PLZ HELP ME OUT Is 1.3 rational or irrational? Is 36 rational or irrational Is 3.14 or pi rational or irrational Is 2/3 rational or irrational

Answer:

Step-by-step explanation:

42/14 = 57/x

42x = 57*14

42x = 798

x = 19 months

Answer: Actually its 18 months they calculated wrong

Answer:

[See Below]

Step-by-step explanation:

Multiply 7 by 5.

*35

Now add n to it.

*35 + n

Answer:

Eddie spent $26 total

Step-by-step explanation:

15% of 20 is 3

He paid 15% tax which is $3

He also tipped 15% of the $20 which he paid for lunch so another $3

3+3+20= $26

Answer:

1, 2, 3 and 6.

Step-by-step explanation:

Factors of 6 are 1, 2, 3 and 6.

Answer:

The answer is 47200000000

Answer:

equal and equivalent sets

Step-by-step explanation:

Answer:

9 miles

Step-by-step explanation:

Hour = 6 miles

Half an hour = 3

6 + 3 = 9

Answer:

851- 473 = 373

(751)-378 = 373

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

Find the average rate of change of the area of a circle with respect to its radius r as r changes from 3 to each of the following.

(i)    3 to 4

(ii)    3 to 3.5

(iii)    3 to 3.1

(b) Find the instantaneous rate of change when r = 3.  A'(3)

Area of a circle A(r)= πr²

The average rate of change of the area of a circle with respect to its radius

ΔA(r)/Δr = πr₂²-πr₁²/r₂-r₁

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

i) If the radius changes from 3 to 4

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(4²-3²)/4-3

ΔA(r)/Δr = π(16-9)/1

ΔA(r)/Δr = 7π

Hence, average rate of the area of a circle when the radius changes from 3 to 4 is 7π

ii) If the radius changes from 3 to 3.1

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(3.5²-3²)/3.5-3

ΔA(r)/Δr = π(12.25-9)/0.5

ΔA(r)/Δr = 3.25π/0.5

ΔA(r)/Δr = 6.5π

Hence, average rate of the area of a circle when the radius changes from 3 to 3.5 is 6.5π

iii) If the radius changes from 3 to 3.1

ΔA(r)/Δr = π(r₂²-r₁²)/r₂-r₁

ΔA(r)/Δr = π(3.1²-3²)/3.1-3

ΔA(r)/Δr = π(9.61-9)/0.1

ΔA(r)/Δr = 0.61π/0.1

ΔA(r)/Δr = 6.1π

Hence, average rate of the area of a circle when the radius changes from 3 to 3.1 is 6.1π

iv) Instantaneous rate of change A'(r) = 2πr

When r = 3;

A'(3) = 2π(3)

A'(3) = 6π

Hence, the instantaneous rate of change when r = 3 is 6π

Answer:A number decreased by 4 is the same as 12.5

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

"Sum" indicates that we add the two variables so we can eliminate option A because that has x - y = 12 not x + y = 12. We can eliminate option B because the second equation should be 4x - 2y = 18, not x - y = 18. For that same reason, we can eliminate C because the coefficients are swapped. I will assume that in option D, the second equation is 4x - 2y = 18. Since we have eliminated everything else, the answer is D.

Answer:

A:{(-9/7,-17/7)}

Step-by-step explanation:

3x - 2y - 1 = 0    ⇒  3x - 2y = 1

y = 5x + 4

then:

3x - 2(5x+4) = 1

3x - 2*5x - 2*4 = 1

3x - 10x - 8 = 1

-7x = 1 + 8

7x = 9

x = -9/7

y = 5x + 4

y = 5(-9/7) + 4

y = -45/7 + 4

y = -45/7 + 28/7

y = -17/7

Answer:

A:{(-9/7, -17/7)}

Answer:

d

Step-by-step explanation:

trust

Answer:

x = -733

Step-by-step explanation:

[tex]\sqrt[3]{x+4}[/tex] + 12 = 3

[tex]\sqrt[3]{x+4}[/tex]  = -9 (cube both sides)

x + 4 = -729

x = -733

Step-by-step explanation:

3x-12 + 6 = 14

3x-12 = 14 - 6

3x = 8 + 12

x= 20 ÷ 3

x = 6.7

Internal Angle Bisector Theoram:

Interior Angle Bisector Theorem : The angle bisector of an angle of a triangle divides the opposite side internally in the ratio of the sides containing the angle.

[tex] \Large{ \boxed{ \bf{ \color{limegreen}{Solution:}}}}[/tex]

Here, We can see that angle bisector of an angle is dividing the opposite side.

And,

From here, we can say that the ratio of side being divided is same as the ratio of sides containing this angle.

