Answer:
9.22 m=s
Explanation:
m=s×v
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jdjkdo
How much work does gravity do on a 0.110-kg ball falling from a height of 19.0 m? (Neglect air resistance.)
I’m not sure what the answers to these questions are for this sheet can u help?
Answer:
Explanation:
b. helmet is aerodynamic; and he is leaning down, which reduces his surface area
c. open parachute exposes more surface area to the air, which increases the drag
9. A and D will float because density is less than 1.0
When he pushes the object down, then lets it go, it bobs back up because of the upward force (upthrust) of the water acting on the object.
when stress is applied to an object and the object changes shape, we call this distortion, or strain. label the four images below with the type of strain shown.
Stretching, shear, shortening, and unstrained types of strain A c D 2. Displacement, rotation, and distortion are the three ways that deformation manifests.
What is an object in physics?In physics, an object is a visible grouping of matter that may move together in three dimensions via translation or rotation and may be contained by an obvious border. Everything has a unique identity that exists independently of any other features.
Is it a force or an object?A force is a push or pull that an object feels as a result of contact with another thing. Each time two things come into contact, a force is applied to each one of them.
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A 0.600-kg ball traveling at 4.00 m/s to the right collides with a 1.00-kg ball traveling at 5.00 m/s to the left. After the collision, the lighter ball is traveling 7.25 m/s to the left. What is the velocity of the heavier ball after the collision?
Explanation:
Step 1: Let the velocity of the heavier ball be V.
Step 2: Set up the equation for momentum conservation.
0.6*4 + 1.0*(-5) = 0.6*V + 1.0*7.25
Step 3: Solve the equation for V.
0.6*4 + 1.0*(-5) = 0.6*V + 1.0*7.25
0.6*4 - 1.0*7.25 = 0.6*V - 1.0*5
2.4 - 7.25 = 0.6V - 5
-4.85 = 0.6V
V = -4.85/0.6
V = -8.08 m/s
Answer:
The velocity of the heavier ball after the collision is 3.05 m/s
Explanation:
My explanation is included the pictures attached below
If the atmosphere was much thicker than it is now, how would the sun appear? A. The sun would appear the same. B. The sun would appear blue-violet. C. The sun would appear green-blue. D. The sun would appear red-orange. E. The sun would appear yellow-green.
If the atmosphere was much thicker than it is now, the sun would appear red-orange. Thus, the correct option for this question is D.
What is an atmosphere?An atmosphere may be defined as a type of layer that significantly involves the mixture that significantly surrounds any celestial body or planets like earth and mars.
According to the context of this question, if the atmosphere was twice as thick as it is now, the sky when the sun is directly above you would be a stronger blue and the sun would look yellower. The red coloration of the sun at sunrise and sunset would begin earlier at sunset and last longer in the morning. It is due to refraction.
Therefore, if the atmosphere was much thicker than it is now, the sun would appear red-orange. Thus, the correct option for this question is D.
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If a waterfall and a dam have the same height,
which one would have the most kinetic energy?
Explain why.
the following questions refer to the below molecules: (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3 question the molecule with the largest dipole moment
The CH4 molecule will have the biggest dipole moment. The symmetric of the molecules is established using the dipole moment.
A dipole moment is defined.
The size of the charge Q at each end of something like the molecules dipole times the space r seen between charges gives rise to the dipole moment (), which is a measure representing net molecular polarity. We can learn about a molecule's charge separation from its dipole moments.
What is the water dipole moment?
Its anisotropy has been calculated experimentally to be 1.855 D for a shallow groundwater monomers (1) An individual water molecule's dipole moment is known to be greatly increased in water clustered and cell contents due to polarization and molecular orbitals effects.
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The molecule with the largest dipole moment (a) co2 (b) h2o (c) ch4 (d) c2h4 (e) ph3
A space probe traveling from Earth will hit the asteroid belt at what distance? A. 3 AU B. 30 AU C. 50 AU D. 5,000 AU
A space probe traveling from Earth will hit the asteroid belt at 3 AU. Hence, option (A) is correct.
What is the asteroid belt?The Solar System's asteroid belt is a torus-shaped region that is located between the orbits of Jupiter and Mars and is centered on the Sun.
