Answer:
mehoimehoihoi
Step-by-step explanation:
A triangle has vertices at L(2, 2), M(4,4), and N(1,6).
The triangle is transformed according to the rule Ro.
Which statements are true regarding the
transformation? Select three options.
180
The rule for the transformation is (x, y) (-X, -y).
The coordinates of L'are (-2,-2).
The coordinates of Mare (-4,4).
The coordinates of N' are (6,-1).
The coordinates of N'are (-1,-6).
Answer:
The rule for the transformation is (x, y) (-x, -y).
The coordinates of L'are (-2,-2).
The coordinates of N'are (-1,-6).
Step-by-step explanation:
Given
[tex]L = (2,2)[/tex]
[tex]M = (4,4)[/tex]
[tex]N = (1,6)[/tex]
[tex]Ro=180[/tex]
Required
Select three options
The rule to this is:
[tex](x,y) \to (-x,-y)[/tex]
So, we have:
[tex]L = (2,2)[/tex]
[tex]L' =(-2,-2)[/tex]
[tex]M = (4,4)[/tex]
[tex]M =(-4,-4)[/tex]
[tex]N = (1,6)[/tex]
[tex]N' = (-1,-6)[/tex]
It takes Caroline 1 hr to ride the train to some place and 1.5 hr to ride the bus. Every week, she must make at least 8 trips to the place, and she plans to spend no more than 9 hr in travel time. If a train trip costs $6 and a bus trip costs $5, how many times per week should she ride each in order to minimize her cost?
She should ride the train for ___ trips and the bus for ___ trips in order to minimize her cost.
Answer:
She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.
Step-by-step explanation:
Let x represent the number of times that she travels using the train and let y represent the number of times she travels using the bus. Since she makes at least 8 trips to the place, hence:
x + y ≥ 8
Also, she plans to spend no more than 9 hr in travel time. Hence:
x + 1.5y ≤ 9
x ≥ 0, y ≥ 0.
Plotting the above equations on geogebra online graphing tool, the solution is (6, 2), (8, 0) and (9, 0).
If a train trip costs $6 and a bus trip costs $5, The cost equation (C) is:
C = 6x + 5y
At point (6, 2): C = 6(6) + 5(2) = $46
At point (8, 0): C = 6(8) + 5(0) = $48
At point (9, 0): C = 6(9) + 5(0) = $54
Therefore the minimum cost is at (6, 2). She should ride the train for 6 trips and the bus for 2 trips in order to minimize her cost.
find a number such that when it is multiplied by 7 and 17 is subtracted from the product the result is the same as when it is multiplied by 3 and 19 added to the product .
Answer:
9
Step-by-step explanation:
Let the number be X
From the problem we have the following equation:
7x - 17 = 3x + 19
-> 4x = 36
-> x = 9
Answer:
9
Step-by-step explanation:
that is the procedure above
its
A bag contains 5 green candies and 7 blue candies.
A piece of candy is selected at random, put back into the bag, and then
another piece of candy is chosen.
What is the probability that both pieces are green?
Answer:
[tex]P(Green\ and\ Green) = \frac{25}{144}[/tex]
Step-by-step explanation:
Given
[tex]Green=5[/tex]
[tex]Blue = 7[/tex]
Required
[tex]P(Green\ and\ Green)[/tex]
This is calculated as:
[tex]P(Green\ and\ Green) = P(Green) * P(Green)[/tex]
Since, it is a probability with replacement, we have:
[tex]P(Green\ and\ Green) = \frac{Green}{Total} * \frac{Green}{Total}[/tex]
So, we have:
[tex]P(Green\ and\ Green) = \frac{5}{12} * \frac{5}{12}[/tex]
[tex]P(Green\ and\ Green) = \frac{25}{144}[/tex]
Suppose y varies inversely with x, and y = 18 when x = 12. What is the value of x when y = 24? NO LINKS OR ANSWERING YOU DON'T KNOW?
a. 24
b. 9
c. 12
d. 18
Answer:
B. 9
Step-by-step explanation:
We are given that y varies inversely with x. Recall that inverse variation has the form:
[tex]\displaystyle y=\frac{k}{x}[/tex]
Where k is the constant of variation.
