Help me please guys if you don’t mind

Answer:

The finishing point 4

Step-by-step explanation:

32/8=4

Answer:

DOMAIN

RANGE

Answer:

B. 7.2

Step-by-step explanation:

radius=24÷2= 12

other line =19.2÷2=9.6 because line from centre bisects chord and is perpendicular to it

Therefore: X²=√ 12²-9.6² ( theorem of Pythagoras)

X=7.2

Answer:

Cylinder H has the greater volume.

Step-by-step explanation:

Recall that the volume of a cylinder is given by:

[tex]\displaystyle V=\pi r^2h[/tex]

Where r is the radius and h is the height.

Cylinder H has a radius of 4.5 meters and a height of 3 meters. Thus, its volume is:

[tex]\displaystyle \begin{aligned} V&=\pi(4.5)^2(3)\\&=60.75\pi \\&\approx190.8518\text{ m}^3\end{aligned}[/tex]

Cylinder J has a diameter of 7 meters and a height of 4.5 meters. The radius is half the diameter, so Cylinder J's radius is 3.5 meters. Thus, its volume is:

[tex]\displaystyle \begin{aligned}V&=\pi(3.5)^2(4.5)\\&=55.125\pi \\&\approx 173.1803\text{ m}^3\end{aligned}[/tex]

Thus, Cylinder H has the greater volume.

(9-3)+18÷9

= 6+18÷9

= 6+2

= 8

Answer:

8

Step-by-step explanation:

Well, we need to use order of operations. Since there are parenthesis, we solve what is inside that first. So, 9-3=6. We have solved one part of the equation. There are no exponents so division comes next. 18/9=2. Now we are left with 6+2. 6+2=8. Therefore, your final answer is 8.

Answer: Yes

Step-by-step explanation: Let's first find the missing angle in the second triangle and to find this angle, remember that the sum of the measures of a triangle is 180 degrees so you should find that our missing angle is 67°.

Now, notice that we have two angles and the included side of one triangle

congruent to two angles and the included side of a second triangle.

Therefore, we can say the triangles are congruent by ASA.

Answer:

A,C,D.

Step-by-step explanation:

Answer:

Part A

Group A is a cluster of points with similar property or relationship.

Point B is an outlier. This is the point outside of the common relationship.

Part B

There is a negative tendency. As number of hours spent on computer games increase, the test scores decrease.

Step-by-step explanation:

so basically A, and B

Evelyn and Meredith were paddling at a rate of [tex]\frac{3+\sqrt{493}}{11}mph[/tex] which is equivalent to 2.29mph approximately.

Step 2: See attached picture

Step 3: In this case we only have different variables, there is the rate at which Evelyn and Meredith were paddling, the rate at which they moved when rowing upstream, the rate at which they moved when rowing downstream, the time it took them to paddle upstream and the time it took them to paddle downstream.

v = rate at which Evelyn and Meredith were paddling.

[tex]v_{up}[/tex]= velocity at which they were moving when paddling upstream.

[tex]v_{down}[/tex]= velocity at which they were moving when paddling downstreamstream.

[tex]t_{up}[/tex]= time it took them paddling upstream.

[tex]t_{down}[/tex]= time it took them paddling downstream

Se attached picture for the table.

Step 4: Building this equation will require us to combine different equations into a single one. Let's start with the equation for the final rate at which they paddled when rowing upstream.

[tex]v-2=v_{up}[/tex]

When rowing upstream, the current will drag the kayak, so we subtract it from the rate at which they were rowing.

Let's find the final rat at which they moved when rowing downstream.

[tex]v+2=v{down}[/tex]

next, the problem tells us it took them 3 hours and 40 minutes to row up and down the channel so we can convert it into just hours like this:

[tex]40min*\frac{1hr}{60min}=\frac{2}{3}hr[/tex]

[tex]3hr+\frac{2}{3}hr=\frac{11}{3}hr[/tex]

so now we can build our equation for time.

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

We also know that the rate is built by dividing the distance over the time it took them to travel the distance, so:

[tex]v_{up}=\frac{1}{t_{up}}[/tex]

[tex]v_{down}=\frac{1}{t_{down}}[/tex]

If we solved each of those equations for their respective times, we would end up with the following:

[tex]t_{up}=\frac{1}{v_{up}}[/tex]

[tex]t_{down}=\frac{1}{v_{down}}[/tex]

so we can now combine all the equations together so we get:

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

[tex]\frac{1}{v_{up}}+\frac{1}{v_{down}}=\frac{11}{3}[/tex]

[tex]\frac{1}{v-2}+\frac{1}{v+2}=\frac{11}{3}[/tex]

So this equation models the problem.

