The energy dissipated by friction is approximately 15,840 J.
The energy dissipated by friction can be calculated as the difference between the initial potential energy and the final kinetic energy.
The initial potential energy can be calculated using the formula:
PE_initial = mgh
where m is the mass of the skier, g is the acceleration due to gravity, and h is the height difference from the top to the bottom of the trail.
The final kinetic energy can be calculated using the formula:
KE_final = 0.5m[tex]v^{2}[/tex]
where v is the final velocity of the skier at the bottom of the trail.
Subtracting the final kinetic energy from the initial potential energy gives the energy dissipated by friction:
E_dissipated = PE_initial - KE_final
Using the given values, the energy dissipated by friction can be calculated as approximately:
E_dissipated = (66 kg)×(9.8 m/[tex]s^{2}[/tex])×(240 m) - 0.5×(66 kg)×[tex](11 m/s)^{2}[/tex] = 15,840 J.
Therefore, the energy dissipated by friction is approximately 15,840 J.
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URGENT
In a dry desert environment, the climate will typically show wide temperature swings on a daily basis, from very cold to very hot. Florida typically has much smaller temperature swings. What causes that difference?
Group of answer choices
The lower altitude of Florida
The water surrounding Florida
Increased sunshine in Florida
The shorter daylight period in the desert
Florida typically has a much smaller temperature swing than a dry desert environment, where the climate will typically show wide temperature swings on a daily basis, from very cold to very hot because of the water surrounding Florida.
The correct option is B.
What are the waters surrounding Florida?The State of Florida is a peninsula, which means it is surrounded on three sides by water: the Gulf of Mexico, the Atlantic Ocean, and the Straits of Florida.
Hence, because of the waters surrounding Florida, it has fewer temperature swings.
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A bus is initially traveling north at a constant speed, as shown in the figure above. As the bus starts to make a left turn without changing speed, a passenger notices that a box on the floor starts sliding toward the right side of the bus. Which of the following top views of the box, when correctly labeled, would best represent all of the horizontal forces exerted on the box as it starts sliding?
Assuming that the box is not sliding off the bus, the forces exerted on it can be represented by the following diagram:
F
F: friction force
The friction force, represented by F in the diagram, acts in the opposite direction of the box's sliding motion. This force is caused by the friction between the box and the bus floor, and it is the only force present in the system. As the bus turns to the left, the box's sliding motion is directed to the right. The direction of the friction force then changes to the left, opposing the motion of the box and slowing it down until it stops.
A ball is thrown from a roof top at an angle of 45° above the horizontal. It hits the ground a few seconds later. At what point during its motion, does the ball have (a) greatest speed. (b) smallest speed. (c) greatest acceleration? Explain
Answer:
Explanation:
WHEN WE PROJECT A BALL FROM THE ROOFTOP, THE BALL travels down and the ball have greatest speed at the moment strike on the earth. ball have smallest speed at the moment of release.. the acceleration is constant.
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(ii) a person scuffing her feet on a wool rug on a dry day accumulates a net charge of -34 mc. how many excess electrons does she get, and by how much does her mass increase?
The person gets 34 million excess electrons but her mass does not increase.
What is the mass ?Mass is a measure of the amount of matter in an object. It is typically measured in kilograms (kg), though other units like grams (g) and pounds (lbs) are also used. Mass is different from weight, which is a measure of the force of gravity on an object. Mass is constant in all gravitational fields, while weight changes depending on the strength of the gravitational field.
The person scuffing her feet on the wool rug is accumulating a net charge of -34 mc (microcoulombs). This means that she is gaining 34 million electrons. However, this does not increase her mass, since electrons have a very small mass compared to the overall mass of a person.
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Explain why sound waves are mechanical waves rather than electromagnetic waves.
Explanation:
Sound is a mechanical wave. Electromagnetic wave is a by-product of both electric and magnetic fields. It does not require the presence of any medium and can travel through a vacuum. In comparison, mechanical waves require the presence of a medium. It works by pushing the medium's molecules and traveling through it. Sound works this way.
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Your Best,EdwinAn iron rail is 20cm² in area. how much will it expand when heated from 100∅ to 50∅
Answer:
0.024
Explanation:
no expansivity ok but I can do it
linear expansivity=1.2*10^-5
=2a
=2*1.2*20^-5
=2.4*10^-5
∆A =?
