Answer:
See the explanation below.
Explanation:
Solving the first image question:
C ) The resulting force is defined by Newton's second law which tells us that the sum of the forces on a body is equal to the product of mass by acceleration. That is, there must be a force that acts on a body to produce an acceleration. If there is no acceleration it is because there are no external forces or developed by the body. And if there is no acceleration the body moves at a constant speed, in a straight line, so the response is C.
For the second image, we must remember that weight is defined as the product of mass by gravitational acceleration.
W = m*g
where:
W = weight [N]
m = mass [kg]
g = gravity acceleration [m/s²]
Now we have
m = 50 [kg]
ge = Earth gravity acceleration = 10 [m/s²]
gp = Distant planet gravity acceleration = 4 [m/s²]
We = ge*m
We = 10*50 = 500 [N]
Wp =gp*m
Wp = 4*50 = 200 [N]
Therefore the answer is D
For the third image, The mass is always going to be preserved, regardless of where the body or object is in space, its weight is the only one that changes since the gravitational force is modified. That is, the mass on the moon and on Earth will always be the same.
m = 70 [kg]
First, we must calculate the acceleration, by means of the following equation of kinematics.
[tex]v_{f} =v_{o} +a*t[/tex]
where:
Vf = final velocity = 20 [m/s]
Vo = initial velocity = 0 (because stars from the rest)
a = acceleration [m/s²]
t = time = 4 [s]
20 = 0 + a*4
20 = 4*a
a = 5 [m/s²]
Now using Newton's second law which tells us that the total force acting on a body is equal to the product of mass by acceleration.
F = m*a
where:
F = force [N] (units of Newtons)
m = mass = 2 [kg]
a = acceleration = 5 [m/s²]
F = 2*5
F = 10 [N]
The body of Figure D, since a total force of 25 [N] to the left acts on it, in the rest of cases the force is zero or much less than 25 [N]
50 + 40 - 35 - 30 = F
F = 25 [N]
5. A force probe is used to pull the block with a constant speed. The probe measures a force of
1.8 N. What is the size of the friction force you are pulling with? Explain how you came up
with this answer.
Answer:
Frictional Force = 1.8 N
Explanation:
From Newton's Second Law, we know that the acceleration is produced in an object, whenever an unbalanced force is applied to it. So, for the production of acceleration application of an unbalanced force is necessary. Since, the block is moving with uniform speed in this case. Therefore, there is no acceleration involved in the motion of block. So, the all the forces acting on the block must cancel the effect of each other. So, that there is no unbalanced force to produce any acceleration. Therefore, the frictional force must be equal to the applied force in order to cancel its effect and balance it.
Frictional Force = Applied Force
Frictional Force = 1.8 N
HELP=BRAILIEST+40 POINTS PLS HELP MEEEEEEEEEE
which of the following is not an example transverse wave?
1) X-rays
2) Ocean waves
3) Microwaves
4) Ripples on a pond
5) Hitting a slinky at one end
Answer:
2, Ocean waves
Explanation:
Transverse waves look more like ocean waves, and have the same movement.
How fast is a wave traveling if it has a wavelength of 7 meters and a frequency of 11 Hz?
Answer:
[tex] \huge{ \boxed{ \bold{ \sf{77 \: m/s}}}}[/tex]
☯ Question :
How fast is a wave travelling if it has a wavelength of 7 meters and a frequency of 11 Hz?☯ [tex] \underbrace{ \sf{Required \: Answer : }}[/tex]
☥ Given :
Wavelength ( λ ) = 7 metersFrequency ( f ) = 11 Hz☥ To find :
Speed of sound ( v ) = ?☄ We know ,
[tex] \boxed{ \sf{v = f \times λ}}[/tex]
where ,
v = speed of soundf = frequencyλ = wavelengthNow, substitute the values and solve for v.
➺ [tex] \sf{v = 11 \times 7}[/tex]
➺ [tex] \boxed{ \sf{v = 77 \: m/s}}[/tex]
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✑ Additional Info :
Frequency : The number of complete vibrations made by a particle of a body in one second is called it's frequency. It is denoted by the letter f . The SI unit of frequency is hertz ( Hz ).Wavelength : The distance between two consecutive compressions or rarefactions of a sound wave is called wavelength of that wave. It is denoted by λ ( lambda ) and it's SI unit is m.Speed of a sound wave : The distance covered by a sound wave in one second is called speed of sound wave. It depends on the product of wavelength and frequency of the wave.Hope I helped!