Step 5: We can solve this equation by multiplying everything by the LCD

In this case the LCD is:

3(v-2)(v+2)

so, when doing the respective multiplications we end up with:

[tex]\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}[/tex]

We can now simplify to get:

3(v+2)+3(v-2)=11(v+2)(v-2)

We can now do the respective multiplications to get:

[tex]3v+6+3v-6=11(v^{2}-4)[/tex]

and we can further simplify:

[tex]6v=11v^{2}-44[/tex]

Step 5: So we can now solve it by using the quadratic formula, first, we need to rewrite the equation in standard form:

[tex]11v^{2}-6v-44=0[/tex]

So we can now use the quadratic formula:

[tex]v=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

we substitute:

[tex]v=\frac{-(-6) \pm \sqrt{(-6)^{2}-4(11)(-44)}}{2(11)}[/tex]

and simplify:

[tex]v=\frac{6 \pm \sqrt{36+1936}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{1972}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{4(493)}}{22}[/tex]

[tex]v=\frac{6 \pm 2\sqrt{493}}{22}[/tex]

[tex]v=\frac{3 \pm \sqrt{493}}{11}[/tex]

this gives us two possible results:

[tex]v=\frac{3 + \sqrt{493}}{11}[/tex] and [tex]v=\frac{3 - \sqrt{493}}{11}[/tex]

Step 6: We only pick the first result since it's the positive result. We don't take the second one because a negative result represents the kayak moving in the opposite direction which is not how the situation was modeled.

For further information, take a look at the following link:

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Answer:

the answer is D

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Total number of subsets is given as

[tex] {2}^{n} [/tex]

But the subset of a set consists of the proper subsets, an empty set and the set itself.

Total number of subsets are 64

Therefore,

[tex] {2}^{n} = 64[/tex]

[tex] {2}^{n} = {2}^{6} [/tex]

Comparing both sides

[tex]n = 6[/tex]

Answer:

D

Step-by-step explanation:

Answer:

B=45

Step-by-step explanation:

Answer:

thank you for the points

Step-by-step explanation:

Answer:

Patel will require more orange juice = [tex]\frac{371}{660}[/tex] cups

Step-by-step explanation:

Patel needs the orange juice for his family = 3 cups

He needs more orange juice = 3 cups - Sum of juice squeezed from different oranges

[tex]=3-(\frac{13}{15}+\frac{1}{5}+\frac{9}{20}+\frac{5}{11}+\frac{7}{15})[/tex]

L.C.M. of the denominators = 660

[tex]=3-\frac{572+132+297+300+308}{660}[/tex]

[tex]=3-\frac{1609}{660}[/tex]

= [tex]\frac{1980-1609}{660}[/tex]

= [tex]\frac{371}{660}[/tex]

Therefore, amount of orange juice required more = [tex]\frac{371}{660}[/tex] cups

Step-by-step explanation:

149......hshdbhdhsbhsjsusvshhs

Answer:

6 possible intergers brainliest me

Answer:

its 7

Step-by-step explanation:

Answer:

0.25 feet

7.62 centimeters

3 inches

Step-by-step explanation:

Not really a clear question-

witw6oweo6ssitsi5sutaurzhfztzjxisi5

Answer:

B. 13.95 meters

Step-by-step explanation:

The question is just asking you to talk the amount of time taken, and divide it in half.

d= 0.5(27.9)

Answer:

Option A

Step-by-step explanation:

Sarah took 4 days to write a paper.

She wrote 12 pages per day, so total number of pages she wrote in 4 days = 12 × 4

= 48 pages

On day 1, she wrote number of pages = 12

On day 2, she wrote number of pages = 15

On day 3, she wrote number of pages = 9

On day 4, she wrote number of pages = P

She wrote total number pages in 4 days = 12 + 15 + 9 + P

                                                                    = 36 + P

Therefore, P + 36 = 48

P = 48 - 36

P = 12

She wrote 12 pages on day 4.

Option A is the answer.

Step-by-step explanation:

some to check if it correct

The length of the  line segment AB is 8.48 unit.

The term used for identifying the size of an object or the distance from one point to another is known as length.

The length of the line segment having endpoints A (x1, y1) and B (x2, y2) can be determined using the formula,

[tex]AB=\sqrt{(x_{2} ^{2} -x_{1} ^{2} )+(y_{2} ^{2} - y_{1} ^{2} )}[/tex]

Given that x1 = -1, x2= 11, y1= 7, and y2= -1.

Substituting the given values in the above equation

[tex]AB=\sqrt{(11^{2}-(-1)^2 )+((-1)^2-7^2)}[/tex]

[tex]AB=\sqrt{72} = 8.48[/tex]

Hence, 8.48 unit is the length of line segment AB.

To learn more about length, use the link given below:

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Answer:

In step 2, the subtraction property of equality was applied

In step 4, the division property of equality was applied

Step-by-step explanation:

Answer:

It should be option c, [tex]\sqrt 37 - \sqrt26\\\\[/tex]

Step-by-step explanation: i hope this helps

Answer:

The graph is a circle with a radius of 3 and a center of (0,0).

