?
Find the mass of the parts, and then add those masses together.
Find the mass of each pencil and the mass of the box, and then add those masses together.
Find the mass of the whole.
all of the above
Explanation:
All of the ways mentioned can be used to determine the mass of the box and pencils contained.
Mass is the amount of matter contained in a substance. The substance here is the box and the pencils it contains. We can set off to measure the mass of the box and pencil as a wholeAlso, we can group the pencil find their mass and add to the mass of the box. All of these methods will accurately give us the mass of the box and pencil it contains.is prey abiotic or biotic?
An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
Answer:
[tex]\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}[/tex]
Explanation:
From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.
Hence, the material dispersion is [tex]\dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )[/tex]
Now, using the pulse spread formula:
[tex]\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda[/tex]
[tex]\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ ) \times (45 \ nm)[/tex]
Thus, the pulse spreading as a result of material dispersion is:[tex]\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}[/tex]
The pulses spreading will be 3.6 ns/km. The greatest frequency or the number of pulses per second that may be transmitted into a fiber is pulse spreading.
What is pulse spreading?As an optical pulse travels the length of a fiber, it widens. This feature, which is commonly represented in nanoseconds of widening per kilometer, restricts the usable bandwidth of the Fiber.
The greatest frequency, or the number of pulses per second that may be transmitted into a fiber and anticipated to emerge intact at the other end, has a limit.
This is due to a process known as pulse spreading, which restricts the file's "Bandwidth."
The given data in the problem is;
[tex]\lambda[/tex] is the wavelength = 850 nm
The pulse spreading formula is given as;
[tex]\rm \frac{\sigma_{mat}}{L} =\frac{d \tau_{mat}}{d \lambda} \sigma\lambda \\\\ \rm \frac{\sigma_{mat}}{L} = 80 \times 45 \\\\ \frac{\sigma_{mat}}{L} =3.6 \ ns/km[/tex]
Hence the pulses spreading will be 3.6 ns/km
To learn more about the pulse spreading refer to the link;
https://brainly.com/question/9351212
Find the length of a simple pendulum that has a period of 1.00 s. Assume that the acceleration of gravity is g
Answer:
The length of the simple pendulum is 0.248 m.
Explanation:
Given;
period of the simple pendulum, T = 1.00 s
let the length of the simple pendulum = L
The period of oscillation of a simple pendulum is calculated as;
[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi } = \sqrt{\frac{l}{g} }\\\\\frac{T^2}{4\pi ^2 } = \frac{l}{g}\\\\l = \frac{gT^2}{4\pi ^2 } \\\\l = \frac{(9.8)(1)^2}{4\pi ^2 } \\\\l = 0.248 \ m[/tex]
Therefore, the length of the simple pendulum is 0.248 m.
an impulse is a force acting over some amount of time to cause a change in momentum. on the other hand, work is a
Answer:
force; distance; energy.
Explanation:
An impulse can be defined as the net force acting an object for a very short period of time.
Mathematically, impulse is given by the formula;
[tex] Impulse = force * time[/tex]
An impulse is a force acting over some amount of time to cause a change in momentum. On the other hand, work is a force acting over some amount of distance to cause a change in energy.
Mathematically, work done is given by the formula;
[tex] Work done = force * distance [/tex]
Assume that, as the battery wears out, the voltage decreases at 0.03 volts per second and, as the resistor heats up, the resistance is increasing at 0.02 ohms per second. When the resistance is 100 ohms and the current is 0.02 amperes, at what rate is the current changing
Answer:
[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]
Explanation:
From the question we are told that
Voltage decreases at [tex]\frac{dv}{dt} =-0.03volts/sec[/tex]
Resistance increase at [tex]\frac{dR}{dt}=0.02ohms /sec[/tex]
Resistance at [tex]R=100ohms[/tex]
Current at [tex]I=0.02amps[/tex]
Generally the equation for ohms law is mathematically represented as
[tex]V=IR[/tex]
Therefore
[tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
Generally making [tex]\frac{dI}{dt}[/tex] subject of the formula in the above equation mathematically gives
[tex]\frac{dV}{dt} =R\frac{dI}{dt} +I\frac{dR}{dt}[/tex]
[tex]R\frac{dI}{dt} = \frac{dV}{dt} -I\frac{dR}{dt}[/tex]
[tex]\frac{dI}{dt} =\frac{1}{R} (\frac{dV}{dt} -I\frac{dR}{dt})[/tex]
Therefore
[tex]\frac{dI}{dt} =\frac{1}{100}((-0.03) -(0.02)*(0.02))[/tex]
Generally it is given that the change in current is
[tex]\frac{dI}{dt} =-3*10^-^4amps/sec[/tex]
An inductor is connected to a 120-V, 60-Hz supply. The current in the circuit is 2.4 A. What is the inductive reactance
Answer:
Inductive reactance is 50.00 ohms
Explanation:
Given the following data;
Voltage = 120v
Frequency = 60Hz
Current = 2.4 A
To find the inductive reactance;
Inductive reactance, XL = V/I
Where;
XL represents the inductive reactance. V represents the voltage. I represents the current.Substituting into the equation, we have;
XL = 120/2.4
XL = 50.00 ohms
A light wave travels from one medium into a second medium with a greater absolute index of refraction. Which characteristic of the wave can
Explanation:
With the change in medium the speed of light wave travel changes. Therefore, the absolute refractive index changes. The speed of light is maximum is vacuum and changes with the change in medium. This is the refractive indices of different medium are different.
