Answer:
m = [tex]-\frac{8}{5}[/tex]
Step-by-step explanation:
m = slope
m = [tex]\frac{y2-y1}{x2-x1}[/tex]
m = [tex]\frac{1--7}{-6--1}[/tex]
m = [tex]\frac{8}{-5}[/tex]
m = [tex]-\frac{8}{5}[/tex]
Please help!! First person gets award or whatever it is!! Awarding 10 points
HELP!! I don’t know part C or D and I need to know if part A and B are correct
Answer:
Step-by-step explanation:
A and B are correct!
For part C, just multiply the dimensions given to you by four.
For part D, the answer would be 4 x 4 x 4 which is 264
Which inequality models this situation? 3 The company president sets a goal that the percentage of working phones must increase from 30% to at least 80% by the end of the day. 3 8 -> 103 8. 3+% 10+ DONE () Intro
Answer:
3+x/10+x>8/10
order of operation problem who two operations inside parentheses and two ex outside ( using all add, subtract, multiply and divide)
PLEASE SHOW ALL WORK
Answer:
17 + 123 (4 - 1) + (36 / 18) 52 =
17 + 123 x 3 + 2 x 52 =
17 + 369 + 104 =
17 + 473 =
490
Step-by-step explanation:
hope this helps! i made up everything so i hope its okay!
Pls help I’ll brainlest
If f(x) is an exponential function where f(-2,5) = 9 and f(7) = 91, then find the value of f(12), to the nearest hundredth.
Answer:
[tex]f(12) = 323.02[/tex]
Step-by-step explanation:
Given
[tex]f(-2.5) = 9[/tex]
[tex]f(7) = 91[/tex]
[tex]f(12) = 16.7 * 1.28^{12[/tex]
Required
[tex]f(12)[/tex]
An exponential function is:
[tex]f(x) = ab^x[/tex]
[tex]f(-2.5) = 9[/tex] implies that:
[tex]9 = ab^{-2.5}[/tex]
[tex]f(7) = 91[/tex] implies that:
[tex]91 = ab^7[/tex]
Divide both equations
[tex]91/9 = ab^7/ab^{-2.5}[/tex]
[tex]91/9 = b^7/b^{-2.5}[/tex]
Apply law of indices
[tex]91/9 = b^{7+2.5}[/tex]
[tex]10.11 = b^{9.5}[/tex]
Take 9,5th root of both sides
[tex]b = 1.28[/tex]
So, we have:
[tex]9 = ab^{-2.5}[/tex]
[tex]9 = a * 1.28^{-2.5}[/tex]
[tex]9 = a * 0.54[/tex]
[tex]a = 9/0.54[/tex]
[tex]a = 16.7[/tex]
f(12) is calculated as:
[tex]f(x) = ab^x[/tex]
[tex]f(12) = 16.7 * 1.28^{12[/tex]
[tex]f(12) = 323.02[/tex]
write equation of the line below
Hi there!
We are given two ordered pairs which are:
(0,0)(5,4)If you are curious how do I get these ordered pairs, they come from those two big circles or dots. x and y make relation and can be written as (x,y).
1. Find the slope
Yes, our first step is to find the slope of a graph if you want to find an equation. You may be curious how to find that right? No worries! We have got a special formula for you to find the slope![tex] \large \boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }[/tex]
Since we have two given points, we can substitute them in the formula.
[tex] \large{m = \frac{4 - 0}{5 - 0} } \\ \large \boxed{m = \frac{4}{5} }[/tex]
2. Form an equation.
Since we have finally found, got or evaluated the slope. Next step is to find the y-intercept. Oh! Before we get to form an equation, do you know the slope-intercept form? We will be using that linear equation form since it is commonly used in the topic.[tex] \large \boxed{y = mx + b}[/tex]
Where m = slope and b = y-intercept. We substitute m = 4/5.
[tex] \large{y = \frac{4}{5} x + b}[/tex]
Next thing to remember is that when the graph intersects an origin point, b-term or y-intercept would be 0. Therefore b = 0 since the graph intersects (0,0).