So, we can write it as,

➝ 14 : 21 = 6 : 3x - 12

Prdouct of means = Product of extremes

➝ 21 × 6 = 14(3x -12)

➝ 126 = 14(3x - 12)

➝ 9 = 3x - 12

Flipping it,

➝ 3x - 12 = 9

➝ 3x = 21

➝ x = 7

☘️ So, Value of x is [tex]\boxed{\sf{x = 7}}[/tex]

━━━━━━━━━━━━━━━━━━━━

Complete Question

A newsletter publisher believes that above 41% of their readers own a personal computer. Is there sufficient evidence at the 0.10 level to substantiate the publisher's claim?

State the null and alternative hypotheses for the above scenario.

Answer:

The null hypothesis is  [tex]H_o : p \le 0.41[/tex]

The  alternative hypothesis  [tex]H_1 : p> 0.41[/tex]

Step-by-step explanation:

From the question we are told that

      The population proportion is [tex]p = 0.41[/tex]

        The level of significance is  [tex]\alpha = 0.10[/tex]

The null hypothesis is  [tex]H_o : p \le 0.41[/tex]

The  alternative hypothesis  [tex]H_1 : p> 0.41[/tex]

Answer: a. 0.6759    b. 0.3752    c. 0.1480

Step-by-step explanation:

Given : The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard deviation of 2.2 minutes

i.e. [tex]\mu = 6.3[/tex] minutes

[tex]\sigma=2.2[/tex] minutes

Let x be the long-distance call length.

a. The probability that a call lasts between 5 and 10 minutes will be :-

[tex]P(5<X<10)=P(\dfrac{5-6.3}{2.2}<\dfrac{X-\mu}{\sigma}>\dfrac{10-6.3}{2.2})\\\\=P(-0.59<Z<1.68)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=P(z<1.68)-(1-P(z<0.59))\\\\=0.9535-(1-0.7224)\ \ \ \ [\text{by z-table}]\\\\=0.6759[/tex]

b. The probability that a call lasts more than 7 minutes. :

[tex]P(X>7)=P(\dfrac{X-\mu}{\sigma}>\dfrac{7-6.3}{2.2})\\\\=P(Z>0.318)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<0.318)\\\\=1-0.6248\ \ \ \ [\text{by z-table}]\\\\=0.3752[/tex]

c. The probability that a call lasts more than 4 minutes. :

[tex]P(X<4)=P(\dfrac{X-\mu}{\sigma}<\dfrac{4-6.3}{2.2})\\\\=P(Z<-1.045)\ \ \ \ [z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Z<1.045)\\\\=1-0.8520 \ \ \ [\text{by z-table}]\\\\=0.1480[/tex]

Complete question is;

Use technology and a t-test to test the claim about the population mean μ at the given level of significance α using the given sample statistics. Assume the population is normally distributed.

Claim: μ > 71; α = 0.05

Sample statistics:

¯x = 73.9, s = 3.7, n = 25

A) What are the null and alternative hypotheses?

Choose the correct answer below.

A. H0:μ = 71 ; HA:μ ≠ 71

B. H0:μ ≤ 71; HA:μ > 71

C. H0: μ ≥ 71; HA: μ < 71

D. H0: μ ≠ 71; HA: μ = 71

B) What is the value of the standardized test statistic? The standardized test statistic is (Round to two decimal places as needed.)

C) What is the P-value of the test statistic? P-value = Round to three decimal places as needed.)

D) Decide whether to reject or fail to reject the null hypothesis.

Answer:

A) Option B - Alternative hypothesis: HA: μ > 71

Null hypothesis: H0: μ ≤ 71

B) t = -7.54

C) p-value = 0.000

D) we reject the null hypothesis

Step-by-step explanation:

A) We are told that the claim is: μ > 71. Thus, due to the sign, the alternative hypothesis would be the claim. So;

Alternative hypothesis: HA: μ > 71

Null hypothesis: H0: μ ≤ 71

B)Formula for standardized test statistic with a t-test is;

t = (¯x - μ)/√(s/n)

Plugging in the relevant values, we have;

t = (71 - 73.9)/√(3.7/25)

t = -7.54

C) From online p-value from t-score calculator attached using t = -7.54, n = 25, significance level = 0.05, DF = 25 - 1 = 24 and a one - tailed test, we have;

p-value = 0.00001 ≈ 0.000

D) The p-value of 0.000 is less than the significance value of 0.05,thus we will reject the null hypothesis

Answer:

Estimated cost per capsule = 4.288 (penny)

Step-by-step explanation:

Given:

Cost of 1000 capsule = $42.88

Number of capsules = 1000

Find:

Estimated cost per capsule

Computation:

1 dollar = 100 penny

So,

$42.88 = 4288 penny

Estimated cost per capsule = 4288 / 1000

Estimated cost per capsule = 4.288 (penny)

Answer:

The question is not complete, but I found a possible match:

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given question. Listed below are the jersey numbers of 11 players randomly selected from the roster of a championship sports team. What do the results tell us?

