Find the product. Write your answer in descending order with respect to the power c
(n-p)² (n+p)

This domain may be rewritten as:

[tex][tex]-3\le x\le4\, and\, 4[/tex]

Thus, option C is correct.

In the graph, we can see the domain by looking at the x values in which the function is defined.

As we can see, the left part of the graph starts at point (-3, 9) and it is filled so it includes it. So, the domain "starts" at x = -3, values below it are undefined on the function.

The quadratic part ends at point (4, 16), so at x = 4 and including it. However, the linear part starts at (4, -1), excluding the point, so at the exact point one ends, the other starts, and no x value is left out on the the transition from one part to the other.

Then, the linear part is defined until point (9, -3.xxx). We don't know exactly the value of the y coordinate, bu the x = 9 is enough for use to know that the function is only defined until x = 9, including it.

Putting these together, we see that the function is defined between the x values of -3 and 9, including both, so the domain is:

[tex][tex]-3\le x\le9\,[/tex]

As the proper alternative divided this interval into the quadratic and linear sections, we don't have an accurate alternative.

So, this domain may be rewritten as:

[tex][tex]-3\le x\le4\, and\, 4[/tex]

Thus, option C is correct.

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Answer: If the question is how many halves will you need in total, then the answer is 14 halves in total or 7 wholes      

Step-by-step explanation:

Answer:

That's a total of 7 cupcakes.

Step-by-step explanation:

5 halves is 2 1/2.

6 halves is 3.

3 halves is 1 1/2.

2 + 3 + 1 + (1/2 + 1/2)

2 + 3 + 1 + (1)

2 + 3 + 1 + 1

5 + 1 + 1

6 + 1

7

The missing side of the right triangle is 5

Right triangles are described as having a right angle that is 90 degrees. The hypotenuse, or side facing the right angle, is the longest side. The other two sides of a right triangle are its legs.

Using the Pythagorean theorem;

According to the theorem that I have just mentioned above, we can write for the right triangle that;

[tex]c^2 = a^2 + b^2[/tex]

Then in the particular case that we have in this problem;

[tex]c = \sqrt{} 13^2 - 12^2[/tex]

c = 5

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Therefore,  SE1/SE2 is less than 1, we can conclude that the sampling distribution for the SRS from California (1700 people) would have a smaller standard deviation compared to the SRS from Detroit (1000 people).

The sampling distribution for the SRS of 1000 people from Detroit would have a smaller standard deviation because the population size is smaller. As population size increases, the standard deviation of the sampling distribution decreases, so the larger population of California (34 million) would result in a larger standard deviation for the sampling distribution of the SRS of 1700 people.

we need to compare the standard errors of the two simple random samples (SRS) from California and Detroit.
Standard Error (SE) is calculated as follows:
SE = σ / √n
where σ is the population standard deviation and n is the sample size.

1. For California:
Sample size (n1) = 1700
Population size (N1) = 34 million

2. For Detroit:
Sample size (n2) = 1000
Population size (N2) = 1 million
Now, let's compare the SE for both:
SE1/SE2 = (σ1/√n1) / (σ2/√n2)

Without knowing the population standard deviations (σ1 and σ2), we cannot determine the exact standard errors. However, since both samples are taken from human populations, it's reasonable to assume that the population standard deviations are relatively similar.
Therefore, we can focus on the sample sizes to compare the standard errors:
SE1/SE2 ≈ (√n2) / (√n1)
SE1/SE2 ≈ (√1000) / (√1700)
SE1/SE2 ≈ (31.62) / (41.23)
SE1/SE2 ≈ 0.77

Therefore,  SE1/SE2 is less than 1, we can conclude that the sampling distribution for the SRS from California (1700 people) would have a smaller standard deviation compared to the SRS from Detroit (1000 people).

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It is important to conduct further research to determine the underlying causes of this phenomenon and to rule out alternative explanations.

The finding that more baseball players are hit with pitches on the hottest days of the season could be due to several reasons. One possible explanation is that the heat makes the pitchers more fatigued, which could lead to them losing control of their pitches and accidentally hitting batters. Another possibility is that the heat may make the ball more difficult to grip, which could affect the accuracy of the pitch.

However, it is also possible that this finding is simply a coincidence or the result of other factors. Therefore, it is important to conduct further research to determine the underlying causes of this phenomenon and to rule out alternative explanations.

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Many diuretic drugs reduce the reabsorption of sodium and water in the kidneys. As a result, the volume of urine produced by the kidneys increases, leading to decreased fluid retention and reduced blood pressure.