The refractive index is the characteristic of the wave that can not change as the wave enters the second medium.
What is a refractive index?The refractive index of a substance also known as the refraction index or index of refraction is a dimensionless quantity that specifies how quickly light passes through it in optics.
When the refractive index of a substance is increased, the speed of light in the material decreases.
The speed at which light waves travel changes as the medium changes. The absolute refractive index changes.
As a result, the speed of light is greatest in a vacuum and decreases as the medium changes. This is due to the fact that the refractive indices of various media are different.
Hence the refractive index is the characteristic of the wave that can not change as the wave enters the second medium.
To learn more about the refractive index refer to the link;
https://brainly.com/question/14592350
A truck engine slows down from 3700 rpm to 1800 rpm in 4.25 s. How many revolutions were made by the engine during this time
Answer:
194.81 revolutions
Explanation:
Given that,
Initial angular velocity, [tex]\omega_i=3700\ rpm[/tex]
Final angular velocity, [tex]\omega_f=1800\ rpm[/tex]
Time, t = 4.25 seconds
We need to find the number of revolutions occur during this time.
3700 rpm = 387.46 rad/s
1800 rpm = 188.49 rad/s
Let [tex]\alpha[/tex] is angular acceleration. Using first equation to find it.
[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{188.49 -387.463 }{4.25}\\\\\alpha =-46.81\ rad/s^2[/tex]
Now let us suppose that the number of revolutions are [tex]\theta[/tex].
[tex]\theta=\dfrac{\omega_f^2+\omega_i^2}{2\alpha}\\\\=\dfrac{188.49 ^2-387.463 ^2}{2\times -46.81}\\\\=1224.087\ rad[/tex]
or
[tex]\theta=\dfrac{1224.087}{2\pi}\\\\=194.81\ rev[/tex]
Hence, there are 194.81 revolutions.
Q2. Point D is located at 49.3 m above the ground. The speed of the roller
coaster at point D is 0.49 m/s. Find the speed of the roller coaster at A, B, C
and E, located at the following heights above the ground:
A - 12.4 m
B-3.2 m
C-41.8 m
E-35.3 m
Water falls without splashing at a rate of 0.200 L/s from a height of 3.60 m into a 0.730 kg bucket on a scale. If the bucket is originally empty, what does the scale read (in newtons) 3.20 s after water starts to accumulate in it
Answer:
15.106 N
Explanation:
From the given information,
The weight of the bucket can be calculated as:
[tex]W_b = m_bg = \\ \\ W_b = (0.730 \ kg) ( 9.80 \ m/s^2) \\ \\ W_b = 7.154 \ N[/tex]
The mass of the water accumulated in the bucket after 3.20s is:
[tex]m_w= (0.20 \ L/s) ( 3.20)s[/tex]
[tex]m _w=0.64 \ kg[/tex]
To determine the weight of the water accumulated in the bucket, we have:
[tex]W_w = m_w g[/tex]
[tex]W_w = ( 0.64 \ kg )(9.80\ m \ /s^2)[/tex]
[tex]W_w = 6.272 \ N[/tex]
For the speed of the water before hitting the bucket; we have:
[tex]v = \sqrt{2gh}[/tex]
[tex]v = \sqrt{2*9.80 \ m/s^2 * 3.60 \ m}[/tex]
v = 8.4 m/s
Now, the force required to stop the water later when it already hit the bucket is:
[tex]F = v ( \dfrac {dm}{dt} )[/tex]
[tex]F = (8.4 \ m/s)( 0.200 \ L/s)[/tex]
F = 1.68 N
Finally, the reading scale is:
[tex]F_{scale[/tex] = 7.154 N + 6.272 N + 1.68 N
= 15.106 N
Answer:
F_scale ≈ 15.12 N
Explanation:
We are given;
Mass flow rate; m' = 0.2 l/s
Time; t = 3.2 s
Mass of bucket; m_b = 0.730 kg
Height; h = 3.6 m
Now, mass of water is;
m_w = 0.2 l/s × 3.2 s
m_w = 0.64 l
From conversion, 1 litre = 1 kg
Thus: m_w = 0.64 kg
Now, let's calculate final velocity from Newton's third equation of motion.
