Help with geometry please

Step-by-step explanation:

2x - y = 5

-y = 5 - 2x

.........

Answer:

250 milliliters

Step-by-step explanation:

3.5 liters = 3.5 × 1000 milliliters=3500milliliters

3750-3500 = 250 milliliters

Answer:

Hope this helps :D

Step-by-step explanation:

The simplified form of the given expression is x-z-3.

The given expression is 8z + x -5 - 9z + 2.

An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.

The given expression is written in simplified form is as follows

Group the like terms

8z - 9z + x -5 + 2

= -z+x-3

= x-z-3

Hence, the simplified form of the given expression is x-z-3.

To learn more about an expression visit;

https://brainly.com/question/28170201.

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Answer:

19

Step-by-step explanation:

1 x 4 = 4

15 + 4 = 19

Try this out, hope it helps!

Answer:

equation for how tall sunflower would be after 'w' weeks: y = 15 + w

Step-by-step explanation:

Answer:

Let the amounts be 2x and 3x.

Then 2x+3x=60

So, 5x=60

So, x=60/5=12

So, amounts are

2x=2*12=24

And 3x=3*12=36

Hope this helps you!

Step-by-step explanation:

um are you ok dude/ma'am?

Answer: 24 coconuts

Step-by-step explanation:

Let the number of coconuts that were originally on the tree be represented by x.

The information given in the question can then be presented to an equation as:

25% × x = 6

25/100 × x = 6

0.25 × x = 6

0.25x = 6

x = 6/0.25

x = 24

Therefore, 24 coconut were originally on the tree.

Answer: 24 coconuts

Step-by-step explanation:

Answer: y=8

Step-by-step explanation:

Answer:

Y = 8

Step-by-step explanation:

Answer:

The speed of the jet with no wind is 240 miles per hour.

Step-by-step explanation:

The speed of the jet with no wind is equivalent to the speed of the jet relative to wind. Physically speaking, we have the following system of linear equations under the assumption that both speeds of wind and jet are constant:

In favor of wind

[tex]\frac{s}{t_{F}} = v_{W}+v_{J/W}[/tex] (1)

Against wind

[tex]-\frac{s}{t_{A}} = v_{W} -v_{J/W}[/tex] (2)

Where:

[tex]s[/tex] - Travelled distance, measured in miles.

[tex]t_{F}[/tex], [tex]t_{A}[/tex] - Time, measured in hours.

[tex]v_{W}[/tex] - Wind speed, measured in miles per hour.

[tex]v_{J/W}[/tex] - Jet speed relative to wind, measured in miles per hour.

If we know that [tex]t_{F} = 5\,h[/tex], [tex]t_{A} = 7\,h[/tex], [tex]v_{W} = 40\,\frac{mi}{h}[/tex], then the speed of the jet with no wind is:

[tex]\frac{s}{5} = 40 + v_{J/W}[/tex] (3)

[tex]-\frac{s}{7} = 40-v_{J/W}[/tex] (4)

[tex]\frac{s}{5}-40 = 40 +\frac{s}{7}[/tex]

[tex]\frac{s}{5}-\frac{s}{7} = 80[/tex]

[tex]\frac{7\cdot s - 5\cdot s}{35} = 80[/tex]

[tex]2\cdot s = 2800[/tex]

[tex]s = 1400\,mi[/tex]

From (3), we find that speed of the jet with no wind is:

[tex]v_{J/W} = \frac{s}{5}-40[/tex]

[tex]v_{J/W} = \frac{1400}{5}-40[/tex]

[tex]v_{J/W} = 240\,\frac{mi}{h}[/tex]

The speed of the jet with no wind is 240 miles per hour.

Answer: NUMBER 3

Step-by-step explanation:

Answer:

equalities

Please put the Brainlest

Answer:

A

Step-by-step explanation:

Answer:

c=6√2

Step-by-step explanation:

yh I know but not at the moment srry

Answer:

0.281 ; 0.864

Step-by-step explanation:

1.)

p decreases as n increases (n increases, p--> 0)

λ ≥ 0

P(x = x) = (e^-λ * λ^x) ÷ x!

λ for Ford = 1.27

B) zero problems :

P(x = 0) :

(e^-1.27 * 1.27^0) ÷ 0! = 0.281

P(x = 0) = 0.281

Two or fewer problems :

P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)

P(x ≤ 2) = 0.281 + 0.357 + 0.226

P(x ≤ 2) = 0.864

D.) It allows for early detection and thus adequate curtailment of the problem at an a stage in which it seems easier to curb.

