Answer:
The value is [tex]\theta _2 = 0.08 \ arcsec[/tex]
Explanation:
From the question we are told that
The first wavelength is [tex]\lambda_1 = 660 \ nm = 660 *10^{-9 }[/tex]
The first angular size is [tex]\theta_1 = 0.04 \ arcsec[/tex]
The second wavelength is [tex]\lambda _2 = 1320 \ nm = 1320 *10^{-9 } \ m[/tex]
Generally according to Rayleigh Criterion we have that
[tex]\theta= 1.22 * \frac{\lambda }{D}[/tex]
given every other thing remains constant we have that
[tex]\theta = k * \lambda[/tex]
Here k represented constant so
[tex]k = \frac{\theta }{\lambda}[/tex]
=> [tex]\frac{\theta_1}{ \lambda_1} = \frac{\theta_2}{ \lambda_2}[/tex]
=> [tex]\frac{\theta_1}{ \theta_2} = \frac{\lambda_1}{ \lambda_2}[/tex]
So
[tex]\frac{ 0.04}{ \theta_2} =0.5[/tex]
=> [tex]\theta _2 = 0.08 \ arcsec[/tex]
A lens is designed to work in the visible, near-infrared, and near-ultraviolet. The best resolution of this lens from a diffraction standpoint is A) The same for all wavelengths B) In the near-ultraviolet C) In the visible D) In the near-infrared E) Indeterminate
Answer:
B) In the near-ultraviolet
Explanation:
The best option to this problem is : In the near-ultraviolet
What are various names of tropical storms
based upon the ocean they occur in?
Answer:
hurricanes,Typhoons and cyclones
The energy released in the fission of one 235U92 is 206.6 MeV. A Nuclear reactor that uses this element has an output of 28.7 Mega Watts. What is the mass of 235U92 that is consumed in one day in this reactor
Answer: the required mass is 1.7628 × 10²⁵ μ
Explanation:
Given that;
energy released in the fission of one ²³⁵U₉₂ is 206.6 MeV
power p = 28.7 Mega Watts = 28.7 × 10⁶ W = 28.7 × 10⁶/ 1.6× 10⁻¹³ = 17.9375 × 10¹⁹ MeV/s
now fission need per second will be;
⇒ power / energy released i fission
= 17.9375 × 10¹⁹ MeV / 206.6 MeV = 8.68 × 10¹⁷ per second
now fission need per day will be;
⇒ ( 8.68 × 10¹⁷ × 360 × 24 ) = 7.5 × 10²² per day
hence mass of ²³⁵U₉₂ that is consumed in one day in this reactor will be;
⇒ (235 × 7.5 × 10²²)μ
= 1.7628 × 10²⁵ μ
Therefore the required mass is 1.7628 × 10²⁵ μ
How long is a simple pendulum with a period of 1 second?
Answer:
the second pendulum ( also called the royal pendulum) o.994m (39.1 in) long, in which each swing takes one second, became widely used in quality clocks.
A car accidently roll of a cliff. As it leaves the cliff it has horzontal velocity of 13 m/s it hits the ground 60m from the shoreline. Calculate the hight of the cliff
Answer: The height of the cliff is 104.59 m
Explanation:
The horizontal speed of the car when it leaves the cliff is 13 m/s, and it hits the ground 60m from the shoreline.
Here we can use the relationship:
Time*Speed = Distance.
To find the time that the car is in the air, we know that:
speed = 13m/s
distance = 60m
time = T
13m/s*T = 60m
T = (60m)/13m/s = 4.62 s
This means that the car is falling for 4.62 seconds.
Now let's analyze the vertical problem.
As the car leaves the cliff, it only has horizontal velocity, this means that the vertical initial velocity will be zero
The only force acting in the vertical axis is the gravitational force, this means that the acceleration will be equal to the gravitational acceleration, which is:
g = 9.8m/s^2
then:
a = -9.8m/s^2
Where the negative sign is because the acceleration is pulling the car downwards.
