Here is a circle. Points A, B, C, and D are drawn, as
well as Segments AD and BC.
D.
What is the area of the circle, in square units?

Here Is A Circle. Points A, B, C, And D Are Drawn, Aswell As Segments AD And BC.D.What Is The Area Of

Answers

Answer 1
Area of a circle = pi *r^2
A=pi*4^2
A=50.24 square units

Hope it helps

Related Questions

answer all
(make sure to show work
6th grade work

Answers

8+ ( 8 - 6)
8 + 2
10 - answer

4 times 4
16 + 20
36 - answer


Ur welcome


Fast help pls

13¢ per mile. Company B charges $50.50 and 8€ per mile. How much more does Company A
charge for x miles than Company B?

Answers

it might be 5 if you subtract 13 from 8

1/3 as long as 6 meters meter(s) ??​

Answers

Answer:

1/3 of 6 meters is 2 meters

Step-by-step explanation:

PLEASE HELP DUE IN 3 minutes

Answers

130-139=4

140-149=7

150-159=4

160-169=5

Other Academics
4: Assessment Form A
Henry sells rings for $8 each. His expenses are $1.50 per ring, plus $91 for supplies. How many rings does he need to sell for his revenue to equal his
expenses?
A 140
B. 9
C. 10
D. 14

Answers

Answer: B





hope it helps :)

ill mark brainlist plss help

Answers

Answer:

Quadrilateral, parallelogram, rhombus; rhombus

Step-by-step explanation:

It’s a quadrilateral becasue it has 4 sides and vertices.

It’s a rhombus because opposite angles are equal and opposite sides are equal.

It‘s a parallelogram because all rhombuses are parallelograms.

The correct answer is 222 ft.

Please indicate which type of sampling design is most appropriate for each of the following studies. The choices are SRS, stratified random sampling, and matched pair design.

a. A campus newspaper randomly selects 20 common Spring Break destinations and surveys the residents about their attitudes of students spending Spring Break in their city.
b. A developer in West Lafayette wants to know if students who are renting off-campus like their apartment complex. They chose 10 students who lived in 5 different complexes.
c. A researcher wants to know the difference in time it takes to apply brakes between people who are not talking on the phone and people who are talking on a hands-free cell phone. She chose 100 individuals and then drive both ways in a simulator and measured their responses. A student organization has 55 members. Out of these members, five are selected randomly to attend a national conference.

Answers

Answer:

Following are the responses to the given question:

Step-by-step explanation:

In point 1

The random selection stratified: although 50 statements belong to 5 different groups.

In point 2:

Coincide pair design: As we're in the SAME location to measure the difference between the downstream and upstream fractures. Although when calculating a top-down split they need only to calculate the low-up split which corresponds to the top-down split.

In point 3:

Matched layout: As 100 individuals were chosen and ALL were required to give BOTH and document certain responses.

In point 4:

SRS: RANDOMLY has also been selected since 20 spring break goals.

A local bakery sells bread and breakfast items. The bakery also offers two dessert options each day. Yesterday, the bakery offered decorated sugar cookies and miniature cakes. Each decorated sugar cookie sells for $3 and each miniature cake sells for $2. Yesterday, the bakery sold 40 bakery items, which sold for $96 total.

The system of equations shown can be used to represent this situation. In the system of equations, s equals the number of decorated sugar cookies sold and c represents the number of miniature cakes sold.

s+c=40 3s+2c=96

Answers

Answer:

I can't understand your equation. Please rewrite it.

Step-by-step explanation:

James invests a total of $18,000 in two accounts paying 13% and 3% annual interest, respectively. How
much was invested in each account if, after one year, the total interest was $2,040.00.
S
was invested at 13% and
S
was invested at 3%.

Answers

Answer:

$15,000 was invested at 13% per year, and $ 3,000 was invested at 3% per year.

Step-by-step explanation:

Given that James invests a total of $ 18,000 in two accounts paying 13% and 3% annual interest, respectively, to determine how much was invested in each account if, after one year, the total interest was $ 2,040.00, the following calculation must be performed:

18,000 x 0.13 + 0 x 0.03 = 2340

16,000 x 0.13 + 2,000 x 0.03 = 2140

15,000 x 0.13 + 3,000 x 0.03 = 2040

Thus, $ 15,000 was invested at 13% per year, and $ 3,000 was invested at 3% per year.

What is the slope of the line through (-9,6) and (-3, 9)?

