HELP FAST 100 PTS Calculate the amount of heat needed to raise the temperature of 96 g of water vapor from 124 °C to 158 °C. must provide explanation

Answers

Answer 1

Answer:

[tex]\huge\boxed{\sf Q = 13.7\ Joules}[/tex]

Explanation:

Given Data:

Mass = m = 96 g = 0.096 kg

[tex]T_1[/tex] = 124 °C

[tex]T_2[/tex] = 158 °C

Change in Temp. = ΔT = 158 - 124 = 34 °C

Specific Heat Constant = c = 4.186 J/g °C

Required:

Specific Heat Capacity = Q = ?

Formula:

Q = mcΔT

Solution:

Q = (0.096)(4.186)(34)

Q = 13.7 Joules

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

Answer 2

Answer:

[tex]\Large \boxed{\sf 13600 \ J}[/tex]

Explanation:

Use formula

[tex]\displaystyle \sf Heat \ (J)=mass \ (g) \times specific \ heat \ capacity \ (Jg^{-1}\°C^{-1}) \times change \ in \ temperature \ (\°C)[/tex]

Specific heat capacity of water is 4.18 J/(g °C)

Substitute the values in formula and evaluate

[tex]\displaystyle \sf Heat \ (J)=96 \ g \times 4.18 \ Jg^{-1}\°C^{-1} \times (158\°C-124 \°C)[/tex]

[tex]\displaystyle Q=96 \times 4.18 \times (158-124 )=13643.52[/tex]


Related Questions

Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?

Answers

Answer:

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Explanation:

The Boyle's Law is represented by the following expression:

[tex]P\cdot V = k[/tex] (1)

Where:

[tex]P[/tex] - Pressure, in kilopascals.

[tex]V[/tex] - Volume, in cubic centimeters.

[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.

By definitions of rate of change and implicit differentiation, we derive the following differential equation:

[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)

Where:

[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.

[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.

Then, we clear the rate of change of the volume within (2):

[tex]P\cdot \dot V = -\dot P\cdot V[/tex]

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:

[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]

[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]

The gas is decreasing at a rate of 50 cubic centimeters per minute.

Is the Swedish timber industry more likely a result of good resource availability or a lack of trees elsewhere on Earth?

Answers

Answer:

The forest products industry plays a major role in the Swedish economy, and accounts for between nine and 12 percent of Swedish industry's total employment, exports, sales and added value. It includes companies within the pulp and paper industry, as well as the wood-mechanical industry.

is sublimation exothermic or endothermic

Answers

Answer:

endormic

Explanation:

It occurs at a temperature and pressures below a substance's triple point on its phase diagram, which corresponds to the lowest pressure at which the substance can exist as a liquid

How many grams are in 1.2 x 1024 atoms of sodium?

Answers

Answer:

46 g

Explanation:

First we convert 1.2 x 10²⁴ atoms of sodium into moles, using Avogadro's number:

1.2x10²⁴ atoms ÷ 6.023x10²³ atoms/mol = 2.0 mol

Then we convert 2.0 moles of sodium into grams, using sodium's molar mass:

2.0 mol Na * 23 g/mol = 46 g

Thus, there are 46 grams in 1.2x10²⁴ atoms of sodium.

If 0.000066 moles of 0.01 M solution of carbonic acid dissociates, then what is Ka of carbonic acid

Answers

Answer: 4.4 x 10^-7

Explanation:

0.000066 x 0.0000066 / 0.01

= 4.4 x 10^-7

To prepare a buffer solution with a pH of 4.1, which acid should be used?
glycine: pka = 2.35
benzoic acid: pka = 4.19
hydrobromous: pKa = 8.7

Answers

Answer:

benzoic acid: pka = 4.19

Explanation:

What are ALL full chemical reactions that ensue for each of the following disinfectants (may be more than one for each): (5 points) Cl2 (g) at pH 9

Answers

Answer:

The reactions that might ensue are

Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ----------  > HOCl + HCl

 HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)

Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl

Explanation:

The Disinfectant Given is

CI2 (g) at PH 9

Determine the chemical reactions that might ensue

due to the High concentration of [tex]H^{+} (aq)[/tex] the formation of [tex]OCI^-[/tex](aq) will be better and this will decrease the power of the disinfectant.

