g A person exploring a deep cave system becomes injured and needs to be rescued. The fastest way to get them is to pull them straight up out of the cave through a small opening just overhead, using a motor-driven cable. The lift is performed in three stages, each of them 10 m in height (total of 30 meters to extract the person). In the first stage, the person is accelerated to a speed of 5 m/s. They are then lifted at constant speed of 5 m/s, then in the last stage they are slowly decelerated to zero speed. If the person weighs 80 kg, how much work is done in each stage

Answer:

Explanation:

Before you can find the force, you need to find the acceleration.

Givens

vi = 0

vf = 30 m/s

t = 7 seconds

Formula

a = (vf - vi) / t

Solution

a = (30 - 0)/7

a = 4.28 m/s

Now you can look at the Force

F = m * a

F = 1.00*10^3 * 4.28

F = 4.28 * 10^3 N

Answer:Type of metal

Explanation:Basically certain types of metal may heat and get cold faster maybe the alumm may collect more sun and heat more and stay that way

Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.

The ability of a material to conduct or transport heat is referred to as thermal conductivity.

Here,

It is not the solid itself that moves in bulk as a result of thermal conductivity; rather, it is molecular agitation and contact.

A region of high temperature and high molecular energy is moved towards a region of lower temperature and lower molecular energy via a temperature gradient.

The density of aluminium is small. It is easily castable, machinable, and formable, and it has a high thermal conductivity and great corrosion resistance.

At 20 °C, gold has an electrical resistivity of 0.022 micro-ohm m and a thermal conductivity of 310 W m-1 K-1.

Aluminium conducts more heat than gold.

Hence,

Due to the higher thermal conductivity of aluminium, it has higher temperature than gold.

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Answer:

1-steal an inhaler 2-use it 3-your good

orrrr

1-swallow air(preferably air from space)

Answer:

then breath

Explanation:

Answer:

X-rays are most often used to examine bones and teeth.

Hope this helps!

Explanation:

25.61 cm * 1 Gm

100000000000 cm = 2.561e-10 Gm

1 Gm = 10^9 m =10^11 cm

then 10^11 cm = 1Gm

25.61 cm = 25.61 /10^11

=25.61 * 10^-11 Gm

Answer:

5.634004 × 10^7

Explanation:

the number 7 is for the numbers before the number 5

Answer:

Same, 2 km/h/s

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

The car's acceleration is:

a = (65 km/h − 60 km/h) / 2.5 s

a = 2 km/h/s

The bicycle's acceleration is:

a = (5 km/h − 0 km/h) / 2.5 s

a = 2 km/h/s

The cyclist's acceleration to the nearest tenth is: C. 2.7 [tex]m/s^2[/tex].

Given the following data:

To find the cyclist's acceleration to the nearest tenth:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]A = \frac{V - U}{t}[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]A = \frac{12.5\; - \;0}{4.5} \\\\A = \frac{12.5}{4.5}[/tex]

Acceleration, A = 2.7  [tex]m/s^2[/tex]

Therefore, the cyclist's acceleration to the nearest tenth is 2.7 [tex]m/s^2[/tex].

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Answer:

Pls can you send the following graphs

Answer:

ω = 15275.25 rad/s

Explanation:

Given that,

Radial acceleration of an ultracentrifuge is, [tex]a=5\times 10^5g[/tex]

Distance from the axis, r = 2.1 cm = 0.021 m

g is the free-fall acceleration such that g = 9.8 m/s²

We need to find the angular speed of an ultracentrifuge. The formula that is used to find the angular speed is given by formula as follows :

[tex]a=r\omega^2[/tex]

Putting all the values,

[tex]\omega=\sqrt{\dfrac{a}{r}} \\\\\omega=\sqrt{\dfrac{5\times 10^5\times 9.8}{0.021}} \\\\\omega=15275.25\ rad/s[/tex]

So, the required angular speed, ω, of an ultracentrifuge is 15275.25 rad/s.

Answer:

3

Explanation:

5 1/3 - 2 1/3  = 3

Broken down: 1/3 - 1/3 = 0      5 - 2 = 2

Answer:

152 N

Explanation:

From the question,

F-F' = ma................. Equation 1

Where F = Horizontal force, F' = Frictional force, m = mass of the object, a = accleration of the object.

But,

F' = mgμ............... Equation 2

Where g = acceleration due to gravity, μ = coefficient of friction.

make m the subject of the equation

Substitute equation 2 into equation 1

F-mgμ = ma.

make m the subject of the equation

m = F/(gμ+a).............. Equation 3

Given: F = 125 N, g = 9.8 m/s², μ = 0.7, a = 1.2 m/s²

Substitute these value into equation 3

m = 125/[(9.8×0.7)+1.2)

m = 125/8.06

m = 15.51 kg.

But,

W = mg.............. Equation 4

Where W = weight of the object.

W = 15.51(9.8)

W = 152 N

1)The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.

Answer:

Efficiency = 65%

Explanation:

The formula of Efficiency applied to any circumstance is:

Efficiency = Useful Energy / Energy applied

Then replacing the values given its:

Efficiency = 25 J / 32 J

Efficiency = 0.65

0.65 written as percentage is 65%, then:

Efficiency = 65%

As you do 32 joules of work using a pair of scissors and the scissors do 25 joules of work cutting a piece of fabric, the efficiency of the scissors is 78.125%.