86 4 85 83 9 51 24 34 28 43

Find the mode. Select the correct choice below​ and, if​ necessary, fill in the answer box to complete your choice.

A. The​ mode(s) is(are) nothing. ​(Type an integer or a decimal. Do not round. Use a comma to separate answers as​ needed.)

B. There is no mode.

Answer:

The correct answer is:

There is no mode (B.)

Step-by-step explanation:

b. The mode of data is the number that repeats the most number of times. The number that occurs most frequently. on the list of the distribution, 86 4 8 5 83 9 51 24 34 28 43, every number occurs just once, hence, there is no mode for the distribution.

a. To calculate the Mean

[tex]Mean: \frac{Sum\ of\ terms}{number\ of\ players}\\ Mean = \frac{86\ +\ 4\ +\ 8\ +\ 5\ +\ 83\ +\ 9\ +\ 51\ +\ 24\ +\ 34\ +\ 28\ +\ 43}{11}\\Mean= 34.09[/tex]

c. To calculate the median:

Median is  the mid-way term of the distribution, but first, we have to arrange the terms in ascending order (descending order can also be used)

4, 5, 8, 9, 24, 28, 34, 43, 51, 63, 86

To find the median, count the numbers equally from the left- and right-hand sides to the middle, the remaining number becomes the median. In this case, the median = 28

d. Midrange:

The midrange is the number mid-way between the greatest and smallest number in a data set. To find the midrange, we will add the smallest (4) and largest number (86), and divide by 2:

Midrange = (4 + 86) ÷ 2

Midrange = 90 ÷ 2 = 45

e. what do the results tell us:

Since only 11 of the jersey numbers were in the sample, the statistics cannot give any meaningful results

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

Hence the approximate value of x₂ is 7.9156

Greetings from Brasil...

Making the division

(X⁵ + 2X⁴ - 7X² - 19X + 15) ÷ (X² + 2X + 5)

we get

Answer:

x³ − 5x + 3

Step-by-step explanation:

To solve with long division:

Start by dividing the highest terms:

x⁵ / x² = x³

This becomes the first term of the quotient.  Multiply by the divisor:

x³ (x² + 2x + 5) = x⁵ + 2x⁴ + 5x³

Subtract from the first three terms of dividend:

(x⁵ + 2x⁴ + 0x³) − (x⁵ + 2x⁴ + 5x³) = -5x³

Drop down the next two terms and repeat the process.

To use the "box" method:

Each square in the box is the product of the term at the top of the column and the term at the end of the row.  Also, squares diagonal of each other must add up to the term outside the box.

Look at the first diagonal.  There is only one square, so that must be x⁵.  Knowing this, we can say that x³ must be at the top of the column.  We can fill in the rest of the column (2x⁴ and 5x³).

Repeat this process until all squares are filled in.

Answer: A = 58

Step-by-step explanation: The sketched region enclosed by the curves and the approximating rectangle are shown in the attachment.

From the sketches, the area will be integrated with respect to y.

To calculate the integral, first determine the limits, which will be the points where both curves meet.

In respect to y:

[tex]2x+y^{2} = 48[/tex]

[tex]2x= 48- y^{2}[/tex]

[tex]x= 24 - \frac{y^{2}}{2}[/tex]

Finding limits:

[tex]y= 24 - \frac{y^{2}}{2}[/tex]

[tex]24 - \frac{y^{2}}{2}-y=0[/tex]

Multiply by 2 to facilitate calculations:

[tex]48 - y^{2}-2y=0[/tex]

Resolving quadratic equation:

[tex]y=\frac{-2+\sqrt{2^{2}+192} }{2}[/tex]

y = 6 and y = -8

Then, integral to calculate area will be with limits -8<y<6:

[tex]A = \int {24-\frac{y^{2}}{2}-y } \, dy[/tex]

[tex]A = 24y - \frac{y^{3}}{6}-\frac{y^{2}}{2}[/tex]

[tex]A = 24.6 - \frac{6^{3}}{6}-\frac{6^{2}}{2}-[24.(-8) - \frac{(-8)^{3}}{6}-\frac{(-8)^{2}}{2}][/tex]

A = 58

The area of the enclosed region is 58 square units.

Answer:

  143,344

Step-by-step explanation:

Let d represent the total number of registered doctors. The given relation is ...

  0.323d = 46,300

Dividing by the coefficient of d, we get ...

  d = 46,300/0.323 ≈ 143,343.7

The total number of registered doctors was about 143,344.

Answer:

48.96 cm³/min

Step-by-step explanation:

We are given;

Relationship between pressure P and volume V; PV^(1.4) = C

Volume;V = 610 m³

Pressure; P = 89 KPa

Rate of decreasing pressure; dP/dt = -10 kPa/minute.

