he mass of a single molybdenum atom is 1.59×10-22 grams. How many molybdenum atoms would there be in 38.3 milligrams of molybdenum?

Answer:

If you are thinking of the thermodynamic definitions Internal energy change is defined as the heat gained by a system less the work done by the system

E = Q-W. This combination is a state function meaning it depends on the initial and final states of a system and is path independent while work and heat change are path dependent.

Enthalpy change is defined as H = E+ PV A change in Enthalpy is also a state function. The most useful factor of enthalpy is that at constant pressure The heat of reaction Q is a measure of enthalpy and is also a state function.

hope this helps !!

Answer:

Kinetic Molecular theory of matter

Explanation:

Answer:

The kinetic molecular theory of matter offers a description of the microscopic properties of atoms (or molecules) and their interactions, leading to observable macroscopic properties (such as pressure, volume, temperature).

Explanation:

Answer:

Explanation:

FeCl₂(aq) + Na₂CO₃(aq) ⇒ FeCO₃(s) + 2NaCl(aq)

complete ionic equation

Fe⁺²(aq) + 2 Cl⁻(aq) + 2 Na⁺(aq) + CO₃⁻² (aq) ⇒ FeCO₃(s)+ 2 Na⁺(aq) +2Cl⁻(aq)

Spectator ions =  Cl⁻(aq) , Na⁺(aq)

Net ionic equation

Fe⁺²(aq) + CO₃⁻² (aq) ⇒ FeCO₃(s).

The Complete ionic equation:

Fe²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + CO₃²⁻(aq) → FeCO₃(s) + 2Na⁺(aq) + 2Cl⁻(aq)

ii. Spectator ions: Na⁺(aq) and Cl⁻(aq)

iii. Net ionic equation:

Fe²⁺(aq) + CO₃²⁻(aq) → FeCO₃(s)

An ionic equation is a chemical equation that shows the dissociation of all soluble ionic compounds into their respective ions in a solution. It represents the species present in their ionic form rather than as complete compounds.

In an ionic equation, only the ions involved in the chemical reaction are shown, while the spectator ions, which do not participate in the reaction, are omitted. This type of equation provides a more focused representation of the chemical reaction occurring between the ions.

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Answer:

Van't Hoff factor for AlCl₃ = 3 (Approx)

Explanation:

Given:

Number of observed particular = 1.79 M

Number of theoretical particular = 0.56 M

Find:

Van't Hoff factor for AlCl₃

Computation:

Van't Hoff factor for AlCl₃ = Number of observed particular / Number of theoretical particular

Van't Hoff factor for AlCl₃ = 1.79 M / 0.56 M

Van't Hoff factor for AlCl₃ = 3.19

Van't Hoff factor for AlCl₃ = 3 (Approx)

The Van't Hoff factor for the AlCl₃ solution is 3

Van't Hoff factor describes the number of ions in a solution. The Van't Hoff factor for non-electrolyte is always 1 while it varies for ionic solutions.

From the question given above, the following data were obtained:

Van't Hoff factor = Actual molarity / Theoretical molarity

Van't Hoff factor for AlCl₃ = 1.79  / 0.56

Van't Hoff factor for AlCl₃ ≈ 3

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Answer:

1000 µL; 10 µL  

Explanation:

A p1000 micropipet is set to dispense 1000 µL.

A p10 micropipet set to dispense 10 µL.

Answer:

Activate glycolysis/Inhibit gluconeogenesis: Increased levels of fructose-2,6-bisphosphate, activation of PFK-2

Activate gluconeogenesis/Inhibit glycolysis: Increased levels of glucagon, Increased levels of cAMP, Activation of fructose-2,6-bisphosphatase (FBPase-2)

Note: The question is incomplete. The complete question is given below and in the attachment.

Fructose‑2,6‑bisphosphate is a regulator of both glycolysis and gluconeogenesis for the phosphofructokinase reaction of glycolysis and the fructose‑1,6‑bisphosphatase reaction of gluconeogenesis. In turn, the concentration of fructose‑2,6‑bisphosphate is regulated by many hormones, second messengers, and enzymes. How do the following affect glycolysis and gluconeogenesis?