We are given that y = 18 when x = 12. Hence:
[tex]\displaystyle (18)=\frac{k}{(12)}[/tex]
Solve for k. Multiply both sides by 12:
[tex]k=12(18)=216[/tex]
Thus, our equation is:
[tex]\displaystyle y=\frac{216}{x}[/tex]
We want to find x when y = 24. Substitute:
[tex]\displaystyle \frac{24}{1}=\frac{216}{x}[/tex]
Cross-multiply:
[tex]24x=216[/tex]
Divide both sides by 24. Hence:
[tex]x=9[/tex]
Our answer is B.
Answer:
B
Step-by-step explanation:
Given that y varies inversely with x then the equation relating them is
y = [tex]\frac{k}{x}[/tex] ← k is the constant of variation
To find k use the condition y = 18 when x = 12 , then
18 = [tex]\frac{k}{12}[/tex] ( multiply both sides by 12 )
216 = k
y = [tex]\frac{216}{x}[/tex] ← equation of variation
When y = 24 , then
24 = [tex]\frac{216}{x}[/tex] ( multiply both sides by x )
24x = 216 ( divide both sides by 24 )
x = 9
The average revenue collected on this flight is $145/seat. However, if the flight is overbooked and the airline needs to rebook a ticketed passenger, United typically gives the customer a free round-trip ticket for a future flight. The cost of this free round-trip ticket averages $330. By how many seats should United overbook for this route
This question is incomplete, the complete question is;
United Airline flights from Newark to Seattle are typically booked to capacity. However, due to United’s current lenient rebooking policies, on average 17 customers (with a standard deviation of 10) cancel or are no shows for these flights. The average revenue collected on this flight is is $145/seat. However, if the flight is overbooked and the airline needs to rebook a ticketed passenger, United typically gives the customer a free round-trip ticket for a future flight. The cost of this free round-trip ticket averages $330. By how many seats should United overbook for this route?
Answer:
the number of seats that should be overbooked is approximately 12
Step-by-step explanation:
Given the data in the question;
average = 17 customers
standard deviation = 10
Cost of under booking the flight ( underage ); Cu = $145
Cost of overbooking the flight ( Overage ); Co = $330
we calculate the service level
service level = Cu / ( Cu + Co )
we substitute
Service level = 145 / ( 330 + 145 )
= 145 / 475
Service level = 0.3053
In excel, we use NORMSIV function to determine the z-value
z-value = NORMSIV ( 0.3053 )
z -value = -0.509
Now, the number of seats (Q) that should be overbooked will be;
Q = Average cancellations + Z-value × S.D
we substitute
Q = 17 + ( -0.509 × 10 )
Q = 17 + ( -5.09 )
Q = 17 - 5.09
Q = 11.91 ≈ 12
Therefore, the number of seats that should be overbooked is approximately 12
Help me with this question, please!!
Answer:
4yz^2
Step-by-step Explanation:
What is the area of the sector that is not shaded?
12Pi units squared
24Pi units squared
120Pi units squared
144Pi units squared
Answer:
120Pi units squared
Step-by-step explanation:
π*12²*(360-60)/360
= π*144*300/360
= π*144*5/6
= π*720/6
= π*120
= 120π or 120Pi units squared
Answer:
120Pi units squared
Step-by-step explanation:
on edge
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5. Assume that the groups consist of 40 couples. Complete parts (a) through (c) below. a. Find the mean and the standard deviation for the numbers of girls in groups of 40 births. The value of the mean is μ
Factor completely 4x2 − 8x + 4.
Given :-
4x² - 8x - 4 .To Find :-
To find the factorised form .Answer :-
Taking the given expression,
→ 4x² - 8x + 4
→ 4x² - 4x -4x + 4
→ 4x ( x - 1 ) -4( x -1)
→ (4x - 4)(x-1)
Hence the required answer is (4x - 4)( x - 1) .
51
What is the inverse of the function f(x) = 2x + 1?
Oh(x) =
1
2x-
o h«x)= kx +
- 3x-2
Oh(x) =
Oh(x) =
Mark this and return
Save and Exit
Next
Submit
Type here to search
81
O
10:49 AM
^ D 0x
mamman
Answer:
let inverse f(x) be m:
[tex]m = \frac{1}{2x + 1} \\ 2x + 1 = \frac{1}{m} \\ 2x = \frac{1 - m}{m} \\ x = \frac{1 - m}{2m} [/tex]
substitute x in place of m:
[tex]{ \bf{ {f}^{ - 1}(x) = \frac{1 - x}{2x } }}[/tex]
Which of the following statements are true?
