The direction of vector v is 330° (or -30°) counterclockwise from the positive x-axis.
The magnitude of a vector v = (a, b) is given by the formula:
[tex]|v| = \sqrt{(a^2 + b^2)}[/tex]
So for vector v = (5√3, −5), we have:
[tex]|v| = \sqrt{((5\sqrt{3} )^2 + (-5)^2)} \\= \sqrt{(75 + 25)} \\= \sqrt{100}[/tex]
= 10
Therefore, the magnitude of vector v is 10.
The direction of vector v can be expressed as an angle measured counterclockwise from the positive x-axis. To find this angle, we use the formula:
θ = tan⁻¹(b/a)
So for vector v = (5√3, −5), we have:
θ = tan⁻¹((-5)/(5√3))
= tan⁻¹(-1/√3)
= -30°
That we use the negative sign for the angle because the vector points in the direction of the negative y-axis, which is below the x-axis. Therefore, the direction of vector v is 330° (or -30°) counterclockwise from the positive x-axis.
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To find the magnitude of v⃗ , we use the formula. The magnitude and direction of vector v = (5√3, -5) are 10 and 330 degrees, respectively.
|v⃗ | = √(5√3)² + (-5)²
|v⃗ | = √75 + 25
|v⃗ | = √100
|v⃗ | = 10
So, the magnitude of v⃗ is 10.
To find the direction of v⃗ , we use the formula:
θ = tan⁻¹(y/x)
where y is the second component of v⃗ and x is the first component of v⃗ . Therefore:
θ = tan⁻¹(-5/(5√3))
θ = tan⁻¹(-1/√3)
θ = -30°
So, the direction of v⃗ is -30 degrees.
To find the magnitude and direction of the vector v = (5√3, -5), follow these steps:
Step 1: Find the magnitude
The magnitude of a vector (v) can be found using the formula: |v| = √(x^2 + y^2), where x and y are the components of the vector. In this case, x = 5√3 and y = -5.
|v| = √((5√3)^2 + (-5)^2)
|v| = √(75 + 25)
|v| = √100
|v| = 10
The magnitude of vector v is 10.
Step 2: Find the direction
To find the direction of the vector, we will use the arctangent function (atan2) of the ratio of the y-component to the x-component. In this case, y = -5 and x = 5√3.
θ = atan2(-5, 5√3)
Since the arctangent function provides results in radians, we need to convert it to degrees.
θ = atan2(-5, 5√3) × (180/π)
θ ≈ -30 degrees
Since we want the angle in the standard [0, 360) range, we add 360 to the result:
θ = -30 + 360 = 330 degrees
The direction of vector v is 330 degrees.
So, the magnitude and direction of vector v = (5√3, -5) are 10 and 330 degrees, respectively.
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how many 'words' can be made from the name ESTABROK with no restrictions
The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
How to determine the number of waysGiven the word:
ESTABROK
Then n = 8
p = 6
The formula for permutation without restrictions
P = n! ( n - p + 1)!
P = 8! ( 8 - 6 + 1) !
P = 8! (8 - 7)!
P = 8! (1)!
P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1
P = 40, 320 ways
Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
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Find the inverse of the function.
y = 2x^2 -4
Answer:The inverse of the function y = 2x^2 –4 is;. y = √(x +4)/2To find the inverse of the function;We must first solve for x in the equation as follows;y = 2x² - 4y + 4 = 2x²x² = (y +4)/2x = √ (y +4)/2By swapping x and y; we then have;y = √(x +4)/2
How many 4-digit positive integers are there for which there are no repeated digits, or for which there may be repeated digits, but all digits are odd?
The number of ways of arranging 4-digit positive integers with no repeated digits is 4536 ways and number of ways of 4-digit positive integers with repeated digits, but all digits are odd is 625 ways.
In this question,
Positive integers are 0,1,2,3,4,5,6,7,8,9
Total number of integers = 10
This can be solved by permutation concepts.
Case 1: 4-digit positive integers with no repeated digits,
First digit, cannot be zero. So remaining 9 digits.
Second digit, can be any digit other than the first digit. So 9 digits.
