Answer:
The ability of a substance to be reused depends on various factors such as its chemical and physical properties, how it is processed and used, and the environmental conditions it is exposed to. Some substances can be easily purified or restored to their original state, while others may undergo chemical changes or deteriorate during use, making it difficult or impossible to reuse them. Additionally, the cost and availability of alternative materials, as well as regulations and policies, can also impact the decision to reuse a substance.
A container with volume 1.54 L is initially evacuated. Then it is filled with 0.221 g of N2. Assume that the pressure of the gas is low enough for the gas to obey the ideal-gas law to a high degree of accuracy.
If the root-mean-square speed of the gas molecules is 182 m/s , what is the pressure of the gas?
The pressure of the gas in a container with a volume of 1.54 L is initially evacuated. Then it is filled with 0.221 g of N2 is 1619Pa.
A gas with a small density and at a sufficiently high temperature so that the interaction between its particles can be neglected can be considered an ideal gas. In this case, the pressure, volume, and temperature of the gas are related as follows:
PV=mMRT, where m is the mass of the gas and M is the molar mass of the gas. The pressure of the gas can be found using the ideal gas law:p =mRT/MV.
The temperature of the gas can be found from the RMS speed of the molecules of nitrogen, which is given by: vrms=√3RT/M. Solving for the temperature, we obtain: T= Mv² / 3 R. And pressure is P= mv² /3V. So P=[ 0.221×(184)²]/ 3×1.54 = 1619 Pa.
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The takeoff speed for an Airbus A320 jetliner is 80 m/s. Velocity data measured during takeoff are as shown.a. Is the jetliner’s acceleration constant during takeoff? Explain.b. At what time do the wheels leave the ground?c. For safety reasons, in case of an aborted takeoff, the runway must be three times the takeoff distance. Can an A320 take off safely on a 2.5-mi-long runway?
The acceleration is expressed as the product of the change in time and the change in velocity, and it is 2.3 m/s. 34.78 seconds pass before the wheels lift off the ground.
How do velocity and speed differ?Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.
Taking the first interval, we find
a = Δvx/Δt
a = 23m/s/10m/s
a = 2.3m/s
By dividing the acceleration in m/s2 by the value of g, or the acceleration of gravity (9.81 m/s2), we may determine the jet's acceleration in g's.
ag = a/g
2.3/9,8
ag = 0.33g
When the jet reaches its takeoff velocity, which is 80 m/s, the wheels come off the ground.
The jet's velocity is zero at time t=0 s. Since we are aware that the acceleration is constant (a=2.3 m/s2), we can use the equation to determine the time t at which the jet achieves a velocity of vf=80 m/s.
vf = vi + at
Re-arranging and substituting numbers, we find
t = vf/a
t = 80/2.3
t = 34.78s
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a space shuttle is in a 250 mile high orbit what are the shuttle's orbit period in minutes and its speed
The orbital period of a space shuttle in a 250 mile high orbit is approximately 91.3 minutes, and the orbital speed is approximately 17,500 miles per hour (7.68 kilometers per second).
This speed is determined by the gravitational pull from Earth, as well as the height of the orbit. The higher the orbit, the slower the orbital speed. For a 250 mile high orbit, the shuttle will need to maintain a constant speed in order to stay in orbit. The speed and orbital period of a space shuttle in orbit depend on a number of factors, including the height of the orbit, the mass of the shuttle, and the gravitational pull of the Earth.
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Use the provided Smith charts to find the normalized input impedance of a lossless line of length l terminated in a normalized load impedance zL for each of the following combinations. Show your work on the Smith chart clearly
a) l = 0.75λ, zL = 1+ j0
(b) l = 0.5λ, zL = 1- j1
(c) l = 0.2λ, zL = 1+ j1
(d) l = 1.3λ, zL = 0.5 + j0.5
(e) l = 0.2λ, zL = 0 (short circuit)
Use the provided Smith charts to find the normalized input impedance of a lossless line of length l terminated in a normalized load impedance zL for each of the following combinations. l = 1.3λ, zL = 0.5 + j0.5.so, option (c) is correct.
What is impedance?The measure of resistance to electrical flow is called impedance, and it is denoted by the letter Z. In ohms, it is measured.