Answer:
D
Step-by-step explanation:
i think it's correct if not I'm sorry
09:30 am - 4:30 pm minus 30 minutes?
Answer:
4:30
because 9:30 minus 4:30 = 5:00 and 5:00 minus 30 =4:30
Please help me i will give Brainly
Answer:
Step-by-step explanation:
[tex]\frac{3x + 5}{2x + 7}[/tex] = 5
do cross multiplication
3x + 5 = 5(2x + 7)
3x + 5 = 10x + 35
5 - 35 = 10x - 3x
-30 = 7x
-30/7 = x
20 A
since there are 7 angles given it means that the polygon is heptagon as heptagon has 7 sides.
sum of interior angle of heptagon = (n-2)*180
(7-2)*180
5*180
900
Now ,
110 + 90 + 150 + 102 + 110 + 170 + x = 900
732 + x = 900
x = 900 - 732
x = 168 degree
20 B
since 5 angles are given it means that the polygon is pentagon as pentagon has 5 sides.
sum of interior angles of a pentagon = (n-2)*180
(5-2)*180
3*180
540 degree
Now ,
110 + 95 + 120 + 114 + x = 540
465 + x = 540
x = 540 - 465
x = 75 degree
21
let one rational number be x
according to the question,
1/7 * x = 2
x/7 = 2
do cross multiplication
x = 14
Time Remaining 59 minutes 49 seconds00:59:49 PrintItem 1 Time Remaining 59 minutes 49 seconds00:59:49 At the end of Year 2, retained earnings for the Baker Company was $2,950. Revenue earned by the company in Year 2 was $3,200, expenses paid during the period were $1,700, and dividends paid during the period were $1,100. Based on this information alone, what was the amount of retained earnings at the beginning of Year 2?
Answer:
$2550
Step-by-step explanation:
Calculation to determine the amount of retained earnings at the beginning of Year 2
Using this formula
Beginning Retained Earnings + Revenue − Expenses − Dividends = Ending Retained Earnings
Let plug in the formula
Beginning Retained Earnings + $3,200 − $1,700 − $1,100 = $2950
Beginning Retained Earnings= $2,950-$400
Beginning Retained Earnings = $2,550
Therefore the amount of retained earnings at the beginning of Year 2 is $2550
Find the volume of this sphere.
Use 3 for TT.
V [?]in3
V = Tr3
8 in
Answer:
The volume of the sphere is 2048 in³.
Step-by-step explanation:
The volume of a sphere is given by:
[tex] V = \frac{4}{3}\pi r^{3} [/tex]
Where:
r: is the radius = 8 in
Having the radius and by using 3 for π, the volume is:
[tex] V = \frac{4}{3}*3 (8 in)^{3} = 2048 in^{3} [/tex]
Therefore, the volume of the sphere is 2048 in³.
I hope it helps you!
insert a digit in place of each ... to make a number that is divisible by 6
4 . . . 6
Answer:
2
Step-by-step explanation:
help me plz----------------------------
9514 1404 393
Answer:
A. 5 should have been subtracted in step 4
Step-by-step explanation:
No question is stated, so there is no "answer."
__
If we assume the question is, "What error did Keith make?" then choice A properly describes it.
Step 4 should look like ...
x -5 = 7y . . . . . . . 5 should be subtracted from both sides
and the final result should be ...
g(x) = (x -5)/7
What is the distance between -10.2 and 5.7?
Answer:
15.9
Step-by-step explanation:
The distance between -10.2 and 5.7 is 15.9 after plotting the points on a number line.
What is a number line?It is defined as the representation of the numbers on a straight line that goes infinitely on both sides.
It is given that:
Two numbers on a number line:
-10.2 and 5.7
As we know, a number is a mathematical entity that can be used to count, measure, or name things. For example, 1, 2, 56, etc. are the numbers.
Indicating the above numbers on a number line:
= 5.7 -(-10.5)
The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
= 5.7 + 10.5
= 15.9
Thus, the distance between -10.2 and 5.7 is 15.9 after plotting the points on a number line.
Learn more about the number line here:
brainly.com/question/13189025
#SPJ5
What is the meaning proportion between 3 and 27?
Answer:
you mean the mean not the meaning right?
The mean proportional of 3 and 27 = +√3×27 = +√81 = 9.