It is home to a large number of asteroids and minor planets, which are solid bodies with erratic shapes. The discovered objects range in size, but they are all considerably smaller than planets.
On average, they are around one million kilometers (or six hundred thousand miles) away. To distinguish it from other asteroid populations in the Solar System.
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The thrust bearing is subjected to the loads as shown. Determine the order of average normal stress developed on cross section through BC and D.
the order of average normal stress developed on cross section through B, C and D c) B>C>D.
What is the primary variation in normal stress?When examined at constant levels of the applied shear stress s, the initial stress distribution differences N1 (cv) show a decreasing trend as the solid fraction cv increases.In other words, the shear stress increases more quickly than the usual stress differential does with filler volume fraction.
How is the typical soil stress determined?
EF is the area, and is the stress, hence F1 = EF.EF = EF = θ θ θ θ θ θ = θ θ θ θregular stress on the plane's EF.We can select the value of from this equation in a way that it equals zero.The primary plane is the one that forms this angle with block, which only experiences normal stress.
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the paperwork needed to start a corporation is extensive and a corporation must also keep detailed records documenting all financial transactions in detail.
"The paperwork needed to start a corporation is extensive and a corporation must also keep detailed financial records documenting all financial transactions in detail."
Incorporation enables enterprises to raise money through the sale of stock. This is a significant benefit as a business expands and requires more funding to function and compete. In comparison to other business entities, the corporation may have an advantage in obtaining bank loans depending on its size and financial stability.
When a firm or person gets taxed twice on the same income, this is known as double taxation. One instance of this is when a business pays corporate taxes on earnings or profits before paying dividends to shareholders who then have to pay personal taxes on the money.
The given question is inappropriate. Corrected question is 'The paperwork needed to start a corporation is extensive and a corporation must also keep detailed ___ records documenting all financial transactions in detail.'
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A proton and an electron of masses 1.67x10^-27kg and 9.1x10^-31kg respectively are separated by a distance of 1m. Determine: a) Force due to gravitatiobal attraction (Fg). [G=6.67x10^-11Nm^2/kg^2] [F=GMm/d^2]
The force of gravitational attraction between the proton and electron is 8.23 x 10^-62 N.
Gravitational Force CalculationThe force of gravitational attraction between two masses can be calculated using the formula F = G * (m1 * m2) / d^2, where F is the force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and d is the distance between them.
For the proton and electron, the force of gravitational attraction can be calculated as follows:
F = G * (1.67 x 10^-27 kg) * (9.1 x 10^-31 kg) / (1 m)^2
G = 6.67 x 10^-11 Nm^2/kg^2
Plugging in the values, we get:
F = 6.67 x 10^-11 Nm^2/kg^2 * (1.67 x 10^-27 kg) * (9.1 x 10^-31 kg) / (1 m)^2
= 8.23 x 10^-62 N
So the force of gravitational attraction between the proton and electron is 8.23 x 10^-62 N.
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differentiate between bar magnet and electro magnet
Permanent(Bar)magnet
(1)hey are permanently magnetized
(2)These are usually made of hard materials.
(3) The strength of the magnetic field line is constant. it can not be varied.
(4)The pole of permanent magnet can not change
(5)Example of permanent magnet is Bar Magnet
Electromagnet
(1) These are temporary Magnetized.
(2) They are usually made of soft materials.
(3)The strength of the magnetic fields can be varied accordingly to our need.
(4) The poles of an electromagnet can be altered
(5) Example of a temporary magnet is solenoid wounded across a nail and connected to a battery..
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An Objects moves in a Circular Path of radius 0.5m worth a Speed of 0.5m/s what is its anglur velocity
Answer:
w=0.25rad/s
Explanation:
w=vr
where v=speed in m/s,r=0.5 in m,w=rad/s
w=0.5×0.5
w=0.25rad/s
An object is 20 cm in front of a diverging lens with a focal length of 10 cm. Use ray tracing to determine the location of the image. Is the image upright or inverted? Is it real or virtual?
The location of the image (object is 20 cm in front of a diverging lens with a focal length of 10 cm = 6.66 cm. The image created by a diverging lens:
Image reduction
Image is vertical
The image is virtual.
