Geometry please someone help i cant fail this class

Answer:

Needed point estimate is $372

Step-by-step explanation:

Given:

Number of houses in resident area = 121

Monthly mean car payment = $372

Find:

Best point estimate for the mean monthly car payment

Explanation:

The "best point estimate" for such average monthly automobile payment for all inhabitants of the nearby apartment complex is used as the "sample mean." In this example, a $372 sample was obtained on 121 residents.

As a result, the needed point estimate is $372.

Answer:

8 batches

in workings show whats left over but not counted.

As a batch its a whole number as the multiplier will usually be the fraction

and fraction / fraction should always show fraction but the whole number given with a remainder can be shown if not a whole number.

Step-by-step explanation:

6 1/2 = 6.5

and ;

3/4 of a pound = 0.75  of 1 pound

6.5 / 0.75 = 8.7         or in full workings write = 8.6666.....7

8.7/ 1 = 8 batches with 0.7 or 0.66667 left over

Answer In fraction for exam question given in fraction  8.7 = 8  batches

with  7/10 left over.

Step-by-step explanation:

she gives each of her children $25 each,if Raul spends $15 then he would have $10 left.

Division then subtraction can be used to solve the problem.

An expression in mathematics is made up of numbers, variables, and functions (such as addition, subtraction, multiplication or division etc.) You can think of expressions as being comparable to phrases.

Given

she gives each of her children $25 each,if Raul spends $15 then he would have $10 left.

to learn more about mathematical expressions refer to:

https://brainly.com/question/14712183

#SPJ2

Answer:

y = -4/3x -46/3

Step-by-step explanation:

The question tells us to write an equation that is:

- parallel to the given line

- goes through the point (-7, -6)

Parallel lines will have the same slope, because if the slope was different, they would eventually intersect and not be parallel lines anymore.

We are going to use the point-slope form to find the other line.

Point-slope form uses a point that the graph will cross through and the slope of the graph to find the graph in y = mx + b form (also called slope-intercept form).

(I attached the point-slope form as an image below)

m = slope

x1 = x coordinate of the point

y1 = y coordinate of the point

We are going to substitute our slope into the form first:

y - y1 = (-4/3)(x - x1)

Next let's put in our point (-7, -6):

(Remember! -7 is our x coordinate & -6 is our y coordinate :-) )

y - (-6) = -4/3(x - (-7))

(cancel out the negatives to make them positive)

y + 6 = -4/3 (x +7)

Now solve for x using basic algebra:

y + 6 = -4/3 (x +7)

(distribue the -4/3)

y + 6 = -4/3x - 28/3

(subtract 6 from both sides)

y = -4/3x -46/3

That's your answer!

Hope it helps (●'◡'●)

Answer:

Step-by-step explanation:

y + 6 = -4/3(x + 7)

y + 6 = -4/3x - 28/3

y + 18/3 = -4/3x - 28/3

y = -4/3x - 46/3

Answer:

a) 8:3, b) no formula is there, c) 30

Step-by-step explanation:

because 200/75=8:3

because there formula being obtained

because 300/24=12.5

375/12.5=30

This is the answer.

Hope it helps!!

Answer:

[tex]120.\sqrt{2}.\sqrt[3]{3}[/tex]

Step-by-step explanation:

[tex]\sqrt{32} = \sqrt{16.2} =\sqrt{4^{2}.2} = 4\sqrt{2}[/tex]

[tex]\sqrt[3]{81} =\sqrt[3]{27.3} =\sqrt[3]{3^{3}.3 }=3\sqrt[3]{3}[/tex]

∴[tex]5\sqrt{32}.2\sqrt[3]{81} =5. [4\sqrt{2}].2.[3\sqrt[3]{3} ][/tex]

                   [tex]=120.\sqrt{2}.\sqrt[3]{3}[/tex]

Answer:

We know that for a line:

y = a*x + b

where a is the slope and b is the y-intercept.

Any line with a slope equal to -(1/a) will be perpendicular to the one above.

So here we start with the line:

3x + 4y + 5 = 0

let's rewrite this as:

4y = -3x - 5

y = -(3/4)*x - (5/4)

So a line perpendicular to this one, has a slope equal to:

- (-4/3) = (4/3)

So the perpendicular line will be something like:

y = (4/3)*x + c

We know that this line passes through the point (a, 3)

this means that, when x = a, y must be equal to 3.

Replacing these in the above line equation, we get:

3 = (4/3)*a + c

c = 3 - (4/3)*a

Then the equation for our line is:

y = (4/3)*x + 3 - (4/3)*a

We can rewrite this as:

y = (4/3)*(x -a) + 3

now we need to find the point where this line ( y = -(3/4)*x - (5/4)) and the original line intersect.