Solve the right triangle ABC, with C = 90.00◦ , a = 15.21 cm, b = 17.34 cm. Round to two decimal places.
Answer:
the hypotenuse side, c = 23.1 cmangle A = 41.26 ⁰angle B = 48.74 ⁰Step-by-step explanation:
Given;
first leg of the right triangle, a = 15.21 cm
second leg of the right triangle, b = 17.34 cm
Angle C = 90 ⁰
The missing parameters;
the hypotenuse side = cangle Aangle BUse Pythagoras theorem to calculate the missing side "c", which is the hypotenuse
c² = a² + b²
c² = (15.21)² + (17.34)²
c² = 532.02
c = √532.02
c = 23.1 cm
The missing angle A is calculated as;
[tex]tan(A) = \frac{a}{b} \\\\tan(A) = \frac{15.21}{17.34} \\\\tan(A) = 0.8772 \\\\A = tan^{-1} (0.8772)\\\\A = 41.26^0[/tex]
The missing angle is calculated as;
B = 90⁰ - A
B = 90⁰ - 41.26⁰
B = 48.74⁰
pls answer fast I need to submit in 5 mins !!
What is the volume of the prism?
Enter your answer, as a mixed number in simplest form, in the box.
Life Expectancies In a study of the life expectancy of people in a certain geographic region, the mean age at death was years and the standard deviation was years. If a sample of people from this region is selected, find the probability that the mean life expectancy will be less than years. Round intermediate -value calculations to decimal places and round the final answer to at least decimal places.
Answer:
The probability that the mean life expectancy of the sample is less than X years is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean life expectancy, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
We have:
Mean [tex]\mu[/tex], standard deviation [tex]\sigma[/tex].
Sample of size n:
This means that the z-score is now, by the Central Limit Theorem:
[tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
Find the probability that the mean life expectancy will be less than years.
The probability that the mean life expectancy of the sample is less than X years is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean life expectancy, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
To find the equation of a line, we need the slope of the line and a point on the line. Since we are requested to find the equation of the tangent line at the point (36, 6), we know that (36, 6) is a point on the line. So we just need to find its slope. The slope of a tangent line to f(x) at x
Answer:
[tex]m = \frac{1}{12}[/tex]
Step-by-step explanation:
Given
[tex](x,y) = (36,6)[/tex]
[tex]f(x) = \sqrt x[/tex] ----- the equation of the curve
Required
The slope of f(x)
The slope (m) is calculated using:
[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]
[tex](x,y) = (36,6)[/tex] implies that:
[tex]a = 36; f(a) = 6[/tex]
So, we have:
[tex]m = \lim_{h \to 0} \frac{f(a + h) - f(a)}{h}[/tex]
[tex]m = \lim_{h \to 0} \frac{f(36 + h) - 6}{h}[/tex]
If [tex]f(x) = \sqrt x[/tex]; then:
[tex]f(36 + h) = \sqrt{36 + h}[/tex]
So, we have:
[tex]m = \lim_{h \to 0} \frac{\sqrt{36 + h} - 6}{h}[/tex]
Multiply by: [tex]\sqrt{36 + h} + 6[/tex]
[tex]m = \lim_{h \to 0} \frac{(\sqrt{36 + h} - 6)(\sqrt{36 + h} + 6)}{h(\sqrt{36 + h} + 6)}[/tex]
Expand the numerator
[tex]m = \lim_{h \to 0} \frac{36 + h - 36}{h(\sqrt{36 + h} + 6)}[/tex]
Collect like terms
[tex]m = \lim_{h \to 0} \frac{36 - 36+ h }{h(\sqrt{36 + h} + 6)}[/tex]
[tex]m = \lim_{h \to 0} \frac{h }{h(\sqrt{36 + h} + 6)}[/tex]
Cancel out h
[tex]m = \lim_{h \to 0} \frac{1}{\sqrt{36 + h} + 6}[/tex]
[tex]h \to 0[/tex] implies that we substitute 0 for h;
So, we have:
[tex]m = \frac{1}{\sqrt{36 + 0} + 6}[/tex]
[tex]m = \frac{1}{\sqrt{36} + 6}[/tex]
[tex]m = \frac{1}{6 + 6}[/tex]
[tex]m = \frac{1}{12}[/tex]
Hence, the slope is 1/12
Four brands of lightbulbs are being considered for use in the final assembly area of the Ford F-150 truck plant in Dearborn, Michigan. The director of purchasing asked for samples of 200 from each manufacturer. The numbers of acceptable and unacceptable bulbs from each manufacturer are shown below. At the 0.10 significance level, is there a difference in the quality of the bulbs?