Third digit, can be any digits other than first and second. So 8 digits.
Fourth digit, can be any digits other than first, second, third digit. So 7 digits.
Thus, Number of ways of 4-digit positive integers with no repeated digits ⇒ (9)(9)(8)(7)
⇒ 4536 ways.
Case 2: 4-digit positive integers, there may be repeated digits, but all digits are odd
Odd integers are 1,3,5,7,9
Number of digits = 5
In this case, we can repeat the digits. So all places can have 5 possibilities.
Thus number of ways of 4-digit positive integers with repeated digits, but all digits are odd = (5)(5)(5)(5)
⇒ 625 ways.
Hence we can conclude that the number of ways of arranging 4-digit positive integers with no repeated digits is 4536 ways and number of ways of 4-digit positive integers with repeated digits, but all digits are odd is 625 ways.
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ppppp-pp help please.
Answer:
There are two complex roots:
[tex]-3\pm i[/tex]============
Given equation:x² - 6x + 10 = 0The standard form is:
ax² + bx + c = 0Compared we can find values of the coefficients and the constant:
a = 1, b = - 6, c = 10Substitute these values into quadratic formula:
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]
and work out roots:
[tex]x=\dfrac{-(-6)\pm\sqrt{(-6)^2-4*1*10} }{2*1}=x=\dfrac{6\pm\sqrt{36-40} }{2}=\dfrac{6\pm2\sqrt{-1} }{2}=3 \pm i[/tex]
Given g of x equals cube root of the quantity x plus 6, on what interval is the function negative? (–∞, –6) (–∞, 6) (–6, ∞) (6, ∞)
The interval where the function is negative is (–∞, –6)
How to determine the negative interval?The function is given as:
[tex]f(x) = \sqrt[3]{x + 6}[/tex]
Set the radicand to less than 0
x + 6 < 0
Subtract 6 from both sides
x < -6
Rewrite as an interval notation.
(–∞, –6)
Hence, the interval where the function is negative is (–∞, –6)
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Based on the graphs of the equations y = x + 7 and y = x2 – 3x + 7, the solutions are located at points:
The correct option is A. (4, 11) and (0, 7).
The solution of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points: (4, 11) and (0, 7).
What is the system of linear equation?Estimate the y-intercept, slope, and express the equation in the form of the y-intercept (y = mx + b) to find the graphed equation. The slope is the difference between the y- and x-axis values.
A graph equation is an equation in graph theory where the unknown is a graph. Isomorphic ideas are one of the key issues in graph theory.
The equations are; y = x + 7 and y = x² - 3x + 7
At the solution, the u-values are equal, which gives;
y = y
x + 7 = x² - 3·x + 7
x² - 3·x + 7 - (x + 7) = 0
x² - 4·x = 0
x·(x - 4) = 0
x = 4, or x = 0
When x = 4, y = 4 + 7 = 11
When x = 0,
y = 0 + 7 = 7
Therefore, the solution for the equations y = x + 7 and y = x² - 3x + 7 are are located at points: (4, 11) and (0, 7).
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The complete question is-
Based on the graphs of the equations y = x + 7 and y = x² – 3x + 7, the solutions are located at points:
A. (4, 11) and (0, 7)
B. (4, 11) and (–7, 0)
C. (–7, 0) and (1.5, 4.75)
D. (1.5, 4.75) and (0, 7)
Four pounds of apples cost $5 How much would 10 pounds o apples cost?
Answer:
Step-by-step explanation:
plus all of them 5times 10
Do you think any resulting prediction would be more or less reliable than your original one?
No, The resulting prediction would be more or less reliable than your original one.
Importance:
Prediction is a forecast or a prophecy. An example of a prediction is a psychic telling a couple they will have a child soon, before they know the woman is pregnant. A statement of what will happen in the future.
Predictions provide a reference point for the scientist. If predictions are confirmed, the scientist has supported the hypothesis. If the predictions are not supported, the hypothesis is falsified. Either way, the scientist has increased knowledge of the process being studied.