Step-by-step explanation:

Graph

The equation  x² + y² = 9 represents a circle with center (0, 0) and radius = 3

"It is a mathematical statement which consists of equal (=) symbol between two algebraic statements."

"It is a set of points (x, y) which satisfy given equation."

For given question,

We have been given an equation x² + y² = 9

The graph of above equation as shown below.

We know, the equation of the circle with center (0, 0) and radius 'r' is,          x² + y² = r²

We can write given equation as  x² + y² = 3²

Comparing given equation with x² + y² = r² we have r = 3 units

The graph of above equation represents a circle with center (0, 0) and radius = 3

Therefore, the equation  x² + y² = 9 represents a circle with center (0, 0) and radius = 3

Learn more graph of function here:

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Answer:

Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°

Step-by-step explanation:

To find the measure of Angle a, we add 55 and 45, then subtract the sum from 180.

180 - 100 = 80

Angle a is 80°.

Then, we solve for Angle b. Line segment CD is congruent to Line AB, so Angle b is congruent to 55°.

After that, we find Angle c. Line segment AC is congruent to Line segment BD, so Angle c is congruent to 45°.

Lastly, we solve for Angle d using the same method we used for Angle b and Angle c. Angle d is congruent to Angle a, so it measures 80°.

So, Angle a = 80°, Angle b = 55°, Angle c = 45°, Angle d = 80°.

Answer:

I don't understand your question.............!

Step-by-step explanation:

Respuesta:

720 cm³

Explicación paso a paso:

El volumen de un prisma rectangular viene dado por:

V = largo * ancho * alto

Dimensión de la caja de arte = 12 por 20 por 5

Dimensión del borrador = largo * ancho * alto

Volumen del borrador = 2 por 4 por 0,5

Dimensión del estuche de arte que no contiene borrador:

(12 por 20 por 5) - (2 por 4 por 0,5)

(10 por 16 por 4,5)

Volumen de la caja que no contiene borrador:

10 * 16 * 4,5 = 720 cm³

Answer:

[tex]\angle DFE = \angle DFG[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required

What makes DEF and DGF congruent

We have:

[tex]EF = GF[/tex] --- this is indicated by the single line on both sides

Also:

[tex]DF = DF[/tex] --- both triangle share same side

For SAS to be true;

2 sides and 1 angle must be equal in either triangles

So far, we have:

[tex]EF = GF[/tex] ---- S

[tex]DF = DF[/tex] ---- S

The additional to complete the proof is:

[tex]\angle DFE = \angle DFG[/tex] ---- angle between the above sides

Reflection is a type of rigid transformation which requires the turning of an object, shape or figure about a reference point or line. Therefore, the needed additional information is ∠DFE ≅ ∠ DFG. Option B.

Reflection implies turning the given triangle DEF about its side DF, so as to produce an image with the same dimensions but different orientation.

The required proof by Side-Angle-Side (SAS) implies that the relations will be in respect of two of its sides and their included angle.

So that,

GF ≅ FE (given)

DF is the common side to triangles DEF and DFG.

DFG is the included side.

Thus;

∠DFE ≅ ∠ DFG (Side-Angle-Side postulate, SAS)

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Answer:

[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z

Step-by-step explanation:

Given

[tex]$$A _ { 0 } = \{n \in \mathbf { Z } | n = 4 k$$,[/tex] for some integer k[tex]\}[/tex]

[tex]$$A _ { 1 } = \{ n \in \mathbf { Z } | n = 4 k + 1$$,[/tex] for some integer k},

[tex]$$A _ { 2 } = { n \in \mathbf { Z } | n = 4 k + 2$$,[/tex] for some integer k},

and

[tex]$$A _ { 3 } = { n \in \mathbf { Z } | n = 4 k + 3$$,[/tex]for some integer k}.

Required

Is [tex]\{0, 1, 2, 3\}[/tex] a partition of Z

Let

[tex]k = 0[/tex]

So:

[tex]$$A _ { 0 } = 4 k[/tex]

[tex]$$A _ { 0 } = 4 k \to $$A _ { 0 } = 4 * 0 = 0[/tex]

[tex]$$A _ { 1 } = 4 k + 1$$,[/tex]

[tex]A _ { 1 } = 4 *0 + 1$$ \to A_1 = 1[/tex]

[tex]A _ { 2 } = 4 k + 2[/tex]

[tex]A _ { 2} = 4 *0 + 2$$ \to A_2 = 2[/tex]

[tex]A _ { 3 } = 4 k + 3[/tex]

[tex]A _ { 3 } = 4 *0 + 3$$ \to A_3 = 3[/tex]

So, we have:

[tex]\{A_0,A_1,A_2,A_3\} = \{0,1,2,3\}[/tex]

Hence:

[tex]\{0, 1, 2, 3\}[/tex] is a partition of Z