Answers

To find slope, y2-y1/x2-x1
9-6/-3-(-9)=
3/6= 1/2
Slope = 1/2.
Y=1/2x.

write the equation of a line parallel to the line 2x + y = 3 that passes through the point (2,6)

Answers

Answer (assuming it can be in slope-intercept form):

[tex]y = -2x +10[/tex]    

Step-by-step explanation:

1) First, we need to find the slope of the given equation. To do that easily, convert it to slope-intercept form, represented by the formula  [tex]y = mx + b[/tex]. Isolate y:

[tex]2x + y = 3\\y = -2x + 3[/tex]

The number in place of [tex]m[/tex], or the coefficient of the x-term, represents the slope of the equation. So, the slope of the given equation is -2.

Lines that are parallel share the same slope. So, the slope of the new equation will be -2 as well.  

2) Now, remember that the slope-intercept form is represented by the formula [tex]y = mx + b[/tex]. In order to write an equation of a line using that formula, we need to substitute values for [tex]m[/tex] and [tex]b[/tex]. We know [tex]m[/tex] is the slope, so we already know what that equals. Now, we just need to find [tex]b[/tex].

To do that, substitute -2 for [tex]m[/tex] in the slope-intercept formula. Additionally, substitute the x and y values of the point (2,6) for the x and y in the formula as well. This sets up the equation so that we can isolate [tex]b[/tex] and find its values:  

[tex]y = mx +b\\6 = (-2)(2)+b\\6 = -4 + b\\10 = b[/tex]

So, [tex]b[/tex] = 10.

3) Substitute values for [tex]b[/tex] and [tex]m[/tex] into the slope-intercept formula to write the slope-intercept form of the line:

[tex]y = -2x +10[/tex]

Equation of a line parallel to the line 2x + y = 3 that passes through the point (2,6) is y+2x=10

What are parallel lines ?

Lines which does not intersect each other at any point is said to be Parallel.

Here given equation of line is 2x+y=3

first we will write this equation in y=mx+c form

So y=3-2x

y= -2x+3

We know that slope of parallel lines is same

So equation of parallel line will be

y=-2x+a

Now we know that line is passing through (2,6)

So

[tex]6=-2(2)+a\\\\6+4=a\\\\a=10[/tex]

Hence equation of parallel line is y=-2x+10

or we can write it as y+2x=10

Equation of a line parallel to the line 2x + y = 3 that passes through the point (2,6) is y+2x=10

To learn more about parallel lines visit :https://brainly.com/question/24607467

Simplify by combining Like terms: m + 9 - 4m

Answers

Answer:

9-3m

Step-by-step explanation:

m and -4m are like terms, combining them yields (1m-4m) which is -3m. The 9 is a constant.

PLSSS HELP ASAPPPPPP​

Answers

it will be A.25

Step-by-step explanation:

hope its right

Write the slope intercept form of the equation of the line. x + 8y = 24​

Answers

The answer is y= -1/8x+3

Please help with math question.

Answers

9514 1404 393

Answer:

  C

Step-by-step explanation:

Multiply numerator and denominator by the conjugate of the denominator.

  [tex]\displaystyle\frac{7}{-4-\sqrt{x}}=\frac{7(-4+\sqrt{x})}{(-4-\sqrt{x})(-4+\sqrt{x})}=\frac{-28+7\sqrt{x}}{16-x}=\boxed{\frac{7\sqrt{x}-28}{16-x}}[/tex]

4. Determine the volume of the eraser below. 3 in 1.5 in eraser 1 in​

Answers

Answer:

volume = 4.5 in³

Step-by-step explanation:

V = L x W x H

V = 3 x 1.5 x 1 = 4.5

The ordered pair (a,b)give the location of point P on the coordinate plane.The values of a and b have the same sign neither a nor b is 0 where could point P be located on the coordinate plane

Choices

Quadrant l
Quadrant ll
Quadrant lll
Quadrant lV
X-axis
Y-axis

Answers

Answer:

Q I  & Q III

Step-by-step explanation:

See the picture I have attached. The Quadrant numbers are in bold Roman numerals.

Only in quadrants I and III are x and Y both of the same sign.

If the point (a,b)  is on an axis, one of the coordinates must be zero, but you were told that neither a nor b is zero, so the axes can be counted out as possible answers.

The area of a rectangle is 245.25. If it has a width of 14 1/4, what is the length?

Answers

Answer:

3 6 8

Step-by-step explanation:

i just need them points.

The parent function is given by f(x) = x^2
Choose the BEST description for f(x - 3)+2.

Answers

right 3 units and 2 units up ⬆️

Option D
option D is correct

30. President Ronald Reagan earned a yearly salary of 2 x 10^5 dollars as
president. He served 8 years as president. What was the total amount of
money Ronald Reagan earned as president?
A 1.6 x 106 dollars
B. 2.0 x 106 dollars
c. 1.6 x 107 dollars
D. 2.0 x 107 dollars

Answers

Answer:

a) 1.6 x 10 ^6 dollars.