Hence the chemical reactions that might ensue can be represented below as :

Cl[tex]_{2}[/tex](g) + H[tex]_{2}[/tex]O ----------  > HOCl + HCl

            HOCl -------- > [tex]H^+[/tex](aq) + O[tex]CI^-[/tex](aq)

Cl2(g) + [tex]OH^-[/tex](aq) ----- > O[tex]CI^-[/tex](aq) + HCl

Select the description of a galvanic (voltaic) cell. An electrochemical cell that uses electricity to produce an oxidation-reduction reaction. An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction. One-half of an electrochemical cell in which either oxidation or reduction occurs. Connects the two half-cells in an electrochemical cell to maintain electrical neutrality.

Answers

Answer:  An electrochemical cell that produces electricity from a spontaneous oxidation-reduction reaction

Explanation:

Galvanic cell is a device which is used for the conversion of the chemical energy produced in a redox reaction into the electrical energy.

Galvanic cell consists of two half cells known as anode and cathode. Oxidation takes place at anode and reduction takes place at cathode. The two half cells are connected by a salt bridge which contains an electrolyte which maintains the electrical neutrality.

Write a structural formula for each of the following: (a) 3-Methylcyclobutene (b) 1-Methylcyclopentene (c) 2,3-Dimethyl-2-pentene (d) (Z)-3-Hexene (e) (E)-2-Pentene (f) 3,3,3-Tribromopropene (g) (Z,4R)-4-Methyl-2-hexene (h) (E,4S )-4-Chloro-2-pentene (i) (Z)-1-Cyclopropyl-1-pentene (j) 5-Cyclobutyl-1-pentene (k) (R)-4-Chloro-2-pentyne (l) (E)-4-Methylhex-4-en-1-yne

Answers

Answer:

Attached below

Explanation:

(a) 3-Methylcyclobutene

(b) 1-Methylcyclopentene

(c) 2,3-Dimethyl-2-pentene

(d) (Z)-3-Hexene  

(e) (E)-2-Pentene

(f) 3,3,3-Tribromopropene

(g) (Z,4R)-4-Methyl-2-hexene

(h) (E,4S )-4-Chloro-2-pentene

(i) (Z)-1-Cyclopropyl-1-pentene

(j) 5-Cyclobutyl-1-pentene

(k) (R)-4-Chloro-2-pentyne

(l) (E)-4-Methylhex-4-en-1-yne

The structural formula of a compound ( chemical ) is the representation of the molecular structure of the compounds ( i.e. it shows how the atoms in the compound is arranged, also the chemical bonding within the molecules are represented as well.

Calculate the molarity of a solution that contains 3.00x10-2 mol NH4Cl in exactly 450 cm3 of solution.

Answers

Answer:

0.06moles/litres

Explanation:

molarity = no of moles / volume in litres = 3.00*10^-2/(450/1000)=0.06 moles/litres

Answer:

0.07mol/dm^3

Explanation:

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2.0M Propionic Acid HC3H5O2 Dissolves In Distilled Water. If It Has A Ka Of 1.3*10-5, What Is The Final PH?

The base ethylamine C2H5NH2 has a Kb of 5.6*10-4. What will the pH be in .53 molar solution?

Answers

Answer: first you have to calculate the amount ionized. We will say it is x mol / L

then % ionization = (amount ionized / initial concentration) * 100%

x can be calculated using an ice chart

HC3H5O2           -----> H+    + C3H5O2-

Initial HC3H5O2 = 0.250  

change              = -x

equilibrium         = 0.250 - x

initial H+            = 0

change              = +x

equilibrium         = x

C3H5O2- initial   = 0

change              = +x

equilibrium         = x

Ka         = [H=][C3H5O2-] / HC3H5O2]

 1.3 * 10 ^ -5    = [x][x] / (0.250 - x)  

So 1.3 * 10 ^ -5 * (0.250 - x)   = x ^ 2  

     3.25 * 10^ -6 - (1.3 * 10^-5)x = x^2   now this is a quadratic equation and you have to rearrange it and solve for x

x^2 + 1.3 * 10^-5)x - 3.25 * 10^ -6 = 0

use the equation x = {-b (+ or -)[b^2 - 4.a.c] ^ 1/2} / 2a

you should get x = 1.80 * 10 ^ -3 or x = -1.80* 10^-3

but x can not be negative..

