Answer:
step 1: X1=2 , y1=-5
step 2: X2=7, . y2=1
step 3: M=6/5
Step-by-step explanation:
just did it
Martha will build a pool in her backyard. She wants the pool to have a rectangular shape
and to be five meters long and three meters wide. What would the area in Martha's backyard that will be lost due to the construction of the pool? There are 3.28084 feet in
one meter.
A 15 square feet
B 80.729 square feet
C 161.459 square feet
D 322.918 square feet
9514 1404 393
Answer:
C. 161.459 square feet
Step-by-step explanation:
In feet, the dimensions of the pool are ...
(5 m)(3.28084 ft/m) = 16.4042 ft
(3 m)(3.28084 ft/m) = 9.84252 ft
Then the area of the pool is ...
(16.4042 ft)(9.84252 ft) = 161.458666584 square feet
about 161.459 square feet
_____
Additional comment
If you consider that a square meter is slightly less than 11 square feet, the pool area can be estimated to be (5 m)(3 m)(11 ft²/m²) = 165 ft². This is close enough to point you to the correct answer choice.
help Please I’m stuck
Answer:
b and c
Step-by-step explanation:
Let $f(x) = 4x - 7$, $g(x) = (x + 1)^2$, and $s(x) = f(x) + g(x)$. What is $s(3)$?
s(3)=4(3)-7+(3+1)^2
s(3)=12-7+16
s(3)=21
Answer:
21
Step-by-step explanation:
We find that s(x) = 4x - 7 + (x + 1)^2. Expanding, we get s(x) = x^2 + 6x - 6. Plugging in x = 3, we have s(3) = 3^2 + 6 x 3 - 6 = 21.
Alternatively, we can compute that f(3) = 5 and g(3) = 16, so s(3) = f(3) + g(3) = 21.
Which equation is true when x = 6 a. 7x = 35 b. (8+3)x = 28 c. 3x – x + 2 = 14 d. 6x + 3x =225
Answer:
c
Step-by-step explanation:
3X-x+2=14
3*6-6+2=14
14=14
plz make me brainliest
PLEASE HELP ON #3 ASAP!
9514 1404 393
Answer:
1a: x+3 = 5
1c: 6 = 2z
2b: x = 2
2d: 3 = z
3: the solutions make the hangars balance
Step-by-step explanation:
1. We can write the equations by listing the contents of the hangar and using an equal sign to show the balance between left side and right side. It can work well to put left side contents of the hangar on the left side of the equal sign.
A: x + 3 = 5
C: 1 + 1 + 1 + 1 + 1 + 1 = z + z simplifies to 6 = 2z
__
2. B: We can subtract 3 from both sides of the hangar (and equation) to find the value of x.
(x +3) -3 = 5 -3
x = 2 . . . . . hangar balances with 2 on the right
D: We can divide both sides of the hangar by 2, splitting the content into two equal parts. Then one of those parts can be removed from each side.
2(3) = 2(z)
3 = z . . . . . . hangar balances with 3 on the left
__
3. The found values will keep the hangar in balance when they are substituted for the corresponding variables.
A: 2 + 3 = 5
C: 1 + 1 + 1 + 1 + 1 + 1 = 3 + 3
Help!! I’ll give u Brainly!
Answer:
(-4,-2)
Step-by-step explanation:
Point f is on x -4, which is in the first slot and y -2 which is your second slot
How would the area of a triangle be affected if the base and height are dilated by 1/2
Answer:
The area would reduce to 1/4 the original area
Step-by-step explanation:
The area of a triangle = (1/2)(base)(height) or bh/2
If the triangle base and height were to reduce by one-half, the formula would change to:
Area = (1/2)(1/2 base)(1/2 height) or bh/8. Which is a reduction by 1/4
The lengths of wo sides of a right triangle are 5 inches and 8 inches. What is the difference betwen the two
possible lengths of the third side of the triangle? Round your answer to the nearest tenth.
Answer:
The difference between the 2 possible lengths is 3.2 inches.
Step-by-step explanation:
Can someone solve this please
Answer:
35: x=10
36: 9:100
37: 2/3
38: 2 1/42
Step-by-step explanation:
Gwen takes out a loan of $400 to pay for an online course. Flat rate interest is charged at 8% p.a
If she repays the loan in 3
months, how much interest does she pay in total?