What is resistor?An electrical component known as a resistor controls or restricts the passage of electrical current in an electronic circuit.
Knowing about different parts, such as resistors, inductors, capacitors, power sources, connecting wires, and more, is necessary when building a circuit. Among the circuit's essential elements is the resistor.
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Find the amount of heat needed to increase the temperature of 5.0Mol of an ideal monatomic gas by 23K if (a)the pressure or (b)the volume is held constant.
The amount of heat needed is 2812.5 Joules.
To find the amount of heat needed to increase the temperature of 5.0 moles of an ideal monatomic gas by 23K when the pressure or volume is held constant, you can use the formula Q = nCΔT, where Q is the amount of heat, n is the number of moles, C is the heat capacity of the gas, and ΔT is the change in temperature.
In this case, n = 5.0 moles, C = 24.5 (the heat capacity of an ideal monatomic gas at constant pressure), and ΔT = 23K. Therefore, the amount of heat needed is Q = 5.0 * 24.5 * 23 = 2812.5 Joules.
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Part A: How much pressure is needed to compress the volume of an iron block by 0.20% ? Express your answer in N/m2. Use Biron=9.0×10^10 N/m^2.
Express your answer using two significant figures.
Part B: Compare it to atmospheric pressure (1.0×10^5 N/m^2).
Express your answer using two significant figures.
The bulk modulus of the iron block is given 9 × 10¹⁰ N/m². The volume change is 0.20 %. Then the pressure required for the compression is 1.8 × 10⁸ N/m².
What is bulk modulus?Bulk modulus of an object is the measure of its resistance to compression. It is the ratio of infinitesimal increase in pressure to the decrease in volume.
B = ΔP/ΔV/V
= ΔPV/ΔV.
Given B = 9 × 10¹⁰ N/m²
ΔV/V = 0.20/100 = 0.002
then ΔP = B ΔV/V
ΔP = 9 × 10¹⁰ N/m² × 0.002 = 1.8 × 10⁸ N/m²
Atmospheric pressure = 1 × 10⁵ N/m²
then ΔP/Patm = 1.8 × 10⁸ N/m²/1 × 10⁵ N/m² = 1800
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Which equation represents inverse proportionality?
Responses
y=m/x
y equals m divided by x
y=mx2+b for nonzero b
y equals m x squared plus b for nonzero b
y=mx
y equals m x
y=mx2
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Inverse proportionality means that the two terms should be proportional to inverse of each other ~
That is :
[tex]\qquad \sf \dashrightarrow \: y \propto \dfrac{1}{x} [/tex]
And according to given options, only option 1 shows inverse proportionality. where y is inversely proportional to x and m is proportionality constant.
[tex]\qquad \sf \dashrightarrow \: y = \dfrac{m}{x} [/tex]
Transmission describes what happens when ____
A. two waves collide in the same medium.
B. a wave splits into two waves within the same medium.
C. multiple waves exchange energy within a single medium.
D. a wave passes into a new medium and travels through that medium.
Answer:
Explanation:
D. a wave passes into a new medium and travels through that medium.
Transmission refers to the process of a wave traveling through a new medium, such as when light passes through a pane of glass or sound travels through air.
The given diagram shows the motion of a mass on a string which is swung in a circle. Which of the given arrows correctly shows the direction of the tangential velocity at the instant the mass is at the position shown?
- A
- B
- C
- D
The direction of the tangential velocity at the instant the mass is at position is diagram A.
What is tangential velocity?Tangential velocity is the velocity of an object along a circle or curved path, at any given point. It is the component of the velocity that is perpendicular to the radius of the circle, and it is perpendicular to the radial velocity, which is the component of velocity that points towards or away from the center of the circle.
The tangential velocity determines the speed of an object as it moves along the circular path.
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Find the area of a parallelogram defined by the vector A(6,3,1)m and B(-2,4,5)
The area of the parallelogram is 40.60m^2.
What is the area of the parallelogram?Generally, To find the area of a parallelogram defined by two vectors, we can use the formula
A = |A x B|,
where
A and B are the two vectors.