Step-by-step explanation:

since President Ronald Reagan served for 8 years. So the total amount of money that he earned is 2 x 10^5 x 8 = 16 x 10 ^ 5 = 1.6 x 10^6 dollars.

Angel and Kellie each have the same amount of money in their wallet. Angel buys two juice drinks and receives $1.10 in change after she pays. Kellie buys 1 juice drink and receives $3.05 in change after she pays. Which equation shows how to find the cost of a juice drink, j?

Answers

Answer:

y= 2x+1.10

y=x+3.05

Step-by-step explanation:

According to a researcher who was quoted in a New York Times article in March, 2011, 65% of U.S. community college students must take at least one remedial course in English, reading, or mathematics.2 A reporter for the student newspaper at a community college in Florida believes that the percentage of students taking at least one remedial course at her school is greater than 65%. She surveys a random sample of students at her school, asking the students whether they were required to take any remedial courses.

The null hypothesis assumes a specific value for the population proportion. In this case, it assumes that the proportion of students taking at least one remedial course at the Florida college is the same as the proportion that was reported in the New York Times. Complete the null hypothesis using this assumption.

Null Hypothesis: p = _________

Answers

Answer:

Null Hypothesis: p = 0.65.

Step-by-step explanation:

The null hypothesis is the expected population population, from an assumption deriving for example, from a previous experiment.

According to a researcher who was quoted in a New York Times article in March, 2011, 65% of U.S. community college students must take at least one remedial course in English

This means that the expected value of the population proportion is [tex]p = 0.65[/tex], which is the null hypothesis.

Null Hypothesis: p = 0.65.

Dominick and Janelle are working to simplify the expression 2c + 4 + c + 6. Janelle simplifies her expression to 2c + 10, while Dominick simplifies his to 3c + 10.

Answers

Answer:

3c + 10

Step-by-step explanation:

1c = c

2c + 4 + c + 6

(combine like terms)

3c + 10

Answer:

Dominic is right

Step-by-step explanation:

equation:

2c + 4 + c + 6

combine like terms:

2c + c = 3c

4 + 6 = 10

new equation:

3c + 10

evaluate the following definite integral​

Answers

Answer:

[tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}[/tex]

General Formulas and Concepts:

Symbols

e (Euler's number) ≈ 2.71828

Algebra I

Exponential Rule [Multiplying]:                                                                     [tex]\displaystyle b^m \cdot b^n = b^{m + n}[/tex]

Calculus

Differentiation

DerivativesDerivative Notation

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Integration

IntegralsDefinite IntegralsIntegration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Rule [Fundamental Theorem of Calculus 1]:                                     [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

U-Substitution

U-Solve

Integration by Parts:                                                                                               [tex]\displaystyle \int {u} \, dv = uv - \int {v} \, du[/tex]

[IBP] LIPET: Logs, inverses, Polynomials, Exponentials, Trig

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx[/tex]

Step 2: Integrate Pt. 1

[Integrand] Rewrite [Exponential Rule - Multiplying]:                                 [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \int\limits^1_0 {x^5e^{x^3}e} \, dx[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]:                 [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = e\int\limits^1_0 {x^5e^{x^3}} \, dx[/tex]

Step 3: Integrate Pt. 2

Identify variables for u-solve.

Set u:                                                                                                             [tex]\displaystyle u = x^3[/tex][u] Differentiate [Basic Power Rule]:                                                             [tex]\displaystyle du = 3x^2 \ dx[/tex][u] Rewrite:                                                                                                     [tex]\displaystyle x = \sqrt[3]{u}[/tex][du] Rewrite:                                                                                                   [tex]\displaystyle dx = \frac{1}{3x^2} \ du[/tex]

Step 4: Integrate Pt. 3

[Integral] U-Solve:                                                                                         [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = e\int\limits^1_0 {x^5e^{(\sqrt[3]{u})^3}\frac{1}{3x^2}} \, du[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]:                 [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}\int\limits^1_0 {x^5e^{(\sqrt[3]{u})^3}\frac{1}{x^2}} \, du[/tex][Integral] Simplify:                                                                                         [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}\int\limits^1_0 {x^3e^u} \, du[/tex][Integrand] U-Solve:                                                                                      [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}\int\limits^1_0 {ue^u} \, du[/tex]

Step 5: integrate Pt. 4

Identify variables for integration by parts using LIPET.