so x = 1.80 * 10 ^ -3

so percent ionization = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

the other way which is more easier is  

assuming that x is very small and therefore 0.250 - x is approximately equals to 0.250  

then 1.3 * 10^-5 = x^2 / 0.250

so x^2    = 1.3 * 10^-5 * 0.250

        x   = 1.80 * 10 ^-3

then percent ionization is = (1.80 * 10 ^ -3 / 0.250) * 100%

                               =0.72 %

if the percent ionization is > 5 % you can not do that approximation. in such a case you have to solve the quadratic equation. that is why I showed both methods.

now you can do the parts b and c

b answer : percent ionization = 1.27 %  

c answer : 2.54%

good luck

Calculate the pH of a 4.988 M solution of ascorbic acid, which has a ka of 8.0 x 10-5.
Report your answer with two decimal places. Example: 6.99

Answers

Answer:

pH= 1.70

Explanation:

I      4.988        0     0

C     -x             +x     +x

E     4.988 -x    x       x

8.0 x 10^-5 = X^2/ 4.988 - x

(since the X value is so small, round 4.988-x to 4.988 because X is close to zero)

8.0 x 10^-5 = x^2/4.988

x4.988           x4.988

4.0 x 10^-4 = x^2

x = .0199

pH=-log[.0199] = 1.70

Calculate the pH of a solution with [H+] =1x10^-5

Answers

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Answer: 5

Explanation:

I hope this helped!

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- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

3. How many joules are required to raise the temperature of a 29.352g sample of water by 52.0°C? (the specific heat of water is 4.184 J/g °C)​

Answers

Answer:

6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q= ?c= 4.184 [tex]\frac{J}{g*C}[/tex]m= 29.352 gΔT= 52 C

Replacing:

Q= 4.184 [tex]\frac{J}{g*C}[/tex] *29.352 g* 52 C

Solving you  get:

Q= 6,386.05 J

6,386.05 J are required to raise the temperature of a 29.352g sample of water by 52.0°C.

how many atoms are in 0.5 mole of aluminum

Answers

Answer is:
0.5•(6.022 • 10^23)=3.011 • 10^23
Explanation in photo below

According to the Avogadro's number, there are 3.011×10²³ atoms in 0.5 mole of aluminium.

What is Avogadro's number?

Avogadro's number is defined as a proportionality factor which relates number of constituent particles with the amount of substance which is present in the sample.

It has a SI unit of reciprocal mole whose numeric value is expressed in reciprocal mole which is a dimensionless number and is called as Avogadro's constant.It relates the volume of a substance with it's average volume occupied by one of it's particles .

According to the definitions, Avogadro's number depend on determined value of mass of one atom of those elements.It bridges the gap between macroscopic and microscopic world by relating amount of substance with number of particles.

Number of atoms can be calculated using Avogadro's number as follows: mass/molar mass×Avogadro's number, on substituting values in formula, 0.5×6.023×10²³=3.011×10²³ atoms.

Thus, there are 3.011×10²³ atoms in 0.5 mole of aluminium.

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Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution according to the equation H C 2 H 3 O 2 + N a O H ⟶ H 2 O + N a C 2 H 3 O 2 HCX2HX3OX2+NaOH⟶HX2O+NaCX2HX3OX2 If you require 33.98 mL of 0.1656 M N a O H NaOH solution to titrate 10.0 mL of H C 2 H 3 O 2 HCX2HX3OX2 solution, what is the molar concentration of acetic acid in the vinegar? Type answer:

Answers

Answer:

[tex]M_{acid}=0.563M[/tex]

Explanation:

Hello there!

In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

[tex]M_{acid}V_{acid}=M_{base}V_{base}[/tex]

Thus, we solve for the molarity of the acid to obtain:

[tex]M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M[/tex]

Regards!

Help bestie pls help ASAP thank you

Answers

Explanation:

heyyyyyyyyy how are you sure

Pictures of every moon

Answers

Answer:

Where?

Explanation:

10) 81 grams of Au is how many mL ?

Answers

Answer: Thus 81 grams of Au is 9210 ml

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

[tex]\text{moles of Au}=\frac{81g}{196.96g/mol}=0.411moles[/tex]

1 mole of Au occupies = 22.4 L

Thus 0.411 moles of Au occupy = [tex]\frac{22.4}{1}\times 0.411=9.21L=9210ml[/tex]

81 grams of Au is 9210 ml

Look at the H-R diagram. Which area of the diagram represents the white dwarfs? Give answer like top, right corner.