To get the vertical velocity, we could integrate over time to get:
v(t) = (-9.8m/s^2)*t + v0
Where v0 is the constant of integration and the initial vertical velocity, that we already know that is equal to zero, then the vertical velocity as a function of time can be written as:
v(t) = (-9.8m/s^2)*t
To get the vertical position equation, we need to integrate again over the time:
P(t) = (1/2)*(-9.8m/s^2)*t^2 + H
Where H is the constant of integration and the initial vertical position, then H will be the height of the cliff.
We know that the car needs 4.62 seconds to hit the ground, this means that:
P(4.6s) = 0m
Then:
P(t) = (1/2)*(-9.8m/s^2)*(4.62s)^2 + H = 0
(-4.9m/s^2)*(4.62s)^2 + H = 0
H = (4.9m/s^2)*(4.62s)^2 = 104.59 m
This means that the cliff is 104.59 meters high
Which of the following best illustrates Lewin's interactionist perspective?
Answer:
The options are
a. Sally is a very creative kind of person who likes to build things.
b. Jerry only works because he receives a very large income.
c. Rikki is usually shy, but at work she appears to be quite outgoing.
d. Maury gives money to charities because he wants other people to think he is very generous.
The answer is c. Rikki is usually shy, but at work she appears to be quite outgoing.
Lewin's interactionist perspective explains that an individual’s behavior is usually dependent on his personal behavior/ trait and the environment. The best option is that Rikki is usually shy which is her personal behavior but at work she appears to be quite outgoing due to her environment.
What do your observations show you about the forces exerted on objects in a collision?
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HELP ME NOW PLZ
What is the speed of a boy moving around a circular park of
radius 6 m if he goes once around the park in 20 s?
A-1.88m/s
B-3.76m/s
C-5.65m/s
D-None of the above
Answer: 1.88 m/s
Explanation:
The speed of the boy moving around a circular park of radius 6 m and taking time 20 seconds is 1.88 m/s.
What is speed?Speed is a measurement of how quickly an object's distance traveled changes. Speed is a scalar, which implies it has magnitude but no direction as a unit of measurement.
A thing that moves quickly and with great speed, covering a lot of ground in a short time. On the other hand, a slow-moving object traveling at a low speed covers a comparatively small distance in the same amount of time.
Given information:
The radius of the circular park, r = 6 m,
The time is taken to cover one round, t = 20s,
The total distance covered by the boy is equal to the circumference of the park, so
d = 2[tex]\pi[/tex]r,
[tex]d = 2*3.14*6\\d = 37.68 m[/tex]
Now,
the speed of the boy, s = [tex]37.68/20[/tex] ,
s = 1.88 m/s
Therefore, the speed of the boy moving around a circular park of radius 6 m and taking time 20 seconds is 1.88 m/s.
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How are clouds formed? What are the three major
Types of clouds and what do they look like?
O
Answer:
clouds are created when water vapor and invisible gas turns into water droplets and these water droplets form tiny particles like dust and float in the air.
you have cumulus
cirrus
cirrostraus
Explanation:
X- rays with a wavelgnth of 0.0700 nm diffract from a crystal. Two adjacne angels of x-ray diffraciton are 45.6 and 21.0 degrees. What is the distance in nm between the atomic planes responsible for the diffraction? (Use 2dcos(θ)=m(λ))
Answer:
0.15 nm
Explanation:
d = Distance between the atomic planes
m = Order
[tex]\theta_{m}[/tex] = First angle = [tex]45.6^{\circ}[/tex]
[tex]\theta_{m+1}[/tex] = Adjacent angle = [tex]21^{\circ}[/tex]
[tex]\lambda[/tex] = Wavelength = 0.07 nm
From Bragg's relation we know
[tex]2d\cos\theta_{m}=m\lambda[/tex]
[tex]2d\cos45.6^{\circ}=m0.07[/tex]
[tex]2d\cos\theta_{m+1}=(m+1)\lambda[/tex]
[tex]2d\cos21^{\circ}=(m+1)0.07\\\Rightarrow 2d\cos21^{\circ}=m(0.07)+0.07[/tex]
So
[tex]2d\cos21^{\circ}=2d\cos45.6^{\circ}+0.07\\\Rightarrow 2d(\cos21^{\circ}-\cos45.6^{\circ})=0.07\\\Rightarrow d=\dfrac{0.07}{2(\cos21^{\circ}-\cos45.6^{\circ})}\\\Rightarrow d=0.14962\ \text{nm}[/tex]
The distance between the atomic planes is 0.15 nm.