Explanation:

Fructose-2,6-bisphosphate is an allosteric effector for the enzymes phosphofructokinase-1 (PFK-1) and fructose-1,6-bisphosphatase (FBPase-1). It increases the affinity of PFK-1 for fructose-6-phosphate thereby activating glycolysis. However, it reduces the affinity of FBPase-1 for its substrate, fructose-1,6-bisphosphate thereby inhibiting gluconeogenesis.

Activation of phosphofructokinase-2 activates glycolysis and inhibits gluconeogenesis by catalyzing the phosphorylation of fructose-6-phosphate to form fructose-2,6-bisphosphate.

Increased levels of glucagon stimulates the synthesis of cAMpP which activates cAMP-dependent ptrotein kinase which phosphorylates the bifunctional enzyme PFK-2/FBPase-2. The phosphorylation of this enzyme inhibits its PFK-2 activity and activates its FBPase-2 activity. This results in the activation of gluconeogenesis and inhibition of glycolysis.

Fructose-2,6-bisphosphatase breaks down fructose-2,6-bisphosphate to fructose-6-phospshate and a phosphoryl group. This results in the activation of gluconeogenesis and the inhibition of glycolysis.

Answer:

One.

Explanation:

Hello,

In this case, the equilibrium condition is characterized by the equality of the rates at which a process happen and the contrary process happen, so its ratio is 1. For instance, a chemical reaction at equilibrium will have a contant ratio of the velocity at which the products are formed and the reactants consumed

However, for the described insoluble solid that is allowed the reach equilibrium, the ratio of the rate at which ions join the solution and the rate at which ions join the lattice will be one since it reaches an equilibrium state.

Best regards.

Answer:

ZnS, Ksp=2.0×10−25

Explanation:

The Ksp is a constant that let us know the capacity of the compound to easily dissociates in water. The higher the Ksp, the more soluble the compound is. In the exercise giving, the highest Ksp is 2.0×10−25, that means ZnS will dilutes easily than others

Answer:

[tex]C_3H_7Cl[/tex] = Two structures

[tex]C_3H_6Cl_2[/tex] = Four structures

Explanation:

We must remember that in an isomer we have the same molecular formula but different structures. Thus, for the molecule [tex]C_3H_7Cl[/tex] we can draw a linear structure of 3 carbons and change the position of the chlorine atom, obtaining two different structures.

For the molecule [tex]C_3H_6Cl_2[/tex], we can use similar logic. Place a chain of 3 carbons and change the position of the chlorine atoms in such a way that for this formula we will have 4 different structures.

See figures 1 and 2 for further explanations.

The question is incomplete. Here is the complete question.

Consider the selenium atom, Se, and the bromine atom, Br.

Write out the full electron configuration fro each atom.

Se:

Br:

Calculate the Effective Nuclear Charge for each atom. Show all of your work for full credit.

Se:

Br:

Which atom is larger?

Answer and Explanation: Electron Configuration of an atom demonstrates the shape and energy of its electrons. One of the rules used for it is given by using Madelung's Rule, in which the order of increased energy of the electrons is:

1s < 2s < 2p < 3s < 3p < 4s < 4p < 5s < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7p

Atom of Selenium (Se) has 34 electrons. Its electron configuration is

Se: [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{4}[/tex]

Atom of Bromine has 35 electrons. Its electron configuration is

Br: [tex]1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{5}[/tex]

Effective Nuclear Charge ([tex]Z_{eff}[/tex])is the net positive charge experienced by an electron in a multi-electron atom. In other words, it is the net force that helds nucleus and electrons together.

It is calculated by: [tex]Z_{eff}=Z-S[/tex]

where

Z is the atomic number, i.e., number of protons of the atom

S is the nonvalence electrons, i.e., the number of electrons between the nucleus and the electron in question.

For Selenium (Se):

From the electron configuration, the valence shell is 4 with 6 valence electrons. Nonvalence electrons is the difference between valence and total electrons:

S = 34 - 6 = 28

[tex]Z_{eff}=34-28[/tex] = 6

The Effective Nuclear Charge of Se is 6

For Bromine (Br):

The valence shell, according to the configuration, is 4 and valence electrons are 7.

S = 35 - 7 = 28

[tex]Z_{eff}=35-28[/tex] = 7

The Effective Nuclear Charge fo Br is 7.

Bromine is larger than Selenium because it has bigger Effective Nuclear Charge, which means it held its electrons more loosely and, consequently, has a larger atomic radius.