Manufacturer
A B C D
Unacceptable 29 17 9 22
Acceptable 171 183 191 178
Total 200 200 200 200
H0: There is no relationship between quality and manufacturer.
H1: There is a relationship.
1) State the decision rule using 0.10 significance level. (Round your answer to 3 decimal places.)
Reject H0 if chi-square >
2) Compute the value of chi-square. (Round your answer to 3 decimal places.)
Chi-square value
Answer:
Decison region :
Reject H0 : if χ² > 6.251
12.229
Step-by-step explanation:
Given :
Manufacturer A B C D
Unacceptable 29 17 9 22
Acceptable 171 183 191 178
Total 200 200 200 200
H0: There is no relationship between quality and manufacturer.
H1: There is a relationship.
Testing using the goodness of fit :
Chisquare = (observed - Expected)² / Expected
Expected Values:
19.25 19.25 19.25 19.25
180.75 180.75 180.75 180.75
Chi-Squared Values:
4.93831 0.262987 5.45779 0.392857
0.525934 0.0280083 0.581259 0.0418396
χ² = 4.93831 + 0.262987 + 5.45779 + 0.392857
+ 0.525934 + 0.0280083 + 0.581259 + 0.0418396 = 12.229
Degree of freedom, df = (4-1)(2-1) = 3*1= 3
The critical value,
χ² at 0.10, 3 = 6.251
Decison region :
Reject H0 : if χ² > 6.251
Reject H0 : 12.229 > 6.251
. Use trigonometric expressions to build an equivalent trigonometric identity with the given expression: cos (x) − cos3 (x) = ?
A)cos (x) sin (x)
B)cos (x) sin2 (x)
C)sin2 (x)
D)sin (x) cos2 (x)
Answer:
B
Step-by-step explanation:
We want to determine an equivalent trignometric identity with the given expression:
[tex]\cos (x) - \cos^3 (x)[/tex]
We can factor out a cos(x):
[tex]=\cos (x) (1-\cos^2 (x))[/tex]
Recall from the Pythagorean Identity that:
[tex]\sin^2(x) + \cos^2(x) = 1[/tex]
Therefore:
[tex]\displaystyle \sin^2(x) = 1 - \cos^2(x)[/tex]
Substitute:
[tex]=\cos(x)(\sin^2(x))=\cos(x)\sin^2(x)[/tex]
Our answer is B.
PLEASE HELP MATH⚠️⚠️⚠️⚠️⚠️
Convert this into algerbraic expression:
The difference of a number cubed and the same number
Step-by-step explanation
n^3-n.
Hope this will help you :) <3
An experiment consists of tossing a coin and rolling a six-sided die simultaneously. Step 1 of 2 : What is the probability of getting a head on the coin and the number 2 on the die
Answer:
[tex]\frac{1}{12}[/tex] probability of getting a head on the coin and the number 2 on the die
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
Independent events:
If two events, A and B are independent, the probability of both events happening is the multiplication of the probabilities of each event happening, that is:
[tex]P(A \cap B) = P(A)P(B)[/tex]
Probability of getting a head on the coin:
Head or tails, fair coin, so:
[tex]P(A) = \frac{1}{2}[/tex]
Probability of getting the number 2 on the die:
6 numbers, one of which is 2, so:
[tex]P(B) = \frac{1}{6}[/tex]
What is the probability of getting a head on the coin and the number 2 on the die?