The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.4 V is across it at a frequency of 1400 Hz. What is the value of the inductance
Answer:
The value of the inductance is 1.364 mH.
Explanation:
Given;
amplitude current, I₀ = 200 mA = 0.2 A
amplitude voltage, V₀ = 2.4 V
frequency of the wave, f = 1400 Hz
The inductive reactance is calculated;
[tex]X_l = \frac{V_o}{I_o} \\\\X_l = \frac{2.4}{0.2} \\\\X_l =12 \ ohms[/tex]
The inductive reactance is calculated as;
[tex]X_l = \omega L\\\\X_l = 2\pi fL\\\\L = \frac{X_l}{2 \pi f}[/tex]
where;
L is the inductance
[tex]L = \frac{12}{2 \pi \times \ 1400} \\\\L = 1.364 \times \ 10^{-3} \ H\\\\L = 1.364 \ mH[/tex]
Therefore, the value of the inductance is 1.364 mH.
Given values are:
Current, [tex]I_0 = 200 \ mA, or \ 0.2 \ A[/tex]Voltage, [tex]V_0 = 2.4 \ V[/tex]Frequency, [tex]f = 1400 \ Hz[/tex]As we know the formula,
→ [tex]X_l = \frac{V_0}{I_0}[/tex]
By substituting the values, we get
[tex]= \frac{2.4}{0.2}[/tex]
[tex]= 12 \ ohms[/tex]
Now,
The inductive reactance will be:
→ [tex]X_l = \omega L[/tex]
or,
→ [tex]X_l = 2 \pi f L[/tex]
Hence,
The Inductance will be:
→ [tex]L = \frac{X_i}{2 \pi f}[/tex]
By putting the values, we get
[tex]= \frac{12}{2 \pi\times 1400}[/tex]
[tex]= 1.364\times 10^{-3} \ H[/tex]
[tex]= 1.36 \ mH[/tex]
Thus the above answer is right.
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A tissue is a group of similar cells that perform a specific function in an organism true or false
Answer:
true
Explanation:
A man stands on top of a cliff and shouts.
He hears the echo on the third clap when
he claps his hand at the rate of two claps
per second. What is the distance between
man & the obstruction, if the velocity of
sound is 320 m/s
[tex] \small\bf \: let \: the \: distance \: of \: the \: man \: from \: the \: cliff \: be \: x[/tex]
[tex] \small\bf \: thus \: time \: taken \: by \: sound \: to \: hit \: the \: cilff \: and \: return = \frac{2x}{v} = 1[/tex]
[tex] \bf \to \: x = \frac{320}{2} m = 160m[/tex]
[tex] \small \bf \: thus \: the \: distance \: between \: the \: cliffs \: = 160m \times 2 = 320m[/tex]
To understand the meaning of the variables that appear in the equations for rotational kinematics with constant angular acceleration. Rotational motion with a constant nonzero acceleration is not uncommon in the world around us. For instance, many machines have spinning parts. When the machine is turned on or off, the spinning parts tend to change the rate of their rotation with virtually constant angular acceleration. Many introductory problems in rotational kinematics involve motion of a particle with constant, nonzero angular acceleration. The kinematic equations for such motion can be written as
Answer:
ω = ω₀ + α t
ω² = ω₀² + 2 α θ
θ = θ₀ + ω₀ t + ½ α t²
Explanation:
Rotational kinematics can be treated as equivalent to linear kinematics, for this change the displacement will change to the angular displacement, the velocity to the angular velocity and the acceleration to the angular relation, that is
x → θ
v → ω
a → α
with these changes the three linear kinematics relations change to
ω = ω₀ + α t
ω² = ω₀² + 2 α θ
θ = θ₀ + ω₀ t + ½ α t²
where it should be clarified that to use these equations the angles must be measured in radians
An object that is initially traveling at 17.6 m/s has
1,743 J of work performed on it. If the mass of the
object is 283 kg, its final kinetic energy will be
J.