2. m < -5

Answer:

Because if you take 18:3 and divide both sides by 3, you will get 6:1

Step-by-step explanation:

Because 18:3 divided by 3 on both sides equals 6:1, also 6:1 times 3 on both sides equals 18:3.

Answer:

There isn’t any question sry

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

You should not base your reasons on a chocolate bar.

Answer:

3.590ft

Step-by-step explanation:

We know what the circumference of the circle is, and we need to find its diameter. Therefore, we need to find an equation that links the two together.

Well, what comes to mind is the fact that the circumeference, [tex]c[/tex], is equal to [tex]\pi[/tex] multiplied by the diameter, [tex]d[/tex]. We can express this like so:

[tex]c = \pi d[/tex].

In this scenario, we know what [tex]c[/tex] is, so we need to rearrange the formula to make [tex]d[/tex] the subject. Dividing both sides by [tex]\pi[/tex] will accomplish this, and gives us:

[tex]\frac{c}{\pi} = d[/tex].

So if we divide the circumference by [tex]\pi[/tex], we will find the diamater. Well,

[tex]\frac{11.277}{\pi} = 3.58958...[/tex]

and so to 3 decimal places we get the answer

[tex]d = 3.590\text{ft}[/tex].

Step-by-step explanation:

i think True

99% wrong 1% right

Answer:

if anyone is looking at this it's warm front is when a warm air mass slides over a cold air mass and stationary front is when a cold air mass and a warm air mass me and do not move and a cold front when a cold air mass slides under a warm air mass and it included front is when two cold fronts force a warm front up and block it from the surface

Warm front formation is different from that of occluded type such that warm air mass rises above a cold air mass during a warm front, but two cold air masses surround a warm air mass during an occluded front.

This can be defined as the transition zone between two different air masses at the Earth's surface.

here, we have,

The warm front and occluded front form under different conditions which is mentioned above and makes option A the most appropriate choice.

so, we get,

Warm front formation is different from that of occluded type such that warm air mass rises above a cold air mass during a warm front, but two cold air masses surround a warm air mass during an occluded front.

Read more about Front formation here

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Complete question:

How is warm front formation different from occluded front formation?

A. A warm air mass rises above a cold air mass during a warm front, but two cold air masses surround a warm air mass during an occluded front.

B. Two cold air masses surround a warm air mass during a warm front, but a cold air mass moves against a warm air mass during an occluded front.

C. A cold air mass moves faster than a warm air mass during a warm front formation, but a cold air mass is pushed upward during an occluded front.

D. A warm air mass and a cold air mass form a boundary during a warm front, but water condenses between two air masses during an occluded front.

Answer:

803%

Step-by-step explanation:

365*2.2

Por ejemplo, vamos a hacer la descomposición factorial en números primos del número 24. Ahora buscamos un número primo que sea divisor de 24. Como 24 es un número par, sabemos que un divisor es 2. ... Dividimos 12 entre 2 y el resultado es 6

Answer:

I dont kn0w try g00gle searches

Answer:

B. M(t)= 5240+240t

Step-by-step explanation:

cause

Answer:

Im not sure but i think its  10.4 if im wrong im so sry

Step-by-step explanation:

Answer:

numbers dont do into math please move this to englash

Step-by-step explanation:

it posted Wong

9514 1404 393

Answer:

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Step-by-step explanation:

The applicable derivative formula is ...

  d(u/v) = (v·du -u·dv)/v²

__

  f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²

  f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

__

Similarly, the second derivative is the derivative of f'(x).

  f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴

  f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Answer:

a) mean =  11.1

b) Standard Deviation = 5.191

Step-by-step explanation:

Given the data in the question;

x = 5.2, 13.8, 8.6, and 16.8

sample n = 4

so;

            x            ( x - mean)²

          5.2             34.81

          13.8            7.29

          8.6             6.25

          16.8            32.49

∑        44.4            80.84

a) Mean

Mean = total sum of the sample divided by the sample size

mean = ∑x / n

we substitute

mean = 44.4 / 4

mean =  11.1

b)

Standard Deviation is the Square root of variance;

Variance = ∑(x-mean)² / n - 1

we substitute from the above table

Variance =  80.81 / 4 - 1

Variance =  80.81 / 3

Variance =  26.94667

now since Standard Deviation is the Square root of variance;

Standard Deviation = √Variance

Standard Deviation = √26.94667

Standard Deviation = 5.191