v² = u² + 2gh
Initial velocity is 0. Thus;
v² = 0 + 2(9.8 × 3.6)
v² = 70.56
v = √70.56
v = 8.4 m/s
Now, total mass of water and bucket is;
m_t = m_w + m_b = 0.64 + 0.73
m_t = 1.37 kg
Force on the scale is calculated from;
F_scale = (m_t)g + (m_w)v/t
F_scale = (1.37 × 9.81) + (0.64 × 8.4/3.2)
F_scale ≈ 15.12 N
What can we conclude from observing an attractive force between a positively charged rod and some object
Answer: that the object is negatively charged.
Explanation:
We know that the force between objects that have the same type of charge is a repulsive force, while for objects with an opposite charge, the force is attractive.
In this case, we know that we have an attractive force between an object and a positively charged rod.
Then the only conclusion we can take in this situation is that the object is negatively charged.
A standard 1 kilogram weight is a cylinder 47.0 mm in height and 49.0 mm in diameter. What is the density of the material
Answer:
11,627.91 kg/m^3
Explanation:
The computation of the density of the material is shown below
Given that
Mass , m = 1 kg
Height, H - 47 mm = 0.047 m
Diameter, d = 49 mm = 0.049 m
Now radius, r = D ÷ 2
= 0.049 ÷ 2
= 0.0245
Volume = πr^2h
= 3.14 × (0.0245)^2 × 0.047
= 0.000086m^3
Now the density of the material is
= mass ÷ volume
= 1÷ 0.000086m^3
= 11,627.91 kg/m^3
Answer: 11,282.8 kg/m^3
Explanation:
We know:
Density = mass/volume
1 kg = mass
(π)(r^2)(h) = volume
Density = m/(πr^2h)
Plug in your values:
Density = 1kg/(π)(24.5 mm)^2(47 mm)
^we have to cut 49 (the diameter) in half because the equation calls for radius
Remember to multiply the density by 10^9 mm/ 1 m because the answer asks for kg/m^3
for the same type of atom with 8 protons, 9 neutrons, and 10 electrons, what type of atom or ion is it
Answer:
O²⁻
Explanation:
Number of protons = 8
Number of neutrons = 9
Number of electrons = 10
What type of atom or ion is it = ?
Solution:
Protons are the positively charged particle in an atom
Neutrons do not carry any charges
Electrons are negatively charged particles
For this atom, the number of protons helps to identify what specie it is; so this is an oxygen atom.
Now,
Charge = Number of protons - Number of electrons
Charge = 8 - 10 = -2
The charge on the atom is -2 and so it is an oxygen ion with -2 charge
The ion is O²⁻
Suppose you stand on a bathroom scale and it reads 580.0 N (about 130 lbs). Afterwards, a giant vacuuum machine sucks all the air out of the room. Would the scale reading increase, decrease, or remain the same
Answer:
the reading of the balance must decrease
Explanation:
The balance of the span is within a fluid the air, for which it is subjected to the pressure of the same, if we write the equilibrium equation we have
F_net = B -W - F_armosphere
in this case F_net = 540 N
where the thrust is given by Archimedes' principle which states that the thrust is equal to the weight of the fluid dislodged
B = ρ g V
in this case the density of the air is
ρ = 1.1 kg / m³
therefore the value of the thrust is small
the force of the air is
P = F / A
F = P A
the air pressure is approximately P = 1 10⁵ Pa
Thus
B <F_atmosphere
Now we can analyze what happens when we remove the air from the room, the pressure at atmospheric pressure decreases therefore the force of the air decreases, while there is some air the thrust is maintained even when it also decreases since the density of the air decreases when decreasing the Pressure.
Consequently, the reading of the balance changes depending on how the thrust and the air force decreases, in general the air force decreases much faster than the thrust, therefore the reading of the balance must decrease
What are input energy and output energy?
Answer:
Explanation:
Input refers to the amount of energy put into a device, and output refers to the amount of energy that comes out. A device may change the type of energy but not the amount. For example, a light bulb's input energy is the form of electrical energy, and its output energy is in the form of light and heat. Efficiency.