[tex] \large \boxed{y = \frac{4}{5} x}[/tex]
3. Answer
Therefore the equation of the line is y = 4x/5.need help pls gving brainliest
one fourth of a number is 5. find the number
Hope this helps. Please mark brainliest
Answer: 20
let the number be x
1/4 x = 5
x=5*4
x=20
Answer:
x=20
Step-by-step explanation:
[tex]\frac{1}{4}x=5\\x=20[/tex]
divide [tex]\frac{1}{4}[/tex] on both sides, which gives you 20.
The graph of the function f(x)=4/5 sqrt x is shown.
What is the domain of the function?
Answer:
All real number greater than equal to zero.
Step-by-step explanation:
The function is given by
[tex]f(x) = \frac{4}{5}\sqrt x[/tex]
The domain is defined as the input values so that the function is well defined.
here, the values of x should be all real number and zero also.
So, the correct option is (d).
Answer:
D
Step-by-step explanation:
HELP AFAP I WILL GIVE BRAINLIST
Each person in a group of students was identified by year and asked when he or she preferred taking classes: in the morning, afternoon, or evening. The results are shown in the contingency table. Find the probability that the student preferred afternoon classes given he or she is a junior. Round to the nearest thousandth. Be sure to show and explain your work.
When Do You Prefer to Take Classes?
Freshman
Sophomore
Junior
Senior
Morning
2
9
5
10
Afternoon
8
9
8
8
Evening
9
15
16
3
Answer:
Ok where only looking for junior so heres the stats for that
Morning:5
Afternoon:8
Evening:16
so if we add that up
5+8+16=29
and 8 like after noon so
8/29 as a percent 27.5862%
Hope This Helps!!!
If P = (7,-4), Find:
(180° (P)
([?], []
Enter
Step-by-step explanation:
the answer is in the above image
Need help on this question been stuck on it
Answer:
Exponential Function
Step-by-step explanation:
y values increase by x4
Answer:
exponential function
the ans is b
Examine the geometric relationships in the diagram below which option shows the correct value of x and y?
Answer:all of them
Step-by-step explanation:
Find the equation of the line with Slope = 3 and passing through (4, 10) .write your equation in the form y=mx+b
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,637 miles, with a variance of 11,282,880. What is the probability that the sample mean would differ from the population mean by less than 778 miles in a sample of 143 tires if the manager is correct
Answer:
[tex]P(x < -778) = 0[/tex]
Step-by-step explanation:
Given
[tex]\bar x = 48673[/tex]
[tex]\sigma^2 = 11282880[/tex]
[tex]n = 143[/tex]
Required
[tex]P(x <- 778)[/tex]
First, we calculate the z score
[tex]z = \frac{x}{\sqrt{\sigma^2}/n}[/tex]
So, we have:
[tex]z = \frac{-778}{\sqrt{11282880}/143}[/tex]
[tex]z = \frac{-778}{3359.0/143}[/tex]
[tex]z = \frac{-778}{23.49}[/tex]
[tex]z = -33.12[/tex]
So:
[tex]P(x < -778) = P(z < -33.12)[/tex]
From z score probability, we have:
[tex]P(x < -778) = 0[/tex]
The table shows a linear relationship between x and y.
х
у
-20
96
-12
60
-6
33
-2
15
What is the rate of change of y with respect to x?
Answer:
[tex] -\frac{9}{2} [/tex]
Step-by-step explanation:
Rate of change of x and y can be calculated using the following formula and using any two given pair of values from the table:
Rate of change = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]
Using (-12, 60) and (-6, 33).
Where,
[tex] (-12, 60) = (x_1, y_1) [/tex]
[tex] (-6, 33) = (x_2, y_2) [/tex]
Plug is the values
Rate of change = [tex] \frac{33 - 60}{-6 -(-12)} [/tex]
Rate of change = [tex] \frac{-27}{6} [/tex]
Simplify
Rate of change = [tex] \frac{-9}{2} [/tex]
Rate of change = [tex] -\frac{9}{2} [/tex]
3+5 plz help will gibe brain
Answer:
8
Step-by-step explanation:
What is the equation x^2+12x-3=16 written in the form (x-p)^2=q using the method of completing the square ?
