How high must you lift a 25 Newton book for it to have the same increase in potential energy as a 20 Newton book that was lifted to 0.5 meters?

Answer:

F = 159.07 N

Explanation:

Given that,

Mass of a tennis ball, m = 54.9 g = 0.0549 kg

It accelerates from rest to a speed of 45.1 m/s.

The impact with the racket gives the ball a constant acceleration over a distance of 35.1 cm = 0.351 m

We need to find the magnitude of net force acting on the ball.

Let a be the acceleration of the ball. Using third equation of motion to find it.

[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(45.1)^2-(0)^2}{2\times 0.351}\\\\=2897.45\ m/s^2[/tex]

Net force,

F = ma

F = 0.0549 kg × 2897.45 m/s²

= 159.07 N

Hence, the net force acting on the ball is 159.07 N.

Answer:

a. t = 2.02 s

b. d = 20.2 m

Explanation:

Horizontal Motion

If an object is thrown horizontally from a height h with a speed v, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The time the object takes to hit the ground can be calculated as follows:

[tex]\displaystyle t=\sqrt{\frac{2h}{g}}[/tex]

The time does not depend on the initial speed.

The range or maximum horizontal distance traveled by the object can be calculated by the equation:

[tex]\displaystyle d=v.t[/tex]

The man standing on the edge of the h=20 m cliff throws a rock with an initial horizontal speed of v=10 m/s.

a.

The time taken by the rock to reach the ground is:

[tex]\displaystyle t=\sqrt{\frac{2*20}{9.8}}[/tex]

[tex]\displaystyle t=\sqrt{4.0816}[/tex]

t = 2.02 s

b.

The range is:

[tex]\displaystyle d=10\cdot 2.02[/tex]

d = 20.2 m

Answer:

10 m/s

Explanation:

Speed = Distance / Time

Speed = 400 / 40

Speed = 10

Unit = meters per second = m/s

Answer:

The value is [tex]\lambda = 0.335 \ m[/tex]  

Explanation:

From the question we are told that

     The length of the string is  [tex]l = 0.67 \ m[/tex]

      The mass is  [tex]m = 2.0 \ g = 0.002 \ kg[/tex]

      The frequency produced at  fourth harmonic vibration(i.e n =4 )  is  [tex]f = 700 \ Hz[/tex]

  Generally the wavelength of the string is  mathematically represented as

            [tex]\lambda = \frac{ 2L }{n }[/tex]

=>          [tex]\lambda = \frac{ 2 * 0.67 }{ 4 }[/tex]  

=>          [tex]\lambda = 0.335 \ m[/tex]  

Answer: Well the answer is KE = 5.625E-7 i just don't know the units for it...

Hope this helps....... Stay safe and have a Merry Christmas!!!!!!!!!! :D

Explanation:

list in order with the smallest molecules at the top and largest molecules at the bottom:

1.Oxygen

2.Water

3.Carbon dioxide

4.amino acid

5.Glucose

6. Starch

7. Protein

The molecules can be arranged as follows with the smallest at the top is oxygen, water, carbon dioxide, amino acid, glucose, starch, protein.

The given molecules;

starch, water, glucose, carbon dioxide, protein, amino acid, oxygen

The molecular weight of the given compounds is listed as follows;

water -------- 18 g/mol

glucose -------  180.2 g/mol

starch (2 or more glucose) ------ 360 g/mol

carbon dioxide ------ 44 g/mol

protein -------- 20,000 g/mol

amino acid (glycine) ----- 75 g/mol

oxygen -------- 16 g/mol

Thus, the molecules can be arranged as follows with the smallest at the top;

Learn more here:https://brainly.com/question/19537339

Answer:

is changing in direction, but constant in magnitude

Explanation:

This question is a bit tricky since the velocity of the satellite is changing, but the speed is constant.

Speed is simply a measure of how fast you are going. It doesn't matter where you're going, just how quickly.

Velocity, on the other hand, does care about which direction you're going. For example, it could be then when you travel right, your velocity is positive, and when you travel left, your velocity is negative. This is the similar for a 2D shape like a circular orbit

Since we know velocity is changing, there must be acceleration which changes that velocity (since acceleration is the change in velocity: going from 0 to 60 mph, for example)

Thus, with a non-zero net acceleration, we know that there must be a force that is changing in direction, but constant in magnitude (since the orbit is a circle, and always attracted to the center of the Earth at equal distance).

