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Physics Word Problem

An archer shoots an arrow at a 75 m distant target; the bull’s-eye of the target is at same height as the release height of the arrow. If d = 75 m and v = 37 m/s. At what angle must the arrow be released to hit the bull’s-eye if its initial speed is 37m/s?

Electron flow out of the negative terminal, through the circuit and into the positive terminal of the source is accurate about Electron flow.

Electron flow is the current produced by the movement of free electrons moving along a positive terminal; the direction of electron flow is opposite to that of current.

Electron flow out of the negative terminal, through the circuit and into the positive terminal of the source.

Therefore, Electron flow out of the negative terminal, through the circuit and into the positive terminal of the source is accurate about Electron flow.

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Answer: 0.28 m/s (1 km/hr)

Explanation:

This is an inelastic conservation of momentum question.

First, convert the speed to m/s: 3 km/hr (1000m/1km)(1hr/3600s) = .83 m/s

Then, Momentum before = Momentum after;

Momentum before = m1v1 + m2v2 = 4000(.83) + 8000(0)

Momentum after: (m1 + m2)v3 → (4000 + 8000)v3

Set these equal: 4000(.83) = 12000v3 and solve to get: v3=.28 m/s :)

Answer:

I LOVED that show when I was 10

Explanation:

Answer: I want to learn about Raid Shadow Legends

Explanation: Please Mark Brainliest W!

Answer:

It depends...

Explanation:

If you know how much watts the pair of hair straighteners use, you can use that as the energy every second. A normal flat iron for hair would be 300 watts, so we could say that it uses 300 jolts or watts of energy per second.

Based on the first law of thermodynamics, the energy gained by a system is equal to the energy lost by the surroundings.

The laws of thermodynamics can be summarised as follow

From the laws given above precisely the first law, we can conclude that the energy gained by a system is equal to the energy lost by the surroundings

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Answer:

2512.8 meters

Explanation:

s=d/t

by using speed formula

The decarboxylation reaction involves the removal and replacement of a carboxyl group with hydrogen.

A decarboxylation reaction is one in which the carboxyl group in a carboxylic acid is replaced with hydrogen.

In living organisms, decarboxylation reactions are catalyzed by enzymes called decarboxylases or carboxy-lyases.

The decarboxylation of beta-carbonyl esters proceeds through a cyclic transition state giving an enol intermediate which then tautomerises to the carbonyl.

Therefore, a decarboxylation reaction involves the removal and replacement of a carboxyl group with hydrogen.

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The decarboxylation reaction is given with the removal of the carbon dioxide from the carboxyl group.

The carboxyl group is the attachment of the OH and the =O functional group to the carbon atom.

In the decarboxylation reaction, there has been the removal of the carbon dioxide and the carboxyl group is replaces with the Hydrogen atom.

The decarboxylation reaction for the given reactant with the missing groups is given in the image attached.

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Answer:

false

Explanation:

it moves from positive to negative

Two equations will be needed to solve for the energy used in this procedure.

This is defined as the ability or capacity to do work. Ice being converted to vapor requires energy and the equations are seen below:

H₂O₍s₎  ⇒ H₂O₍l₎

H₂O₍l₎ ⇒ H₂O₍g₎

These are the equations which are used to calculate energy with heat being involved in both reactions.

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Answer:

A, B, C, E

Explanation:

Who wants to be shipped out, am I right?

Answer:

It would be equal pay, equal treatment, access to credit

AND access to higher education.

Explanation:

Hope this helps you!!!!

Answer:

B, A, A, B

Explanation:

Just trust me on this one.

Answer:

apple fall on his head, then he discovers gravity. Law of motion

Explanation:

Answer:

gravity is the theory of Newton.

Explanation:

The reason for this is because one day he was sitting under the apple tree and an apple fell on top of his head. So he wanted to figure out what had caused the apple to fall on his head.

Answer:

Barium nitrate

Answer:

I for a rod about its center is I = M L^2 / 12

A = L (1/2 - 1/3) = L / 6     distance from middle to location L/3

A^2 = L^2 / 36

I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9

I about given location by parallel axis theorem

Answer:

SD

Explanation:

Answer:

E = 1/2 K x^2        (1/2 *F * x * x)

E = 2300 / 2 N/m * (.18 m)^2 = 37.3 Joules

The quantity of elastic potential energy that is currently stored in the system is equal to 37.26 Joules (J).

We may use the formula for elastic potential energy to compute the amount of elastic potential energy that is stored in the system, which is as follows:

PE, or Elastic Potential Energy, is 0.5 times k times x squared.

where k represents the constant force that the spring exerts and x represents the amount of compression that the spring experiences.

Given:

The spring has a force constant of 2300 Newton-meters (k).

The spring was compressed (x) by 18.0 centimetres, which is equivalent to 0.18 metres when measured in metres.

To finish, enter the values into the formula as follows:

PE = 0.5 × 2300 N/m × (0.18 m)² PE = 0.5 × 2300 N/m × 0.0324 m² PE = 37.26 J

37.26 Joules (J) is the amount of elastic potential energy that is stored in the system.

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The electric potential energy of the charge will be =3.5*10^8 J  

Electric potential energy is the energy that is needed to move a charge against an electric field.