This is because the excess sodium and water in the body are excreted through urine, causing the blood volume to decrease, and blood vessels to dilate, resulting in lower blood pressure. However, it is important to note that diuretic drugs can also cause side effects such as electrolyte imbalances, dehydration, and increased urination frequency. It is crucial to follow the prescribed dosage and consult a healthcare professional before taking diuretic drugs.

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The correct format for a multiple regression equation is: Weight = b0 + b1(Age) + b2(Length) + b3(Calories) + e

Yvette can use a multiple regression equation to relate the weight of a cat with its age, length, and average daily intake of cat food. The regression equation: Weight = b0 + b1(Age) + b2(Length) + b3(Calories) + e

where Weight is the cat's weight in pounds, Age is the cat's age in years, Length is the cat's length in inches, Calories is the average daily intake of cat food in calories, b0 is the constant term, b1, b2, and b3 are the coefficients for each variable, and e is the error term.

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A pricing policy change for a hardware store, all products containing the word "saw" in their description have been discounted by 15%, and all products containing the word "hammer" in their description have been discounted by 7%.

This statement describes a pricing strategy employed by SaleCo hardware store, which involves offering discounts on certain products. Specifically, the store has lowered prices on saws and hammers by 15% and 7%, respectively.

Discounting is a common pricing strategy used by businesses to stimulate sales and attract customers.

By lowering the prices of certain products, a store can increase the perceived value of these items and make them more appealing to customers.

This can result in increased sales, which can ultimately lead to higher profits.

The store has chosen to discount saws and hammers.

These products are likely to be in high demand among customers who engage in woodworking or DIY projects, and the discounts are intended to attract these customers and encourage them to make a purchase.

The discounts offered by SaleCo on saws and hammers are relatively modest, with a 15% discount on saws and a 7% discount on hammers. Even small discounts can have a significant impact on sales if they are applied to high-demand products.

The pricing strategy employed by SaleCo is a common one in the retail industry, and it is intended to stimulate sales and attract customers.

By offering discounts on saws and hammers, the store is hoping to increase its customer base and generate more revenue.

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The ladder will reach up to a height of approximately 27.39 feet (rounded to two decimal places).

We can use the Pythagorean theorem to solve this problem. Let's call the distance from the base of the ladder to the house "x". Then, according to the Pythagorean theorem:

[tex]x^2 + 48^2 = 50^2[/tex]

Simplifying this equation, we get:

[tex]x^2 + 2304 = 2500[/tex]

Subtracting 2304 from both sides, we get:

[tex]x^2 = 196[/tex]

Taking the square root of both sides, we get:

x = 14

So the ladder is currently 14 feet away from the house. If Mila pulls the ladder 6 feet farther away from the house, it will be 20 feet away from the house. We can use the same equation to find out how high up the ladder will reach:

[tex]x^2 + y^2 = 50^2[/tex]

Substituting x = 20 and simplifying, we get:

[tex]y^2 = 1500[/tex]

Taking the square root of both sides, we get:

y = 5√30

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The volume of a square pyramid is equal to 1/6 times the volume of a cube when the bases are the same, and the square pyramid is half the height of the cube. The best answer is A.

The volume of a square pyramid can be found using the formula V = (1/3)Bh, where V represents the volume, B is the area of the base, and h is the height of the pyramid. For a cube, the volume formula is V = s^3, where s is the length of a side.

In this scenario, the bases of the square pyramid and the cube are the same, which means that the area of the base (B) and the length of a side (s) of the cube are equal. Additionally, the square pyramid has half the height of the cube. Let's denote the height of the pyramid as h and the height of the cube as 2h.

Now, let's compare their volumes:

Volume of the square pyramid = (1/3)Bh
Volume of the cube = s^3 = B * 2h (since B = s^2)

To find the relationship between their volumes, divide the volume of the square pyramid by the volume of the cube:

(Volume of the square pyramid) / (Volume of the cube) = ((1/3)Bh) / (B * 2h)

Simplify this equation:

(1/3) / 2 = 1/6

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The probability of out of any two students chosen at random, one student will be absent while the other is present is 29/450 or approximately 0.064.

Let's denote the event that a student is absent as A and the event that a student is present as P.

The probability of a student being absent is P(A) = 1/30, which means the probability of a student being present is P(P) = 29/30.

We want to find the probability that out of any two students chosen at random, one student will be absent while the other is present.