Set u:                                                                                                             [tex]\displaystyle u = u[/tex][u] Differentiate [Basic Power Rule]:                                                             [tex]\displaystyle du = du[/tex]Set dv:                                                                                                           [tex]\displaystyle dv = e^u \ du[/tex][dv] Exponential Integration:                                                                         [tex]\displaystyle v = e^u[/tex]

Step 6: Integrate Pt. 5

[Integral] Integration by Parts:                                                                        [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3} \bigg[ ue^u \bigg| \limits^1_0 - \int\limits^1_0 {e^u} \, du \bigg][/tex][Integral] Exponential Integration:                                                               [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3} \bigg[ ue^u \bigg| \limits^1_0 - e^u \bigg| \limits^1_0 \bigg][/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]:           [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}[ e - e ][/tex]Simplify:                                                                                                         [tex]\displaystyle \int\limits^1_0 {x^5e^{x^3 + 1}} \, dx = \frac{e}{3}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

Book: College Calculus 10e

50 points help me please

Answers

3•3/6 = 9/6 = 3/2

Simplified Improper Fraction: 3/2
Mixed Number: 1 1/2

If Fx) = 8x, which of the following is the inverse of F(x)?

Answers

hope this helps . it’s quite a simple

Answer

y=x/8

Step-by-step explanation:

f(x)=8x

f(x)=y

y=8x(interchange the values)

x=8y(divide by 8 both sides)

y=x/8

What is the range of the data set? *
2 points
53, 39, 123, 59, 25, 79, 88
84
53
123
98
25

Answers

Answer:

25

Step-by-step explanation:

range = largest value - smallest value (123-25)

98 because range is the largest number - the smallest

I need help please.

Answers

Answer:

B

Step-by-step explanation:

Rectangle MNPQ is graphed on a coordinate grid with vertices at MCU,), N(4,14), P(8,6),
and QC-8,-2). Rectangle MNPQ is dilated by a scale factor of 3 with the origin as the center
of dilation to create rectangle M'N'P'Q'.
Which ordered pair represents the coordinates of vertex M'?
A
B (3u, 3v)
C (u + 3,v + 3)
33
D

Answers

the answer would be C , ending with 33

Maximize −4x + 5y + 70 subject to the constraints:

2x + y ≤ 8
x + 3y ≥ 5
x + y ≤ 6
x ≥ 0,
y ≥ 0

a. Fix any constraints, as needed, and then convert the linear programming problem into a system of linear equations.
b. Give a fully labeled initial tableau, and circle the pivot element.

Answers

Answer:

Step-by-step explanation:

[tex]\text{To maximize -4x + 5y + 70 subject to } \\ \\ 2x + y \le 8 --- (1) \\ \\ x + 3y \ge 5 --- (2) \\ \\ x + y \le 6----(3) \\ \\ x \ge 0, y \ge 0[/tex]

[tex]\text{From above equationn (1)} : 2x + y = 8 \\ \\ \text{Divide boths sides by 8} \\ \\ \dfrac{2x}{8} + \dfrac{y}{8} = \dfrac{8}{8}[/tex]

[tex]\dfrac{x}{4} + \dfrac{y}{8} = 1 \\ \\ x = 4; y = 8[/tex]

[tex]\text{From above equationn (2)} : x + 3y = 5 \\ \\ \text{Divide boths sides by 5} \\ \\ \dfrac{x}{5} + \dfrac{3y}{5} = \dfrac{5}{5} \\ \\ x = 5; \ y = 1.66[/tex]

[tex]\text{From above equation (3)} : x + y = 6 \\ \\ \text{Divide boths sides by 5} \\ \\ \dfrac{x}{6} + \dfrac{y}{6} = \dfrac{6}{6} \\ \\ x = 6; \ y = 6[/tex]

[tex]\text{From the image attached below, we can see the representation in the graph}[/tex]

-   [tex]\text{Now from equation (1) ad (III)} \\ \\ 2x + y = 8 \\ \\ x+y = 6[/tex]

                 

    [tex]x[/tex]      [tex]= 2[/tex]

                 

[tex]From : x + y = 6 \\ \\ 2 + y = 6 \\ \\ y = 6-2 \\ \\ y =4[/tex]

[tex]\text{From equation (1) and (II) } \\ \\ \ \ 2x + y = 8 \\ - \\ \ \ x + 3y = 5 \\ \\[/tex]

[tex]-5y = -2 \\ \\ y = \dfrac{2}{5} \ o r\ 0.4 \\ \\ From : 2x+ y = 8 \\ \\ 2x = 8 - \dfrac{2}{5} \\ \\ x = \dfrac{ 8 - \dfrac{2}{5} }{2} \\ \\ x = 3.8[/tex]

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