help me frll frll, my test is timed !!!! Which of the following scatterplots would have a trend line with a negative slope?
*y,
1
4.5
5 4
1.5
5.5
2.
4.25
3
25
5
2
3
3.75
1
3.5
3.5
1
2
3 4
5
35
425
Xy,
1
25
5
ا
1.5
3.5
4
2.
4.25
3
O
254 25
27

Help Me Frll Frll, My Test Is Timed !!!! Which Of The Following Scatterplots Would Have A Trend Line

Answers

Answer 1

Answer:

i toke it on edu

Step-by-step explanation:

it is 2

Answer 2

Answer:

c

Step-by-step explanation:


Related Questions

A triangle ABC is right angled at A, AL is perpendicular to BC. Prove that angle BAL= angle BCA.

Answers

Step-by-step explanation:

triangle BCA=BAL bcoz Angle BCA= Angle BAL

The question is in the photo

Answers

Answer:

Step-by-step explanation:

This is a right triangle because angle V is 90. Draw out a right triangle and put V at the 90 degree angle. It doesn't matter where you put U or T; you get the same cos value for T regardless of how you place your other 2 angles. The things you need to know are that UT is the hypotenuse of the triangle, side VU is across from angle T, and side TV is across from angle U.

The cos ratio is side adjacent to the reference angle over the hypotenuse.

Our reference angle is T, so we are looking for the side next to T that is NOT the hypotenuse. This side measures 33; the hypotenuse measures 65, so the tangent ratio of T is

[tex]tanT=\frac{33}{65}[/tex]

Determine if the sequence below is arithmetic or geometric and determine the common difference / ratio in simplest form.
19,10,1,...

Answers

[tex]\displaystyle\bf \underbrace{19}_910{\underbrace{1}_9} \Longrightarrow This\: is \:an \:\:arithmetic\:\: progression[/tex]

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

Answers

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

AABC has vertices at A(5,1), B(-3,1), and C(-2,5).
Point D is located on the intersection of the altitude and AB, in such a way that D has coordinates at
(-2,1).

Answers

AC and the length BC.
The length of AB is 7

Select "equivalent" or "not equivalent" to indicate whether the expression above is equivalent or not equivalent to the values or expressions in the last column.

Answers

Answer:

equivalent

Step-by-step explanation:

If < A and < B are a linear pair, and < A = 68 °, then < B = _____.

Select one:
a. 68 °
b. 112 °
c. 101 °
d. 90 °

Answers

Answer:

Option b, 112°

Step-by-step explanation:

<A+<B=180

or, 68+<B=180

or, <B=112

Answered by GAUTHMATH

Find the greatest common factor of the
following monomials:
30a^4b^4 28a^6b^5

Answers

The answer is 2a^4b^4, hope this helps

Circle w has a radius of 20 in and central right angle. VWX find the length of VX. Leave answer in terms of pi

Answers

The arc length is 10 Pi

(I don't know for sure, but its what I got)

Find the 66th term of the arithmetic sequence 25, 10, -5, ...

Answers

Answer:

1000

Step-by-step explanation:

Given data

we have the sequence

25, 10, -5, ...

we want to find the 66th term, let us apply the formula

an = a + (n – 1)d

a= 25

n= 66

d= 15

substitute

a66= 25+(66-1)15

a66= 25+(65)*15

a66= 25+975

a66= 1000

Hence the 66th term is 1000

Factorise this equasion
X^2-5



Answers

Answer:

(x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Step-by-step explanation:

x² - 5 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b) , then

x² - 5

= x² - ([tex]\sqrt{5}[/tex] )²

= (x - [tex]\sqrt{5}[/tex] )(x + [tex]\sqrt{5}[/tex] )

Which function is graphed below?

algebra 2

Answers

Answer:

x=0..............................

It is an exponential decay curve.
The general form of these is y = k.a^x where 0 < a < 1 [negative values for a are much more complicated]
Some key points can be read from the graph - (0, 3) (1, 1) and less accurately (-1, 9) and (2, 1/3)
This points the the equation y = 3(1/3)^x

Which expression is equivalent to −10x−10+2x+9?