Answers

Answer:

I did this TGA got it right it is bottom left corner

Explanation:

GROUP NUMBER
ELEMENT
Potassium
Fluorine
Silicon
Radon
Gold
Beryllium
Oxygen
Neon
Rubidium
Tungsten
Arsenic
Calcium
Sodium
Aluminum
Chromium
Iodine
Helium
Nitrogen
Iron
Zinc

Answers

Answer:

Jet ğıpep2pep2p2pp3oroe88r82

The
14. Use the graph to respond to the
question 14,
ga
ba
1
2
1
344 m/s
5000 m/s
1455 m/s
No sound
3
2
3
4
4

Answers

Answer:

21

Explanation:

definitely

What is entropy?

A. Entropy is the measure of ability to do work.

B. Entropy is the measure of heat content.

C. Entropy is the measure of energy in molecules.

D. Entropy is the measure of randomness.

Answers

Answer:

D. Entropy is the measure of randomness

Explanation:

I got it right so I don't know if it's going to be right for you. All questions/answers are not the same but since I personally got it right then I wanted to help you out! I apologize if I'm late/wrong! God bless you guys!

Answer:

Entropy is a measure of randomness.

Explanation:

i just took the test on a pex.

write a balanced equation between oxalic acid and potassium hydroxide ​

Answers

2 KOH(aq) + H2C2O4(s) → K2C2O4(aq) + 2 H2O(l) When a sample of oxalic acid (H2C2O4), which is a diprotic acid (both H-atoms are acidic), is titrated with 0.250 M potassium hydroxide solution, 24.66 mL of the potassium hydroxide solution are required to neutralize the acid. I don’t know is this gonna help but ok ._.

when are igneous rocks formed?

A. When layers of mud form inside Earth

B. When layers of mud are compressed

C. When melted rock solidifies

D. When solid rock melts

Answers

Answer:

C. When melted rock solidifies.

I don’t understand please help

Answers

It’s C)H2SO4
Good luck
I agree the answer is C according to my research about it

Ethanol (C2H5OH) is produced from the fermentation of sucrose in the presence of enzymes.
C12H22O11(aq) + H2O(g) 4 C2H5OH(l) + 4 CO2(g)
Determine the theoretical yield and the percent yields of ethanol if 665 g sucrose undergoes fermentation and 305.0 g ethanol is obtained.
theoretical

Answers

actual yield of ethanol = 305.0g

molar mass of sucrose = 342g

molar mass of ethanol  =46g

mass of sucrose = 665g

mole of sucrose = mass / molar mass = 665/342

mole of sucrose =1.9 mole

sucrose :  C2H5OH

       1      :  4

     1.9     : 1.9x4 =7.6 mole of C2H5OH are formed

mass (therotical yield ) of C2H5OH= mole x mass

mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g

percent yields of ethanol =  actual /therotical x100

=305/349.6x100 = 87.24 %

During a running (dynamic) compression test at idle, a good engine should produce PSI. A. 150 to 200 B. 100 to 150 C. 30 to 60 D. 60 to 90​

Answers

Answer:

b

Explanation:

During a running (dynamic) compression test at idle, a good engine should produce PSI between 60 to 90​. The correct answer is option D.

A running compression test is a diagnostic test that measures the compression pressure of an engine while it is running.

The test is performed by connecting a compression gauge to the spark plug hole of each cylinder and then cranking the engine over to measure the compression pressure. The compression pressure of an engine is an important indicator of its overall health and performance. A low compression pressure can indicate a number of issues, such as worn piston rings, damaged valves, or a blown head gasket. On the other hand, a high compression pressure can indicate that the engine is in good condition and has strong compression.

Therefore, in general, a good engine should produce compression pressure between 60 to 90​ PSI during a running compression test at idle. Option D is the correct answer.

Learn more about compression test here:

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what is another name for horse

Answers

Answer:

Mount, Charger, Colt, Pony, and Folt

Explanation:

Answer:

A stallion or a mare

Explanation:

If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?

Answers

Answer:

2.64 M

Explanation:

Use the dilution equation M1V1 = M2V2, where:

M1 = 12.0 M HCl

V1 = 220 mL HCl

M2 = ?

V2 = 1000 mL HCl

(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)

M2 = 2.64 M HCl

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