Have a wonderful time! ツ
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Force is measured in what unit? What is this unit equal to in other units?
Answer:
Explanation:
Nnewton=kgm/s²
In 2-3 sentences, explain the difference between constructive and destructive interference.
Plz help!!
Found throughout the nervous system, __________ aid and support the function of neurons.
Answer:
Glia
Explanation:
Answer:
C
Explanation:
Why does an ice cube float on water?
Answer:
Ice cubes float on water because they are less dense.
Explanation:
Ice is about 9% less dense than water. Water is heavier, so ice is lighter, causing it to float. It is less dense because the density of water decreases along with a decrease in temperature. Therefore, causing ice to be less dense than water
A car accelerates at 2.90 m/s2. Assuming the car starts from rest, how much time does it need to accelerate to a speed of 23.6m/s?
Answer:
[tex] \huge{ \boxed{ \bold{ \sf{8.13 \: seconds}}}}[/tex]
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☯ Question
A car accelerates at 2.90 m/s . Assuming the car starts from rest , how much time does it need to accelerate to a speed of 23.6 m/s ?☯[tex] \underbrace{ \sf{Required \: Answer : }}[/tex]
✒ Given :
Initial velocity ( u ) = 0 Final velocity ( v ) = 23.6 m/sAcceleration ( a ) = 2.90 m/s²✒ To find :
Time ( t )✎ We know ,
[tex] \boxed{ \underline{ \sf{acceleration \: (a) \: = \frac{final \: velocity \: (v) - initial \: velocity \: (u )}{time \: ( \: t \: )}}}}[/tex]
Substitute the values :
➵ [tex] \sf{2.90 = \frac{23.6 - 0}{t}} [/tex]
➵ [tex] \sf{2.90 = \frac{23.6}{t}} [/tex]
Apply cross product property
➵ [tex] \sf{2.90 \: t \: = 23.6}[/tex]
Divide both sides by 2.90
➵ [tex] \sf{ \frac{2.90 \: t}{2.90} = \frac{23.6}{2.90} }[/tex]
➵ [tex] \sf{t = 8.13 \: seconds}[/tex]
Hope I helped!
Have a wonderful time シ
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Which of the following is composed of two conductors separated by an insulator? O A. A resistor O B. Light C. A point charge O D. A capacitor
Answer is D. A capacitor
Which statement best explains why light can travel with or without a medium?
A medium is necessary for light waves to travel.
Light waves cannot travel in a vacuum.
Light waves are longitudinal waves that do not require a medium to travel.
Transverse waves do not require a medium to travel.
Answer:
Transverse Waves do not require a medium to travel
Explanation:
Two major types of energy waves are longitudinal waves and transverse waves. A longitudinal wave is a wave where the particles of matter in the medium move in a parallel direction to the motion of the wave. This shows the energy transport and particle movement. The particles of matter only move temporarily. A wave is transferred energy it does not transfer particles of matter. A transverse wave is a wave in which the particles of matter in the medium move in a perpendicular direction to the motion of the wave.
Answer:
Transverse waves do not require a medium to travel.
Explanation:
help asap ill give brainest
Answer:
I would say C
Explanation:
Hope I helped
Answer:
I think it is c
Explanation:
I don't know how to explain it I'm not really the best at explaining things.
A ball is thrown horizontally from the top of a building at 2 m/s. It takes 3 seconds to reach the ground. How far did the ball travel horizontally (dx)?
help please i give brainlyest
D is the correct answer!
Answer; D is the answer
Explanation:
A 1500 kg car is parked at the top of a hill 5.2 m high. What is the velocity of the car, in meters per second, when it reaches the bottom of the hill?
Answer:
Explanation:
The car will fall with acceleration due to gravity which is equal to 9.8 m /s²
For downward fall ,
initial velocity u = o
acceleration due to gravity = g = 9.8 m /s
final velocity v = ?
displacement h = 5.2 m
v² = u² + 2 gh
v² = 0 + 2 x 9.8 x 5.2
= 101.92
v = 10.1 m /s
2. A car is sitting at the top of a hill that is 14 m high. The car has a mass of 53 kg. The car has
energy. Calculate it.