A1 =20
2.4*10^-5 =∆A/A1(100-50)
∆A =2.4*10^-5*1000
=0.024
a baseball is thrown straight up at a speed of 30.0 m/s. at what time will the ball be at a height of 25.0 m?
Answer:
t = 0.995 s, 5.127 s
Explanation:
Δx = v₀t + 1/2at²
25.0 m = (30 m/s)t + 1/2(-9.8 m/s²)t²
-4.9t² + 30t - 25 = 0 solve this quadratic equation for t (2 solutions)
t = 0.995 s, 5.127 s
It reaches a height of 25 m in 0.995 s, then again 5.127 s later on its way back down
3) an electric wagon changes its speed at the average rate of 11.2 m/s2. how much time does it take to increase its speed from 79.4 m/s to 119.5 m/s?
To calculate the time required to increase the speed of an electric wagon from 79.4 m/s to 119.5 m/s at an average rate of 11.2 m/s2, you can use the following equation:
Time = (119.5 - 79.4) / 11.2This gives a result of 4.03 seconds.
When the electric wagon is accelerating, the driver should be mindful of the acceleration rate to ensure that the vehicle is accelerated safely. If an excessive rate of acceleration is used, the vehicle may end up going too fast and this could be dangerous. Therefore, it is important to be aware of the acceleration rate and to keep an eye on the speedometer to ensure that it does not exceed the desired speed.
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on a two-lane highway (not divided), a car headed north experiences a centripetal acceleration directed toward the east. simultaneously, a truck passes the car, headed south in the other lane. the direction of the centripetal acceleration on the truck is
The direction of the centripetal acceleration on the truck is toward the west is zero.
Find the acceleration of the truck?Centripetal acceleration is always towards the center of circular motion. In this case, a car traveling north on a two-lane highway is experiencing eastward centripetal acceleration. This indicates that the car is turning east.
At the same time, a truck overtakes a southbound vehicle in the opposite lane. The track does not turn east, so there is no eastward centripetal acceleration. Since the truck is only moving in a straight line, the centripetal acceleration is zero.
Therefore, the direction of centripetal acceleration of the track is zero.
What is the acceleration ?Acceleration is defined as the rate of change of velocity. It is a vector quantity, meaning that it has both magnitude and direction. In physics, acceleration is most commonly defined as the rate of change of velocity divided by the time interval over which the change occurs. Acceleration is typically measured in meters per second squared (m/s2). Acceleration can also be defined as the rate of change of momentum over a given time interval.
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Two friends meet up at the ice skating rink. They skate up to each other and come to a stop. Then they push off each other, moving in opposite directions. If the first friend has a mass of 50 kg and goes forward at 3 m/s, then what speed does the other 75kg friend go back at? [Explosion]
Answer:
yes becomes two friends are the same
When that two friend are coming in opposite direction after explosion a friend having having 75kg mass will go back at 2 m/s speed.
What is momentum ?Momentum is defined as mass times velocity of body. it is denoted by p and its SI unit is Kg.m/s. It has both magnitude and direction. it is a vector quantity. it tells about the moment of the body. it is denoted by p and expressed in kg.m/s. mathematically it is written as p = mv. A body having zero velocity or zero mass has zero momentum. its dimensions is [M¹ L¹ T⁻¹].
Momentum is conserved throughout the motion.
initial momentum = final momentum
Given,
mass of first friend m₁ = 50kg
velocity of first friend v₁ = 3m/s
mass of second friend m₂ = 75kg
velocity of second friend v₂ = ?
According to conservation of momentum,
m₁v₁ = m₂v₂
50×3 = 75×v₂
v₂ = 150 ÷ 75
v₂ = 2 m/s
Hence second friend will go back at 2m/s.
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7. Determine what happens to the wavelength when the
waves change between the following parts of the
electromagnetic spectrum.
Infrared to Radio waves:
Radio waves to Microwaves:
Ultraviolet to gamma rays:
Gamma rays to X-rays:
Infrared to Ultraviolet:
Yellow to blue:
Green to orange:
Infrared to red:
Ultraviolet to violet:
At the point when waves change starting with one medium then onto the next, the frequency of the wave changes relying upon the properties of the two mediums.