Answer:

(1) chess is played by him

(2) The great black engine was seen by her

(3) Arrangements for functions had been made by him

(4) A meeting is being attended by Raman

= when the last of the guests left, I went back into the hall to look for my mobile phone that I had kept on the table, I found that my mobile phone was not there. I felt freaked and I asked to every member of my family about my phone, but nobody had idea about that. then there was a phone call made by my uncle to my father, that his son had taken the mobile by mistake. After sometime, My uncle came to return my mobile. Then I took a sigh of relief .

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Answer:

W = MG

750 = M * 10

M = 750/10

M = 75 kg

Answer:

76.479 Kilograms Force (kgf)

Explanation:

Answer:

The lower fixed point, or ice point, is the temperature of pure melting ice at normal atmospheric pressure. The upper fixed point, or steam point, is the temperature of pure boiling water at normal atmospheric pressure.

Explanation:

Note that when the ball is in the air, the only force acting on it is the downward pull of gravity, so the force of the swing is a red herring.

The ball hits the ground at the same height from which it was hit, so its final velocity will have the same magnitude of 49 m/s, but pointing at an angle of 35° below the horizontal.

Answer:

ν=293.53 Hz

Explanation:

ν= speed/λ

speed = 204 m/s

λ=0.695 m

v = 204 m/s * 1/0.695m

meters cancels out

1/s = Hz

v = 204/0.695 Hz

ν=293.53 Hz

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apparently it is wrong, but my work and online calculator says otherwise... possibly round your answer? I'm not sure then...

Answer:146.75

Explanation:

Answer:

Vr = 20 [km/h]

Explanation:

In order to solve this problem, we have to add the relative velocities. We must remember that velocity is a vector, therefore it has magnitude and direction. We will take the sea as the reference measurement level.

Let's take the direction of the ship as positive. Therefore the boy moves in the opposite direction (Negative) to the reference level (the sea).

[tex]V_{r}=30-10\\V_{r}=20 [km/h][/tex]

Answer:

A & D

Explanation:

A single-displacement reaction is a chemical reaction whereby one element is substituted for another one in a compound and thereby generating a new element and also a new compound as products.

From the options, only options A & D fits this definition of single-displacement reactions.

For option D: Both left and hand and right hand sides each have one element and one compound. We can see that K is substituted from KBr to join Cl to form KCl and Br2 on the right hand side.

For option A: Both left and hand and right hand sides each have one element and one compound. We can see that OH is substituted from 2H2O to join Mg to form Mg(OH)2 and H2 on the right hand side.

The other options are not correct because they don't involve only and element and a compound on each side of the reaction.

Answer:

417.5 kg

Explanation:

Since the gravitational for of attraction F, equals the weight of the object W when its close to the earth, F = GMm/R² = W = mg where m = mass of object and g = acceleration due to gravity close to the earth = 9.8 m/s².

g = GM/R² where  g = acceleration due to gravity close to the earth, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.927 × 10²⁴ kg and R = radius of earth = 6.4 × 10⁶ m

So, g = GM/R²

= 6.67 × 10⁻¹¹ Nm²/kg² × 5.927 × 10²⁴ kg/(6.4 × 10⁶ m)²

= 39.53 × 10¹³ Nm²/kg ÷ 40.96 × 10¹² m²

= 9.65 N/kg

≅ 9.7 N/kg

= 9.7 m/s²

Since W = 4050 N and W = mg

m = W/g = 4050 N/9.7 m/s²

= 417.53 kg

≅ 417.5 kg

So, the mass of the object is 417.5 kg

Given :

[tex]m_1 = 82 \ kg\\\\v_1 = 257 m/s\\\\m_2 = 60 kg[/tex]

Let, us assume that momentum is conserved during the process.

To Find :

The velocity [tex]v_2[/tex] .

Solution :

Applying conservation of momentum :

Initial momentum = Final momentum

[tex]m_1v_1 = m_2v_2\\\\82\times 257=60\times v_2\\\\v_2 = \dfrac{82\times 257}{60}\ m/s\\\\v_2 = 351.23\ m/s[/tex]

Hence, this is the required solution.

Answer:

105 m

Explanation:

Given that the initial velocity of the body, u= 50 m/s in upward direction.

Acceleration due to gravity, g= 10 m / [tex]s ^ 2[/tex] in the downward direction.