We know, 1 year = 12 month.
So, 3 month = 3/12 = 0.25 year.
Now, principle amount, P = $400 .
Rate is, r = 8% = 0.08
Time period, t = 0.25 year.
Now, Interest is given by :
I = P × r × t
I = $( 400 × 0.08 × 0.25 )
I = $8
Therefore, she will pay $8 interest in total.
An investment will pay $100 at the end of each of the next 3 years, $250 at the end of Year 4, $300 at the end of Year 5, and $600 at the end of Year 6. If other investments of equal risk earn 12% annually, what is its present value? Round your answer to the nearest cent.
Answer:
Your parents will retire in 18 years. ... You expect to earn 12% annually on the account. ... An investment will pay $100 at the end of each of the next 3 years, $200 at the end of Year 4, ...
Tim deposit 4500 in a savings account that pays 4.5% simple interest. How much interest does she earn into years?
Answer:
ummmm is it meant to ask in 2 years instead of into years? if so
(-2)⁰+(-2)¹+(-2)²+-2)³
Answer:
-15
Step-by-step explanation:
-2 to the power 0 = -1
-2 to the power 1 = -2
-2² = -4
-2³ = -8
-1 + -2 + -4 + -8 = -15
Help please, I need help understanding this. I'm in Geometry
Answer:
I believe you can set the equations equal to each other and solve for x.
Step-by-step explanation:
reason being is that by definition, a line can be infinite, so in theory, those 2 lines can be equal.
Sketch the graph of each function. Then State the domain, range and increasing, decreasing intervals. Part 1
Problem 15
Answers:
Graph: Shown belowDomain: [3, infinity) Range: [2, infinity)Increasing interval: [2, infinity)Decreasing interval: NoneEach interval is interval notation.
----------------------------------
Explanation:
To get the graph, you can plug in various x values to find their paired y values, then draw a curve through those points. You can only plug in x values that are 3 or larger, as I'll mention later in the next paragraph. A quicker way to get the graph is to use technology. I used GeoGebra to generate the graphs below.
To get the domain, we need to ensure that the stuff under the square root is never negative. So we need to make the x-3 to be 0 or larger. Solving [tex]x-3 \ge 0[/tex] leads to [tex]x \ge 3[/tex] showing that 3 is the smallest value we can plug in. The domain is the interval from 3 to positive infinity. We can write that as [tex]3 \le x < \infty[/tex] which condenses to the interval notation [3, infinity). Note how the square bracket is used to include the endpoint.
The range can be determined from the graph. The lowest point is when y = 2, so the range consists of y outputs that are 2 or larger. We write the interval notation [2, infinity) to mean [tex]2 \le y < \infty[/tex]
The graph also helps us see where the curve is increasing or decreasing. In this case, the curve goes uphill as we move from left to right. Therefore, the graph is increasing over its entire domain. We write the domain as the answer here. Because the function increases over the entire domain, there's no room for the function to decrease.
===========================================================
Problem 16
Answers:
Graph: Shown belowDomain: [-1, infinity) Range: [-3, infinity)Increasing interval: [-1, infinity)Decreasing interval: None----------------------------------
Explanation:
We follow the same idea as the previous problem.
This time we want the x+1 under the square root to be 0 or larger, so [tex]x+1 \ge 0[/tex] solves to [tex]x \ge -1[/tex] telling us the smallest input allowed. The value of x can be this or larger.
Since this is an increasing function throughout the domain (similar to the previous problem), this means that the smallest domain value corresponds exactly to the smallest range value. Plugging in x = -1 leads to y = -3 which is the smallest possible output. As x gets bigger, so does y. The graph shows that the lowest point occurs when y = -3 to visually confirm this.
The increasing interval is over the entire domain, so we just write the domain again for the increasing interval. This means we write "none" for the decreasing interval.
Side note: The graphs are shown together on the same xy coordinate axis, but for your hw problem, you'll have the graphs on their own separate grid.
A path 5m wide is to be built along the border and inside a square garden of side 90m. Find the cost of cementing the path at the rate of Rs.10 per meter square.Required to answer. Single choice.
Answer:
Total cost of cementing the path = Rs. 17,000.
Step-by-step explanation:
Let the square garden be PQRS
Let the region inside the garden (PQRS) be KLMN.