What befalls the frequency when the waves change between the accompanying pieces of the electromagnetic range?Infrared to Radio waves: Frequency increments
Radio waves to Microwaves: Frequency diminishes
Bright to Gamma beams: Frequency diminishes
Gamma beams to X-beams: Frequency diminishes
Infrared to Bright: Frequency diminishes
Yellow to blue: Frequency diminishes
Green to orange: Frequency increments
Infrared to red: Frequency increments
Bright to violet: Frequency diminishes
At the point when waves change starting with one medium then onto the next, the frequency might change relying upon the refractive lists of the two media.
Assuming the refractive list of the subsequent medium is more noteworthy than the first, then, at that point, the frequency will diminish. In the event that the refractive record of the subsequent medium is lower than the first, then, at that point, the frequency will increment.
The electromagnetic spectrum is what?The spectrum of all EM radiation is known as the electromagnetic (EM) spectrum. The visible light from your house's lamp and the radio waves from a radio station are both examples of electromagnetic radiation, which is energy that moves and spreads out.
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consider two identical spherical balls submerged in water at different depths. will the buoyant forces acting on the two balls be the same or different? why?
The buoyant forces acting on the two balls will be the sam. This is because buoyant force is determined by the volume of the object and not the depth at which it is submerged.
The buoyant force is the same for any object of the same volume regardless of the depth.
The buoyant force is an upward force exerted on a submerged object by the surrounding liquid. The magnitude of this force is equal to the weight of the liquid displaced by the object. This force is commonly used to explain why objects float in water.
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as part of an exercise program, a woman walks south at a speed of 2.00 m/s for 60.0 minutes. she then turns around and walks north a distance 3000 m in 30.0 minutes. what is the woman's average velocity during her entire motion?
The woman's average velocity during her entire motion is 0.823m/s.
Distance traveled in the south = 60×60×2= 7200m
Distance traveled in the North = 3000m
Net Displacement = 7200-3000= 4200m
Average velocity= Net Displacement /Time = 4200m / (60+25)×60= 0.823m/s.
The pace is the directional speed of an item in motion as a demonstration of its price of alternate in the role as observed from a specific body of reference and as measured via a particular widespread of time (e.g. 60 km/h northbound). speed is a fundamental concept in kinematics, the branch of classical mechanics that describes the motion of our bodies.
Velocity is a bodily vector amount; each significance and route are needed to define it. The scalar absolute value (significance) of speed is known as velocity, being a coherent derived unit whose quantity is measured inside the SI (metric device) as meters in step with second (m/s or m⋅s−1). as an example, "5 meters in step with 2d" is a scalar, whereas "5 meters consistent with 2nd east" is a vector. If there is a trade-in velocity, route, or each, then the object is stated to be present process an acceleration.
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What are the byproducts of nuclear energy and what are the options for disposing of the waste?
Nuclear energy production generates several byproducts, including spent nuclear fuel and high-level radioactive waste. These byproducts pose a significant challenge for safe disposal and management.
There are several options for disposing of nuclear waste, including:
Deep geological disposal: This involves burying the waste in deep geological formations, such as salt mines or clay deposits, where it will be isolated from the biosphere for a very long time.
Reprocessing: This involves separating reusable materials from spent nuclear fuel, with the remaining waste being further processed and prepared for disposal.
Interim storage: This involves temporarily storing waste in secure facilities until a permanent disposal solution can be found.
Ocean dumping: This involves disposing of waste in the deep ocean, which is currently banned under international agreements.
The most widely accepted method of disposing of high-level radioactive waste is deep geological disposal. However, the implementation of this method requires significant investment, public acceptance, and technical expertise, and is currently only being carried out in a few countries. As the amount of nuclear waste continues to grow, it is important for countries to develop safe and sustainable disposal solutions to protect human health and the environment.
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103) if the collision is elastic and the final speed of object b is 5.0 m/s, what is the final velocity of object a?
The final velocity of object A is equal to the final velocity of object B, which is 5.0 m/s.
If the collision between objects A and B is elastic, then both momentum and kinetic energy are conserved.