F=Force experienced by the charge = 3.6*10^-4 N

q1 = magnitude of charge producing the electric field

q2 = magnitude of charge experiencing the electric force

r1 = distance between the two charges

Electric force experienced by the charge is given using coulomb's law as

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]

[tex]3.6\times 10^{-4}=\dfrac{9\times 10^9 q_1q_2}{(9.8\times 10^{-5})^2}[/tex]

[tex]q_1q_2=3.84\times 10^{-22}[/tex]

Electric potential energy of the charge can be given as

[tex]U=\dfrac{kq_1q_2}{r}[/tex]

[tex]U=\dfrac{(9\times 10^9)q_1q_2}{(9.8\times 10^{-5})^2}[/tex]

[tex]U=3.5\times 10^{-8}\ J[/tex]

Thus Electric potential energy of the charge can be given as [tex]U=3.5\times 10^{-8}\ J[/tex]

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Hi there!

We can use Ohm's law to solve:
[tex]V = IR[/tex]

V = Potential Difference (V)
I = Current (A)
R = Resistance (Ω)

We can rearrange the equation to solve for resistance:

[tex]R = \frac{V}{I}[/tex]

Plug in the given values to solve.  

[tex]R = \frac{10}{2} = \boxed{5 \Omega}[/tex]

Answer:

12.5 m/s

Explanation:

By conservation of momentum, we have that:
[tex]\displaystyle m_1v_1 + m_2v_2 = m_1v_1' + m_2v_2'[/tex]

Because the two objects combine after collision, they will have the same velocity:

[tex]\displaystyle m_1v_1 + m_2v_2 = (m_1+m_2)v_f[/tex]

Substitute and solve for final velocity:

[tex]\displaystyle \begin{aligned} (50 \text{ kg})(15\text{ m/s}) + (50\text{ kg})(10\text{ m/s}) & = ((50+50)\text{ kg})v_f \\ \\ v_f & = 12.5\text{ m/s}\end{aligned}[/tex]

In conclusion, the final velocity of the system will be 12.5 m/s.

Answer:

B. Energy

Explanation:

Sound is a kind of energy. In physics, sound is seen as anenergy that is generated through vibrations

Answer:

Energy

Explanation:

Explanation:

a= -5m/s^2 t=2s

a= v-u

-------

t

at=v-u

(-5x2)

= -10m/s

The net torque on this system is (ml2g-ml1g)k

This refers to the type of force that causes rotation in objects which has mass and is a twisting force

Based on the complete question, we can see the given parameters:

The torque due to farther mass above the pivot is ml2gk

The torque due to nearer mass about the pivot is ml1gk

Therefore, the net torque is (ml2g-ml1g)k

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The net torque on this system in which two blocks each of mass m are attached to the ends of a massless rod, above pivot, is (ml₂g-ml_₁g)\hat k.

The torque of a body is the rate of change of angular momentum of the body. Torque is the product of moment of inertia and the angular acceleration.[tex]\tau =I\times \alpha[/tex][tex]\tau=mlg[/tex]

Here, (I) is the moment of inertia and (α) is the angular acceleration.

Two blocks each of the mass m are attached to the ends of a massless rod which pivots as shown in fig.

Initially, the rod is held in the horizontal position and then released. When, the mass was kept at farther to pivot, then the value of torque is,

[tex]\tau=ml_2g\hat k[/tex]

When, the mass was kept at nearer to pivot, then the value of torque is,

[tex]\tau=-ml_1g\hat k[/tex]

Thus, the net torque on this system above pivot is,

[tex]\tau=ml_2g\hat k+(-ml_2g\hat k)\\\tau=(ml_2g-ml_1g)\hat k[/tex]

Thus, the net torque on this system in which two blocks each of mass m are attached to the ends of a massless rod, above pivot is (ml₂g-ml_₁g)\hat k.

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Answer:

Planets that are farther from the sun than the earth (all but Mercury and Venus) will exhibit retrograde motion.

If the position of the planet is observed relative to the background stars, the planet will appear to move backward relative to the stars when the earth is moving in an Eastward direction faster than the planet, and the planet appears to move backwards relative to the stars

(The planet will be on the side of the earth that is opposite that of the sun)

Answer: .0380575J

Explanation:

The coffee filter originally only had potential energy, which can be found by:

PE = m * g * h → PE = .0013 * 9.8 * 3 = .03822 J

*Note the mass must be in kg!!!

All of this energy should be converted to kinetic energy, but the air molecules take some of the energy; the energy they gain can be found by finding how much energy the filter has at the bottom of its fall, and subtracting this from the original energy to see how much was lost;

All of the energy at the bottom equals kinetic energy, which can be found by:

KE = 1/2 * m * v^2 → KE = 1/2 * .0013 * .5^2 = .0001625 J

Thus, the air gained .03822 - .0001625 = .0380575J :)

Answer:

That's Rontgen

Explanation:

Wilhem Rontgen

The heat will flow towards the air surrounding the soup bowl and towards the countertop below the bowl.

We know that when two bodies of different temperatures there will be a flow of heat between the objects, from the hotter one to the colder one.

In this case, we have the bowl of soup as the hot object, and the ambient (the countertop, the air surrounding the bowl, etc) itself will be the cooler object.

Then the heat will flow towards the air surrounding the soup bowl and towards the countertop below the bowl.

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