Efficiency is the proportion of work done by a machine or throughout a process to the overall amount of energy or heat used.

The ratio of usable output to total input can be used to objectively measure efficiency. The efficiency of the device is defined as the ratio of energy converted to a useable form to the original amount of energy supplied.

Mathematically,

efficiency of a machine = (work output/work input)×100%

Given parameters:

Input work to the pair of scissors= 32 joules.

Output work from the pair of scissors= 25 joules.

Hence,

The efficiency of a machine = (work output/work input)×100%

= ( 25 joule/32joule)×100%

= 78.125%

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Answer:

Correct choice: 5,400 Km/h

Explanation:

Unit Conversions

We'll use the following conversions:

1 Km = 1,000 m

1 h = 3,600 s

Convert the speed of sound in water (1.5\cdot 10^3\ m/s) to Km/h:

[tex]\displaystyle 1.5\cdot 10^3\ m/s*\frac{ 3,600\ s/h}{ 1000 \ Km/m}[/tex]

[tex]=5,400\ Km/h[/tex]

Correct choice: 5,400 Km/h

Answer:

"is constant"

Answer:

Find the explanation below.

Explanation:

Earth is properly designed to support life. This is seen in the favorable temperature that supports life, the water cycle that recycles water for plant and animal life, the atmosphere, energy, and nutrients.

1. Temperature: The temperature which is regulated by the different weather conditions such as the rains, snows, dry seasons all help to maintain a stable condition for life.

2. Water: The water cycle through processes like evaporation, condensation, precipitation, helps to ensure that there is never a lack of water in the earth. The numerous water bodies like the seas, oceans, rivers, lakes, also provide a habitat for some living things. Water makes up 70% of the earth.

3. Atmosphere: The atmosphere is a mixture of gases in the right proportions that are necessary for life. Oxygen, Nitrogen, Carbon, etc are released and inhaled by man and other living things. They are also involved in so many biochemical reactions that help in metabolism and catabolism.

4. Energy: Energy generated from the sun and within the earth is stored in various forms and is always conserved. This energy is converted to different states such as the potential, chemical, kinetic, mechanical forms to get work done and to release heat.

5. Nutrients​: Though cycles such as the carbon, nitrogen, oxygen, and phosphorous cycles, the earth maintains its stock of essential nutrients that help to sustain life.

An interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.

Temperature: Monitoring and analyzing climate data from numerous sources, including weather stations, satellites, and ocean buoys, is necessary to determine the Earth's temperature. To understand how temperature patterns vary over time, scientists look at long-term trends, seasonal variations, and severe events. They forecast future temperature increases and their possible effects on life and ecosystems using global climate models.

Water: Monitoring freshwater availability, water quality, and water distribution throughout various regions are all part of the assessment of Earth's water resources. Studies of precipitation patterns, data on ice melting from polar regions, and measurements of water levels in lakes, rivers, and aquifers are all conducted by researchers. Testing for toxins, pollutants, and chemical compositions is part of evaluating water quality to make sure it adheres to acceptable standards for both ecological and human health.

Atmosphere: scientists measure and research a number of factors, such as greenhouse gases, air quality, and atmospheric pressure, in order to evaluate the Earth's atmosphere. Carbon dioxide (CO2), methane (CH4), and other greenhouse gases are measured at monitoring sites throughout the globe to better understand how they contribute to climate change. Pollutants like particle matter and ozone, which have an influence on both human health and ecosystems, are measured by air quality monitoring stations.

Energy: studying diverse energy sources and their effects on the environment and ecosystems is necessary to evaluate the amount of energy present on Earth. Scientists assess the usage of non-renewable energy sources like fossil fuels as well as renewable energy sources like solar, wind, hydro, and geothermal energy. To create sustainable energy plans that support life on Earth, they examine energy consumption trends, carbon emissions, and energy efficiency.

Nutrients: studying nutrient cycles and availability in soils, oceans, and terrestrial ecosystems is necessary for evaluating the availability of nutrients in the Earth's ecosystems. To determine the nutrient levels for agriculture and plant growth, researchers examine soil samples. In order to gauge the productivity and availability of nutrients for marine life, they also research marine ecosystems.

Hence, an interdisciplinary approach encompassing climatology, oceanography, environmental science, and other fields of study is necessary to evaluate the Earth's capacity to support life.

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Answer:

Explanation:

The velocity of the car can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex]v = \frac{600}{25} \\ [/tex]

We have the final answer as

Hope this helps you

Complete Question

The positive [tex]muon (^+)[/tex], an unstable particle, lives on average [tex]2.20 * 10^{-6}\ s[/tex]  (measured in its own frame of reference) before decaying.

If such a particle is moving, with respect to the laboratory, with a speed of 0.950 c , what average lifetime is measured in the laboratory?