Answers

Answer:

-8x - 1

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

-10x - 10 + 2x + 9

Step 2: Simplify

Combine like terms (x):                                                                                        -8x - 10 + 9Combine like term:                                                                                              -8x - 1

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{-10x - 10 + 2x + 9}[/tex]

[tex]\huge\textsf{COMBINE the LIKE TERMS}[/tex]

[tex]\large\textsf{-10x + 2x - 10 + 9}[/tex]

[tex]\large\textsf{-10x + 2x}\\\\\large\textsf{ = \bf -8x}[/tex]

[tex]\large\textsf{-10 + 9}\\\\\large\textsf{ = \bf -1}[/tex]

[tex]\boxed{= \large\textsf{\bf -8x - 1}}\large\checkmark[/tex]

[tex]\boxed{\boxed{\huge\textsf{Answer: \bf -8x - 1 }}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

proportional linear relationships can be represented in how many different forms

Answers

Linear relationships can be represented in several different ways: a graph, an equation, or a list of points. ... We can then graph the line to find the y-intercept, and use the slope and y-intercept to write an equation of the line.

Proportional Linear Relationships can be expressed in the following ways:

a graphan equation, or a list of points.

What is a proportional linear relationship?

From a graphical point of view, a relationship is proportional and linear if the line representing the equation goes via the origin. It is to be noted that a relationship must be linear for it to be proportional and vice versa.

Thus, it is correct to state that Proportional Linear Relationships can be expressed in the following ways:

a graphan equation, or a list of points.

An example of an equation that is proportional and linear is:
y = 6x + 8. Note that this linear equation is proportional because it has a constant component.

Learn more about the proportional linear relationships at;
https://brainly.com/question/2143065
#SPJ6

5. Nicholas bought a map of a city. It uses a scale of 1 inch to 8 miles.
Nicholas's house and school are 1/2 inches apart on the map. How far apart
would his house and school be on the map if the scale was 1 inch to 6 miles?
What’s the answer to this?

Answers

Scale is 1 inch to 6 mile.

So, ½ inch = 6 mile/2 = 3 mile

The graph of y=x^3+x^2-6x is shown....

Answers

hello,

" a turning point is defined as the point where a graph changes from either  increasing to decreasing, or  decreasing to increasing"

a)

[tex]y=x^3+x^2-6x\\\\y'=3x^2+2x-6=0\\x=\dfrac{-2-\sqrt{76} }{6} \approx{-1.786299647...}\\or\\x=\dfrac{-2+\sqrt{76} }{6} \approx{1.1196329...}\\[/tex]

b)

Zeros are -3,0,2.

Sol={-3,0,2}

The solution of the graph function y=x³+x²-6x are -3 , 0 and 2

What is graph?

The link between lines and points is described by a graph, which is a mathematical description of a network. A graph is made up of certain points and the connecting lines. It doesn't matter how long the lines are or where the points are located. A node is the name for each element in a graph.

We have the function

y=x³+x²-6x

now, equating it to 0

x³+x²-6x = 0

x² + x - 6= 0

x² - 3x + 2x -6 =0

x(x -3) + 2(x -3)

x= 3 and -2

Now, ew can see from the that the equation is touching the x-axis at three points and it will represent three zeroes of the equation.

So, the solution of the graph are -3 , 0 and 2

Learn more about graph here:

https://brainly.com/question/17267403

#SPJ2

the sum of all the exponents on all the variables of a term
plsss answer

Answers

Answer:

Answer: for polynomials in two or more variables, the degree of a term is the sum of the exponents of the variables in the term; the degree (sometimes called the total degree) of the polynomial is again the maximum of the degrees of all terms in the polynomial

Find the circumference of this circle
using 3 for TT.
C = ?