A x B = (3*5 - 4*1, 6*5 - (-2)*1, 6*4 - (-2)*3)
= (17, 28, 24)
|A x B| = √(17² + 28² + 24²)
= 40.60m2
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Electric field lines always begin at _______ charges (or at infinity) and end at _______ charges (or at infinity). One could also say that the lines we use to represent an electric field indicate the direction in which a _______ test charge would initially move when released from rest. Which of the following fills in the three missing words correctly?
Electric field lines always begin at positive charges (or at infinity) and end at negative charges (or at infinity). One could also say that the lines we use to represent an electric field indicate the direction in which a positive test charge would initially move when released from rest.
The field lines show us the motion of a positive test charge on one of those field lines. As a result, the field lines point in the direction of negative charges and away from positive charges. Instead, we may state that what we need is information about the movement of negative test charges from the field lines. Then the arrows would turn around, and someone would innocently inquire about the exact opposite.
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What did each of the boys add to the success of the science fair win? Would Homer have been able to full-fill his dream without each of his friends or others? - October Sky
Three equal charges are placed at three corners of the square of side length d. If q 4.0 nC and d= 4.0 m, what is the electric potential at the origin ?
The electric potential at the origin is 1.079 x 10^5 V.
What is electric potential?Electric potential is a measure of the electric potential energy per unit charge in an electric field.
The electric potential at the origin can be calculated using Coulomb's law and the principle of superposition. The electric potential at a point due to a single charge is given by:
V = k * q / r
where
k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2)q is the charge r is the distance from the point to the chargeThe total electric potential at the origin due to all three charges is the sum of the potentials due to each charge.
Assuming the charges are all positive, the electric potential at the origin is:
V = k * q * (1/d + 1/√(2d^2) + 1/d)
Plugging in the values, we get:
V = 8.99 x 10^9 Nm^2/C^2 * 4.0 x 10^-9 C * (1/4.0 + 1/2 * 4.0 + 1/4.0) = 1.079 x 10^5 V.
Therefore, The electric potential at the origin is 1.079 x 10^5 V.
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A 6. 96-nc charge is located 1. 90 m from a 3. 86-nc point charge. Find the magnitude of the electrostatic force that one charge exerts on the other.
The required electrostatic force when the charges and distance are specified is calculated to be 66.98 × 10⁻⁹ N.
The charge q₁ is given as 6.96 nC.
The charge q₂ is given as 3.86 nC.
Distance r = 1.9 m
The magnitude of the electrostatic force that one charge exerts on the other is to be found out. The force between two charges at a distance is given by the formula,
F = k q₁ q₂/r² = (9 × 10⁹ × 6.96 × 10⁻⁹ × 3.86× 10⁻⁹)/1.9² = 66.98 × 10⁻⁹ N
Thus, the required electrostatic force is calculated to be 66.98 × 10⁻⁹ N.
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Rigid rods of negligible mass lying along the y axis connected three particles. The system rotates about the x axis with an angular speed of 2.00 rad/s. Find the total rotational kinetic energy evaluated from 1/2 Iω ^2
The total rotational kinetic energy of the system can be found by evaluating the above expression using the given values of m, r, and ω [tex]KE = 1/2 * (m1 * r1^2 + m2 * r2^2 + m3 * r3^2) * (2.00 rad/s)^2[/tex]
The total rotational kinetic energy of a system can be found by evaluating the expression 1/2 Iω^2, where I is the moment of inertia of the system and ω is its angular velocity. In this case, the moment of inertia of the system can be found by adding the moments of inertia of each particle and the connecting rods.
Since the rods have negligible mass, their moment of inertia is also negligible and can be ignored. The moment of inertia of each particle is given by the formula:
I = mr^2
where m is the mass of the particle and r is its distance from the axis of rotation.
Assuming the particles have masses m1, m2, and m3 and distances from the axis of rotation r1, r2, and r3, respectively, the total moment of inertia is:
[tex]I = m1 * r1^2 + m2 * r2^2 + m3 * r3^2[/tex]
Substituting the given values, we find:
I = (m1 * r1^2 + m2 * r2^2 + m3 * r3^2)
Finally, substituting the moment of inertia and angular velocity into the expression for rotational kinetic energy, we find:
KE = 1/2 * I * ω^2
[tex]KE = 1/2 * (m1 * r1^2 + m2 * r2^2 + m3 * r3^2) * (2.00 rad/s)^2[/tex]
So, the total rotational kinetic energy of the system can be found by evaluating the above expression using the given values of m, r, and ω.