[tex]P(A \cap B) = P(A)P(B) = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}[/tex]
[tex]\frac{1}{12}[/tex] probability of getting a head on the coin and the number 2 on the die
What’s the answer for this
Answer:
3, 6, 11, 18, 27
Step-by-step explanation:
hope it helps
Answer pllllllleeeaaaaasssss
(3.1) … … …
[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{2x-y}{x-2y}[/tex]
Multiply the right side by x/x :
[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{2-\dfrac yx}{1-\dfrac{2y}x}[/tex]
Substitute y(x) = x v(x), so that dy/dx = x dv/dx + v :
[tex]x\dfrac{\mathrm dv}{\mathrm dx} + v = \dfrac{2-v}{1-2v}[/tex]
This DE is now separable. With some simplification, you get
[tex]x\dfrac{\mathrm dv}{\mathrm dx} = \dfrac{2-2v+2v^2}{1-2v}[/tex]
[tex]\dfrac{1-2v}{2-2v+2v^2}\,\mathrm dv = \dfrac{\mathrm dx}x[/tex]
Now you're ready to integrate both sides (on the left, the denominator makes for a smooth substitution), which gives
[tex]-\dfrac12\ln\left|2v^2-2v+2\right| = \ln|x| + C[/tex]
Solve for v, then for y (or leave the solution in implicit form):
[tex]\ln\left|2v^2-2v+2\right| = -2\ln|x| + C[/tex]
[tex]\ln(2) + \ln\left|v^2-v+1\right| = \ln\left(\dfrac1{x^2}\right) + C[/tex]
[tex]\ln\left|v^2-v+1\right| = \ln\left(\dfrac1{x^2}\right) + C[/tex]
[tex]v^2-v+1 = e^{\ln\left(1/x^2\right)+C}[/tex]
[tex]v^2-v+1 = \dfrac C{x^2}[/tex]
[tex]\boxed{\left(\dfrac yx\right)^2 - \dfrac yx+1 = \dfrac C{x^2}}[/tex]
(3.2) … … …
[tex]y' + \dfrac yx = \dfrac{y^{-3/4}}{x^4}[/tex]
It may help to recognize this as a Bernoulli equation. Multiply both sides by [tex]y^{\frac34}[/tex] :
[tex]y^{3/4}y' + \dfrac{y^{7/4}}x = \dfrac1{x^4}[/tex]
Substitute [tex]z(x)=y(x)^{\frac74}[/tex], so that [tex]z' = \frac74 y^{3/4}y'[/tex]. Then you get a linear equation in z, which I write here in standard form:
[tex]\dfrac47 z' + \dfrac zx = \dfrac1{x^4} \implies z' + \dfrac7{4x}z=\dfrac7{4x^4}[/tex]
Multiply both sides by an integrating factor, [tex]x^{\frac74}[/tex], which gives
[tex]x^{7/4}z'+\dfrac74 x^{3/4}z = \dfrac74 x^{-9/4}[/tex]
and lets us condense the left side into the derivative of a product,
[tex]\left(x^{7/4}z\right)' = \dfrac74 x^{-9/4}[/tex]
Integrate both sides:
[tex]x^{7/4}z=\dfrac74\left(-\dfrac45\right) x^{-5/4}+C[/tex]
[tex]z=-\dfrac75 x^{-3} + Cx^{-7/4}[/tex]
Solve in terms of y :
[tex]y^{4/7}=-\dfrac7{5x^3} + \dfrac C{x^{7/4}}[/tex]
[tex]\boxed{y=\left(\dfrac C{x^{7/4}} - \dfrac7{5x^3}\right)^{7/4}}[/tex]
(3.3) … … …
[tex](\cos(x) - 2xy)\,\mathrm dx + \left(e^y-x^2\right)\,\mathrm dy = 0[/tex]
This DE is exact, since
[tex]\dfrac{\partial(-2xy)}{\partial y} = -2x[/tex]
[tex]\dfrac{\partial\left(e^y-x^2\right)}{\partial x} = -2x[/tex]
are the same. Then the general solution is a function f(x, y) = C, such that
[tex]\dfrac{\partial f}{\partial x}=\cos(x)-2xy[/tex]
[tex]\dfrac{\partial f}{\partial y} = e^y-x^2[/tex]
Integrating both sides of the first equation with respect to x gives
[tex]f(x,y) = \sin(x) - x^2y + g(y)[/tex]
Differentiating this result with respect to y then gives
[tex]-x^2 + \dfrac{\mathrm dg}{\mathrm dy} = e^y - x^2[/tex]
[tex]\implies\dfrac{\mathrm dg}{\mathrm dy} = e^y \implies g(y) = e^y + C[/tex]
Then the general solution is
[tex]\sin(x) - x^2y + e^y = C[/tex]
Given that y (1) = 4, we find
[tex]C = \sin(1) - 4 + e^4[/tex]
so that the particular solution is
[tex]\boxed{\sin(x) - x^2y + e^y = \sin(1) - 4 + e^4}[/tex]