There are two possible cases for this event:

The first student is absent and the second student is present

The first student is present and the second student is absent

Let's calculate the probability of each case separately:

Case 1: The probability of the first student being absent is P(A) = 1/30. The probability of the second student being present is P(P) = 29/30. Therefore, the probability of the first student being absent and the second student being present is:

P(A and P) = P(A) × P(P) = (1/30) × (29/30) = 29/900

Case 2: The probability of the first student being present is P(P) = 29/30. The probability of the second student being absent is P(A) = 1/30. Therefore, the probability of the first student being present and the second student being absent is:

P(P and A) = P(P) × P(A) = (29/30) × (1/30) = 29/900

The total probability of one student being absent and the other being present is the sum of the probabilities of the two cases:

P = P(A and P) + P(P and A) = (29/900) + (29/900) = 58/900

Simplifying the fraction by dividing both the numerator and denominator by 2, we get:

P = 29/450

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There are 2,520 ways to form a committee consisting of 3 men and 5 women from a group of 5 men and 10 women.

The combination formula gives the number of possibilities to choose a committee of three persons from a group of five:

C(5, 3) = 5! / (3! * 2!) = 10

Also, the number of ways to select a committee of 5 women from 10 women is given by:

C(10, 5) = 10! / (5! * 5!) = 252

The total number of ways to select a committee consisting of 3 men and 5 women: 10 * 252 = 2,520

Therefore, there are 2,520 ways to form a committee consisting of 3 men and 5 women from a group of 5 men and 10 women.

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If the z-score falls below the critical value, we reject the null hypothesis and conclude that the proportion of people who own cats is indeed smaller than 30%.

The null hypothesis is typically denoted as H0, and the alternative hypothesis is denoted as H1 or Ha. In this case, the hypotheses would be:

H0: The proportion of people who own cats is equal to or greater than 30%.

H1: The proportion of people who own cats is less than 30%.

We can represent this symbolically as:

H0: p >= 0.3

H1: p < 0.3

where p represents the true proportion of people who own cats in the population.

To test this claim, we can use a one-tailed z-test for proportions, where we calculate the z-score of the sample proportion and compare it to the critical value of the standard normal distribution at the chosen significance level (0.05 in this case).

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A picking list is used by forklift drivers to let them know how much of each item to get from specific storage areas in a distribution center.

Explanation:

A picking list is a document that is used by forklift drivers and other warehouse personnel to identify the specific items and quantities that need to be picked from specific storage locations in a distribution center.

The picking list typically contains information such as the item number, description, location, and quantity needed for each item. It may also include other details such as the customer's name, order number, and delivery date.

The purpose of the picking list is to ensure that the correct items are picked in the correct quantities, and that they are picked from the correct storage locations. This helps to ensure that orders are filled accurately and efficiently, and that inventory levels are properly managed.

Once the items are picked, the picking list may be used to update inventory records and to generate packing slips or other shipping documents. The picking list is an essential tool in the warehouse and distribution process, and it helps to ensure that customers receive the correct products on time.

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The pedestrian who started in town A walked for 8 hours before the noon meeting, and the pedestrian who started in town B walked for 6 hours before the noon meeting.

Let's call the distance between town A and town B "D".

When the two pedestrians meet at noon, they have together covered a distance of D, which means they each have walked half the distance, or D/2.

Let's say the pedestrian who started in town A arrives at 4 PM, which means they have walked for 4 hours after the noon meeting. We can use the formula distance = rate x time, where rate is the pedestrian's speed, to find how far they have walked before the noon meeting:

distance = rate x time

D/2 = rate x (noon - 4)

D/2 = rate x (-4)

D/2 = -4rate

rate = -D/8

The negative sign indicates that this pedestrian is walking from town A to town B, in the opposite direction from the positive direction we defined earlier. The magnitude of the rate is D/8, meaning this pedestrian covers 1/8th of the distance every hour.

Similarly, we can use the same formula for the pedestrian who started in town B and arrived at 9 PM:

distance = rate x time

D/2 = rate x (9 - noon)

D/2 = rate x 3

D/6 = rate

rate = D/18

This pedestrian is walking from town B to town A, in the positive direction we defined earlier. The magnitude of the rate is D/18, meaning this pedestrian covers 1/18th of the distance every hour.

Now we can calculate how long each pedestrian walked before the noon meeting:

time = distance / rate

For the pedestrian who arrived in town A at 4 PM:

time = D/2 / (-D/8) = -4 hours

For the pedestrian who arrived in town B at 9 PM:

time = D/2 / (D/18) = 9 hours

The negative sign for the pedestrian who arrived in town A indicates that they started walking in the wrong direction, so they actually walked for 4 - (-4) = 8 hours in the correct direction before reaching the noon meeting point. The pedestrian who arrived in town B walked for 9 - 3 = 6 hours in the correct direction before the noon meeting.

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The area of the right triangle that is given would be = 60.