Step-by-step explanation:
[tex] {x}^{2} + 12x - 3 = 16[/tex]
[tex] {x}^{2} + 12x = 19[/tex]
[tex] {x}^{2} + 12x + 36 = 19 + 36[/tex]
[tex](x + 6) {}^{2} = 55[/tex]
x + 3y = 10
-x + y = 6
Answer:
X= -2. Y= 4.
Step-by-step explanation:
y = 2x - 3
y = -x + 3 solve for x and y
We are given the system of equations:
[tex] \large{ \begin{cases} y = 2x - 3 \\ y = - x + 3 \end{cases}}[/tex]
Since both are y-isolated equation, we can combine them together.
[tex] \large{2x - 3 = - x + 3}[/tex]
Isolate and solve for x-term.
[tex] \large{2x - 3 + 3 + x = - x + 3 + x + 3} \\ \large{2x + x = 6 \longrightarrow 3x = 6} \\ \large{ \frac{3x}{3} = \frac{6}{3} \longrightarrow \boxed{ \red{x = 2}}}[/tex]
Next, we find the value of y. Simply substitute x = 2 in one of these equations. The less coefficient values, the faster and better. I will substitute x = 2 in y = -x+3. You can substitute x = 2 in y = 2x-3 if you want but the result would be the same.
[tex] \large{y = - x + 3}[/tex]
Substitute x = 2 in the equation.
[tex] \large{y = - 2 + 3} \\ \large \boxed{ \blue{y = 1}}[/tex]
Therefore - when x = 2, y = 1. We can write in coordinate point or ordered pair as (2,1) from (x,y).
Answer
x = 2, y = 1(2,1) --- ordered pairIt costs $21.50 to enter an amusement park and $0.50 to ride a ride. You have $24. Write an equation that represents the number r of rides you can ride.
Answer:
$24.00=$21.50+r*$.50
Step-by-step explanation:
total cost= entrance fee + r (number of rides) * $0.50 (cost of rides)
$24.00=$21.50+r*$.50
2.50=r*.50
2.5/.5=r
r=5
7 + 8/5-2
Could someone help me with this?
Answer:
hope it's helpful for you
peter bought 3 suits and 3 pairs of jeans and paid $2397. James bought 8 suits and 11 pairs of jeans and paid $6989. What is the price of each?
Answer:
Therefore each suit cost $600 and each jean cost $199
Step-by-step explanation:
Let x represent the price of each suit and let y represent the price of each jeans.
Since 3 suits and 3 pairs of jeans cost $2397, this can be represented by the equation:
3x + 3y = 2397
Dividing through by 3:
3x/3 + 3y.3 = 2397/3
x + y = 799 (1)
Also, 8 suits and 11 pairs of jeans cost $6989, this can be represented by the equation:
8x + 11y = 6989 (2)
To find x and y, solve equation 1 and 2 simultaneously. Multiply equation 1 by 8 and subtract from equation 2 to get y:
3y = 597
y = $199
Put y = $199 in equation 1:
x + 199 = 799
x = $600
Therefore each suit cost $600 and each jean cost $199.
A jean manufacturer makes three types of jeans, each of which goes through three manufacturing phases: cutting, sewing, and finishing. The number of minutes each type of product requires in each of the three phases is given below:
Jean Cutting Sewing Finishing
I 8 12 4
II 12 18 8
III 18 24 12
There are 5200 minutes of cutting time, 6000 minutes of sewing time, and 2200 minutes of finishing time each day. The company can sell all the jeans it makes and makes a profit of $4 on each Jean I, $4.50 on each Jean II, and 6 on each Jean III.
Required:
a. What number of jeans in each category should be made each day to maximize profits?
b. Formulate a linear programming problem that models the problem given above. Be sure to identify all variables used.
c. Analyze the solution.