We want to find the rate at which the volume is increasing at that instance, thus, its means we need to find dV/dt

So, we will differentiate the relationship equation of P and V given.

Thus, we have;

[V^(1.4)(dP/dt)] + d(V^(1.4))/dt = dC/dt

Differentiating this gives us;

[(dP/dt) × (V^(1.4))] + [1.4 × P × V^(0.4) × (dV/dt)] = 0

Plugging in the relevant values, we have;

(-10 × 610^(1.4)) + (1.4 × 89 × 610^(0.4) × (dV/dt)) = 0

This gives;

-79334.44155 + 1620.5035(dV/dt) = 0

Rearranging, we have;

1620.5035(dV/dt) = 79334.44155

Divide both sides by 1620.5035 to give;

dV/dt = 79334.44155/1620.5035

dV/dt = 48.96 cm³/min

Answer:

Perimeter = (8x-30)

Area=(X-5)(3x-10)

Step-by-step explanation:

Perimeter equation for solving is this

2(X-5+3x-10)=p

it is length plus width twice which will equal the perimeter

solving this out

2(4x-15)=p

8x-30=p

area equation for solving this is

(x-5)(3x-10)=a

I don’t know how to solve this one out but i hope the setup helps!

Answer:

x = ±8

Step-by-step explanation:

A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

[tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]

From the question, the polar equation of the circle is:

[tex]r=\frac{8}{4+cos\theta}[/tex]

We have to make the equation to be in the form of [tex]r=\frac{ep}{1 \pm e*cos\theta}\\ \\[/tex]. Therefore:

[tex]r=\frac{8}{4+cos\theta}\\\\Multiply \ through\ numerator\ and\ denminator\ by\ \frac{1}{4}\\\\ r=\frac{8*\frac{1}{4} }{(4+cos\theta)*\frac{1}{4} }\\\\r=\frac{2}{4*\frac{1}{4} +cos\theta*\frac{1}{4}}\\ \\r=\frac{\frac{1}{4}*8}{1+\frac{1}{4}cos\theta}[/tex]

This means that the eccentricity (e) = 1/4 and the equation of the directrix is x = ±8

Answer:

x +13.

where

x is number of people

Step-by-step explanation:

Let the number of people be x

given that number of people increased by 13

increased by 13 means that we whatever is the initial number of people, new number of people is 13 more than that.

thus, new number of people = x +13

to  translate the number of people increased by 13 into an algebraic expression

we add 13 to number of people which can be represented by  x +13.

Answer: Absolute minimum: f(-1) = -2[tex]\sqrt{6}[/tex]

              Absolute maximum: f([tex]\sqrt{12.5}[/tex]) = 12.5

Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = [tex]t\sqrt{25-t^{2}}[/tex]

f'(t) = [tex]1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)[/tex]

f'(t) = [tex]\sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }[/tex]

f'(t) = [tex]\frac{25-2t^{2}}{\sqrt{25-t^{2}} }[/tex] = 0

For this function to be zero, only denominator must be zero:

[tex]25-2t^{2} = 0[/tex]

t = ±[tex]\sqrt{2.5}[/tex]

[tex]\sqrt{25-t^{2}}[/tex] ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = [tex]-\sqrt{2.5}[/tex] and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = [tex]t\sqrt{25-t^{2}}[/tex]

f(-1) = [tex]-1\sqrt{25-(-1)^{2}}[/tex]

f(-1) = [tex]-\sqrt{24}[/tex]

f(-1) = [tex]-2\sqrt{6}[/tex]

f([tex]\sqrt{12.5}[/tex]) = [tex]\sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}[/tex]

f([tex]\sqrt{12.5}[/tex]) = 12.5

f(5) = [tex]5\sqrt{25-5^{2}}[/tex]

f(5) = 0

Therefore, absolute maximum is f([tex]\sqrt{12.5}[/tex]) = 12.5 and absolute minimum is

f(-1) = [tex]-2\sqrt{6}[/tex].

Answer:

A. There are four terms.

C. The term [tex]\frac{30}{y}[/tex] is a ratio.

Step-by-step explanation:

The expression given is the sum of four components: a third order monomial ([tex]4\cdot x^{3}[/tex]), a second order monomial ([tex]-7\cdot x^{2}[/tex]), a zero order monomial ([tex]15[/tex]) and a ratio ([tex]\frac{30}{y}[/tex]). There are a sum and two differences. Hence, the correct answers are:

A. There are four terms.

C. The term [tex]\frac{30}{y}[/tex] is a ratio.

Answer:

there are 4 terms

the term 30/y is a ratio

Step-by-step explanation:

got it right on my quiz

Answer:

i believe it is 1

Step-by-step explanation:

Answer:

the slope is 1

Step-by-step explanation:

rise/run

1/1 = 1