Answer:

yes

Explanation:

the number of protons in the nucleus of an atom determines the type element: the number of protons in an element is the atomic number on the periodic table (number at the top)

Each atom has characteristic number of protons present in it's nucleus which is unique for that element.

An element  is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

The number of protons in the nucleus is the defining property of an element and is related to the atomic number.All atoms with same atomic number are atoms of same element.

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Answer:

The formula of the first compound is RQ

Explanation:

Chemical formula is the simplest whole number ratio of moles of each element in the compound.

To determine the formula of a compound we must know the molar mass of each element (How many grams weighs a mole of the compound).

The formula of the second compound is RQ₃. That is 1 mole of R and 3 moles of Q.

1 mole of R weighs 7.00g. That means its molar mass is 7g/mol.

3 moles of Q weighs 4.50g. Its molar mass is 4.50g / 3 moles: 1.50g/mol

In the first compound, there are 14.0g = 2 moles of R

And 3.00g of Q = 2 moles of Q.

And you can think formula is:

R₂Q₂

But, as formula is the simplest whole number ratio,

Answer:

CH₃CH₂-CH₂CH₃

Explanation:

When an alkene, R-CH=CH-R reacts with H₂ in a Pt catalyst, the analogue alkane, R-CH₂-CH₂-R, is produced (Hydrogenation of alkenes via Pt/Pd catalyst)

Thus, the reaction of CH₃CH=CHCH₃ with H₂ under a platinum catalyst produce:

The analogue alkane

The addition of hydrogen to CH3CH=CHCH3 leads to the formation of CH3CH2CH2CH3.

An alkene is a hydrocarbon that contains a C=C double bond. An alkene undergoes addition reaction in which a molecule is added across the double bond to form a saturated hydrocarbon.

The addition of H2 to CH3CH=CHCH3 yields butane as shown in the image attached. The platinum metal serves a catalyst in the reaction.

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Answer:

A.  NaOH

B.  20 g

C.  18.4 g

D.  108%

Explanation:

Al₂O₃  +  6 NaOH  +  12 HF  ⇒  2 Na₃AlF₆  +  9 H₂O

A.  Since you have excess HF, this is not the limiting reagent.  The two possibilities are Al₂O₃ and NaOH.  Find out how many moles you have of each.  Then, use the mole ratio in the chemical equation to find out how much product each reagent can produce.  The reagent the produces the least is the limiting reagent.  The molar mass of Al₂O₃ is 101.96 g/mol.

(6.55 g Al₂O₃)/(101.96 g/mol Al₂O₃) = 0.06424 mol Al₂O₃

(0.06424 mol Al₂O₃) × (2 mol Na₃AlF₆/1 mol Al₂O₃) = 0.12848 mol Na₃AlF₆

(1.75 L NaOH) × (0.15 M NaOH) = 0.2625 mol NaOH

(0.2625 mol NaOH) × (2 mol Na₃AlF₆/6 mol NaOH) = 0.0875 mol Na₃AlF₆

NaOH produces less product, making it the limiting reagent.

B.  The actual yield is 20 g.  This information is given in the problem.

C.  Since you know how much product you will get, convert moles of Na₃AlF₆ to grams to find actual yield.  Use the value found for Na₃AlF₆ that you got from the limiting reagent.  The molar mass is 209.94 g/mol.

(0.0875 mol Na₃AlF₆) × (209.94 g/mol Na₃AlF₆) = 18.4 g Na₃AlF₆

D.  To find the percent yield, divide the actual yield by the theoretical yield  and multiply by 100%.

(20 g)/(18.4 g) × 100% = 108%

If your percent yield is greater than 100% when performing a reaction, there has been a mistake somewhere.  Either you recorded the numbers incorrectly or there has been some human error in your experiment.  This might be the right answer for this problem, but you might want to double check to make sure the numbers you gave me were right.

Answer:

Oxygen and glucose

Explanation:

____________

The given question is incomplete, the complete question is:

Balance the following chemical equations: A) P4+ O2 → P406 B) _P406+ LO2 → P4010 a) A reaction container holds 5.33 g of P4 and 3.77 g of O2 and reaction A occurs. If enough oxygen is available then the P406 reacts further to undergo reaction B. What is the limiting reactant for the formation of P406? b) What mass of P406 is produced (theoretical yield in grams)? c) If 7.12g of P406 were obtained what is the percent yield? d) Will reaction B occur? Why or why not? What mass of excess reactant is left in the reaction container?