We can find this by solving:

(4/3)*(x -a) + 3 =  y = -(3/4)*x - (5/4)

(4/3)*(x -a) + 3  = -(3/4)*x - (5/4)

(4/3)*x - (3/4)*x = -(4/3)*a - 3 - (5/4)

(16/12)*x - (9/12)*x = -(4/3)*a - 12/4 - 5/4

(7/12)*x = -(4/13)*a - 17/4

x = (-(4/13)*a - 17/4)*(12/7) = - (48/91)*a - 51/7

And the y-value is given by inputin this in any of the two lines, for example with the first one we get:

y =  -(3/4)*(- (48/91)*a - 51/7) - (5/4)

  = (36/91)*a + (153/28) - 5/4

Then the intersection point is:

( - (48/91)*a - 51/7,  (36/91)*a + (153/28) - 5/4)

And we want that the distance between this point, and our original point (3, a) to be equal to 4.

Remember that the distance between two points (a, b) and (c, d) is:

distance = √( (a - c)^2 + (b - d)^2)

So here, the distance between (a, 3) and ( - (48/91)*a - 51/7,  (36/91)*a + (153/28) - 5/4) is 4

4 = √( (a + (48/91)*a + 51/7)^2 + (3 -  (36/91)*a + (153/28) - 5/4 )^2)

If we square both sides, we get:

4^2 = 16 =  (a + (48/91)*a + 51/7)^2 + (3 -  (36/91)*a - (153/28) + 5/4 )^2)

Now we need to solve this for a.

16 = (a*(1 + 48/91)  + 51/7)^2 + ( -(36/91)*a  + 3 - 5/4 + (153/28) )^2

16 = ( a*(139/91) + 51/7)^2 + ( -(36/91)*a  - (43/28) )^2

16 = a^2*(139/91)^2 + 2*a*(139/91)*51/7 + (51/7)^2 +  a^2*(36/91)^2 + 2*(36/91)*a*(43/28) + (43/28)^2

16 = a^2*( (139/91)^2 + (36/91)^2) + a*( 2*(139/91)*51/7 + 2*(36/91)*(43/28)) +  (51/7)^2 + (43/28)^2

At this point we can see that this is really messy, so let's start solving these fractions.

16 = (2.49)*a^2 + a*(23.47) + 55.44

0 = (2.49)*a^2 + a*(23.47) + 55.44 - 16

0 = (2.49)*a^2 + a*(23.47) + 39.44

Now we can use the Bhaskara's formula for quadratic equations, the two solutions will be:

[tex]a = \frac{-23.47 \pm \sqrt{23.47^2 - 4*2.49*39.4} }{2*2.49} \\\\a = \frac{-23.47 \pm 12.57 }{4.98}[/tex]

Then the two possible values of a are:

a = (-23.47 + 12.57)/4.98  = -2.19

a = (-23.47 - 12.57)/4.98 = -7.23

Answer:

Distance between Amber and Claire's house = 17.63 blocks

Step-by-step explanation:

In this graph three points are showing the locations of Amber's, Betsey's and Claire's houses.

Each unit on the graph represents 1 block.

Amber walks from her house to Claire's house, then on to Betsey's house.  

We have to calculate the distance covered by Amber.

Since Distance from Claire's house to Betsey's house = 7 blocks = 7 units

and distance between Amber and Betsey's house = 8 blocks = 8 units

Now we will calculate the distance between Amber and Claire's house by Pythagoras theorem.

Distance² = 7² + 8² = 49 + 64 = 113

Distance = √113 units = 10.63 units

Therefore, total distance walked by Amber = 10.63 + 7 = 17.63 units = 17.63 blocks

Answer:

the answer might be 17. 63 because there are 7 blocks in between them so try that sorry if its wrong

Answer:

2.113

Step-by-step explanation:

               [tex]3.600\\1.487 \ -\\\overline{2.113}[/tex]

Answer: 21

Step-by-step explanation:

My teacher just did it

9514 1404 393

Answer:

  b. Victoria's method is linear because the number of minutes increased by an equal number every month

Step-by-step explanation:

Zach's reading doubled each month, a characteristic of an exponential function.

Victoria's reading increased by 15 minutes each month, characteristic of a linear function.

The only reasonable description among those offered is the one shown above: choice B.