Let the initial velocity of object A be [tex]v_A[/tex] and the initial velocity of object B be [tex]v_B[/tex]. The mass of object A is and the mass of object B is [tex]m_B[/tex].
Conservation of momentum:
[tex]m_A v_A + m_B v_B = m_A v' + m_B v'[/tex]
where v' is the final velocity of both objects.
Conservation of kinetic energy:
[tex]\dfrac{1}{2} m_A v_A^2 + \dfrac{1}{2} m_B v_B^2 = \dfrac{1}{2} m_A v'^2 + \dfrac{1}{2} m_B v'^2[/tex]
Substituting v' in terms of [tex]v_A[/tex] and [tex]v_B[/tex] using the momentum conservation equation,
[tex]v_A = \dfrac{m_A - m_B}{m_A + m_B}v_B + \dfrac{2m_B}{m_A + m_B}v_B[/tex]
[tex]v_A = \dfrac{(m_A - m_B + 2m_B)v_B}{m_A + m_B}[/tex]
[tex]v_A = \dfrac{(m_A + m_B)v_B}{m_A + m_B}\\= v_B[/tex]
Therefore, the final velocity of object A is equal to the final velocity of object B.
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a ping-pong ball of mass m rolls off the edge of a table that is 1.0 m high. when the ball strikes the floor its speed is5.0 m/s. how fast was it rolling when it left the table.
The ball was rolling at a speed of 4.44 m/s when it left the table.
What is speed?
Speed is a scalar quantity that describes the magnitude of an object's velocity, or the rate at which an object is moving. It is defined as the distance traveled by an object divided by the time it takes to travel that distance. The unit of speed is usually meters per second (m/s) or kilometers per hour (km/h).
We can use the conservation of energy principle to solve this problem. The initial potential energy of the ball when it was at the edge of the table is equal to its weight multiplied by its height above the floor:
PEi = mgh
PEi = m * 9.8 m/s² * 1.0 m = 9.8 N * m
At the moment the ball strikes the floor, all of its potential energy has been converted into kinetic energy:
KEf = 1/2 * m * v²
where v is the velocity of the ball just before it strikes the floor. We can equate the initial potential energy to the final kinetic energy and solve for the velocity of the ball when it left the table:
PEi = KEf
9.8 N * m = 1/2 * m * v²
v²= 2 * PEi / m = 2 * 9.8 N * m / m = 19.6 m²/s²
v = √(v²) = √(19.6 m²/s²) = 4.44 m/s
So, the ball was rolling at a speed of 4.44 m/s when it left the table.
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the timer was set for 40 hz in this experiment and it produced a spot on the tape every 25 ms. if you set the timer to 10 hz, what would be the elapsed time between spots?
The required elapsed time between spots when frequency and time for an experiment is specified is calculated to be 100 ms.
We know the relation between frequency and time as,
f = 1/T
where,
f is frequency
T is time period
It is given that f₁ = 40 hz
Time T₁ = 25 ms
If the timer is set to f₂ = 10 hz, time T₂ = ?
From the above relation, the equation can be written as,
f₁ T₁ = f₂ T₂
T₂ = f₁ T₁/f₂ = 40(25)/10 = 100 ms
Thus, the elapsed time between spots is calculated to be 100 ms.
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a projectile is fired in such a way that its horizontal range is equal to 8.5 times its maximum height. what is the angle of projection?
The angle of projection is 25.2°. The result is obtained by using the formula for maximum height and horizontal range of projectile motion.
What is maximum height and horizontal range of projectile motion?The maximum height can be reached by a projectile motion is
H = (v₀²sin²θ)/2g
Where
H = maximum heightv₀ = initial velocityθ = angle of projectiong = acceleration due to gravityMeanwhile, the horizontal range can be reached is
R = (v₀² sin 2θ)/g
A projectile is fired. The horizontal range is equal to 8.5 times the maximum height. Find the angle of projection!
In this case, we get
R = 8.5 H
(v₀² sin 2θ)/g = 8.5 × (v₀²sin²θ)/2g
2(sin 2θ) = 8.5 × (sin²θ)
2(sin 2θ) = 8.5(sin²θ)
2/8.5 = (sin²θ)/(sin 2θ)
0.235 = (tan θ)/2
tan θ = 0.47
θ = arc tan 0.47
θ = 25.2°
Hence, the projectile motion has the angle of 25.2°.