Which type of bond has elements with the greatest difference in electronegativity?
Covalent
Ionic
Metallic
Polar
Plz Help
Answer:
inonic bond has greatest difference in electronegativiru
The type of bond that has elements with the greatest difference in electronegativity ionic bond. The correct option is is B.
What is electronegativity?Electronegativity is a chemical property that describes an atom's or functional group's tendency to attract electrons toward itself.
An atom's electronegativity is affected by both its atomic number and the distance between its valence electrons and the charged nuclei.
Electronegativity is a measurement of an atom's proclivity to attract electrons (or electron density) towards itself.
It governs the distribution of shared electrons between two atoms in a bond. The greater an atom's electronegativity, the more strongly it attracts electrons in its bonds.
Ionic bonds are formed by elements with large differences in electronegativity. Covalent bonds are formed between atoms of elements with similar electronegativity.
Thus, the correct option is B.
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If a paratroopers legs have enough strength to support five times her weight, and they can do so over a travel distance of 0.5 m as they flex, from what height can she free fall to a solid surface without injury
Answer: the required height is 2.5 m
Explanation:
given the given data in question
Lime to come in rest;
using S = ((U1 + U2)/2) t
⇒ 0.5 = ((√(2gh) + 0)/2) t
t = (0.5 × 2) / √(2gh)
now fat = impulse = change in momentum dp
F = 5mg = dp/dt = [(m√(2gh))/(0.5 × 2)] × √(2gh)
5mg = 2mgh/(0.5 × 2)
5 = h / 0.5
h = 5 × 0.5
h = 2.5 m
Therefore the required height is 2.5 m
HELP PLZ!!!!!!!!!!!!!!
Answer:
Since binary is only 1 and 0, you can use a flashlight to display something similar to Morse code (see explanation below)
Explanation:
In binary, 1 means "on" and 0 means "off". A way you can use visible light is through turning on and off a flashlight. If the flashlight is turned on, it would represent a 1. If the flashlight is turned off, it would represent a 0. To make the message easier and more accurately understood for the receiver make sure to flash the lights in a consistent pattern (ex. each flash lasts no longer than half a second, one second between each digit, etc.)
For example, let's say you're trying to send the message "11001"
on on off off on
0 1 2 3 4 5 Numbers represent seconds
As you can see above the message starts at 0 seconds. Between 0 and 1 seconds the flashlight is turned on once. Between 1 and 2 seconds the flashlight is turned on again, Between 2 and 3 seconds as well as 3 and 4 seconds the flashlight is not turned on at all. And finally between 4 and 5 seconds the flashlight is turned on.
Coherent light from a laser shines through two slits 0.002 cm apart, producing an interference pattern on a screen. A bright central fringe is seen on the screen in line with a point directly between the slits. The next bright fringe is seen at an angle of 2 degrees above the central fringe (with a dark fringe between). What is the wavelength of the laser’s light? (1 nm = 10-9 m)
Answer:
λ = 698 nm (Approx)
Explanation:
Given:
Width d = 0.002 cm = 0.002 x 10⁻² nm
θ = 2°
Computation:
d sinθ = mλ
(0.002 x 10⁻²) sin2° = mλ
λ = 698 nm (Approx)
The aorta carries blood away from the heart at a speed of about 42 cm/s and has a diameter of approximately 1.1 cm. The aorta branches eventually into a large number of tiny capillaries that distribute the blood to the various body organs. In a capillary, the blood speed is approximately 0.08 cm/s, and the diameter is about 0.0005 cm. Treat the blood as an incompressible fluid, and determine N the approximate number of capillaries in the human body.
Answer:
ok fine I'll answer u on comment
football or basketball which one is easier to get you offers
Answer:
basketball
Explanation: cause it is
Answer:
It honestly depends on which one you're better at.
Explanation: I mean that's what I think.
A car slows down uniformly from a speed of 21.0m/s to rest in 6.00s. How far did it travel in that time?
(sorry something wrong w my keyboard so write each line for the explnation!)