To calculate the area of the given triangle, the base of the triangle should first be calculated using the Pythagorean theorem.

That is ;

C² = a²+b²

c = 17

a = 8

b = ?

make b the subject of formula;

b² = c²-a²

= 17²-8²

= 289-64

= 225

b = √225 = 15

The area = ½ base ×height

= 1/2× 15 × 8

= 60

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The surface area of the actual Kaaba is 1260 square meters.

To find the surface area of the actual Kaaba, we need to know the dimensions of the real Kaaba. Since we know the dimensions of Kamal's replica and the scale factor, we can use proportion to find the dimensions of the actual Kaaba.

Let x be the length of the actual Kaaba in meters.

Then we have:

x/24 = 50

x = 24 × 50 = 1200 cm = 12 meters

Similarly, the width and height of the actual Kaaba can be found using the same method:

Width of actual Kaaba = 21 cm × 50 = 1050 cm = 10.5 meters

Height of actual Kaaba = 30 cm × 50 = 1500 cm = 15 meters

Now we can find the surface area of the actual Kaaba. The surface area of a rectangular prism (which the Kaaba resembles) is given by:

Surface area = 2lw + 2lh + 2wh

Plugging in the values we found, we get:

Surface area = 2(1210.5) + 2(1215) + 2(10.5 × 15) = 1260 square meters

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The salesman needs to sell $23,050 worth of products to reach his target monthly income of $3000.

To determine how much the salesman needs to sell in a month to reach a monthly income of $3000, we need to consider both his base salary and commission.

Let X be the total amount of sales he needs to make to reach his target income. We can start by setting up an equation to represent his total income in terms of his base salary and commission:

Total Income = Base Salary + Commission

Total Income = $750 + 10%(Sales - $550)

Since his commission is only earned on sales above $550, we subtract $550 from the total sales to calculate the commissionable amount.

We know that his total income needs to be $3000, so we can set up an equation to solve for X:

$3000 = $750 + 10%(X - $550)

$2250 = 10%(X - $550)

$22500 = X - $550

$23050 = X

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30-degree is the smallest value of the [tex]\theta\\[/tex].

If sin(θ) = 1/2 and 0° < θ < 180°, then we know that θ is an acute angle in the first or second quadrant of the unit circle, since sine is positive in those quadrants.

To find the value of θ, we can use the inverse sine function (sin^-1) on both sides of the equation:

[tex]sin^{-1}(sin(\theta)) = sin{^-1}(1/2)[/tex]

θ = 30° or 150°

Since 0° < θ < 180°, the smaller value of θ is 30°.

Therefore, the smaller value of θ is 30°.

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The speed of the boat in still water is 8 miles per hour.

Let's call the speed of the boat in still water "x" (in miles per hour).

When Mackenzie rows downstream, the current is helping her, so the effective speed of the boat is (x + 4) miles per hour. The distance traveled is 96 miles. We can use the formula:

distance = rate × time

to set up an equation for the downstream trip:

96 = (x + 4) t

where "t" is the time (in hours) it takes for the downstream trip.

For the upstream trip, the current is working against Mackenzie, so the effective speed of the boat is (x - 4) miles per hour. The distance traveled is still 96 miles, but this time the trip takes 16 hours longer than the downstream trip. So we can set up another equation:

96 = (x - 4) (t + 16)

Now we have two equations with two unknowns (x and t). We can solve for t in the first equation and substitute into the second equation:

96 = (x - 4) (t + 16)

96 = (x - 4) (96/(x + 4) + 16)

Simplifying, we get:

96 = (x - 4) (96/(x + 4) + 16)

96 = 96(x - 4)/(x + 4) + 16(x - 4)

96(x + 4) = 96(x - 4) + 16(x + 4)(x - 4)

96x + 384 = 96x - 384 + 16(x^2 - 16)

96x + 384 = 96x - 384 + 16x^2 - 256

16x^2 = 256 + 384 + 384

16x^2 = 1024

x^2 = 64

x = 8

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To prove that e(h) has a minimum at h = 3€/M, we need to first understand the terms involved. The upper bound for total numerical error E h2 eh) + M h 6 refers to the maximum possible error in a numerical computation.