Let h be the height of the body when the velocity of the body is 20 m/s.

As the gravitational force acting in the downward direction, so taking it negative as

a= - 10 m/[tex]s ^ 2[/tex]  in the upward direction.

By using the equation of motion [tex]v^2=u^2+2as[/tex] ...(i)

Here, u= 50 m/s

v= 20 m/s

[tex]a=- 10 m/s^2[/tex]

s=h

Putting all the values in the equation (i), we have

[tex]20^2=50^2+2(-10)h \\\\400=2500-20h \\\\h=\frac{2500-400}{20} \\\\h=105 m[/tex]

Hence, the height of the body is 105 m.

Answer:

Therefore, the work done to lift a 20 kg sack of potatoes of potatoes vertically 6.5 m is 1, 274 J.

Answer:

  capacitive

Explanation:

In a capacitive circuit, current is proportional to the derivative of the voltage. For a sinusoidal excitation, this means current is at the highest level when voltage is increasing through zero. That is, current leads the voltage.

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{p}{v} \\ [/tex]

p is the momentum

v is the velocity

From the question we have

[tex]m = \frac{56.59}{5.3} \\ = 10.677358...[/tex]

We have the final answer as

Hope this helps you

Answer:

D

Explanation:

Answer:

Astronomical Unit = 4.8481×10−6 pc; 1.5813×1.

Or even AU = Equal to

Explanation:

Answer:

3.2

Explanation:

I remember taking this quiz and I think that one is correct

Answer:

[tex]F_{g}=7.4704\times10^{-5}[/tex]

Explanation:

Givens: d = 1.0 × [tex]10^{4}[/tex]  [tex]m_{1} = 4.0 x 10^{8}[/tex]  [tex]m_{2} = 2.8[/tex]×[tex]10^{5}[/tex]

Required: [tex]F_{g}=?[/tex]

Formula:  [tex]F_{g}= \frac{(6.67x10^{-11})(m_{1})(m_{2}) }{d^{2}}[/tex]    (6.67x10^-11  is the gravitational constant)

[tex]F_{g}=\frac{\left(6.67\cdot10^{-11}\right)\left(4.0\cdot10^{8}\right)\left(2.8\cdot10^{5}\right)}{\left(1.0\cdot10^{4}\right)^{2}}[/tex]

[tex]F_{g}=7.4704\times10^{-5}[/tex]

Answer:

true false

Explanation:

Answer:

1.true

2.true

3.true                              4.false                        5.true

Answer:

When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J

Explanation:

Kinetic Energy

Is the type of energy an object has due to its speed. It's proportional to the square of the speed.

The equation for the kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]

Where:

m = mass of the object

v = speed at which the object moves

The kinetic energy is expressed in Joules (J)

The object has a kinetic energy of K=25 J when moving at v=5 m/s, thus the mass can be calculated by solving for m:

[tex]\displaystyle m=\frac{2K}{v^2}[/tex]

[tex]\displaystyle m=\frac{2*25}{5^2}=2[/tex]

m = 2 Kg

If the speed is doubled, v=10 m/s, the new kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}2\cdot 10^2[/tex]

K = 100 J

If the speed is tripled, v=15 m/s, the new kinetic energy is:

[tex]\displaystyle K=\frac{1}{2}2\cdot 15^2[/tex]

K = 225 J

When the speed is doubled, K = 100 J, when the speed is tripled, K = 225 J

The net force on the block acting perpendicular to the incline is

∑ F = n - w cos(29.4°) = 0

where n is the magnitude of the normal force and w = m g is the weight of the block.

The equation itself comes from splitting up the forces acting on the block into components pointing parallel or perpendicular to the incline. The only forces acting on the block in the perpendicular direction are the normal force and the perpendicular component of the block's weight.

Solve for n :

n = m g cos(29.4°)

n = (6 kg) (9.80 m/s²) cos(29.4°)

n ≈ 51.2 N

Answer:

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Answer:

The work done by Ramas is 3920 N.

Explanation:

Given;

mass of the load lifted by Ramas, m = 20 kg

height through which the load is lifted, h = 20 m

The work done by Ramas is equal to gravitational potential due to the height in which the load is lifted.

W = PE = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

W = 20 x 9.8 x 20

W = 3920 N.

Therefore, the work done by Ramas is 3920 N.