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A conjecture and the paragraph proof used to prove the conjecture are shown. Given: angle 2 is congruent to angle 3. Prove: angle 1 and angle 3 are supplementary. A horizontal line. Two rays extend from upper region of the line diagonally down to the left and right and intersect the line forming interior angles labeled as 2 and 3 and an exterior angle labeled as 1. Drag an expression or statement to each box to complete the proof. Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse. ∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Response area. Therefore, m∠1+ Response area = 180° by the definition of supplementary. It is given that ∠2≅ Response area, so m∠2=m∠3 by the Response area. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary by the definition of supplementary. angle congruence postulatelinear pair postulatem∠2m∠3∠3∠2
The fill up of the missing points are:
∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Linear Postulate theorem. Therefore, m∠1+m∠2 = 180° by the definition of supplementary. It is given that ∠2≅ ∠3, so m∠2=m∠3 by the Congruence Postulate theorem. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary.What is the angles about?Using the image attached, one can see that m<1 and m<2 creates a kind of linear pair hence one can say they are both supplementary using the law of LINEAR POSTULATE THEOREM.
Based on the fact that the supplementary angles add up to 180 degrees, therefore:
m<1 + m<2 = 180 - will be equation 1
Since the interior angles m<2 and m<3 are known to be equal based on the CONGRUENCE POSTULATE THEOREM. Therefore
m<2 = m<3 --- will be equation 2
Then place eqn. 2 into eqn. 2
m <1 + m <3 = 180
This connote that m<1 and m<3 are supplementary.
Hence, The fill up of the missing points are:
∠1 and ∠2 form a linear pair, so ∠1 and ∠2 are supplementary by the Linear Postulate theorem. Therefore, m∠1+m∠2 = 180° by the definition of supplementary. It is given that ∠2≅ ∠3, so m∠2=m∠3 by the Congruence Postulate theorem. By substitution, m∠1+m∠3=180°, so ∠1 and ∠3 are supplementary.Learn more about the angle from
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How much work is performed lifting in order to lift a 50.0 kg block 7.00 meters? Use g=9.81 m/s^2
The work done in lifting the block is 3430 J
Calculating workFrom the question, we are to determine the work done in lifting the block
Using the formula,
Work done = mgh
Where m is the mass
g is the acceleration due to gravity
and h is the height
From the question,
m = 50.0 kg
g = 9.81 m/s²
h = 7.00 m
Putting the parameters into the formula,
Work done = 50.0 ×9.8 × 7.00
Work done = 3430 J
Hence, the work done in lifting the block is 3430 J
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Can someone help me please
Answer: B. [tex]12log(x)-4log(y)[/tex]
Step-by-step explanation:
Properties of logs:
[tex]log_{a} (\frac{B}{C} )=log_{A}B-log_{A} C[/tex]
[tex]logA^B = BlogA[/tex]
So, [tex]log\frac{x^{12} }{y^4} =logx^{12} -logy^4 =12log(x)-4log(y)[/tex]
It would be 12 log x - 4 log y (B)
Find the slope of the line on the graph.write your answer as a fraction or a whole number, not a mixed number
Answer:
slope = [tex]-\frac{1}{2}[/tex] if it were in an
Step-by-step explanation:
the graph is a negative and will therefore have a negative slope. to find the slope, pick a point on the graph and find the [tex]\frac{rise}{run}[/tex].
for instance, start with the point (0,1). Then go down 1 and left 2 to get to the next point on the graph (2,0). 1 is the "rise" and 2 is the "run" hence -1/2 being the slope.
you could also use the slope formula: [tex]\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]
point 1: (0,1) (x₁ ,y₁)
point 2: (2,0) (x₂ , y₂)
[tex]\frac{0-1}{2-0} =-\frac{1}{2}[/tex]
Quick algebra 1 assignment for 50 points!
Only answer if you know the answer, tysm!
1. Create 5 questions referencing “Finding Function Values for Elements of the Domain”Below is an example of one.
——————————————————————
Example :
For the problem below find the range for the given.
Given: b(x) = -2x + 12, find the range of b for the domain {-3, 5, 9}.