Answer:
z ( max) = 2000 $
x₁ = 500 x₂ = 0 x₃ = 0
Step-by-step explanation:
cutting sewing finishing Profit $
Jean1 (x₁ ) 8 12 4 4
Jean2 (x₂ ) 12 18 8 4.5
Jean3 (x₃ ) 18 24 12 6
Time available 5200 6000 2200
b) Formulation of a linear programming problem:
Objective Function z
z = 4*x₁ + 4.5*x₂ + 6*x₃ to maximize
Constrains:
Constrain 1
Available cutting time 5200 minutes
8*x₁ + 12*x₂ + 18*x₃ ≤ 5200
Constrain 2:
Available sewing time 6000 minutes
12*x₁ + 18*x₂ + 24*x₃ ≤ 6000
Constrain 3:
Available finishing time 2200 minutes
4*x₁ + 8*x₂ + 12*x₃ ≤ 2200
General constraints:
x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 all integers
After 6 iterations the optimal solution is:
z ( max) = 2000 $
x₁ = 500 x₂ = 0 x₃ = 0
We can see in the model that times required to make jean 2 and jean 3
are much bigger than jean 1 and but the price of jean 2 is only 0.5 $ above the price of jean 1 and jean 3 is only 2 $.
How many pounds of each type of fruit did she buy? she bought
pounds of limes and pounds of pears.
Pat bought 5 pounds of apples.
(1) 1 pound of pears cost $0.5 more that 1 pound of apples.
If 1 pound of pears cost $1 and 1 pound of apples cost $0.5, then the cost of 5 pounds of apples is 5*0.5=$2.5. For $2.5 we can buy 2.5/1=2.5 pounds of pears.
If 1 pound of pears cost $1.5 and 1 pound of apples cost $1, then the cost of 5 pounds of apples is 5*1=$5. For $5 we can buy 5/1.5=10/3 pounds of pears.
(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples.
The cost of 5 pounds of apples is $5a (where a is the cost of 1 pound of apples). For $5a we can buy 5a/(1.5a)=5/1.5 pounds of pears. Sufficient.
Learn more about total cost at:
https://brainly.com/question/25109150
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Given question is incomplete , the complete question is given below ,
Pat bought 5 pounds of apples. How many pounds of pears could he have bought for same amount of money?
(1) 1 pound of pears cost $0.5 more that 1 pound of apples
(2) 1 pound of pears cost 1.5 times as much as 1 pound of apples
Here is a trapezium drawn on a centimetre grid (not drawn to scale).
Work out the area of the trapezium, stating the units of your answer.
Answer:
Step-by-step explanation:
equation
area(base1 + base2)
please help meeeeeeee
pt 4
Answer:
The answer is
[tex]2 {x}^{2} + 3x - 1 = 0[/tex]
Why? Below I explain
Step-by-step explanation:
That formula has three variables a, b and c.
So, a = 2, b = 3 and c = -1
Because the formula is written like
[tex] \frac{ - b + - \sqrt{ {b}^{2} - 4 \times a \times c} }{2 \times a} [/tex]
Find an equation for the line with the given property. (a) It passes through the point (2, −6) and is parallel to the line 4x + y − 10 = 0.
It has x-intercept 6 and y-intercept 4.
Answer:
[tex]y = -4x + 2[/tex]
Step-by-step explanation:
Required
Determine the equation
From the question, we understand that, it is parallel to:
[tex]4x + y -10 = 0[/tex]
This means that they have the same slope.
Make y the subject to calculate the slope of: [tex]4x + y -10 = 0[/tex]
[tex]y = -4x + 10[/tex]
The slope of a line with equation [tex]y =mx + c[/tex] is m
By comparison:
[tex]m = -4[/tex]
So, the slope of the required equation is -4.
The equation is then calculated as:
[tex]y = m(x - x_1) + y_1[/tex]
Where:
[tex](x_1.y_1) = (2,-6)[/tex]
So, we have:
[tex]y = -4(x - 2) -6[/tex]
Open bracket
[tex]y = -4x + 8 -6[/tex]
[tex]y = -4x + 2[/tex]
In the questions below suppose the variable x represents students and represents courses, and:
•M(y): y is a math course F(x): x is a freshman
•B(x): x is a full-time student T(x,y): x is taking
•Write the statement in good English without using variables in your answers.
Answer:
Here the answer is given as follows,
Step-by-step explanation:
The last three parts are coming with a question mark, so can't answer those parts. post the image or write it properly
a) Every student is taking at least one course.
[tex]\forall x \exists y T(x,y)[/tex]
So for all x, there is a y such that T(x,y) is a true will be given by the above statement
b) There is a part-time student who is not taking any math courses.
[tex]\exists x \forall y [A(x) \Lambda (M(y) \rightarrow ~T(x,y))][/tex]