63.0 m
Explanation:
Acceleration of car
=
v
−
u
t
=
0 ms
−
1
−
21.0 ms
−
1
6.00 s
=
−
3.50 ms
−
2
S
=
v
2
−
u
2
2a
S
=
(
0 ms
−
1
)
2
−
(
21.0 ms
−
1
)
2
2
×
−
3.50 ms
−
2
S
=
63.0
m
Lisa made the electromagnet shown. (Image above) What can Lisa do to increase the strength of the electromagnet?
O She can use a nail with weaker magnetic properties.
O She can change the direction of the nail.
O She can increase the number of wire loops.
O She can reduce the current in the wire.
If correct first gets Brainliest Please hurry this is a timed test( this is second time just in case I didn't go through)
Answer:
I think C
Explanation:
if im wrong then what is it im taking the exam too
Answer: C. She can increase the number of wire loops.
Explanation:
A(n) 70.1 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 41.4 m away from the shuttle and moving with zero speed relative to the shuttle. She has a(n) 0.916 kg camera in her hand and decides to get back to the shuttle by throwing the camera at a speed of 12 m/s in the direction away from the shuttle. How long will it take for her to reach the shuttle
Answer:
4.4 min
Explanation:
To solve this, we use the law of conservation of momentum
0 = -m(a).v(a) + m(c).v(c), where
m(a) = mass of the astronaut
m(c) = mass of the camera
v(a) = velocity of the astronaut
v(c) = velocity of the camera
Making v(a) subject of the formula, we have
v(a) = m(c).v(c)/m(a)
Now, we make one last assumption, that the astronaut is moving at constant speed and time, thus the time needed will be
t = s/v -> since s = vt
Now, we already have our v from above, so we substitute
t = s/[m(c).v(c)/m(a)]
t = s.m(a)/m(c).v(c)
Applying the values, we have
t = (41.4 * 70.1) / (0.916 * 12)
t = 2902.14 / 10.992
t = 264 seconds or 4.4 minutes
Do dwarf planets has several other bodies in their path orbiting the Sun just as they do?
Answer:
No they just orbit the sun
Explanation:
if the instantaneous current in the circuit is giveen by I=3 sin theta amperes, the rms value of the current will be
Answer:
[tex]I_{rms}=2.12\ A[/tex]
Explanation:
Given that,
The instantaneous current in the circuit is giveen by :
[tex]I=3\sin\theta\ A[/tex]
We need to find the rms value of the current.
The general equation of current is given by :
[tex]I=I_o\sin\theta[/tex]
It means, [tex]I_o=3\ A[/tex]
We know that,
[tex]I_{rms}=\dfrac{I_o}{\sqrt2}\\\\=\dfrac{3}{\sqrt2}\\\\=2.12\ A[/tex]
So, the rms value of current is 2.12 A.
A 1500 kg car sits on a 3.5° inclined hill. Find the force of friction required to keep it from
sliding down the hill. The coefficient of static friction is μ=0.45
Answer:
The force of friction required to keep the car from sliding down the hill is 898.054 newtons and since [tex]f<f_{max}[/tex], the car will not slide down the hill.
Explanation:
The free body diagram is included below and now we prepare each equation of equilibrium for respective orthogonal axis:
[tex]\Sigma F_{x'} = f-m\cdot g \cdot \sin \theta = 0[/tex] (1)
[tex]\Sigma F_{y'} = N-m\cdot g \cdot \cos \theta = 0[/tex] (2)
Where:
[tex]f[/tex] - Static friction force, measured in newtons.
[tex]N[/tex] - Normal force from the inclined hill to the car, measured in newtons.
[tex]m[/tex] - Mass of the car, measured in newtons.
[tex]g[/tex] - Gravitational constant, measured in meters per square second.
[tex]\theta[/tex] - Angle of inclination of the hill, measured in sexagesimal degrees.
If we know that [tex]m = 1500\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 3.5^{\circ}[/tex], then the friction force required to keep the car from sliding down the hill is:
[tex]f = m\cdot g \cdot \sin \theta[/tex]
[tex]f = (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \sin 3.5^{\circ}[/tex]
[tex]f = 898.054\,N[/tex]
The force of friction required to keep the car from sliding down the hill is 898.054 newtons.