Give a description of of lower mantle
Answer:
The lower mantle is the liquid inner layer of the earth from 400 to 1,800 miles below the surface.
Explanation:
A track star runs 100 meters in 10 seconds. What is the star's average speed?
Answer:
10m/s
Explanation:
Answer: 10
Explanation: Because, 10*10= 100 or 100/10=10
Jupiter, the largest planet in the solar system, has an equatorial radius of about 7.1 x 10^4km (more than 10 times that of Earth). Its period of rotation, however, is only 9h, 50 min. That means that every point on Jupiter's equator "goes around the planet" in that interval of time. Calculate the average speed (in m/s) of an equatorial point during one period of Jupiter's rotation. Is the average velocity different from the average speed in this case?
Answer:
The average speed is [tex]v = 1260 \ km/s[/tex]
The average speed is different from the average velocity in this question
Explanation:
From the question we are told that
The equatorial radius of Jupiter is [tex]R_j = 7.1*10^{4} \ km[/tex]
The period of oscillation of Jupiter is [tex]T_J = 9 \ hours , 50 \ min = 35400 \ seconds[/tex]
Generally the average speed is mathematically represented as
[tex]v = \frac{2 \pi * R_j }{T_J}[/tex]
=> [tex]v = \frac{2 *3.142 * 7.1*10^{4} }{35400}[/tex]
=> [tex]v = 1260 \ km/s[/tex]
Generally in average speed the direction is not considered while in average velocity the direction is considered for the case of this question the movement equitorial point has no direction in that it start from one point and after its periodic motion it still remains at that point
a 3.5 kg mass has an initial velocity of 4.0 m/s. How much force is required to increase the velocity of the mass to 8.0 m/s in 3.0 seconds?
Answer:
4.67 N of force are required
Explanation:
The second Newton's law states the net force exerted on a body of mass m that has an acceleration a, is given by:
F=m.a
On the other hand, the kinematics equations relate the acceleration with the change of speed over time, expressed as:
[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]
We are given the initial speed of vo=4 m/s on a mass of m=3.5 Kg, the final speed of vf=8 m/s which took t=3 seconds.
The acceleration is:
[tex]\displaystyle a=\frac{8-4}{3}=1.33[/tex]
[tex]a=1.33\ m/s^2[/tex]
Thus, the force is:
[tex]F=3.5\ Kg\cdot 1.33\ m/s^2[/tex]
[tex]F=4.67\ N[/tex]
4.67 N of force are required
Medical technologists are developing a new type of pacemaker that, when planted inside a human’s chest, uses electrical impulses to help keep a steady heartbeat. The new design will send warning signals to a patient’s hospital sooner when it detects an upcoming heart problem. In testing so far, this new feature has only worked in about 25% of test patients. How does this product most likely need to be improved before doctors can report that the new technological design is successful? The product needs to better solve the problem for which it was designed. The product needs to become available to the public more quickly. The product needs to become more time effective when it is being built. The product needs to make better use of available building materials.
Answer:
A
Explanation:
got it right on edge 2021 :)
The product needs to better solve the problem for which it was designed ( first option )
After testing the new technology on patients and it showed only 25% success rate ( very low success rate). It is concluded that before Doctors can report that the new technology design is successful is when it better solves the problem for which it was designed for ( i.e. increase in the success rate to > 50% ). because for a procedure to be considered successful for deployment it will need to record a success rate of over 50% of the test patients.
Therefore the product needs to better solve the problem for which it was designed
learn more about medical technology : https://brainly.com/question/1590235
A 2.00 kg ball is thrown upward at some unknown angle from
the top of a 20.0 m high building. If the initial magnitude of the
velocity of the ball is 20.0 m/s. What is the value of total
energy?
Answer: 792J
Explanation:
The value of the total energy will be "792 Joules". To undestand the calculation, check below.
Energy and VelocityAccording to the question,
Mass of ball, m = 2.0 kg
Building's height, h = 20.0 m
Ball's initial velocity, v = 20.0 m/s
We know the formula,
Potential energy (U) = mgh
Kinetic energy (K) = [tex]\frac{1}{2}[/tex] mv²
and,
The total energy be:
= U + K
= mgh + [tex]\frac{1}{2}[/tex] mv²
By substituting the values,
= 2.00 × 9.8 × 20.0 + [tex]\frac{1}{2}[/tex] × 2.00 × (20.0)²
= 392 + 400
= 792 Joules
Thus the above answer is correct.