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EXPERIMEXPERIMENT: SIMPLE MACHINES When we think of a machine, car engines, cranes, lifts, power drills, and vacuum cleaners usually come to mind. These devices are complex machines. Simple machines are the wedge, inclined plane, screw (an inclined plane wrapped on an axle), pulley, and lever. The jack used to lift a car is an example of a simple machine; it is simply a lever. In this investigation you will use a lever as a simple machine, and calculate its mechanical advantage and efficiency. Here are your goals for this lesson: Make quantitative observations and measurements with precision Analyze, evaluate and predict patterns from data Communicate findings These supplies are needed: meter stick string weights Play Mute Remaining TimeÂ-1:08 Picture-in-Picture Follow these directions and complete the activities. 1. Suspend the meter stick by a string from its center. 2. Notice carefully where it balances. It probably will not balance exactly at 50 cm. All distances must be measured to this point (called the fulcrum). 3. Hang a 200 g mass on one side and a 50 g mass on the other and adjust the distances from the fulcrum until the meter stick balances.(Be sure to account for the mass of the hanger from which you are suspending the masses. This can either be part of the total mass or, alternatively, if you are using something like coffee cups to hold the masses, their masses need to be matched perfectly before starting the experiment. You can do this by first checking to see how close they com
Answer:
This a practical that you have to do. Not to us.
Explanation:
EXPERIMEXPERIMENT: SIMPLE MACHINES When we think of a machine, car engines, cranes, lifts, power drills, and vacuum cleaners usually come to mind. These devices are complex machines. Simple machines are the wedge, inclined plane, screw (an inclined plane wrapped on an axle), pulley, and lever. The jack used to lift a car is an example of a simple machine; it is simply a lever. In this investigation you will use a lever as a simple machine, and calculate its mechanical advantage and efficiency. Here are your goals for this lesson: Make quantitative observations and measurements with precision Analyze, evaluate and predict patterns from data Communicate findings These supplies are needed: meter stick string weights Play Mute Remaining TimeÂ-1:08 Picture-in-Picture Follow these directions and complete the activities. 1. Suspend the meter stick by a string from its center. 2. Notice carefully where it balances. It probably will not balance exactly at 50 cm. All distances must be measured to this point (called the fulcrum). 3. Hang a 200 g mass on one side and a 50 g mass on the other and adjust the distances from the fulcrum until the meter stick balances.(Be sure to account for the mass of the hanger from which you are suspending the masses. This can either be part of the total mass or, alternatively, if you are using something like coffee cups to hold the masses, their masses need to be matched perfectly before starting the experiment. You can do this by first checking to see how close they com
For the following questions consider the electric field and forces produced by a pair of charged particles that are held at fixed positions on the x-axis at x= +d and x=−d.
The charge at +d is positive q and the one at−d is negative q. A third positive charge of q is placed at y= 10d. What is the approximate magnitude of the force on this third charge?
The correct option is E. The magnitude and direction of the force on this third charge [tex]2kq^2/d[/tex]; the positive x-direction.
An electric area (now and again E-discipline) is the bodily field that surrounds electrically charged particles and exerts force on all other charged debris in the subject, either attracting or repelling them. It also refers to the physical discipline for a system of charged debris. electric powered fields originate from electric expenses and time-varying electric powered currents. electric powered fields and magnetic fields are both manifestations of the electromagnetic discipline, one of the four fundamental interactions (also called forces) of nature.
Electric fields are critical in lots of regions of physics and are exploited in electrical technology. In atomic physics and chemistry, for instance, the electric field is the attractive pressure protecting the atomic nucleus and electrons together in atoms. it is also the pressure accountable for chemical bonding among atoms that bring about molecules. the electrical discipline is defined as a vector area that friends to each factor in space the electrostatic (Coulomb) force in keeping with unit of fee exerted on a tiny tremendous check rate at relaxation at that factor.
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Complete Question:
For the following question, consider the electric field and forces produced by a pair of charged particles held at fixed positions on the x-axis at x= +d and x=−d.
The charge at +d is positive q and the one at −d is negative q. A third negative charge of −q is placed at the origin. What is the magnitude and direction of the force on this third charge?