Answer:

The balanced reaction will be,

A) P₄ + 3O₂ ⇒ P₄O₆

B) P₄O₆ + 2O₂ ⇒ P₄O₆

a) Based on the given information, the reaction container holds 5.33 grams of P₄ and 3.77 grams of oxygen. Thus, the moles of P₄ will be,

Moles = mass of P₄/Molar mass of P₄ = 5.33 grams/124 g/mole = 0.043 mole

Now the moles of O₂ will be,

Moles = mass of O₂/Molar mass of O₂ = 3.77 grams/32 g/mol = 0.112 mole

Now the moles of P₄O₆ formed when 0.043 moles of P₄ react completely will be = 1/1 × 0.043 = 0.043 mole of P₄O₆

Similarly, the moles of P₄O₆ formed, when 0.112 moles of O₂ react completely will be = 1/3 × 0.112 = 0.0373 mole of P₄O₆

Thus, from the analysis, the maximum moles of P₄O₆ formed will be 0.0373 moles. Therefore, oxygen will be the limiting reagent, which will react completely in the reaction.

b) From the above findings, the maximum moles of P₄O₆ produced is 0.0373 mole. Thus, the theoretical yield of P₄O₆ produced will be,

= Moles of P₄O₆ × Molar mass of P₄O₆

Theoretical yield = 0.0373 mole × 220 g/mole = 8.206 grams

c) Based on the given information, the actual mass of P₄O₆ produced is 7.12 grams.

Hence, percent yield = Actual yield/Theoretical yield * 100

= 7.12/8.206 × 100 = 86.77 %

d) In the given case, reaction B will not take place. This is due to the fact that oxygen is not left for reaction B, which was the limiting regent for reaction A. Here P₄ is the excess reactant, which was left in the reaction.

The initial moles of P₄ is 0.043, O₂ is 0.112, and P₄O₆ is O. The final moles of P₄ is 0.043 -1/3 × 0.112 = 0.0057 mole, O₂ is 0, and P₄O₆ is 0.0373 mole.

Thus, moles of P₄ left is 0.0057 mole. Hence, the mass of P₄ left will be,

= 0.0057 mole × Molar mass of P₄

= 0.0057 mole × 124 g/mole = 0.7068 grams.

Answer:

a. See figure 1

b. See figure 2

c. Three cycles

d. Four Acetyl-CoAs

Explanation:

a. Draw the condensed structural formula for the activated form of caprylic acid

For the activation of the fatty acid, an ATP molecule is needed to bind AMP in the acid group and then an Acetyl-CoA molecule to generate the activated fatty acid. (See figure 1)

b. Indicate the α- & β-carbon atoms in caprylic acid

By definition, the alpha and beta carbons are the carbons that are in positions 2 and 3 respectively to the main carbon. In this case, the main carbon is the carbon from the acid group, therefore the alpha carbon will be carbon 2 (red arrow) and the beta carbon will be carbon 3 (blue arrow). (See figure 2).

c. State the number of β-oxidation cycles for the complete oxidation of caprylic acid.

To calculate the cycles we have to use the equation:

[tex]Number~of~cycles:\frac{n}{2}-1[/tex], where n is the amount of carbons, in this case, we have 8 carbons, so:

[tex]Number~of~cycles:\frac{8}{2}-1=3[/tex]

We will have 3 cycles. (See figure 3)

d. State the number of acetyl-CoAs from the complete oxidation of caprylic acid

In the β-oxidation metabolic cycle, we have a relationship between Acetyl-CoA produced and the number of carbons:

[tex]Number~of~Acetyl~Coas:\frac{n}{2}[/tex] if n=8 we will have:

[tex]Number~of~Acetyl~Coas:\frac{8}{2}=4~Acetyl~Coas[/tex]

We will have 4 Acetyl-CoAs.

I hope it helps!

Answer:

a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.

Explanation:

Step 1: Write the dissociation reaction for nitrous acid

HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)

Step 2: Calculate the acid dissociation constant

Ka = [H⁺] × [NO₂⁻] / [HNO₂]

Ka = 0.022 × 0.022 / 0.68

Ka = 7.1 × 10⁻⁴

Step 3: Determine the strength of the acid

Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.