Answers

[tex]{ \bf{ \underbrace{Given}}}[/tex]:

Diameter of the circle "[tex]d[/tex]" = [tex]36[/tex]

Value of [tex]π[/tex] = [tex]3[/tex]

[tex]{ \bf{ \underbrace{To\:find}}}[/tex]:

The circumference "[tex]C[/tex]" of the circle.

[tex]{ \bf{ \underbrace{Solution }}}[/tex]:

[tex]\sf\pink{The\:circumference \:"C"\:of\:the\:circle\:is\:108.}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]

We know that,

[tex]\sf\purple{Circumference\:of\:a\:circle \:=\:πd }[/tex]

[tex] = 3 \times 36[/tex]

[tex] = 108[/tex]

Therefore, the circumference of the circle is [tex]108[/tex].

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

Answer:

[tex]\Longrightarrow: \boxed{\sf{108}}[/tex]

Step-by-step explanation:

Apply the formula for the circle's circumference.

[tex]\text{Circumference circle formula:}[/tex]

[tex]\Longrightarrow: \sf{C=\pi d}[/tex]

[tex]\Longrightarrow:\sf{C=?}\\\\\Longrightarrow:\sf{\pi =3}\\\\\Longrightarrow:\sf{d=36}[/tex]

Multiply.

[tex]\sf{3*36=\boxed{\sf{108}}[/tex]

Therefore, the correct answer is 108.

I hope this helps! Let me know if you have any questions.

id like some help here... if possible.

Answers

Answer:

use average seep hours

top = 77/12 = 6.4 (most)

middle = 6 (middle)

bottom = 50/9 = 5.5 (least)

Step-by-step explanation:

How would the one-step equation x/5 = 5 be solved?


Multiply both sides by 1/5


Multiply both sides by the reciprocal of 1/5


Divide 5 by both sides


Divide one side by 5

Answers

Multiply both sides by the reciprocal of 1/5

Answer:

2nd option

Step-by-step explanation:

Given

[tex]\frac{x}{5}[/tex] = 5 ( multiply both sides by 5, the reciprocal of [tex]\frac{1}{5}[/tex] to clear the fraction )

x = 25

____ more than 3455 is two hundred seventy -eight thousand five hundred eighty three​

Answers

I think it’s 275,128

Answer:

275,128

Step-by-step explanation:

"___ more than 3455" is the same as saying "___ added to 3455"

So it will look something like this:

___ + 3,455 = 278,583

Then rearrange the equation to use subtraction to solve it:

278,583 - 3,455 = ____

Plug it in the calculator or solve it by hand, and you have your answer!

(To double check, add 3,455 and 275,128, and you get 278,583)

Hope it helps (●'◡'●)

Which of the following shows 5x + 17 + 8x – 9 + 2y in simplest terms?

Answers

Answer:

5x+8x+17-9+2y

13x+8+2y

Answer:

13x+8+2y

Step-by-step explanation:

5x+8x=13x

17–9=8

2y=2y

What is the slope of the line? What is the y-intercept of the line? y = 2x + 5

Answers

Slope intercept form of a line is, y = mx + c where m is the slope and c is constant.

Judging the given equation y = 2x + 5

Slope (m) of the line is 2,

y-intercept of the line,

y = 2x + 5

y = 2×0 + 5

y = 5

Answered by GAUTHMATH

Answer:

m = 2

y intercept = 5

Step-by-step explanation:

The given equation of the line is ,

[tex]\implies y = 2x +5[/tex]

We know that the Standard equation of Slope Intercept Form of the line is,

[tex]\implies y = mx + c[/tex]

Where ,

m is slope c is y intercept

On comparing to the Standard form of the line we get ,

[tex]\implies Slope = 2 [/tex]

[tex]\implies y - intercept= 5[/tex]

If a car is moving on a straight line with a velocity of 40 m/s and it changes its velocity to 60 m/s in 4 seconds, calculate its acceleration.

Answers

Answer:

5m/s²

Step-by-step explanation:

Given :-

Initial Velocity = 40m/s Final velocity = 60 m/sTime = 4s

To Find :-

The acceleration .