A). [tex]2kq^2/d^2[/tex]; the negative direction
B).[tex]2kq^2/d[/tex]; the positive x-direction
C). [tex]2kq^2/d[/tex]; the negative direction
D). [tex]2kq/d^2[/tex]; the positive x-direction
E).[tex]2kq^2/d[/tex]; the positive x-direction
F). [tex]2kq/d^2[/tex]; the negative x-direction
An 85 L flexible container holds 3.4 moles of gas. How many moles of gas should be removed to decrease the volume of the container to 40 L?
1.8 moles of gas should be removed to decrease the volume of the container to 40 L
What is Avogadro's law?Avogadro's Law states that the volume of a gas is directly proportional to the number of moles (or a number of particles) of gas when the temperature and pressure are held constant.
Given, An 85 L flexible container holds 3.4 moles of gas.
This problem requires Avogadro's law, which states that the amount (moles) of a gas is directly proportional to its volume, such that if the amount increases, the volume increases and vice versa. You correctly determined the formula to use:
V = k×n or. V₁n₁=V₂n₂.
Let "x" be the number of moles in a 40l container
85/40 = x/3.4
Thus,
x = 1.8
Therefore, 1.8 moles of gas should be removed to decrease the volume of the container to 40 L
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What is the potential energy of a 5.0 kg object located 3 m above the ground?
Answer:
147 J
Explanation:
PE = mgh = (5.0 kg)(9.8 m/s²)(3 m) = 147 J
Unscramble the terms in italics to complete the sentences below. Write the terms on the lines provided. 5. In dry regions where sheep and cattle eat the grasses, reggianvorz increases soil erosion.
The term which describes the increased soil erosion in the regions where sheep and cattle eat the grasses and reggianvorz is called overgrazing.
What is overgrazing ?Overgrazing happens when livestock and other grazers (such as wildlife) consume more plant biomass than the vegetation can replenish in a reasonable amount of time, exposing the soil and lowering the vegetation's potential for production.
The exposure of the soil might hasten the potential for processes of water and wind erosion, which can result in soil losses. Less water infiltration into the soil might result in slower plant growth due to accelerated erosion processes and soil compaction caused by grazing animals.
Because less plant biomass is accessible as litter due to ongoing overgrazing, less soil organic matter, nutrients, and biotic activity are added to the soil. This causes the soil structure to deteriorate, which lowers the soil's capacity to store water and raises the risk of erosion.
Therefore, the term describing the given action is overgrazing.
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How much work must we do on an electron to move it from point A, which is at a potential of +50V, to point B, which is at a potential of -50V, along the semicircular path shown in the figure? Assume the system is isolated from outside forces
[tex]1.602 x 10^-17[/tex] is the work must we do on an electron to move it from point A, , to point B, that is at a potential of -50V, along the semicircular path.
What is electron?In order to move the electron from point A to point B, we need to do work on it to overcome the electric potential difference between the two points. Since the two points have potentials of +50V and -50V respectively, the total potential difference is 100V.
Since the electric field is conservative, the work done by it depends only on the potential difference between points A and B and not on the path taken. The potential difference between points A and B is given by:
ΔV = V_B - V_A = -50 V - (+50 V) = -100 V
To move an electron from point A to point B, we need to do work on it equal to the change in its potential energy. The potential energy of an electron in an electric field is given by:
U = qΔV
where q is the charge of the electron, and ΔV is the potential difference.
The charge of an electron is:
q = -1.6 x [tex]10^{-19 }[/tex]C
Substituting the values, we get:
U = (-1.6 x [tex]10^{-19 }[/tex] C) x (-100 V)
U = 1.6 x [tex]10^{-19 }[/tex]
Therefore, we need to do work on the electron equal to 1.6 x 10^-17 J to move it from point A to point B along the given semicircular path.
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A skier starts down a 10 degree incline at 2 m/s, reaching a speed of 15m/s at the bottom. What is the length of the incline?
How long does it take the skier to reach the bottom.
The length of the incline is 65 meter.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Initial speed is = 2 m/s
Final speed is = 15 m/s
Acceleration of the skier is = gsin10° = 9.8 × sin10° m/s² = 1.7 m/s
Let the length of the incline is l
Hence,
15² = 2² + 2×1.7×s
s = 65
Hence, the length of the incline is 65 meter.