If the car does not slide down the hill, then the following condition must be observed:
[tex]f\le \mu_{s}\cdot m\cdot g \cdot \cos \theta[/tex] (2)
Where [tex]\mu_{s}[/tex] is the static coefficient of friction, dimensionless.
If we know that [tex]\mu_{s} = 0.45[/tex], [tex]m = 1500\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 3.5^{\circ}[/tex], then the maximum allowable static friction force is:
[tex]f_{max} = \mu_{s}\cdot m \cdot g \cdot \cos \theta[/tex]
[tex]f_{max} = (0.45)\cdot (1500\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot \cos 3.5^{\circ}[/tex]
[tex]f_{max} = 6607.378\,N[/tex]
Since [tex]f<f_{max}[/tex], the car will not slide down the hill.
An Airplane moves 70 m/s as it travels around a vertical circular loop which has a 3 km radius. What is the magnitude of the net force on the 95 kg pilot at the bottom of this loop?
Answer:
155.17N.
Explanation:
The magnitude of the net force is expressed as;
F = mv²/r where;
m is the mass
v is the velocity of the airplane
r is the radius of the loop
Given
m = 95kg
v = 70m/s
r = 3km = 3000m
Required
Magnitude of the net force
F = 95*70²/3000
F = 95*4900/3000
F = 95*49/30
F = 4655/30
F = 155.17N
Hence the magnitude of the net force on the 95 kg pilot at the bottom of this loop is 155.17N.
The net force on the pilot is 1551.67 N.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the magnitude of the net force at the bottom of the loop, we use the formula below.
Formula:
F = mv²/r............. Equation 1Where:
m = mass of the pilotv = velocity of the Airplaner = radius of the loopF = net force on the pilot.From the question,
Given:
m = 95 kgr = 3 km = 3000 mv = 70 m/sSubstitute these values into equation 1
F = 95(70²)/300F = 465500/300F = 1551.67 NHence, the net force on the pilot is 1551.67 N.
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Two objects of same material are travelling near you. Object A is a 1.1 kg mass traveling 10.2 m/s; object B is a 2 kg mass traveling 5 m/s. Which object would make you feel worse if you are hit by it
Answer:
Object A
Explanation:
The object that would make you feel worse if you're hit by it is the object possessing the highest momentum. Thus, we need to find the momentum of the two objects.
Momentum of an object is the product of its mass and that of it's velocity. Momentum is given by the formula
P = M * V, where
P = momentum
M = mass of the object
V = velocity of the object
Now, solving for object A, we have
P(a) = 1.1 * 10.2
P(a) = 11.22 kgm/s
And then, solving for object B, we have
P(b) = 2 * 5
P(b) = 10 kgm/s
The object when the highest momentum is object A, and thus would make you feel worse when hit by it
g You want to make simultaneous measurements of the position and momentum of an electron and a proton that are moving along a straight line. An alternate statement of the uncertainty principle involves relationship between position (Δx) and momentum (Δp) uncertainties in the form . If both of them are located with an uncertainty of 1 × 10-10 m, what is the ratio of uncertainty in the velocity of the electron to that of the proton?
Answer:
1832
Explanation:
From;
Δp Δx = h/4π
Δp = uncertainty in momentum
Δx = uncertainty in position
h= Plank's constant
But p =mv hence, Δp= Δmv
m= mass, v= velocity
mass of electron = 9.11 * 10^-31 Kg
Mass of proton = 1.67 * 10^-27 Kg
since m is a constant,
Δv = h/Δxm4π
For proton;
Δv = 6.6 * 10^-34/4 * 3.14 * 1.67 * 10^-27 * 1 * 10^-10
Δv = 315 ms-1
For electron;
Δv = 6.6 * 10^-34/4 * 3.14 * 9.11 * 10^-31 * 1 * 10^-10
Δv = 577000 ms-1
Ratio of uncertainty of electron to that of proton = 577000 ms-1/315 ms-1= 1832