Additionally known as a dispersive lens, negative lens, divergent lens, or concave lens. A lens that creates parallel light beams that spread out and veer away from the optical axis after leaving the lens.
The equation:
1/f = 1/v - 1/u
Where,
f = focal length
v = image distance
u = the object distance
Hence,
1/v = - ⅒ - 1/20
= -2/20 - 1/20
v = 6.66 cm
The image created by a diverging lens
Image reduction
Image is vertical
The image is virtual.
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a racing sports car traveling with a constant velocity of 100 mph due west startles a turtle by the side of the road who begins to move out of the way. which of these two objects is likely to have the larger acceleration at that instant? explain ____
The object that is likely to have the larger acceleration at that instant is the turtle. The begins to move from rest.
Analysis of a moving objectA racing sports car traveling with a constant velocity of 100 mph due west.It startles a turtle by the side of the road.The turtle begins to move out of the way.Of these two objects at that instant, find which is likely to have the larger acceleration!
The racing sports car moves with a constant speed. it means that it doesn't accelerate. No information explains that the car accelerated or decelerated as well. The car has no acceleration.
The turtle is initially at rest, then it begins to move out of the way. It moves from 0 m/s to a certain speed of v in a certain time. So, the turtle has an acceleration.
Hence, of these two objects, the turtle is likely to have the larger acceleration
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1kg of air at 1.02 bar , 20°c is compressed reversibly according to a law PV^1.3 = C, to a pressure of 5.5 bar. calculate the work done on the air and the heat supplied during compression.
The heat supplied during compression is 432.26 K and the work done on the air is -3.859 KJ/kg
To find the compression temperature use the formula:
P₁T₁= P₂T₂
To answer this question, we can use the following formula of work:
W = mR (T₁ - T₂)/η - 1
now given,
mass: m = 1 kg
Law PV^1.3 : η = 1.3 (P¹°³)
initial pressure: P₁ = 1.02 bar,
initial temperature: T₁ = 20 + 273 = 293 K
final pressure: P₂ = 5.5 bar
final temperature: T₂ = ?
work: W = ?
Putting the given values in the above equation, we get,
Temperature:
P₁T₁ = P₂T₂
T₂ = P₁T₁/P₂
T₂ = (5.5/1.02)0.3/1.3 × 293
T₂= (5.392)0.2308 × 293
T₂ = 1.4753 x 293
T₂ = 432.26 K.
So, the heat supplied during compression is 432.26 K.
Work:
W = mR (T₁ - T₂)/η - 1 → R = 8.314 J/Kmol
W = 1(8.314)(293 - 432.26)/1.3 - 1
W = 8.314(-139.26)/0.3
W = -1157.8/0.3
W = -3859.3 J/kg
W = -3.859 KJ/kg
So, the work done on the air is -3.859 KJ/kg
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In the circuit shown below batteries and all meters have no significant resistances.
a. If the switch S is open:
(i)
(ii)
Calculate the current through the 100 £2 resistor.
What is the reading of the voltmeter?
b. If the switch S is closed:
(i)
(ii)
(iii)
Calculate the current through the 100 2 resistor.
Calculate the current through the 75 22 resistor.
What is the reading of the ammeter?
V = IP
(a) Sign conventions for emfs
+E: Travel direction
from-to +:
-Travel →
-E: Travel direction
from+to-
←Travel-
E
(b) Sign conventions for resistors
+IR: Travel opposite
to current direction:
-Travel-
14
-IR: Travel in
current direction:
←Travel
-
100.0 Ω
25.0+
V
"L
(1 mark)
(1 mark)
(1 mark)
(1 mark)
(1 mark)
a
15.0
S
s TV
:75.0
A
2
Ω
b
V
Since every resistance is connected in series, the current flowing through the 100 ohm resistor is 0.02 A.
Describe the current formula.The formula for electric current can be used to calculate it: The "current equation," which is derived from Ohm's Law, is the equation I=V/R. Current is represented by the variable "I," voltage by the variable "V," and resistance by the variable "R."