It includes two types of error: the truncation error (E h2) which results from approximating a mathematical function using a finite number of terms, and the round-off error (eh) which results from the limited precision of computer arithmetic.
The numerical error e(h) is a function of the step size h used in numerical approximations. It is given by e(h) = E h2 + M h 6 + eh.
Now, to prove that e(h) has a minimum at h = 3€/M, we can take the derivative of e(h) with respect to h and set it to zero.
de(h)/dh = 2Eh - Mh5 + eh'
Setting this equal to zero, we get:
2Eh - Mh5 + eh' = 0
Rearranging and solving for h, we get:
h = (2E/Me')^(1/4)
Substituting this value of h in e(h), we get:
e(h) = (4/3)^(3/4) * (EM)^(1/4) * eh'
Since eh' is a constant, e(h) is minimized when EM is minimized.
Therefore, we need to find the minimum value of EM, which is achieved when h = 3€/M.
Thus, we can conclude that e(h) has a minimum at h = 3€/M.

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The daily growth rate of the bacteria, rounded to the nearest tenth of a percent is approximately 7.2% .

The population of a particular type of bacteria triples in 16 days, and we need to find the daily growth rate rounded to the nearest tenth of a percent.

To find the daily growth rate, we can use the formula for exponential growth:

Final Population = Initial Population * [tex](1 + Growth Rate)^{Number of Days}[/tex]

Since the population triples, the final population is 3 times the initial population. Let's denote the growth rate as 'r' and plug the given information into the formula:

3 * Initial Population = Initial Population * [tex](1+r)^{16}[/tex]

Divide both sides by the initial population:

3 = [tex](1+r)^{16}[/tex]

Now, we need to find the 16th root of 3 to get (1 + r):

(1 + r) = [tex]3^{1/16}[/tex]

Next, subtract 1 from both sides to find the growth rate:

r = [tex]3^{1/16}[/tex] - 1

Calculate the value of r and multiply by 100 to get the percentage:

r ≈ (1.07177 - 1) * 100 ≈ 7.2%

The daily growth rate of the bacteria is approximately 7.2%, rounded to the nearest tenth of a percent. This means that the bacteria population increases by about 7.2% every day for 16 days, resulting in a tripling of the population.

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The above are irregular polygons. Their missing external angles are given as follows:

A) x = 30°

6) x = 105°, y = 55°

B)  x = 70°; y =

F) x =  138.33°

A)

Sum of angles in a pentagon = 540°

Missing internal angle = 540 - (95+100+110+85) = 150

Since exterior angle = 180 degre - it's liner pair

180 - 150 = 30°

so , x = 30°

6)

Sum of angles in hexagon = 720°

To get x and y we must find the missing internal angle (e) between vertex 105° and 145° and (f) between 105° and 115°

Since its' external angel = 45

e = 180-45 = 135°

So f = 720 - (135 + 105 + 115+ 125+ 145)

f = 95°
so x = 180-f = 180-95 = 105°

y = 180-125 = 55°

b) Sum of angles in  a heptagon = 900°

Lets call missing internal angles e1 and e2

Let e1 = 180-y
let e2 = 180-60°

e2 = 120°

So e1 = 900 - (160+120+115+110+125+115)

e1 = 155°

Since e1 = 180 -y
155 = 180-y

y = 180 - 155

y = 25°

x = 180-110

x = 70°

F)  Sum of angles in an Octagon is 1080°

To solve for x, we must realize all internal angles.
Let call the missing angle between x and x+25 e1; and

the one between 135° and (x-5) e2 and
the one between x+25 and 140 e3


e1 = 180-25 = 155°
e2 = 155°

e3 = 180-20=60°

to find x:

1080 = (x+25) + 60 + 140 + (x-5)+155+135+155+x)

collect like terms

1080 - 60 - 155- 155-140-25+5 -135 = x + x + x
415 = 3x
x = 415/3
x = 138.33°

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Answer:

I was not sure if it was positive or negative so I did both

Positive = 15a^5

Negative = -15a^5

Step-by-step explanation:

:)

This is because of the empirical rule, which states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. The answer is option B: 120; 135.

In this case, one standard deviation above the mean is 150 pounds (135 + 15) and one standard deviation below the mean is 120 pounds (135 - 15). Therefore, approximately 68% of all women should weigh between 120 and 150 pounds.
If the average weight for women is normally distributed with a mean of 135 pounds and a standard deviation of 15 pounds, then approximately 68% of all women should weigh between:

1. Calculate the lower limit: mean - standard deviation = 135 - 15 = 120 pounds
2. Calculate the upper limit: mean + standard deviation = 135 + 15 = 150 pounds

So, approximately 68% of all women should weigh between 120 and 150 pounds. The correct answer is option a. 120; 150.

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In match play, when the players agree to consider the hole tied after it has begun, the ruling is known as "halving the hole."

In match play, if the players agree to consider the hole tied after it has begun, the hole is deemed halved, and the players move on to the next hole without any penalty strokes. This is called "conceding the hole" and is a common practice in match play.

This means that both players receive half a point for the hole, and the match proceeds to the next hole.

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