Answer:

dilation

Step-by-step explanation:

Answer:

y=1

Step-by-step explanation:

Answer:

SEESH thanks for the points

Step-by-step explanation:

Answer:

283 flowers

Step-by-step explanation:

c=2pi*r

c = 1130.973 =1131

1131/4

282.75 = 283

Answer:

it is (4,120)

hope this helps you

Answer:

[tex]x = 2.62[/tex] and [tex]x = 0.381[/tex]

Step-by-step explanation:

[tex]y = \sqrt x\\[/tex]

[tex]y = x - 1[/tex]

Required

y, when they are equal.

To do this, we set them to another

[tex]\sqrt{x} = x - 1[/tex]

Square both sides

[tex]x = (x - 1)^2[/tex]

Expand

[tex]x = x^2 - 2x + 1[/tex]

Collect like terms

[tex]x^2 -x-2x+1 = 0[/tex]

[tex]x^2 - 3x + 1 = 0[/tex]

Using quadratic formula

[tex]x = 2.62[/tex] and [tex]x = 0.381[/tex]

Answer:

x = ±i√2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Multiplication Property of Equality

Division Property of Equality

Addition Property of Equality

Subtraction Property of Equality

Algebra II

Imaginary root i

Step-by-step explanation:

Step 1: Define

Identify

5x² - 2 = -12

Step 2: Solve for x

Answer:

The answer is 10, hope this helps!

Step-by-step explanation:

Step-by-step explanation:

Given

f(x) = 2x + 9

f^-1 (x) = ?

Let

y = f(x)

y = 2x + 9

Interchanging the roles of x and y we get

x = 2y + 9

2y = x - 9

y = ( x - 9) / 2

Therefore

⏩f^-1(x) = (x-9)/2

Hope it will help :)

Answer:

The maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

Step-by-step explanation:

Given;

F = 4y - 3x

The function is subject to  y ≤ 2x - 1,

                                            y ≥ -2x + 3,

                                               x ≤ 3

           y ≤ 2x - 1  

      -  ( y ≥ -2x + 3)

        -------------------

          0 ≤ 4x - 4

           4 ≤ 4x

            1 ≤ x

thus,   1 ≤  x ≤ 3

When x = 3

y ≤ 2x - 1     ⇒     y ≤ 2(3) - 1,        ⇒ y ≤ 5

y ≥ -2x + 3,  ⇒    y ≥ -2(3) + 3,      ⇒ y ≥ - 3

thus, -3 ≤  y  ≤ 5

When x = 1

y ≤ 2x - 1     ⇒     y ≤ 2(1) - 1,        ⇒ y ≤ 1

y ≥ -2x + 3,  ⇒    y ≥ -2(1) + 3,      ⇒ y ≥ 1

when x = 1 and y = 1

F = 4(1) - 3(1)

F = 1

when y = -3, and x = 3

F = 4(-3) - 3(3)

F = -12 - 9

F = - 21

When y = 5 and x = 3

F = 4(5) - 3(3)

F = 20 - 9

F = 11

Therefore, the maximum value of the function = 11, at x = 3 and y = 5

The minimum value of the function = -21, at x = 3 and y = -3

Answer:

C. <C is congruent to <Y

Step-by-step explanation:

to be AAS the angles need to be next to each other

Answer:

The 95% confidence interval for the proportion of students who work out 4 or more times a week is (0.2432, 0.3568).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

In a random sample of 250 students, we found that 75 work out 4 or more times a week.

This means that [tex]n = 250, \pi = \frac{75}{250} = 0.3[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

The lower limit of this interval is:

[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3 - 1.96\sqrt{\frac{0.3*0.7}{250}} = 0.2432[/tex]

The upper limit of this interval is:

[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3 + 1.96\sqrt{\frac{0.3*0.7}{250}} = 0.3568[/tex]

The 95% confidence interval for the proportion of students who work out 4 or more times a week is (0.2432, 0.3568).

Answer:

50.24 or 50.272

Step-by-step explanation:

Square radius and then times by 3.14 or 3.142

4^2*3.14 = 50.24

4^2*3.142 = 50.272

Answer:

Step-by-step explanation:

Answer:

hope it will help u

Answer:

Sample Answer: If there is no remainder, then the dividend is equal to the quotient times the divisor.

The quotient and divisor are both polynomials, and their product, the dividend, is a polynomial.

If there is a remainder, then it gets added on to the product of the quotient and the divisor.

The sum of the remainder and the product of the quotient and divisor is the dividend, which is a polynomial.

Step-by-step explanation:

for sure enjoy!

Answer:

If there is no remainder, then the dividend is equal to the quotient times the divisor.

The quotient and divisor are both polynomials, and their product, the dividend, is a polynomial.

If there is a remainder, then it gets added on to the product of the quotient and the divisor.

The sum of the remainder and the product of the quotient and divisor is the dividend, which is a polynomial.