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200g of water at 90 degree celsius is mixed with 100g of water at 30 degree celsius. What is the temperature
Answer:
For temperatures between the freezing and boiling point of water, the heating curve is linear. Thus, we can use:
((200 * 90) + (100* 30))/300
Or: ((200 * 90)(temperature of first sample weighted by mass) + (100 * 30)(temperature of second sample weighted by mass) / (300)(total mass)
to find the final temperature.
100 can be factored out to get (2 * 90) + (1 * 30)) / 3
3 can be factored out every term: (2 * 30) + (1 * 10)
(The factoring out just makes mental math easier; if a calculator is available doing so is unnecessary.)
And then just work through the order of operations.
60 + 10
=70.
So in mathematics, which assumes a perfect world, you get 70.
what two stars alternate every 13,000 years as earth’s northern star?
Every 13,000 years, Polaris and Vega switch places as the North Star. Today, Polaris, the brightest star in the constellation Ursa Minor, lies within one degree of the Earth's axis.
What northern star was Earth's before Polaris?Currently, Polaris is practically exactly where the Earth's rotation axis points. However, the North Star in the year 3000 BCE was a star called Thuban (also known as Alpha Draconis), and due to the precession of the rotation axis, the bright star Vega will become the North Star in roughly 13,000 years.
Polaris became the North Star at what point?The North Star around 3000 BC was a slender star called Thuban in the constellation of Draco. The North Star did not replace Polaris.
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examine the sketch of a bend in a river. the arrows show the water flow direction. in which of the four lettered locations will the water be moving at the highest velocity?
The river speed is maximum at point A. Option A is the correct answer.
The speed of a river on a circular turn is maximum at the outer part of the curve. This is because the water flowing in the river has to travel a greater distance on the outer curve as compared to the inner curve. Therefore, to cover the same distance in the same amount of time, the speed of the water has to be greater on the outer curve.
This is known as the principle of conservation of angular momentum, which states that the angular momentum of the water flowing in the river is conserved as it moves around the curve.
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--The complete question is, Examine the sketch of a bend in a river. The arrows show the water flow direction. In which of the four lettered locations will the water be moving at the highest velocity?
A) A
B) B
C) C
D) D--
A 8 kg Ice skater is moving at 5 m/s and is headed towards a stationary 2 kg snowman. After the two collide, the ice skater has 0 m/s of velocity and the snowman moves forward. What is the velocity of the snowman?
Answer:
[tex]20\; {\rm m\cdot s^{-1}}[/tex], assuming that friction is negligible.
Explanation:
If an object of mass [tex]m[/tex] moves at a velocity of [tex]v[/tex], the momentum [tex]p[/tex] of this object would be [tex]p = m\, v[/tex].
if friction is negligible, the sum of the momentum should be the same before and after the collision.
Before the collision:
Momentum of the ice skater was [tex](8\; {\rm kg})\, (5\; {\rm m\cdot s^{-1}}) = 40\; {\rm kg \cdot m\cdot s^{-1}}[/tex].Momentum of the snowman was [tex](2\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg\cdot m\cdot s^{-1}}[/tex].In other words, the sum of momentum was [tex]40\; {\rm kg\cdot m\cdot s^{-1}}[/tex] before the collision.
After the collision:
Momentum of the ice skater became [tex](8\; {\rm kg})\, (0\; {\rm m\cdot s^{-1}}) = 0\; {\rm kg \cdot m\cdot s^{-1}}[/tex].Momentum of the snowman needs to be found.The sum of the momentum stays unchanged at [tex]40\; {\rm kg\cdot m\cdot s^{-1}}[/tex]. Subtract the momentum of the ice skater from the sum to find the momentum of the snowman:
[tex]40\; {\rm kg\cdot m\cdot s^{-1}} - 0\; {\rm kg\cdot m\cdot s^{-1}} = 40\; {\rm kg\cdot m\cdot s^{-1}}[/tex].