Answer:

The value is  [tex]\Delat  t  =  7.046 *10^{-6} \  s[/tex]

Explanation:

From the question we are told that

   The the average live time of  [tex]muon (^+)[/tex] is  [tex]\Delta t_o  =  2.20 *10^{-6} \  s[/tex]

    The speed of of [tex]muon (^+)[/tex]  in the laboratory is  [tex]v  =  0.950 c[/tex]

Generally the average life time of the positive [tex]muon (^+)[/tex] measured in the laboratory  is mathematically represented as

 [tex]\Delat  t  =  \frac{\Delta t_o }{ \sqrt{1 - \frac{v^2}{c^2} } }[/tex]

 [tex]\Delat  t  =  \frac{2.20 *10^{-6}}{ \sqrt{1 - \frac{(0.950 c)^2}{c^2} } }[/tex]

   [tex]\Delat  t  =  \frac{2.20 *10^{-6}}{ \sqrt{1 - \frac{0.9025 c^2}{c^2} } }[/tex]  

   [tex]\Delat  t  =  \frac{2.20 *10^{-6}}{ \sqrt{1 - 0.9025  } }[/tex]

   [tex]\Delat  t  =  \frac{2.20 *10^{-6}}{ \sqrt{ 0.0975  } }[/tex]

     [tex]\Delat  t  =  7.046 *10^{-6} \  s[/tex]

Answer:

Initial position of a body is the position of the body before accelerating or increasing its velocity the position changes and then that position is the final position.

hope it is helpful...

Answer:

Rotation frequency is 0.377 hertz.

Explanation:

After a careful reading of statement, we need to apply the concept of radial acceleration due to uniform circular motion, whose formula is:

[tex]a_{r} = \omega^{2}\cdot L[/tex] (Eq. 1)

Where:

[tex]a_{r}[/tex] - Radial acceleration, measured in meters per square second.

[tex]\omega[/tex] - Angular velocity, measured in radians per second.

[tex]L[/tex] - Length of the beam, measured in meters.

Now we clear the angular velocity within:

[tex]\omega = \sqrt{\frac{a_{r}}{L} }[/tex]

If [tex]a_{r} = 29.9\,\frac{m}{s^{2}}[/tex] and [tex]L = 5.33\,m[/tex], the angular velocity is:

[tex]\omega = \sqrt{\frac{29.9\,\frac{m}{s^{2}} }{5.33\,m} }[/tex]

[tex]\omega \approx 2.368\,\frac{rad}{s}[/tex]

The frequency is the number of revolutions done by device per second and can be found by using this expression:

[tex]f = \frac{\omega}{2\pi}[/tex] (Eq. 2)

Where [tex]f[/tex] is the frequency, measured in hertz.

If we know that [tex]\omega \approx 2.368\,\frac{rad}{s}[/tex], then rotation frequency is:

[tex]f = \frac{2.368\,\frac{rad}{s} }{2\pi}[/tex]

[tex]f = 0.377\,hz[/tex]

Rotation frequency is 0.377 hertz.

Answer:

v = 20.69 m/s

Explanation:

Given that,

Initial speed of a stone, u = 7.59 m/s

he stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand, h = 18.9 m

We need to find the speed of the stone impact the ground. Let the speed be v. Using the equation of kinematics to find v. So,

[tex]v^2-u^2=2as[/tex]

Here, a = g

So,

[tex]v^2=2gs+u^2\\\\v=\sqrt{2gs+u^2} \\\\v=\sqrt{2\times 9.81\times 18.9+(7.59)^2} \\\\v=20.69\ m/s[/tex]

So, the speed of the stone impact the ground is 20.69 m/s.

Answer:

356°C.

Explanation:

(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.

That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.

(2). The next thing to do is to determine the fourier number.

fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.

(3). The next thing is to determine the temperature at the center plane after 15 s of heating.

The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).

The temperature at the center plane after 15 s of heating = 356°C.

Answer:

Sound Waves

Light Waves

Explanation:

Answer:

a = - 3 m/s^2 (negative 3 meters per second squared)

Explanation:

We use the formula for acceleration as the change in velocities (from initial velocity "vi" to final velocity "vf") divided the time "t" it took. In our case:

a = (vf - vi) / t = (0 - 10) / 3.3 = -10 /3.33 = -3 m/s^2

Answer:

mol

Explanation:

Answer:

Explanation:

Ideal gas equation- The volume (V) occupied by the n moles of any gas has pressure(P) and temperature (T) Kelvin,

the relationship for these variables PV=nRT where R gas constant is called the ideal gas law

Derivation of the Ideal Gas Equation

Let us consider the pressure exerted by the gas to be ‘p,’

The volume of the gas be – ‘v’  

Temperature be – T  

n – be the number of moles of gas

Universal gas constant – R

According to Boyle’s Law,

it constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.

i.e. v∝1p ………………………………(i)

According to Charles’ Law,

When p & n are constant, the volume of a gas bears a direct relation with the Temperature.

i.e. v∝T ………………………………(ii)

According to Avogadro’s Law,

When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.

i.e. v∝n ………………………………(iii)

Combining all the three equations, we have-

v∝nTp

or pv=nRT

where R is the Universal gas constant, which has a value of 8.314 J/mol-K

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved