For the scale factor n = 3, select a line segment other than LK that is not a vertical or horizontal line segment. Next, compute the slope m of your
line segment in the preimage and the image using the slope formula m= Show your work.

Answer: A/D/E

Step-by-step explanation:

2x + y = -5

-2x = y

2x = 4 - y

Answer:

line r

Step-by-step explanation:

Given that circle A is externally tangent to Circle B

line AM is perpendicular to line r

Answer:

[tex]\alpha = 35º[/tex]

Step-by-step explanation:

Primeiro, vamos dizer que essa folha tem extremidades nos pontos [tex]A, B, C, D[/tex].

E vamos chamar os vértices do triângulo que contém o ângulo [tex]\alpha[/tex] de [tex]E, F, G[/tex].

Na semireta de baixo, formada por [tex]DC[/tex], a gente tem um ângulo de [tex]70º[/tex] e um outro ângulo de [tex]90º[/tex] (porque ele indica um ângulo reto).

Vamos dizer que estes dois ângulos se encontram no ponto [tex]E[/tex], que combinamos antes, como vértice (extremidade) do triângulo de cima.

Como os dois ângulos, estão num mesmo ponto, [tex]E[/tex], podemos dizer que existe um terceiro ângulo para o qual sua soma seja [tex]180º[/tex]. E tem, seria o ângulo à esquerda de

Vamos chamar este ângulo de [tex]\beta _{I}[/tex]. Portanto:

[tex]\beta _{I} + 90º + 70º = 180º\\\beta _{I} = 180º - 160º\\\beta _{I} = 20º[/tex]

Agora, temos um outro triângulo no canto inferior esquerdo da folha, cujos ângulos são [tex]\beta x_{I}[/tex], [tex]90º[/tex] e um outro ângulo, que vamos chamar de [tex]\beta x_{II}[/tex]

Esse último vai ser o ângulo superior deste triângulo, tá legal?

Então, vamos ter que:

[tex]\beta _{I} + 90º + \beta _{II} = 180º\\\beta _{I} + \beta _{II} = 90º\\[/tex]

Como [tex]\beta _{I} = 20º[/tex],

[tex]\beta _{I} + \beta _{II} =20º + \beta _{II}[/tex]

[tex]20º + \beta _{II} = 90º\\\beta _{II} = 90º - 20º\\\beta _{II} = 70º[/tex]

Ou seja, o ângulo superior do triângulo no canto inferior esquerdo, é 70º.

Vamos concordar, que este mesmo triângulo tem vértices nos pontos [tex]F, D, E[/tex]. Onde [tex]F[/tex] é o ponto superior, [tex]D[/tex] é a extremidade inferior esquerda do retângulo e [tex]E[/tex] é aquele mesmo ponto em que se encontram os ângulos de [tex]90º[/tex]e [tex]70º[/tex].

Mais à frente, você vai entender o porquê é importante nomear estes pontos, eu fiquei 40 minutos tentando fazer essa questão sem fazer isso e  não conseguia porque empacava numa parte da resolução.

Então, agora, sabemos que o ângulo [tex]\beta _{II}[/tex], que é o encontro dos seguimentos [tex]FD[/tex] e [tex]EF[/tex] vale [tex]70º[/tex].

Até aqui, foi só aplicar propriedades. Mas, a partir desse ponto, você vai precisar usar a criatividade.

Então, você entende que o ângulo [tex]\beta _{II}[/tex] está inserido numa reta com outros dois ângulos concentrados no ponto [tex]F[/tex].

Então, pode dizer que esse ângulo externo é o suplemento de [tex]\beta _{II}[/tex].

Vamos chamar todo ele de [tex]\beta _{III}[/tex]

[tex]\beta _{II} + \beta _{III} = 180º\\70º + \beta _{III} = 180º\\\beta _{III} = 180º - 70º\\\beta _{III} = 110º[/tex]

Agora, vamos elevar o nível de criatividade no raciocínio e ver também que temos um quadrilátero formado pelos pontos [tex]A, G, F, E[/tex]

A soma dos ângulos de qualquer quadrilátero é 360º.

E temos que esse mesmo quadrilátero é formado por dois ângulos retos, além do ângulo de 110º que calculamos.

A última extremidade que falta é um ângulo formado pela soma de [tex]\alpha[/tex] a um outro ângulo, que vamos chamar de [tex]\beta _{IV}[/tex].

Então, temos que:

[tex]90º + 110º + 90º + \alpha + \beta _{IV} = 360º\\\alpha + \beta _{IV} +290º = 360º\\\alpha + \beta _{IV} = 360º + 290º\\\alpha + \beta _{IV} = 70º\\[/tex]

De todas, as etapas dessa resolução essa é a mais importante de entendermos os pontos que definimos. Eu refiz ela várias vezes porque não fiz isso antes.

Mas, veja, quando a gente dobra a folha, pegamos um formato qualquer e destacamos do resto dela.

Isso quer dizer que o formato que ficou dobrado é o mesmo que falta na folha. Do contrário, estaríamos criando folha ou excluindo matéria, o que não é possível no caso de uma simples dobra.

Em outras palavras, os triângulos [tex]AGF[/tex] e [tex]EFG[/tex] são os mesmos. (Eu recomendo que você construa esse desenho e coloque as letras em cada ponto, pra visualizar melhor.)

Isso é o mesmo que dizer que os ângulos de um vão ser os ângulos do outro.

Portanto, os ângulos são equivalentes. (Mesmos ângulos para ambos os triângulos, mudando só de posição.)

Assim, você pode afirmar que [tex]\alpha[/tex] = [tex]\beta _{IV}[/tex]

Se subirmos um pouco a resolução, vamos lembrar que encontramos que [tex]\alpha + \beta _{IV} = 70º\\[/tex]

Se [tex]\alpha = \beta _{IV}[/tex]

Temos:

[tex]\alpha + \alpha = 70º\\2\alpha = 70º\\\alpha = \frac{70º}{2} \\[/tex]

e TCHARAAN!

[tex]\alpha = 35º[/tex]

-------------------------

Força, guerreiro(a). Sucesso e que Deus te abençoe nos estudos.

Answer:

35

Step-by-step explanation:

j(j + 3) = 1330

Trial and error method:

j and j + 3 are pretty close to each other. Start by taking the square root of 1330.

sqrt(1330) = 36.5. One number is less than 36.5 and the other number if 3 more than that.

Since the product of j and j + 3 is 1330 which ends in 0, it is a multiply of 10 and 5.

Try 35 and 38. 35 * 38 = 1330

Answer: 35

Equation method:

j(j + 3) = 1330

j^2 + 3j - 1330 = 0

(j + 38)(j - 35) = 0

j = -38 or j = 35

Answer: 35

If Jon is 3 years younger than Laura, then Jon's age is 35years.

Let the age of John be j

If Jon is 3 years younger than Laura, then;

Laura's age = j + 3

Based on the question, we are told that the product of their ages is 1,330, this can be expressed as:

j(j+3) = 1330

Expand

j²+3j = 1330

j²+3j - 1330 = 0

j²+38j-35j-1330 =0

j(j+38)-35(j+38) = 0

(j−35)(j+38) = 0

j = 35 and j = -38

j = 35

Hence Jon's age is 35years.

Learn more here: https://brainly.com/question/14294864

Answer:

2972.5

Step-by-step explanation:

3500*7/8 - 90 = 2972.5

Answer: 4:3

eats out : not eating out

Step-by-step explanation:

so theres 7 days in a week so you do simple subtraction and do 7-4=3

then you get the remaining days of the week that you dont eat out.

10c^6d^-5×2c^-5d^4

20cd^-1

20c×1/d

20c/d

Answer:

No.

Step-by-step explanation:

Irrational numbers are numbers that you can't solve like 3 squared. See you can't find the end of 3 squared, the numbers will go on forever just like pi.

Answer:

No

Step-by-step explanation:

A rational number can be written as the ratio of integers

-4/-1 = -4

This is a rational number

Answer: [tex]x(t)=-1[/tex]

[tex]y(t)=-4+4(t)[/tex]

[tex]z(t)=2-5(t)[/tex]

Step-by-step explanation:

To find: The vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3).

Let A (−1,−4,2) and B(−1,0,−3)

First we find direction vectors : [tex]\overrightarrow{AB}=<-1-(-1),0-(-4),-3-2>[/tex]

[tex]<0,4,-5>[/tex]

Now, the parametric equations of the line:

[tex]x(t)=-1+0(t)[/tex]

[tex]y(t)=-4+4(t)[/tex]

[tex]z(t)=2-5(t)[/tex]

Hence, the vector parametric equations for the line through the points (−1,−4,2) and (−1,0,−3):

[tex]x(t)=-1[/tex]

[tex]y(t)=-4+4(t)[/tex]

[tex]z(t)=2-5(t)[/tex]

Answer:

91

Step-by-step explanation: 7*13 = 91

91/7 = 13

Answer: D. (-2, 1)

Step-by-step explanation:

original coordinate of L: (0, -3)

2 units left: x-2

4 units up: y+4

 (x-2, y+4)

=(0-2, -3+4)

=(-2, 1)

Hope this helps!! :)

Answer:

Interquartile range => 7

Third quartile => 22

Range => 13

First quartile => 15

Step-by-step explanation:

Order your data set, from the least amount to the highest amount:

$12, $14, $15, $15, $15, $15, $16, $22, $24, $25

Interquartile range (IQR) = third quartile (Q3) - first quartile (Q1)

Q1 = the middle value of the lower part of the data set, from the median to your left.

Q3 = the middle value of the upper part of the data set, from the median to your right.

The median lies between the 5th and 6th value that is enclosed in the parenthesis below:

$12, $14, ($15), $15, $15,[Median], $15, $16, ($22), $24, $25

The median divides the data set into upper and lower part.

Median = [tex] \frac{15 + 15}{2} = 15 [/tex]

First quartile: Q1 = $15

Third quartile: Q3 = $22

IQR = $22 - $15 = $7

Range = highest amount - least amount = 25 - 12 = $13

Answer: First solve the parentheses using order of operations. Then add and subtract from left to right.

Demo:

(3 * 11) = 33

Equation now looks like:

63 - 21 + 33

63 - 21 = 42

Equation now looks like:

42 + 33

42 + 33 = 75

The value of this expression is 75.

Answer:

Step-by-step explanation:

Answer: 0.07 calculatorsoup for significant rounding

Answer:

$12 the hour

Step-by-step explanation:$360 divided by 30 is 12, meaning he will need to make a minimum of 12 an hour to support his family.

Answer: 12 dollars

Step-by-step explanation:

360 divided by 30 is 12

Answer: 0.7 liters

Step-by-step explanation:

First convert 3 cups to Liters

3 cups = 0.709765

Now round 0.709765 to the nearest 10 which give you 0.7

Answer:

0.7 liters Hope this helps!

Step-by-step explanation:

Answer:

The answer is "It is not highly probable".

Step-by-step explanation:

In the given question some data is missing, that's why first we define value than its solution:

Missing value:

[tex]\bar x= 0.15\\\\s=0.06[/tex]

Solution:

[tex]\to \ H_0 : \mu \leq 0.10\\\to H_1: \mu > 0.10[/tex]

Formula:

[tex]Z= \frac{x-\mu}{s}\\\\[/tex]

   [tex]=\frac{0.15- 0.10}{0.06}\\\\=\frac{0.05}{0.06}\\\\=\frac{0.05}{0.06}\\\\=.833\\[/tex]

calculating the value of x:

formula:

[tex]x=X(Z>z)[/tex]

   [tex]=0.833-0.841\\\\=-0.008[/tex]

Answer:  $6,144

Step-by-step explanation:

In March her commission was;

= 3% * 20,000 + 8% ( 54,500 - 20,000)

= $3,360

In April;

= 3% * 20,000 + 8% ( 47,300 - 20,000)

= $2,784‬

Total commission

= 3,360 + 2,784

= $6,144

Answer:

Graph the two struts on the model of the roller coaster. Take a screenshot of your graph and paste the image below, or sketch a graph by hand. (5 points)

Recall that a reinforcement beam will extend from one strut to the other when the two struts are 2 feet apart.

•

• Algebraically determine the x -value of where the beam should be placed. (15 points)

root(x + 8) = 2 + rootx − 4)

x + 8 = 4 + 4root(x − 4) + x − 4

8 = 4root(x − 4)

2 = root(x − 4)

x − 4 = 4

x = 8

• Explain where to place the beam.  (10 points)

The beam should be places 8 feet apart.

Step-by-step explanation:

I don't have a graph. Correct on E2020

Hope that this helps. If someone finds a graph i have a question on my page that needs it

Peace and love

Answer:

Here is the missing graph.

Answer:

480 markers

Step-by-step explanation:

694 - (78+136) =

694 - 214

= 480 markers

Answer:

694 - 78 = 616, then you take 616 - 136 = 480 total markers left.

         (out of ^ ink)           (the ones she ^ gives to her friend)                                    

Step-by-step explanation:

480 markers are left for her first week of summer! hope this helps, good luck!

Answer:

-$50 lol

Step-by-step explanation:

Hi :)

To find your balance after you withdraw $50, simply take your balance, and subtract $50

balance-withdraw=balance

Hope this helps,

Jeron

Answer:

Step-by-step explanation:

Given the functions  z=(x+y)[tex]e^y\\[/tex] and x=u²+v² and y=u²−v²

Using the composite derivative formula;

∂z/∂u= ∂z/∂x*∂x/∂u+∂z/∂y*∂y/∂u

∂z/∂u = y[tex]e^y[/tex]*2u + [(x+y)[tex]e^y[/tex]+x[tex]e^y[/tex]]*2u

∂z/∂u =y[tex]e^y[/tex]*2u + 2u[x[tex]e^y[/tex]+y[tex]e^y[/tex]+x[tex]e^y[/tex]]

∂z/∂u = y[tex]e^y[/tex]*2u + 2u[2x[tex]e^y[/tex]+y[tex]e^y[/tex]]

∂z/∂u = 2u[u²−v²][tex]e^{u^2-v^2}[/tex]+ 2u[2(u²+v²)[tex]e^{u^2-v^2}[/tex]+y[tex]e^{u^2-v^2}[/tex]]]

∂z/∂v= ∂z/∂x*∂x/∂v+∂z/∂y*∂y/∂v

∂z/∂v = y[tex]e^y[/tex]*2v + [(x+y)[tex]e^y[/tex]+x[tex]e^y[/tex]]*-2v

∂z/∂v =y[tex]e^y[/tex]*2v -2v[x[tex]e^y[/tex]+y[tex]e^y[/tex]+x[tex]e^y[/tex]]

∂z/∂v = y[tex]e^y[/tex]*2v -2v[2x[tex]e^y[/tex]+y[tex]e^y[/tex]]

∂z/∂v = 2v[u²−v²][tex]e^{u^2-v^2}[/tex]-2v[2(u²+v²)[tex]e^{u^2-v^2}[/tex]+y[tex]e^{u^2-v^2}[/tex]]

Answer:

Rational

Explanation: because it can be expressed in the quotient of two integers:67÷1

Answer:

Step-by-step explanation:

√2 + √3 + √3 - √7 + √7 - √ 2

by changing the position

√2 - √2 + √3 + √3 - √7 + √7

√2 and -√2 gets canceled

-√7 and √7 gets cancelled

we are left out with √3 + √3

√3 + √3 gives 2√3

so the answer is 2√3

hope this helps

plz mark as brainliest!!!!!!!!