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Which of the following is an advantage that electronic brainstorming has over traditional brainstorming?It prevents participants from all answering at once.Cost effectiveIt allows participants to answer anonymously.It allows only one person to talk at a time.It encourages "social loafing".
An advantage that electronic brainstorming has over traditional brainstorming: Option. It allows participants to answer anonymously.
Electronic brainstorming provides anonymity, allowing participants to contribute freely without fear of judgement.
Electronic brainstorming provides a unique advantage over traditional brainstorming in that it allows participants to answer anonymously. This means that participants can contribute freely without the fear of judgement or criticism from others.
This allows more honest and open dialogue, as participants can express their ideas without the worry of being judged or having their ideas dismissed.
Additionally, electronic brainstorming is usually more cost-effective, as there is no need to arrange a physical meeting space or provide food and beverages. This makes it an ideal choice for those looking to brainstorm without the hassle or cost of traditional brainstorming.
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A wheel turning 4.50 rad/s
experiences an angular
acceleration of -0.822 rad/s^2.
What is its angular velocity
after 12.0 s?
angular velocity after 12.0 s = 4.50 rad/s - (0.822 rad/s^2 * 12.0s)
angular velocity after 12.0 s = 2.052 rad/s
What is angular velocity?
Angular velocity is a measure of the angular displacement over time of a rotating object. It is expressed as the rate of change of angular displacement with respect to time, and is usually expressed in radians per second or revolutions per minute. Angular velocity is considered to be a vector quantity, meaning it has magnitude and direction. It is also a measure of the speed at which an object is rotating. When an object is rotating in a circular motion, its angular velocity is the same as its tangential velocity. Angular velocity can also be used to calculate the linear velocity of an object, by multiplying its angular velocity by the radius of its circular path.
Therefore, angular velocity after 12.0 s = 2.052 rad/s
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Answer: -5.36
Explanation:
ik this can help you now but i was doing this problem and figured id leave this here lolz
convert the displacement amplitude, 2.58 mils peak-to-peak at 900 CPM to the equivalent velocity amplitude in inches per second-peak?
According to the problem the Velocity amplitude (in/s-peak) is 1.827 in/s-peak.
What is Velocity amplitude?Velocity amplitude is the maximum speed at which a particle or object is traveling in a specific direction. It is a measure of the strength of the motion expressed in terms of the magnitude of the velocity. It can be determined by measuring the maximum value of the velocity vector over a given period of time. Velocity amplitude is an important concept in physics, as it allows for the calculation of the acceleration, momentum, and energy of a particle or object. It can also be used to determine the frequency of a periodic motion, such as the frequency of a wave or the frequency of oscillation.
The equation for converting displacement amplitude to velocity amplitude is:
Velocity amplitude (in/s-peak) = (2 x Displacement amplitude (mils-p-p)) / (π x Frequency (cpm))
Therefore, the velocity amplitude in inches per second-peak for a displacement amplitude of 2.58 mils peak-to-peak at 900 CPM is:
Velocity amplitude (in/s-peak) = (2 x 2.58 mils-p-p) / (π x 900 cpm)
Velocity amplitude (in/s-peak) = (5.16 mils-p-p) / (2,827.43 cpm)
Velocity amplitude (in/s-peak) = 1.827 in/s-peak
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A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were initially compressed by the same amount. Which of the following statements about these darts are correct?
The statement which is correct about the lighter dart leaves the spring moving faster than the heavy dart. Option B is correct.
This is because both darts are launched with the same initial elastic potential energy from the compressed springs, but the lighter dart has less mass than the heavier dart. According to the law of conservation of energy, the lighter dart must move faster than the heavier dart in order to have the same amount of kinetic energy as the heavier dart once it leaves the spring.
The initial potential energy is the same for both darts, and since the potential energy is converted to kinetic energy, the lighter dart must have a higher velocity than the heavier dart in order to have the same amount of kinetic energy.
Therefore, option B is correct, while options A, C, D, and E are not, as they do not accurately describe the behavior of the darts in this scenario.
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--The complete question is, A heavy dart and a light dart are launched horizontally on a frictionless table by identical ideal springs. Both springs were initially compressed by the same amount. Which of the following statements about these darts are correct?
A) The darts both have the same kinetic energy just as they move free of the spring.
B) The lighter dart leaves the spring moving faster than the heavy dart.
C) The heavy dart had more initial elastic potential energy than the light dart.
D) Both darts move free of the spring with the same speed. E) Both darts had the same initial elastic potential energy.--
a metal having a cubic structure has a density of 19.302 g/cm 3 an atomic weight of 196.97 g/mol and a lattice paramater of 4,0786 a one atom is associated with each lattice point determine the crystal structure of the metal
The metal's crystal structure is FCC.
Finding a metal's density to atomic weight ratio and lattice parameter value will reveal the metal's crystal structure. The ratio of density to atomic weight is about equivalent to the quantity of atoms per unit cell in the crystal structure if the metal has a density of 19.302 g/cm3 and an atomic weight of 196.97 g/mol.
One atom per lattice point in a cubic structure with a lattice parameter of 4.0786 corresponds to a simple cubic (SC), body-centered cubic (BCC), or face-centered cubic (FCC) structure. The lattice parameter and density to atomic weight ratio are most consistent with an FCC crystal structure.
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The equation of a wave traveling in a horizontal direction is expressed as y - 5sin(60t - x)
What's the phase angle
(a)90° (b)180° (c)270° (d)360° (e)0°
what's the wave number?
(a) 2m-¹ (b) 3.142m (c) 1m (d) 0.2m (e) non of the above
Basic function of a wave is given as, [tex]y(x,t)=Asin(kx\pm wt \pm $\Phi$)[/tex]. Where
"A" is amplitude, "k" is the wave number, "w" is angular frequency, and "Ф" is the phase angle.
Based off the given wave function, [tex]y(x,t)=5sin(60t - x)[/tex], we can say that the phase angle is 0° and the wave number is 1 m.
Someone tries to tell you that a freezer cools food by transferring cold to the particles in the food. (has to be 1 sentence)
How would you respond? Construct an argument.
am in 8th grade
pls explain as well bc I’m like rlly slow
Freezing keeps food safe by slowing the movement of molecules, causing microbes to enter a dormant stage. Freezing preserves food for extended periods because it prevents the growth of microorganisms that cause both food spoilage and foodborne illness.
What is freezing food?
Food is preserved when frozen, keeping it fresh from preparation until consumption.Farmers, fishers, and trappers have traditionally stored their produce and grains over the winter months in unheated structures.By turning any remaining moisture in food into ice, freezing it slows the breakdown process and prevents the majority of bacterial species from proliferating.Mechanical and cryogenic techniques are used in the food commodities industry (or flash freezing).To maintain the food's flavour and texture, freezing kinetics is crucial. Smaller ice crystals are produced more quickly, preserving cellular structure.To know more about the freezing food, click the link given below:
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the conductor offers some amount of ohmic resistance to the flow of electrons, depending on the type of material from which the conductor is made, its length, and its .
Depending on the type of material used, the length, and other factors, the conductor provides some ohmic resistance to the flow of electrons.
Because electrons in a conducting wire reject one another, a conducting wire provides resistance to the flow of electrons. The electrolyte resistance, the current collector resistance, the active mass, and the transition resistance between the current collector and active mass are added to create the ohmic resistance, or RB.
Theoretically, in accordance with Ohm's rule, the voltage at the ohmic resistance instantly follows the battery current. A substance or material that permits the flow of electricity is known as an electrical conductor. Electrical charge carriers, often electrons or ions, flow freely in a conductor.
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Contingent upon the sort of material utilized, the length, and different variables, the guide gives ohmic protection from the progression of electrons.
Since electrons in a directing wire reject each other, a leading wire gives protection from the progression of electrons. The electrolyte obstruction, the ongoing authority opposition, the dynamic mass, and the progress obstruction between the ongoing gatherer and dynamic mass are added to make the ohmic obstruction or RB.
Hypothetically, as per Ohm's standard, the voltage at the ohmic obstruction in a split second follows the battery current. A substance or material that allows the progression of power is known as an electrical transmitter. Electrical charge transporters, frequently electrons or particles, stream uninhibitedly in a transmitter.
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