Find out more information about energy here:
https://brainly.com/question/20562687
4. How long would it take for a water balloon to fall 39 m if we dropped it starting from rest down an
elevator shaft from the 13th floor? Ignore air resistance and use a = -9.8 m/s2.
x, = x + vt + (1/2) a t?
Answer:
Around 2.8212 sec
Explanation:
Given the eqn x=1/2at^2+vot
your vo=0
39=1/2(-9.8)t^2
=7.95=t^2
=2.82sec
HELP!!!
i’ve been stuck at this question for a whole day
True or False: The medium moves up and down in a transverse wave.
A jumbo jet weighing 65,000 kg Is accelerating at 3 m/s^2 while its jet engines are putting out 200000 N of thrust.
How much air drag acts on the craft?
Please, show your work.
Answer:
Fa = 5000 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.
Let's assume that the movement of the plane is to the right, any movement or force to the right will be marked with a positive sign, while any force or movement to the left, will be taken as negative.
The force of the turbine drives the plane to the right, therefore it is positive, the acceleration is constant and keeps the movement to the right, therefore it is positive, the wind drag force tries to prevent the movement of the plane to the left therefore it is negative, with this analysis we deduce the following equation.
ΣF = m*a
where:
ΣF = sum of forces [N] (units of Newtons)
m = mass = 65000 [kg]
a = acceleration = 3 [m/s²]
Fa = force exerted by the air [N]
200000 - Fa = 65000*3
Fa = 200000 - (3*65000)
Fa = 5000 [N]
You see a lightning bolt flash in the distant sky. You hear the corresponding thunder 6.8 seconds later. If the temperature is 28º C, how far away in, kilometers, from you did the lightning strike?
Answer:
[tex]Distance = 2.4\ km[/tex]
Explanation:
Given
[tex]Time (t) = 6.8s[/tex]
[tex]Temperature = 28C[/tex]
Required
Determine the distance at which the lighting struck
First, we need to determine the speed at which the lighting struck because the peed of sound varies with temperature.
At about 28C, the speed of sound is 346m/s
So, we have the following:
[tex]Speed = 346m/s[/tex]
[tex]Time = 6.8s[/tex]
Distance is calculated as thus:
[tex]Distance = Speed * Time[/tex]
[tex]Distance = 346m/s * 6.8s[/tex]
[tex]Distance = 2352.8[/tex]
Divide by 1000 to get distance equivalent in kilometers
[tex]Distance = \frac{2352.8km}{1000}[/tex]
[tex]Distance = 2.3528km[/tex]
[tex]Distance = 2.4\ km[/tex] ---- Approximated
A biker begins to move from an initial speed of 0.0 m/sec to a final speed of 25 m/sec in 10 sec. what is the acceleration of the skater?
1 nm is equal to how many centimeters
Answer:
0,00000001 cm = 1 nm is correct
A 2.5. Gram arrow enters a 100 g apple with a speed of 115 m/s. If the apple was originally at rest, then what speed will it have as the arrow enters it? Remember the formula is P=MxV
Answer:
The speed of the apple will be 2.81 m/s when the arrow enters it.
Explanation:
We can find the speed of the apple by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{ap}v_{ap_{i}} + m_{a}v_{a_{i}} = m_{ap}v_{ap_{f}} + m_{a}v_{a_{f}} [/tex]
Where:
[tex]m_{ap}[/tex] is the mass of the apple = 100 g = 0.1 kg
[tex]m_{a}[/tex] is the mass of the arrow = 2.5 g = 0.0025 kg
[tex]v_{ap_{i}}[/tex] and [tex]v_{ap_{f}}[/tex] is the initial and final speed of the apple respectively
[tex]v_{a_{i}}[/tex] and [tex]v_{a_{f}}[/tex] is the initial and final speed of the arrow respectively
Since the apple was originally at rest ([tex]v_{ap_{i}}[/tex] = 0) and knowing that [tex]v_{a_{f}}[/tex] = [tex]v_{ap_{f}}[/tex] when the arrow enters into the apple, we have:
[tex] 0 + 0.0025 kg*115 m/s = v(0.0025 kg + 0.1 kg) [/tex]
[tex]v = 2.81 m/s[/tex]
Therefore, the speed of the apple will be 2.81 m/s when the arrow enters it.
I hope it helps you!