Given the following data;
Length of sides of PQRS = 90m
Width of path = 5m
Cost = Rs. 10 per m²
Area of PQRS = 90 * 90
Area of PQRS = 8100m²
To find the area of KLMN;
KL = KN = 90 - (5 + 5)
KL = KN = 90 - 10
KL = KN = 80m
Area of KLMN = KL * KN
Substituting into the equation, we have;
Area of KLMN = 80 * 80
Area of KLMN = 6400 m²
Area of path = Area of PQRS - Area of KLMN
Area of path = 8100 - 6400
Area of path = 1700 m²
Total cost of cementing the path = Area of path * Cost
Total cost of cementing the path = 1700 * 10
Total cost of cementing the path = Rs. 17,000
Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that
S(T(x)) = x and U (T(x)) = x for all x in R^n
Show that
U(v)= S(v) for all v in R^n
Required:
Compute S(v) and U(v).
Answer:
Follows are the solution to this question:
Step-by-step explanation:
[tex]T: 1 \ R^n \to 1 \ R^n[/tex] is invertible lines transformation
[tex]S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \ \varepsilon\ 1 R^n\\\\[/tex]
T is invertiable linear transformation means that is
[tex]T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix[/tex]
and [tex]\ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists[/tex]
Let
[tex]V \varepsilon\ a\ R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v[/tex]
so,
[tex]s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \ \forall \ \ v \ \ \varepsilon \ \ 1 R^n[/tex]
An area of a wall is 50 in. wide and 35 in. high. Will a mirror with a 62 in. diagonal fit in it? Identify the correct explanation.
Answer:
yes
Step-by-step explanation:
i used the pythagorean theorem and used 50 and 35 as the legs and the diagonal as the hypotenuse
35² + 50² = c²
c² = 3725
c = [tex]\sqrt{3725}[/tex], which is 61.03
since 61.03 is less than 62" then it should fit in
No, Given Mirror will be not fit in the wall.
Here, we use Pythagoras theorem
Base is 50 inch , Height is 35 inch
Now we have to find hypotenuse
[tex]h^{2} =(50)^{2}+(35)^{2} \\\\h^{2}=2500+1225=3725\\\\h=\sqrt{3725}=61.03[/tex]
Since, Diagonal length of wall is 61.03 inch which is less than mirror diagonal length.
Therefore, mirror is not fit in the wall.
Learn more:
https://brainly.com/question/13391411
An article in Fire Technology, 2014 (50.3) studied the effectiveness of sprinklers in firecontrol by the number of sprinklers that activate correctly. The researchers estimate the probability of a sprinkler to activate correctly to be 0.7. Suppose that you are an inspector hired to write a safety report for a large ballroom with 10 sprinklers. Assume the sprinklers activate correctly or not independently.
Required:
a. What is the probability that all of the sprinklers will operate correctly in a fire?
b. What is the probability that at least 7 of the sprinklers will operate correctly in a fire?
c. What is the minimum number of sprinklers needed so that the probability that at least one operates correctly is at least 0.98?
Answer:
0.028 ; 0.649 ; 4
Step-by-step explanation:
P(correctly activation), p = 0.7
Number of sprinklers, n = 10
q = 1 - p = 1 - 0.7 = 0.3
Using the binomial probability relation :
P(x =x) = nCx * p^x * (1 - p)^(n - x)
Probability that all sprinklers activate correctly;
P(x = 10) = 10C10 * 0.7^10 * 0.3^0
P(x = 10) = 1 * 0.0282475249 * 1
P(x = 10) = 0.028
Probability that atleast 7 will operate correctly :
P(x ≥ 7) = p(x = 7) + p(x = 8) + p(x = 9) + p(x = 10)
P(x ≥ 7) = 0.267 + 0.233 + 0.121 + 0.028
P(x ≥ 7) = 0.649
3.)
Probability of atleast 1 operates :
P(x ≥ 1) = 0.98
1 - probability of 0 operates
1 - p(x =0)
P(x = 0) = nC0 * 0.7^0 * 0.3^n = 0.02
Recall :
nC0 = 1 ;
1 - p(x = 0)
P(x = 0) = 1 * 1 * 0.3^n = 0.02
0.3^n = 0.02 - - - (1)
0.3^3.24 = 0.02 - - - (2)
Comparing (1) and (2)
n = 3.24
Since, n cannot be a fraction ;
Then n is rounded to the next whole number = 4
61. Often it is necessary to rearrange an equation so that one variable is expressed in terms of others. For example, the equation D = 3t expresses D in terms of t. To express t in terms of D, divide both sides of this equation by 3 to obtain D/3 = t.