Divide the momentum of the snowman by its mass to find its velocity:
[tex]\begin{aligned}\frac{40\; {\rm kg\cdot m\cdot s^{-1}}}{2\; {\rm kg}} = 20\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
In other words, the collision of the snowman would be [tex]20\; {\rm m\cdot s^{-1}}[/tex] after the collision.
predict which penny will land first, the penny moving horizontally, or the one that simply drops off the table. explain.
It is observed that both the pennies will land at the same time. This is because second penny has only horizontal velocity.
Projectile motion occurs when an object moves through two or more dimensions simultaneously, usually under the influence of gravity. The kinematic equations regulating projectile motion apply independently in each dimension, which is a crucial aspect of the motion.
Both pennies will land at the same time. The second penny's velocity is fully horizontal, therefore its vertical velocity is still zero, and this is the explanation for it. As a result, it will have the exact same kinematic equation in the y-dimension as the first penny and will fall to the ground at the same moment. The time till impact will not alter regardless of the second penny's horizontal speed.
The question is incomplete. The complete question is 'If one penny is balanced on the edge of the table and you place your index finger on a second penny then flick the second penny so that it ravels off the table, while the first penny is gently nudged off the edge, which penny will land first, the penny moving horizontally or the one that simply drops off the table. Please explain the answer.'
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water flows through a horizontal plastic pipe with a diameter of 0.2 m at a velocity of 9 cm/s. (a) determine the pressure drop per meter of pipe using the moody chart. (b) calculate the power lost to the friction per meter of pipe. assume that the water is at 20oc.
The pressure is 0.00038 Pa/m, and the power lost to friction per meter of pipe is approximately [tex]2.28 * 10^-7 W/m.[/tex]
To determine the pressure drop per meter of pipe and the power lost to friction, we need to calculate the friction factor using the Moody chart and the Darcy-Weisbach equation. The Darcy-Weisbach equation is:
ΔP = [tex]f * L * (v^2) / (2 * g * d)[/tex]
where ΔP is the pressure drop per meter of pipe, f is the friction factor, L is the length of pipe, v is the velocity of the water, g is acceleration that occurs because of gravity and d is pipe's diameter.
We can use the Moody chart to find the friction factor, f, based on the Reynolds number, which is a measure of the fluid flow regime. For a smooth plastic pipe, the Reynolds number can be calculated as:
Re = (v * d) / ν
where ν is the kinematic viscosity of the water, which is approximately [tex]0.000001 m^2/s[/tex] at 20°C.
Once we have the Reynolds number, we can find the friction factor from the Moody chart. For a Reynolds number of approximately 2200, the friction factor for a smooth plastic pipe is approximately 0.022.
Plugging the values into the Darcy-Weisbach equation, we find that the pressure drop per meter of pipe is:
ΔP = [tex](0.022) * (1 m) * (0.09 m/s)^2 / (2 * 9.8 m/s^2 * 0.2 m)[/tex] = 0.00038 Pa/m
To calculate the power lost to friction, we can use the equation:
P = ΔP * Q
where P is the power lost to friction and Q is the flow rate, which can be calculated as:
Q = A * v = [tex](pi/4) * d^2 * v = (pi/4) * (0.2 m)^2 * (0.09 m/s)[/tex]= [tex]0.0006 m^3/s[/tex]
Plugging the values into the power equation, we find that:
P = ΔP * Q = (0.00038 Pa/m) * (0.0006 [tex]m^3/s[/tex]) = [tex]2.28 * 10^-7 W/m[/tex]
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calculate the horizontal distance, xmax , in meters, that the ball has traveled when it returns to ground level.
A ball that leaves a bat and returns to the ground level will reach a maximum horizontal distance of 145.8 meters.
An object moves in projectile motion when it follows a parabolic route. When gravity is the only influencing force after one force launches the object, it happens. Projectile trajectory refers to the path that the object takes when subjected to this gravitational pull. We typically ignore air resistance out of convenience.
The following equation can be used to determine the ball's maximum horizontal distance ([tex]x_{max}[/tex]) before it hits the ground:
[tex]x_{max} =\frac{v_o^2 \times sin(2\theta)}{g}[/tex]
Where:
[tex]v_{o}[/tex] is the starting speed = 38[tex]\frac{m}{s}[/tex]
[tex]\theta[/tex] is the angle 41° higher than the horizontal
g = 9.81 [tex]\frac{m}{s^2}[/tex] is the acceleration caused by gravity.