According to Ohm's law, the current flowing through a conductor is proportional to the voltage V and the resistance R; thus, V equals IR. If a charge Q flows through the cross-section of a conductor in time t, the current I is equal to Q/t, which is an alternative statement of Ohm's law. The S.I. charge unit is the coulomb, and electric current is measured in amperes, or coulombs per second.
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state what the gradient of a graph of kinetic friction vs normal force represents
A water tank located at a depth of 8 m from ground level is half full of water. This water is pumped up by a water pump in the basement and drilled at 2 mis'' access. 10 minutes until the water in the tank is finished 0: The power of the motor is 1 kW and the cross-sectional area of the tank is 2m. * ii) Determine the useful work (output) done by the equation /x, (ii) Find the energy required for friction, (iii) Find the efficiency of the pump. (iv) Suggest a way to increase the value of (iii) above. (Density of water = 1000 kgm ]
The output by the equation and energy required for friction is 160,000 J. Efficiency is 0.267 or 26.7% and this efficiency can be improved by friction reduction.
How to calculate output, friction and efficiency?The useful work done by the pump can be calculated as the product of the weight of the water pumped and the height it is lifted. The weight of the water in the tank can be calculated as the density of water times the volume of water in the tank. The volume of water in the tank is half the total volume of the tank, which can be calculated as the cross-sectional area of the tank times its height (8 m). So the weight of the water is:
Volume = cross-sectional area x height = 2 m x 8 m = 16 m³
Weight = Volume x density = 16 m³ x 1000 kg/m³ = 16,000 kg
Useful work = Weight x height = 16,000 kg x 10 m = 160,000 J
The energy required for friction can be estimated as a percentage of the useful work. This percentage depends on the design of the pump, the viscosity of the water and other factors. Assuming a friction loss of 10%, the energy required for friction can be calculated as:
Energy required for friction = 0.1 x 160,000 J = 16,000 J
The efficiency of the pump can be calculated as the ratio of the useful work done by the pump to the energy input. The energy input can be calculated as the product of the power of the motor (1 kW) and the time it is run (10 minutes, or 600 seconds). So the efficiency can be calculated as: Energy input = Power * time = 1 kW x 600 sec = 600,000 J
Efficiency = Useful work / Energy input = 160,000 J / 600,000 J = 0.267 or 26.7%
The efficiency of the pump can be increased by reducing the friction loss, improving the design of the pump to reduce energy losses, or increasing the power of the motor. Another option is to increase the height the water is lifted, as the useful work done by the pump is directly proportional to the height the water is lifted.
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I don't know what to put here is there a formula to find the period?
The period of the oscillation is obtained by dividing the time with the number of oscillation.
What is the period of oscillation?
The period of oscillation is the time taken by a repeating periodic motion to complete one full cycle. It is a measure of the time it takes for an object in a repeating motion to return to its original position.
The period of an oscillation is usually denoted by the symbol T and is usually expressed in units of seconds
The period for the different run is calculated as follows;
T = t / n
where;
t is the time n is the number of oscillation = 10Run 1 , T = 14.22/10 = 1.422 seconds
Run 2, T = 14.18 / 10 = 1.418 s
Run 3, T = 14.15 / 10 = 1.415 s
Run 4, T = 14.28 / 10 = 1.428 s
Run 5, T = 14.33 / 10 = 1.433 s
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A Hockey puck Slides across
the ice at a constant speed of
3.0 m/s for 1.5 seconds. How far does it move during this time.
The distance travelled by the huckey puck, given that it slides across the ice with a speed of 3.0 m/s for 1.5 seconds is 4.5 meters
How do I determine the distance travelled?We know that speed is defined as the distanced travelled in a particular time.
Speed = distance / time
Making distance the subject, we have
Cross multiply
Distance = speed × time
With the above formula, we can obtain the distance the hockey puck will slide Details below:
Speed = 3.0 m/sTime = 1.5 secondsDistance travelled =?Distance = speed × time
Distance travelled = 3.0 m/s × 1.5 seconds
Distance travelled = 4.5 meters
Thus, we conclude that the distance travelled is 4.5 meters
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Answer:
4.5m
Explanation:
Using
Distance= speed * time
D = 1.5 * 3 m
D = 4.5 m
the member with a cross-section area of a is subjected to axial loading p as shown. what is the maximum shearing stress and its corresponding plane?