Answer:

2.90

Explanation:

Any buffer system can be described with the reaction:

[tex]HA~->~H^+~+~A^-[/tex]

Where [tex]HA[/tex] is the acid and [tex]A^-[/tex] is the base. Additionally, the calculation of the pH of any buffer system can be made with the Henderson-Hasselbach equation:

[tex]pH=pKa~+~Log\frac{[A^-]}{[HA]}[/tex]

With all this in mind, we can write the reaction for our buffer system:

[tex]HF~->~H^+~+~F^-[/tex]

In this case, the acid is [tex]HF[/tex] with a concentration of 0.413 M and the base is [tex]F^-[/tex] with a concentration of 0.237 M. We can calculate the pKa value if we do the "-Log Ka", so:

[tex]pKa~=~-Log(7.2X10^-^4)=~3.14[/tex]

Now, we can plug the values into the Henderson-Hasselbach

[tex]pH=~3.14~+~Log(\frac{[0.237~M]}{[0.413~M]})~=~2.90[/tex]

The pH value would be 2.90

I hope it helps!

Answer:

HI!!

Explanation:

The correct answer is A) they both must decide how to allocate resources. Based on the lesson, individuals and economies are similar because both must decide how to allocate resources.

Answer:

A - They both must decide how to allocate resources

Explanation:

>.<

Answer:

Option d. 0.10 m Cr₂(SO₄)₃

Explanation:

Formula for the osmotic pressure is determined as:

π = M . R . T . i

So you have to take account the i (Van't Hoff factor, numbers of ions dissolved)

Urea is an organic compound, so the i value is 1

Zync acetate can be dissociated:

Zn(CH₃COO)₂  →  1Zn²⁺  + 2CH₃COO⁻

In this case, the i is 3. (you see, the stoichiometry of ions)

Cr₂(SO₄)₃ →  0.10 m

Chromium sulfate is dissociated:

Cr₂(SO₄)₃ →  2Cr³⁺  +  3SO₄⁻²

i = 5

BaI₂ → 0.16 m

BaI₂ →  1Ba²⁺  +  2I⁻

i = 3

Answer:

Butanoic acid.

Explanation:

Hello,

In this case, when a primary alcohol such as 1-butanol (OH is bonded to a primary carbon) is oxidized in the presence of a strong oxidizing media such as potassium dichromate (K2Cr2O7) and sulfuric acid, the stepwise oxidation goes to the corresponding aldehyde with a further oxidation to the corresponding carboxylic acid:

[tex]R-CH_2-OH\longrightarrow R-COH\longrightarrow R-COOH[/tex]

Therefore, on the attached picture you can find that the formed aldehyde is butanal and the inly organic product, due to the strong oxidizing media is finally butanoic acid.

Best regards.

Answer:

how strong it is

Explanation:

Seismographs are not able to say when earthquake will happen, but they help humans to know how strong it is or if it is happening or not

Answer:

an element is a atom like titanium and a compound is like a water, glucose, alcohol and salt

Explanation:

the titanium is a element and water, glucose, alcohol, and salt those are a compound

Answer:

Boiling an egg is a chemical reaction

Vegetable rotting is a chemical reaction.

Chemical reaction: In this Chemical reaction takes place and new products is formed.

Explanation:

Answer:

prepare

creates

observe

ask

records

present

Answer:

Mars

Explanation:

Mars is the planet with features that are really similar to the earth. As a matter of fact, Mars and the earth are referred to as "twin planets".

Mars and Earth are believed to have historically had even more similar attributes, however, that of mars was lost due to changes in the solar system.

The two planets are mostly similar because of their relatively similar size and proximity to the sun.

Answer:

hex-1-ene with a hydroboration-oxidation reaction

Explanation:

In this case, we can start with the structure of 1-hexanol. In this alcohol, the "OH" is on the first carbon. Thus, the alkene that this alcohol can produce must have a double bond between carbons 1 and 2, that is, hex-1-ene.

Now, it is important to know which of the reactions we can use, hydroboration-oxidation, or oxymercuration-reduction. To decide which reaction to using, we must look again at the alcohol we want to produce. In this alcohol, the "OH" is attached to a primary carbon. Therefore, the addition of the "OH" must be made on the least substituted carbon, that is, carbon number 1.

Because of this, an anti-Markovnikov reaction (a reaction in which the "OH" is added on the less substituted carbon) must be used. The reaction, which serves us then is: hydroboration-oxidation since this reaction is anti-markovnikov.

See figure 1

I hope it helps!