(a) Solve the equation C = 2πr for r in terms of C.
(b) Solve the equation p = 2w + 2h for w in terms of p and h.
(c) Solve the equation 3x − 2y = 6 for y in terms of x.
Search entries or author
Answer:
after it is necessary to rearrange and equations for that one variable is expressed in terms de in term of tea to express it in terms of d we need to solve the equation c is equal to fir for our in terms of c solve the equation p is equal to 2 w plus two hours for w in terms of p and h
Answer:
after it is necessary to rearrange and equations for that one variable is expressed in terms de in term of tea to express it in terms of d we need to solve the equation c is equal to fir for our in terms of c solve the equation p is equal to 2 w plus two hours for w in terms of p and h
What does g =???
2/5g = 5
i really need help!!
Answer:
#8. 2
#9. 7
#10. 2
#11. 2
#12. 0
#13. -4
#14. 17
#15. 1
Answer:#8=2
#9=-11
#10=8
#11=2
#12=0
#14=17
#15=1
Step-by-step explanation: #8-13 (Subtract the numbers using a number line, than add the numbers using a integer chips, after that calculate the sum of the differences) #14-15( normal solving stepping for integers(recommend using a T1-84 Calculator)
GUESS AND CHECK
Problem
Lito went to his friend's farm. His friend's farm has pigs, cows and chickens. He asked him how heads many
per animals he has. His friend answered. There are 4 heads with 128 legs in all.
Problem 2:
There are 4 in a group who are all teenagers. The product of their ages is 56, 160.one of them are of the same age.
Pls I need an answer right now..
Answer:
with 128 legsin in all 56 160 one of them
x (power1)+ 10 and x(power0)+10, when x =10
Answer:
20
11
Step-by-step explanation:
10^1+10 steps:
10^1+10
Calculate 10 to the power of 1 and get 10.
10+10
Add 10 and 10 to get 20.
20
10^0+10 steps:
10^0 +10
Calculate 10 to the power of 0 and get 1.
1+10
Add 1 and 10 to get 11.
11
What is the square root
Answer:
the square root is 2.2
Answer:
2.2
Step-by-step explanation:
make me brainestly
the guy who did the second answer wants beef
A 6 foot man measured his shadow at13 feet 9 inches. Then he measured the
shadow of a flagpole at 125 feet. How tall is the flagpole?(Round to the
nearest tenth)
Answer:
The flagpole is 54.5 inches tall.
Step-by-step explanation:
We solve this question using proportions, by rule of three.
Each feet has 12 inches. So
A 6 foot man measured his shadow at13 feet 9 inches.
So when the real height is of 6 feet, the shadow is of 13 feet + (9/12) feet = 13.75 feet.
When the shadow is of 125 feet, the height is x. So
6 feet - 13.75 feet
x feet - 125 feet
Applying cross multiplication
[tex]13.75x = 6*125[/tex]
[tex]x = \frac{6*125}{13.75}[/tex]
[tex]x = 54.5[/tex]
The flagpole is 54.5 inches tall.
11 + 5 + 52 x 12 – 10 =
(11 + 5) + 52 x (12 - 10) =
Question 8 (1 point) Mrs. Hernandez is making a circular skirt for her daughter's Valentine banquet. She will glue a piece of sequin trim at the edge of the skirt. If the diameter of the circular skirt is 36 inches, what will be the closest measurement needed for the sequin trim in inches? 113 inches 57 Inches 1017 inches 72 inches
Answer: 113 inches
Step-by-step explanation:
To solve the question, we have to find the perimeter of a circle since the skirt is circular. This will be:
Perimeter = 2πr
where
π = 3.142
r = diameter/2 = 36/2 = 18
The closest measurement needed for the sequin trim will then be:
= 2πr
= 2 × 3.142 × 18
= 113.112
= 113 inches
Which of the following could be the lengths of the sides of a 30-60-90 triangle?
Answer: D. 15 square root with 3 inside
Step-by-step explanation:
Just try it
Answer:
c
Step-by-step explanation:
What da answer I’d does not say