To determine the maximum shearing stress and its corresponding plane, you would need to know the value of the axial load p, and the cross-sectional area A of the member.
What is shearing stress?
Shearing stress is a type of stress that occurs in a material when the applied forces generate sliding or slippage along the parallel planes within the material. It is a measure of the force per unit area that is resisting this sliding or shearing.
The maximum shearing stress in a member subjected to axial loading is given by the formula:
τ_max = p / (2A)
where p is the axial load, and A is the cross-sectional area of the member. The plane where the maximum shearing stress occurs is perpendicular to the plane of the cross section.
It is important to note that the maximum shearing stress occurs at 45 degrees to the axis of the member, at the point where the stress is acting at right angles to both the longitudinal and radial axes of the cross section.
Therefore, to determine the maximum shearing stress and its corresponding plane, you would need to know the value of the axial load p, and the cross-sectional area A of the member.
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Compare the magnitude and direction of the gravitational force the sun exerts on Earth to the gravitational force Earth exerts on the sun.
The force that Earth applies to the sun is equal to the force that the sun applies to Earth. Between the Sun and the Earth, there is a gravitational force of 32.10.1021 N.
What does Earth's true name entail?Contrary to popular belief, Earth doesn't even have a recognized international name. "Only a common mistake of the galaxy's scientific name, "Terra," exists. the planet's official name in English.
Why is the planet Earth referred to?All living creatures, including plants, animals, and people, call the Earth their home, which is why it is referred to as a "living planet." The optimal solar proximity of the Earth provides it the perfect environment for the development of life things.
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What determines how much of a wave is reflected or transmitted when it meets a new medium?
A. The speed of the wave
B. The amplitude of a wave
C. The wavelength of a wave
D. The properties of the two media
Answer:
the answer is D
Explanation:
D. The properties of the two media determine how much of a wave is reflected or transmitted when it meets a new medium. When a wave encounters a new medium, part of the wave energy may be reflected back and part may be transmitted through the medium. The amount of reflection and transmission depends on the properties of the two media, such as their density, elasticity, and refractive index. These properties determine how much the wave is absorbed or scattered, and how much is transmitted through the new medium. Therefore, the answer is D.
leon started a project to design and create a new video game for the animation studio where he develops graphics and animations for video games and movies.
Computers used by staff during the project item below would be considered an overhead cost.
In business, overhead or overhead fee refers to an ongoing expense of running a commercial enterprise. Overheads are expenditures that can't be without problems traced to or identified with any specific revenue unit, in contrast to operating fees along with raw fabric and labor. consequently, overheads can't be without delay associated with the products or offerings being presented, accordingly do now not directly generate profits.
However, overheads are still critical to business operations as they provide critical support for the business to carry out profit-making activities. as an example, overhead charges which include the lease for a manufacturing unit allow employees to manufacture products that could then be offered for an income. Such costs are incurred for output typically and no longer for particular work orders; e.g., wages paid to watch and ward body of workers, heating and lights fees of the factory, etc. Overheads also are a very essential value detail together with direct substances and direct labor.
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Complete Question:
Leon started a project to design and create a new video game for the animation studio where he develops graphics and animations for video games and movies.
Which item below would be considered an overhead cost?
Each of the images below represents a plot. The horizontal axis on each plot represents time. The vertical axis represents whichever quantity (position, velocity, acceleration) is being discussed. The origin of each plot is represented by 0, and the function is represented by the colored line. For each of the statements at the bottom select the image that best represents the requested plot. You may use the same image for multiple statements if it is appropriate.
Constant velocity - Image D
Constant acceleration - Image A
Constant acceleration to the east - Image C
To release a ball from rest - Image B
What is the velocity time graph?A velocity-time graph is a graph that represents the relationship between the velocity of an object and the time it has been moving. In this type of graph, the velocity of an object is plotted on the y-axis and the time elapsed is plotted on the x-axis.