Solution :-

We know that the rate of change of velocity is called acceleration. Therefore ,

[tex]\sf\implies a = v - u / t \\ [/tex]

[tex]\sf\implies a = 60m/s - 40m/s/ 4 \\ [/tex]

[tex]\sf\implies a = 20m/s \div 4 \\[/tex]

[tex]\bf\implies a = 5m/s^2[/tex]

help me pls i don't ge this

Answers

Answer:

9. The area of rectangle S is four times bigger than rectangle R

10. (1, 3)

Step-by-step explanation:

To find the solution of the two linear equations:

y=x+2

y=-2x+5

x+2=y=-2x+5

3x=3

x=1

y=1+2

y=3

(1,3)

Evaluate the function. f(x)=3x^2 −4x Find f(−1)

Answers

Answer:

7

Step-by-step explanation:

evaluate the function means substitute x=-1 and calculate

f(x) = 3x²-4x

f(-1) =f(x=-1) = 3(-1)²-4(-1) =3+4 =7, because (-1)²=1 and -4(-1) =4

Of the four choices given, which two, when written as a system, have a solution of (-4,5)?
х
-1
2
3
5
y
2
-1
-2
-4
2x+y=-3
-2x+y=-3
Х
-1
2.
3
7
0
-3
4
-8
2x+y=-3 and
Х
--1
2
3
5
y
2.
-1
-2
-4
0-2x+y=-3 and
х
-1
2
3
5
у
2.
-1
-2
-4

Answers

Answer:

both choices with 2x+y = -3

Step-by-step explanation:

to have the solution (-4, 5), that point must be on both equations/functions, meaning it must be on either one.

in other words, if the point is not on at least one of the functions, it cannot be a solution for that system.

the given function

2x + y = -3

looks like for the point (-4, 5)

2×-4 + 5 = -3

-8 + 5 = -3

-3 = -3

correct.

but

-2x + y = -3

looks like for (-4, 5)

-2×-4 + 5 = -3

8 + 5 = -3

13 = -3

wrong. the point is not on this function.

as we can therefore rule out 2 of the answer options, the other 2 most be correct.

The two equations which when written as a system has a solution of (-4, 5) is; 2x + y = -3 and 2x + y = -3

Inequalities

The correct equations must have same output with the given one when we place -4 and 5 for x and y respectively.

Now, for 2x + y = -3

At x = -4, and y = 5 we have;

2(-4) + 5 = -3

Same with the right hand side.

For -2x + y = -3;

At x = -4, and y = 5 we have;

-2(-4) + 5 = 13

Not the same with the right hand side.

Thus, the two equations with 2x + y = -3 are correct

Read more about Inequalities at; https://brainly.com/question/24372553

What is the distance between
(

5
,

5
)
(−5,−5)left parenthesis, minus, 5, comma, minus, 5, right parenthesis and
(

9
,

2
)
(−9,−2)left parenthesis, minus, 9, comma, minus, 2, right parenthesis?

Answers

Answer:

do you have a pic of the problem

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

the answer is the sqare rute of 25 which is 5

The width of a rectangle is (2x – 7)inches and its width is (x^2 – 5) inches. Find an expression for the perimeter of the rectangle.
a. 2x^3 + 35
b. x^2 - 2x + 2
c. x^2 + 2x – 12
d. 2x^2 + 4x – 24

Answers

Answer:

(2x²+4x-24) in.

Step-by-step explanation:

.

the answer is D you’re welcome

These points are linear. Find
the slope.
x1234 5/6
y 0 48 12 16 20

Answers

Answer:

m = 4

Step-by-step explanation:

The slope for the linear points is given by :

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have,

y₂ = 4, y₁ = 0, x₂ = 2, x₁ = 1

Putting all the values,

[tex]m=\dfrac{4-0}{2-1}\\\\\implies m=\dfrac{4}{1}\\\\m=4[/tex]

So, the slope of the line is equal to 4.

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