Holiday Inn charges its cost one dollar plus $.80 per minute for long distance calls. Across the street, La Quinta charges its guests $2 plus $0.75 per minute for long distance calls. Which equation correctly models the length of a call for which the two hotels charge the same amount

Answer:

The correct answer is B) (7,2).

Step-by-step explanation:

I hope this helps!

Answer:

y=6x

Step-by-step explanation:

direct variation equation is like y=kx (k: constant)

substitute (5,30) to solve k,

30=5k

k=6

Answer:y=6x

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

Answer:

the value of x is 45 degree

Answer:

45

Step-by-step explanation:

Step 1:

2x + 55° + x - 10° = 180°            Sum of a Δ

Step 2:

3x + 45° = 180°            Combine Like Terms

Step 3:

3x = 135°      Subtract 45° on both sides

Step 4:

x = 135° ÷ 3     Divide

Answer:

x = 45

Hope This Helps :)

Answer:

2/5 is bigger

Step-by-step explanation:

2/5 is 0.40

Answer:

its b Brother

Step-by-step explanation:

Answer:

vvhcfggfcc

Step-by-step explanation:

ccgvvhhh I don't I need more points buddy

Answer:

The slope of the line given by the linear equation is -2

The slope of the line shown in the graph is -1

Step-by-step explanation:

The line equation, y = -2x + 7 is written in the slope-intercept form, which is represented by the formula, y = mx + b.

m is the slope, while b is the y-intercept.

Therefore, the slope of the line of the linear equation, y = -2x + 7 is -2.

Find the slope of the line shown in the graph using the formula, [tex] m = \frac{y_2 - y_1}{x_2 - x_1} [/tex].

Use the coordinates of any two points on the line. Let's use (0, 5) and (5, 0)

Let,

[tex] (0, 5) = (x_1, y_1) [/tex]

[tex] (5, 0) = (x_2, y_2) [/tex]

[tex] m = \frac{0 - 5}{5 - 0} = \frac{-5}{5} = -1 [/tex]

Therefore:

The slope of the line given by the linear equation is -2

The slope of the line shown in the graph is -1

So basically you factor 4 out of 16

4(4b-1)

Answer:

janelle is 2,015.75 ft above sea level the altimeter should read plus 2,015.75

2,015.75 ft is the Janelle's position relative to sea level while hiking and the altimeterread this position as 2,015.75.

hope this hep you

Answer:

I believe the answer is A

Step-by-step explanation:

I say it's A because the volume is double like it told us. Compared to the new box it's twice as long as the old boxes.

I hope this helps! ~~~~

The volume of the new box is 8 times the volume of the old box.

The correct answer is option (D).

The volume of a rectangular box with length L, width W and height H is,

V = L × W × H

Given: -

Let [tex]l,w,h[/tex] represents the length, width and height of the old rectangular boxes.

Let [tex]V_o[/tex] represents the volume of the old rectangular box.

⇒ [tex]V_o=l\times w \times h[/tex]

The length, width and height of the new boxes are all twice as long as those of the old boxes.

This means the length, width and height of the new boxes would be [tex]2l,2w,2h[/tex].

Let [tex]V_n[/tex] represents the volume of the new rectangular box.

So, the volume of the new rectangular box would be,

⇒ [tex]V_n=2l \times 2w \times 2h[/tex]

⇒ [tex]V_n = 8 \times l \times w \times h[/tex]

⇒ [tex]V_n=8 \times V_o[/tex]

This means, the volume of the new box is 8 times the volume of the old box.

Hence, option (D) is the correct answer.

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Answer: actually the mass

Step-by-step explanation: regardless on where you are the mass never change, it's the wait within a substance or a matter

Answer:

She did 5.60-2.31=2.25

Step-by-step explanation:

She should have subtracted 5.6-2.31=3.29

-    Answer:

the answer is 3.29

she didn't put the decimal point in the right place when subtracting

Step-by-step explanation:

correct

5.6

-

2.31 =

3.29

NOTICE THAT IN THIS PROBLEM THE  DECIMAL POINTS ARE ALIGNED WITH EACH OTHER.

wrong

 5.6  

-

2.31

=

2.25

     NOTICE THAT IN THIS PROBLEM THE  DECIMAL POINTS ARE NOT ALIGNED WITH EACH OTHER.

Also plz mark brainliest and try to answer my question

Answer:

5

Step-by-step explanation:

The function intersects the y-axis at 1, and its slope is 1, so the function of the graph is y = x+1. Plugin 4, and you get y = 5.

Answer:

18x^2 - 40x / 3

Answer:

its either D or C

Step-by-step explanation:

A makes no sense because u only moving 2 and for B too and E it not it

The question is incomplete. The full question is below.

The path of a particular punt follows the quadratic function

[tex]h(x)=\frac{-1}{8}(x-25)^{2}+50[/tex]

where h(x) is the height of the ball in yards and x corresponds to the horizontal distance in yards. Assume x=0 corresponds to midfield (the 50 yards line). For example, x=20 corresponds to the punter's own 30 yard line, whereas corresponds to the other team's 30 yard line.

a. Find the maximum height the ball achieves.

b. Find the horizontal distance the ball covers. Assume the height is zero when the ball is kicked and when the ball is caught.

Answer: a. Maximum height = 50

              b. Horizontal distance = 40

Step-by-step explanation: A quadratic function has its maximum or minimum point on its vertex.

When the function is negative, function has a maximum point.

The quadratic function h(x) is written in vertex form, meaning the coordinate of vertex is explicit in the function.

General vertex form: [tex]f(x)=A(x-h)^{2}+k[/tex]

A is vertical scaling parameter

(h,k) are the coordinates of vertex

So, the quadratic function for the height for the ball:

[tex]h(x)=\frac{-1}{8}(x-25)^{2}+50[/tex]

shows its vertex:

(h,k) = (25,50)

a. The maximum height the ball achieves the maximum value corresponds to the y-axis, which means, maximum height is 50 yards.

b. Horizontal distance is when h(x)=0, so:

[tex]\frac{-1}{8}(x-25)^{2}+50=0[/tex]

[tex]\frac{-1}{8}(x-25)^{2}=-50[/tex]

[tex](x-25)^{2}=400[/tex]

[tex]x^{2}-50x+625=400[/tex]

[tex]x^{2}-50x+225=0[/tex]

Solving quadratic equation:

[tex]x_{1}=\frac{50+\sqrt{1600} }{2}[/tex] = 45

[tex]x_{2}=\frac{50-\sqrt{1600} }{2}[/tex] = 5

When ball is kicked, it is in position 5. When is caught, is position 45. So, distance the balls covers is 40 yards.

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. The square root of 10 lies between 3 and 4.

A number line is just that – a straight, horizontal line with numbers placed at even increments along the length. It’s not a ruler, so the space between each number doesn’t matter, but the numbers included on the line determine how it’s meant to be used.

In order to find the square root of 10 lies between which two numbers the approximate value of the root is needed to be calculated.

√10 = 3.162.......

Now, if we plot √10 on the number line its value will lie between 3 and 4.

Hence, The square root of 10 lies between 3 and 4.

Learn more about the Number line:

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Answer:

BC=FD

Step-by-step explanation:

Answer: I agree it’s BC congruent to FD

Step-by-step explanation:

Answer:

-2x - 28

Step-by-step explanation:

-4(x+6) +2 (x-2)    Distribute the -4 to (x+6) and the 2 to (x-2):

-4x - 24 + 2x - 4  Combine like terms  -4 + 2x and -24-4:

-2x - 28

Hope this helped :)

Answer:

Please see explanation.

Step-by-step explanation:

-4(x+6) + 2(x-2)   First, distribute the -4 to x+6

-4x - 24 + 2(x-2)   Now distribute the 2 into x-2

-4x - 24 + 2x - 4   Combine like terms

-4x + 2x - 24 - 4

-2x - 28                  This might be your answer but if you are looking for what x is equal to then keep following along.

If you are solving for x then most likely the equation says that it is equal to zero

-2x - 28 = 0   Add 28 to both sides

-2x = 28        divide both sides by -2

x = -14

Answer:

hey you can use google

Step-by-step explanation:

first write your question then look for useful answers

Answer:

where points are on a grid

Step-by-step explanation:

Answer(-14x power2+18x)

Answer:

(140-15)÷15=W

Step-by-step explanation:

140-15=125

125 still needed.  divide that by the amount that will be saved each week which is 15 a week and you get 8.3.  If they want an actual answer you would say 9 weeks because if you only did 8 Anthony would be short $5 so hed have to wait an additional week to have enough to cover the purchase.  So thats why the answer would be 9

Brainliest please!!!

Answer:

A. [tex](x+5)^2+(y-4)^2=16[/tex]

B. [tex](x-1)^2+(y-4)^2=2\\[/tex]

C. [tex]$\left(x-3\right)^2+\left(y-5\right)^2=9$[/tex]

Step-by-Step Explanation:

A. Tangent to x-axis, r=4, contains (-5,8)

The equation of a circle is this: [tex](x-h)^2+(y-k)^2=r^2\\[/tex]

Therefore, we know that our equation will be: [tex](x-h)^2+(y-k)^2=4^2=16[/tex]

Because the circle is tangent to the x-axis, the point (-5,8) will be the top of the circle.

Therefore, the center is (-5,4), where -5=h and 4=k.

The answer is [tex](x+5)^2+(y-4)^2=16[/tex]

B. Diameter endpoints (2,5) and (0,3)

To solve for the diameter, we can use this equation: [tex]d=\sqrt{(x_{1}-x_{2})^2+(y_{1}-y_{2})^2 }[/tex]

[tex]d=\sqrt{(2-0)^2+(5-3)^2 }\\\\d=\sqrt{2^2+2^2}=\sqrt{4+4} =\sqrt{8}= 2\sqrt{2}[/tex]

Because the radius is half of the diameter, [tex]r=\sqrt{2}[/tex]

Therefore, we know that our equation will be: [tex](x-h)^2+(y-k)^2=(\sqrt{2}) ^2=2[/tex]

Then, we can decipher that h=1, as the midpoint of 0 and 2 is 1, and k=4, as the midpoint of 3 and 5 is 4.

The answer is [tex](x-1)^2+(y-4)^2=2[/tex]

C. Center on x=3, tangent to y-axis at (0,5)

We can see that the center is (3,5). Therefore, the equation is [tex](x-3)^2+(y-5)^2=r^2\\[/tex]

To solve for r, we can substitute the point (0,5) into the equation.

[tex](0-3)^2+(5-5)^2=r^2\\(-3)^2+(0)^2=r^2\\r^2=9[/tex]

The answer is [tex](x-3)^2+(y-5)^2=9[/tex]

Hope this helped!

Answer:  see below

Step-by-step explanation:

Domain represents the x-values from the smallest (furthest left) to the biggest (furthest right).

Range represents the y-values from the lowest (furthest down) to the highest (furthest up).

Interval notation: If a value is included (closed dot), use a bracket [  ]

                      If a value is NOT included (open dot), use a parenthesis (  )

                     Note that ± ∞ is never included.

1. Domain: smallest x-value is -4 (included). biggest x-value is 3 (included)

  Range: lowest y-value is 2 (included). highest y-value is 5 (included)

                 D: x = [-4, 3]        R: y = [2, 5]

2. Domain: smallest x-value is -∞ (←). biggest x-value is 2 (included)

  Range: lowest y-value is 2 (included). highest y-value is ∞ (↑)

                 D: x = (-∞, 2]        R: y = [2, ∞)

3. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is -∞ (↓). highest y-value is ∞ (↑)

                 D: x = (-∞, ∞)        R: y = (-∞, ∞)

4. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is -∞ (↓). highest y-value is 4 (included)

                 D: x = (-∞, ∞)        R: y = (-∞, 4]

5. Domain: smallest x-value is -∞ (←). biggest x-value is ∞ (→)

  Range: lowest y-value is 3 (included). highest y-value is ∞ (↑)

                 D: x = (-∞, ∞)        R: y = [3, ∞)

6. Domain: smallest x-value is -2 (included). biggest x-value is ∞ (→)

  Range: lowest y-value is -3 (included). highest y-value is ∞ (↑)

                 D: x = [-2, ∞)        R: y = [-3, ∞)

Answer:

[tex]C(t)=5\cdot(0.9)^t[/tex]

Step-by-step explanation:

The exponential function is often used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

[tex]C(t)=C_o\cdot(1-r)^t[/tex]

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The concentration of the pollutants starts at Co=5 mg/lt. We also know the pollutant reduces its concentration by 10% each hour. This gives us a value of r = 10% / 100 = 0.1

Substituting into the general equation:

[tex]C(t)=5\cdot(1-0.1)^t[/tex]

Operating:

[tex]\boxed{C(t)=5\cdot(0.9)^t}[/tex]

y(n) = 5(0.9)ⁿ

y(n) = a(1 - b)ⁿ

where;

y is the final amount at time n,

a is the original amount

b is the decay factor

x is the amount of time that has passed.

Thus;

a = 5 mg/L.

We are told that the pollutant reduces its concentration by 10% each hour. Thus; b= 10%

b = 0.1

y(n) = 5(1 - 0.1)ⁿ

y(n) = 5(0.9)ⁿ

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