A velocity-time graph can be used to determine various properties of an object's motion, such as its acceleration, velocity, and displacement. For example, the slope of the velocity-time graph gives the acceleration of the object. If the graph is a straight line, the object is undergoing constant acceleration. If the graph is a curved line, the object is undergoing non-uniform acceleration.
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a gps satellite orbits at an altitude of 20,200 km above the surface of earth. what is the speed of the satellite? (recall that re
The speed of the GPS satellite in orbit is approximately 3.87 km/s.
What is the GPS satellite's orbital speed?MEO, or medium earth orbit, is the term used to describe orbits of this altitude.
We can use the formula for the speed of an object in circular orbit:
v = √(GM/r)
where v is the speed of the satellite, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the center of the Earth and the satellite (which is the sum of the radius of the Earth and the altitude of the satellite).
The mass of the Earth is approximately 5.97 x 10²⁴kg, the radius of the Earth is approximately 6,371 km, and the altitude of the GPS satellite is 20,200 km.
Converting the units to meters, we have:
M = 5.97 x 10²⁴ kg
r = (6,371 km + 20,200 km) x 1000 m/km
= 26,371,000 m
G = 6.674 x 10⁻¹¹ N·m²/kg²
[tex]\mathrm{v = \sqrt{\dfrac{(6.674 \times 10^{-11} N\cdot m^2/kg^2) \times (5.97 x 10^24 kg)}{(26,371,000 m)} } }[/tex]
= 3.87 km/s
Therefore, the speed of the GPS satellite in orbit is approximately 3.87 km/s.
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A cylindrical soda can has a diameter of 6 cm and a height of 12 cm when upright. When the can is placed on its side, the soda reaches a height of 5 cm. What percentage of the volume of the can does the soda fill? (you may use a calculator for the final calculation. ).
The soda fills approximately 41.67% of the volume of the can.
How to find the percentage of the can's volume that is filled with soda?The volume of the cylindrical soda can is given by the formula V = πr^2h,
where
r is the radius of the can h is the height of the canWe are given that the diameter of the can is 6 cm, so the radius is 3 cm. Also, the height of the can is 12 cm when upright. Therefore, the volume of the can is:
V = π(3 cm)^2(12 cm) = 108π cubic centimeters.
When the can is placed on its side and the soda fills to a height of 5 cm, the volume of soda in the can is:
V_soda = π(3 cm)^2(5 cm) = 45π cubic centimeters.
To find the percentage of the can's volume that is filled with soda, we can divide the volume of the soda by the total volume of the can and multiply by 100:
Percentage = (V_soda / V) x 100%
= (45π / 108π) x 100%
= 41.67%
Therefore, the soda fills approximately 41.67% of the volume of the can.
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make figures showing the patellar reflex conduction times and patellar reflex conduction velocites under te various experimental conditions
The patellar reflex happens when there is a sudden change in muscle length; in this situation, the tendon velocity is stretched as a result of the application of the hammer stroke [3, 4].
How does one measure a normal patellar reflex?The deep tendon reflexes are ordinarily ranked as follows: The response of zero is always abnormal. 1+ indicates a weak but unmistakably present response; this could or could not be typical. Fast response; 2+; considered usual.
If your knee doesn't respond, what does that mean?
A symptom of hyporeflexia is a diminished or nonexistent reflex reaction in your skeletal muscles. Damage to any area of your reflex arc—which may have occurred as a result of an underlying medical condition—causes it to occur.
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Identify the FALSE statement. Differentiation of large planetesimals and protoplanets:
is the process by which these bodies develop internal layering.
began with heating up component materials within these bodies.
was caused by heat created by the transformation of kinetic energy from collisions into thermal energy.
was inhibited if radioactive elements were present because their decay required heat input from the surroundings.
resulted in a central ball of iron alloy (the core) and an outer shell of lighter rocky materials (the mantle.)
The false statement is D: "was inhibited if radioactive elements were present because their decay required heat input from the surroundings."
This is false because radioactive elements can provide heat within the planetesimals and protoplanets, helping to drive differentiation by releasing heat from their decay. This heat can cause melting, which can lead to the differentiation of these bodies into internal layering, with a central ball of iron alloy (the core) and an outer shell of lighter rocky materials (the mantle).
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