Answer:

7 and 11.

Step-by-step explanation:

so if we say the 2 "parts" are "a" and "b" then we are left with 2 equations

a + b = 18

ab = 77

a = 18 - b

so if ab = 77

b (18 - b) also equals 77

so

-b^2 + 18b = 77

b^2 - 18b + 77 = 0

So b = 7 and 11

You could also solve this via trial and error, but this is a more analytical approach.

Answer:

2.6 ft

Step-by-step explanation:

8.3/sin 90 = MK/sin 18

MK = 8.3 sin 18 / sin 90

MK = 2.6 ft

Answer:

2.6

Step-by-step explanation:

Answer:

Our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

Step-by-step explanation:

The hypotheses would be;

Null hypothesis;H0: μ = 500

Alternative hypothesis;Ha: μ ≠ 500

Since it's two - tailed at 0.1 level of significance, then each tail will contain 5% or 0.05. From the z-table attached, the corresponding critical value of 0.05 is approximately 1.645 standard deviations from the mean.

Thus, our decision rule will be to reject The null hypothesis H0 if the test statistic is less than -1.645, or if it is greater than +1.645.

Answer:

(x + 1) (x + 2) / 2

Step-by-step explanation:

(x² − 4x − 5) / (x − 2) ÷ (2x − 10) / (x² − 4)

To divide by a fraction, multiply by its reciprocal.

(x² − 4x − 5) / (x − 2) × (x² − 4) / (2x − 10)

Factor.

(x − 5) (x + 1) / (x − 2) × (x − 2) (x + 2) / (2 (x − 5))

Reduce.

(x + 1) × (x + 2) / 2

(x + 1) (x + 2) / 2

the answer is c hope this help's

You intend to estimate a population mean μ from the following sample. 26.2 27.7 8.6 3.8 11.6 You believe the population is normally distributed. Find the 80% confidence interval.  Enter your answer as an open-interval (i.e., parentheses) accurate to twp decimal places.

Answer:

The  Confidence interval = (8.98 , 22.18)

Step-by-step explanation:

From the given information:

mean = [tex]\dfrac{ 26.2+ 27.7+ 8.6+ 3.8 +11.6 }{5}[/tex]

mean = 15.58

the standard deviation [tex]\sigma[/tex] = [tex]\sqrt{\dfrac{\sum(x_i - \mu)^2 }{n}}[/tex]

the standard deviation = [tex]\sqrt{\dfrac{(26.2 - 15.58)^2 +(27.7 - 15.58)^2 +(8.6 - 15.58)^2 + (3.8 - 15.58)^2 + (11.6 - 15.58)^2 }{5 } }[/tex]

standard deviation = 9.62297

Degrees of freedom df = n-1

Degrees of freedom df = 5 - 1

Degrees of freedom df = 4

For df  at 4 and 80% confidence level, the critical value t from t table  = 1.533

The Margin of Error M.O.E = [tex]t \times \dfrac{\sigma}{\sqrt{n}}[/tex]

The Margin of Error M.O.E = [tex]1.533 \times \dfrac{9.62297}{\sqrt{5}}[/tex]

The Margin of Error M.O.E = [tex]1.533 \times 4.3035[/tex]

The Margin of Error M.O.E = 6.60

The  Confidence interval = ( [tex]\mu \pm M.O.E[/tex] )

The  Confidence interval = ( [tex]\mu + M.O.E[/tex] , [tex]\mu - M.O.E[/tex] )

The  Confidence interval = ( 15.58 - 6.60 , 15.58 + 6.60)

The  Confidence interval = (8.98 , 22.18)