——————————————————————
2. Answer each question and write a brief step by step process on how you got the answer to each of your questions.
This question is asking to create 5 of your own questions, so here are mine with the process on how I got each:
Question 1: Given c(x) = 8x + 32, find the range of c for the domain {1, 3, 5}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by 8, and adding by 32.
c(1) = 8(1) + 32 = 8 + 32 = 40
c(3) = 8(3) + 32 = 24 + 32 = 56
c(5) = 8(5) + 32 = 40 + 32 = 72
Range: {40, 56, 72}
Question 2: Given d(x) = x - 7, find the range of d for the domain {-2, 3}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, and subtracting 7.
d(-2) = -2 - 7 = -9
d(3) = 3 - 7 = -4
Range: {-9. -4}
Question 3: Given f(x) = 7x + 738, find the range of f for the domain {1.5, 11}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by 7, and adding 738.
f(1.5) = 7(1.5) + 738 = 10.5 + 738 = 748.5
f(11) = 7(11) + 738 = 77 + 738 = 815
Range: {748.5, 815}
Question 4: Given g(x) = -2804x + 7268, find the range of g for the domain {50, 75, 256}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by -2804, and adding 7268.
g(50) = -2804(50) + 7268 = -140200 + 7268 = -132932
g(75) = -2804(75) + 7268 = -210300 + 7268 = -203032
g(256) = -2804(256) + 7268 = -717824 + 7268 = -710556
Range: {-132932, -203032, -710556}
Question 5: Given h(x) = -3x - 4, find the range of h for the domain {1, 2, 3}.
Answer w/ Process:
For each equation, I am plugging in each domain value for x in the function, multiplying by -3, and subtracting by 4.
h(1) = -3(1) - 4 = -3 - 4 = -7
h(2) = -3(2) - 4 = -6 - 4 = -10
h(3) - -3(3) - 4 = -9 - 4 = -13
Range: {-13, -10, -7}
b(-3)
-2(-3)+126+1218b(5)
-2(5)+12-10+122b(9)
-2(9)+12-18+12-6Range
{-6,2,18}Rest questions
#1
k(x)=2x²-5
Find the range of k for domain {1,2,6}
#2
h(x)=9x³
Find the range of h for domain {9,0,8}
#3
o(x)=6x-7
find the range of o for domain {0,1,9}
#4
p(x)=23x²-5x
Find the range of p for domain {3,4,8}
P(A)=[tex]\frac{9}{20}[/tex],P(B)=[tex]\frac{3}{5}[/tex],P(A∩B)=[tex]\frac{27}{100}[/tex] ,P(A∪B)=?
The value of the probability P(A∪B) is 39/50
How to determine the probability?The given parameters are:
P(A)= 9/20
P(B) = 3/5
P(A∩B) = 27/100
To calculate the probability P(A∪B), we make use of the following equation
P(A∪B) = P(A) + P(B) - P(A∩B)
So, we have:
P(A∪B) = 9/20 + 3/5 - 27/100
Evaluate the expression
P(A∪B) = 78/100
Simplify
P(A∪B) = 39/50
Hence, the value of the probability P(A∪B) is 39/50
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What is the conditional probability that, when flipping a non-biased coin four times, there are at least two hs, given that the first flip is a h?
The conditional probability that, when flipping a non-biased coin four times, there are at least two heads, given that the first flip is a head, is 3/4.
Calculating the Conditional Probability:
Let us assume that getting a head in the first flip of coin is event B
Also, let us assume that getting a head in on of the remaining three flips is A
Then we have to find the probability of A given B, that is, P(A|B).
The formula for conditional probability is given as follows,
P(A|B) = P (A∩B) / P(B)
The probability of getting two heads, P(A∩B) = 3/8
The probability of getting head in the first flip, P(B) = 1/2
∴ P(A|B) = (3/8) / (1/2)
P(A|B) = 3/4
Thus, the conditional probability of getting at least two heads, given that the first flip is a head is 3/4.
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I am a 3 digit positive number. The sum of my digits is 18. My middle digit is the product of -2 and -4. My first digit is 3^2.
Hi! ⋇
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
The first digit of this number is 3², which is 9.
The Number is : 9xx
________
The second digit is: -2·(-4)=8.
The Number is : 98x.
________
The sum of all the digits is 18. This gives us an equation that we can solve in terms of x!
[tex]\multimap\sf{9+8+x=18}[/tex] (x is the digit we are looking for)
Now it takes a little arithmetic to find x :)
[tex]\multimap\sf{17+x=18}[/tex]. Just subtract 17 from both sides to find x!
[tex]\multimap\sf{x=1}[/tex]. And Now, can you see the number!
It's 981, of course :)
Hope this made sense to you!
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
[tex]\large\it{\overbrace{Calligrxphy}}[/tex]
1. in the function equation ff (xx ) = 1500 (1.43)^x,is this growth or decay? what is the percent of growth/decay? what is the initial value? 2. the number of bacteria in a sample can be modeled by the equation yy = 75(.8)^x, where y is the number of bacteria and x is the number of days elapsed. what is the rate of decay? 3. monthly car sales for a certain type of car are $350,000 and sales are depreciating at a rate of 3% per month. a. write an equation to represent this situation. b. what will the monthly sales be after 8 months? 4. two auction websites start with 100 members each. at site a, the number of members doubles each month. at site b, 500 new members are added each month. between months 5 and 6, which website gains more members and by how much?
1. The given function is growth.
The percent of growth is 43%.
The initial value is 1500.
2. The rate of decay is 20% per day.
3. a. The exponential equation representing the sales after x months for the given situation is 3500000(0.97ˣ).
b. The monthly sales after 8 months will be $274,310.1758.
4. Between months 5 and 6, the website gains more members. The difference between the two sites for this period is 2700 members.
An exponential function is of the form f(x) = (a)(bˣ), where a is the initial value, and b is the exponential factor.
When b > 1, we have growth, and when b < 1, we have decay or depreciation.
1. Given function, f(x) = 1500(1.43ˣ).
The exponential factor in this function is 1.43, which is greater than 1, thus we have growth.
The percent of growth = (1.43 - 1)*100% = 43%.
The initial value = 1500.
2. Given an equation, y = 75(.8ˣ).
The exponential factor in this function is 0.8, and x signifies the days passed.
Thus, the rate of decay = (1 - 0.8)*100% per day = 20% per day.
3. Initial value = $350,000.
Rate of depreciation = 3% per month.
a. Thus, the equation for the sales after x months can be given as:
f(x) = 350000(1 - 0.03)ˣ = 350000(0.97ˣ).
b. To find the monthly sales after 8 months, we substitute x = 8.
Sales = 350000(0.97⁸) = $274,310.1758.
4. Initial members for both sites = 100.
For site a:-
Members double each month.
This makes an exponential equation, f(x) = 100.(2ˣ), where x is the number of months.
The growth between months 5 and 6 can be calculated as:
f(6) - f(5) = 100.(2⁶) - 100.(2⁵) = 6400 - 3200 = 3200.
For site b:-
500 new members are added each month.
This makes a linear equation, f(x) = 100 + 500x, where x is the number of months.
The growth between months 5 and 6 can be calculated as:
f(6) - f(5) = (100 + 500*6) - (100 + 500*5) = 3100 - 2600 = 500.
Thus, between months 5 and 6, the website a gains more members. The difference between the two sites for this period is 2700 members.
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Make a study of minimum amount of basic nutrients needed for a 12-year-old child to survive in the world
Basic nutrients a 12-year-old needs are:
ProteinCarbohydratesFatsCalciumIronFolate FiberVitamin AVitamin CWhat are nutrients?A nutrient is a material that an organism requires in order to survive, grow, and reproduce. Animals, plants, fungi, and protists are all required to consume dietary nutrients. Nutrients can be absorbed by cells for metabolic reasons or expelled by cells to form non-cellular structures such as hair, scales, feathers, or exoskeletons. Some nutrients, such as carbohydrates, lipids, proteins, and fermentation products (ethanol or vinegar), can be metabolically reduced to smaller molecules in the process of generating energy, resulting in the end products of water and carbon dioxide.The following are the nine nutrients that a youngster should consume on a daily basis:
ProteinCarbohydratesFatsCalciumIronFolate FiberVitamin AVitamin CTherefore, basic nutrients a 12-year-old needs are given.
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What is the slope of the line through parentheses two, three parentheses and parentheses -3, four parentheses?
The Slope of the line :
[tex]m=-\frac{1}{5} \approx-0.2[/tex]
What is slope?Using small, whole integer coordinates, it is simple to manually determine a line's slope. The formula becomes more effective if the coordinates are given greater or decimal values.
Because all horizontal lines have the same y-coordinates, it is important to note that all of them have a gradient of zero. In the slope formula's numerator, this will produce a zero. A vertical line, on the other hand, will have an arbitrary slope because the x-coordinates are constant. When applying the formula, this will lead to a division by zero error.
slope = (y₂ - y₁) / (x₂ - x₁)
Using the two points P=(2,3) and Q=(-3,4) as your input, determine the slope.
P=(x1,y1) and Q=(x2,y2) are two points on a line, and the slope of that line is given by :
[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
we have that:
[tex]x_{1}=2, y_{1}=3, x_{2}=-3, y_{2}=4[/tex]
Fill in the blanks in the slope calculation,
[tex]m=\frac{(4)-(3)}{(-3)-(2)}\\\\=\frac{1}{-5}\\\\=-\frac{1}{5}[/tex]
Reaction: the slope of the line is =[tex]m=-\frac{1}{5} \approx-0.2[/tex]
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El rio Lempa sirve de linea fronteriza entre Honduras y El Salvador, mide 300km
de largo. ¿Cuántos metros mide este rio?
Answer:
El río mide:
300000 metros.
Step-by-step explanation:
1 km = 1000 metros
300 km = 300 * 1000 = 300000 metros
...
What is the probability that any given car will have a brake failure if it is make a?
The probability that any given car will have a brake failure if it is make a is 0.0065%
How to determine the probability?The complete question is added as an attachment
From the table in the question, we have:
P(Brake failure|car a) = 0.0065%
The above represents the required conditional probability
Hence, the probability that any given car will have a brake failure if it is make a is 0.0065%
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Answer: The probability that any given car will have a brake failure if it is making A, is 0.0065%.
Step-by-step explanation:
I got it right on Edmentum!
Part a: is the probability of hitting the black circle inside the target closer to 0 or 1? explain your answer and show your work. (5 points) part b: is the probability of hitting the white portion of the target closer to 0 or 1? explain your answer and show your work. (5 points)
The probability of hitting the black circle inside the target is close to 0, and the probability of hitting the white portion is close to 1.
Given:
The square's length is 10 units.
The circle's diameter is equal to two units.
To Determine:
It is necessary to determine the probability that the target's white section and black circle will both be hit.
Solution:
The square's area is 10 x 10 or 100 units.
The shaded circle's area is given by πr² = 3.14 (1)² = 3.14 units.
The white area has a surface area of (100 - 3.14) = 96.86 units.
Probability of an event = The number of favorable events /Total number of events
The probability that it will occur in the shaded area = 3.14/100 = 0.0314 (The probability is close to 0).
The probability of hitting the white section is equal = 96.86/100= 0.9686.
(The probability is quite near to 1)
Hence, the probability of hitting the black circle inside the target is close to 0, and the probability of hitting the white portion is close to 1.
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what is x
x =x=x, equals
^\circ
∘
degrees
HELP ASAP PLEASE
Select the correct answer. Figure 1 has been transformed to produce figure 2. Which notation describes this transformation?
Figure 1 was translated using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.
What is transformation?Transformation is the movement of a point from its initial location to a new location. Types of transformation are translation, reflection, rotation and dilation.
Translation is the movement of a point either up, down, left or right on the coordinate plane.
Figure 1 was translated 9 units left and 2 units up using the rule (x', y') ⇒ (x -9, y + 2) to produce figure 2.
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why is there always more than one parallelogram with the same area and base
Answer:
If every line parallel to two lines intersects both regions in line segments of equal length, then the two regions have equal areas. In the case of your problem, every line parallel to the bases of the two parallelograms will intersect them in lines segments, each with a width of ℓ.
There are infinitely many parallelograms with the same area and base due to the variability of the height.
We have,
There is always more than one parallelogram with the same area and base because the height of the parallelogram can vary while keeping the base and area constant.
The formula to calculate the area of a parallelogram is:
Area = base × height
If the base and area of a parallelogram are fixed, we can rearrange the formula to solve for the height:
height = Area/base
Since the height can be any value as long as it satisfies the above equation, there are infinitely many possible heights for a given base and area.
And for each height, there will be a unique parallelogram with that base and area.
Imagine a rectangle as a special case of a parallelogram where all angles are 90 degrees.
For a given base and area, you can have an infinite number of rectangles by varying the height.
Each rectangle will have different side lengths, but they will all have the same base and area.
Thus,
The variability of the height while keeping the base and area constant allows for the existence of multiple parallelograms with the same area and base.
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Which statements about the system are true? Select two options.
y = y equals StartFraction 1 over 3 EndFraction x minus 4.x – 4
3y – x = –7
Answer:
no solution
Step-by-step explanation:
y = (1/3)x - 4
3y - x = -7
put the first equation into the second
3(1/3)x - (3)4 - x = -7
x - 12 - x = -7
-12 = -7 can never be true so this is no solution
5/8 + 1 1/4 = x/10
solve for x
Answer:
x = 75/4
Step-by-step explanation:
5/8 + 1 1/4 = x/10
5/8 + 5/4 = x/10
15/8 = x/10
8x = 15 × 10
8x/8 = 150/8
x = 150/8
x = 75/4
12 x (3 + 2 to the second power) divied by 2 - 10
Answer:
32Step-by-step explanation:
Assuming that the question is:
12 * (3 + 2^2) : 2 - 10 = remember PEMDAS
12 * (3 + 4) : 2 - 10 =
12 * 7 : 2 - 10 =
84 : 2 - 10 =
42 - 10 =
32
Answer:
-10.5
Step-by-step explanation:
[tex]\frac{12*(3+2^2)}{2-10}[/tex]
2²= 4
3+4=7
12×7=84
2-10=-8
84÷-8= -10.5
Hope it helped, comment below if you need more assistance! :)
i’ll give brainliest!!
(last choice is d^2sqrt7e)
Answer:
D (the last choice)
Step-by-step explanation:
Taking the fourth root of each element individually:
49^(1/4) = sqrt(7)
(d^8)^(1/4) = d^2
(e^2)^(1/4) = sqrt(e)
Multiplying them back together:
sqrt(7) * d^2 * sqrt(e) = d^2 * sqrt(7e)
Answer:
The last bubble (that of which is cut from the screen) is simplified.
Step-by-step explanation:
The provided equation is simplified by following these steps:
[tex](49d^{8}e^2)^\frac{1}{4}[/tex]
= [tex](49)^\frac{1}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}[/tex]
[tex](7)^\frac{2}{4}(d)^\frac{8}{4}(e)^\frac{2}{4}[/tex]
=[tex]\sqrt{7} (d^2)(\sqrt{e})[/tex]
To find proportion of the area under the normal curve between two Z scores that are both above the mean, it is necessary to examine the ______. Group of answer choices
It is necessary to imagine the sum of the areas between each z-score and the average.
Given as the ratio of the area under the normal curve between two z-scores, both above average.
The Z score accurately measures the number of standard deviations above or below the mean of the data points.
The formula for calculating the z-score is
z = (data points – mean) / (standard deviation).
It is also expressed as z = (x-μ) / σ.
A positive z-score indicates that the data points are above average.A negative z-score indicates that the data points are below average.A z-score close to 0 means that the data points are close to average. The normal curve is symmetric with respect to the mean and needs to be investigated.Therefore, to find the percentage of the area under the normal curve between two z-scores, both above the mean, you need to look at the sum of the areas between the z-score and the mean.
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