The maximum horizontal distance is as follows:
[tex]x_{max} =\frac{v_o^2 \times sin(2\theta)}{g}=\frac{38^2 \times sin(2\times 41)}{9.8}[/tex]=145.8m
The horizontal distance, then, is 145.8 meters when the ball lands at ground level.
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A rope that makes a 15° angle with the
horizontal pulls a block weighing 3 Na
distance of 10 meters to the right at a
constant velocity. The tension in the rope
is a 2 N force. How much work is done
by the rope acting on the block in the
horizontal directi on? Let F, be the
tension in the rope and Ax be the
3. displacement in the x-direction.
A. 28.98 J
B. 20 J
C. 189.34 J
D. 19.32 J
Answer:
Explanation:
d
somewhat idealized graph of the velocity of blood in the ascending aorta during one beat of the heart. approximately how far, in cm, does the blood move during one beat?
According to the graph the blood move 8 cm during one beat.
To find how far does the blood move during one beat, we need to find the area under the velocity curve.
The blood displaces [tex]\triangle x =x_f-x_i[/tex] between t = 0.1 s and t = 0.3 s is the area under the curve from t = 0.1 s to t = 0.3 s.
In this case, the curve is a triangle, thus the area of a triangle is, area of the triangle between t = 0.1 s to t = 0.3 s.
[tex]\dfrac{1}{2} \times 0.2 \times 0.8[/tex] = 8cm
Therefore, blood moves 8 cm during one beat.
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what would happen to the motion of the projectile if we do not ignore air resistance? group of answer choices it is impossible to think about what would happen to the object. the object would move in a straight line. the range would be a shorter distance. purple the object would not fall to the ground.
Projectile motion exhibits negligible horizontal acceleration if air resistance is disregarded. As a result, the particle moves horizontally at a constant speed.
A projectile is an item on which gravity is the only force at work. Projectiles come in a variety of forms. A fallen object is referred to as a projectile motion (provided that the influence of air resistance is negligible).A projectile is something that is thrown vertically upward (provided that the influence of air resistance is negligible). In addition, any object sent upward at an angle to the horizontal is considered a projectile (provided that the influence of air resistance is negligible). Any object that, after being launched or dropped, keeps moving due to its own inertia and is solely impacted by the gravitational force acting downward is considered a projectile.
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why is a battery used when we require more electricity
A battery is used when we require more electricity because it can store and release electrical energy as needed.
Batteries consist of one or more cells, each of which contains two electrodes and an electrolyte that allows for the flow of charged particles between the electrodes. When a battery is connected to a device, the charged particles flow from the positively charged electrode to the negatively charged electrode, providing a flow of the electricity.
The amount of electricity stored in a battery is limited, but it can be released as needed, even when the source of the electricity is not available. This makes batteries useful for supplying electrical energy in situations where there is a temporary increase in demand, such as when more devices are turned on or when the source of electrical energy is unavailable, such as during a power outage.
Additionally, batteries are portable and can be easily carried, making them useful for supplying electrical energy in remote locations where there is no access to the electrical grid.
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A 500-kg ball at the end of a 30-m cablesuspended from a crane is used to demolish an old building.If the ball has an initial angular displacement of 15°from the vertical , determine its speed at the bottom of the arc.
The velocity at the bottom of the arc with the ball of 500kg at the end of a 30 m cable suspended will be 8.88 m/s.
What is Velocity?Velocity can be defined as the displacement of the object in a particular time period. Velocity is a vector quantity because it has both the magnitude and direction. The SI unit of velocity is m/s.
We have given mass, m = 500 kg
Length of cable, l = 30 m
Angular displacement of the ball, θ = 30°
Gravitational potential energy of the ball at the displaced position is equal to,
U = mgl (1 - cosθ)
Maximum kinetic energy of the ball, Ke = 1/2 mv²
According to energy conservation,
1/2 mv² = mgl (1 - cosθ)
v = √2gl(1 - cosθ)
v = √2 × 9.8 × 30(1-cos30)
v = 8.875 m/s
Therefore, the velocity of the arc is 8.88 m/s.
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